AQA Level 2 Certificate in Further Mathematics 8360 Worksheet 10 Factor Theorem Mark Scheme

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Version 1.0 AQA Level 2 Certificate in Further Mathematics 8360 Worksheet 10 Mark Scheme

Further copies of this Feedback are available to download from the AQA Website: www.aqa.org.uk Copyright 2011 AQA and its licensors. All rights reserved. COPYRIGHT AQA retains the copyright on all its publications. However, registered centres for AQA are permitted to copy material from this booklet for their own internal use, with the following important exception: AQA cannot give permission to centres to photocopy any material that is acknowledged to a third party even for internal use within the centre. Set and published by the Assessment and Qualifications Alliance. The Assessment and Qualifications Alliance (AQA) is a company limited by guarantee registered in England and Wales (company number 3644723) and a registered charity (registered charity number 1073334). Registered address: AQA, Devas Street, Manchester 5 6EX

Glossary for Mark Schemes These examinations are marked in such a way as to award positive achievement wherever possible. Thus, for these papers, marks are awarded under various categories. M A B M Dep B Dep ft SC oe Method marks are awarded for a correct method which could lead to a correct answer. Accuracy marks are awarded when following on from a correct method. It is not necessary to always see the method. This can be implied. Marks awarded independent of method. A method mark dependent on a previous method mark being awarded. A mark that can only be awarded if a previous independent mark has been awarded. Follow through marks. Marks awarded following a mistake in an earlier step. Special case. Marks awarded within the scheme for a common misinterpretation which has some mathematical worth. Or equivalent. Accept answers that are equivalent. eg, accept 0.5 as well as 2 1 3

1(a) x(x 2 5x 36) B1 1(b) x = 0, x = 4, x = 9 B2 B1 For two solutions 2(a) f(1) = 1 + 2 5 6 = 8 B1 f( 1) = 1 + 2 + 5 6 = 0 B1 2(b) f(2) = 8 + 8 10 6 = 0 B1 f( 2) = 8 + 8 + 10 6 = 4 B1 2(c) f(3) = 27 + 18 15 6 = 24 B1 f( 3) = 27 + 18 + 15 6 = 0 B1 2(d) (x + 1), (x 2) and (x + 3) B1 3(a) ( 5) 3 + 7( 5) 2 + 2( 5) 40 oe 125 + 175 10 40 = 0 Clearly shown to = 0 3(b) x 3 + 7x 2 + 2x 40 (x + 5)(x 2 + kx 8) Sight of x 2 and 8 in a quadratic factor (x 2) (x + 4) Alt 1 3(b) Substitutes another value into the (x 2) (x + 4) Alt 2 3(b) Long division of polynomials getting as far as x 2 + 2x (x 2) (x + 4) 3(c) (x =) 5, 4 and 2 B1 4

4 ( 2) 3 + 5( 2) 2 + 9( 2) + k = 0 8 + 20 18 + k = 0 k = 6 5(a) ( 3) 3 + ( 3) 2 + ( 3)a 72 = 0 27 + 9 3a 72 = 0 a = 30 5(b) x 3 + x 2 30x 72 (x + 3)(x 2 + kx 24) Sight of x 2 and 24 in a quadratic factor (x + 4) (x 6) Alt 1 5(b) Substitutes another value into the (x + 4) (x 6) Alt 2 5(b) Long division of polynomials getting as far as x 2 2x (x + 4) (x 6) 5

6(a) (x 3)(x + 4)(x + k) x 3 + ax 2 + bx + 24 or 3 4 k = 24 (x 2) 6(b) (x 3)(x + 4)(x 2) (x 3)(x 2 + 2x 8) oe x 3 x 2 14x + 24 a = 1 and b = 14 ft ft Their expansion Alt 6(b) Substitutes any two of x = 4, x = 2 or x = 3 into x 3 + ax 2 + bx + 24 to create simultaneous equations Any two of 64 + 16a 4b + 24 = 0 or 8 + 4a + 2b + 24 = 0 or 27 + 9a + 3b + 24 = 0 a = 1 b = 14 ft ft Their first solution 6

7(a) (5) 3 + k(5) 2 + 9(5) 20 = 0 125 + 25k + 45 20 = 0 k = 6 7(b) x 3 6x 2 + 9x 20 (x 5)(x 2 + kx + 4) Sight of x 2 and 4 in a quadratic factor (x 5)(x 2 x + 4) 7c Tests b 2 4ac for the quadratic ft Their quadratic or attempts to solve their quadratic = 0 Shows b 2 4ac = 15 (or < 0) and states no more linear factors States 'no solutions' to their quadratic = 0 8 Substitutes a value of x into the Works out first linear factor (x + 1), (x + 2) or (x 9) x 3 6x 2 25x 18 (x + 1)(x 2 + kx 18) or (x + 2)(x 2 + kx 9) or (x 9)(x 2 + kx + 2) 2nd and 3rd linear factors Attempts to work out the quadratic factor Sight of x 2 and 18 in a quadratic factor or sight of x 2 and 9 in a quadratic factor or sight of x 2 and 2 in a quadratic factor 1, 2 and 9 Alt 1 8 Substitutes a value of x into the Works out first linear factor (x + 1), (x + 2) or (x 9) Substitutes another value into the 2nd and 3rd linear factors 1, 2 and 9 7

Alt 2 8 Substitutes a value of x into the Works out first linear factor (x + 1), (x + 2) or (x 9) Long division of polynomials getting as far as x 2 7x or or x 2 8x x 2 + 3x 2nd and 3rd linear factors Depending on first linear factor 1, 2 and 9 8