Announcement. Will be graded and sent back before Th. class. Review session next time Closed book One 8.5 by 11 sheet of paper permitted
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1 Announcement Homework 2 in tonight Will be graded and sent back before Th. class Midterm next Tu. in class Review session next time Closed book One 8.5 by 11 sheet of paper permitted Recitation tomorrow on midterm review and project 2
2 Review of Previous Lecture Reliable transfer protocols Pipelined protocols Selective repeat Connection-oriented transport: TCP Overview and segment structure Reliable data transfer Some slides are in courtesy of J. Kurose and K. Ross
3 TCP: retransmission scenarios Host A Host B Host A Host B Seq=92, 8 bytes data Seq=92, 8 bytes data Seq=100, 20 bytes data ACK=120 ACK=100 Seq=92 timeout ACK=100 X timeout loss Seq=92, 8 bytes data Seq=92, 8 bytes data ACK=120 Seq=92 timeout ACK=100 SendBase = 100 time lost ACK scenario Sendbase = 100 SendBase = 120 SendBase = 120 time premature timeout
4 Outline Flow control Connection management Congestion control
5 receive side of TCP connection has a receive buffer: TCP Flow Control flow control sender won t overflow receiver s buffer by transmitting too much, too fast app process may be slow at reading from buffer speed-matching service: matching the send rate to the receiving app s drain rate
6 TCP Flow control: how it works Rcvr advertises spare room by including value of RcvWindow in segments (Suppose TCP receiver discards out-of-order segments) spare room in buffer Sender limits unacked data to RcvWindow guarantees receive buffer doesn t overflow = RcvWindow = RcvBuffer-[LastByteRcvd - LastByteRead]
7 TCP Connection Management Recall: TCP sender, receiver establish connection before exchanging data segments initialize TCP variables: seq. #s buffers, flow control info (e.g. RcvWindow) client: connection initiator server: contacted by client Three way handshake: Step 1: client host sends TCP SYN segment to server specifies initial seq # no data Step 2: server host receives SYN, replies with SYNACK segment server allocates buffers specifies server initial seq. # Step 3: client receives SYNACK, replies with ACK segment, which may contain data
8 TCP Connection Management: Closing Step 1: client end system sends TCP FIN control segment to server client server Step 2: server receives FIN, replies with ACK. Closes connection, sends FIN. Step 3: client receives FIN, replies with ACK. closing FIN ACK FIN closing Enters timed wait - will respond with ACK to received FINs Step 4: server, receives ACK. Connection closed. timed wait closed ACK closed Note: with small modification, can handle simultaneous FINs
9 TCP Connection Management (cont) TCP server lifecycle TCP client lifecycle
10 Outline Flow control Connection management Congestion control
11 Principles of Congestion Control Congestion: informally: too many sources sending too much data too fast for network to handle different from flow control! manifestations: lost packets (buffer overflow at routers) long delays (queueing in router buffers) Reasons Limited bandwidth, queues Unneeded retransmission for data and ACKs
12 TCP Congestion Control end-end control (no network assistance) sender limits transmission: LastByteSent-LastByteAcked Roughly, rate = CongWin RTT CongWin Bytes/sec CongWin is dynamic, function of perceived network congestion How does sender perceive congestion? loss event = timeout or 3 duplicate acks TCP sender reduces rate (CongWin) after loss event three mechanisms: AIMD slow start conservative after timeout events
13 TCP AIMD multiplicative decrease: cut CongWin in half after loss event congestion window additive increase: increase CongWin by 1 MSS every RTT in the absence of loss events: probing 24 Kbytes 16 Kbytes 8 Kbytes time Long-lived TCP connection
14 TCP Slow Start When connection begins, CongWin = 1 MSS Example: MSS = 500 bytes & RTT = 200 msec initial rate = 20 kbps When connection begins, increase rate exponentially fast until first loss event available bandwidth may be >> MSS/RTT desirable to quickly ramp up to respectable rate
15 TCP Slow Start (more) When connection begins, increase rate exponentially until first loss event: RTT Host A Host B one segment double CongWin every RTT two segments done by incrementing CongWin for every ACK received four segments Summary: initial rate is slow but ramps up exponentially fast time
16 Refinement After 3 dup ACKs: CongWin is cut in half window then grows linearly Butafter timeout event: Enter slow start CongWin instead set to 1 MSS; window then grows exponentially to a threshold, then grows linearly Philosophy: 3 dup ACKs indicates network capable of delivering some segments timeout before 3 dup ACKs is more alarming
17 Refinement (more) Q: When should the exponential increase switch to linear? A: When CongWin gets to 1/2 of its value before timeout. Implementation: congestion window size (segments) threshold Variable Threshold Transmission round At loss event, Threshold is set to 1/2 of CongWin just before loss event
18 Summary: TCP Congestion Control When CongWin is below Threshold, sender in slow-start phase, window grows exponentially. When CongWin is above Threshold, sender is in congestion-avoidance phase, window grows linearly. When a triple duplicate ACK occurs, Threshold set to CongWin/2 and CongWin set to Threshold. When timeout occurs, Threshold set to CongWin/2 and CongWin is set to 1 MSS.
19 TCP Fairness Fairness goal: if K TCP sessions share same bottleneck link of bandwidth R, each should have average rate of R/K TCP connection 1 TCP connection 2 bottleneck router capacity R
20 Why is TCP fair? Two competing sessions: Additive increase gives slope of 1, as throughout increases multiplicative decrease decreases throughput proportionally R Connection 2 throughput Connection 1 throughput equal bandwidth share loss: decrease window by factor of 2 congestion avoidance: additive increase loss: decrease window by factor of 2 congestion avoidance: additive increase R
21 Fairness (more) Fairness and UDP Multimedia apps often do not use TCP do not want rate throttled by congestion control Instead use UDP: pump audio/video at constant rate, tolerate packet loss Research area: TCP friendly Fairness and parallel TCP connections nothing prevents app from opening parallel connections between 2 hosts. Web browsers do this Example: link of rate R supporting 9 connections; new app asks for 1 TCP, gets rate R/10 new app asks for 11 TCPs, gets R/2!
22 Q: How long does it take to receive an object from a Web server after sending a request? Ignoring congestion, delay is influenced by: TCP connection establishment data transmission delay slow start Delay modeling Notation, assumptions: Assume one link between client and server of rate R S: MSS (bits) O: object size (bits) no retransmissions (no loss, no corruption) Window size: First assume: fixed congestion window, W segments Then dynamic window, modeling slow start
23 Fixed congestion window (1) First case: WS/R > RTT + S/R: ACK for first segment in window returns before window s worth of data sent delay = 2RTT + O/R
24 Fixed congestion window (2) Second case: WS/R < RTT + S/R: wait for ACK after sending window s worth of data sent delay = 2RTT + O/R + (K-1)[S/R + RTT - WS/R]
25 TCP Delay Modeling: Slow Start (1) Now suppose window grows according to slow start Will show that the delay for one object is: O S P Latency = 2RTT + + P RTT (2 1) R + R where P is the number of times TCP idles at server: S R P = min{ Q, K 1} - where Q is the number of times the server idles if the object were of infinite size. - and K is the number of windows that cover the object.
26 TCP Delay Modeling: Slow Start (2) Delay components: 2 RTT for connection estab and request O/R to transmit object time server idles due to slow start initiate TCP connection request object RTT first window = S/R second window = 2S/R Server idles: P = min{k-1,q} times third window = 4S/R Example: O/S = 15 segments K = 4 windows Q = 2 P = min{k-1,q} = 2 Server idles P=2 times object delivered time at client time at server fourth window = 8S/R complete transmission
27 HTTP Modeling Assume Web page consists of: 1 base HTML page (of size O bits) M images (each of size O bits) Non-persistent HTTP: M+1 TCP connections in series Response time = (M+1)O/R + (M+1)2RTT + sum of idle times Persistent HTTP: 2 RTT to request and receive base HTML file 1 RTT to request and receive M images Response time = (M+1)O/R + 3RTT + sum of idle times Non-persistent HTTP with X parallel connections Suppose M/X integer. 1 TCP connection for base file M/X sets of parallel connections for images. Response time = (M+1)O/R + (M/X + 1)2RTT + sum of idle times
28 HTTP Response time (in seconds) RTT = 100 msec, O = 5 Kbytes, M=10 and X= non-persistent persistent parallel nonpersistent 28 Kbps 100 Kbps 1 Mbps 10 Mbps For low bandwidth, connection & response time dominated by transmission time. Persistent connections only give minor improvement over parallel connections for small RTT.
29 HTTP Response time (in seconds) RTT =1 sec, O = 5 Kbytes, M=10 and X= non-persistent 30 persistent parallel nonpersistent 0 28 Kbps 100 Kbps 1 Mbps 10 Mbps For larger RTT, response time dominated by TCP establishment & slow start delays. Persistent connections now give important improvement: particularly in high delay bandwidth networks.
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