Sample or Random Security A Security Model for Segment-Based Visual Cryptography
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1 Sample or Random Security A Security Model for Segment-Based Visual Cryptography Sebastian Pape Dortmund Technical University March 5th, 2014 Financial Cryptography and Data Security 2014 Sebastian Pape Sample or Random Security March 5th, FC14 1 / 24
2 Overview 1 Introduction Visual Cryptography 2 Sample-Or-Random Security 3 Summary and Outlook Sebastian Pape Sample or Random Security March 5th, FC14 2 / 24
3 Introduction SOR-CO Summary and Outlook Scenario Untrustworthy Hardware / Software Sebastian Pape Sample or Random Security March 5th, FC14 3 / 24
4 Visual Cryptography - Idea (a) Transparencies side by side (b) Transparencies stacked Sebastian Pape Sample or Random Security March 5th, FC14 4 / 24
5 Pixel-based Visual Crypt. (Naor and Shamir, 1994) + = Figure: Example Figure: Shares With 4 Sub-pixels in a 2x2 Matrix Sebastian Pape Sample or Random Security March 5th, FC14 5 / 24
6 Segment-based Visual Cryptography (Borchert, 2007) Overlay Top Layer (a) full (b) c 1 (c) c 2 Bottom Layer Table: Contingency Table (d) k (e) c 1 k (f) c 2 k Sebastian Pape Sample or Random Security March 5th, FC14 6 / 24
7 Dice Codings (Doberitz, 2008) + Ciphertext Dec Key = Key Cipher Table: Contingency Table Plaintext (5) Sebastian Pape Sample or Random Security March 5th, FC14 7 / 24
8 Visual Cryptography - Application Figure: Keypad of a cash machine Figure: Keypads in visual Cryptography (Borchert, 2007) Sebastian Pape Sample or Random Security March 5th, FC14 8 / 24
9 Reminder: Reusing Key-Transparencies (1) + (2) = (1) + (3) = (2) + (3) = Figure: Combination of 3 transparencies Sebastian Pape Sample or Random Security March 5th, FC14 9 / 24
10 Overview 1 Introduction 2 Sample-Or-Random Security Real-Or-Random Security Sample-Or-Random Security Relation between ROR CPA and SOR CO Evaluation 3 Summary and Outlook Sebastian Pape Sample or Random Security March 5th, FC14 10 / 24
11 Real-Or-Random (ROR CPA) Bellare et al. (1997) Experiment Exp ror cpa b (n) = b k GenKey(1 n ) Key generation b R {0, 1} Random choice of b b A O RR(,b) Adversary tries to determine b Adversary s advantage Adv = Pr[correct] Pr[false] Adv ror cpa (n) def = Pr[Exp ror cpa 1 (n) = 1] Pr[Exp ror cpa 0 (n) = 1] Sebastian Pape Sample or Random Security March 5th, FC14 11 / 24
12 Why Ciphertext-Only Securitymodel? CPA is not suitable for visual cryptography Adversary may not have access to an encryption oracle CPA is too strong use of XOR allows determining the key e.g. encryptions of or 8 Allow Trade-off: Weaker securitymodel vs. easier key handling CO-Securitymodel Sample Structure sample struct sample struct returns a finite set of plaintexts following the pattern of struct. Example for Γ = {0, 1,..., n} Π(0, 1,..., n) sample keypad R {γ γ = γ 0 γ 1... γ n i, j with 0 i, j n. γ i γ j } Sebastian Pape Sample or Random Security March 5th, FC14 12 / 24
13 Sample-Or-Random (SOR CO) Experiment Exp sor co b (n) = b k GenKey(1 n ) Key generation b R {0, 1} Random choice of b b A O SR(struct) Adversary tries to determine b Adversary s advantage Adv sor co (n) def Adv = Pr[correct] Pr[false] = Pr[Exp sor co 1 (n) = 1] Pr[Exp sor co 0 A, Π (n) = 1] Sebastian Pape Sample or Random Security March 5th, FC14 13 / 24
14 Relation between ROR CPA and SOR CO LOR-CPA Bellare et al. (1997) ROR-CPA? SOR-CO Figure: Relation between Securitymodels for Symmetric Encryption Sebastian Pape Sample or Random Security March 5th, FC14 14 / 24
15 Relation between ROR CPA and SOR CO Theorem Notion of SOR CO is weaker than ROR CPA. Lemma 1: [ROR CPA SOR CO] If an encryption scheme Π is secure in the sense of ROR CPA, then Π is also secure in the sense of SOR CO. Lemma 2: [SOR CO ROR CPA] If there exists an encryption scheme Π which is secure in the sense of SOR CO, then there is an encryption scheme Π which is secure in the sense of SOR CO but not ROR CPA. Sebastian Pape Sample or Random Security March 5th, FC14 15 / 24
16 [SOR CO ROR CPA] Proof Lemma 2: [SOR CO ROR CPA] If there exists an encryption scheme Π which is secure in the sense of SOR CO, then there is an encryption scheme Π which is secure in the sense of SOR CO but not ROR CPA. Sketch of Proof Assumption: Π = (GenKey, Enc, Dec), SOR CO-secure exists Derive Π = (GenKey, Enc, Dec ), Lemma 2a: SOR CO-secure, Lemma 2b: but not ROR CPA-secure Idea: mark ciphertexts, to contradict ROR CPA-security Sebastian Pape Sample or Random Security March 5th, FC14 16 / 24
17 [SOR CO ROR CPA] derived encryption scheme Sample struct sample 1 sample keypad R {γ γ = γ 0 γ 1... γ n i, j with 0 i, j n. γ i γ j } Algorithms Π = (GenKey, Enc, Dec ): Algorithm GenKey (1 n ): Algorithm Enc k (m): k GenKey(1 n ) c Enc k (c) Algorithm Dec k (c ): c = α 1 α 2... α c return k if m = c := α 2... α c then c := 0 c m := Dec k (c) else return m c := 1 c return c Sebastian Pape Sample or Random Security March 5th, FC14 17 / 24
18 [SOR CO ROR CPA] Lemma 2a - Details Lemma 2a: Π = (GenKey, Enc, Dec ) is secure in the sense of SOR CO given the sample structure sample 1. Proof. b = 0 ( sample mode ): No change, never appears b = 1 ( random mode ): Negligible Adv, Pr[0... 0] = 1 (n+1) n+1 Adv sor co (n) = Pr[Exp sor co 1 (n) = 1] Pr[Exp sor co 0 A, Π (n) = 1] Pr[Exp sor co 1 (n) = 1] + Adv Pr[Exp sor co 0 A, Π (n) = 1] = Adv sor co (n) + Adv Sebastian Pape Sample or Random Security March 5th, FC14 18 / 24
19 [SOR CO ROR CPA] Lemma 2b - Details Lemma 2b: Π = (GenKey, Enc, Dec ) is not secure in the sense of ROR CPA. Proof. Adversary asks O RR (, b) for encryption of If O RR 0... b = 0 ( real mode ) If O RR 1... b = 1 ( random mode ) Adv ror cpa A cpa,π (n) = Pr[Exp ror cpa 1 A cpa,π (n) = 1] Pr[Exp ror cpa 0 A cpa,π (n) = 1] = 1 1 (n + 1) n+1 0 Sebastian Pape Sample or Random Security March 5th, FC14 19 / 24
20 Relation between ROR CPA und SOR CO Lemma 2: [SOR CO ROR CPA] If there exists an encryption scheme Π which is secure in the sense of SOR CO, then there is an encryption scheme Π which is secure in the sense of SOR CO but not ROR CPA. Theorem SOR CO is weaker than ROR CPA. LOR-CPA Bellare et al. (1997) ROR-CPA SOR-CO Sebastian Pape Sample or Random Security March 5th, FC14 20 / 24
21 Evaluation: SOR CO at 7-Segment / Dice Codings Difference of 2 Keypad- Ciphertexts is even Adversary asks for 2 ciphertexts if difference is even b = 0 ( sample mode ) if difference is odd b = 1 ( random mode ) Adv sor co (n) = Pr[Exp sor co 1 (n) = 1] Pr[Exp sor co 0 A, Π (n) = 1] = Pr[A = rand O = rand] Pr[A = rand O = samp] = Idea for countermeasure: add noise to the ciphertexts Sebastian Pape Sample or Random Security March 5th, FC14 21 / 24
22 Dice Codings with Noise + = Ciphertext Key Plaintext (4) Figure: Visualization for n = 9 and ν = 7 Dec Key Cipher Table: Contingency Table Sebastian Pape Sample or Random Security March 5th, FC14 22 / 24
23 Overview 1 Introduction 2 Sample-Or-Random Security 3 Summary and Outlook Sebastian Pape Sample or Random Security March 5th, FC14 23 / 24
24 Summary and Open Questions SOR CO Securitymodel Relation to ROR CPA Visual encryption scheme making use of noise Conjecture: SOR-CO-secure if parameters chosen accordingly SOR CO-security Is Random-or-Sample Security a sufficient choice SampleA-or-SampleB Security? What about active adversaries? Dice codings with noise Given n and ν for how many ciphertexts is the scheme SOR-CO-secure? Sebastian Pape Sample or Random Security March 5th, FC14 24 / 24
25 References References References I M. Bellare, A. Desai, E. Jokipii, and P. Rogaway. A concrete security treatment of symmetric encryption. In Proceedings of 38th Annual Symposium on Foundations of Computer Science (FOCS 97), pages , B. Borchert. Segment-based visual cryptography. Technical Report WSI , Wilhelm-Schickard-Institut für Informatik, Tübingen, D. Doberitz. Visual cryptography protocols and their deployment against malware. Master s thesis, Ruhr-Universität Bochum, Germany, M. Naor and A. Shamir. Visual cryptography. In A. D. Santis, editor, EUROCRYPT, volume 950 of Lecture Notes in Computer Science, pages Springer, ISBN Sebastian Pape Sample or Random Security March 5th, FC14 25 / 24
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