Chapter 14 Fundamentals of Electrochemistry continued Vocabulary: Oxidation - Loss of electrons (increase oxidation state) Reduction Gain of

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Chapter 14 Fundamentals of Electrochemistry continued Vocabulary: Oxidation - Loss of electrons (increase oxidation state) Reduction Gain of electrons (decrease oxidation state) Oxidizing agent Substance that takes electrons (Standard reduction potential is more positive.) Reducing agent Substance that gives up electrons (Standard reduction potential is more negative.) Anode Electrode that oxidation takes place (positive polarity) Cathode Electrode that reduction takes place (negative polarity) Coulombs unit of charge Volt unit of potential Ampere unit of current (coulomb/sec) Joule unit of work Watt unit of power (work/sec)

Review of Important Electrochem Equations q (coulombs) = n (moles) x F (Faraday constant, coulombs/mole) Work (joules) = E (volts) x q (coulombs) E (volts) = I (Amp) x R (ohms, Ω) Power (joules/sec) = E (volts) x I (Amp) ΔG (Gibb s free energy) = - n (moles) x F (Faraday constant) x E (volts) (This equation shows the thermodynamic importance of the cell potential.)

Cell Potential For any cell, the measured potential between the anode and the cathode can be calculated: Ecell = E+ E- where E+ is the calculated potential for the half - cell (electrode) connected to the ( + ) terminal of the potentiometer (reduction reaction) (the right cell and the right side of the potentiometer, usually) E- is the potential for the half - cell (electrode) connected to the (-) terminal of the potentiometer (oxidation reaction) (usually the left side of the potentiometer and the left cell) NOTE: E + and E - are both reduction potentials

What is happening at the electrode(s) and how do we describe the cell?

What is happening at the electrode(s) and how do we describe the cell? Anodehalf - rxn: Zn (s) 4(aq) (s) 0 (s) Cathodehalf - rxn: Cu CompleteCell reaction: Zn Zn ZnSO + 2 (aq) CuSO + 2 (aq) 4(aq) + 2 (aq) - Cu (s) - 0 (s) + 2 (aq) in shorthand,we use symbols! a single verticalline marks the phase difference a double verticalline marks the salt bridge Anodeon the left,cathodeon the right Includingthe counter- ions tells us somethingabout the solutions + Cu Zn + 2 e Cu + Zn 2 e + Cu 0 (s)

The Standard Hydrogen Electrode (SHE) The basis by which all other measurements are made. Assigned a potential of zero by definition! Not practical for regular use Hydrogen Half-Cell H 2(g) = 2 H + (aq) + 2 e - reversible reaction SHE consists of a platinum electrode covered with a fine powder of platinum around which H 2(g) is bubbled. Its potential is defined as zero volts.

Standard Potentials Standardized potentials (E o ), listed as reductions, for all half-reactions Measured versus the S.H.E (0) Used in predicting the action in either a galvanic cell or how much energy would be needed to force a specific reaction in a non-spontaneous cell Assumes an activity of one for the species of interest (usually a fair approximation) at a known temperature in a cell with the S.H.E. Assumes that the cell of interest is connected to the (+) terminal of the potentiometer (voltmeter) and the S.H.E. is connected to the (-) terminal

Better Oxidizing Agents in upper left hand corner. Better Reducing Agents in lower Right hand corner

Calculating E cell Determine E + and E - (Even though E - is an oxidation reaction, the E - is determined for the reduction reaction then subtracted.) Calculate E cell Write a balanced cell reaction, by adding the two half-reactions Write out the right cell half reaction Write out the left cell half reaction and reverse it Add the two reactions together to get a net, balanced cell reaction. If, you use the conventions described here,then: If E cell >0, the reaction is spontaneous to the right If E cell <0, the reaction is spontaneous to the left

Relationship between E and the Equilibrium Constant Recall: ΔG (Gibb s free energy) = - n (moles) x F (Faraday constant) x E (volts) K (equilbrium constant) = e - ΔG/RT K = e - (-nfe /RT) At 25 C K = 10 ne /0.05916 or E = (0.05916/n) log K

Problem - Calculate the E and K for the following reaction: Cr 2+ + Fe (s) Fe2+ + Cr (s)

Nernst Equation The Nernst equation allows you to determine the cell potential when the activities of the species involved 1 (i.e. non-standard conditions, more typical to real-life) For aa + ne - bb At 25 C: E = E - (RT/nF) ln (A bb / A aa ) E = E - (0.05916/n) log (A bb / A aa )

Nernst Equation Accounts for potentials of cells where the reagents are not at an activity of 1 Remember that standard potentials are at A=1 Accounts for the number of electrons transferred in a reaction, the temperature of the reaction, LeChatelier s Principle and a variety of other factors Used to calculate E + and E - under nonstandard conditions Most real cases!

The Nernst Equation for Complete Reactions.. Setup two Nernst equations One for E + One for E - Solve each Nernst equation to get E + and E - Solve for E cell (E cell = E + -E - )

A galvanic cell is assembled in which the left cell is the anode where cadmium metal electrode is oxidized to cadmium ion in 0.010 M cadmium nitrate. In the right cell, the cathode, silver ion is reduced to silver metal on a silver metal electrode in 0.50 M silver nitrate. 1. Draw the cell (both a picture and a schematic diagram) 2. Write the half and net cell reactions 3. Calculate the net cell voltage 4. Indicate in which direction the cell is spontaneous