NB: All the figures are modifiable and can be provided as a PPT file, so do not hesitate to contact Maggy Fostier to get the files.

Similar documents
Cystic Fibrosis Webquest Sarah Follenweider, The English High School 2009 Summer Research Internship Program

Heredity - Patterns of Inheritance

1 Mutation and Genetic Change

This fact sheet describes how genes affect our health when they follow a well understood pattern of genetic inheritance known as autosomal recessive.

Name: 4. A typical phenotypic ratio for a dihybrid cross is a) 9:1 b) 3:4 c) 9:3:3:1 d) 1:2:1:2:1 e) 6:3:3:6

Genetic Mutations. Indicator 4.8: Compare the consequences of mutations in body cells with those in gametes.

A and B are not absolutely linked. They could be far enough apart on the chromosome that they assort independently.

SICKLE CELL ANEMIA & THE HEMOGLOBIN GENE TEACHER S GUIDE

Genetics 1. Defective enzyme that does not make melanin. Very pale skin and hair color (albino)

Chapter 4 Pedigree Analysis in Human Genetics. Chapter 4 Human Heredity by Michael Cummings 2006 Brooks/Cole-Thomson Learning

Genetics Lecture Notes Lectures 1 2

12.1 The Role of DNA in Heredity

The correct answer is c A. Answer a is incorrect. The white-eye gene must be recessive since heterozygous females have red eyes.

Name: Class: Date: ID: A

Mendelian and Non-Mendelian Heredity Grade Ten

Genetics Module B, Anchor 3

A trait is a variation of a particular character (e.g. color, height). Traits are passed from parents to offspring through genes.

Practice Problems 4. (a) 19. (b) 36. (c) 17

Evolution (18%) 11 Items Sample Test Prep Questions

Heredity. Sarah crosses a homozygous white flower and a homozygous purple flower. The cross results in all purple flowers.

Can receive blood from: * I A I A and I A i o Type A Yes No A or AB A or O I B I B and I B i o Type B No Yes B or AB B or O

Alpha-1 Antitrypsin Deficiency A future NBS candidate?

GENETIC CROSSES. Monohybrid Crosses

Patient Information. for Childhood

Bio 102 Practice Problems Genetic Code and Mutation

Bio EOC Topics for Cell Reproduction: Bio EOC Questions for Cell Reproduction:

Chromosomes, Mapping, and the Meiosis Inheritance Connection

CCR Biology - Chapter 7 Practice Test - Summer 2012

Mendelian inheritance and the

BioBoot Camp Genetics

Chapter 9 Patterns of Inheritance

The Developing Person Through the Life Span 8e by Kathleen Stassen Berger

CHAPTER 15 THE CHROMOSOMAL BASIS OF INHERITANCE. Section B: Sex Chromosomes

Terms: The following terms are presented in this lesson (shown in bold italics and on PowerPoint Slides 2 and 3):

Hardy-Weinberg Equilibrium Problems

AP BIOLOGY 2010 SCORING GUIDELINES (Form B)

Respiration occurs in the mitochondria in cells.

Gene mutation and molecular medicine Chapter 15

Genetic Technology. Name: Class: Date: Multiple Choice Identify the choice that best completes the statement or answers the question.

Long-Term Effects of Drug Addiction

B2 5 Inheritrance Genetic Crosses

Trasposable elements: P elements

About The Causes of Hearing Loss

Organelle Speed Dating Game Instructions and answers for teachers

Lecture 3: Mutations

UNIT 13 (OPTION) Genetic Abnormalities

Human Blood Types: Codominance and Multiple Alleles. Codominance: both alleles in the heterozygous genotype express themselves fully

Tuesday 14 May 2013 Morning

MCAS Biology. Review Packet

Influence of Sex on Genetics. Chapter Six

The Making of the Fittest: Natural Selection in Humans

Marrying a relative. Is there an increased chance that a child will have genetic problems if its parents are related to each other?

PRACTICE PROBLEMS - PEDIGREES AND PROBABILITIES

Biology 1406 Exam 4 Notes Cell Division and Genetics Ch. 8, 9

CHROMOSOMES AND INHERITANCE

Biology Final Exam Study Guide: Semester 2

Lecture 6: Single nucleotide polymorphisms (SNPs) and Restriction Fragment Length Polymorphisms (RFLPs)

(1-p) 2. p(1-p) From the table, frequency of DpyUnc = ¼ (p^2) = #DpyUnc = p^2 = ¼(1-p)^2 + ½(1-p)p + ¼(p^2) #Dpy + #DpyUnc

BCOR101 Midterm II Wednesday, October 26, 2005

somatic cell egg genotype gamete polar body phenotype homologous chromosome trait dominant autosome genetics recessive

How Cancer Begins???????? Chithra Manikandan Nov 2009

LAB : THE CHI-SQUARE TEST. Probability, Random Chance, and Genetics

Why are some drugs only available on prescription? Depressants. Pain killers. Stimulants. Performance enhancers. Hallucinogens

Biology Notes for exam 5 - Population genetics Ch 13, 14, 15

Genetic Testing in Research & Healthcare

Chapter 8: Recombinant DNA 2002 by W. H. Freeman and Company Chapter 8: Recombinant DNA 2002 by W. H. Freeman and Company

Thymine = orange Adenine = dark green Guanine = purple Cytosine = yellow Uracil = brown

Basic Concepts Recombinant DNA Use with Chapter 13, Section 13.2

Sickle cell anemia: Altered beta chain Single AA change (#6 Glu to Val) Consequence: Protein polymerizes Change in RBC shape ---> phenotypes

The chemical reactions inside cells are controlled by enzymes. Cells may be specialised to carry out a particular function.

Biological Sciences Initiative. Human Genome

AP: LAB 8: THE CHI-SQUARE TEST. Probability, Random Chance, and Genetics

Helen Geeson BSc PGCE. Background

Mutation and its consequences. Notes at: tcd.ie/biology_teaching_centre/local/ junior-freshman/ by1101local

Lecture 13: DNA Technology. DNA Sequencing. DNA Sequencing Genetic Markers - RFLPs polymerase chain reaction (PCR) products of biotechnology

DNA Determines Your Appearance!

LECTURE 6 Gene Mutation (Chapter )

Causes of Birth Defects

Chapter 4 The role of mutation in evolution

Activity 4 Long-Term Effects of Drug Addiction

Mendelian Genetics in Drosophila

How To Understand How Gene Expression Is Regulated

Gene Therapy and Genetic Counseling. Chapter 20

March 19, Dear Dr. Duvall, Dr. Hambrick, and Ms. Smith,

Genomes and SNPs in Malaria and Sickle Cell Anemia

14.3 Studying the Human Genome

ISTEP+: Biology I End-of-Course Assessment Released Items and Scoring Notes

Mitosis, Meiosis and Fertilization 1

Chapter 3. Chapter Outline. Chapter Outline 9/11/10. Heredity and Evolu4on

Muscular Dystrophy: Stem Cell Therapy

Problems 1-6: In tomato fruit, red flesh color is dominant over yellow flesh color, Use R for the Red allele and r for the yellow allele.

Summary Genes and Variation Evolution as Genetic Change. Name Class Date

GCSE Additional Science Biology Contents Guide

Continuous and discontinuous variation

Answer Key Problem Set 5

Name Class Date. Figure Which nucleotide in Figure 13 1 indicates the nucleic acid above is RNA? a. uracil c. cytosine b. guanine d.

CCR Biology - Chapter 9 Practice Test - Summer 2012

Replication Study Guide

7A The Origin of Modern Genetics

Umm AL Qura University MUTATIONS. Dr Neda M Bogari

Transcription:

Title Workshop on genetic disease and gene therapy Authors Danielle Higham (BSc Genetics), Dr. Maggy Fostier Contact Maggy.fostier@manchester.ac.uk Target level KS4 science, GCSE (or A-level) Publication date July 03 NB: All the figures are modifiable and can be provided as a PPT file, so do not hesitate to contact Maggy Fostier to get the files. Activity Effect of mutations on proteins Can you predict if this patient has Cystic Fibrosis? Introduction to gene therapy Length Content included from the GCSE curriculum 5 Genetic diseases; mins DNA encodes for proteins Terminology: chromosome; gene; allele; proteins; enzymes 5 mins 0 mins Monohybrid inheritance Terminology: genotype; phenotype; dominant; recessive; (un)affected ; carrier; cystic fibrosis Structure of animal cells Terminology: chromosome; gene; allele; nucleus Building on the GCSE curriculum Mutations in DNA can result in non- or partially functional proteins Terminology: ligand; receptor; protein complex; mutations Phenotype resulting from the addition of an extra healthy allele (as in gene therapy). Terminology: compound heterozygote Gene therapy procedure Terminology: Gene expression; target cells; trisomy. The three activities follow a natural progression but all can be performed independently. - Activity gets students to draw the effects of mutations on the resulting proteins. Three activity cards illustrate different types of proteins and help define a dominant versus recessive effect. - Activity gets students to predict based on genotype whether a patient will have cystic fibrosis. The transition to gene therapy is made by asking what would happen if a copy of a healthy allele was added to the genome of each patient. - Activity 3 introduces the process of gene therapy and gets students to think about why certain aspects of this technique may be performed as it is.

Workshop on genetic disease and gene therapy Activity : Effect of mutations on proteins 5-0 mins. This activity gets students to draw the effects of mutations on the resulting proteins. Three activity cards illustrate different types of proteins and help define a dominant versus recessive effect. Students work in pairs. The cards below are within a PowerPoint presentation and the slides are modifiable. Each pair should have copy of each slide or the slides could be projected. The introduction card (if needed) shows that we have two alleles for each gene and each allele produces many copies of the protein it encodes. Effect of mutations on proteins - Introduction A gene is a section of DNA that codes for a specific protein. Each gene is made up of two alleles (one on each chromosome), each coding for proteins. allele allele Proteins made from allele chromosome Proteins made from allele If a mutation occurs in the DNA of an allele, the protein made may have an incorrect structure and not work properly. Alternatively, some mutations can result in no protein being made at all. The tasks below will make you explore the differences between normal and mutated proteins and how changes in their structure can affect their interactions and function. Activity card : [ next page]

Effect of mutations on proteins - Task Some proteins act as an enzyme. Below is an enzyme with two active sites for substrates and. Allele Here students should see that mutations can have multiple effects on proteins and that you need the same mutation on both alleles to get a homozygous effect. Variant: Get students to draw only one mutated protein. Would it affect the overall function of the cell/body? i.e. Is it likely to result in a recessive or dominant effect? Answer: Probably recessive as the normal enzyme will compensate up to a good level. Activity card : Allele Task: Draw a mutated form of the enzyme for each allele, preventing either substrate to fit into the active sites. The mutations in the two alleles should be the same. Effect of mutations on proteins - Task Some proteins act as receptor for other proteins called ligand. After binding with a ligand, the structure of a receptor changes. One result of this could be that a second molecule binds to the receptor as shown below: The ligand is not bound The ligand is bound Receptor default structure Receptor changed structure Allele The second molecule cannot bind The second molecule CAN bind Allele Task: Draw a mutated form of the receptor for each allele, preventing the ligand from binding. The mutations in the two alleles should be different. What happens when the ligand can no longer bind to the receptor?

Here students should appreciate that a person can carry two different mutations (compound heterozygote). This is usually what happens in Cystic Fibrosis Variant: Get students to draw only one mutated protein. Would it affect the overall function of the cell? i.e. Is it likely to result in a recessive or dominant effect? Answer: Probably recessive as the normal receptor will compensate up to a good level. Activity card 3: Effect of mutations on proteins - Task 3 Some proteins need to form complexes to carry out their function. Below is a complex made by 6 identical proteins interacting with each other. Proteins from allele and assemble randomly into these complexes. Allele Possible complex A Possible complex B Allele Possible complex D Possible complex C Task: Draw a mutant shape of the protein produced by allele so that it can not longer assemble with the other proteins. Which of the possible complex presented will be affected? The answer is that all complexes but complex C (only made of proteins from allele ) will be affected. Here students should appreciate that this is how a mutation can have a dominant effect. This happens in the disease called Osteogenesis imperfecta or Brittle bone disease, where type I collagen is not produced and so the collagen filaments (protein complexes made of several different proteins) cannot form. Variant. Instead of drawing the proteins, the students could cut them out (more hands on, but takes longer).

Activity : Can you predict if this patient has Cystic Fibrosis? 0 mins This activity gets students to predict based on genotype whether a patient will have cystic fibrosis. The transition to gene therapy is made by asking what would happen if a copy of a healthy allele was added to the genome of each patient. Students work in pairs. The card below is within a PowerPoint presentation and the slide is modifiable. Each pair should have copy of the slide or the slide could be projected. Cystic fibrosis is a disease caused by mutations in a gene coding for a receptor. These mutations are usually recessive. Task: Predict the phenotype of each patient. Patient A Genotype Phenotype? Phenotype? Gene Allele Allele Healthy? Ill? Healthy but carrier of CF? + therapy intervention Healthy? Ill? Healthy but carrier of CF? Patient B Recessive CF- allele + Patient C Recessive CF- allele Recessive CF- allele + Patient D Recessive CF- allele Recessive CF- allele + Patient Phenotype Phenotype after gene therapy A Healthy Healthy (although actually having three healthy copies of the gene could lead to over-expression and problems). B Healthy but Healthy but carrier carrier C ill Healthy but carrier ** D ill * Healthy but carrier ** * Card of the previous activity can be used to illustrate the types of mutation that the mutations in yellow or red could be. ** Adding one extra copy of a normal allele to a patient who carries two recessive mutations is equivalent to cancelling out the effect of one mutation, thus bringing this person back to a normal healthy but carrier status. For a carrier, an extra copy does not change their carrier status as they can still pass on this allele to their progeny.

NB: The normal allele is neither dominant nor recessive. In combination with a recessive mutation (as here), it is dominant because the normal protein can compensate for the loss of protein function from the mutant. In combination with a dominant mutation, it will behave either as co-dominant or recessive, as the normal protein will only partially compensate or not at all the loss of protein function from the mutant. If you think that adding dominant in the normal allele box may confuse students, then remove it. This slide illustrates the take home message that gene therapy is the addition of a normal allele to the genome to cancel out the effect of a mutation by adding a dose of normal proteins to the cell gene therapy is rarely the replacement of a faulty gene. Activity 3: Introduction to gene therapy. 0 mins Activity 3 introduces the process of gene therapy and gets students to think about why certain aspects of this technique may be performed as it is. Students work in pairs. The card below is within a PowerPoint presentation and the slide is modifiable. The worksheet in on the next page Each pair should have copy of the slide or the slide could be projected. Effect of gene therapy on a patient suffering from Cystic Fibrosis. Our patient is affected by CF because he has two copies of a recessive mutation (red below). The gene therapy process consists of adding a copy of the normal allele into the genome of the cells that need it for their function (e.g. cells from the lungs). Step Step Isolate a normal allele Replicate the normal allele Step 3 Put one copy of the normal allele into the patient s cells that need treatment Red: patient s mutated alleles on chromosome 7 Blue: One copy of the normal allele gets inserted randomly in the genome. It will produce enough normal protein to compensate for the bad proteins produced by the red alleles. Let s magnify the nucleus

Worksheet for gene therapy. NB: Question 3, 4 and 6 are very advanced; just do your best. Q: Is the disorder being treated here dominant / recessive? Q: This patient has two mutated, disease causing alleles. In step, we isolate the normal allele. Where do you think we could we isolate the normal allele from in order to treat him?. Q3: During gene therapy, we insert one copy of a normal allele per cell that needs it. Why don t we insert a whole chromosome from a healthy patient instead? Q4: Why is the normal allele not inserted into every cell of the patient (e.g. for CF we aim at the lungs and not the brain nor the heart)? Q5: Where does the copy of the normal allele inserts in the cell nucleus? Q6: This patient has two mutated allele in its genome, why do we insert only one copy of the normal allele in the cells that need, instead of copies?

Q7: Select the answer that best summarises the diagram on the card (A, B, C, D, E, or F).

Worksheet for gene therapy. Answers. Q: Is the disorder being treated here dominant / recessive? Recessive. Q: This patient has two mutated, disease causing alleles. In step, we isolate the normal allele. Where do you think we could we isolate the normal allele from in order to treat him? Cells from a person who does not have the disorder. Q3: During gene therapy, we insert one copy of a normal allele per cell that needs it. Why don t we insert a whole chromosome from a healthy patient instead? The normal chromosome would be too big and complicated to insert, but more worryingly, ) it would cause these cells to have a trisomy of chromosome 7, i.e. three copies of chromosome 7, i.e. each gene on chromosome 7 would have 3 alleles (instead of ), each producing proteins. This is a problem because our body is designed for the amount of proteins produced by alleles, and in the same way that having too little protein produced is problematic, having too much protein is not good either. Trisomy is also the term for genetic conditions that can occur when the gametes are being formed. It is usually lethal before birth or causes huge problems in development (e.g. trisomy 3 or ). Q4: Why is the normal allele not inserted into every cell of the patient (e.g. for CF we aim at the lungs and not the brain nor the heart)? Only few genes are required in every cell or our body. Most genes are only expressed as proteins in a subset of cells, e.g. the CF receptor is expressed and used in the lungs and not the brain. This is actually good news for gene therapy because we would not know how to insert the normal allele in all cells. Q5: Where does the copy of the normal allele inserts in the cell nucleus? Randomly on any chromosome. Q6: This patient has two mutated allele in its genome, why do we insert only one copy of the normal allele in the cells that need, instead of copies?

The main reason is that this random integration of the extra allele on any chromosome can cause mutations/problems in the neighbouring genes of the insertion sites, so inserting one copy is already risky. One copy is also enough as it will produce enough protein to compensate for the loss or not functional proteins in the target cells. Q7: Select the answer that best summarises the diagram on the card (A, B, C, D, E, or F). Answer: E But note that scientists also try to conduct gene therapy with method D and F, as explained on this concise and accurate webpage: http://www.news-medical.net/health/what-is-gene-therapy.aspx