Chemical Structures. Part I: Structures on paper and in 3-d

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hemical Structures bjectives 1. To practice with the different atoms used in Bio 111: to know the number of bonds made by each kind of atom, the structures that they form, and the charges they have. 2. To build molecular models of various bio-molecules. 3. To understand and be able to work with the different representations of molecules used in Bio 111. Introduction Matter is made up of approximately 100 elements. f these, only carbon, hydrogen, oxygen, nitrogen, sulfur and about a dozen others are found in living organisms. Atoms of these elements can attach to one another by chemical bonds. There are five types of bonds important to us in Bio 111: l. covalent bonds 2. hydrogen bonds 3. ionic bonds 4. ydrophobic interaction 5. van der Waals interaction Today, we will focus on covalent bonds, which are the result of a sharing of electrons between two or more atoms. In this case the electrons of the atoms forming the bond occupy the space between each others' nuclei. Molecules can be made up of atoms of different elements, such as the gas methane ( 4 ), in which one atom of carbon shares electrons with four atoms of hydrogen, or the molecule can be made up of atoms of the same element ( 2 ). arbon atoms are unusual in that they will bond together to form long chains of carbons (-----) thus making possible very elaborate molecules with carbon "backbones". Part I: Structures on paper and in 3-d Using the model kits The molecular model kits have five different types of atoms. arbon (black), xygen (red), Nitrogen (light blue), hlorine (green), and ydrogen (white). Each of these represents an atom, composed of its nucleus and the surrounding electrons. These atoms can be connected to each other by inserting the white rods into the holes. It will become apparent to you that different atoms have different capacities for bonding with other atoms. The holes in the plastic "atoms" indicate the number of electrons that the atom is able to share with another atom. Note that there are two types of blue nitrogen atoms. ne type has 3 holes - you should use these ones. thers have 2 holes; don t use them since the geometry will be wrong. hemical Structures - 3

A reminder of the number of bonds each atom makes and the corresponding charge: Number of Bonds Element 0 1 2 3 4 5 + neutral neutral N neutral + neutral S neutral P neutral A simple mnemonic is N makes 1 bond, makes 2, N makes 3, and makes 4. Also a reminder of the relative electronegativities of a few relevant elements: Low:, S, P, and igh: N,, and l These properties can all be explained in terms of the electronic structures of the elements involved. You may want to take time to discuss this as a class. See periodic table at the end of this section for details. The short rods are used to indicate the covalent bond involving hydrogen, since hydrogen, being the smallest atom, has a smaller distance between it and a carbon atom. Similarly, the curved rods are used to show double and triple bonds and have the effect of bringing the atoms closer together, which reflects the true situation. The nuclei of carbon atoms in a = bond are closer together than in an -, but not so close as in a º bond. Working in groups of three, build these molecules using the stick models and have your TA check them off. 1) Simple hydrocarbons methane 4 2) Alcohols butanol 4 9 -- Note: there are 5 isomers of butanol. Three are structural isomers. Two are enantiomers - that is, they are mirror-image isomers (Wikipedia has a good entry on isomers and enantiomers). Build models of all five forms. hemical Structures - 4

3) Amino acids 2 N glycine 2 alanine 2 N 3 note that - is not Take two amino acids and join them to make a dipeptide, such as the one below: what did you have to remove to make this molecule? You have made a peptide bond. a dipeptide (glycine-alanine) 2 N 2 3 N 4) hirality is a very important feature of biological molecules because their exact 3- dimensional shape determines their function. An interesting example of this are the two forms of the molecule carvone: 3 3 d or (+) carvone * oil of caraway (rye bread) * l or (-) carvone oil of spearmint (mint) 3 2 3 2 Both have the identical formulas ( 10 14 ) and identical structures except for the arrangement of the atoms at the *ed carbon. With the ring of carbons lying flat on the table and the = on the right, as shown, the dashed bond (usually, we ll use dashed bonds to indicate hydrogen bonds; in this case, we use it to show the 3-d shape of a particular covalent bond) points down into the table and the triangle bond points up from the table. ne groups will make one of the forms of carvone and another group will make the other. onvince yourself that they are not the same structure. They are mirror-image isomers, or enantiomers. Your TA will give you samples of the two carvones to smell. Notice that their similar structures lead to similar smells, but there is a difference due to the slight difference in shape. hemical Structures - 5

Part II: Molecules on the computer bjectives To look at the structures of some important biological molecules and get a feel for their three-dimensional structure. To familiarize yourself with the representations of molecules used by the Jmol program, which we will use extensively in future labs. Background Jmol is a molecular viewing application. It lets you rotate, highlight, zoom in on, etc. a two-dimensional image of a three-dimensional molecule. It shows molecules in a simplified format, specifically: all covalent bonds are shown as a single rod, whether the bond is single, double, or triple atoms are shown as colored spheres; the colors identify each type of atom Procedure You will follow the exercise on the course web site for this lab and fill in the worksheet described below. You should work in groups of three; your worksheet will be a group effort for a group grade. 1) Go back to the dock at the bottom of the screen. 2) lick on the Safari icon. 3) Safari will start up and go to the Biology 111/112 home page. 5) lick on the link to the LLM ( n-line Lab Manual ) 6) lick on the link to hemical Structures Exercises for this lab. 7) Follow the exercise there and fill in the worksheet on pages 9 and 10 of this section of the lab manual. Briefly, you will: (1) Based on the image on the computer, draw the structures of two sugars, glucose and fructose as well as an amino acid. These images have hydrogen atoms included as a warm-up. You will be asked to find the differences between the sugar structures and identify the amino acid. hemical Structures - 6

Part III: Possible and Impossible Formulas (optional) bjective: to get more practice with the bonding rules. Background: While there are many molecules with the formula 4 10, there are no molecules with the formula 5 since carbon only makes 4 covalent bonds and hydrogen only makes one, there is no molecule that satisfies the rules and has this formula. Learning to figure out which are possible and which are not is a great way to practice with the bonding rules. hallenges: For each of the following formulae, draw a molecule with that formula or determine that it is not possible. If it is possible, try to come up with as many different molecule with that formula as you can. Try also to write them in complete and abbreviated forms. 1. 6 6 2. 5 5 N(+) 3. 4 6 4. 4 12 N(+) 5. 4 4 6. Make up some of your own. Lab report There is no report for this part of the lab. You will turn in the worksheet to your TA at the end of lab to be graded. A copy of this worksheet is at the end of this section. hemical Structures - 7

hemical Structures - 8

Bio 111 Small Molecules Worksheet Name This is a TA & Sect. group effort Name for a group grade. Name Score /20 This is due at the end of lab today. The numbers of these questions correspond to the numbers on the web site. 1) Using the image from the web site, draw the structure of the linear form of glucose. You need not indicate the chiral parts of the molecule. (4 pts) 2) Using the image from the web site, draw the structure of the linear form of fructose. You need not indicate the chiral parts of the molecule. (4 pts) 3) n the structure in question (2), indicate the differences between glucose and fructose. (2 pts) 4) Using the image from the web site, draw the structure of the circular form of glucose. You need not indicate the chiral parts of the molecule. (4 pts) 5) n the structure in question (1), make a drawing that shows which parts of the molecule have been linked to form ring structure. (2 pts) hemical Structures - 9

6) Using the image from the web site, draw the structure of the amino acid for part (6). You need not indicate the chiral parts of the molecule. (2 pts) 7) Using the chart of amino acid structures in the lab manual, identify the amino acid you drew in question (6). (2 pts) hemical Structures - 10

N 3 N 3 2 3 2 2 Alanine (Ala) N N 2 Arginine (Arg) N 2 Structures of Amino Acids N 3 N 3 2 2 N 2 Asparagine (Asn) Aspartic Acid (Asp) N 3 2 S ysteine (ys) N 3 2 2 Glutamic Acid (Glu) N 3 2 2 N 2 Glutamine (Gln) N 3 Glycine (Gly) N N 3 N 2 istidine (is) N 3 3 2 3 Isoleucine (Ile) N 3 N 3 2 2 3 2 3 2 Leucine (Leu) 2 Lysine (Lys) N 3 N 3 2 2 S 3 Methionine (Met) N 3 2 Phenylalanine (Phe) 2 N 2 2 2 Proline (Pro) N 3 2 Serine (Ser) N 3 3 Threonine (Thr) N N 3 Tryptophan(Trp) 2 N 3 2 Tyrosine (Tyr) N 3 3 3 Valine (Val) hemical Structures - 11

Partial Periodic Table ydrogen e elium 1p + 0n 0 1e 1(1 open) 2p + 2n 0 2e En = 2.1 Li Lithium Be Beryllium B Boron arbon N Nitrogen xygen F Fluorine En = none Ne Neon 3p + 4n 0 3e 1 (7 open) En = 1.0 4p + 5n 0 4e 2 (6 open) En = 1.5 Symbol Name Total number of electrons (e ; (-1 charge). Balances protons. 5p + 6n 0 5e 3 (5 open) En = 2.0 P Phosphorus 15p + 16n 0 15e 8 (full) 5 (3 open) En = 2.1 6p + 6n 0 6e 4 (4 open) En = 2.5 7p + 7n 0 7e 5 (3 open) En = 3.0 P Phosphorus 15p + 16n 0 15e 8 (full) 5 (3 open) En = 2.1 8p + 8n 0 8e 6 (2 open) En = 3.5 S Sulfur 16p + 16n 0 16e 8 (full) 6 (2 open) En = 2.5 ontents of nucleus: p + = proton (+1 charge) n 0 = neutron (0 charge) 9p + 10n 0 9e 7 (1 open) En = 4.0 # electrons in innermost shell # electrons in next shell out 10p + 10n 0 10e 8 (full) En = none Elements in this column do not form any covalent bonds (at least, not in Bio 111) # electrons in outer (valence) shell ( # open = # required to fill outer shell) Electronegativity. Increases as you go Ý and Þ hemical Structures - 12