USEFUL DEFINITIONS. A substance which cannot be split into anything simpler by chemical means.

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Formulae and equations 1 USEFUL DEFINITIONS Element Atom A substance which cannot be split into anything simpler by chemical means. The smallest part of an element that can take part in a chemical reaction. Molecule The smallest particle of a compound (a combination of two or more elements). It is also the name given to the smallest part of those elements which do not exist as atoms in the free state i.e. hydrogen H 2, oxygen O 2, nitrogen N 2, fluorine F 2, chlorine Cl 2, bromine Br 2 and iodine I 2. N.B. ionic compounds (e.g. sodium chloride) DO NOT exist as molecules. Ion The name given to any electrically charged atom or molecule. positively charged ions are known as cations negatively charged ions are known as anions Symbol Formula Like charges repel but unlike (opposite) charges attract. If the sum of all the positive charges is equal and opposite to all the negative charges then the species will be neutral (no overall charge). A symbol represents one atom, or one mole, of an element. A formula represents one molecule of a compound, or the simplest ratio of the ions present. As with symbols, a formula represents a single particle or one mole of particles. The number of atoms or groups of atoms in a formula is given by putting a small number just below and behind the symbol(s). As the appearance of a symbol indicates one atom is present, a 1 isn t written (you put NaCl not Na 1 Cl 1 ). In some formulae, brackets are used to avoid ambiguity. Aluminium sulphate has the formula Al 2 (SO 4 ) 3 to show that there are two Al s to every three SO 4 s. Without the brackets it would appear as though there were forty three O s i.e. Al 2 SO 43. Valency A numerical measure of the combining power of an atom / ion. Historically, it was the number of hydrogen atoms which will combine with one atom, or group of atoms. It is also the number of positive (+) or negative (-) charges on an ion. A list of common valencies appears below to help you construct formulae. Atom Valency Compound C 4 CH 4 N 3 NH 3 O 2 H 2 O Cl 1 HCl

2 Formulae and equations VALENCY TABLE POSITIVE IONS NEGATIVE IONS hydrogen H + chloride Cl sodium Na + bromide Br potassium K + iodide I 1 lithium Li + hydroxide OH rubidium Rb + nitrate NO 3 caesium Cs + nitrite NO 2 copper(i) Cu + hydrogencarbonate HCO 3 silver(i) Ag + hydrogensulphate HSO 4 ammonium + NH 4 calcium Ca 2+ sulphate 2- SO 4 barium Ba 2+ sulphite 2- SO 3 magnesium Mg 2+ sulphide S 2-2 zinc Zn 2+ oxide O 2- iron(ii) Fe 2+ carbonate 2- CO 3 cobalt Co 2+ copper(ii) Cu 2+ manganese(ii) Mn 2+ 3 aluminium Al 3+ phosphate 3- PO 4 iron(iii) Fe 3+ ions in bold contain more than one element Many elements (e.g. iron) have more than one valency. To avoid ambiguity, a number appears in brackets after the name e.g. iron(iii); this is the oxidation number and can be used to give you the valency. Q. Name the following Sn 2+ Sn 4+ Sb 3+ Give the symbol of lead(iv) scandium(iii) What do you notice about the valency of elements in... Group I Group II Group VII

Formulae and equations 3 CONSTRUCTION OF FORMULAE Method The table lists a selection of valencies of some common ions and atoms. It is not complete but there are enough for you to appreciate the basic principles of formulae construction. Several methods are available, choose the one which suits you, or the situation, best. Magnesium chloride is used as an example. 1. Balance the number of ionic charges. All compounds are electrically neutral so the number of positive and negative charges must balance. Magnesium ions are Mg 2+, chloride ions Cl. You need two Cl ions to balance the 2+ ion of magnesium. Therefore the formula will be MgCl 2. 2. Use hooks. The valency is the number of hooks an element or group has. All hooks must be joined up so there are no spares. Magnesium has two hooks, Mg, chlorine has one, Cl. Join up all hooks ; this gives you Cl Mg Cl. The formula is thus MgCl 2. 3. Switching the valency numbers if two valencies are different. Don t write in a 1 and cancel any combination of numbers which can be reduced (e.g. Mg 2 O 2 will become MgO). The valency of magnesium is two so multiply chlorine by two and the valency of chlorine is one, so multiply magnesium by one to give Mg 1 Cl 2 ; the formula will be MgCl 2. example: aluminium sulphate the valency of aluminium is 3 and that of sulphate is 2 they will combine in the ratio of 2 aluminiums to 3 sulphates [i.e. 2x3 = 3x2] the formula will be Al 2 (SO 4 ) 3. [Notice the use of brackets] It is useful to learn some formulae... Acids hydrochloric acid HCl nitric acid HNO 3 sulphuric acid H 2 SO 4 ethanoic acid CH 3 COOH Gases ammonia NH 3 carbon dioxide CO 2 carbon monoxide CO methane CH 4 sulphur dioxide SO 2 Equations show the formulae of the reactants and the products can show in which state the substances exist show the relationship between the numbers of each substance involved this is known as the STOICHIOMETRY of the reaction

4 Formulae and equations BALANCING EQUATIONS 1 Work out what has reacted and what has been formed. A word equation can help. 2 Get the correct formula for each species. Include the state symbols if necessary. Once you have obtained the correct formula of a species you must not change it to help balance an equation. 3 Having written out the initial equation, check to see if it is balanced. An equation balances if the same number of each type of atom appears on either side of the arrow. 4 Place large numbers in front of any formula to indicate if more than one of it is required. This multiplies everything in the formula immediately behind it. Continue until the equation balances. 5 Finally, check the equation to see that you have balanced it correctly. Worked example Step 1 sodium + water > sodium hydroxide + hydrogen Step 2 Na(s) + H 2 O(l) > NaOH(aq) + H 2 (g) Step 3 Count up the atoms : LHS... 1 x Na, 2 x H, 1 x O RHS... 1 x Na, 3 x H, 1 x O. The equation doesn t balance; an extra H is needed on the LHS. However we must not change any formulae. One can only get extra H s by having two waters; multiply H 2 O by two. Step 4 Na(s) + 2 H 2 O(l) > NaOH(aq) + H 2 (g) This doesn t solve the problem as we now have too many O s (2) and H s (4) on the LHS; multiplying the NaOH by two will solve this problem. Na(s) + 2 H 2 O(l) > 2 NaOH(aq) + H 2 (g) However, it creates yet another problem because it has introduced an extra Na on the RHS; multiply the Na on the LHS by two. 2 Na(s) + 2 H 2 O(l) > 2 NaOH(aq) + H 2 (g) Step 5 Check the equation; it balances. As you can see it can take time but with a little effort a balanced equation can be achieved.

Formulae and equations 5 FORMULAE AND EQUATIONS - Test questions Q.1 Write out the correct formula for each of the following compounds. a) sodium chloride b) magnesium sulphate c) calcium oxide d) calcium chloride e) copper(ii) nitrate f) potassium sulphate g) manganese(iv) oxide h) zinc carbonate i) aluminium oxide j) aluminium sulphate k) aluminium bromide l) calcium hydroxide Q.2 Write out the correct formulae under the names in these word equations. Do not attempt to balance the equations at this stage. a) hydrogen + oxygen > water b) zinc + sulphuric acid > zinc sulphate + hydrogen c) copper(ii) oxide + sulphuric acid > copper(ii) sulphate + water d) nitrogen + hydrogen > ammonia e) magnesium + oxygen > magnesium oxide Q.3 How many atoms of each type are in the following? a) H 2 O H = O = b) H 2 SO 4 H = O = S = c) (NH 4 ) 2 SO 4 H = N = O = S = d) CuSO 4.5H 2 O H = O = S = Cu = e) 2 NaOH H = O = Na = f) 3 Ca(OH) 2 H = O = Ca = g) 2 Na 2 HPO 4 H = O = Na = P = h) 2 NH 4 Al(SO 4 ) 2.12H 2 O H = N = O = Al = S =

6 Formulae and equations Q.4 Are the equations balanced? a) 2H 2 + O 2 > 2H 2 O Y / N b) CH 4 + O 2 > CO 2 + H 2 O Y / N c) H 2 + Cl 2 > 2HCl Y / N d) NaOH + H 2 SO 4 > Na 2 SO 4 + H 2 O Y / N e) Ag 2 CO 3 + 2HNO 3 > 2AgNO 3 + CO 2 + H 2 O Y / N Q.5 Balance the following equations. a) Mg + HCl > MgCl 2 + H 2 b) Na + O 2 > Na 2 O c) Ca(OH) 2 + HNO 3 > Ca(NO 3 ) 2 + H 2 O d) Ca + H 2 O > Ca(OH) 2 + H 2 e) NaNO 3 > NaNO 2 + O 2 f) Mg(NO 3 ) 2 > MgO + NO 2 + O 2 g) Cu + H 2 SO 4 > CuSO 4 + SO 2 + H 2 O h) Al + O 2 > Al 2 O 3 i) Fe + Cl 2 > FeCl 3 j) C 2 H 6 + O 2 > CO 2 + H 2 O k) Al 2 O 3 + NaOH + H 2 O > NaAl(OH) 4 l) Cu + HNO 3 > Cu(NO 3 ) 2 + H 2 O + NO m) KOH + F 2 > KF + F 2 O + H 2 O n) KOH + Cl 2 > KCl + KClO 3 + H 2 O

Formulae and equations 7 ANSWERS TO TEST QUESTIONS Q.1 Write out the correct formula for each of the following compounds. a) NaCl b) MgSO 4 c) CaO d) CaCl 2 e) Cu(NO 3 ) 2 f) K 2 SO 4 g) MnO 2 h) ZnCO 3 i) Al 2 O 3 j) Al 2 (SO 4 ) 3 k) AlBr 3 l) Ca(OH) 2 Q.2 a) hydrogen + oxygen > water H 2 O 2 H 2 O b) zinc + sulphuric acid > zinc sulphate + hydrogen Zn H 2 SO 4 ZnSO 4 H 2 c) copper(ii) oxide + sulphuric acid > copper(ii) sulphate + water CuO H 2 SO 4 CuSO 4 H 2 O d) nitrogen + hydrogen > ammonia N 2 H 2 NH 3 e) magnesium + oxygen > magnesium oxide Mg O 2 MgO Q.3 How many atoms of each type are in the following? a) H 2 O H = 2 O = 1 b) H 2 SO 4 H = 2 O = 4 S = 1 c) (NH 4 ) 2 SO 4 H = 8 N = 2 O = 4 S = 1 d) CuSO 4.5H 2 O H = 14 O = 9 S = 1 Cu = 1 e) 2 NaOH H = 2 O = 2 Na = 2 f) 3 Ca(OH) 2 H = 6 O = 6 Ca = 3 g) 2 Na 2 HPO 4 H = 2 O = 8 Na = 4 P = 2 h) 2 NH 4 Al(SO 4 ) 2.12H 2 O H = 56 N = 2 O = 40 Al = 2 S = 4 Q.4 Are the equations balanced? a) 2H 2 + O 2 > 2H 2 O Y b) CH 4 + O 2 > CO 2 + H 2 O N c) H 2 + Cl 2 > 2HCl Y d) NaOH + H 2 SO 4 > Na 2 SO 4 + H 2 O N e) Ag 2 CO 3 + 2HNO 3 > 2AgNO 3 + CO 2 + H 2 O Y Q.5 Balance the following equations. a) Mg + 2HCl > MgCl 2 + H 2 b) 4Na + O 2 > 2Na 2 O c) Ca(OH) 2 + 2HNO 3 > Ca(NO 3 ) 2 + 2H 2 O d) Ca + 2H 2 O > Ca(OH) 2 + H 2 e) 2NaNO 3 > 2NaNO 2 + O 2 f) 2Mg(NO 3 ) 2 > 2MgO + 4NO 2 + O 2 g) Cu + 2H 2 SO 4 > CuSO 4 + SO 2 + 2H 2 O h) 4Al + 3O 2 > 2Al 2 O 3 i) 2Fe + 3Cl 2 > 2FeCl 3 j) 2C 2 H 6 + 7O 2 > 4CO 2 + 6H 2 O k) Al 2 O 3 + 2NaOH + 3H 2 O > 2NaAl(OH) 4 l) 3Cu + 8HNO 3 > 3Cu(NO 3 ) 2 + 4H 2 O + 2NO m) 2KOH + 2F 2 > 2KF + F 2 O + H 2 O n) 6KOH + 3Cl 2 > 5KCl + KClO 3 + 3H 2 O