Determination of Equilibrium Constants using NMR Spectroscopy



Similar documents
Determination of Equilibrium Constants using NMR Spectrscopy

Proton Nuclear Magnetic Resonance Spectroscopy

Organic Chemistry Tenth Edition

Proton Nuclear Magnetic Resonance Spectroscopy

Used to determine relative location of atoms within a molecule Most helpful spectroscopic technique in organic chemistry Related to MRI in medicine

Nuclear Magnetic Resonance Spectroscopy

The Four Questions to Ask While Interpreting Spectra. 1. How many different environments are there?

13C NMR Spectroscopy

Nuclear Magnetic Resonance Spectroscopy

Chapter 13 Spectroscopy NMR, IR, MS, UV-Vis

Proton Nuclear Magnetic Resonance ( 1 H-NMR) Spectroscopy

Determining the Structure of an Organic Compound

PROTON NUCLEAR MAGNETIC RESONANCE SPECTROSCOPY (H-NMR)

Nuclear Magnetic Resonance notes

NMR SPECTROSCOPY A N I N T R O D U C T I O N T O... Self-study booklet NUCLEAR MAGNETIC RESONANCE δ PUBLISHING

Peptide Bonds: Structure

Chapter 5 Classification of Organic Compounds by Solubility

For example: (Example is from page 50 of the Thinkbook)

Solving Spectroscopy Problems

Background A nucleus with an odd atomic number or an odd mass number has a nuclear spin that can be observed by NMR spectrometers.

Chapter 2 Polar Covalent Bonds; Acids and Bases

Combinatorial Biochemistry and Phage Display

18.2 Protein Structure and Function: An Overview

4. It is possible to excite, or flip the nuclear magnetic vector from the α-state to the β-state by bridging the energy gap between the two. This is a

INFRARED SPECTROSCOPY (IR)

Paper: 6 Chemistry University I Chemistry: Models Page: 2 of Which of the following weak acids would make the best buffer at ph = 5.0?

Name Lab #3: Solubility of Organic Compounds Objectives: Introduction: soluble insoluble partially soluble miscible immiscible

Chapter 11 Structure Determination: Nuclear Magnetic Resonance Spectroscopy. Nuclear Magnetic Resonance Spectroscopy Nuclear Magnetic Resonance

This class deals with the fundamental structural features of proteins, which one can understand from the structure of amino acids, and how they are

Role of Hydrogen Bonding on Protein Secondary Structure Introduction

Lecture 15: Enzymes & Kinetics Mechanisms

Peptide Bond Amino acids are linked together by peptide bonds to form polypepetide chain.

Infrared Spectroscopy 紅 外 線 光 譜 儀

Peptide bonds: resonance structure. Properties of proteins: Peptide bonds and side chains. Dihedral angles. Peptide bond. Protein physics, Lecture 5

IR Applied to Isomer Analysis

Chemical Bonds and Groups - Part 1

Amino Acids. Amino acids are the building blocks of proteins. All AA s have the same basic structure: Side Chain. Alpha Carbon. Carboxyl. Group.

Nuclear Magnetic Resonance (NMR) Wade Textbook

The peptide bond Peptides and proteins are linear polymers of amino acids. The amino acids are

Survival Organic Chemistry Part I: Molecular Models

Nuclear Magnetic Resonance

Examination of Proton NMR Spectra

Hydrogen Bonds The electrostatic nature of hydrogen bonds

Signal Manipulation. time domain NMR signal in MHz range is converted to khz (audio) range by mixing with the reference ( carrier ) frequency

Amino Acids as Acids, Bases and Buffers:

Ionization of amino acids

IV. -Amino Acids: carboxyl and amino groups bonded to -Carbon. V. Polypeptides and Proteins

INTERMOLECULAR FORCES

Advanced Medicinal & Pharmaceutical Chemistry CHEM 5412 Dept. of Chemistry, TAMUK

NMR - Basic principles

Introduction to Nuclear Magnetic Resonance Spectroscopy

EXPERIMENT 5: DIPEPTIDE RESEARCH PROJECT

Lecture #7 (2D NMR) Utility of Resonance Assignments

How to Quickly Solve Spectrometry Problems

Symmetric Stretch: allows molecule to move through space

Chemistry 307 Chapter 10 Nuclear Magnetic Resonance

NMR and other Instrumental Techniques in Chemistry and the proposed National Curriculum.

electron does not become part of the compound; one electron goes in but two electrons come out.

Chapter 2 Polar Covalent Bonds: Acids and Bases

Introduction, Noncovalent Bonds, and Properties of Water

MCAT Organic Chemistry - Problem Drill 23: Amino Acids, Peptides and Proteins

Nuclear Magnetic Resonance Spectroscopy

Nuclear Magnetic Resonance (NMR) Spectroscopy cont... Recommended Reading:

Chemical Basis of Life Module A Anchor 2

Ultraviolet Spectroscopy

Chapter 3 Molecules of Cells

CHE334 Identification of an Unknown Compound By NMR/IR/MS

NMR SPECTROSCOPY. Basic Principles, Concepts, and Applications in Chemistry. Harald Günther University of Siegen, Siegen, Germany.

for excitation to occur, there must be an exact match between the frequency of the applied radiation and the frequency of the vibration

Structure of proteins

HOMEWORK PROBLEMS: IR SPECTROSCOPY AND 13C NMR. The peak at 1720 indicates a C=O bond (carbonyl). One possibility is acetone:

Determination of Molecular Structure by MOLECULAR SPECTROSCOPY

4. Which carbohydrate would you find as part of a molecule of RNA? a. Galactose b. Deoxyribose c. Ribose d. Glucose

H 2O gas: molecules are very far apart

Molecular Cell Biology

Organic Spectroscopy

Separation of Amino Acids by Paper Chromatography

Previously published in Biophysical Society On-line Textbook PROTEINS CHAPTER 1. PROTEIN STRUCTURE. Section 1. Primary structure, secondary motifs,

CHEM 51LB EXP 1 SPECTROSCOPIC METHODS: INFRARED AND NUCLEAR MAGNETIC RESONANCE SPECTROSCOPY

Nuclear Shielding and 1. H Chemical Shifts. 1 H NMR Spectroscopy Nuclear Magnetic Resonance

In addition to being shorter than a single bond, the double bonds in ethylene don t twist the way single bonds do. In other words, the other atoms

Chemical Bonds. Chemical Bonds. The Nature of Molecules. Energy and Metabolism < < Covalent bonds form when atoms share 2 or more valence electrons.

Massachusetts Institute of Technology Department of Chemistry 5.33 Advanced Chemical Instrumentation FALL SEMESTER 2005

NMR Nuclear Magnetic Resonance

m/z

Acids and Bases. but we will use the term Lewis acid to denote only those acids to which a bond can be made without breaking another bond

Copyright by Mark Brandt, Ph.D. 12

Infrared Spectroscopy

3.4 BRØNSTED LOWRY ACIDS AND BASES

NMR Spectroscopy of Aromatic Compounds (#1e)

Time out states and transitions

Biological Molecules

RESONANCE, USING CURVED ARROWS AND ACID-BASE REACTIONS

Preliminary MFM Quiz

Which substance contains positive ions immersed in a sea of mobile electrons? A) O2(s) B) Cu(s) C) CuO(s) D) SiO2(s)

Bonds. Bond Length. Forces that hold groups of atoms together and make them function as a unit. Bond Energy. Chapter 8. Bonding: General Concepts

The Experiment Some nuclei have nuclear magnetic moments; just as importantly, some do not

A pure covalent bond is an equal sharing of shared electron pair(s) in a bond. A polar covalent bond is an unequal sharing.

Acids and Bases: Molecular Structure and Acidity

Lecture Overview. Hydrogen Bonds. Special Properties of Water Molecules. Universal Solvent. ph Scale Illustrated. special properties of water

Transcription:

CHEM 331L Physical Chemistry Laboratory Revision 2.1 Determination of Equilibrium Constants using NMR Spectroscopy In this laboratory exercise we will measure the equilibrium constant for the cis-trans isomerism about a peptide bond involving the amino acid L-Proline. This will be accomplished by determining the relative concentrations of each isomer using key proton signals in a Nuclear Magnetic Resonance (NMR) spectrum of a solution of an N-Acetyl derivative of the amino acid, which will serve as a model for peptide bonds involving Proline. In each case, the relative concentration of the equilibrium species can be determined from the NMR signal strength. The relative concentrations can then be leveraged to determine the desired equilibrium constant. This data can then be used to determine for the isomerization reaction. We will consider the equilibrium in both polar and non-polar solvents as well as in aqueous solutions of various ph's. In general, we write the equilibrium constant K c for a chemical reaction: a A + b B c C + d D as: K c = (Eq. 1) Recall, each concentration [i] is the equilibrium concentration of species i relative to the standard concentration of 1 M. Thus, K c is unit-less. Once K c has been determined, the Standard Gibbs Free Energy change for the reaction can be calculated according to: G o (T) = - RT ln K c (Eq. 2) Naturally occurring -amino acids are the monomeric building blocks of proteins and small peptides and bond together via a peptide linkage. Because the peptide bond has a resonance form that exhibits significant C=N double bond character, rotation about this bond is typically restricted.

P a g e 2 This means the peptide bond can exist in both cis and trans isomeric forms: The equilibrium constant for the isomerization reaction can be written as: K trans = [trans] / [cis] (Eq. 5) Biologically, generally the trans isomer dominates because of the energetically unfavorable interaction between the R side-chains in the cis isomer; the cis configuration being ~ 8 kj/mol less stable than the trans. Biochemistry, 2 nd Ed. Donald Voet and Judith G. Voet However, Proline residues are special because the side-chain consists of a pyrrolidine ring which includes the -amine of the amino acid. L-Proline For this reason, both the cis and trans isomers of peptide bonds involving Proline followed by another amino acid residue are roughly equivalent energetically.

P a g e 3 And, roughly 10% of peptide bonds in naturally occurring proteins involving Proline occur in the cis configuration. In this configuration Proline acts to induce hairpin turns in the proteins's secondary structure. This is illustrated by the case of the secondary structure of the protein Ribonuclease S. Hairpin in Ribonuclease S Biochemistry, 4 th Ed. Lubert Stryer As noted by Stryer, "Prolyl [or Proline-Amino Acid peptide bond] isomerization is the rate-limiting step in the folding of many proteins in vitro. Spontaneous isomerization is slow because the bond between the carbonyl carbon and the amide nitrogen has partial double bond character. Peptidyl prolyl isomerases (PPIases) accelerate cis-trans isomerization more than 300 fold by twisting the peptide bond so that the C, O, and N atoms are no longer planar." Additionally, it is commonly found that Proline residues initiate or terminate -helical protein segments... [rotations of residue i] within a polypeptide chain are [generally] independent of rotations within neighbors i-1 and i+1. However, in the case of the succeeding residue (i+1), it matters whether or not the (i+1)th residue is proline; the usual interactions of the ith residue with the amide hydrogen of the (i+1)th are replaced by steric conflicts involving the atoms of the pyrrolidine ring, particularly the - CH 2 - group attached to the imide nitrogen. Therefore, the rotational freedom of a residue succeeded by proline may be expected to be more restricted than if it preceded one of the other residues. a proline can occur at the beginning of an -helical sequence, but it prevents the preceding residue from adopting the helical conformation if that residue is not glycine. Thus, the fact that the proline nitrogen cannot participate in a hydrogen bond is not the primary cause for the ability of this residue

P a g e 4 to disrupt -helical sequences, although this reason is often given as the basis for proline's helixdisrupting tendencies. Biophysical Chemistry Part I: The Conformation of Biological Macromolecules Charles R. Cantor and Paul R. Schimmel We will use N-acetyl-L-proline as a model for peptide bonds involving Proline. We will measure the equilibrium constant for the cis-trans isomerism of this compound and treat this constant as being representative of Proline involved peptide bonds with other amino acids. N-Acetyl-L-Proline (trans Configuration) The NMR signals of the and protons of N-acetyl-L-Proline are sensitive to its cis-trans isomerization. The relative strengths of the NMR signals will be proportional to the concentration of each different form. Thus, the equilibrium constant for the cis-trans isomerization reaction can be determined by measuring the integrated NMR signals from and protons of each form. In non-aqueous environments, it is expected that the carboxyl hydrogen of this molecule can form an intramolecular hydrogen bond with the peptide carbonyl when the peptide bond is in the trans conformation, thus stabilizing the trans isomer. N-Acetyl-L-Proline (trans Configuration - Intramolecularly H-Bonded) The H-bond also partially "neutralizes" the dipole moment of the carbonyl group C=O, increasing its affinity for a non-polar environment. Thus, it is expected that the trans isomer will be increasing favored as the polarity of the solvent decreases. To illustrate this effect, we will measure the cis-trans equilibrium constant in two non-aqueous environments; Acetone ( = 21) and a 45:55 Benzene ( = 2.3):Chloroform ( = 4.81) mixture.

P a g e 5 (Recall, the dielectric constant is a rough measure of the polarity of a liquid.) In the former case the solvent is relatively polar, whereas in the latter, the solvent is non-polar. Finally, we will measure the equilibrium constant in aqueous solutions of lower and higher ph. The carboxyl Hydrogen is ionizable. This is important because the cis configuration is slightly more acidic (pk a ~ 2.8-3.5) than the trans form (pk a ~ 3.4-4.1) and when ionized the trans form has two negatively charged Oxygens, one being the Oxygen of the peptide carbonyl C=O and the other being the deprotonated carboxylate, in proximity to each other. This serves to destabilize the trans isomer and shifts the equilibrium toward the cis isomer. We should observe this deprotonization effect at higher ph's. N-Acetyl-L-Proline (trans Configuration - Deprotonated) NMR Spectra in General The proton at the heart of the Hydrogen atom, like the electron, exhibits behavior reminiscent of a spinning top. And, like the electron, its spin is quantized; limited to the states of Up and Down. In the presence of a strong external magnetic field (H o ), the energy of the two spin states splits; the stronger the field the greater the splitting. A photon whose frequency is such that its energy matches the energy difference between the spin states can be absorbed: E = E photon = hc / In NMR spectroscopy, these photons will lie in the Radio Frequency region of the electromagnetic spectrum.

P a g e 6 Now, this would be rather uninteresting if all the Hydrogen atoms in a molecule had nuclei that absorbed at exactly the same frequency. We would observe a single absorbance peak. However, locally, each Hydrogen atom is in a different environment. These environmental differences will lead to slight differences in the magnetic field experienced by the proton and will cause the splitting to vary slightly. This will lead to differences in the frequency of the absorbed photons. For instance, protons near the exterior of a Benzene ring experience a deshielding due to a locally induced magnetic field arising from the circulation of the electrons. This causes the spin state splitting to increase and shifts the absorbance frequency. This Chemical shift effect is measured in machine independent units of. The chemical shift is highly correlated with molecular structure and will provide us with an important clue as to the environment in which each proton finds itself. Finally, neighboring protons can influence the environment of each other via a mechanism called spin-spin coupling. Consider two neighboring protons A and B. A will observe that B can occupy its two possible spin states. Whether B is spin Up or Down will influence the spin states of A; the coupling is through the chemical bonds connecting the Hydrogen atoms. One case will cause A to absorb at a slightly higher frequency and the other a slightly lower frequency. This will lead to a splitting of A s absorbance into a doublet. If A couples to two Hydrogen atoms, then the splitting will occur again and a triplet will be observed; etc. As an example, the molecule CH 3 CH 2 Cl should exhibit two NMR signals. The first is due to the CH 3 - protons and will be split into a triplet due to the neighboring two protons. The other signal,

P a g e 7 due to the -CH 2 - protons, should be split into a quartet. As seen in the spectrum below, this is in fact the case: Introduction to Organic Chemistry, 2 nd Ed. Andrew Streitwiesser & Clayton H. Heathcock So, spectral information concerning Chemical Shift and Coupling will provide important clues about the molecular environment of each Hydrogen atom in a molecule. In the present case, the proton NMR signals from the and hydrogen atoms are sensitive to the isomeric configuration of the N-Acetyl-L-Proline molecule. This is illustrated in the following spectrum.

P a g e 8 The integrated area under a given signal's peak is proportional to the number of molecules in the specified configuration. Thus, ratios of trans peak areas to cis peak areas will yield the desired K trans. We will measure the following trans-cis peak ratios -trans to -cis, -trans to -cis, -trans to -cis, -trans to -cis and average the results to determine K trans. Peak assignments in the proton NMR spectrum can be made according to observations of Dorman et al: The major contributors to these [cis-trans] mixtures have been clearly demonstrated by pmr spectroscopy to be the trans conformers. Due to the general experience that carbons syn to the carbonyl oxygen of amides are shielded relative to those which are anti, one would expect the carbon of the trans conformer to be shielded relative to that of the cis. The carbon, however, would be more shielded in the cis, or minor, isomer. Such a situation should lead to a back-toback pattern for these resonances

P a g e 9 Procedure 1. Dissolve about 5 mg of N-Acetyl-L-Proline in ~0.7 ml of Acetone-d 6 containing TMS. 2. Dissolve about 5 mg of N-Acetyl-L-Proline in ~0.7 ml of a 45:55 mixture of Benzene-d 6 and CDCl 3 containing TMS. 3. Dissolve about 5 mg of N-Acetyl-L-Proline in ~0.7 ml of D 2 O; acidic solution. 4. Dissolve about 5 mg of N-Acetyl-L-Proline in ~0.7 ml of D 2 O to which a small amount of NaOH has been added; basic solution. 5. Record the NMR spectrum for each solution. Identify the signals due to the and protons of the Proline residue. Integrate the relative strengths of these signals for each case. Do this at least three times for each signal. This will allow for an estimation of the error in these values.

P a g e 10 Data Analysis 1. Calculate the following NMR peak ratios: -trans to -cis -trans to -cis -trans to -cis -trans to -cis 2. Calculate the average K trans, as determined from the above data, for each solvent. Include an appropriate error estimate. 3. Calculate G o for each solvent. Include an appropriate error estimate. 4. Discuss the effect of solvent and ph on K trans. Include a molecular interpretation for each case.

P a g e 11 References Cantor, Charles R. and Schimmel, Paul R. (1980) "Biophysical Chemistry, Part I: The Conformation of Biological Macromolecules," Freeman, San Francisco. Cook, Gilbert and Feltman, Paul M. Determination of Solvent Effects on Keto-Enol Equilbria of 1,3-Dicarbonyl Compounds Using NMR, J. Chem. Ed. 84 (2007) 1827. Dorman, Douglas E. and Bovey, Frank A. "Carbon-13 Magnetic Resonance Spectroscopy. The Spectrum of Proline in Oligopeptides" J. Org. Chem. 38 (1973) 2379. Kim, Eunice E.; Varadarajan, Raghavan; Wyckoff, Harold W. and Richards, Frederic M. "Refinement of the Crystal Structure of Ribonuclease S. Comparison with and between Various Ribonuclease A Structures," Biochemistry 31 (1992) 12304. Shoemaker, David P.; Garland, Carl W. and Nibler, Joseph W. (2009) Experiments in Physical Chemistry, 8 th Ed. McGraw-Hill, New York. Streitwiesser, Andrew and Heathcock, Clayton H. (1981) Introduction to Organic Chemistry, 2 nd Ed. Macmillan, New York. Stryer, Lubert (1995) "Biochemistry," 4 th Ed. W.H. Freeman and Company, New York. van Holde, Kensal E.; Johnson, W. Curtis; and Ho, P. Shing. (2006) Principles of Physical Biochemistry, 2 nd Ed. Pearson, New Jersey. Williams, Kathryn R.; Adhyaru, Bhavin; German, Igor; and Alvarez, Eric. The Cis-Trans Equilibrium of N-Acetyl-L-Proline: An Experiment for the Biophysical Chemistry Laboratory, J. Chem. Ed. 79 (2002) 372.