SENIOR CERTIFICATE EXAMINATION

Similar documents
Biology Final Exam Study Guide: Semester 2

Heredity. Sarah crosses a homozygous white flower and a homozygous purple flower. The cross results in all purple flowers.

Heredity - Patterns of Inheritance

Genetics Module B, Anchor 3

12.1 The Role of DNA in Heredity

CCR Biology - Chapter 7 Practice Test - Summer 2012

NATIONAL SENIOR CERTIFICATE GRADE 11

CHROMOSOMES AND INHERITANCE

Name: 4. A typical phenotypic ratio for a dihybrid cross is a) 9:1 b) 3:4 c) 9:3:3:1 d) 1:2:1:2:1 e) 6:3:3:6

Name: Class: Date: ID: A

Terms: The following terms are presented in this lesson (shown in bold italics and on PowerPoint Slides 2 and 3):

Problems 1-6: In tomato fruit, red flesh color is dominant over yellow flesh color, Use R for the Red allele and r for the yellow allele.

Bio EOC Topics for Cell Reproduction: Bio EOC Questions for Cell Reproduction:

7A The Origin of Modern Genetics

A trait is a variation of a particular character (e.g. color, height). Traits are passed from parents to offspring through genes.

NATIONAL SENIOR CERTIFICATE GRADE 12

BioBoot Camp Genetics

RNA and Protein Synthesis

B2 5 Inheritrance Genetic Crosses

Biology Notes for exam 5 - Population genetics Ch 13, 14, 15

MCAS Biology. Review Packet

DNA Replication & Protein Synthesis. This isn t a baaaaaaaddd chapter!!!

Introduction to Physical Anthropology - Study Guide - Focus Topics

Transcription and Translation of DNA

Summary Genes and Variation Evolution as Genetic Change. Name Class Date

Chapter 9 Patterns of Inheritance

Human Blood Types: Codominance and Multiple Alleles. Codominance: both alleles in the heterozygous genotype express themselves fully

Mendelian and Non-Mendelian Heredity Grade Ten

Cell Division and Mitosis DNA. Sexual Reproduction and Meiosis. 2. Meiosis occurs in the reproductive organs, producing four haploid sex cells.

Chapter 13: Meiosis and Sexual Life Cycles

Name Date Period. 2. When a molecule of double-stranded DNA undergoes replication, it results in

DNA Determines Your Appearance!

Test Two Study Guide

Tuesday 14 May 2013 Morning

The Making of the Fittest: Natural Selection in Humans

GENETIC CROSSES. Monohybrid Crosses

NATIONAL SENIOR CERTIFICATE GRADE 11

The correct answer is c A. Answer a is incorrect. The white-eye gene must be recessive since heterozygous females have red eyes.

Multiple Choice Write the letter that best answers the question or completes the statement on the line provided.

AP: LAB 8: THE CHI-SQUARE TEST. Probability, Random Chance, and Genetics

PRACTICE TEST QUESTIONS

LAB : PAPER PET GENETICS. male (hat) female (hair bow) Skin color green or orange Eyes round or square Nose triangle or oval Teeth pointed or square

Genetics Test Biology I

Thymine = orange Adenine = dark green Guanine = purple Cytosine = yellow Uracil = brown

Ms. Campbell Protein Synthesis Practice Questions Regents L.E.

Chapter 13: Meiosis and Sexual Life Cycles

AS Biology Unit 2 Key Terms and Definitions. Make sure you use these terms when answering exam questions!

Genetics for the Novice

Genetics 1. Defective enzyme that does not make melanin. Very pale skin and hair color (albino)

NATIONAL SENIOR CERTIFICATE GRADE 12

Biology 1406 Exam 4 Notes Cell Division and Genetics Ch. 8, 9

Genetics Part 1: Inheritance of Traits

Introduction. What is Ecological Genetics?

The Developing Person Through the Life Span 8e by Kathleen Stassen Berger

Incomplete Dominance and Codominance

Biology Behind the Crime Scene Week 4: Lab #4 Genetics Exercise (Meiosis) and RFLP Analysis of DNA

BIOLOGY HIGHER LEVEL

Answer: 2. Uracil. Answer: 2. hydrogen bonds. Adenine, Cytosine and Guanine are found in both RNA and DNA.

Mendelian Genetics in Drosophila

Worksheet: The theory of natural selection

Genetic Mutations. Indicator 4.8: Compare the consequences of mutations in body cells with those in gametes.

BioSci 2200 General Genetics Problem Set 1 Answer Key Introduction and Mitosis/ Meiosis

CHROMOSOME STRUCTURE CHROMOSOME NUMBERS

Genetic information (DNA) determines structure of proteins DNA RNA proteins cell structure enzymes control cell chemistry ( metabolism )

Forensic DNA Testing Terminology

Outline 22: Hominid Fossil Record

somatic cell egg genotype gamete polar body phenotype homologous chromosome trait dominant autosome genetics recessive

MCB41: Second Midterm Spring 2009

STUDENT NUMBER Letter Figures Words BIOLOGY. Written examination 2. Monday 5 November 2007

Protein Synthesis. Page 41 Page 44 Page 47 Page 42 Page 45 Page 48 Page 43 Page 46 Page 49. Page 41. DNA RNA Protein. Vocabulary

Name Class Date. Figure Which nucleotide in Figure 13 1 indicates the nucleic acid above is RNA? a. uracil c. cytosine b. guanine d.

Academic Nucleic Acids and Protein Synthesis Test

Genetics Lecture Notes Lectures 1 2

DNA, RNA, Protein synthesis, and Mutations. Chapters

Meiosis is a special form of cell division.

Regents Biology REGENTS REVIEW: PROTEIN SYNTHESIS

Practice Problems 4. (a) 19. (b) 36. (c) 17

Chapter 3. Chapter Outline. Chapter Outline 9/11/10. Heredity and Evolu4on

Bio 102 Practice Problems Genetic Code and Mutation

2. True or False? The sequence of nucleotides in the human genome is 90.9% identical from one person to the next. False (it s 99.

Two copies of each autosomal gene affect phenotype.

Molecular Genetics. RNA, Transcription, & Protein Synthesis

Chromosome Mapping Assignment INSTRUCTIONS

A and B are not absolutely linked. They could be far enough apart on the chromosome that they assort independently.

240Tutoring Life Science Study Material

5. The cells of a multicellular organism, other than gametes and the germ cells from which it develops, are known as

ISTEP+: Biology I End-of-Course Assessment Released Items and Scoring Notes

Influence of Sex on Genetics. Chapter Six

Respiration occurs in the mitochondria in cells.

Scheme of work Cambridge IGCSE Biology (0610)

The Story of Human Evolution Part 1: From ape-like ancestors to modern humans

LAB : THE CHI-SQUARE TEST. Probability, Random Chance, and Genetics

If you crossed a homozygous, black guinea pig with a white guinea pig, what would be the phenotype(s)

XII. Biology, Grade 10

KENDRIYAVIDYALAYASANGATHAN.CHENNAI REGION CLASS XII COMMONPREBOARD EXAMINATION SUBJECT- BIOLOGY. Section - A

Can receive blood from: * I A I A and I A i o Type A Yes No A or AB A or O I B I B and I B i o Type B No Yes B or AB B or O

Lecture Series 7. From DNA to Protein. Genotype to Phenotype. Reading Assignments. A. Genes and the Synthesis of Polypeptides

Variations on a Human Face Lab

Ex) A tall green pea plant (TTGG) is crossed with a short white pea plant (ttgg). TT or Tt = tall tt = short GG or Gg = green gg = white

Transcription:

SENIOR ERTIFITE EXMINTION LIFE SIENES P2 2015 MRKS: 150 TIME: 2½ hours This question paper consists of 14 pages.

Life Sciences/P2 2 E/2015 INSTRUTIONS N INFORMTION Read the following instructions carefully before answering the questions. 1. 2. 3. 4. 5. 6. 7. 8. 9. 10. 11. nswer LL the questions. Write LL the answers in the NSWER OOK. Start the answers to EH question at the top of a NEW page. Number the answers correctly according to the numbering system used in this question paper. Present your answers according to the instructions of each question. LL drawings must be done in pencil and labelled in blue or black ink. raw diagrams, flow charts or tables only when asked to do so. The diagrams in this question paper are NOT necessarily drawn to scale. o NOT use graph paper. You must use a non-programmable calculator, protractor and a compass where necessary. Write neatly and legibly.

Life Sciences/P2 3 E/2015 SETION QUESTION 1 1.1 Various options are given as possible answers to the following questions. hoose the answer and write only the letter ( to ) next to the question number (1.1.1 to 1.1.8) in the NSWER OOK, for example 1.1.9. 1.1.1 Humans have 46 chromosomes in each somatic cell. Each gamete produced will have 22 autosomes and 1 gonosome. 21 autosomes and 2 gonosomes. 23 autosomes. 23 gonosomes. 1.1.2 The table below shows the results of the F 1 generation after an investigation into the inheritance of eye colour in fruit flies was carried out. EYE OLOUR NUMER OF FLIES Red 182 White 61 The genotypes of the parents were RR x Rr. Rr x rr. Rr x Rr. RR x rr. 1.1.3 Which ONE of the following is TRUE about genes? Genes are codes for a particular characteristic. made up of amino acids. made up of RN. found in a ribosome. 1.1.4 Which ONE of the following is used to produce genetically identical individuals? Stem cell research Genetic modification loning N profiling

Life Sciences/P2 4 E/2015 QUESTIONS 1.1.5 and 1.1.6 are based on the pedigree diagram below. The pedigree diagram shows the inheritance of blood groups in a family. The blood groups of the individuals are represented by the letters. O O 1 O 2 KEY Female Male PEIGREE IGRM 1.1.5 Which ONE of the following represents the genotype and phenotype of individual number 1 above? ii and blood group O I i and blood group I i and blood group O I i and blood group 1.1.6 If individual 2 has a child with blood group, then her partner could only have blood group.. O..

Life Sciences/P2 5 E/2015 1.1.7 Which ONE of the following is ORRET with regard to the structure of N and RN? RN is double-stranded and N is single-stranded. RN contains uracil and N contains thymine. RN is a very long molecule while N is a short molecule. RN forms a double helix while N does not. 1.1.8 Which ONE of the following represents molecules that make up a single nucleotide? Phosphate, sugar and a nitrogenous base Sugar, protein and phosphate Nitrogenous base, phospholipid and sugar denine, sugar and a nitrogenous base (8 x 2) (16) 1.2 Give the correct biological term for each of the following descriptions. Write only the term next to the question number (1.2.1 to 1.2.9) in the NSWER OOK. 1.2.1 1.2.2 1.2.3 1.2.4 1.2.5 1.2.6 1.2.7 1.2.8 1.2.9 The type of inheritance involving two alleles of a gene that are not dominant over one other haracteristics controlled by genes which are located on the sex chromosomes hromosomes that are similar in structure and code for the same characteristics The monomers/building blocks of proteins The type of inheritance involving alleles that equally determine the phenotype of heterozygous offspring Undifferentiated cells which are able to develop into any other types of cells Intermediate fossils showing features of both more primitive and more advanced organisms n allele that is expressed phenotypically only in the homozygous condition genetic cross involving one characteristic only (9)

Life Sciences/P2 6 E/2015 1.3 Indicate whether each of the statements in OLUMN I applies to ONLY, ONLY, OTH N or NONE of the items in OLUMN II. Write only, only, both and, or none next to the question number (1.3.1 to 1.3.4) in the NSWER OOK. OLUMN I 1.3.1 iscovered the fossil of : ustralopithecus sediba : 1.3.2 Example of continuous variation : : 1.3.3 Pronounced brow ridges : : 1.3.4 iscovered the structure of : N : OLUMN II Raymond art Ron lark Height lood groups frican apes Homo sapiens Watson rick (4 x 2) (8) 1.4 In tomato plants the allele for red fruit (R) is dominant over the allele for yellow fruit (r). The allele for tallness (T) is dominant over the allele for shortness (t). Plant, which is heterozygous for red fruit and homozygous tall, was crossed with Plant, which has yellow fruit and is short. 1.4.1 Write down the genotype of: Plant Plant 1.4.2 1.4.3 Write down LL the possible genotypes of the gametes of plant. Name the phenotype of an offspring having the genotype: Rrtt RrTt 1.4.4 Plant was then crossed with another plant (Plant ) and all the offspring had red fruit and were tall. Use this information to write down the genotype of Plant. (8)

Life Sciences/P2 7 E/2015 1.5 The diagram below shows cells of an organism in one of the phases of meiosis. E PHSE OF MEIOSIS 1.5.1 1.5.2 Which phase of meiosis is represented in the diagram? Give the LETTER and NME of the part that: (c) Is responsible for the formation of the spindle fibres arries the genetic information Holds the chromatids together 1.5.3 State the number of chromosomes that would be present in each of the cells of this organism: t the beginning of meiosis In a gamete of this organism (9) TOTL SETION : 50

Life Sciences/P2 8 E/2015 SETION QUESTION 2 2.1 iagram 1 shows variation in a species of fish living in a lake. There was a rocky island that extended across the whole length of the lake, but it was under water due to the high water level. The fish were therefore able to move freely throughout the lake. iagram 2 shows the same lake many years later. drought had caused the level of the water in the lake to drop so that the rocky island in the centre separated the lake into two smaller lakes, and, for a long period of time. iagram 1 Rocky island iagram 2 Lake Lake FISH POPULTION IN LKE 2.1.1 2.1.2 2.1.3 efine population. State FOUR possible causes of the variation in the fish population in iagram 1. Eventually, as shown in iagram 2, lake and lake contained two different species of fish. (4) Name the process that resulted in the fish population becoming two different species. Explain how the new species was formed. (6) (13) 2.2 grey (G) male rabbit was mated with an albino (g) female rabbit. The entire F 1 generation was grey. Use a genetic cross to show the phenotypic ratio of their offspring if one of the males of the F 1 generation was mated with an albino female. (7)

Life Sciences/P2 9 E/2015 2.3 The diagram below shows the process of protein synthesis. Y Process W X Z Process PROTEIN SYNTHESIS 2.3.1 Identify the following molecules: W Y 2.3.2 2.3.3 Name the part of protein synthesis indicated by process. escribe how a mutation on molecule W will affect the structure of the protein formed by process. (4) 2.3.4 The following sequence represents a part of the nitrogenous base sequence on molecule X. G UG GG triplet 1 triplet 2 triplet 3 Write down the base sequence of the anticodon of triplet 1 shown above. The table below shows the amino acids that correspond with different N codes. MINO I rginine Glycine Methionine N OE TT T T Write down the correct sequence of amino acids for triplets 1 to 3. (3) (11)

Life Sciences/P2 10 E/2015 2.4 The graph below represents the results of an investigation which compares the conviction (number of people found guilty) of criminals with the use of N evidence and without the use of N evidence from 1989 to 2003. OMPRISON OF THE ONVITIONS WITH THE USE OF N EVIENE N WITHOUT THE USE OF N EVIENE, FROM 1989 TO 2003 50 Number of people found guilty (per 1 000 arrests) 40 30 20 10 0 1989 1991 1993 1995 1997 1999 2001 2003 Year onvictions with N evidence onvictions without N evidence 2.4.1 2.4.2 2.4.3 2.4.4 Formulate a hypothesis for this investigation. State the dependent variable in this investigation. [dapted from http://www.mindfully.org] How many more successful convictions per 1 000 arrests were made in 2003 with the use of N evidence? Show LL calculations. N database is a collection of the N profiles of all the citizens of a country. Explain how you would use the information in the graph to convince the government to create a N database. (4) (9) [40]

Life Sciences/P2 11 E/2015 QUESTION 3 3.1 The photographs of two butterflies are provided below. oth butterflies live in the same habitat and are preyed on by predators. lthough these butterflies are very similar in appearance they are two separate biological species. mauris ochlea has an unpleasant taste while Hypolimnas deceptor does not have an unpleasant taste. mauris ochlea Hypolimnas deceptor 3.1.1 3.1.2 3.1.3 TWO SPEIES OF UTTERFLY [From http://www.biodiversityexplorer.org.] Explain why most predators are less likely to feed on Hypolimnas deceptor. Use arwin's theory of evolution through natural selection to explain the evolution of the Hypolimnas deceptor butterfly. State ONE way in which natural selection differs from artificial selection. (3) (6) (11)

Life Sciences/P2 12 E/2015 3.2 The diagram below shows possible relationships between members of the family Hominidae. POSSILE RELTIONSHIPS ETWEEN HOMINIS Present Time (million years ago) Homo sapiens Homo erectus Homo habilis ustralopithecus africanus ustralopithecus robustus ustralopithecus boisei ustralopithecus afarensis [dapted from http://www.ideacentre.org] 3.2.1 3.2.2 What is the name given to the type of diagram above? How many of each of the following are represented in the diagram? Genera Species 3.2.3 3.2.4 3.2.5 3.2.6 Explain why. robustus and. boisei are more closely related than. boisei and. afarensis. Which of the hominids in the diagram above is considered to have been the first to use tools? Name TWO ustralopithecus fossils found in South frica. Explain how the location and the age of Homo fossils are used as evidence for the 'Out of frica' hypothesis. (3) (11)

Life Sciences/P2 13 E/2015 3.3 The diagrams below represent parts of the skeletons of an frican ape and a human. iagrams and are drawn to scale. IGRM IGRM IGRM IGRM SKELETON PRTS OF FRIN PE N HUMN 3.3.1 3.3.2 3.3.3 3.3.4 3.3.5 Write down the LETTERS only of the diagrams ( ) that represent bipedal organisms. Explain how the shape of the pelvis contributes to bipedalism. Explain the significance of the position of the foramen magnum in the skulls in diagram and in diagram. Tabulate THREE visible differences between the jaws/teeth of the skulls labelled and that indicate trends in human evolution. State THREE physical characteristics of the forelimb/upper limb that humans share with frican apes. TOTL SETION : (4) (7) (3) (18) [40] 80

Life Sciences/P2 14 E/2015 SETION QUESTION 4 escribe TWO types of mutations and how they lead to altered characteristics in FOUR genetic disorders you have studied. ontent: Synthesis: (17) (3) NOTE: NO marks will be awarded for answers in the form of tables, flow charts or diagrams. TOTL SETION : GRN TOTL: 20 150