2016 Regional Mathematics Contest Geometry Test

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2016 Regional Mathematics Contest Geometry Test In each of the following, choose the BEST answer and record your choice on the answer sheet provided. To ensure correct scoring, be sure to make all erasures completely. The tiebreaker questions at the end of the exam will be used to resolve ties in first, second, and/or third place. They will be used in the order given. Complete the 25 multiple choice questions before attempting the tiebreaker questions. Figures are not necessarily drawn to scale. 1. Find the measure of α. a. 45 b. 78 c. 33 d. 69 e. Not enough information 2. If the angles of a triangle are 42, 73, and 65, which of the following would be an exterior angle of the triangle. a. 115 b. 65 c. 86 d. 117 e. None of these 3. To inscribe a circle in a triangle, which of the following must be constructed? a. The perpendicular bisectors of two sides. b. The bisectors of two angles. c. The altitudes of the triangle. d. The diameter of the circle. e. None of these.

4. Which of the following are properties of parallelograms? I. The opposite angles are congruent. II. The diagonals are perpendicular. III. The adjacent angles are supplementary. IV. The diagonals bisect each other. a. I and II only b. I, II and III c. II and III only d. I, III and IV e. All are properties of parallelograms. 5. Which of the following transformations will not map the square onto itself? a. A rotation of 180 about the center. b. A rotation of 270 about the center. c. A reflection about the perpendicular bisector of a side. d. A rotation of 45 about the center. e. A reflection about a diagonal. 6. Write the equation of the circle with center at ( 4, 3) passing through the origin. a. x 4! + y + 3! = 25 b. x 4! + y + 3! = 16 c. x + 4! + y 3! = 9 d. x + 4! + y 3! = 25 e. x + 4! + y 3! = 16 7. Find the area of the isosceles triangle ABC. a. 64.3 b. 68.7 c. 34.4 d. 73.1 e. None of these

8. The circle with center P is divided into sectors. The segment QT is a diameter of circle P. What is the measure of arc QTS? a. 143 b. 233 c. 217 d. 57 e. Not enough information 9. In the above figure, if m QPU = 57, and QT = 4, what is the length of arc RQU? a.!"!!" b.!!!! c.!!!! d.!!!!" e.!!! 10. If a regular octagon has a side length of 6, what is the radius, to the nearest tenth, of the circle circumscribing the octagon? a. 4.2 b. 7.8 c. 7.2 d. 6.0 e. 8.4 11. For the octagon in Question 13, to the nearest tenth, what is the radius if the circle inscribed in the octagon? a. 4.2 b. 7.8 c. 7.2 d. 6.0 e. 8.4

Use the information provided to answer questions 12 14. Given: ΔABC with AC DE Prove:!"!" =!"!" Statements Reasons 1. AC DE 1. Given 2. BDE BAC, BED BCA 2.? 3. ΔABC~ DBE 3. If two pairs of corresponding angles are congruent, the triangles are similar.!" 4. =!" 4. The lengths of corresponding sides of!"!" similar triangles are proportional. 5. A property of proportions 5.!"!!"!" =!"!!"!" 6. AB = AD + DB, CB = CE + EB 6.? 7. AD = AB DB, CE = CB EB 7. Subtraction Property of Equality 8.!"!" =!"!" 8. Substitution 12. Which reason justifies the statement in step 2 of the proof? a. If two parallel lines are cut by a transversal, the alternate interior angles are congruent. b. If two parallel lines are cut by a transversal, the corresponding interior angles are congruent. c. Vertical angles are congruent. d. If two parallel lines are cut by a transversal, the alternate exterior angles are congruent. e. None of the above.

13. Which reason justifies the statement instep 6 of the proof? a. Addition Property of Equality b. Definition of congruence. c. Definition of betweenness. d. Definition of midpoint. e. None of the above. 14. If AC = 12, DE = 8, and BD = 6, then AD = a. 9 b. 4 c. 16 d. 3 e. Not enough information 15. What is the sum of the measures of all interior angles of the figure below? a. 900 b. 1260 c. 1080 d. 1440 e. None of these 16. Which of the following is not used in the construction of the perpendicular bisector of the segment AB? a. A circle of radius AB with center A b. A circle of radius AB with center B c. The intersection points of the circles of radius AB with centers A and B. d. The midpoint of the segment AB. e. All of these are used.

17. In two similar right triangles, the lengths of the corresponding sides are in the ratio of 5:3. If the larger triangle has a hypotenuse of length 17 and the length of the shortest side is 8, what is the area of the smaller triangle? a. 72 b. 40.8 c. 21.6 d. 36 e. None of these 18. Given the points A 2, 9, B 3, 1 and C(10, 2), Which of the following points could be the fourth vertex of parallelogram ABCD? a. 8, 11 b. 5, 8 c. 15, 6 d. (5, 6) e. None of these. 19. Which of the following could be done to quadruple the volume of a right circular cone? a. Quadrupling the height. b. Quadrupling the radius. c. Doubling the radius. d. Quadrupling the height and doubling the radius. e. Quadrupling the height or doubling the radius. 20. Find the area of the isosceles trapezoid below. a. 504 b. 203 3 c. 406 3 d. 873 e. None of these

21. If A(1, 1) is the midpoint of BC with B 7, 2, what are the coordinates of the midpoint of AC? a. 2, 2.5 b. (3, 1.5) c. 5, 4 d. (4, 0.5) e. None of these 22. Find the measure of ACB. a. 35 b. 75 c. 92.5 d. 70 e. Not enough information 23. In the right triangle ABC below, if BC = 6 and AC = 8, find AD. a. 10 b. 3.6 c. 4.8 d. 6.4 e. None of these 24. If quadrilateral A B C D is the reflection of quadrilateral ABCD about the line y = x, what are the coordinates of B? a. 6, 1 b. 2, 1 c. ( 5, 2) d. 2, 5 e. ( 1, 2)

25. The Eiffel Tower is approximately 1,063 feet tall. A tourist whose eyes are 5 feet above the ground observes the tower from 1000 feet away. To the nearest hundredth, what is the angle of elevation from her eyes to the top of the tower? a. 46.75 b. 43.39 c. 46.61 d. 43.25 e. 44.89

Tie Breaker #1 The two circles below are concentric. The length of the chord tangent to the inner circle is 30 mm. What is the area between the two circles?

Tie Breaker #2 In the square ABCD, M is the midpoint of AB. A line perpendicular to MC intersects AD at K. Prove that BCM KCM.

Tie Breaker #3 In triangle ABC, median BD is such that A DBC. If m ADB = 45, prove that m A = 30.

Answer Key 2016 Regional Geometry Exam 1. D 2. A 3. B 4. D 5. D 6. D 7. B 8. C 9. B 10. B 11. C 12. B 13. C 14. D 15. B 16. D 17. C 18. C 19. E 20. B 21. A 22. B 23. D 24. C 25. C

Tie Breaker #1 The two circles below are concentric. The length of the chord tangent to the inner circle is 30 mm. What is the area between the two circles? Solution: By Pythagorean Theorem, R! r! = 225. The area between the circles is the difference of the areas of the larger and smaller circles: A = πr! πr! = π R! r! = 225π mm!

Tie Breaker #2 In the square ABCD, M is the midpoint of AB. A line perpendicular to MC intersects AD at K. Prove that BCM KCM. Solution: Draw ML AD. Then since AM MB, KP PC. This means MP is the median of right triangle KMC to the hypotenuse. Therefore, triangle MPC is an isosceles triangle. Hence PCM PMC. By the Alternate Interior Angles Theorem, we also have BCM LMC. Therefore, by transitivity, we have BCM LMC PMC KMC.

Tie Breaker #3 In triangle ABC, median BD is such that A DBC. If m ADB = 45, prove that m A = 30. Solution: Since A DBC and BCD is a common angle, triangle ABC is similar to triangle BDC. Draw the perpendicular from C to AB and extend AB to intersect the perpendicular at E. Let y = m ABD. By angle sum of triangles, x + y + 45 = 180, or equivalently, x + y = 135. Since EBC is the supplement of ABC, and m ABC = x + y, m EBC = 45. Since triangle BCE is a right triangle, m BCE = 45. Let p = CE Pythagorean Theorem, By similarity,!" =!", or equivalently,!"!" BC! = CE! + BE! = 2CE! = 2p! BC! = AC DC = 2DC DC = 2DC! Combining these equations, we get that DC = p, so AC = 2p. Therefore, since the hypotenuse is twice the length of the shortest side, the right triangle ACE is a 30 60 90 triangle, and since CE is the shortest side, m A = 30.