Assembly Language Tutorial

Transcription

1 Assembly Language Tutorial

2 ASSEMBLY LANGUAGE TUTORIAL by tutorialspoint.com tutorialspoint.com i

3 ABOUT THE TUTORIAL Assembly Programming Tutorial Assembly language is a low-level programming language for a computer, or other programmable device specific to a particular computer architecture in contrast to most highlevel programming languages, which are generally portable across multiple systems. Assembly language is converted into executable machine code by a utility program referred to as an assembler like NASM, MASM etc. Audience This tutorial has been designed for software programmers with a need to understand the Assembly programming language starting from scratch. This tutorial will give you enough understanding on Assembly programming language from where you can take yourself at higher level of expertise. Prerequisites Before proceeding with this tutorial you should have a basic understanding of Computer Programming terminologies. A basic understanding of any of the programming languages will help you in understanding the Assembly programming concepts and move fast on the learning track.

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5 Table of Content Assembly Programming Tutorial... 2 Audience... 2 Prerequisites... 2 Copyright & Disclaimer Notice... 3 Assembly Introduction... 8 What is Assembly Language?... 8 Advantages of Assembly Language... 8 Basic Features of PC Hardware... 9 The Binary Number System... 9 The Hexadecimal Number System... 9 Binary Arithmetic Addressing Data in Memory Assembly Environment Setup Installing NASM Assembly Basic Syntax The data Section The bss Section The text section Comments Assembly Language Statements Syntax of Assembly Language Statements The Hello World Program in Assembly Compiling and Linking an Assembly Program in NASM Assembly Memory Segments Memory Segments Assembly Registers Processor Registers Data Registers Pointer Registers Index Registers Control Registers Segment Registers Example: Assembly System Calls Linux System Calls Example Addressing Modes... 27

6 Register Addressing Immediate Addressing Direct Memory Addressing Direct-Offset Addressing Indirect Memory Addressing The MOV Instruction SYNTAX: EXAMPLE: Assembly Variables Allocating Storage Space for Initialized Data Allocating Storage Space for Uninitialized Data Multiple Definitions Multiple Initializations Assembly Constants The EQU Directive Example: The %assign Directive The %define Directive Arithmetic Instructions SYNTAX: EXAMPLE: The DEC Instruction SYNTAX: EXAMPLE: The ADD and SUB Instructions SYNTAX: EXAMPLE: The MUL/IMUL Instruction SYNTAX: EXAMPLE: EXAMPLE: The DIV/IDIV Instructions SYNTAX: EXAMPLE: Logical Instructions The AND Instruction Example: The OR Instruction Example:... 47

7 The XOR Instruction The TEST Instruction The NOT Instruction Assembly Conditions The CMP Instruction SYNTAX EXAMPLE: Unconditional Jump SYNTAX: EXAMPLE: Conditional Jump Example: Assembly Loops Example: Assembly Numbers ASCII Representation BCD Representation Example: Assembly Strings String Instructions MOVS LODS CMPS SCAS Repetition Prefixes Assembly Arrays Example: Assembly Procedures Syntax: Example: Stacks Data Structure: EXAMPLE: Assembly Recursion Assembly Macros Example: Assembly File Management File Descriptor File Pointer File Handling System Calls... 74

8 Creating and Opening a File Opening an Existing File Reading from a File Writing to a File Closing a File Updating a File Example: Memory Management Example:... 79

9 CHAPTER 1 Assembly Introduction What is Assembly Language? Each personal computer has a microprocessor that manages the computer's arithmetical, logical and control activities. Each family of processors has its own set of instructions for handling various operations like getting input from keyboard, displaying information on screen and performing various other jobs. These set of instructions are called 'machine language instruction'. Processor understands only machine language instructions which are strings of 1s and 0s. However machine language is too obscure and complex for using in software development. So the low level assembly language is designed for a specific family of processors that represents various instructions in symbolic code and a more understandable form. Advantages of Assembly Language An understanding of assembly language provides knowledge of: Interface of programs with OS, processor and BIOS; Representation of data in memory and other external devices; How processor accesses and executes instruction; How instructions accesses and process data; How a program access external devices. Other advantages of using assembly language are: It requires less memory and execution time; It allows hardware-specific complex jobs in an easier way; It is suitable for time-critical jobs;

10 It is most suitable for writing interrupt service routines and other memory resident programs. Basic Features of PC Hardware The main internal hardware of a PC consists of the processor, memory and the registers. The registers are processor components that hold data and address. To execute a program the system copies it from the external device into the internal memory. The processor executes the program instructions. The fundamental unit of computer storage is a bit; it could be on (1) or off (0). A group of nine related bits makes a byte. Eight bits are used for data and the last one is used for parity. According to the rule of parity, number of bits that are on (1) in each byte should always be odd. So the parity bit is used to make the number of bits in a byte odd. If the parity is even, the system assumes that there had been a parity error (though rare) which might have caused due to hardware fault or electrical disturbance. The processor supports the following data sizes: Word: a 2-byte data item Doubleword: a 4-byte (32 bit) data item Quadword: an 8-byte (64 bit) data item Paragraph: a 16-byte (128 bit) area Kilobyte: 1024 bytes Megabyte: 1,048,576 bytes The Binary Number System Every number system uses positional notation i.e., each position in which a digit is written has a different positional value. Each position is power of the base, which is 2 for binary number system, and these powers begin at 0 and increase by 1. The following table shows the positional values for an 8-bit binary number, where all bits are set on. Bit value Position value as a power of base Bit number The value of a binary number is based on the presence of 1 bits and their positional value. So the value of the given binary number is: = 255, which is same as The Hexadecimal Number System Hexadecimal number system uses base 16. The digits range from 0 to 15. By convention, the letters A through F is used to represent the hexadecimal digits corresponding to decimal values 10 through 15.

11 Main use of hexadecimal numbers in computing is for abbreviating lengthy binary representations. Basically hexadecimal number system represents a binary data by dividing each byte in half and expressing the value of each half-byte. The following table provides the decimal, binary and hexadecimal equivalents: Decimal number Binary representation Hexadecimal representation A B C D E F To convert a binary number to its hexadecimal equivalent, break it into groups of 4 consecutive groups each, starting from the right, and write those groups over the corresponding digits of the hexadecimal number. Example: Binary number is equivalent to hexadecimal - 8CD1 To convert a hexadecimal number to binary just write each hexadecimal digit into its 4-digit binary equivalent. Example: Hexadecimal number FAD8 is equivalent to binary Binary Arithmetic The following table illustrates four simple rules for binary addition: (i) (ii) (iii) (iv) =0 =1 =10 =11 Rules (iii) and (iv) shows a carry of a 1-bit into the next left position. Example: 1

12 Decimal Binary A negative binary value is expressed in two's complement notation. According to this rule, to convert a binary number to its negative value is to reverse its bit values and add 1. Example: Number Reverse the bits Add 1 1 Number To subtract one value from another, convert the number being subtracted to two's complement format and add the numbers. Example: Subtract 42 from 53 Number Number Reverse the bits of Add 1 1 Number = Overflow of the last 1 bit is lost. Addressing Data in Memory The process through which the processor controls the execution of instructions is referred as the fetch-decodeexecute cycle, or the execution cycle. It consists of three continuous steps: Fetching the instruction from memory Decoding or identifying the instruction Executing the instruction The processor may access one or more bytes of memory at a time. Let us consider a hexadecimal number 0725H. This number will require two bytes of memory. The high-order byte or most significant byte is 07 and the low order byte is 25. The processor stores data in reverse-byte sequence i.e., the low-order byte is stored in low memory address and high-order byte in high memory address. So if processor brings the value 0725H from register to memory, it will transfer 25 first to the lower memory address and 07 to the next memory address.

13 x: memory address When the processor gets the numeric data from memory to register, it again reverses the bytes. There are two kinds of memory addresses: An absolute address - a direct reference of specific location. The segment address (or offset) - starting address of a memory segment with the offset value

14 CHAPTER 2 Assembly Environment Setup Assembly language is dependent upon the instruction set and the architecture of the processor. In this tutorial, we focus on Intel 32 processors like Pentium. To follow this tutorial, you will need: An IBM PC or any equivalent compatible computer A copy of Linux operating system A copy of NASM assembler program There are many good assembler programs, like: Microsoft Assembler (MASM) Borland Turbo Assembler (TASM) The GNU assembler (GAS) We will use the NASM assembler, as it is: Free. You can download it from various web sources. Well documented and you will get lots of information on net. Could be used on both Linux and Windows Installing NASM If you select "Development Tools" while installed Linux, you may NASM installed along with the Linux operating system and you do not need to download and install it separately. For checking whether you already have NASM installed, take the following steps: Open a Linux terminal. Type whereis nasm and press ENTER. If it is already installed then a line like, nasm: /usr/bin/nasm appears. Otherwise, you will see justnasm:, then you need to install NASM. To install NASM take the following steps:

15 Check The netwide assembler (NASM) website for the latest version. Download the Linux source archive nasm-x.xx. ta.gz, where X.XX is the NASM version number in the archive. Unpack the archive into a directory, which creates a subdirectory nasm-x. XX. cd to nasm-x. XX and type./configure. This shell script will find the best C compiler to use and set up Makefiles accordingly. Type make to build the nasm and ndisasm binaries. Type make install to install nasm and ndisasm in /usr/local/bin and to install the man pages. This should install NASM on your system. Alternatively, you can use an RPM distribution for the Fedora Linux. This version is simpler to install, just double-click the RPM file.

16 CHAPTER 3 Assembly Basic Syntax An assembly program can be divided into three sections: The data section The bss section The text section The data Section The data section is used for declaring initialized data or constants. This data does not change at runtime. You can declare various constant values, file names or buffer size etc. in this section. The syntax for declaring data section is: section.data The bss Section The bss section is used for declaring variables. The syntax for declaring bss section is: section.bss The text section The text section is used for keeping the actual code. This section must begin with the declarationglobal main, which tells the kernel where the program execution begins. The syntax for declaring text section is: section.text global main main: Comments Assembly language comment begins with a semicolon (;). It may contain any printable character including blank. It can appear on a line by itself, like:

17 ; This program displays a message on screen or, on the same line along with an instruction, like: add eax,ebx ; adds ebx to eax Assembly Language Statements Assembly language programs consist of three types of statements: Executable instructions or instructions Assembler directives or pseudo-ops Macros The executable instructions or simply instructions tell the processor what to do. Each instruction consists of an operation code (opcode). Each executable instruction generates one machine language instruction. The assembler directives or pseudo-ops tell the assembler about the various aspects of the assembly process. These are non-executable and do not generate machine language instructions. Macros are basically a text substitution mechanism. Syntax of Assembly Language Statements Assembly language statements are entered one statement per line. Each statement follows the following format: [label] mnemonic [operands] [;comment] The fields in the square brackets are optional. A basic instruction has two parts, the first one is the name of the instruction (or the mnemonic) which is to be executed, and the second are the operands or the parameters of the command. Following are some examples of typical assembly language statements: INC COUNT MOV TOTAL, 48 ADD AH, BH AND MASK1, 128 ADD MARKS, 10 MOV AL, 10 ; Increment the memory variable COUNT ; Transfer the value 48 in the ; memory variable TOTAL ; Add the content of the ; BH register into the AH register ; Perform AND operation on the ; variable MASK1 and 128 ; Add 10 to the variable MARKS ; Transfer the value 10 to the AL register The Hello World Program in Assembly The following assembly language code displays the string 'Hello World' on the screen: section.text global main main: mov edx,len mov ecx,msg mov ebx,1 mov eax,4 int 0x80 ;must be declared for linker (ld) ;tells linker entry point ;message length ;message to write ;file descriptor (stdout) ;system call number (sys_write) ;call kernel

18 mov eax,1 int 0x80 ;system call number (sys_exit) ;call kernel section.data msg db 'Hello, world!', 0xa ;our dear string len equ $ - msg ;length of our dear string When the above code is compiled and executed, it produces following result: Hello, world! Compiling and Linking an Assembly Program in NASM Make sure you have set the path of nasm and ld binaries in your PATH environment variable. Now take the following steps for compiling and linking the above program: Type the above code using a text editor and save it as hello.asm. Make sure that you are in the same directory as where you saved hello.asm. To assemble the program, type nasm -f elf hello.asm If there is any error, you will be prompted about that at this stage. Otherwise an object file of your program named hello.o will be created. To link the object file and create an executable file named hello, type ld -m elf_i386 -s -o hello hello.o Execute the program by typing./hello If you have done everything correctly, it will display Hello, world! on the screen.

19 CHAPTER 4 Assembly Memory Segments We have already discussed three sections of an assembly program. These sections represent various memory segments as well. Interestingly, if you replace the section keyword with segment, you will get the same result. Try the following code: segment.text ;code segment global main ;must be declared for linker main: ;tell linker entry point mov edx,len ;message length mov ecx,msg ;message to write mov ebx,1 ;file descriptor (stdout) mov eax,4 ;system call number (sys_write) int 0x80 ;call kernel mov eax,1 int 0x80 ;system call number (sys_exit) ;call kernel segment.data ;data segment msg db Hello, world!',0xa ;our dear string len equ $ - msg ;length of our dear string When the above code is compiled and executed, it produces following result: Hello, world! Memory Segments A segmented memory model divides the system memory into groups of independent segments, referenced by pointers located in the segment registers. Each segment is used to contain a specific type of data. One segment is used to contain instruction codes, another segment stores the data elements, and a third segment keeps the program stack. In the light of the above discussion, we can specify various memory segments as: Data segment - it is represented by.data section and the.bss. The.data section is used to declare the memory region where data elements are stored for the program. This section cannot be expanded after the data elements are declared, and it remains static throughout the program. The.bss section is also a static memory section that contains buffers for data to be declared later in the program. This buffer memory is zero-filled.

20 Code segment - it is represented by.text section. This defines an area in memory that stores the instruction codes. This is also a fixed area. Stack - this segment contains data values passed to functions and procedures within the program.

21 CHAPTER 5 Assembly Registers Processor operations mostly involve processing data. This data can be stored in memory and accessed from thereon. However, reading data from and storing data into memory slows down the processor, as it involves complicated processes of sending the data request across the control bus, and into the memory storage unit and getting the data through the same channel. To speed up the processor operations, the processor includes some internal memory storage locations, called registers. The registers stores data elements for processing without having to access the memory. A limited number of registers are built into the processor chip. Processor Registers There are ten 32-bit and six 16-bit processor registers in IA-32 architecture. The registers are grouped into three categories: General registers Control registers Segment registers The general registers are further divided into the following groups: Data registers Pointer registers Index registers Data Registers Four 32-bit data registers are used for arithmetic, logical and other operations. These 32-bit registers can be used in three ways: 1. As complete 32-bit data registers: EAX, EBX, ECX, EDX.

22 2. Lower halves of the 32-bit registers can be used as four 16-bit data registers: AX, BX, CX and DX. 3. Lower and higher halves of the above-mentioned four 16-bit registers can be used as eight 8-bit data registers: AH, AL, BH, BL, CH, CL, DH, and DL. Some of these data registers has specific used in arithmetical operations. AX is the primary accumulator; it is used in input/output and most arithmetic instructions. For example, in multiplication operation, one operand is stored in EAX, or AX or AL register according to the size of the operand. BX is known as the base register as it could be used in indexed addressing. CX is known as the count register as the ECX, CX registers store the loop count in iterative operations. DX is known as the data register. It is also used in input/output operations. It is also used with AX register along with DX for multiply and divide operations involving large values. Pointer Registers The pointer registers are 32-bit EIP, ESP and EBP registers and corresponding 16-bit right portions IP, SP and BP. There are three categories of pointer registers: Instruction Pointer (IP) - the 16-bit IP register stores the offset address of the next instruction to be executed. IP in association with the CS register (as CS:IP) gives the complete address of the current instruction in the code segment. Stack Pointer (SP) - the 16-bit SP register provides the offset value within the program stack. SP in association with the SS register (SS:SP) refers to be current position of data or address within the program stack. Base Pointer (BP) - the 16-bit BP register mainly helps in referencing the parameter variables passed to a subroutine. The address in SS register is combined with the offset in BP to get the location of the parameter. BP can also be combined with DI and SI as base register for special addressing. Index Registers The 32-bit index registers ESI and EDI and their 16-bit rightmost portions SI and DI are used for indexed addressing and sometimes used in addition and subtraction. There are two sets of index pointers: Source Index (SI) - it is used as source index for string operations Destination Index (DI) - it is used as destination index for string operations.

23 Control Registers The 32-bit instruction pointer register and 32-bit flags register combined are considered as the control registers. Many instructions involve comparisons and mathematical calculations and change the status of the flags and some other conditional instructions test the value of these status flags to take the control flow to other location. The common flag bits are: Overflow Flag (OF): indicates the overflow of a high-order bit (leftmost bit) of data after a signed arithmetic operation. Direction Flag (DF): determines left or right direction for moving or comparing string data. When the DF value is 0, the string operation takes left-to-right direction and when the value is set to 1, the string operation takes right-to-left direction. Interrupt Flag (IF): determines whether the external interrupts like, keyboard entry etc. are to be ignored or processed. It disables the external interrupt when the value is 0 and enables interrupts when set to 1. Trap Flag (TF): allows setting the operation of the processor in single-step mode. The DEBUG program we used sets the trap flag, so we could step through the execution one instruction at a time. Sign Flag (SF): shows the sign of the result of an arithmetic operation. This flag is set according to the sign of a data item following the arithmetic operation. The sign is indicated by the high-order of leftmost bit. A positive result clears the value of SF to 0 and negative result sets it to 1. Zero Flag (ZF): indicates the result of an arithmetic or comparison operation. A nonzero result clears the zero flag to 0, and a zero result sets it to 1. Auxiliary Carry Flag (AF): contains the carry from bit 3 to bit 4 following an arithmetic operation; used for specialized arithmetic. The AF is set when a 1-byte arithmetic operation causes a carry from bit 3 into bit 4. Parity Flag (PF): indicates the total number of 1-bits in the result obtained from an arithmetic operation. An even number of 1-bits clears the parity flag to 0 and an odd number of 1-bits sets the parity flag to 1. Carry Flag (CF): contains the carry of 0 or 1 from a high-order bit (leftmost) after an arithmetic operation. It also stores the contents of last bit of a shift or rotate operation. The following table indicates the position of flag bits in the 16-bit Flags register: Flag: O D I T S Z A P C Bit no: Segment Registers Segments are specific areas defined in a program for containing data, code and stack. There are three main segments: Code Segment: it contains all the instructions to be executed. A 16 - bit Code Segment register or CS register stores the starting address of the code segment. Data Segment: it contains data, constants and work areas. A 16 - bit Data Segment register of DS register stores the starting address of the data segment. Stack Segment: it contains data and return addresses of procedures or subroutines. It is implemented as a 'stack' data structure. The Stack Segment register or SS register stores the starting address of the stack.

24 Apart from the DS, CS and SS registers, there are other extra segment registers - ES (extra segment), FS and GS, which provides additional segments for storing data. In assembly programming, a program needs to access the memory locations. All memory locations within a segment are relative to the starting address of the segment. A segment begins in an address evenly disable by 16 or hexadecimal 10. So all the rightmost hex digit in all such memory addresses is 0, which is not generally stored in the segment registers. The segment registers stores the starting addresses of a segment. To get the exact location of data or instruction within a segment, an offset value (or displacement) is required. To reference any memory location in a segment, the processor combines the segment address in the segment register with the offset value of the location. Example: Look at the following simple program to understand the use of registers in assembly programming. This program displays 9 stars on the screen along with a simple message: section.text global main ;must be declared for linker (gcc) main: ;tell linker entry point mov edx,len ;message length mov ecx,msg ;message to write mov ebx,1 ;file descriptor (stdout) mov eax,4 ;system call number (sys_write) mov edx,9 ;message length mov ecx,s2 ;message to write mov ebx,1 ;file descriptor (stdout) mov eax,4 ;system call number (sys_write) mov eax,1 ;system call number (sys_exit) section.data msg db 'Displaying 9 stars',0xa ;a message len equ $ - msg ;length of message s2 times 9 db '*' When the above code is compiled and executed, it produces following result: Displaying 9 stars *********

25 CHAPTER 6 Assembly System Calls System calls are APIs for the interface between user space and kernel space. We have already used the system calls sys_write and sys_exit for writing into the screen and exiting from the program respectively. Linux System Calls You can make use of Linux system calls in your assembly programs. You need to take the following steps for using Linux system calls in your program: Put the system call number in the EAX register. Store the arguments to the system call in the registers EBX, ECX, etc. Call the relevant interrupt (80h) The result is usually returned in the EAX register There are six registers that stores the arguments of the system call used. These are the EBX, ECX, EDX, ESI, EDI, and EBP. These registers take the consecutive arguments, starting with the EBX register. If there are more than six arguments then the memory location of the first argument is stored in the EBX register. The following code snippet shows the use of the system call sys_exit: mov eax,1 ; system call number (sys_exit) int 0x80 ; call kernel The following code snippet shows the use of the system call sys_write: mov edx,4 ; message length mov ecx,msg ; message to write mov ebx,1 ; file descriptor (stdout) mov eax,4 ; system call number (sys_write) int 0x80 ; call kernel All the syscalls are listed in /usr/include/asm/unistd.h, together with their numbers (the value to put in EAX before you call int 80h). The following table shows some of the system calls used in this tutorial:

26 %eax Name %ebx %ecx %edx %esx %edi 1 sys_exit int sys_fork struct pt_regs sys_read unsigned int char * size_t sys_write unsigned int const char * size_t sys_open const char * int int sys_close unsigned int Example The following example reads a number from the keyboard and displays it on the screen: section.data ;Data segment usermsg db 'Please enter a number: ' ;Ask the user to enter a number lenusermsg equ $-usermsg ;The length of the message dispmsg db 'You have entered: ' lendispmsg equ $-dispmsg section.bss ;Uninitialized data num resb 5 section.text ;Code Segment global main main: ;User prompt mov eax, 4 mov ebx, 1 mov ecx, usermsg mov edx, lenusermsg int 80h ;Read and store the user input mov eax, 3 mov ebx, 2 mov ecx, num mov edx, 5 ;5 bytes (numeric, 1 for sign) of that information int 80h ;Output the message 'The entered number is: ' mov eax, 4 mov ebx, 1 mov ecx, dispmsg mov edx, lendispmsg int 80h ;Output the number entered mov eax, 4 mov ebx, 1 mov ecx, num mov edx, 5 int 80h ; Exit code mov eax, 1 mov ebx, 0 int 80h When the above code is compiled and executed, it produces following result:

27 Please enter a number: 1234 You have entered:1234

28 CHAPTER 7 Addressing Modes Most assembly language instructions require operands to be processed. An operand address provides the location where the data to be processed is stored. Some instructions do not require an operand, whereas some other instructions may require one, two or three operands. When an instruction requires two operands, the first operand is generally the destination, which contains data in a register or memory location and the second operand is the source. Source contains either the data to be delivered (immediate addressing) or the address (in register or memory) of the data. Generally the source data remains unaltered after the operation. The three basic modes of addressing are: Register addressing Immediate addressing Memory addressing Register Addressing In this addressing mode, a register contains the operand. Depending upon the instruction, the register may be the first operand, the second operand or both. For example, MOV DX, TAX_RATE MOV COUNT, CX MOV EAX, EBX ; Register in first operand ; Register in second operand ; Both the operands are in registers As processing data between registers does not involve memory, it provides fastest processing of data. Immediate Addressing An immediate operand has a constant value or an expression. When an instruction with two operands uses immediate addressing, the first operand may be a register or memory location, and the second operand is an immediate constant. The first operand defines the length of the data. For example: BYTE_VALUE DB 150 WORD_VALUE DW 300 ADD BYTE_VALUE, 65 MOV AX, 45H ; A byte value is defined ; A word value is defined ; An immediate operand 65 is added ; Immediate constant 45H is transferred to AX

29 Direct Memory Addressing When operands are specified in memory addressing mode, direct access to main memory, usually to the data segment, is required. This way of addressing results in slower processing of data. To locate the exact location of data in memory, we need the segment start address, which is typically found in the DS register and an offset value. This offset value is also called effective address. In direct addressing mode, the offset value is specified directly as part of the instruction, usually indicated by the variable name. The assembler calculates the offset value and maintains a symbol table, which stores the offset values of all the variables used in the program. In direct memory addressing, one of the operands refers to a memory location and the other operand references a register. For example, ADD BYTE_VALUE, DL ; Adds the register in the memory location MOV BX, WORD_VALUE ; Operand from the memory is added to register Direct-Offset Addressing This addressing mode uses the arithmetic operators to modify an address. For example, look at the following definitions that define tables of data: BYTE_TABLE DB 14, 15, 22, 45 ; Tables of bytes WORD_TABLE DW 134, 345, 564, 123 ; Tables of words The following operations access data from the tables in the memory into registers: MOV CL, BYTE_TABLE[2] MOV CL, BYTE_TABLE + 2 MOV CX, WORD_TABLE[3] MOV CX, WORD_TABLE + 3 Indirect Memory Addressing ; Gets the 3rd element of the BYTE_TABLE ; Gets the 3rd element of the BYTE_TABLE ; Gets the 4th element of the WORD_TABLE ; Gets the 4th element of the WORD_TABLE This addressing mode utilizes the computer's ability of Segment:Offset addressing. Generally the base registers EBX, EBP (or BX, BP) and the index registers (DI, SI), coded within square brackets for memory references, are used for this purpose. Indirect addressing is generally used for variables containing several elements like, arrays. Starting address of the array is stored in, say, the EBX register. The following code snippet shows how to access different elements of the variable. MY_TABLE TIMES 10 DW 0 ; Allocates 10 words (2 bytes) each initialized to 0 MOV EBX, [MY_TABLE] ; Effective Address of MY_TABLE in EBX MOV [EBX], 110 ; MY_TABLE[0] = 110 ADD EBX, 2 ; EBX = EBX +2 MOV [EBX], 123 ; MY_TABLE[1] = 123 The MOV Instruction We have already used the MOV instruction that is used for moving data from one storage space to another. The MOV instruction takes two operands. SYNTAX: Syntax of the MOV instruction is:

30 MOV destination, source The MOV instruction may have one of the following five forms: MOV register, register MOV register, immediate MOV memory, immediate MOV register, memory MOV memory, register Please note that: Both the operands in MOV operation should be of same size The value of source operand remains unchanged The MOV instruction causes ambiguity at times. For example, look at the statements: MOV EBX, [MY_TABLE] ; Effective Address of MY_TABLE in EBX MOV [EBX], 110 ; MY_TABLE[0] = 110 It is not clear whether you want to move a byte equivalent or word equivalent of the number 110. In such cases, it is wise to use a type specifier. Following table shows some of the common type specifiers: Type Specifier Bytes addressed BYTE 1 WORD 2 DWORD 4 QWORD 8 TBYTE 10 EXAMPLE: The following program illustrates some of the concepts discussed above. It stores a name 'Zara Ali' in the data section of the memory. Then changes its value to another name 'Nuha Ali' programmatically and displays both the names. section.text global main ;must be declared for linker (ld) main: ;tell linker entry point ;writing the name 'Zara Ali' mov edx,9 ;message length mov ecx, name ;message to write mov ebx,1 ;file descriptor (stdout) mov eax,4 ;system call number (sys_write) mov [name], dword 'Nuha' ; Changed the name to Nuha Ali ;writing the name 'Nuha Ali' mov edx,8 ;message length mov ecx,name ;message to write mov ebx,1 ;file descriptor (stdout) mov eax,4 ;system call number (sys_write)

31 mov eax,1 ;system call number (sys_exit) section.data name db 'Zara Ali ' When the above code is compiled and executed, it produces following result: Zara Ali Nuha Ali

32 CHAPTER 8 Assembly Variables NASM provides various define directives for reserving storage space for variables. The define assembler directive is used for allocation of storage space. It can be used to reserve as well as initialize one or more bytes. Allocating Storage Space for Initialized Data The syntax for storage allocation statement for initialized data is: [variable-name] define-directive initial-value [,initial-value]... Where, variable-name is the identifier for each storage space. The assembler associates an offset value for each variable name defined in the data segment. There are five basic forms of the define directive: Directive Purpose Storage Space DB Define Byte allocates 1 byte DW Define Word allocates 2 bytes DD Define Doubleword allocates 4 bytes DQ Define Quadword allocates 8 bytes DT Define Ten Bytes allocates 10 bytes Following are some examples of using define directives: choice DB 'y' number DW neg_number DW big_number DQ real_number1 DD real_number2 DQ Please note that: Each byte of character is stored as its ASCII value in hexadecimal Each decimal value is automatically converted to its 16-bit binary equivalent and stored as a hexadecimal number

33 Processor uses the little-endian byte ordering Negative numbers are converted to its 2's complement representation Short and long floating-point numbers are represented using 32 or 64 bits, respectively The following program shows use of the define directive: section.text global main ;must be declared for linker (gcc) main: ;tell linker entry point section.data choice DB 'y' mov edx,1 ;message length mov ecx,choice ;message to write mov ebx,1 ;file descriptor (stdout) mov eax,4 ;system call number (sys_write) mov eax,1 ;system call number (sys_exit) When the above code is compiled and executed, it produces following result: y Allocating Storage Space for Uninitialized Data The reserve directives are used for reserving space for uninitialized data. The reserve directives take a single operand that specifies the number of units of space to be reserved. Each define directive has a related reserve directive. There are five basic forms of the reserve directive: Directive RESB RESW RESD RESQ Purpose Reserve a Byte Reserve a Word Reserve a Doubleword Reserve a Quadword REST Multiple Definitions Reserve a Ten Bytes You can have multiple data definition statements in a program. For example: choice DB 'Y' ;ASCII of y = 79H number1 DW ;12345D = 3039H number2 DD ; D = 75BCD15H The assembler allocates contiguous memory for multiple variable definitions.

34 Multiple Initializations The TIMES directive allows multiple initializations to the same value. For example, an array named marks of size 9 can be defined and initialized to zero using the following statement: marks TIMES 9 DW 0 The TIMES directive is useful in defining arrays and tables. The following program displays 9 asterisks on the screen: section.text global main ;must be declared for linker (ld) main: ;tell linker entry point mov edx,9 ;message length mov ecx, stars ;message to write mov ebx,1 ;file descriptor (stdout) mov eax,4 ;system call number (sys_write) mov eax,1 ;system call number (sys_exit) section.data stars times 9 db '*' When the above code is compiled and executed, it produces following result: *********

35 CHAPTER 9 Assembly Constants There are several directives provided by NASM that define constants. We have already used the EQU directive in previous chapters. We will particularly discuss three directives: EQU %assign %define The EQU Directive The EQU directive is used for defining constants. The syntax of the EQU directive is as follows: CONSTANT_NAME EQU expression For example, TOTAL_STUDENTS equ 50 You can then use this constant value in your code, like: mov ecx, TOTAL_STUDENTS cmp eax, TOTAL_STUDENTS The operand of an EQU statement can be an expression: LENGTH equ 20 WIDTH equ 10 AREA equ length * width Above code segment would define AREA as 200. Example: The following example illustrates the use of the EQU directive: SYS_EXIT equ 1 SYS_WRITE equ 4

36 STDIN equ 0 STDOUT equ 1 section.text global main ;must be declared for using gcc main: ;tell linker entry point mov eax, SYS_WRITE mov ebx, STDOUT mov ecx, msg1 mov edx, len1 int 0x80 mov eax, SYS_WRITE mov ebx, STDOUT mov ecx, msg2 mov edx, len2 int 0x80 mov eax, SYS_WRITE mov ebx, STDOUT mov ecx, msg3 mov edx, len3 int 0x80 mov eax,sys_exit int 0x80 ;system call number (sys_exit) ;call kernel section.data msg1 db 'Hello, programmers!',0xa,0xd len1 equ $ - msg1 msg2 db 'Welcome to the world of,', 0xA,0xD len2 equ $ - msg2 msg3 db 'Linux assembly programming! ' len3 equ $- msg3 When the above code is compiled and executed, it produces following result: Hello, programmers! Welcome to the world of, Linux assembly programming! The %assign Directive The %assign directive can be used to define numeric constants like the EQU directive. This directive allows redefinition. For example, you may define the constant TOTAL as: %assign TOTAL 10 Later in the code you can redefine it as: %assign TOTAL 20 This directive is case-sensitive. The %define Directive The %define directive allows defining both numeric and string constants. This directive is similar to the #define in C. For example, you may define the constant PTR as: %define PTR [EBP+4]

37 The above code replaces PTR by [EBP+4]. This directive also allows redefinition and it is case sensitive.

38 Arithmetic Instructions The INC Instruction CHAPTER 10 The INC instruction is used for incrementing an operand by one. It works on a single operand that can be either in a register or in memory. SYNTAX: The INC instruction has the following syntax: INC destination The operand destination could be an 8-bit, 16-bit or 32-bit operand. EXAMPLE: INC EBX ; Increments 32-bit register INC DL ; Increments 8-bit register INC [count] ; Increments the count variable The DEC Instruction The DEC instruction is used for decrementing an operand by one. It works on a single operand that can be either in a register or in memory. SYNTAX: The DEC instruction has the following syntax: DEC destination The operand destination could be an 8-bit, 16-bit or 32-bit operand. EXAMPLE: segment.data count dw 0 value db 15 segment.text inc [count]

39 dec [value] mov ebx, count inc word [ebx] mov esi, value dec byte [esi] The ADD and SUB Instructions The ADD and SUB instructions are used for performing simple addition/subtraction of binary data in byte, word and doubleword size, i.e., for adding or subtracting 8-bit, 16-bit or 32-bit operands respectively. SYNTAX: The ADD and SUB instructions have the following syntax: ADD/SUB destination, source The ADD/SUB instruction can take place between: Register to register Memory to register Register to memory Register to constant data Memory to constant data However, like other instructions, memory-to-memory operations are not possible using ADD/SUB instructions. An ADD or SUB operation sets or clears the overflow and carry flags. EXAMPLE: The following example asks two digits from the user, stores the digits in the EAX and EBX register respectively, adds the values, stores the result in a memory location 'res' and finally displays the result. SYS_EXIT equ 1 SYS_READ equ 3 SYS_WRITE equ 4 STDIN equ 0 STDOUT equ 1 segment.data msg1 db "Enter a digit ", 0xA,0xD len1 equ $- msg1 msg2 db "Please enter a second digit", 0xA,0xD len2 equ $- msg2 msg3 db "The sum is: " len3 equ $- msg3 segment.bss

40 num1 resb 2 num2 resb 2 res resb 1 section.text global main ;must be declared for using gcc main: ;tell linker entry point mov eax, SYS_WRITE mov ebx, STDOUT mov ecx, msg1 mov edx, len1 int 0x80 mov eax, SYS_READ mov ebx, STDIN mov ecx, num1 mov edx, 2 int 0x80 mov eax, SYS_WRITE mov ebx, STDOUT mov ecx, msg2 mov edx, len2 int 0x80 mov eax, SYS_READ mov ebx, STDIN mov ecx, num2 mov edx, 2 int 0x80 mov eax, SYS_WRITE mov ebx, STDOUT mov ecx, msg3 mov edx, len3 int 0x80 ; moving the first number to eax register and second number to ebx ; and subtracting ascii '0' to convert it into a decimal number mov eax, [number1] sub eax, '0' mov ebx, [number2] sub ebx, '0' ; add eax and ebx add eax, ebx ; add '0' to to convert the sum from decimal to ASCII add eax, '0' ; storing the sum in memory location res mov [res], eax ; print the sum mov eax, SYS_WRITE mov ebx, STDOUT mov ecx, res mov edx, 1 int 0x80 exit: mov eax, SYS_EXIT xor ebx, ebx

41 int 0x80 When the above code is compiled and executed, it produces following result: Enter a digit: 3 Please enter a second digit: 4 The sum is: 7 The program with hardcoded variables: section.text global main ;must be declared for using gcc main: ;tell linker entry point mov eax,'3' sub eax, '0' mov ebx, '4' sub ebx, '0' add eax, ebx add eax, '0' mov [sum], eax mov ecx,msg mov edx, len mov ebx,1 ;file descriptor (stdout) mov eax,4 ;system call number (sys_write) nwln mov ecx,sum mov edx, 1 mov ebx,1 ;file descriptor (stdout) mov eax,4 ;system call number (sys_write) mov eax,1 ;system call number (sys_exit) section.data msg db "The sum is:", 0xA,0xD len equ $ - msg segment.bss sum resb 1 When the above code is compiled and executed, it produces following result: The sum is: 7 The MUL/IMUL Instruction There are two instructions for multiplying binary data. The MUL (Multiply) instruction handles unsigned data and the IMUL (Integer Multiply) handles signed data. Both instructions affect the Carry and Overflow flag. SYNTAX: The syntax for the MUL/IMUL instructions is as follows: MUL/IMUL multiplier

42 Multiplicand in both cases will be in an accumulator, depending upon the size of the multiplicand and the multiplier and the generated product is also stored in two registers depending upon the size of the operands. Following section explains MULL instructions with three different cases: SN Scenarios When two bytes are multiplied 1 The multiplicand is in the AL register, and the multiplier is a byte in the memory or in another register. The product is in AX. High order 8 bits of the product is stored in AH and the low order 8 bits are stored in AL When two one-word values are multiplied The multiplicand should be in the AX register, and the multiplier is a word in memory or another register. For example, for an instruction like MUL DX, you must store the multiplier in DX and the multiplicand in AX. 2 The resultant product is a double word, which will need two registers. The High order (leftmost) portion gets stored in DX and the lower-order (rightmost) portion gets stored in AX. When two doubleword values are multiplied 3 When two doubleword values are multiplied, the multiplicand should be in EAX and the multiplier is a doubleword value stored in memory or in another register. The product generated is stored in the EDX:EAX registers, i.e., the high order 32 bits gets stored in the EDX register and the low order 32-bits are stored in the EAX register. EXAMPLE: MOV AL, 10 MOV DL, 25 MUL DL... MOV DL, 0FFH ; DL= -1 MOV AL, 0BEH ; AL = -66 IMUL DL EXAMPLE: The following example multiplies 3 with 2, and displays the result: section.text

43 global main ;must be declared for using gcc main: ;tell linker entry point mov al,'3' sub al, '0' mov bl, '2' sub bl, '0' mul bl add al, '0' mov [res], al mov ecx,msg mov edx, len mov ebx,1 ;file descriptor (stdout) mov eax,4 ;system call number (sys_write) nwln mov ecx,res mov edx, 1 mov ebx,1 ;file descriptor (stdout) mov eax,4 ;system call number (sys_write) mov eax,1 ;system call number (sys_exit) section.data msg db "The result is:", 0xA,0xD len equ $- msg segment.bss res resb 1 When the above code is compiled and executed, it produces following result: The result is: 6 The DIV/IDIV Instructions The division operation generates two elements - a quotient and a remainder. In case of multiplication, overflow does not occur because double-length registers are used to keep the product. However, in case of division, overflow may occur. The processor generates an interrupt if overflow occurs. The DIV (Divide) instruction is used or unsigned data and the IDIV (Integer Divide) is used for signed data. SYNTAX: The format for the DIV/IDIV instruction: DIV/IDIV divisor The dividend is in an accumulator. Both the instructions can work with 8-bit, 16-bit or 32-bit operands. The operation affects all six status flags. Following section explains three cases of division with different operand size: SN Scenarios When the divisor is 1 byte 1 The dividend is assumed to be in the AX register (16 bits). After division, the quotient goes to the AL register and the remainder goes to the AH register.

44 When the divisor is 1 word The dividend is assumed to be 32 bits long and in the DX:AX registers. The high order 16 bits are in DX and the low order 16 bits are in AX. After division, the 16 bit quotient goes to the AX register and the 16 bit remainder goes to the DX register. 2 When the divisor is doubleword The dividend is assumed to be 64 bits long and in the EDX:EAX registers. The high order 32 bits are in EDX and the low order 32 bits are in EAX. After division, the 32 bit quotient goes to the EAX register and the 32 bit remainder goes to the EDX register. 3 EXAMPLE: The following example divides 8 with 2. The dividend 8 is stored in the 16 bit AX register and thedivisor 2 is stored in the 8 bit BL register. section.text global main ;must be declared for using gcc main: ;tell linker entry point mov ax,'8' sub ax, '0' mov bl, '2' sub bl, '0' div bl add ax, '0'

45 mov [res], ax mov ecx,msg mov edx, len mov ebx,1 ;file descriptor (stdout) mov eax,4 ;system call number (sys_write) nwln mov ecx,res mov edx, 1 mov ebx,1 ;file descriptor (stdout) mov eax,4 ;system call number (sys_write) mov eax,1 ;system call number (sys_exit) section.data msg db "The result is:", 0xA,0xD len equ $- msg segment.bss res resb 1 When the above code is compiled and executed, it produces following result: The result is: 4

46 CHAPTER 11 Logical Instructions The processor instruction set provides the instructions AND, OR, XOR, TEST and NOT Boolean logic, which tests, sets and clears the bits according to the need of the program. The format for these instructions: SN Instruction Format 1 AND AND operand1, operand2 2 OR OR operand1, operand2 3 XOR XOR operand1, operand2 4 TEST TEST operand1, operand2 5 NOT NOT operand1 The first operand in all the cases could be either in register or in memory. The second operand could be either in register/memory or an immediate (constant) value. However, memory to memory operations are not possible. These instructions compare or match bits of the operands and set the CF, OF, PF, SF and ZF flags. The AND Instruction The AND instruction is used for supporting logical expressions by performing bitwise AND operation. The bitwise AND operation returns 1, if the matching bits from both the operands are 1, otherwise it returns 0. For example: Operand1: 0101 Operand2: After AND -> Operand1: 0001 The AND operation can be used for clearing one or more bits. For example, say, the BL register contains If you need to clear the high order bits to zero, you AND it with 0FH. AND BL, 0FH ; This sets BL to Let's take up another example. If you want to check whether a given number is odd or even, a simple test would be to check the least significant bit of the number. If this is 1, the number is odd, else the number is even. Assuming the number is in AL register, we can write: