Chem 11 Oa-Section 2. Exam #2. 1 October 2004
|
|
- Shanon Cooper
- 8 years ago
- Views:
Transcription
1 " Chem 11 Oa-Section 2 Exam #2 1 October 2004 Name: K~ Instructions Please read each question carefully and answer it completely and clearly. Do the problems in the order that is easiest for you. Point value is indicated with each question. There are a total of 100 points possible on the exam. Read through the entire exam before beginning. There should be 5 pages including this page and a score tabulation page. You should use clear, carefully drawn structures and pictorial representations for all molecules. Use precise and graphic arrow notation. Show 3-dimensional and resonance forms where necessary. Do not overlook the stereochemistry. Compose your answers so that the logic of your analysis is unmistakable.
2 1. Circle the correct IUPAC name corresponding to each of the following compounds. (3 pts each! 9 pts total) Q ( R)-2-fluoro-5, 6-dimethyl-5-heptene ( R)-6- fluoro-2, 3-d imethyl-2-heptene ~;;~ or ( 5)-2, 3-d imethyl-2-hepten-6-o1 2. a) Calculate the index of hydrogen deficiency (ID) for a molecule with the formula C6sOCI2, (5 pts) ID-= i ((2nt2)- (8..2C-1 )) n:.(p b) In a few words, what does the ID of this molecule tell you about its structure? Draw one possible isomer. This is not an essay question. (4 pts) II-ID: 2. -=> 2. units of UhSa tur-a..nct) (Tr bondslri~) possibl.q isoyy'le..ys: Q 1:1 O, I c..\ -=~ C.I O ( \'Y)o,ny oth;4-fs ~ o..re. t>os'sl b\q.) Ct C..I 3. The following molecule is one of the 10 fragments that were used by Professor Kishi's research group at arvard University to assemble Palytoxin. Label each chiral center as either R or $. (Kishi, V. et. al. J. Am. Chem. Soc. 1989, 111, 7525) (9 pts) 4. A recent article contained the following scheme. While the mechanism of this transformation is beyond the scope of this course, good conformational drawings are not. Each of the conformational drawings below has at least one error. The errors are not in the substituent labels. Clearly indicate three errors in these drawings for full credit. (Fodor, G. B. Tetrahedron 1999, 55, 7391) (6 pts) 'k 0.-\ \ 0,. ( e. ::'9 dk"o,u.)y\ o..~ O-r\0/ ~ ~ or ~ n()1r ~c: r\\ \Y\ 0., ~d~
3 5. a) Five compounds of the molecular formula CS1202 are depicted below. Choose compound(s) from those shown that fit each description. Place the letter corresponding to the compound(s) in the appropriate box. (3 pts each/ 15 pts total) O..r O O O O ~ O h b X;Z XA ~ \\\ A B D I-I I-I ( E all meso compounds a pair of enantiomers all structures that are achiral a pair of diastereomers two structures that describe the same molecule b) In a few words, comment on the optical rotation of a 1 :1 mixture of compounds A and B. What can you say about the optical rotation of a similar 1 :1 mixture of compounds D and E? (6 pts) " \ D: E => r"c) e.ornm2rt\ Co...Y\ be mcade j dl<is-\e.ye.o mer~ do no1 e'1(.h\bit opt\c~ o..c.-\iv\fus fuq,,1 o.re re\a..-\ed. 6. a) Draw two chair conformations of trans-1-ethyl-4-methylcyclohexane that are related to each other by a ring flip. Circle the (10 pts) <;:3 ""'- \- \ \ C.1-!2.C.."" 3 y C3 " W ~ ~~ ~nfby~n b) Is trans-1-ethyl-4-methylcyclohexane chiral? Mark the appropriate box. (3 pts) D Chiral
4 7. a) The 3-dimensional structure of 2,3-dimethylbutane is given below. This question requires you to draw three Newman projections. Draw one Newman projection to represent the conformer as shown with respect the indicated bond. Draw two additional Newman projections representing the lowest and highest energy conformations of 2,3-dimethylbutane. (3 pts each/ 9 pts total) ""(- C3 -- ~...,.. C3 3C --- C ~ " highest en~gy b) Do a "back of the envelope" calculation and predict the Ere, for the lowest energy conformer you just drew. Don't forget units. What interactions are responsible for the Ere,? (6 pts) Erel :. <2> \<.31 mot 8. In class, we discussed A values as a means of gauging the size of a substituent located on a monosubstituted cyclohexane ring. The A values for the ethyl, isopropyl (-C(C3)2). and tertbutyl (-C(C3)3) groups are 1.8 kcal/mol, 2.2 kcal/mol, and 4.8 kcal/mol, respectively. Progression through this series adds one additional methyl group per substituent. One might expect that given the incremental nature of this series, the difference in A value would be consistent as one went from the ethyl to isopropyl groups (difference = 0.4 kcal/mol) and then again from the isopropyl to tert-butyl substituents. Upon analysis, however, the difference in A value between an isopropyl and tert-butyl substituent seems disproportionately large (2.6 kcal/mol). Using a few words and several structures, explain the large difference in A value between the isopropyl and tert-butyl substituents. (12 pts) at a-t.,' I~prop-\\ CO-n adopt 0. ecviorrnatioh,u.)hlc.-h pl0...c.ls 0. intl.) ~ C:lj\\(.X Of +'v'u r(~. -tgrj- butyl ty\us+ pta(!i 0, LClr8er C3 'jroup tntb 9. Explain the concept of chirality in a way that my mom (an accountant in the Midwest with no fu~. real chemistry background) could understand. Use 1-2 sentences and appropriate images in your posltidn answer. (6 pts) ~.your na-nd s O-re. ch\w. l\1~ o.rq. w1\ '(\1) r.\\"{)q~~ \::J~ L(}X\ r\0\ be.~frx'~~d on t)'\e. ~~Y. ~y -\t1\)m~ c'on1 ~\&1 ) ) r ~
5
CONFORMATIONAL ANALYSIS PRACTICE EXERCISES. 1) Draw a Newman projection of the most stable conformation of 2-methylpropane.
CONFORMATIONAL ANALYSIS PRACTICE EXERCISES 1) Draw a Newman projection of the most stable conformation of 2-methylpropane. 2) The structures below are: C 3 C 3 C 3 C 3 A) not isomers. B) conformational
More informationIsomers Have same molecular formula, but different structures
Isomers ave same molecular formula, but different structures Constitutional Isomers Differ in the order of attachment of atoms (different bond connectivity) Stereoisomers Atoms are connected in the same
More informationMolecule Projections
Key Definitions ü Stereochemistry refers to the chemistry in 3 dimensions (greek stereos = solid). This science was created by Pasteur (1860), van Hoff et LeBel (1874). ü Stereisomers are isomeric molecules
More information1. What is the hybridization of the indicated atom in the following molecule?
Practice Final Exam, Chemistry 2210, rganic Chem I 1. What is the hybridization of the indicated atom in the following molecule? A. sp 3 B. sp 2 C. sp D. not hybridized 2. Name the functional groups in
More informationIR Applied to Isomer Analysis
DiscovIR-LC TM Application Note 025 April 2008 Deposition and Detection System IR Applied to Isomer Analysis Infrared spectra provide valuable information about local configurations of atoms in molecules.
More informationcyclohexane cyclopentane Nomenclature Follows same rules as for stright-chain alkanes. Examples: name the following
Structure and Stereochemistry of Alkanes Reading: Wade chapter 3, sections 3-10- 3-16 Study Problems: 3-43, 3-44, 3-45, 3-46 Key oncepts and Skills: ompare the energies of cycloalkanes, and explain ring
More informationMolecular Models Experiment #1
Molecular Models Experiment #1 Objective: To become familiar with the 3-dimensional structure of organic molecules, especially the tetrahedral structure of alkyl carbon atoms and the planar structure of
More informationCHE 232 - Organic Chemistry Exam 1, February 10, 2004
CE 232 - rganic Chemistry Exam 1, February 10, 2004 ame Student ID o. Before you begin this exam: First: You are allowed to have a simple model set at your seat. Please put away all other materials. Second:
More informationChemistry 1110 Organic Chemistry IUPAC Nomenclature
hemistry 1110 rganic hemistry IUPA Nomenclature 1 f the approximately 32 million unique chemical compounds presently known, over 95% of them can be classified as organic; i.e., containing carbon. The IUPA
More informationStereochemistry of Alkanes and Cycloalkanes
Stereochemistry of Alkanes and ycloalkanes onformation of ethane: Rotation is possible around - Different arrangements of atoms that can be converted into one another by rotation about single bonds are
More information2/10/2011. Stability of Cycloalkanes: Ring Strain. Stability of Cycloalkanes: Ring Strain. 4.3 Stability of Cycloalkanes: Ring Strain
4.3 Stability of Cycloalkanes: Ring Strain Angle strain The strain induced in a molecule when bond angles are forced to deviate from the ideal 109º tetrahedral value (Adolf von Baeyer 1885) Stability of
More informationAlcohols. Copyright 2009 by Pearson Education, Inc. Copyright 2009 Pearson Education, Inc. CH 3 CH 2 CH 2 OH 1-propanol OH
Chapter 12 rganic Compounds with xygen and Sulfur 12.1 Alcohols, Thiols, and Ethers Alcohols An alcohol contains a hydroxyl group ( ) attached to a carbon chain. A phenol contains a hydroxyl group ( )
More informationSyllabus for General Organic Chemistry M07A- Fall 2013 Prof. Robert Keil
Syllabus for General Organic Chemistry M07A- Fall 2013 Prof. Robert Keil Textbook and Materials What you must buy: Organic Chemistry 4 th Ed. Janice G. Smith, McGraw Hill. (Older edition is fine) Chem
More informationConjugation is broken completely by the introduction of saturated (sp3) carbon:
Chapter 16 Conjugation, resonance, and dienes Conjugation relies on the partial overlap of p-orbitals on adjacent double or triple bonds. A common conjugated system involves 1,3-dienes, such as 1,3-butadiene.
More informationCHEM 208(Organic Chemistry I) Instructor: Dr. Niranjan Goswami. Tel: (618)545-3361. Email: Ngoswami@kaskaskia.edu. Web: www.kc.cc.il.
CHEM 208(Organic Chemistry I) Instructor: Dr. Niranjan Goswami Tel: (618)545-3361 Email: Ngoswami@kaskaskia.edu Web: www.kc.cc.il.us/ngoswami CHEM 208 COURSE SYLLABUS KASKASKIA COLLEGE NAME TERM YEAR TEXT:
More informationFigure 8. Example of simple benzene naming with chlorine and NO 2 as substituents.
BENZENE NAMING EXPLAINED. This was excerpted from CHEM WIKI and is used with appreciation to the authors. http://chemwiki.ucdavis.edu/organic_chemistry/hydrocarbons/aromatics/naming_the_benzenes. Simple
More informationChapter 12 Organic Compounds with Oxygen and Sulfur
Chapter 12 Organic Compounds with Oxygen and Sulfur 1 Alcohols An alcohol contains a hydroxyl group ( OH) that replaces a hydrogen atom in a hydrocarbon. A phenol contains a hydroxyl group ( OH) attached
More informationH 3 C CH 2 CH 2 CH 2 CH 2 CH 3. Copyright 2012 Nelson Education Ltd. Chapter 1: Organic Compounds 1.1-1
Section 1.1: Alkanes Mini Investigation: Arranging Carbon Atoms, page 10 A. Three different molecules of C 5 H 12 are possible. B. Five arrangements are possible for C 6 H 14, as predicted: H 3 C CH 2
More informationSuggested solutions for Chapter 3
s for Chapter PRBLEM Assuming that the molecular ion is the base peak (00% abundance) what peaks would appear in the mass spectrum of each of these molecules: (a) C5Br (b) C60 (c) C64Br In cases (a) and
More informationUnit Vocabulary: o Organic Acid o Alcohol. o Ester o Ether. o Amine o Aldehyde
Unit Vocabulary: Addition rxn Esterification Polymer Alcohol Ether Polymerization Aldehyde Fermentation Primary Alkane Functional group Saponification Alkene Halide (halocarbon) Saturated hydrocarbon Alkyne
More informationStereochemistry Tutorial: Drawing Enantiomers and Diastereomers
tereochemistry Tutorial: Drawing Enantiomers and Diastereomers Definitions for vocabulary words can be found in the Illustrated Glossary of rganic Chemistry, available on the course web site. A. Discussion
More informationProton Nuclear Magnetic Resonance Spectroscopy
Proton Nuclear Magnetic Resonance Spectroscopy Introduction: The NMR Spectrum serves as a great resource in determining the structure of an organic compound by revealing the hydrogen and carbon skeleton.
More informationChapter 13 Spectroscopy NMR, IR, MS, UV-Vis
Chapter 13 Spectroscopy NMR, IR, MS, UV-Vis Main points of the chapter 1. Hydrogen Nuclear Magnetic Resonance a. Splitting or coupling (what s next to what) b. Chemical shifts (what type is it) c. Integration
More informationChapter 4 Lecture Notes
Chapter 4 Lecture Notes Chapter 4 Educational Goals 1. Given the formula of a molecule, the student will be able to draw the line-bond (Lewis) structure. 2. Understand and construct condensed structural
More informationCalifornia State Polytechnic University, Pomona. Exam Points 1. Nomenclature (1) 30
Chem 316 Final Exam Winter, 2008 Beauchamp ame: Topic Total Points Exam Points 1. omenclature (1) 30 Credit 2. Explanation of elative eactivities of Aromatic 20 Compounds or Carbonyl Compounds 3. eactions
More informationFinal Examination, Organic Chemistry 1 (CHEM 2210) December 2000 Version *A* A. B. C. D.
Final Examination, rganic hemistry 1 (EM 2210) December 2000 Version *A* 1. What are the hybridization of, and the geometrical shape around, the nitrogen atom in the following molecule? N 3 3 A. sp, linear
More informationAssessment Schedule 2013 Chemistry: Demonstrate understanding of the properties of organic compounds (91391)
NCEA Level 3 Chemistry (91391) 2013 page 1 of 8 Assessment Schedule 2013 Chemistry: Demonstrate understanding of the properties of organic compounds (91391) Evidence Statement Q Evidence Achievement Achievement
More informationORGANIC COMPOUNDS IN THREE DIMENSIONS
(adapted from Blackburn et al., Laboratory Manual to Accompany World of hemistry, 2 nd ed., (1996) Saunders ollege Publishing: Fort Worth) Purpose: To become familiar with organic molecules in three dimensions
More informationIUPAC System of Nomenclature
IUPAC System of Nomenclature The IUPAC (International Union of Pure and Applied Chemistry) is composed of chemists representing the national chemical societies of several countries. ne committee of the
More informationAlkanes. Chapter 1.1
Alkanes Chapter 1.1 Organic Chemistry The study of carbon-containing compounds and their properties What s so special about carbon? Carbon has 4 bonding electrons. Thus, it can form 4 strong covalent bonds
More information3.4 The Shapes of Cycloalkanes: Planar or Nonplanar?
3.4 The Shapes of Cycloalkanes: Planar or Nonplanar? Adolf von Baeyer (19th century) assumed cycloalkanes are planar polygons distortion of bond angles from 109.5 gives angle strain to cycloalkanes with
More informationmethyl RX example primary RX example secondary RX example secondary RX example tertiary RX example
ucleophilic Substitution & Elimination hemistry 1 eginning patterns to knowfor S and E eactions - horizontal and vertical templates for practice Example 1 - two possible perspectives (deuterium and tritium
More informationHealth Science Chemistry I CHEM-1180 Experiment No. 15 Molecular Models (Revised 05/22/2015)
(Revised 05/22/2015) Introduction In the early 1900s, the chemist G. N. Lewis proposed that bonds between atoms consist of two electrons apiece and that most atoms are able to accommodate eight electrons
More informationMULTIPLE CHOICE QUESTIONS Part 4 Nomenklatur -konformation
MULTIPLE COICE QUESTIONS Part 4 Nomenklatur -konformation (Answers on pages 21-22) Topic: Nomenclature 1. The IUPAC name for A) 6-Ethyl-3,4-dimethylheptane B) 2-Ethyl-4,5-dimethylheptane C) 3,4,6-Trimethyloctane
More informationSurvival Organic Chemistry Part I: Molecular Models
Survival Organic Chemistry Part I: Molecular Models The goal in this laboratory experience is to get you so you can easily and quickly move between empirical formulas, molecular formulas, condensed formulas,
More informationThe Four Questions to Ask While Interpreting Spectra. 1. How many different environments are there?
1 H NMR Spectroscopy (#1c) The technique of 1 H NMR spectroscopy is central to organic chemistry and other fields involving analysis of organic chemicals, such as forensics and environmental science. It
More informationCourse Prerequisite: Chemistry 141 or 143.
Instructor: Matthias Brewer; Office: Cook A316; email: Matthias.Brewer@uvm.edu BlackBoard Site: bb.uvm.edu Lecture: 10:40am 11:30am MWF, Angell B106 Review Sessions: 5:30pm Thur., Angell B106 Laboratory
More informationChapter 15 Radical Reactions. Radicals are reactive species with a single unpaired electron, formed by
Chapter 15 Radical Reactions Radicals are reactive species with a single unpaired electron, formed by homolysis of a covalent bond; a radical contains an atom that does not have an octet of electrons,
More informationChapter 11 Homework and practice questions Reactions of Alkyl Halides: Nucleophilic Substitutions and Eliminations
Chapter 11 Homework and practice questions Reactions of Alkyl Halides: Nucleophilic Substitutions and Eliminations SHORT ANSWER Exhibit 11-1 Circle your response in each set below. 1. Circle the least
More informationMass Spectrometry. Overview
Mass Spectrometry Overview Mass Spectrometry is an analytic technique that utilizes the degree of deflection of charged particles by a magnetic field to find the relative masses of molecular ions and fragments.2
More informationSuggested solutions for Chapter 7
s for Chapter 7 7 PRBLEM 1 Are these molecules conjugated? Explain your answer in any reasonable way. C Et C Et C Et Revision of the basic kinds of conjugation and how to show conjugation with curly arrows.
More informationAn Introduction to Organic Chemistry
An Introduction to Organic Chemistry 81 Organic Chemistry Organic chemistry is the study of compounds containing carbon with the exception of simple compounds e.g. carbonates (CO 3 2- ), carbon dioxide
More informationA Grignard reagent formed would deprotonate H of the ethyl alcohol OH.
216 S11-E2 Page 2 Name Key I. (9 points) Answer in the boxes below the following questions for the Grignard reagent C 3 -Mg. (1) (2 points) Is the carbon atom associated with magnesium electrophilic or
More informationthe double or triple bond. If the multiple bond is CH 3 C CCHCCH 3
Alkenes, Alkynes, and Aromatic ompounds Alkenes and Alkynes Unsaturated contain carbon-carbon double and triple bond to which more hydrogen atoms can be added. Alkenes: carbon-carbon double bonds Alkynes:
More informationCHEM 203 Exam 1. KEY Name Multiple Choice Identify the letter of the choice that best completes the statement or answers the question.
CHEM 203 Exam 1 KEY Name Multiple Choice Identify the letter of the choice that best completes the statement or answers the question. _D C 1. Which of the following elements is a large percentage of both
More informationList the 3 main types of subatomic particles and indicate the mass and electrical charge of each.
Basic Chemistry Why do we study chemistry in a biology course? All living organisms are composed of chemicals. To understand life, we must understand the structure, function, and properties of the chemicals
More informationChapter 10. Conjugation in Alkadienes and Allylic Systems. Class Notes. B. The allyl group is both a common name and an accepted IUPAC name
Chapter 10 Conjugation in Alkadienes and Allylic Systems Chapter 10 suggested problems: I. The allyl group Class Notes A. B. The allyl group is both a common name and an accepted IUPAC name 1. Allyl alcohol
More informationQ.1 Draw out some suitable structures which fit the molecular formula C 6 H 6
Aromatic compounds GE 1 BENZENE Structure Primary analysis revealed benzene had an... empirical formula of and a molecular formula of 6 6 Q.1 Draw out some suitable structures which fit the molecular formula
More informationCalculating the Degrees of Unsaturation From a Compound s Molecular Formula
Calculating the Degrees of Unsaturation From a Compound s Molecular Formula Alkanes have the molecular formula C n. Alkanes are saturated hydrocarbons because each member of the family has the maximum
More informationChapter 1 Benzene Blues 27
hapter 1 Benzene Blues 27 The ybridization Model of Atoms in Molecules An important question facing chemists about 80 years ago, was, ow does one go from recently invented atomic orbitals to rationalizing
More informationProton Nuclear Magnetic Resonance ( 1 H-NMR) Spectroscopy
Proton Nuclear Magnetic Resonance ( 1 H-NMR) Spectroscopy Theory behind NMR: In the late 1940 s, physical chemists originally developed NMR spectroscopy to study different properties of atomic nuclei,
More informationOrganic chemistry. Bridge course
Organic chemistry Nomenclature of Organic compounds Bridge course Nomenclature of organic compounds There are two systems of naming 1. Trivial system 2. IUPAC system Trivial system: When a few organic
More informationCombinatorial Biochemistry and Phage Display
Combinatorial Biochemistry and Phage Display Prof. Valery A. Petrenko Director - Valery Petrenko Instructors Galina Kouzmitcheva and I-Hsuan Chen Auburn 2006, Spring semester COMBINATORIAL BIOCHEMISTRY
More informationHomolytic vs. Heterolytic Fragmentation
omolytic vs. eterolytic Fragmentation Most organic transformations involve the movement of electron pairs (heterolytic reactions). There are a few important addition reactions, however, in which the electron
More informationCopyright 2010 Pearson Education, Inc. Chapter Fourteen 1
An alcohol has an OH bonded to an alkyl group; a phenol has an OH bonded directly to an aromatic ring; and an ether has an O bonded to two organic groups. Chapter Fourteen 1 Ethyl alcohol, dimethyl ether,
More informationPlease read and sign the Honor Code statement below:
CHEM 3311 Exam #1 Name Dr. Minger June 8, 2015 Please read and sign the Honor Code statement below: I pledge that on my honor, as a University of Colorado at Boulder student, I have neither given nor received
More informationPROTON NUCLEAR MAGNETIC RESONANCE SPECTROSCOPY (H-NMR)
PROTON NUCLEAR MAGNETIC RESONANCE SPECTROSCOPY (H-NMR) WHAT IS H-NMR SPECTROSCOPY? References: Bruice 14.1, 14.2 Introduction NMR or nuclear magnetic resonance spectroscopy is a technique used to determine
More informationAP CHEMISTRY 2007 SCORING GUIDELINES. Question 6
AP CHEMISTRY 2007 SCORING GUIDELINES Question 6 Answer the following questions, which pertain to binary compounds. (a) In the box provided below, draw a complete Lewis electron-dot diagram for the IF 3
More informationChemistry Workbook 2: Problems For Exam 2
Chem 1A Dr. White Updated /5/1 1 Chemistry Workbook 2: Problems For Exam 2 Section 2-1: Covalent Bonding 1. On a potential energy diagram, the most stable state has the highest/lowest potential energy.
More informationAbsolute Structure Absolute Configuration
Absolute Structure Absolute Configuration Some definitions Absolute Configuration -> spatial arrangement of the atoms for a chiral molecule (R/S, P/M or D/L assignment). Absolute Structure -> spatial arrangement
More informationA REVIEW OF GENERAL CHEMISTRY: ELECTRONS, BONDS AND MOLECULAR PROPERTIES
A REVIEW OF GENERAL CEMISTRY: ELECTRONS, BONDS AND MOLECULAR PROPERTIES A STUDENT SOULD BE ABLE TO: 1. Draw Lewis (electron dot and line) structural formulas for simple compounds and ions from molecular
More informationAlcohols An alcohol contains a hydroxyl group ( OH) attached to a carbon chain. A phenol contains a hydroxyl group ( OH) attached to a benzene ring.
Chapter : rganic Compounds with xygen Alcohols, Ethers Alcohols An alcohol contains a hydroxyl group ( H) attached to a carbon chain. A phenol contains a hydroxyl group ( H) attached to a benzene ring.
More informationMolecular Formula Determination
Molecular Formula Determination Classical Approach Qualitative elemental analysis Quantitative elemental analysis Determination of empirical formula Molecular weight determination Molecular formula determination
More informationPaper 2 (7404/2): Organic and Physical Chemistry Mark scheme
AQA Qualifications AS hemistry Paper 2 (7404/2): Organic and Physical hemistry Mark scheme 7404 Specimen paper Version 0.5 MARK SEME AS hemistry Specimen paper 2 Question Marking guidance Mark AO omments
More informationBoston University Dresden Science Program ORGANIC CHEMISTRY CAS CH 203 Lecture
Boston University Dresden Science Program ORGANIC CHEMISTRY CAS CH 203 Lecture Instructor: Professor Wolf D. Habicher, Professor Claus Rüger Meeting Times Lectures: twice a week at 90 minutes each Discussions:
More informationCH 3 Addition to an alkene with Br 2. No reaction when an aromatic molecule is mixed with Br 2. No Reaction. + H Br
RADIALS Reactions with 2 : 2 3 Addition to an alkene with 2 2 No reaction when an aromatic molecule is mixed with 2 2 (in the dark) No Reaction 2 h (in the light) During a demonstration by Dr., the reactants
More informationChemPad3. a tutorial. Ben Shine and Dana Tenneson. May 21, 2008
ChemPad3 a tutorial Ben Shine and Dana Tenneson May 21, 2008 1 Welcome to ChemPad! ChemPad is a Tablet PC application for students learning introductory organic chemistry. ChemPad allows students to draw
More information2814 hains, Rings and Spectroscopy June 2003 Mark Scheme 2814 Mark Scheme June 2003 The following annotations may be used when marking: X = incorrect response (errors may also be underlined) ^ = omission
More informationDNA is found in all organisms from the smallest bacteria to humans. DNA has the same composition and structure in all organisms!
Biological Sciences Initiative HHMI DNA omponents and Structure Introduction Nucleic acids are molecules that are essential to, and characteristic of, life on Earth. There are two basic types of nucleic
More informationWhere Is My Lone Pair?
Where Is My Lone Pair? Goal: In this tutorial we'll learn how to determine which orbital contains a lone pair. This is important for resonance, conjugation, and aromaticity. To master this subject you'll
More informationEXPERIMENT 1: Survival Organic Chemistry: Molecular Models
EXPERIMENT 1: Survival Organic Chemistry: Molecular Models Introduction: The goal in this laboratory experience is for you to easily and quickly move between empirical formulas, molecular formulas, condensed
More informationHOMEWORK PROBLEMS: IR SPECTROSCOPY AND 13C NMR. The peak at 1720 indicates a C=O bond (carbonyl). One possibility is acetone:
HMEWRK PRBLEMS: IR SPECTRSCPY AND 13C NMR 1. You find a bottle on the shelf only labeled C 3 H 6. You take an IR spectrum of the compound and find major peaks at 2950, 1720, and 1400 cm -1. Draw a molecule
More informationC has 4 valence electrons, O has six electrons. The total number of electrons is 4 + 2(6) = 16.
129 Lewis Structures G. N. Lewis hypothesized that electron pair bonds between unlike elements in the second (and sometimes the third) row occurred in a way that electrons were shared such that each element
More informationHOW TO STUDY CHEMISTRY
AN OVERALL STUDY STRATEGY HOW TO STUDY CHEMISTRY For an introductory science course such as Chemistry 1A, lectures usually provide the best guide to the study of the subject. The instructor presents and
More informationThe Experiment Some nuclei have nuclear magnetic moments; just as importantly, some do not
Chemistry 2600 Lecture Notes Chapter 15 Nuclear Magnetic Resonance Spectroscopy Page 1 of 23 Structure Determination in Organic Chemistry: NMR Spectroscopy Three main techniques are used to determine the
More informationOrganic Chemistry Tenth Edition
Organic Chemistry Tenth Edition T. W. Graham Solomons Craig B. Fryhle Welcome to CHM 22 Organic Chemisty II Chapters 2 (IR), 9, 3-20. Chapter 2 and Chapter 9 Spectroscopy (interaction of molecule with
More informationWorksheets for Organic Chemistry
Worksheets for Organic Chemistry Worksheet 1 Alkanes Question 1. Provide IUPAC names for the following structures a) b) c) d) e) f) g) h) Chemistry of Natural Substances Organic Chemistry Worksheets 1
More informationGeorgia Perimeter College - Dunwoody Campus Chemistry 1152-200 Fall 2011 Course Syllabus(revised)
Georgia Perimeter College - Dunwoody Campus Chemistry 1152-200 Fall 2011 Course Syllabus(revised) Course Title: Survey of Chemistry II, TR 1000 1115 Room NE-1260 Instructor: Dr. Jerry L. Poteat, Associate
More information3. Assign these molecules to point groups a. (9) All of the dichlorobenzene isomers Cl
CE 610 Spring 2007 Problem Set 1 key Total points = 200 1. (10 points) What distinguishes transition metals from the other elements in the periodic table? List five physical or chemical features that are
More informationPrentice Hall. Chemistry (Wilbraham) 2008, National Student Edition - South Carolina Teacher s Edition. High School. High School
Prentice Hall Chemistry (Wilbraham) 2008, National Student Edition - South Carolina Teacher s Edition High School C O R R E L A T E D T O High School C-1.1 Apply established rules for significant digits,
More informationChem 30A Fall 2004 QUIZ #2 (BLUE) Weds Nov 10th
Last Name ANSWER First Name KEY MI Student I Number: Circle the name of your TA: iscussion Section ay: Cari / Phil / Adam / eather Time: Total Score 35 / 30 Chem 30A Fall 2004 QUIZ #2 (BLUE) (15 Min) Weds
More informationUsed to determine relative location of atoms within a molecule Most helpful spectroscopic technique in organic chemistry Related to MRI in medicine
Structure Determination: Nuclear Magnetic Resonance CHEM 241 UNIT 5C 1 The Use of NMR Spectroscopy Used to determine relative location of atoms within a molecule Most helpful spectroscopic technique in
More informationPRACTICE PROBLEMS, CHAPTERS 1-3
PRATIE PRBLEMS, APTERS 1-3 (overed from h. 3: Alkane and Alkyl alide nomenclature only) 1. The atomic number of boron is 5. The correct electronic configuration of boron is: A. 1s 2 2s 3 B. 1s 2 2p 3.
More informationDetermination of Molecular Structure by MOLECULAR SPECTROSCOPY
Determination of Molecular Structure by MOLEULAR SPETROSOPY hemistry 3 B.Z. Shakhashiri Fall 29 Much of what we know about molecular structure has been learned by observing and analyzing how electromagnetic
More informationControlling Gold Nanoparticles with Atomic Precision: Synthesis and Structure Determination
Controlling Gold Nanoparticles with Atomic Precision: Synthesis and Structure Determination Huifeng Qian Department of Chemistry, Carnegie Mellon University, USA Advisor: Prof. Rongchao Jin Background
More informationNMR Spectroscopy of Aromatic Compounds (#1e)
NMR Spectroscopy of Aromatic Compounds (#1e) 1 H NMR Spectroscopy of Aromatic Compounds Erich Hückel s study of aromaticity in the 1930s produced a set of rules for determining whether a compound is aromatic.
More informationLOS ANGELES MISSION COLLEGE-SUMMER 2013 CHEMISTRY 51-SECTIONS 0552 Lecture: MTWTh 10:35-12:40 ; Room: CMS-028 Lab: MTWTh 1:00-2:25 ; Room: CMS-201
LOS ANGELES MISSION COLLEGE-SUMMER 2013 CHEMISTRY 51-SECTIONS 0552 Lecture: MTWTh 10:35-12:40 ; Room: CMS-028 Lab: MTWTh 1:00-2:25 ; Room: CMS-201 INSTRUCTOR: Said Pazirandeh OFFICE PHONE: (818)364-7705
More informationCHEM 322 Organic Chemistry II - Professor Kathleen V. Kilway
CHEM 322 Organic Chemistry II - Professor Kathleen V. Kilway "Organic Chemistry" by Maitland Jones, 4th edition Chapter 12 Homework: 1, 2, 4, 5, 6, 7, 15, 16, 17, 19, 21, 24, 26, 28, 29, 30, 38, 39, 44,
More informationAP Chemistry A. Allan Chapter 8 Notes - Bonding: General Concepts
AP Chemistry A. Allan Chapter 8 Notes - Bonding: General Concepts 8.1 Types of Chemical Bonds A. Ionic Bonding 1. Electrons are transferred 2. Metals react with nonmetals 3. Ions paired have lower energy
More informationVisualizing Molecular Orbitals: A MacSpartan Pro Experience
Introduction Name(s) Visualizing Molecular Orbitals: A MacSpartan Pro Experience In class we have discussed Lewis structures, resonance, VSEPR, hybridization and molecular orbitals. These concepts are
More informationCHEM 121. Chapter 18. Name: Date: 1. Which of the following compounds is both an aldose and a hexose? A) Page 1
CEM 121. Chapter 18. Name: Date: 1. Which of the following compounds is both an aldose and a hexose? A) B) C) D) Page 1 2. Which of the following structures is that of an L-monosaccharide? A) B) C) D)
More informationCHM 2210: ORGANIC CHEMISTRY II Third Exam, Form 3 Section 02, Professor A. Herriott November 29, 2007
CM 2210: ORGANIC CEMISTRY II Third Exam, Form 3 Section 02, Professor A. erriott November 29, 2007 No electronic devices (calculators, cell phones, laptops, etc) may be used or consulted during the exam.
More informationQuestion Bank Organic Chemistry-I
Question Bank Organic Chemistry-I 1. (a) What do you understand by the following terms : (i) Organic chemistry (ii) Organic compounds (iii) Catenation? [3] (b) Why are there very large number of organic
More informationElectrophilic Aromatic Substitution
Electrophilic Aromatic Substitution Electrophilic substitution is the typical reaction type for aromatic rings. Generalized electrophilic aromatic substitution: E E Electrophile Lewis acid: may be or neutral.
More informationThis class deals with the fundamental structural features of proteins, which one can understand from the structure of amino acids, and how they are
This class deals with the fundamental structural features of proteins, which one can understand from the structure of amino acids, and how they are put together. 1 A more detailed view of a single protein
More informationName Lab #3: Solubility of Organic Compounds Objectives: Introduction: soluble insoluble partially soluble miscible immiscible
Lab #3: Solubility of rganic Compounds bjectives: - Understanding the relative solubility of organic compounds in various solvents. - Exploration of the effect of polar groups on a nonpolar hydrocarbon
More informationelectron does not become part of the compound; one electron goes in but two electrons come out.
Characterization Techniques for Organic Compounds. When we run a reaction in the laboratory or when we isolate a compound from nature, one of our first tasks is to identify the compound that we have obtained.
More informationORGANIC CHEMISTRY I PRACTICE EXERCISE Sn1 and Sn2 Reactions
ORGANIC CEMISTRY I PRACTICE EXERCISE Sn1 and Sn2 Reactions 1) Which of the following best represents the carbon-chlorine bond of methyl chloride? d d - d - d d d d - d - I II III IV V 2) Provide a detailed,
More informationProperties of a molecule. Absolute configuration, Cahn-Ingold Prelog. Planar, axial, topological chirality and chirality at atoms other than carbon
Key stereochemical terminology Stereochemical terminology in organic chemistry can refer to structure of a molecule or to properties of a physical sample of the molecule. It is very important to recognize
More informationEverything You Need to Know About Mechanisms. First rule: Arrows are used to indicate movement of electrons
Everything You eed to Know About Mechanisms A) The orrect Use of Arrows to Indicate Electron Movement The ability to write an organic reaction mechanism properly is key to success in organic chemistry
More information