Drawing and Using Free-Body Diagrams

Similar documents
Worksheet #1 Free Body or Force diagrams

AP Physics - Chapter 8 Practice Test

Newton s Law of Motion

Two-Body System: Two Hanging Masses

Physics: Principles and Applications, 6e Giancoli Chapter 4 Dynamics: Newton's Laws of Motion

Lecture 6. Weight. Tension. Normal Force. Static Friction. Cutnell+Johnson: , second half of section 4.7

AP Physics Applying Forces

B) 286 m C) 325 m D) 367 m Answer: B

LAB 6: GRAVITATIONAL AND PASSIVE FORCES

LAB 6 - GRAVITATIONAL AND PASSIVE FORCES

Chapter 4. Forces and Newton s Laws of Motion. continued

v v ax v a x a v a v = = = Since F = ma, it follows that a = F/m. The mass of the arrow is unchanged, and ( )

C B A T 3 T 2 T What is the magnitude of the force T 1? A) 37.5 N B) 75.0 N C) 113 N D) 157 N E) 192 N

Chapter 5 Using Newton s Laws: Friction, Circular Motion, Drag Forces. Copyright 2009 Pearson Education, Inc.

Chapter 4: Newton s Laws: Explaining Motion

Serway_ISM_V1 1 Chapter 4

VELOCITY, ACCELERATION, FORCE

TEACHER ANSWER KEY November 12, Phys - Vectors

Physics 11 Assignment KEY Dynamics Chapters 4 & 5

Physics 2A, Sec B00: Mechanics -- Winter 2011 Instructor: B. Grinstein Final Exam

circular motion & gravitation physics 111N

5. Forces and Motion-I. Force is an interaction that causes the acceleration of a body. A vector quantity.

Objective: Equilibrium Applications of Newton s Laws of Motion I

At the skate park on the ramp

If you put the same book on a tilted surface the normal force will be less. The magnitude of the normal force will equal: N = W cos θ

9. The kinetic energy of the moving object is (1) 5 J (3) 15 J (2) 10 J (4) 50 J

Steps to Solving Newtons Laws Problems.

Ideal Cable. Linear Spring - 1. Cables, Springs and Pulleys

Physics 111: Lecture 4: Chapter 4 - Forces and Newton s Laws of Motion. Physics is about forces and how the world around us reacts to these forces.

Experiment: Static and Kinetic Friction

STATIC AND KINETIC FRICTION

PHYSICS 111 HOMEWORK SOLUTION #10. April 8, 2013

Work, Energy and Power Practice Test 1

HW Set II page 1 of 9 PHYSICS 1401 (1) homework solutions

Chapter 6 Work and Energy

Examples of Scalar and Vector Quantities 1. Candidates should be able to : QUANTITY VECTOR SCALAR

Lecture 07: Work and Kinetic Energy. Physics 2210 Fall Semester 2014

Physics 125 Practice Exam #3 Chapters 6-7 Professor Siegel

Force. Force as a Vector Real Forces versus Convenience The System Mass Newton s Second Law. Outline

MULTIPLE CHOICE. Choose the one alternative that best completes the statement or answers the question.

CHAPTER 6 WORK AND ENERGY

Chapter 07 Test A. Name: Class: Date: Multiple Choice Identify the choice that best completes the statement or answers the question.

Newton s Second Law. ΣF = m a. (1) In this equation, ΣF is the sum of the forces acting on an object, m is the mass of

PHY231 Section 2, Form A March 22, Which one of the following statements concerning kinetic energy is true?

KE =? v o. Page 1 of 12

Problem Set 5 Work and Kinetic Energy Solutions

PHY231 Section 1, Form B March 22, 2012

Conceptual Questions: Forces and Newton s Laws

Work Energy & Power. September 2000 Number Work If a force acts on a body and causes it to move, then the force is doing work.

AP1 Dynamics. Answer: (D) foot applies 200 newton force to nose; nose applies an equal force to the foot. Basic application of Newton s 3rd Law.

Displacement (x) Velocity (v) Acceleration (a) x = f(t) differentiate v = dx Acceleration Velocity (v) Displacement x

F N A) 330 N 0.31 B) 310 N 0.33 C) 250 N 0.27 D) 290 N 0.30 E) 370 N 0.26

AP1 Oscillations. 1. Which of the following statements about a spring-block oscillator in simple harmonic motion about its equilibrium point is false?

Pendulum Force and Centripetal Acceleration

Physics 2048 Test 1 Solution (solutions to problems 2-5 are from student papers) Problem 1 (Short Answer: 20 points)

SHORT ANSWER. Write the word or phrase that best completes each statement or answers the question.

8. Potential Energy and Conservation of Energy Potential Energy: When an object has potential to have work done on it, it is said to have potential

PHY121 #8 Midterm I

AP Physics C Fall Final Web Review

Sample Questions for the AP Physics 1 Exam

Fundamental Mechanics: Supplementary Exercises

When showing forces on diagrams, it is important to show the directions in which they act as well as their magnitudes.

W02D2-2 Table Problem Newton s Laws of Motion: Solution

Midterm Solutions. mvr = ω f (I wheel + I bullet ) = ω f 2 MR2 + mr 2 ) ω f = v R. 1 + M 2m

Supplemental Questions

B Answer: neither of these. Mass A is accelerating, so the net force on A must be non-zero Likewise for mass B.

Difference between a vector and a scalar quantity. N or 90 o. S or 270 o

Chapter 11 Equilibrium

Structural Axial, Shear and Bending Moments

4 Gravity: A Force of Attraction

physics 111N work & energy

Chapter 7: Momentum and Impulse

Acceleration due to Gravity

10.1 Quantitative. Answer: A Var: 50+

A) N > W B) N = W C) N < W. speed v. Answer: N = W

PHYSICS 111 HOMEWORK SOLUTION, week 4, chapter 5, sec 1-7. February 13, 2013

Section 6.4: Work. We illustrate with an example.

Laboratory Report Scoring and Cover Sheet

P211 Midterm 2 Spring 2004 Form D

Newton s Laws. Physics 1425 lecture 6. Michael Fowler, UVa.

AP Physics 1 Midterm Exam Review

FRICTION, WORK, AND THE INCLINED PLANE

Physics 590 Homework, Week 6 Week 6, Homework 1

Physical Science Chapter 2. Forces

Tennessee State University

Lecture-IV. Contact forces & Newton s laws of motion

Solving Newton s Second Law Problems

Solution Derivations for Capa #11

Resistance in the Mechanical System. Overview

Conservative vs. Non-conservative forces Gravitational Potential Energy. Work done by non-conservative forces and changes in mechanical energy

WORK DONE BY A CONSTANT FORCE

Physics 1120: Simple Harmonic Motion Solutions

Kinetic Energy (A) stays the same stays the same (B) increases increases (C) stays the same increases (D) increases stays the same.

Unit 3 Work and Energy Suggested Time: 25 Hours

Work, Power, Energy Multiple Choice. PSI Physics. Multiple Choice Questions

Name Class Period. F = G m 1 m 2 d 2. G =6.67 x Nm 2 /kg 2

The Big Idea. Key Concepts

University Physics 226N/231N Old Dominion University. Getting Loopy and Friction

PHYS 211 FINAL FALL 2004 Form A

III. Applications of Force and Motion Concepts. Concept Review. Conflicting Contentions. 1. Airplane Drop 2. Moving Ball Toss 3. Galileo s Argument

Transcription:

Name (First AND Last): Date: Goal: Drawing and Using Free-Body Diagrams Adapted from Minds on Physics Activity #51: Recognizing and Interpreting Free-Body Diagrams After completing this activity, you should be able to draw valid free-body diagrams. Also, you should be able to use free-body diagrams to write expressions for the components of the net force. Explanation of Activity and Examples: You will draw valid free-body diagrams for blocks in a variety of situations. PART A: Drawing Free-Body Diagrams For each block in each situation, draw and label a valid free-body diagram to describe the forces acting on it. (Note: You should ignore the forces of air resistance and buoyancy in this activity.) E1. A block of mass m is support from the ceiling by two ropes as shown. Notes: There are two ropes, so this object: The sketch of the block there are two tension forces, labeled FT1 and/or the and FT2. The force of gravitation points straight down. There are many ways to draw the free-body diagram for this object: The sketch of the block and/or be missing, or the be moved to one side.

Al. A block of mass m is suspended from the ceiling by a light string. A2. A block having mass m is pulled by a horizontal force F a in the positive x- direction along a rough, horizontal surface. A3. A block of mass ml is suspended from the ceiling by a rope. Attached to the bottom of m1 is a second rope, from which a second mass, m2, hangs.

A4. 100kg block is pushed up a smooth (frictionless) ramp by a horizontal force, F a = 2000N. The ramp makes an angle of 30 relative to the horizontal. A5. Two blocks, having masses m 1 = 5kg and m 2 = 10kg, are in contact and sit side-by-side on a smooth, horizontal surface. A force F a directed to the right is applied to ml and both blocks accelerate with a = 2m/s 2

A6. A 5kg block is at rest on a smooth ramp that makes an angle of 30 with the horizontal. The block is supported by a spring placed at the bottom of the ramp. A7. A block of mass m is attached to a string and released from rest when the string is horizontal. (Draw the free-body diagram for the block at the instant shown.)

Summary How are the forces in a free-body diagram related to the net force exerted on an object? The net force is the vector sum of all the external forces exerted on the object, and therefore, it should never appear in a free-body diagram. After all, it is in essence already there! How can I make my free-body diagrams as useful as possible? First of all, you should make sure that the directions of all your forces are accurately drawn. This will help you find the components of the forces, which will help you find the net force, and ultimately, the acceleration of the object. Then, if the sizes of the force vectors are also drawn accurately, often we can identify the direction of the net force F net. By Newton's second law, an object will always accelerate in the same direction as F net. Therefore, the net force implied by your free-body diagram should always be consistent with the magnitude and/or the direction of the object's acceleration (if either is known). For example, an object at rest or traveling with constant velocity has zero acceleration. In this instance, the vectors in your free-body diagram should add to zero, as closely as possible. What if the acceleration of the object is non-zero? Sometimes, we do not know the magnitude of the acceleration, particularly before we have solved the problem! Often we want to solve for the acceleration of an object. Even if we do not yet know the magnitude of the acceleration, sometimes we know its direction. For instance, if an object is sliding along a flat surface, we know that the velocity always points parallel to the surface. Therefore, all changes in velocity (as well as accelerations) also point parallel to the surface. Thus, the direction of the net force is known. Your free-body diagrams should be consistent with this fact. F net should point parallel to the surface; there should be no component of F net perpendicular to the surface.