Topic: The easiest way to calculate Critical Path, Total Float, Free Float, Early Start, Early Finish, Late Start, and Late Finish.

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Hot Topics & hallenges Time Management Topic: The easiest way to calculate ritical Path, Total Float, Free Float, Early, Early, Late, and Late. Presenter: Sohel khter, PMP, N,ISMS PMP and Six Sigma instructor, Netcom Learning djunct Professor, M program, UNY 1

genda Network Diagram ritical Path, Near ritical Path enefits of ritical Path uffer/ Float alculation Early, Early, Late, and Late calculation Total Float and Free Float alculation 2

Network Diagram: Usually it just shows dependencies and if activity duration estimates are added then show the critical path or the duration of the project. This diagramming method is also referred to as ctivity on Node (ON). oxes are used to represent activities and arrows show dependencies. D E 3

2 1 4 6 3 3 D E F 3 5 3 G H I ritical Path : The ritical Path is the longest duration path through a network diagram and determines the shortest time to complete the project. Let s look at the Paths: -,-,-, - = 7 wks, -D, D-, - = 10 wks, -D, D-E, E-F, F- = 12 wks = ritical Path! If the longest or ritical Path is 12 weeks long, the estimated duration of our project is also 12 weeks. Few important points are listed below about critical path: It identifies how much individual activities can be delayed without delaying the project. It is the path with least (usually zero) float so none of the activities in the critical path can slip. Delays experienced with any activity on the critical path translate directly into delays of project completion date. Near ritical Path: Path with very small float (slight delay can shift critical path). 4

Float/Slack or uffer alculation: ctivities in the critical path have no float as any delay will increase the duration of the project. Now to calculate the float or buffer for activities not in the critical path we can use the following techniques Find out the largest path the activity is on Subtract the largest path duration of that activity from critical path duration 2 1 4 6 3 3 D -,-,-, - = 7 wks -D, D-E, E-F, F- = 12 wks = ritical Path! -D, D-, - = 10 wks uffer for = 12 7 = 5 wks, buffer for = 12 7 = 5 wk, buffer for = 12 10 = 2 wks E F 3 5

Other values calculated in PM include: Early : The soonest a task can begin. Early : The soonest a task can end. Early = Early + Duration -1 Late : The latest a task can begin without effecting the project duration. Late = Early + Float Late : The latest a task can end without effecting the project duration. Late = Late + Duration -1 Forward Pass is used to calculate Early and Early. ackward Pass is used to calculate Late and Late. uffer:,5 wks, 5 wks, 2 wks 2 1 4 1 2 6 7 8 8 13 13 9 12 11 14 Forward Pass 6 3 3 ES = 3 EF = 3 Float = LF EF or LS - ES 1 6 D 1 6 E F LS = 8 ackward Pass LF = 8 6

Types of Float/Slack Free Float: mount of time an activity can be delayed without affecting the Early of its successor. Total Float: mount of time an activity can be delayed without effecting the Project ompletion date. 9 10 4 1 9 10 19 20 23 35 38 9 1 9 10 15 D E 6 13 14 11 F G H For E Total Float: ritical path duration Longest path of E = 38 19 = 19 wks Free Float: 16,17,18,19 = 4 wks 7

Draw a network diagram and answer the questions. ctivity 1 can start immediately and has an estimated duration of 3 weeks. ctivity 2 can start after activity 1 is completed and has an estimated duration of 3 weeks. ctivity 3 can start after activity 1 is completed and has an estimated duration of 6 weeks. ctivity 4 can start after activity 2 is completed and has an estimated duration of 8 weeks. ctivity 5 can start after activity 4 is completed and after activity 3 is completed. It has an estimated duration of 4 weeks. 3 3 8 4 ct1 ct2 ct4 ct5 6 11 ct3 ct6 1. What is the duration of the critical path?, ct1, ct2, ct4,ct5, = 18 wks 2. What is the float of activity 3? 18 13 = 5 wks 3. What is the float of activity 2? 0 4. What is the float of the path with the longest float? 5 wks 5. new activity 6 is added to the project. It will take 11 weeks to complete and must be completed before activity 5 and after activity 3. Management is concerned that adding the activity will add 11 weeks to the project. How much longer the project will take? New critical path is,ct1, ct3, ct6, = 24 wks, Old critical path was 18 wks. We are adding 24 18 = 6 wks. 8

ctivity Preceding ctivity Estimate in Month 0 D 4 6 F D, 7 E D 8 G F,E 5 F 5 H G 7 H 8 End, 0 1. What is the duration of the critical path?, D, E, G, H,, = 32 wks, D, F, G, H,, = 31 wks, D, F,, = 16 wks,, F,, = 18 wks,, F, G, H,, = 33 wks, crtical path 1. To shorten the length of the project, the sponsor has offered to remove the work of activity E from the project, making activity D the predecessor to activities G and F. What will be the effect? No impact 1. What is the float of activity? 33 18 = 15 wks 2. What is the float of activity E? 33 32 = 1 wk 3. What is the float of activity D? 33 32 = 1 wk 4 8 5 7 8 D E G H 6 7 5 F 9

Questions? 10