CARBONYL COMPOUNDS - Aldehydes and Ketones



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arbonyl compounds F324 1 ARBYL MPUDS - Aldehydes and Ketones Structure carbonyl groups consists of a carbon-oxygen double bond the bond is polar due to the difference in electronegativity aldehydes / ketones differ in what is attached to the carbon ALDEYDES - at least one attached to the carbonyl group = or = 3 6 5 KETES - two carbons attached to the carbonyl group = 3 3 2 5 3 6 5 3 Bonding the carbonyl carbon is sp 2 hybridised and three sigma (σ) bonds are planar the unhybridised 2p orbital of carbon is at 90 to these it overlaps with a 2p orbital of oxygen to form a pi (π) bond as oxygen is more electronegative than carbon the bond is polar aming aldehydes end in... AL ketones end in... E pick the longest chain of carbon atoms which includes the = substituent positions are based on the carbon with the attached 3 2 2 2 2 3 2 2 2 3 hexanal hexan-2-one Q.1 Draw structures for, and name, all the carbonyl compounds with molecular formulae; a) 4 8 b) 5 10 c) 6 12

2 F324 arbonyl compounds Formation of carbonyl compounds from alcohols Aldehydes xidation of primary (1 ) alcohols - risk of oxidation to acids eg 3 2 (l) + [] > 3 (l) + 2 (l) ethanol ethanal however, this can happen 3 (l) + [] > 3 (l) ethanal ethanoic acid it is essential to distil off the aldehyde before it gets oxidised to the acid the alcohol is dripped into a warm solution of acidified K 2 r 2 7 the aldehyde has a low boiling point - no hydrogen bonding - it distils off if it didn t distil off it would be oxidised to the equivalent carboxylic acid to oxidise an alcohol straight to the acid you would reflux the mixture DISTILLATI gives an ALDEYDE REFLUXIG gives a ARBXYLI AID Ketones xidation of secondary (2 ) alcohols. eg 3 3 (l) + [] > 3 3 (l) + 2 (l) propan-2-ol propanone Q.2 Which alcohol would you use to make the following? 2 5 2 5 3 hexanal 3-methylhexan-2-one 3-methylpentanal

arbonyl compounds F324 3 EMIAL PRPERTIES F ARBYL MPUDS XIDATI provides a way of differentiating between aldehydes and ketones mild oxidising agents are best aldehydes are easier to oxidise powerful oxidising agents oxidise ketones to carboxylic acid mixtures ALDEYDES easily oxidised to acids e.g. R(l) + [] > R(l) 3 (l) + [] > 3 (l) KETES only oxidised under vigorous conditions to acids with fewer carbons. e.g. 2 5 2 3 (l) + 3 [] > 2 5 (l) + 3 (l) Q.3 What product (if any) is formed when the following undergo mild oxidation? 2 5 2 5 3 hexanal 3-methylhexan-2-one 3-methylpentanal cyclohexanone

4 F324 arbonyl compounds IDETIFYIG A ARBYL MPUD Methods characteristically strong peak at 1400-1600 cm -1 in the infra red spectrum or formation of orange crystalline precipitate with 2,4-dinitrophenylhydrazine BUT to narrow it down to an aldehyde or ketone you must do a second test Differentiation to distinguish an aldehyde from a ketone you need a mild oxidising agent... Tollens Reagent ammoniacal silver nitrate contains the diammine silver(i) ion - [Ag( 3 ) 2 ] + acts as a mild oxidising agent and will oxidise aldehydes but not ketones the silver(i) ion is reduced to silver Ag + (aq) + e > Ag(s) the test is known as TE SILVER MIRRR TEST Fehling s Solution contains copper(ii) ions complexed with tartrate ions on warming, it will oxidise aliphatic (but not aromatic) aldehydes copper(ii) is reduced to a red precipitate of copper(i) oxide, u 2 The silver mirror test is the better alternative as it works with all aldehydes. Ketones do not react with Tollens Reagent or Fehling s Solution. Q.4 Which of the following produce an orange precipitate with 2,4-dinitrophenylhydrazine? 2 5 2 5 3 hexanal 3-methylhexan-2-one cyclohexanol 3-methylpentan-1-ol Q.5 Which of the following produce a silver mirror with Tollens reagent? 2 5 2 5 3 hexanal 3-methylhexan-2-one cyclohexanone 3-methylpentanal

arbonyl compounds F324 5 ULEPILI ADDITI REATIS Mechanism occurs with both aldehydes and ketones involves addition to the polar = double bond attack is by nucleophiles at the positive carbon centre alkenes are non-polar and are attacked by electrophiles Bond Polarity Attacked by Result arbonyl = Polar ucleophiles Addition Alkene = on-polar Electrophiles Addition REDUTI Reagent sodium tetrahydridoborate(iii) (sodium borohydride), ab 4 onditions Mechanism ucleophile aqueous or alcoholic solution ucleophilic addition (also reduction as it is addition of ) (hydride ion) Product(s) Aldehydes REDUED to primary (1 ) alcohols Ketones REDUED to secondary (2 ) alcohols Equation(s) 3 + 2[] > 3 2 3 3 + 2[] > 3 3 3 3 3 + Step 1 is a nucleophile and attacks the δ+ An electron pair from the = moves onto making it -ive Step 2 A lone pair on oxygen removes a proton from water verall, there is addition of hydrogen (reduction) Q.6 Draw a diagram to indicate the bonding in ab 4.

6 F324 arbonyl compounds Alternative Method Reagent hydrogen onditions Reaction type catalyst - nickel or platinum ydrogenation, reduction Equation(s) 3 + 2 > 3 2 3 3 + 2 > 3 3 ote ydrogen also reduces = bonds e.g. 2 = + 2 2 > 3 2 2 Q.7 Why are = double bonds T reduced when ab 4 is used? Q.8 Draw structures of the organic products formed when the following are reduced using... ab 4 2 = 2 2

arbonyl compounds F324 7 Reagent hydrogen cyanide - (in the presence of K) onditions ucleophile Product(s) reflux in alkaline solution cyanide ion hydroxynitrile (cyanohydrin) Equation 3 + > 3 () 2-hydroxypropanenitrile Mechanism ucleophilic addition 3 _ 3 + 3 Step 1 acts as a nucleophile and attacks the slightly positive ne of the = bonds breaks; a pair of electrons goes onto the Step 2 A pair of electrons is used to form a bond with + verall, there has been addition of otes is a weak acid ; + + few ions produced the reaction is catalysed by alkali - produces more of the nucleophilic watch out for the possibility of optical isomerism in hydroxynitriles attacks from above 3 _ 3 + 3 attacks from below 3 _ 3 + 3

8 F324 arbonyl compounds 2,4-DIITRPEYLYDRAZIE 6 3 ( 2 ) 2 2 2 2 Theory reacts with carbonyl compounds (aldehydes and ketones) used as a simple test for aldehydes and ketones makes orange crystalline derivatives - 2,4-dinitrophenylhydrazones derivatives have sharp, well-defined melting points also used to characterise (identify) carbonyl compounds. 2 Identification A simple way of characterising a compound (finding out what it is) is to measure the melting point of a solid the boiling point of a liquid The following structural isomers have similar boiling points because of similar van der Waals forces and dipole-dipole interactions. They would be impossible to identify with any precision using boiling point determination. isomeric chlorophenylmethanals l Boiling point of compound 213 214 214 Melting point of 2,4-dnph derivative 209 248 265 l l By forming the 2,4-dinitrophenylhydrazone derivatives and taking the melting point of the purified, crystalline product, it is easy to identify the original compound. Typical equation 2 2 3 2 + 3 + 2 2 2 Mechanism ADDITI-ELIMIATI

arbonyl compounds F324 9 Q.6 Suggest a method for differentiating between the following. What would be seen? 2 5 and 2 5 3 3 7 3 and 2 5 2 5 hexanal and hexanone Q.5 Write out equations for the reactions between and... 2 5 + > 3 3 + > hexanal + > Indicate which reactions give rise to optically active organic compounds? Why is the addition of such a useful reaction?