1) A 2) B 3) C 4) D 5) A & B 6) C & D

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1 LEVEL 1, PROBLEM 1 How many rectangles are there in the figure below? 9 A B C D If we divide the rectangle, into 4 regions A, B, C, D, the 9 rectangles are as follows: 1) A 2) B 3) C 4) D 5) A & B 6) C & D 7) A & C 8) B & D 9) ABCD

2 LEVEL 1, PROBLEM 2 What number must be added to the sum of 13 and 18 to equal the sum of 20 and 22? = = 44 So, 11 much be added to 31 to equal 44.

3 LEVEL 1, PROBLEM 3 If the cost of 6 pieces of candy went up 12 cents, then the cost of 9 pieces of the same candy would go up 18 cents. If 6 pieces of candy went up 12 cents, then each piece of candy is going up 2 cents. So, 9 pieces would go up 9x2 or 18 cents.

4 LEVEL 2, PROBLEM 1 <a,b> means (a + b) (a b). For example, <7,5> = (7 + 5) (7 5) = 12 2 = 10 Express <8,3> in simplest form. 6 <8,3> = (8+3)-(8-3) = 11-5 = 6

5 LEVEL 2, PROBLEM 2 If Jose gave Pedro 3 dimes, he would still have 8 more dimes than Pedro. If Pedro started with 10 dimes, how many dimes did Jose start with? 24 dimes With 3 more dimes, Pedro would end with 13 dimes and Jose would have 21 (because he ends with 8 more). Which means, Jose started with 24 before he gave Pedro 3.

6 LEVEL 2, PROBLEM 3 A Δ weighs 12 ounces. If a Δ and a weigh as much as 4 Δs, then 2 weigh 72 ounces. Δ = 12 ounces Δ + = 48 ounces which means the must weigh 36 ounces = 72

7 LEVEL 3, PROBLEM 1 A horse has 4 legs and 1 nose. If the difference between the total number of legs and the total number of noses is 39, then how many horses are in the barn? 13 horses For each horse there is a difference of 1. (4 legs 1 nose) So, if there is a difference of 39.3 x 13 = 39, so there must be 39 horses.

8 LEVEL 3, PROBLEM 2 Stephen had 20 nickels, 16 dimes and 4 quarters. He put the coins into 4 stacks so that all the stacks had the same money value. What is the least number of coins Stephen could have in any one stack? 5 coins With 20 nickels, 16 dimes, and 4 quarters, Stephen has $3.60. To place that into 4 stacks of equal monetary value, each stack would have to have 90 cents. We can make 90 cents with 5 coins: 3 Q, 1 D, and 1 N.

9 WEDNESDAY MORNING MATH LEVEL 3, PROBLEM 3 Bart, Blake, Bill, Ben, and Bob are standing side by side. Bart is between 2 boys. Bart is next to Ben but not next to Bill. Bob is in the middle. Blake has no one to his left. Put the name under each boy below. Ben Bart Bob Bill Blake *Be careful when you read the last sentence. Blake has no one to his left. His left is different from our left he is facing us. Collegiate School Wednesday Morning Math December 1, 2010

10 LEVEL 4, PROBLEM 1 Jessie has a box containing between 10 and 20 baseball cards. If he counts them out 2 at a time, he has one left over. If he counts them out 5 at a time, then he has 4 left over. How many baseball cards does Jessie have in the box? 19 cards With a remainder of 1 counting by 2s, the only options are 11, 13, 15, 17, or 19. With a remainder of 4 counting by 5s, the only options are 14 & 19. The only number that meets both criteria is 19.

11 LEVEL 4, PROBLEM 2 Tom and Joanie s job is to take their dog for 4 walks each day. Each is to take the dog for 2 walks. For the first week Joanie cannot take the dog for any walks on Monday or on Tuesday. On Wednesday she can only take it for one walk. The week starts on Monday. She tells Tom that starting Thursday she will take the dog for 3 walks to his 1 until they have evened out the number of walks. Counting Thursday, how many days will this take? 5 days Monday: T T T T Tuesday: T T T T Wednesday: J T T T Thursday: J J J T Friday: J J J T Saturday: J J J T Sunday: J J J T Monday: J J J T

12 LEVEL 4, PROBLEM 3 There are 4 girls who play ping-pong after school. Each girl played exactly 3 games of ping-pong with each of the other girls. How many games of ping-pong were played altogether? 18 games To play each other one time each, there will be 6 games: A-B A-C A-D B-C B-D C-D To play each other 3 times, there will be 6x3 or 18 games