Hydrostatic Force on a Submerged Surface



Similar documents
When the fluid velocity is zero, called the hydrostatic condition, the pressure variation is due only to the weight of the fluid.

FLUID FORCES ON CURVED SURFACES; BUOYANCY

Chapter 5: Distributed Forces; Centroids and Centers of Gravity

TWO-DIMENSIONAL TRANSFORMATION

p atmospheric Statics : Pressure Hydrostatic Pressure: linear change in pressure with depth Measure depth, h, from free surface Pressure Head p gh

Reflection and Refraction

Lecture 8 : Coordinate Geometry. The coordinate plane The points on a line can be referenced if we choose an origin and a unit of 20

Chapter 3. Flotation. ELEMENTARY HYDRAULICS National Certificate in Technology (Civil Engineering) Buoyancy

Experiment #9, Magnetic Forces Using the Current Balance

Stack Contents. Pressure Vessels: 1. A Vertical Cut Plane. Pressure Filled Cylinder

Introduction to Beam. Area Moments of Inertia, Deflection, and Volumes of Beams

Prelab Exercises: Hooke's Law and the Behavior of Springs

Structural Axial, Shear and Bending Moments

Physics 41, Winter 1998 Lab 1 - The Current Balance. Theory

Physics 181- Summer Experiment #8 1 Experiment #8, Measurement of Density and Archimedes' Principle

A Determination of g, the Acceleration Due to Gravity, from Newton's Laws of Motion

FRICTION, WORK, AND THE INCLINED PLANE

2.016 Hydrodynamics Reading # Hydrodynamics Prof. A.H. Techet

Electrical Resonance

Laboratory Report Scoring and Cover Sheet

Simple Harmonic Motion

m i: is the mass of each particle

Shear Center in Thin-Walled Beams Lab

CENTER OF GRAVITY, CENTER OF MASS AND CENTROID OF A BODY

Copyright 2011 Casa Software Ltd. Centre of Mass

Section 9.1 Vectors in Two Dimensions

Archimedes Principle. Biological Systems

IDEAL AND NON-IDEAL GASES

Pre-lab Quiz/PHYS 224 Magnetic Force and Current Balance. Your name Lab section

Scientific Graphing in Excel 2010

MECHANICAL PRINCIPLES HNC/D MOMENTS OF AREA. Define and calculate 1st. moments of areas. Define and calculate 2nd moments of areas.

ACCELERATION DUE TO GRAVITY

Activity P13: Buoyant Force (Force Sensor)

Magnetic Fields and Their Effects

Chapter 9. Systems of Linear Equations

General Physics Lab: Atwood s Machine

1 of 7 9/5/2009 6:12 PM

If you put the same book on a tilted surface the normal force will be less. The magnitude of the normal force will equal: N = W cos θ

Determination of Acceleration due to Gravity

F B = ilbsin(f), L x B because we take current i to be a positive quantity. The force FB. L and. B as shown in the Figure below.

Physics 201 Homework 8

The Basics of FEA Procedure

FORCE ON A CURRENT IN A MAGNETIC FIELD

Three Methods for Calculating the Buoyant Force Gleue: Physics

EdExcel Decision Mathematics 1

Figure 1.1 Vector A and Vector F

AP1 Oscillations. 1. Which of the following statements about a spring-block oscillator in simple harmonic motion about its equilibrium point is false?

Experiment #8: Magnetic Forces

Lab: Graphing Activities TOTTEN

Pressure in Fluids. Introduction

Experiment 7: Forces and Torques on Magnetic Dipoles

PENDULUM PERIODS. First Last. Partners: student1, student2, and student3

E/M Experiment: Electrons in a Magnetic Field.

The purposes of this experiment are to test Faraday's Law qualitatively and to test Lenz's Law.

Chapter 27: Taxation. 27.1: Introduction. 27.2: The Two Prices with a Tax. 27.2: The Pre-Tax Position

POWDER PROPERTIES LABORATORY

ENGINEERING MECHANICS STATIC

Part 1: Background - Graphing

PARAMETRIC MODELING. David Rosen. December By carefully laying-out datums and geometry, then constraining them with dimensions and constraints,

PROBLEM SET. Practice Problems for Exam #1. Math 1352, Fall Oct. 1, 2004 ANSWERS

Physics 1A Lecture 10C

ELECTRON SPIN RESONANCE Last Revised: July 2007

Midterm Solutions. mvr = ω f (I wheel + I bullet ) = ω f 2 MR2 + mr 2 ) ω f = v R. 1 + M 2m

Chapter 11 Equilibrium

oil liquid water water liquid Answer, Key Homework 2 David McIntyre 1

11.1. Objectives. Component Form of a Vector. Component Form of a Vector. Component Form of a Vector. Vectors and the Geometry of Space

6. Vectors Scott Surgent (surgent@asu.edu)

What are the place values to the left of the decimal point and their associated powers of ten?

5. Measurement of a magnetic field

Section 16: Neutral Axis and Parallel Axis Theorem 16-1

Objectives. Experimentally determine the yield strength, tensile strength, and modules of elasticity and ductility of given materials.

Physics 3 Summer 1989 Lab 7 - Elasticity

CHAPTER 6 WORK AND ENERGY

Click on the links below to jump directly to the relevant section

MIME 3330 Mechanics Laboratory LAB 5: ROTATING BENDING FATIGUE

Experimental Analysis

Determining the Acceleration Due to Gravity

FURTHER VECTORS (MEI)

Work and Energy. W =!KE = KE f

Geometric Optics Converging Lenses and Mirrors Physics Lab IV

Analysis of Stresses and Strains

3.2 LOGARITHMIC FUNCTIONS AND THEIR GRAPHS. Copyright Cengage Learning. All rights reserved.

Lab 8: Ballistic Pendulum

Elasticity. I. What is Elasticity?

Chapter 6 Work and Energy

Fric-3. force F k and the equation (4.2) may be used. The sense of F k is opposite

MATH 60 NOTEBOOK CERTIFICATIONS

Rotation: Moment of Inertia and Torque

Freehand Sketching. Sections

Magnetic Field of a Circular Coil Lab 12

Math 1B, lecture 5: area and volume

ACCELERATION OF HEAVY TRUCKS Woodrow M. Poplin, P.E.

Graphing Linear Equations

Rotational Motion: Moment of Inertia

Volumes of Revolution

ELECTRIC FIELD LINES AND EQUIPOTENTIAL SURFACES

Experiment 3 Pipe Friction

6.4 Normal Distribution

Awareness of lifetime physical and mental wellness Physical Education Included in a degree or certificate program: Yes No Noncredit Category:

Experiment 2 Free Fall and Projectile Motion

Transcription:

Experiment 3 Hydrostatic Force on a Submerged Surface Purpose The purpose of this experiment is to experimentally locate the center of pressure of a vertical, submerged, plane surface. The experimental measurement is compared with a theoretical prediction. Apparatus Figure 3.1 is a sketch of the device used to measure the center of pressure on a submerged vertical surface. It consists of an annular sector of solid material attached to a balance beam. When the device is properly balanced the face of the sector that is not attached to the beam is directly below (coplanar) with the pivot axis. The solid sector and the balance beam is supported above a tank of water. L P Q H h B r 2 S r 1 T F CG A W Figure 3.1: Apparatus for measuring the location of the center of pressure. 9

10 EXPERIMENT 3. HYDRSTATIC FRCE N A SUBMERGED SURFACE y x y R h Figure 3.2: Detailed nomenclature for locating the center of pressure. Theory Figure 3.2 shows the submerged surface viewed from the left side of the tank in Figure 3.1. The depth of the centroid below the surface of the water is h. The x-y coordinate system has its origin at the centroid. The y-direction position of the center of pressure, y R, is (Munson et al., 2.8) y R = y c + I xc y c A (3.1) where I xc is the moment of inertia of the surface about the x-axis, and A is the surface area. The location of the center of pressure can be measured using the apparatus sketched in Figure 3.1. The counterweight is adjusted so that the beam is horizontal when there is no water in the tank and no weight in the pan. When the tank is filled with water the unbalanced hydrostatic force causes the beam to tilt. Adding weight W to the pan at a distance L from the pivot exerts a moment W L that counterbalances the resultant moment due to the hydrostatic forces on the quarter-annulus-shaped body ABP Q. When the water level is as shown in the figure, there are hydrostatic forces on surfaces AB, BS and AT. Since BS and AT are concentric cylindrical surfaces with the common axis passing through, the hydrostatic forces on BS and AT do not exert any moment about. As a result W L is equal to the moment due to the hydrostatic force F acting on the vertical plane surface AB. In this experiment the force F is not measured. Instead the theoretical value F = ρgha is assumed, where h is the depth of the centroid of the surface. The moment due to F is measured and the theoretical value of F is used to compute the location of the center of pressure. Balancing the moments about gives Substituting F = ρgha and solving for y R yields W L = F (H + y R ) y R = W L ρgha H (3.2)

11 Laboratory Procedure 1. Adjust the counterweight so that the balance the beam is horizontal with no water in the tank. 2. Add water up to some level. During the lab you will use at least four water levels. Make sure some water levels leave part of the vertical face exposed. 3. Add weights to the pan to restore the beam to a horizontal position. Record the weight. Measure H. 4. Measure and record h. 5. Calculate y R,th and compare to y R,m. If the values are not reasonably close, check your measurement procedure. 6. Return to step 2 and repeat the measurements using at least three other water levels. Analysis 1. Calculate y R from equation (3.1). Call this the theoretical value y R,th. 2. For each water depth, calculate y R from equation (3.2). Call this value the measured value y R,m. 3. Plot y R,th versus h and y R,m versus h on the same axes. 4. Plot y R,th y R,m versus h. 5. Plot y R,th y c versus h. The plots created in step 3 and step 4 allow a comparison of the theoretical and measured values of y R. The plot from step 4 shows the difference between the measured and theoretical values. A difference plot (like that required in step 4) is a good way to compare two quantities that have nearly the same value. For example, Figure 2.2 and Figure 2.3 in the lab manual for Experiment 2 are two plots of the calibration data for a pressure gage. The data in Figure 2.2 suggest that the calibration is quite good, but there is no indication of the magnitude of the errors. Figure 2.3 clearly shows the magnitude of the discrepancy between the indicated reading of the pressure gage and the dead weight tester. Furthermore, by plotting the calibration data as in Figure 2.3 one sees that the indicated pressure tends to be lower than the calibration standard (more points fall below the line p indicated p dwt = 0). Report 1. How does the design of the apparatus enable the resultant force on the vertical surface to be measured? Are any significant forces being neglected? Does the section of the vertical surface that is above the water surface contribute any error to the measurement? 2. Compare the experimental and theoretical values of y R and explain any discrepancy. Pick one point in the middle of the range of measurements. For that data point, how much of a change in the measured y R would be caused by an error of 10 grams in the weight measurement? 3. What is the primary trend in y R y c versus water depth? Is this consistent with the theory presented in lecture and in the textbook?

12 EXPERIMENT 3. HYDRSTATIC FRCE N A SUBMERGED SURFACE Reference B.R. Munson, D.F. Young, and T.H. kiishi, Fundamentals of Fluid Mechanics, 4th ed., 2002, Wiley and Sons, New York. Appendix: What About Buoyancy? Is the buoyancy force being neglected in the analysis of the experimental data? The answer is no. To understand why, we will consider two ways to analyze the experiment. The first analysis involves a moment balance that causes the buoyancy force to appear. The second analysis is the same as that presented in the preceding sections, and no buoyancy force appears. How can the buoyancy force be made to disappear? Remember that the buoyancy force is defined as the net pressure force acting on a submerged body. If we consider the pressure force components acting in the horizontal and vertical directions, then the buoyancy force contributes to the moment about the device pivot. If instead we consider the pressure forces acting normal to the surface of the acrylic arc, then the buoyancy force does not appear because the normal forces on the curved surface do not contribute a moment about the pivot of the device. This result is due to the design of the experiment. In other words, the person who designed this device chose the circular arc shape because it allows us to measure the hydrostatic pressure forces without accounting for the buoyancy effect. Initial Balance First consider the force balance on device when the apparatus is dry (the tank is empty), and the balance weight has been properly adjusted. This situation is depicted in Figure 3.3. The balance weight W c is moved left or right until the moment W c L c is equal and opposite to the moment W a L a. When the tank is filled with water, pressure forces on the surface of the curved acrylic cause an additional moment. The moment due to the pressure forces is balanced by adding weights to the pan shown on the right side of Figure 3.3. Adding water does not affect the moment balance W c L c = W a L a because the water does not change the weight of the device. L c L a W c W a Figure 3.3: Moments acting while balance weight is being adjusted and the tank is empty.

13 L L c L b L a F b W c W W a Figure 3.4: Horizontal and vertical forces that create moments. Moments due to Horizontal and Vertical Forces Figure 3.4 shows the horizontal and vertical force components acting the acrylic after water is added to the tank. The horizontal forces are depicted as acting on vertical planes that are the projection of the curved surface. The contributions to the horizontal pressure forces on the left and right sides cancel exactly. Thus, by considering the horizontal pressure forces separately from the vertical pressure forces, we see that the net horizontal force must be zero. The horizontal force on the flat face of the acrylic does not appear separately because it is already included the balance of horizontal pressure forces. The vertical forces acting on the top and bottom of the curved surface create a buoyancy force F b, which acts through the center of buoyancy. The center of buoyancy is the centroid of that portion of the acrylic that is submerged. The weight of the acrylic W a acts through the center of gravity of the solid material. When the system is analyzed with the forces identified in Figure 3.4, the weight W creates a moment W L that balances the buoyancy force F b L b. The moment W a L a caused by the weight of the acrylic is still cancelled exactly by the moment from the balance weight W c L c. Moments due to Normal Forces Now consider the moment balance depicted in Figure 3.5. In this view only the force components normal to the surface are identified. No forces are neglected because the pressure force acts normal to the surface. In this particular apparatus it is easier to analyze the normal forces directly than to separate the forces into horizontal and vertical components. The local pressure force on the curved surface of the acrylic is not zero. However, the pressure forces on the curved surface do not contribute to moments about because these forces have lines of action that pass directly through. In other words, the device is cleverly designed to eliminate the contributions of all surface forces except the force acting on the vertical surface. A moment balance about point shows that the moment F (H + h) is balanced by W L. The buoyancy force is not neglected.

14 EXPERIMENT 3. HYDRSTATIC FRCE N A SUBMERGED SURFACE L H + h F W Figure 3.5: Forces normal to curved surface. Summary of Buoyancy Affect The analysis of Figure 3.4 gives and the analysis of Figure 3.5 gives W L = F b L b (3.3) W L = F (H + h). (3.4) Thus, the weight can be used to measure either the magnitude of the buoyancy force or the magnitude of the net pressure force on the vertical face of the acrylic. To use Equation (3.3) we need to compute L b, which requires locating the center of buoyancy. This is not trivial because the centroid of the submerged region of the acrylic is not a regular geometric shape.