B2 5 Inheritrance Genetic Crosses



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B2 5 Inheritrance Genetic Crosses 65 minutes 65 marks Page of 55

Q. A woman gives birth to triplets. Two of the triplets are boys and the third is a girl. The triplets developed from two egg cells released from the ovary at the same time. The diagram shows how triplets A, B and C developed. (a) Which stages on the diagram show gametes? Draw a ring around your answer. and 2 2 and 3 3 and 7 and 7 () (b) Embryo B is male. Which of the following explains why embryo B is male? Tick ( ) one box. Cell P has an X chromosome; cell R has an X chromosome. Cell P has a Y chromosome; cell R has an X chromosome. Cell P has an X chromosome; cell R has a Y chromosome. () Page 2 of 55

(c) The children that develop from embryos A and C will not be identical. Explain why. You may use words from the box in your answer. egg genes sperm............... (2) (d) Single cells from an embryo at Stage 7 can be separated and grown in a special solution. (i) What term describes cells that are grown in this way? Draw a ring around your answer. lleles screened cells stem cells () (ii) What happens when the cells are placed in the special solution? Tick ( ) two boxes. The cells divide The cells fertilise The cells differentiate The cells separate (2) (iii) Give one use of cells grown in this way. () Page 3 of 55

(iv) Some people might object to using cells from embryos in this way. Give one reason why. () (Total 9 marks) Q2. In humans, sex chromosomes control whether a person is male or female. (a) Use letters X and Y to complete the Punnett square for sex inheritance. Eggs or Sperm or...xx............ (3) (b) A couple already have three boys. What is the probability that their next child will be a girl?...... () (Total 4 marks) Page 4 of 55

Q3. The diagram shows how cells from human embryos can be used to grow replacement body parts for humans. Sue Medaris/University of Wisconsin-Madison (a) Complete the following sentences. (i) (ii) The fertilised egg has... sets of genetic information. The fertilised egg divides to form the 5-day-old embryo by a process called... () () Page 5 of 55

(b) Some statements about stem cells are given below. Tick ( ) two advantages and two disadvantages of using stem cells to grow replacement body parts for humans. Advantage Tick ( ) Disadvantage Tick ( ) Stem cells can grow into many different kinds of body cells. Stem cells may grow out of control. Large numbers of stem cells can be grown in the laboratory. Stem cells may be used to treat some human diseases. Collecting and growing stem cells is expensive. Patients treated with stem cells may need to take drugs for the rest of their life to prevent rejection. (4) (Total 6 marks) Q4. Diagram shows the nucleus of a body cell as it begins to divide by mitosis. Diagram (a) Use a word from the box to label Diagram. alleles chromosomes gametes () Page 6 of 55

(b) Complete Diagram 2 to show what the nucleus of one of the cells produced by this mitosis would look like. Diagram 2 () (c) Stem cells from a recently dead embryo can be grown in special solutions. Some facts about stem cells are given below. Stem cells from an embryo can grow into any type of tissue. Stem cells may grow out of control, to form cancers. Large numbers of stem cells can be grown in the laboratory. Stem cells may be used in medical research or to treat some human diseases. Patients treated with stem cells need to take drugs for the rest of their life to prevent rejection. Collecting and growing stem cells is expensive. Use only the information above to answer these questions. (i) Give two advantages of using stem cells.... 2... (2) Page 7 of 55

(ii) Give two disadvantages of using stem cells.... 2... (2) (Total 6 marks) Q5. The diagrams show one of Mendel s experiments. He bred pea plants. Mendel suggested that flower colour was controlled by inherited factors. Draw a ring around the correct answer to complete the following sentences. (a) The first generation plants show that the red factor is dominant. environmental. recessive. () Page 8 of 55

(b) The second generation plants show that the white factor is dominant. environmental. recessive. () (c) What do we call inherited factors?... () (d) How are inherited factors passed from generation to generation?... () (Total 4 marks) Q6. (a) Alleles are different forms of the same gene. Why does a person usually inherit two alleles of each gene?. () (b) Some humans are albino (they have white hair and pale skin). This condition is caused by a recessive allele, n. The other allele, N, causes a coloured pigment to be made. There are three possible combinations of these alleles: NN Nn nn (i) Which one of these combinations will an albino person have? () Page 9 of 55

(ii) Two non-albino parents can sometimes have an albino child. Which one of the following combinations of alleles must these two parents have? Tick ( ) the box next to the correct answer. Tick one box only. Parent Parent 2 NN NN NN Nn Nn Nn nn nn () (Total 3 marks) Q7. In humans, the sex chromosomes X and Y determine whether the baby will be male or female (its gender). (a) (i) Draw a genetic diagram to show how gender is inherited. The male has XY chromosomes and the female has XX. (2) (ii) What is the likelihood of obtaining a male child?... () Page 0 of 55

(b) In the 6th century Henry VIII was the King of England. He blamed some of his wives for giving birth to daughters instead of sons. With our present day knowledge of genetics this mistake could not be made today. Explain why Henry VIII was wrong.......... (2) (Total 5 marks) Q8. Cystic fibrosis is an inherited disorder that can seriously affect health. (a) Which one of these is affected by cystic fibrosis? Draw a ring around your answer. blood cell membranes kidneys nervous system () (b) The diagram shows the inheritance of cystic fibrosis in a family. The allele that produces cystic fibrosis is recessive. Page of 55

(i) Explain why Alice inherited cystic fibrosis. (2) (ii) Explain why Ted did not inherit cystic fibrosis. (2) (c) Bob and Carol know that there is a risk that their next baby will have cystic fibrosis. Embryos can be screened for the allele that produces cystic fibrosis. Many people support the screening of embryos, but others do not. (i) Suggest one reason why many people support the screening of embryos for the cystic fibrosis allele. () (ii) Suggest one reason why many people are against the screening of embryos for the cystic fibrosis allele. () (Total 7 marks) Page 2 of 55

Q9. (a) The diagram shows a normal body cell which has six chromosomes. (i) Complete the diagram below to show one cell produced from this cell by mitosis. (3) (ii) Complete the diagram below to show one cell produced from the original cell by meiosis. (2) (b) Thalassaemia is a blood disease. It is determined by a single recessive allele. A person with one recessive allele does not get the disease but does act as a carrier. People with this pair of recessive alleles can become ill. (i) Draw a genetic diagram to show the inheritance of' this disease if both parents are heterozygous. [Use the symbols T = dominant allele and t = recessive allele] (3) Page 3 of 55

(ii) What are the chances of a baby inheriting the disease? () (iii) What are the chances of a baby being a carrier if both parents are heterozygous? () (Total 0 marks) Q0. Meiosis and mitosis are different types of division in human cells. Compare the two processes by referring to where each takes place and the kind of products that are made.................................. (Total 6 marks) Q. (a) Mice with black fur can have the genotype BB or Bb, whilst mice with brown fur have the genotype bb. (i) Use a genetic diagram to show what fur colours you would predict in the F offspring produced by two mice who are both Bb. (3) Page 4 of 55

(ii) Why might your prediction of fur colour in the F generation not be proved right? () (b) Using the example in part (a) to help: (i) describe the difference between dominant and recessive alleles; (2) (ii) describe the difference between alleles and genes; (2) (iii) describe the difference between homozygous and heterozygous chromosomes. (2) (Total 0 marks) Page 5 of 55

Q2. The diagrams show four ways in which human twins may be formed. Which diagram, A, B, C or D, shows the process which will produce genetically identical twin boys? Explain the reason for your choice...................... (Total 3 marks) Page 6 of 55

Q3. The diagram shows two patterns of cell division. Cell division type A is used in gamete formation. Cell division type B is used in normal growth. (a) Name the two types of cell division, A and B, shown in the diagram. Type A... Type B... (2) (b) Name the process in which an egg and sperm join together.... () (c) Cell contains 46 chromosomes. How many chromosomes will there be in: (i) cell 0;... () (ii) cell 4?... () (Total 5 marks) Page 7 of 55

Q4. Sometimes babies are born with extra fingers or toes as shown in the photograph. This condition is called polydactyly. CNRI / SCIENCE PHOTO LIBRARY The diagram shows the inheritance of polydactyly in a family. (a) Polydactyly is caused by a dominant allele, D. The recessive allele of the gene is represented by d. Use one genetic diagram to show the inheritance of the polydactyly gene by R and S. (4) Page 8 of 55

(b) In this question you will be assessed on using good English, organising information clearly and using specialist terms where appropriate. Embryos can be screened for genetic disorders. Many people would favour the use of embryo screening for cystic fibrosis but not for polydactyly. Compare the issues involved in the use of embryo screening for cystic fibrosis and for polydactyly. You should use your knowledge and understanding of the process and the two conditions........................................ (6) (Total 0 marks) Page 9 of 55

Q5. Coat colour in rabbits is controlled by one pair of genes. The allele for black coat (N) is dominant to the allele for brown coat (n). The drawing shows the result of crossing a blackcoated rabbit with a brown-coated rabbit. Complete the genetic diagram to show how the young rabbits inherited their coat colour. Use the symbols N and n for the alleles. The alleles of the brown parent have been inserted for you. (Total 3 marks) Page 20 of 55

Q6. Chromosomes contain molecules of DNA. Genes are small sections of DNA. (a) Each gene contains a code. What does a cell use this code for?............ (2) (b) DNA fingerprints can be used to identify people. One example of the use of DNA fingerprints is to find out which man is the father of a child. The diagram shows the DNA fingerprints of a child, the child s mother and two men who claim to be the child s father. The numbers refer to the bars on the DNA fingerprints. (i) Which man, A or B, is more likely to be the father of the child? Use the numbers on the DNA fingerprints to explain your choice. In your answer you should refer to all four people. (3) Page 2 of 55

(ii) Only half the bars of the child s DNA fingerprint match the mother s DNA fingerprint. Explain why. (2) (Total 7 marks) Q7. In the 850s, Gregor Mendel carried out breeding experiments using peas. (a) The importance of Mendel s work was not recognised until the early 900s. Explain why............. (2) Page 22 of 55

(b) A student repeated one of Mendel s experiments. The flow chart shows her procedure. The diagram shows a representative sample of seeds produced by second generation plants. (i) Describe how the student could obtain a sample that is representative of seeds produced by the second generation. () (ii) What was the approximate ratio of yellow seeds to green seeds in the seeds produced by the second generation? () Page 23 of 55

(iii) Seed colour in peas is controlled by a single gene which has two alleles. Use a genetic diagram to show why this ratio of yellow seeds to green seeds was produced by the second generation. Use the symbol A to represent the dominant allele, and a to represent the recessive allele. (4) (Total 8 marks) Q8. The drawing shows some of the stages of reproduction in horses. (a) (i) Name this type of reproduction... (ii) Name the type of cell labelled A... () () (b) Name the type of cell division taking place at the stage labelled: (i) B... (ii) C... (2) Page 24 of 55

(c) How does the number of chromosomes in each cell of the embryo compare with the number of chromosomes in cell A?... () (d) When the foal grows up it will look similar to its parents but it will not be identical to either parent. (i) Explain why it will look similar to its parents. () (ii) Explain why it will not be identical to either of its parents. (2) (Total 8 marks) Q9. The drawings show bolls on cotton plants. Cotton thread is made from these bolls. The size of the bolls is controlled by a single gene. This gene has two alleles. The dominant allele B is the allele for large bolls. The recessive allele b is the allele for small bolls. Page 25 of 55

Use a genetic diagram to show how two cotton plants with large bolls may produce a cotton plant with small bolls. (Total 4 marks) Q20. The fruit fly, Drosophila, has either long wings or vestigial wings, as shown in the diagram. Long-winged fly Vestigial-winged fly The size of the wings is determined by a pair of alleles: A and a. Long-winged flies have one of two possible genotypes: AA or Aa. Vestigial-winged flies have only one genotype: aa. (a) (i) What is the genotype of a heterozygous fly? () (ii) Why can vestigial-winged flies only have the genotype aa? () Page 26 of 55

(b) A male and a female long-winged fly were crossed. They produced 96 offspring. 72 of the offspring had long wings and 24 had vestigial wings. Use a genetic diagram to explain this. (4) (Total 6 marks) Q2. The black pigment in human skin and eyes is called melanin. A single gene controls the production of melanin. A person who is homozygous for the recessive allele of the gene has no melanin and is said to be albino. The diagram shows the inheritance of albinism in a family. Page 27 of 55

(a) Use a genetic diagram to explain the inheritance of the albino allele by children of parents P and Q. (3) (b) R and S decide to have a child. What is the chance that this child will be an albino?... Use a genetic diagram to explain your answer. (3) (Total 6 marks) Page 28 of 55

Q22. In the cell shown in the diagram as a box, one chromosome pair has alleles Aa. The other chromosome pair has alleles Bb. The cell undergoes meiosis. (a) Complete the diagram of the four gametes to show the independent assortment, or reassortment, of genetic material during meiosis. (2) (b) If the cell undergoes mitosis instead of meiosis, draw the two daughter cells which result to show the chromosomes in each. (2) (c) State the number of chromosomes in: (i) a normal human cell; () (ii) a human gamete; () Page 29 of 55

(iii) the daughter cell from mitosis of a human cell. () (Total 7 marks) Q23. The diagram shows a family tree in which some individuals have an inherited disorder, which may cause serious long-term health problems. (a) What proportion of the children of A and B have the disorder?... () (b) Explain the evidence from the diagram which shows that the allele for the disorder is dominant. Use the appropriate letters to identify individuals in your answer. You may use genetic diagrams in your explanation. There is space for you to draw a genetic diagram at the top of the facing page................... (3) Page 30 of 55

(c) (i) What is meant by embryo screening? () (ii) A doctor suggests that couple C and D should have their embryos screened but that couple G and H do not need this procedure. Explain the reasons for the doctor s suggestions. (3) (Total 8 marks) Q24. The family trees below show the inheritance of hair colour in two families. (a) The allele for black hair is dominant over the allele for red hair. Use the letter B as the allele for black hair. Use the letter b as the allele for red hair. Complete the diagram below to show the chances of Mary Jones inheriting red hair. Page 3 of 55

(4) (b) John Smart and Mary Jones grew up, got married and had a child. What would the chances be that the child had red hair?... () Explain your answer. Use a genetic diagram if it makes your answer clearer.......... (3) (Total 8 marks) Page 32 of 55

Q25. Cystic fibrosis is an inherited disease which causes the tubes in the lungs to be blocked with sticky mucus. Two parents who do not have the disease can still produce children who do have the disease. (a) Explain how children can inherit this disease from parents who do not have it (use a genetic diagram in your answer if you want to)................ (4) (b) Mucus contains protein. The information for the production of this protein is stored in a gene. Explain how a change in a gene causes a different protein to be produced............. (3) (Total 7 marks) Page 33 of 55

Q26. The diagram shows one of the experiments performed by a scientist called Mendel in the 850s. He bred pea plants which had different coloured pea seeds. (a) Use words from the box to help you to explain the results of this experiment. dominant factor recessive.................. (3) (b) Mendel explained these results in terms of inherited factors. (i) What do we now call inherited factors? () (ii) Where, in a cell, are these inherited factors found? () (Total 5 marks) Page 34 of 55

M. (a) 2 and 3 (b) (c) cell P has an X chromosome; cell R has a Y chromosome any two from: (formed from) different egg / 2 eggs (formed from) different sperm / 2 sperm have different genes / alleles / chromosomes / DNA allow genetics 2 (d) (i) stem cells (ii) (iii) (iv) the cells divide the cells differentiate (medical) research / named eg growing organs or medical / patient treatment allow (embryo) cloning do not allow designer babies / more babies any one from: ethical / moral / religious objections ignore cruel / not natural / playing God potential harm to embryo allow deformed ignore harm to mother [9] M2. (a) (X) (XX) XX Y XY XY mark for Y in sperm box mark if XX box correct mark if both XY boxes correct 3 Page 35 of 55

(b) : or 50% or ½ or 0.5 or in 2 or out of 2 or 50 : 50 do not accept 50/50 accept equal (probability) [4] M3. (a) (i) two (ii) mitosis (b) Adv. Disadv. Stem cells can grow into many different kinds of body cells. Stem cells may grow out of control. Large numbers of stem cells can be grown in the laboratory. Stem cells may be used to treat some human diseases. Collecting and growing stem cells is expensive. Patients treated with stem cells need to take drugs for the rest of their life to prevent rejection. mark for each correctly ticked advantage up to a maximum of 2 marks mark for each correctly ticked disadvantage up to a maximum of 2 marks deduct mark each for every incorrect box ticked in each column up to a maximum of 2 deductions in each column 4 [6] Page 36 of 55

M4. (a) chromosomes (b) diagram showing four separate chromosomes two long and two short (as in diagram ) allow each chromosome shown as two joined chromatids do not allow if chromosomes touching each other (c) (i) any two from: can grow into any type of tissue / named tissue used in medical research used to treat human diseases large numbers can be grown 2 (ii) any two from: expensive grow out of control / ref cancers may be rejected need for drugs (for rest of life) 2 [6] M5. (a) dominant (b) recessive (c) genes (d) gametes [4] M6. (a) one from each parent / one from egg and one from sperm do not accept egg and sperm join / fertilisation unqualified Page 37 of 55

(b) (i) nn accept a ring around printed nn (ii) Nn Nn [3] M7. (a) (i) gametes correct allow by implication from line diagram only need on X from female offspring genotype correctly derived on suitable diagram or (ii) : or 50% or ½ or 0.5 or in 2 or out of 2 or 50 : 50 do not accept 50/50 accept equal (probability) (b) Y chromosome needed for male child only male has the Y or wives had only X (chromosomes) or sex determined by the sperm [5] M8. (a) cell membranes Page 38 of 55

(b) (i) two recessive / cystic fibrosis / faulty / diseased / the allele(s) / genes two can be implied by second marking point ignore chromosomes from Bob and Carol / both parents / the parents if no other marks awarded Carol is a carrier gains mark (ii) (inherited) dominant / normal allele / gene from Carol / mother ignore references to recessive allele / gene from father / Bob if no other marks awarded he has just / only one recessive allele gains mark (c) (i) reduce number of people with cystic fibrosis (in population) or reduce health-care costs or expensive to have baby with cystic fibrosis accept to allow decision / emotional argument qualified eg allows abortion or allows people to make choices about termination or help to prepare financially / emotionally etc (ii) any one from: possible damage / risk to embryo / fetus / baby allow possible harm / risk to mother screening / it is expensive (may) have to make ethical / moral / religious decisions ignore not natural / playing God / unethical / immoral / religious unqualified right to life [7] Page 39 of 55

## (a) (i) if two nuclei drawn then maximum two marks 6 chromosomes same 3 homologous pairs nuclear membrane drawn (ii) 3 chromosomes from each homologous pair (b) (i) parent line must be separate heterozygous parents Tt Tt maximum of 2 marks if parental genotype is wrong gametes correct T t T t genotypes TT Tt Tt tt (ii) correct analysis of chance i.e. in 4 or 25% (iii) 50% or in 2 [0] Page 40 of 55

M0. one mark for each of the following comparisons to a maximum of 6 candidates must make a clear comparison meiosis sexual gametes ovary or testes or gonads half number of chromsomes mitosis asexual growth all other cells same number of chromosomes haploid or diploid or 23 chromosomes 46 chromosomes reassortment or variation possible or not identical no reassortment or no variation or identical 4 cells produced 2 cells produced 2 divisions division [6] M. (a) (i) gametes i.e. B b and B b correct combination of genotypes i.e. BB, Bb, Bb, bb correct analysis of phenotypes i.e. 3 black fur with brown fur (ii) award one mark for the recognition that it is down to chance (which two gametes fuse) and not simply because it s a prediction do not accept mutation (b) (i) B is dominant/ an allele is dominant if it is expressed in the heterozygous phenotype candidates are likely to use a variety of ways of expressing their ideas b is recessive/ a recessive allele is not expressed in the presence of its contrasting allele do not accept powerful do not accept stronger Page 4 of 55

(ii) alleles are different forms of a gene controlling a characteristic and occupying the same site on homologous chromosomes (e.g. B or b) genes are the units of DNA/sites on chromosomes carrying the information that determines characteristics (e.g. bb) (c) homozygous: BB / bb / possessing a pair of identical alleles for a character/true breeding give credit to an explanation using a diagram heterozygous: Bb / carrying a pair of contrasting/different alleles for a characteristic do not accept references to xx, xy do not accept gene by itself [0] M2. D idea that twins have come from one (fertilised) egg idea that Y sperm / Y chromosome produces boys each for mark allow mark if candidate selects A and states that Y sperm / Y chromosome produce boys (reject Y gene unqualified) OR allow mark if candidate selects C and states that twins must have come from one (fertilised) egg [3] M3. (a) A = meiosis accept mieosis do not accept miosis B = mitosis do not accept meitosis etc (b) fertilisation allow conception (c) (i) 23 (ii) 46 [5] Page 42 of 55

M4. (a) (genotype / gametes from P / father) D and d (*) (genotype / gametes from Q / mother) d and d / accept d(*) offspring genotypes correctly derived from correct gametes(*) offspring phenotypes R and S identified (*) eg may be in punnett square allow own upper and lower case symbols or allow any symbol correctly used with key (b) Marks awarded for this answer will be determined by the Quality of Written Communication (QWC) as well as the standard of the scientific response. No relevant content. There is a brief description of the issues involved in screening for at least one condition. There is some description of issues involved in screening for both conditions but there is a lack of both pros and cons for the two conditions. There is a clear, balanced and detailed description of the issues involved in screening for both conditions, giving pros and cons for each condition. 0 marks Level ( 2 marks) Level 2 (3 4 marks) Level 3 (5 6 marks) examples of biology points made in the response For cystic fibrosis pros: reduce number of people with cystic fibrosis (in population) reduce health-care costs allows decision / emotional argument, eg allows people to make choices about termination cons: possible damage / risk to embryo / fetus / baby possible harm / risk to mother (may) have to make ethical / moral / religious decisions Page 43 of 55

for polydactyly: cures disfigurement but condition not life threatening so risks to foetus / mother unjustified [0] M5. genotype of parent A Nn gametes N n n n young genotypes and phenotypes all correct for mark each [3] M6. (a) any two from: to combine / use amino acids do not allow to make amino acids in specific / particular / correct / right order to manufacture protein / enzymes / hormones allow examples of proteins / enzymes / hormones 2 Page 44 of 55

(b) (i) (man) B no mark for this but max 2 marks if A given any three from: child gets DNA / bars / lines from mother and father / parents ignore genes / chromosomes (child has) mother s 25 / 28 / 30 / 3 or child gets 7 / 9 / 22 / 24 from mother (child has) man B s 0 / 2 / 3 / 4 or child gets 8 / 20 / 2 / 23 from B contradictions disqualify 2 nd and / or 3 rd marking points ignore genes / chromosomes no bars / DNA / lines from man A correspond to child 3 (ii) any two from: gametes / eggs / sperm contain only half of (mother s / father s) DNA / chromosomes / genes / genetic information due to meiosis 2 [7] M7. (a) any two from: accept other logical / reasonable ideas other scientists not aware of his work chromosomes / DNA / genes not seen / discovered / known do not accept there was no interest in genetics other theories accepted at the time not considered to be a scientist / not eminent / respected allow he was just / only a monk 2 Page 45 of 55

(b) (i) random selection accept a method of achieving random selection eg take a handful if number given, minimum 20 (ii) any one from: : / one to one 9:2 accept any ratio to give correct answer, eg 50:50 do not accept 2:9 unqualified (iii) A + a as gametes from st parent a + a as gametes from 2nd parent allow a alone (offspring / 2 nd generation) Aa aa offspring must be derived from correct gametes correct identification of yellow (Aa) other symbols correctly used can gain full marks or green (aa) (if both given, both must be correct) ignore references to previous generations if no other marks awarded, both correct parental genotypes given gains mark Page 46 of 55

examples of award of first three marks [8] M8. (a) (i) sexual / sex (ii) egg / gamete / sex cell / ovum (reject ovule) for mark each 2 (b) (i) meiosis / reduction (ii) mitosis / somatic for mark each 2 (c) twice as many (reject answers based on 23 / 46 chromosomes) for one mark (d) (i) information / genes / DNA passed from parents (chromosomes neutral) for one mark Page 47 of 55

(ii) genes / genetic information / chromosomes from two parents alleles may be different environmental effect / named may have been mutation any two for mark each 2 [8] M9. parental genotypes both correct both Bb gamete genotypes all correct B and b B and b genotype of bb offspring correctly related to gametes bb offspring identified as small bolls for mark each [4] M20. (a) (i) Aa or aa (ii) allele / gene for vestigial wings / a is recessive or vestigial is recessive or A is dominant or A would override the effect of a or A present gives long wings (b) parental genotypes correct both Aa NB can pick up chain of logic at any point correctly derived from candidate s previous point gametes correctly derived from P genotypes offspring genotypes correctly derived from gametes 3: ratio recognised wrong cross and not 3: ratio = max 2 [6] Page 48 of 55

M2. (a) gametes A or a A or a F genotypes correctly derived albino identified OR gametes F genotypes corresponding to lines lines must be correct Albino (aa) identified (lower case) OR A a A AA Aa a Aa aa gametes boxes all correct albino (aa) identified (b) do not credit to 2 or 50/50 gametes A or a a or a or one parent heterozygous, one parent homozygous recessive Page 49 of 55

F genotypes correctly derived OR (R) (S) gametes correctly identified F genotypes correctly derived OR gametes correctly derived F genotypes correctly derived [6] M22. (a) A A a a B b B b Aa allele correctly separated Bb allele arranged to form four different pairings all four pairings must be correct for the second mark (b) A A the two cells the same as the parent cell a B b a B b mark for each cell 2 Page 50 of 55

(c) (i) 46 (ii) 23 (iii) 46 accept 23 pairs accept half if c(i) accept save as c(i) [7] M23. (a) in 4 / /4 / : 3 / 25% / 0.25 do not accept 3: / :4 / 2:6 (b) either from C and D accept synonyms for dominant / recessive eg Normal / faulty accept genetic diagram if clearly referring to correct individuals or genotypes on family tree allow gene for allele any three from: C and D have disorder ignore C & D are carriers I/J don t have disorder C and D have dominant and recessive alleles recessive alleles from C and D passed to I/J or I/J have two recessive alleles or from A and B NB if allele was recessive then all offspring of C and D would have the disorder = 3 marks assume response refers to A + B unless contradicted A is homozygous recessive / rr, and B is heterozygous / Rr can be shown in words or symbols allow any symbol offspring can be rr or Rr described allow without key 3 Page 5 of 55

(c) (i) (embryos) checked for inherited / genetic disorders / conditions accept diseases for disorders (ii) any three from: C/D have disorder / have dominant allele accept disease / condition accept gene for allele ignore reference to carriers chance of embryo / foetus / child having disorder or may pass on alleles for disorder to their offspring C/D might want to decide on termination or prepare for child with disorder G and H don.t have disorder / both homozygous recessive / have no dominant alleles (for this disorder) so offspring (of G and H) cannot / don.t have disorder 3 [8] M24. (a) alleles in parents alleles in sperms/eggs (*) B b B b alleles in children (*) hair colour black black black red (*) NB ecf Allow other letters if a clear key each line correct for mark each 4 (b) evens/50:50/equal/half (e.c.f. from cross below) for mark parents J Smart M Jones Bb bb children Bb Bb bb bb *(ecf) black red each line correct for mark each 3 Page 52 of 55

J Smart must be BB or Bb M Jones must be bb or from (a) Credit cross shown in a matrix: for 2 marks Bb identified as black hair bb identified as red hair or 2 red : 2 black for mark [8] M25. (a) caused by a recessive* gene / allele (allow non / not dominant) both parents heterozygous / carry the gene / allele for mark each offspring needs two recessive genes to have / inherit disease for 2 marks or Nn Nn NN Nn Nn nn for mark each nn identified as having the disease* for 2 marks 4 Page 53 of 55

(b) any reference to DNA gains mark but different genes means difference in DNA gains 2 marks idea of different codes / instructions for making proteins or different (order of) amino acids (in proteins) for mark 3 [7] M26. (a) any three from: factor for colour has two forms accept gene for factor and allele for form yellow dominant since all first generation yellow accept F for first generation green recessive since reappears in second generation accept F2 for second generation 3 (b) (i) genes accept alleles / genetic (ii) nucleus accept chromosomes / DNA [5] Page 54 of 55

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