POPULATION GENETICS AND THE HARDY-WEINBERG LAW

Similar documents
Hardy-Weinberg Equilibrium Problems

Genetics 1. Defective enzyme that does not make melanin. Very pale skin and hair color (albino)

Chapter 4 Pedigree Analysis in Human Genetics. Chapter 4 Human Heredity by Michael Cummings 2006 Brooks/Cole-Thomson Learning

AP BIOLOGY 2010 SCORING GUIDELINES (Form B)

Biology Notes for exam 5 - Population genetics Ch 13, 14, 15

Heredity. Sarah crosses a homozygous white flower and a homozygous purple flower. The cross results in all purple flowers.

The Making of the Fittest: Natural Selection in Humans

Chromosomes, Mapping, and the Meiosis Inheritance Connection

Bio EOC Topics for Cell Reproduction: Bio EOC Questions for Cell Reproduction:

Heredity - Patterns of Inheritance

Name: 4. A typical phenotypic ratio for a dihybrid cross is a) 9:1 b) 3:4 c) 9:3:3:1 d) 1:2:1:2:1 e) 6:3:3:6

LAB : THE CHI-SQUARE TEST. Probability, Random Chance, and Genetics

Genetics Lecture Notes Lectures 1 2

Continuous and discontinuous variation

Basic Principles of Forensic Molecular Biology and Genetics. Population Genetics

Cystic Fibrosis Webquest Sarah Follenweider, The English High School 2009 Summer Research Internship Program

LAB : PAPER PET GENETICS. male (hat) female (hair bow) Skin color green or orange Eyes round or square Nose triangle or oval Teeth pointed or square

DNA Determines Your Appearance!

Mendelian inheritance and the

A Study of Malaria and Sickle Cell Anemia: A Hands-on Mathematical Investigation Student Materials: Reading Assignment

CCR Biology - Chapter 7 Practice Test - Summer 2012

Biology 1406 Exam 4 Notes Cell Division and Genetics Ch. 8, 9

Problems 1-6: In tomato fruit, red flesh color is dominant over yellow flesh color, Use R for the Red allele and r for the yellow allele.

Evolution (18%) 11 Items Sample Test Prep Questions

Tuesday 14 May 2013 Morning

Population Genetics and Multifactorial Inheritance 2002

AP: LAB 8: THE CHI-SQUARE TEST. Probability, Random Chance, and Genetics

Can receive blood from: * I A I A and I A i o Type A Yes No A or AB A or O I B I B and I B i o Type B No Yes B or AB B or O

Mendelian and Non-Mendelian Heredity Grade Ten

Chapter 9 Patterns of Inheritance

Mendelian Genetics in Drosophila

A trait is a variation of a particular character (e.g. color, height). Traits are passed from parents to offspring through genes.

PRACTICE PROBLEMS - PEDIGREES AND PROBABILITIES

Genetics for the Novice

Summary Genes and Variation Evolution as Genetic Change. Name Class Date

GENETIC CROSSES. Monohybrid Crosses

Biology Final Exam Study Guide: Semester 2

7 POPULATION GENETICS

BioBoot Camp Genetics

CHROMOSOMES AND INHERITANCE

Genetic Mutations. Indicator 4.8: Compare the consequences of mutations in body cells with those in gametes.

Human Blood Types: Codominance and Multiple Alleles. Codominance: both alleles in the heterozygous genotype express themselves fully

MCB41: Second Midterm Spring 2009

2 GENETIC DATA ANALYSIS

Basics of Marker Assisted Selection

The correct answer is c A. Answer a is incorrect. The white-eye gene must be recessive since heterozygous females have red eyes.

Incomplete Dominance and Codominance

Answer Key Problem Set 5

Process 3.5. A Pour it down the sink. B Pour it back into its original container. C Dispose of it as directed by his teacher.

Name: Class: Date: ID: A

AP Statistics 7!3! 6!

A and B are not absolutely linked. They could be far enough apart on the chromosome that they assort independently.

Variations on a Human Face Lab

B2 5 Inheritrance Genetic Crosses

Baby Lab. Class Copy. Introduction

Patient Information. for Childhood

12.1 The Role of DNA in Heredity

7 th Grade Life Science Name: Miss Thomas & Mrs. Wilkinson Lab: Superhero Genetics Due Date:

I. Genes found on the same chromosome = linked genes

GENETICS OF HUMAN BLOOD TYPE

This fact sheet describes how genes affect our health when they follow a well understood pattern of genetic inheritance known as autosomal recessive.

Evolution by Natural Selection 1

Blood Stains at the Crime Scene Forensic Investigation

Genetic Technology. Name: Class: Date: Multiple Choice Identify the choice that best completes the statement or answers the question.

Bio 102 Practice Problems Mendelian Genetics: Beyond Pea Plants

Genetics Review for USMLE (Part 2)

Why are some drugs only available on prescription? Depressants. Pain killers. Stimulants. Performance enhancers. Hallucinogens

The Genetics of Drosophila melanogaster

Deterministic computer simulations were performed to evaluate the effect of maternallytransmitted

Worksheet: The theory of natural selection

Exploring contact patterns between two subpopulations

DRAGON GENETICS LAB -- Principles of Mendelian Genetics

Laboratory Procedure Manual. Rh Phenotyping

Introduction to Physical Anthropology - Study Guide - Focus Topics

Genetics and Evolution: An ios Application to Supplement Introductory Courses in. Transmission and Evolutionary Genetics

Chapter 3. Chapter Outline. Chapter Outline 9/11/10. Heredity and Evolu4on

Two copies of each autosomal gene affect phenotype.

Genetics with a Smile

The Developing Person Through the Life Span 8e by Kathleen Stassen Berger

HLA data analysis in anthropology: basic theory and practice

Genetics 301 Sample Final Examination Spring 2003

Scheme of work Cambridge IGCSE Biology (0610)

Ex) A tall green pea plant (TTGG) is crossed with a short white pea plant (ttgg). TT or Tt = tall tt = short GG or Gg = green gg = white

CHAPTER 15 THE CHROMOSOMAL BASIS OF INHERITANCE. Section B: Sex Chromosomes

5 GENETIC LINKAGE AND MAPPING

Gene Mapping Techniques

Evolution, Natural Selection, and Adaptation

Lecture 10 Friday, March 20, 2009

SICKLE CELL ANEMIA & THE HEMOGLOBIN GENE TEACHER S GUIDE

7A The Origin of Modern Genetics

Mechanisms of Evolution

Chapter 4 The role of mutation in evolution

About The Causes of Hearing Loss

Saffiyah Y. Manboard Biology Instructor Seagull Alternative High School

Basic Concepts Recombinant DNA Use with Chapter 13, Section 13.2

Genetics Module B, Anchor 3

Popstats Unplugged. 14 th International Symposium on Human Identification. John V. Planz, Ph.D. UNT Health Science Center at Fort Worth

TEXAS A&M PLANT BREEDING BULLETIN

If you crossed a homozygous, black guinea pig with a white guinea pig, what would be the phenotype(s)

17. A testcross A.is used to determine if an organism that is displaying a recessive trait is heterozygous or homozygous for that trait. B.

Transcription:

POPULATION GENETICS AND THE HARDY-WEINBERG LAW The Hardy-Weinberg formulas allow scientists to determine whether evolution has occurred. Any changes in the gene frequencies in the population over time can be detected. The law essentially states that if no evolution is occurring, then an equilibrium of allele frequencies will remain in effect in each succeeding generation of sexually reproducing individuals. In order for equilibrium to remain in effect (i.e. that no evolution is occurring) then the following five conditions must be met: 1. No mutations must occur so that new alleles do not enter the population. 2. No gene flow can occur (i.e. no migration of individuals into, or out of, the population). 3. Random mating must occur (i.e. individuals must pair by chance) 4. The population must be large so that no genetic drift (random chance) can cause the allele frequencies to change. 5. No selection can occur so that certain alleles are not selected for, or against. Obviously, the Hardy-Weinberg equilibrium cannot exist in real life. Some or all of these types of forces all act on living populations at various times and evolution at some level occurs in all living organisms. The Hardy-Weinberg formulas allow us to detect some allele frequencies that change from generation to generation, thus allowing a simplified method of determining that evolution is occurring. There are two formulas that must be memorized: p 2 + 2pq + q 2 = 1 and p + q = 1 p = frequency of the dominant allele in the population q = frequency of the recessive allele in the population p 2 = percentage of homozygous dominant individuals q 2 = percentage of homozygous recessive individuals Page 1 of 5

2pq = percentage of heterozygous individuals Individuals that have aptitude for math find that working with the above formulas is ridiculously easy. However, for individuals who are unfamiliar with algebra, it takes some practice working problems before you get the hang of it. Below I have provided a series of practice problems that you may wish to try out. Note that I have rounded off some of the numbers in some problems to the second decimal place. PROBLEM #1 You have sampled a population in which you know that the percentage of the homozygous recessive genotype (aa) is 36%. Using that 36%, calculate the following: A. The frequency of the "aa" genotype. B. The frequency of the "a" allele. C. The frequency of the "A" allele. D. The frequencies of the genotypes "AA" and "Aa." E. The frequencies of the two possible phenotypes if "A" is completely dominant over "a." PROBLEM #2. Sickle-cell anemia is an interesting genetic disease. Normal homozygous individuals (SS) have normal blood cells that are easily infected with the malarial parasite. Thus, many of these individuals become very ill from the parasite and many die. Individuals homozygous for the sickle-cell trait (ss) have red blood cells that readily collapse when deoxygenated. Although malaria cannot grow in these red blood cells, individuals often die because of the genetic defect. However, individuals with the heterozygous condition (Ss) have some sickling of red blood cells, but generally not enough to cause mortality. In addition, malaria cannot survive well within these "partially defective" red blood cells. Thus, heterozygotes tend to survive better than either of the homozygous conditions. If 9% of an African population is born with a severe form of sickle-cell anemia (ss), what percentage of the population will be more resistant to malaria because they are heterozygous (Ss) for the sickle-cell gene? Page 2 of 5

PROBLEM #3. There are 100 students in a class. Ninety-six did well in the course whereas four blew it totally and received a grade of F. Sorry. In the highly unlikely event that these traits are genetic rather than environmental, if these traits involve dominant and recessive alleles, and if the four (4%) represent the frequency of the homozygous recessive condition, please calculate the following: A. The frequency of the recessive allele. B. The frequency of the dominant allele. C. The frequency of heterozygous individuals. PROBLEM #4. Within a population of butterflies, the color brown (B) is dominant over the color white (b). And, 40% of all butterflies are white. Given this simple information, which is something that is very likely to be on an exam, calculate the following: A. The percentage of butterflies in the population that are heterozygous. B. The frequency of homozygous dominant individuals. PROBLEM #5. A rather large population of Biology instructors have 396 red-sided individuals and 557 tan-sided individuals. Assume that red is totally recessive. Please calculate the following: A. The allele frequencies of each allele. B. The expected genotype frequencies. C. The number of heterozygous individuals that you would predict to be in this population. D. The expected phenotype frequencies. E. Conditions happen to be really good this year for breeding and next year there are 1,245 young "potential" Biology instructors. Assuming that all of the Hardy-Weinberg conditions are met, how many of these would you expect to be red-sided and how many tan-sided? PROBLEM #6. A very large population of randomly-mating laboratory mice Page 3 of 5

contains 35% white mice. White coloring is caused by the double recessive genotype, "aa". Calculate allelic and genotypic frequencies for this population. PROBLEM #7. After graduation, you and 19 of your closest friends (lets say 10 males and 10 females) charter a plane to go on a round-the-world tour. Unfortunately, you all crash land (safely) on a deserted island. No one finds you and you start a new population totally isolated from the rest of the world. Two of your friends carry (i.e. are heterozygous for) the recessive cystic fibrosis allele (c). Assuming that the frequency of this allele does not change as the population grows, what will be the incidence of cystic fibrosis on your island? PROBLEM #8. You sample 1,000 individuals from a large population for the MN blood group, which can easily be measured since co-dominance is involved (i.e., you can detect the heterozygotes). They are typed accordingly: BLOOD TYPE GENOTYPE NUMBER OF INDIVIDUALS RESULTING FREQUENCY M MM 490 0.49 MN MN 420 0.42 N NN 90 0.09 Using the data provide above, calculate the following: A. The frequency of each allele in the population. B. Supposing the matings are random, the frequencies of the matings. C. The probability of each genotype resulting from each potential cross. PROBLEM #9. Cystic fibrosis is a recessive condition that affects about 1 in 2,500 babies in the Caucasian population of the United States. Please calculate the following: A. The frequency of the recessive allele in the population. Page 4 of 5

B. The frequency of the dominant allele in the population. C. The percentage of heterozygous individuals (carriers) in the population. PROBLEM #10. In a given population, only the "A" and "B" alleles are present in the ABO system; there are no individuals with type "O" blood or with O alleles in this particular population. If 200 people have type A blood, 75 have type AB blood, and 25 have type B blood, what are the allelic frequencies of this population (i.e., what are p and q)? PROBLEM #11. The ability to taste PTC is due to a single dominate allele "T". You sampled 215 individuals in biology, and determined that 150 could detect the bitter taste of PTC and 65 could not. Calculate all of the potential frequencies. ANSWERS Page 5 of 5