Hardy-Weinberg Equilibrium Activity

Similar documents
Hardy-Weinberg Equilibrium Problems

LAB : PAPER PET GENETICS. male (hat) female (hair bow) Skin color green or orange Eyes round or square Nose triangle or oval Teeth pointed or square

GENETIC CROSSES. Monohybrid Crosses

Biology Notes for exam 5 - Population genetics Ch 13, 14, 15

Basic Principles of Forensic Molecular Biology and Genetics. Population Genetics

Variations on a Human Face Lab

Heredity. Sarah crosses a homozygous white flower and a homozygous purple flower. The cross results in all purple flowers.

Evolution (18%) 11 Items Sample Test Prep Questions

2 GENETIC DATA ANALYSIS

Name: Class: Date: ID: A

DNA Determines Your Appearance!

CCR Biology - Chapter 7 Practice Test - Summer 2012

Baby Lab. Class Copy. Introduction

Ex) A tall green pea plant (TTGG) is crossed with a short white pea plant (ttgg). TT or Tt = tall tt = short GG or Gg = green gg = white

Genetics for the Novice

Evolution by Natural Selection 1

Can receive blood from: * I A I A and I A i o Type A Yes No A or AB A or O I B I B and I B i o Type B No Yes B or AB B or O

7 th Grade Life Science Name: Miss Thomas & Mrs. Wilkinson Lab: Superhero Genetics Due Date:

Genetics 1. Defective enzyme that does not make melanin. Very pale skin and hair color (albino)

7A The Origin of Modern Genetics

Genetics with a Smile

Incomplete Dominance and Codominance

A trait is a variation of a particular character (e.g. color, height). Traits are passed from parents to offspring through genes.

Lesson Plan: GENOTYPE AND PHENOTYPE

Bio EOC Topics for Cell Reproduction: Bio EOC Questions for Cell Reproduction:

AP: LAB 8: THE CHI-SQUARE TEST. Probability, Random Chance, and Genetics

Human Blood Types: Codominance and Multiple Alleles. Codominance: both alleles in the heterozygous genotype express themselves fully

Problems 1-6: In tomato fruit, red flesh color is dominant over yellow flesh color, Use R for the Red allele and r for the yellow allele.

Summary Genes and Variation Evolution as Genetic Change. Name Class Date

Mendelian Genetics in Drosophila

A and B are not absolutely linked. They could be far enough apart on the chromosome that they assort independently.

AP BIOLOGY 2010 SCORING GUIDELINES (Form B)

CHROMOSOMES AND INHERITANCE

Heredity - Patterns of Inheritance

LAB : THE CHI-SQUARE TEST. Probability, Random Chance, and Genetics

CCpp X ccpp. CcPp X CcPp. CP Cp cp cp. Purple. White. Purple CcPp. Purple Ccpp White. White. Summary: 9/16 purple, 7/16 white

Mendelian and Non-Mendelian Heredity Grade Ten

The Genetics of Drosophila melanogaster

Evolution, Natural Selection, and Adaptation

Biology Final Exam Study Guide: Semester 2

Genetics and Evolution: An ios Application to Supplement Introductory Courses in. Transmission and Evolutionary Genetics

Chapter 9 Patterns of Inheritance

Population Genetics and Multifactorial Inheritance 2002

Chapter 4 Pedigree Analysis in Human Genetics. Chapter 4 Human Heredity by Michael Cummings 2006 Brooks/Cole-Thomson Learning

Name: 4. A typical phenotypic ratio for a dihybrid cross is a) 9:1 b) 3:4 c) 9:3:3:1 d) 1:2:1:2:1 e) 6:3:3:6

The Developing Person Through the Life Span 8e by Kathleen Stassen Berger

Terms: The following terms are presented in this lesson (shown in bold italics and on PowerPoint Slides 2 and 3):

5 GENETIC LINKAGE AND MAPPING

Cystic Fibrosis Webquest Sarah Follenweider, The English High School 2009 Summer Research Internship Program

The correct answer is c A. Answer a is incorrect. The white-eye gene must be recessive since heterozygous females have red eyes.

BioBoot Camp Genetics

I. Genes found on the same chromosome = linked genes

A Hands-On Exercise To Demonstrate Evolution

Chapter 5. Discrete Probability Distributions

Mendelian inheritance and the

Single Nucleotide Polymorphisms (SNPs)

Chapter 3. Chapter Outline. Chapter Outline 9/11/10. Heredity and Evolu4on

Two copies of each autosomal gene affect phenotype.

Tuesday 14 May 2013 Morning

If you crossed a homozygous, black guinea pig with a white guinea pig, what would be the phenotype(s)

the!sun!to!sugars.!this!is!called!! photosynthesis.!the!byproduct!of!those! Nucleus! sugars!is!our!oxygen.!

Principles of Evolution - Origin of Species

Blood Stains at the Crime Scene Forensic Investigation

The Making of the Fittest: Natural Selection in Humans

edtpa: Task 1 Secondary Science

Continuous and discontinuous variation

Ringneck Doves. A Handbook of Care & Breeding

A Study of Malaria and Sickle Cell Anemia: A Hands-on Mathematical Investigation Student Materials: Reading Assignment

Chapter 4 The role of mutation in evolution

Chromosomes, Mapping, and the Meiosis Inheritance Connection

KENDRIYAVIDYALAYASANGATHAN.CHENNAI REGION CLASS XII COMMONPREBOARD EXAMINATION SUBJECT- BIOLOGY. Section - A

Deterministic computer simulations were performed to evaluate the effect of maternallytransmitted

MCB41: Second Midterm Spring 2009

MAT 155. Key Concept. February 03, S4.1 2_3 Review & Preview; Basic Concepts of Probability. Review. Chapter 4 Probability

Process 3.5. A Pour it down the sink. B Pour it back into its original container. C Dispose of it as directed by his teacher.

Probability & Probability Distributions

Name. Period. Date. Science.. Variation and Selection in the...egyptian Origami Bird (Avis papyrus)..

SeattleSNPs Interactive Tutorial: Web Tools for Site Selection, Linkage Disequilibrium and Haplotype Analysis

Genetics Module B, Anchor 3

Biology 1406 Exam 4 Notes Cell Division and Genetics Ch. 8, 9

ISTEP+: Biology I End-of-Course Assessment Released Items and Scoring Notes

Genetic Algorithm. Based on Darwinian Paradigm. Intrinsically a robust search and optimization mechanism. Conceptual Algorithm

Phenotypes and Genotypes of Single Crosses

Type A carbohydrate molecules on their red blood cells. Type B carbohydrate molecules on their red blood cells

LECTURE 6 Gene Mutation (Chapter )

Using Blood Tests to Identify Babies and Criminals

Cell Growth and Reproduction Module B, Anchor 1

Genetics: Our Past, Present, and Future

240Tutoring Life Science Study Material

Got Lactase? The Co-evolution of Genes and Culture

Genetics Lecture Notes Lectures 1 2

HLA data analysis in anthropology: basic theory and practice

Chapter 13: Meiosis and Sexual Life Cycles

Bio 102 Practice Problems Mendelian Genetics and Extensions

Basics of Marker Assisted Selection

The Evolution of Populations

WEEK #23: Statistics for Spread; Binomial Distribution

Chapter 13: Meiosis and Sexual Life Cycles

Genetics 301 Sample Final Examination Spring 2003

Test Two Study Guide

Transcription:

Name Period Hardy-Weinberg Equilibrium Activity Introduction: In this activity, beans will be used to represent alleles in a population. Black-eyed peas will represent a dominant allele (A). Black beans will represent a recessive allele (a). The Hardy-Weinberg law of equilibrium predicts that allele frequencies will not change in a population if the population meets five conditions. State the five conditions of the Hardy-Weinberg law of equilibrium: 1. 2. 3. 4. 5. The following activity will help you test this law using five different scenarios. In Scenario #1 we will try to meet all the conditions stated above. In each Scenario #2, #3, #4 and #5 we will break one of the conditions of the Hardy-Weinberg law to see how it affects the allele frequency in a population. After each scenario you will be asked to analyze your results to see if the allelic frequency changed. Fill in the blanks below for the following information using your prior knowledge, then perform the activities in each scenario individually or with a partner. Homozygous Dominant Genotype: Heterozygous Genotype: Homozygous Recessive Genotype: Scenario #1: A Population at Genetic Equilibrium 1. Place 50 beans of each color into a cup, these beans represent the alleles available in the gene pool of your population. Shake them well. Keep an empty cup available for step 6. 2. For each generation of offspring born out of this population, you will need to fill in the chart below. The information for Generation 1 is already filled into the chart because the scenario begins with a population of heterozygotes (Aa) who have each contributed a black-eyed peas (A) and a black bean (a) to the population in equal amounts - 50% or 0.5 of the beans represent the black-eyed peas allele and 50% or 0.5 beans represent the black bean allele at the beginning of this scenario. 1

a. What do you think will happen to the frequency of the dominant blackeyed peas alleles (A) over the course of five generations? Support your answer with logic. b. What do you think will happen to the frequency of the recessive black bean alleles (a) over the course of five generations? Support your answer with logic. 3. Remove pairs of beans from the cup to represent an individual the two beans represent the two alleles for a single trait. Make 25 individuals by drawing pairs of beans from the cup until a total of 50 beans have been pulled and laid out on your desk in pairs. 4. Return unused beans (those still in the cup) to the stockpile because they did not survive. 5. Fill in the chart below with the allele frequency information for the 25 individuals laid out on your desk that you have made. This is generation 2 on the chart below. Calculate each allele frequency for p and q by counting the total number of each color bean out of 50 beans. 6. The total number of each color bean survived. The survivors do what they do best and that is reproduce. Return that number of each color bean to the empty cup with their offspring. (Ex. If you had 26 black-eyed peas on your desk and 24 black beans on your desk, add another 26 black-eyed peas and 24 black beans from the stockpile cup to make a total of 52 black-eyed peas and 48 black beans in the empty cup). The beans placed in the empty cup will now be the gene pool of your population for the next round. The cup should have 100 beans at the beginning of each generation. 7. Repeat steps 3-6 three more times until you have completed 5 generations, filling in the chart at the appropriate place each time. Generation 1 0 25 0.5.5 2

#2: Selection Against Homozygous Recessive Individuals 1. Repeat steps 1-7 from Scenario #1 above, but during this scenario, if two black beans are drawn to make an individual, return them to the gene pool and try again. 2. This scenario represents what would happen to the frequency of an allele if the homozygous recessive genotype resulted in the death of an individual prior to reproduction. In this case the homozygous recessive individuals will die and so they do not go on to be part of the gene pool for the next generation. a. What do you think will happen to the frequency of the dominant blackeyed pea alleles (A) over the course of five generations? Support your answer with logic. b. What do you think will happen to the frequency of the recessive black bean alleles (a) over the course of five generations? Support your answer with logic. Complete chart below after each generation of individuals are drawn. Generation 1 0 25 0.5.5 Scenario #3: Selection Against Homozygous Dominant Individuals 1. Repeat steps 1-7 from Scenario #1 above, but during this scenario, if two black-eyed peas are drawn to make an individual, return them to the gene pool and try again. 2. This scenario represents what would happen to the frequency of an allele if the homozygous dominant genotype resulted in the death of an individual prior to reproduction. In this case the homozygous dominant individuals will die and so they do not go on to be part of the gene pool for the next generation. 3

a. What do you think will happen to the frequency of the dominant blackeyed pea alleles (A) over the course of five generations? Support your answer with logic. b. What do you think will happen to the frequency of the recessive black bean alleles (a) over the course of five generations? Support your answer with logic. Complete chart below after each generation of individuals are drawn. Generation 1 0 25 0.5.5 Scenario #4: Heterozygote Advantage in a Population 1. Repeat steps 1-7 from Scenario #1 above, but during this scenario, if two black beans are drawn to make an individual, return them to the gene pool and draw again. 2. If two black-eyed peas are drawn, flip a coin. If it is heads, return the beans to the gene pool. If tails, keep the set and record it as an individual that was added to the gene pool of the next generation. 3. This scenario represents what would happen to the frequency of an allele if the presence of the homozygous recessive genotype resulted in death of an individual and the homozygous dominant genotype resulted in a possible death. In this case the homozygous recessive individuals will die and so they do not go on to be part of the gene pool for the next generation, while some of the homozygous dominant individuals die and others go on to become part of the gene pool for the next generation. a. What do you think will happen to the frequency of the dominant blackeyed peas alleles (A) over the course of five generations? Support your answer with logic. 4

b. What do you think will happen to the frequency of the recessive black bean alleles (a) over the course of five generations? Support your answer with logic. Complete chart below after each generation of individuals are drawn. Generation 1 0 25 0.5.5 Scenario #5: Genetic Drift in a Population 1. Set up the cup o beans as in step 1 (Place 50 beans of each color into a cup, these beans represent the alleles available in the gene pool of your population). Shake them well. 2. Before drawing any pairs, split the cup into three sub-populations without paying attention to the ratio of black-eyed peas to black beans in each cup make one cup with 30 beans, another cup with 30 beans and the last cup with 40 beans. 3. For each generation of offspring born out of this population, you will need to fill in the chart below. The information for Generation 1 represents a parent population of heterozygotes (Aa) who have each contributed a black-eyed peas (A) and a black bean (a) to the population in equal amounts 50% or 0.5 of the beans represent the black-eyed pea allele and 50% or 0.5 beans represent the black bean allele at the beginning of this scenario. However, this population has been fragmented into smaller populations prior to. a. What do you think will happen to the frequency of the dominant black-eyed pea alleles (A) over the course of five generations in this sub-population? Support your answer with logic. b. What do you think will happen to the frequency of the recessive black bean alleles (a) over the course of five generations in this sub-population? Support your answer with logic. 5

Use 30 beans to make 10 individuals for five generations. Generation 1 0 10 0.5.5 Use 30 beans to make 10 individuals for five generations. Generation 1 0 10 0.5.5 Use 40 beans to make 10 individuals for five generations. Generation 1 0 10 0.5.5 Reflection Questions: Scenario #1: 1. Explain why you got the allele frequency results that were recorded. 2. What do you predict the frequency of p and q would have been if you continued the simulation for another ten generations? Explain your reasoning. 6

3. Explain which Hardy-Weinberg condition was broken in this scenario. You must explain your answer to receive credit. 4. Can you think of a population that would represent all the conditions of the Hardy-Weinberg law in real life? Justify your response. Scenario #2: 5. Explain why you got the allele frequency results that were recorded. 6. What do you predict the frequency of p and q would have been if you continued the simulation for another ten generations? Explain your reasoning. 7. Explain which Hardy-Weinberg condition (in addition to the condition named in Reflection Question #3) was broken in this scenario. You must explain your answer to receive credit. 8. This scenario represents a real life situation where the homozygous recessive genotype results in an individual that does not live to reproductive age. Name one real life situation/disease where this scenario is true. 9. What would have to happen in order for a deleterious recessive allele to be completely eliminated from the gene pool? Scenario #3: 10. Explain why you got the allele frequency results that were recorded. 7

11. What do you predict the frequency of p and q would have been if you continued the simulation for another ten generations? Explain your reasoning. 12. Explain which Hardy-Weinberg condition (in addition to the condition named in Reflection Question #3) was broken in this scenario. You must explain your answer to receive credit. 13. This scenario represents a real life situation where the homozygous dominant genotype results in an individual that does not live to reproductive age. Name one real life situation/disease where this scenario is true. 14. What would have to happen in order for a deleterious dominant allele to be completely eliminated from the gene pool? Scenario #4: 15. Explain why you got the allele frequency results that were recorded. 16. What do you predict the frequency of p and q would have been if you continued the simulation for another ten generations? Explain your reasoning. 17. ]Explain which Hardy-Weinberg condition (in addition to the condition named in Reflection Question #3) was broken in this scenario. You must explain your answer to receive credit. 18. This scenario represents a real life situation where the homozygous recessive genotype results in an individual that does not live to reproductive age and an individual with a homozygous dominant genotype often does not live to reproductive age. Name one real life situation/disease where this scenario is true. 8

19. Explain how genetic variation is maintained in a population despite the lethal result of certain genotypes. Scenario #5: 20. Explain why you got the allele frequency results that were recorded. 21. What do you predict the frequency of p and q would have been if you continued the simulation for another ten generations? Explain your reasoning. 22. Explain which Hardy-Weinberg condition was broken in this scenario. You must explain your answer to receive credit. 23. This scenario represents a real life situation where the gene pool is dramatically reduced in size. Name three real life situations where this scenario is true. a. b. c. 9