BEAMS: SHEAR AND MOMENT DIAGRAMS (GRAPHICAL)
|
|
- Noah Wheeler
- 7 years ago
- Views:
Transcription
1 LECTURE Third Edition BES: SHER ND OENT DIGRS (GRPHICL). J. Clark School of Engineering Department of Civil and Environmental Engineering 3 Chapter 5.3 by Dr. Ibrahim. ssakkaf SPRING 003 ENES 0 echanics of aterials Department of Civil and Environmental Engineering University of aryland, College Park LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. Eample 8 The beam is loaded and supported as shown in the figure. Write equations for the shear and bending moment for any section of the beam in the interval B. y 6 kn/m B 9 m
2 LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. Eample 8 (cont d) free-body diagram for the beam is shown Fig. 7. The reactions shown on the diagram are determined from equilibrium equations as follows: 8 kn ; 9 kn (9) 0; B B y B R R F R R LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 3 Eample 8 (cont d) y B 6 kn/m R 9 kn R b 8 kn y 9 kn S ( ) 9 for ; 9 for ; 3 < < + + < < + + F S y 6 kn/m 9 m w w kn/m 3 3 Figure 7
3 LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 4 Eample 9 timber beam is loaded as shown in Fig. 8a. The beam has the cross section shown in Fig.8.b. On a transverse cross section ft from the left end, determine a) The fleural stress at point of the cross section b) The fleural stress at point B of the cross section. LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 5 Eample 9 (cont d) y 600 lb 5600 ft-lb 300 lb/ft 3500 ft-lb 6 ft 0 ft 5 ft 900 lb 500 lb Figure 8a 8 B 8 Figure 8b 6
4 LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 6 Eample 9 (cont d) 8 First, we have to determine the moment of inertia I. From symmetry, the neutral ais is located at a distance y 5 in. either from the bottom or the upper edge. Therefore, 5 6 I 3 3 ( 5) 6( 3) in LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 7 y Eample 9 (cont d) 5600 ft-lb 300 lb/ft 5600 ft-lb ft 900 lb lb 00 lb + F S y 3500 ft-lb 500 lb 0; + (00) 0 for 0 < < ft - lb 0; ()(00)(0.5) 0 at ft
5 5 LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No Eample 9 (cont d) 6 a) Stress at r y σ I psi Compression (C) ( )( ) b) Stress at B r y 5500 σ B I psi Tension (T) ( )( 5) psi + 59 psi LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 9 In cases where a beam is subjected to several concentrated forces, couples, and distributed loads, the equilibrium approach discussed previously can be tedious because it would then require several cuts and several free-body diagrams. In this section, a simpler method for constructing shear and moment diagrams are discussed.
6 LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 0 a b L P w O w 3 Figure 9 LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. The beam shown in the Figure 0 is subjected to an arbitrary distributed loading w w() and a series of concentrated forces and couple moments. We will consider the distributed load w to positive when the loading acts upward as shown in Figure 0.
7 LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. P w L L P w R L + C Figure 0a C Figure 0b R + L LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 3 In reference to Fig. 0a at some location, the beam is acted upon by a distributed load w(), a concentrated load force P, and a concentrated couple C. free-body diagram segment of the beam centered at the location is shown in Figure 0b.
8 LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 4 The element must be in equilibrium, therefore, ( + ) + Fy 0; L + wavg + P L 0 From which P + w avg (8) LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 5 In Eq. 8, if the concentrated force P and distributed force w are both zero in some region of the beam, then 0 or L R (9) This implies that the shear force is constant in any segment of the beam where there are no loads.
9 LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 6 If the concentrated load P is not zero, then in the limit as 0, P or R L + P (30) That is, across any concentrated load P, the shear force graph (shear force versus ) jumps by the amount of the concentrated load. LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 7 Furthermore, moving from left to right along the beam, the shear force graph jumps in the direction of the concentrated load. If the concentrated load is zero, then in the limit as 0, we have wavg 0 (3)
10 LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 8 nd the shear force is a continuous function at. Dividing through by in Eq. 3, gives lim0 X d d w (3) That is, the slope of the shear force graph at any section in the beam is equal to the intensity of loading at that section of the beam. LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 9 oving from left to right along the beam, if the distributed force is upward, the slope of the shear force graph (d/d w) is positive and the shear force graph is increasing (moving upward). If the distributed force is zero, then the slope of the shear graph (d/d 0) and the shear force is constant.
11 LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 0 In any region of the beam in which Eq. 3 is valid (any region in which there are no concentrated loads), the equation can be integrated between definite limits to obtain d w d LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. Load and Shear Force Relationships Slope of d d Shear Diagram w( ) (33) Distributed Load Intensity
12 LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. Load and Shear Force Relationships Change in Shear rea under Loading Curve between d w( ) d and (34) LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 3 Similarly, applying moment equilibrium to the free-body diagram of Fig. 0b we obtain ( + ) ( + ) + a( w ) + c 0; - L L L L avg 0 From which C + L + a wavg ( ) (35)
13 LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 4 P w L L P w R L + C Figure 0a C Figure 0b R + L LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 5 In which - / < a < / and in the limit as 0, a 0 and w avg w. Three important relationships are clear from Eq. 35. First, if the concentrated couple is not zero, then in the limit as 0, C or C (36) R L +
14 LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 6 That is, across any concentrated couple C, the bending moment graph (bending moment versus ) jumps by the amount of the concentrated couple. Furthermore, moving from left to right along the beam, the bending moment graph jumps upward for a clockwise concentrated couple and jumps downward for a concentrated counterclockwise C. LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 7 Second, if the concentrated couple C and concentrated force P are both zero, then in the limit as 0, we have L + a( wavg ) 0 (37) and dividing by, gives lim d d (38) 0
15 LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 8 That is, the slope of the bending moment graph at any location in the beam is equal to the value of the shear force at that section of the beam. oving from left to right along the beam, if is positive, then d/d is positive, and the bending moment graph is increasing LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 9 In the region of the beam I which Eq. 38 is valid (any region in which there are no concentrated loads or couples), the equation can be integrated between definite limits to get d d (39)
16 LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 30 Shear Force and Bending oment Relationships Slope of oment Diagram Shear d (40) d LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 3 Shear Force and Bending oment Relationships Change in oment rea under Shear diagram between d d and (4)
17 LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 3 Shear and oment Diagrams Procedure for nalysis Support Reactions Determine the support reactions and resolve the forces acting on the beam into components which are perpendicular and parallel to the beam s ais Shear Diagram Establish the and aes and plot the values of the shear at two ends of the beam. Since d/d w, the slope of the shear diagram at any point is equal to the intensity of the distributed loading at the point. LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 33 Shear and oment Diagrams If a numerical value of the shear is to be determined at the point, one can find this value either by using the methods of establishing equations (formulas)for each section under study or by using Eq. 34, which states that the change in the shear force is equal to the area under the distributed loading diagram. Since w() is integrated to obtain, if w() is a curve of degree n, then () will be a curve of degree n +. For eample, if w() is uniform, () will be linear. oment Diagram Establish the and aes and plot the values of the moment at the ends of the beam.
18 LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 34 Shear and oment Diagrams Since d/d, the slope of the moment diagram at any point is equal to the intensity of the shear at the point. In particular, note that at the point where the shear is zero, that is d/d 0, and therefore this may be a point of maimum or minimum moment. If the numerical value of the moment is to be determined at a point, one can find this value either by using the method of establishing equations (formulas) for each section under study or by using Eq. 4, which states that the change in the moment is equal to the area under the shear diagram. Since w() is integrated to obtain, if w() is a curve of degree n, then () will be a curve of degree n +. For eample, if w() is uniform, () will be linear. LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 35 Shear and oment Diagrams Loading Shear Diagram, d w d oment Diagram, d d
19 LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 36 Shear and oment Diagrams Loading Shear Diagram, d w d oment Diagram, d d LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 37 Shear and oment Diagrams Eample 0 Draw the shear and bending moment diagrams for the beam shown in Figure a. 40 lb/ft 600 lb ft 0 ft 000 lb in Figure a
20 LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 38 Shear and oment Diagrams Eample 0 (cont d) Support Reactions The reactions at the fied support can be calculated as follows: + Fy 0; R 40( ) R Figure b + 0; + 40() ( 6) + 600( 0) + 5,880 lb in 40 lb/ft 600 lb 080 lb ft 5,880 lb ft R 080 lb 0 ft 000 lb ft LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 39 Shear and oment Diagrams 5,880 lb ft Eample 0 (cont d) Shear Diagram Using the established sign convention, the shear at the ends of the beam is plotted first. For eample, when 0, 080; and when 0, lb 40 lb/ft ( ) for 0 < < ,880 for 0 < <
21 LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 40 Shear and oment Diagrams Eample 0 (cont d) 40 lb/ft 5,880 lb in ft 080 lb ( ) 600 for < < 0 ( )( - 6) for < 0 5, < LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 4 Shear and oment Diagrams Eample 0 (cont d) 40 lb/ft 600 lb Shear Digram ft 0 ft 000 lb in (lb) ( ) for 0 < < (ft)
22 LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 4 Shear and oment Diagrams (ft. lb) Eample 0 (cont d) Bending oment Diagram (ft) 40 lb/ft 600 lb ft 0 ft 000 lb in LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 43 Shear and oment Diagrams Eample 0 (cont d) 40 lb/ft 600 lb 5,880 lb ft ft R 080 lb 0 ft 000 lb ft 080 (lb) (+) 600 (ft lb) (-) -000
23 LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 44 Shear and oment Diagrams Eample Draw complete shear and bending moment diagrams for the beam shown in Fig. y 8000 lb 000 lb/ft B C D Figure a ft 4 ft 8 ft LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 45 Shear and oment Diagrams Eample (cont d) The support reactions were computed from equilibrium as shown in Fig..b. y 8000 lb 000 lb/ft B C D ft 4 ft 8 ft Figure a R,000 lb R C,000 lb
24 LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 46 Shear and oment Diagrams Eample (cont d) 8000 lb 000 lb/ft B C D,000 lb ft 4 ft 8 ft,000 lb,000 8,000 lb (lb) (+) (+) 5.5 ft (-) 3,000 lb 30,50 (ft -lb) (-) (-),000 64,000 LECTURE 3. BES: SHER ND OENT DIGRS (GRPHICL) (5.3) Slide No. 47 Shear and oment Diagrams Eample (cont d),000,000 3, ,000
Shear and Moment Diagrams. Shear and Moment Diagrams. Shear and Moment Diagrams. Shear and Moment Diagrams. Shear and Moment Diagrams
CI 3 Shear Force and Bending oment Diagrams /8 If the variation of and are written as functions of position,, and plotted, the resulting graphs are called the shear diagram and the moment diagram. Developing
More informationProblem 1: Computation of Reactions. Problem 2: Computation of Reactions. Problem 3: Computation of Reactions
Problem 1: Computation of Reactions Problem 2: Computation of Reactions Problem 3: Computation of Reactions Problem 4: Computation of forces and moments Problem 5: Bending Moment and Shear force Problem
More informationHØGSKOLEN I GJØVIK Avdeling for teknologi, økonomi og ledelse. Løsningsforslag for kontinuasjonseksamen i Mekanikk 4/1-10
Løsningsforslag for kontinuasjonseksamen i 4/1-10 Oppgave 1 (T betyr tension, dvs. strekk, og C betyr compression, dvs. trykk.) Side 1 av 9 Leif Erik Storm Oppgave 2 Løsning (fra http://www.public.iastate.edu/~statics/examples/vmdiags/vmdiaga.html
More informationBEAMS: SHEAR FLOW, THIN WALLED MEMBERS
LECTURE BEAMS: SHEAR FLOW, THN WALLED MEMBERS Third Edition A. J. Clark School of Engineering Department of Civil and Environmental Engineering 15 Chapter 6.6 6.7 by Dr. brahim A. Assakkaf SPRNG 200 ENES
More informationMechanics of Materials. Chapter 4 Shear and Moment In Beams
Mechanics of Materials Chapter 4 Shear and Moment In Beams 4.1 Introduction The term beam refers to a slender bar that carries transverse loading; that is, the applied force are perpendicular to the bar.
More informationENGINEERING SCIENCE H1 OUTCOME 1 - TUTORIAL 3 BENDING MOMENTS EDEXCEL HNC/D ENGINEERING SCIENCE LEVEL 4 H1 FORMERLY UNIT 21718P
ENGINEERING SCIENCE H1 OUTCOME 1 - TUTORIAL 3 BENDING MOMENTS EDEXCEL HNC/D ENGINEERING SCIENCE LEVEL 4 H1 FORMERLY UNIT 21718P This material is duplicated in the Mechanical Principles module H2 and those
More informationShear Forces and Bending Moments
Chapter 4 Shear Forces and Bending Moments 4.1 Introduction Consider a beam subjected to transverse loads as shown in figure, the deflections occur in the plane same as the loading plane, is called the
More informationMECHANICS OF SOLIDS - BEAMS TUTORIAL 2 SHEAR FORCE AND BENDING MOMENTS IN BEAMS
MECHANICS OF SOLIDS - BEAMS TUTORIAL 2 SHEAR FORCE AND BENDING MOMENTS IN BEAMS This is the second tutorial on bending of beams. You should judge your progress by completing the self assessment exercises.
More informationMATERIALS AND MECHANICS OF BENDING
HAPTER Reinforced oncrete Design Fifth Edition MATERIALS AND MEHANIS OF BENDING A. J. lark School of Engineering Department of ivil and Environmental Engineering Part I oncrete Design and Analysis b FALL
More informationStructural Axial, Shear and Bending Moments
Structural Axial, Shear and Bending Moments Positive Internal Forces Acting Recall from mechanics of materials that the internal forces P (generic axial), V (shear) and M (moment) represent resultants
More information2. Axial Force, Shear Force, Torque and Bending Moment Diagrams
2. Axial Force, Shear Force, Torque and Bending Moment Diagrams In this section, we learn how to summarize the internal actions (shear force and bending moment) that occur throughout an axial member, shaft,
More informationRecitation #5. Understanding Shear Force and Bending Moment Diagrams
Recitation #5 Understanding Shear Force and Bending Moment Diagrams Shear force and bending moment are examples of interanl forces that are induced in a structure when loads are applied to that structure.
More informationShear Force and Moment Diagrams
C h a p t e r 9 Shear Force and Moment Diagrams In this chapter, you will learn the following to World Class standards: Making a Shear Force Diagram Simple Shear Force Diagram Practice Problems More Complex
More informationChapter 8. Shear Force and Bending Moment Diagrams for Uniformly Distributed Loads.
hapter 8 Shear Force and ending Moment Diagrams for Uniformly Distributed Loads. 8.1 Introduction In Unit 4 we saw how to calculate moments for uniformly distributed loads. You might find it worthwhile
More informationSTRESS AND DEFORMATION ANALYSIS OF LINEAR ELASTIC BARS IN TENSION
Chapter 11 STRESS AND DEFORMATION ANALYSIS OF LINEAR ELASTIC BARS IN TENSION Figure 11.1: In Chapter10, the equilibrium, kinematic and constitutive equations for a general three-dimensional solid deformable
More informationIntroduction to Mechanical Behavior of Biological Materials
Introduction to Mechanical Behavior of Biological Materials Ozkaya and Nordin Chapter 7, pages 127-151 Chapter 8, pages 173-194 Outline Modes of loading Internal forces and moments Stiffness of a structure
More information8.2 Elastic Strain Energy
Section 8. 8. Elastic Strain Energy The strain energy stored in an elastic material upon deformation is calculated below for a number of different geometries and loading conditions. These expressions for
More informationINTRODUCTION TO BEAMS
CHAPTER Structural Steel Design LRFD Method INTRODUCTION TO BEAMS Third Edition A. J. Clark School of Engineering Department of Civil and Environmental Engineering Part II Structural Steel Design and Analysis
More informationEQUILIBRIUM STRESS SYSTEMS
EQUILIBRIUM STRESS SYSTEMS Definition of stress The general definition of stress is: Stress = Force Area where the area is the cross-sectional area on which the force is acting. Consider the rectangular
More informationMECHANICS OF SOLIDS - BEAMS TUTORIAL 1 STRESSES IN BEAMS DUE TO BENDING. On completion of this tutorial you should be able to do the following.
MECHANICS OF SOLIDS - BEAMS TUTOIAL 1 STESSES IN BEAMS DUE TO BENDING This is the first tutorial on bending of beams designed for anyone wishing to study it at a fairly advanced level. You should judge
More informationBending Stress in Beams
936-73-600 Bending Stress in Beams Derive a relationship for bending stress in a beam: Basic Assumptions:. Deflections are very small with respect to the depth of the beam. Plane sections before bending
More informationType of Force 1 Axial (tension / compression) Shear. 3 Bending 4 Torsion 5 Images 6 Symbol (+ -)
Cause: external force P Force vs. Stress Effect: internal stress f 05 Force vs. Stress Copyright G G Schierle, 2001-05 press Esc to end, for next, for previous slide 1 Type of Force 1 Axial (tension /
More informationQualitative Influence Lines. Qualitative Influence Lines. Qualitative Influence Lines. Qualitative Influence Lines. Qualitative Influence Lines
IL 32 Influence Lines - Muller-reslau Principle /5 In 886, Heinrich Müller-reslau develop a method for rapidly constructing the shape of an influence line. Heinrich Franz ernhard Müller was born in Wroclaw
More informationStresses in Beam (Basic Topics)
Chapter 5 Stresses in Beam (Basic Topics) 5.1 Introduction Beam : loads acting transversely to the longitudinal axis the loads create shear forces and bending moments, stresses and strains due to V and
More informationSOLUTION 6 6. Determine the force in each member of the truss, and state if the members are in tension or compression.
6 6. etermine the force in each member of the truss, and state if the members are in tension or compression. 600 N 4 m Method of Joints: We will begin by analyzing the equilibrium of joint, and then proceed
More informationNACA Nomenclature NACA 2421. NACA Airfoils. Definitions: Airfoil Geometry
0.40 m 0.21 m 0.02 m NACA Airfoils 6-Feb-08 AE 315 Lesson 10: Airfoil nomenclature and properties 1 Definitions: Airfoil Geometry z Mean camber line Chord line x Chord x=0 x=c Leading edge Trailing edge
More informationSPECIFICATIONS, LOADS, AND METHODS OF DESIGN
CHAPTER Structural Steel Design LRFD Method Third Edition SPECIFICATIONS, LOADS, AND METHODS OF DESIGN A. J. Clark School of Engineering Department of Civil and Environmental Engineering Part II Structural
More informationCE 201 (STATICS) DR. SHAMSHAD AHMAD CIVIL ENGINEERING ENGINEERING MECHANICS-STATICS
COURSE: CE 201 (STATICS) LECTURE NO.: 28 to 30 FACULTY: DR. SHAMSHAD AHMAD DEPARTMENT: CIVIL ENGINEERING UNIVERSITY: KING FAHD UNIVERSITY OF PETROLEUM & MINERALS, DHAHRAN, SAUDI ARABIA TEXT BOOK: ENGINEERING
More informationIntroduction to Plates
Chapter Introduction to Plates Plate is a flat surface having considerabl large dimensions as compared to its thickness. Common eamples of plates in civil engineering are. Slab in a building.. Base slab
More informationCOMPLEX STRESS TUTORIAL 3 COMPLEX STRESS AND STRAIN
COMPLX STRSS TUTORIAL COMPLX STRSS AND STRAIN This tutorial is not part of the decel unit mechanical Principles but covers elements of the following sllabi. o Parts of the ngineering Council eam subject
More informationPRESTRESSED CONCRETE. Introduction REINFORCED CONCRETE CHAPTER SPRING 2004. Reinforced Concrete Design. Fifth Edition. By Dr. Ibrahim.
CHAPTER REINFORCED CONCRETE Reinforced Concrete Design A Fundamental Approach - Fifth Edition Fifth Edition PRESTRESSED CONCRETE A. J. Clark School of Engineering Department of Civil and Environmental
More informationModule 2. Analysis of Statically Indeterminate Structures by the Matrix Force Method. Version 2 CE IIT, Kharagpur
Module Analysis of Statically Indeterminate Structures by the Matrix Force Method esson 11 The Force Method of Analysis: Frames Instructional Objectives After reading this chapter the student will be able
More informationChapter 5A. Torque. A PowerPoint Presentation by Paul E. Tippens, Professor of Physics Southern Polytechnic State University
Chapter 5A. Torque A PowerPoint Presentation by Paul E. Tippens, Professor of Physics Southern Polytechnic State University 2007 Torque is a twist or turn that tends to produce rotation. * * * Applications
More informationAwell-known lecture demonstration1
Acceleration of a Pulled Spool Carl E. Mungan, Physics Department, U.S. Naval Academy, Annapolis, MD 40-506; mungan@usna.edu Awell-known lecture demonstration consists of pulling a spool by the free end
More informationAnalysis of Stresses and Strains
Chapter 7 Analysis of Stresses and Strains 7.1 Introduction axial load = P / A torsional load in circular shaft = T / I p bending moment and shear force in beam = M y / I = V Q / I b in this chapter, we
More informationMohr s Circle. Academic Resource Center
Mohr s Circle Academic Resource Center Introduction The transformation equations for plane stress can be represented in graphical form by a plot known as Mohr s Circle. This graphical representation is
More informationDeflections. Question: What are Structural Deflections?
Question: What are Structural Deflections? Answer: The deformations or movements of a structure and its components, such as beams and trusses, from their original positions. It is as important for the
More informationShear Center in Thin-Walled Beams Lab
Shear Center in Thin-Walled Beams Lab Shear flow is developed in beams with thin-walled cross sections shear flow (q sx ): shear force per unit length along cross section q sx =τ sx t behaves much like
More informationWhy should we learn this? One real-world connection is to find the rate of change in an airplane s altitude. The Slope of a Line VOCABULARY
Wh should we learn this? The Slope of a Line Objectives: To find slope of a line given two points, and to graph a line using the slope and the -intercept. One real-world connection is to find the rate
More informationMechanics of Materials. Chapter 5 Stresses In Beams
Mechanics of Materials Chapter 5 Stresses In Beams 5.1 Introduction In previous chapters, the stresses in bars caused by axial loading and torsion. Here consider the third fundamental loading : bending.
More informationF. P. Beer et al., Meccanica dei solidi, Elementi di scienza delle costruzioni, 5e - isbn 9788838668579, 2014 McGraw-Hill Education (Italy) srl
F. P. Beer et al., eccanica dei solidi, Elementi di scienza delle costruzioni, 5e - isbn 9788888579, 04 cgraw-hill Education (Italy) srl Reactions: Σ = 0: bp = 0 = Pb Σ = 0: ap = 0 = Pa From to B: 0
More informationNew approaches in Eurocode 3 efficient global structural design
New approaches in Eurocode 3 efficient global structural design Part 1: 3D model based analysis using general beam-column FEM Ferenc Papp* and József Szalai ** * Associate Professor, Department of Structural
More informationApproximate Analysis of Statically Indeterminate Structures
Approximate Analysis of Statically Indeterminate Structures Every successful structure must be capable of reaching stable equilibrium under its applied loads, regardless of structural behavior. Exact analysis
More informationMECHANICS OF SOLIDS - BEAMS TUTORIAL TUTORIAL 4 - COMPLEMENTARY SHEAR STRESS
MECHANICS OF SOLIDS - BEAMS TUTORIAL TUTORIAL 4 - COMPLEMENTARY SHEAR STRESS This the fourth and final tutorial on bending of beams. You should judge our progress b completing the self assessment exercises.
More informationPhysics 9e/Cutnell. correlated to the. College Board AP Physics 1 Course Objectives
Physics 9e/Cutnell correlated to the College Board AP Physics 1 Course Objectives Big Idea 1: Objects and systems have properties such as mass and charge. Systems may have internal structure. Enduring
More informationREINFORCED CONCRETE. Reinforced Concrete Design. A Fundamental Approach - Fifth Edition. Walls are generally used to provide lateral support for:
HANDOUT REINFORCED CONCRETE Reinforced Concrete Design A Fundamental Approach - Fifth Edition RETAINING WALLS Fifth Edition A. J. Clark School of Engineering Department of Civil and Environmental Engineering
More informationDESIGN OF SLABS. 3) Based on support or boundary condition: Simply supported, Cantilever slab,
DESIGN OF SLABS Dr. G. P. Chandradhara Professor of Civil Engineering S. J. College of Engineering Mysore 1. GENERAL A slab is a flat two dimensional planar structural element having thickness small compared
More informationSection 16: Neutral Axis and Parallel Axis Theorem 16-1
Section 16: Neutral Axis and Parallel Axis Theorem 16-1 Geometry of deformation We will consider the deformation of an ideal, isotropic prismatic beam the cross section is symmetric about y-axis All parts
More informationWhen the fluid velocity is zero, called the hydrostatic condition, the pressure variation is due only to the weight of the fluid.
Fluid Statics When the fluid velocity is zero, called the hydrostatic condition, the pressure variation is due only to the weight of the fluid. Consider a small wedge of fluid at rest of size Δx, Δz, Δs
More informationENGINEERING MECHANICS STATIC
EX 16 Using the method of joints, determine the force in each member of the truss shown. State whether each member in tension or in compression. Sol Free-body diagram of the pin at B X = 0 500- BC sin
More informationFORCE ON A CURRENT IN A MAGNETIC FIELD
7/16 Force current 1/8 FORCE ON A CURRENT IN A MAGNETIC FIELD PURPOSE: To study the force exerted on an electric current by a magnetic field. BACKGROUND: When an electric charge moves with a velocity v
More informationStatics of Structural Supports
Statics of Structural Supports TYPES OF FORCES External Forces actions of other bodies on the structure under consideration. Internal Forces forces and couples exerted on a member or portion of the structure
More informationCOMPONENTS OF VECTORS
COMPONENTS OF VECTORS To describe motion in two dimensions we need a coordinate sstem with two perpendicular aes, and. In such a coordinate sstem, an vector A can be uniquel decomposed into a sum of two
More information16. Beam-and-Slab Design
ENDP311 Structural Concrete Design 16. Beam-and-Slab Design Beam-and-Slab System How does the slab work? L- beams and T- beams Holding beam and slab together University of Western Australia School of Civil
More informationSolid Mechanics. Stress. What you ll learn: Motivation
Solid Mechanics Stress What you ll learn: What is stress? Why stress is important? What are normal and shear stresses? What is strain? Hooke s law (relationship between stress and strain) Stress strain
More informationSECTION 3 DESIGN OF POST TENSIONED COMPONENTS FOR FLEXURE
SECTION 3 DESIGN OF POST TENSIONED COMPONENTS FOR FLEXURE DEVELOPED BY THE PTI EDC-130 EDUCATION COMMITTEE LEAD AUTHOR: TREY HAMILTON, UNIVERSITY OF FLORIDA NOTE: MOMENT DIAGRAM CONVENTION In PT design,
More informationCHAP 4 FINITE ELEMENT ANALYSIS OF BEAMS AND FRAMES INTRODUCTION
CHAP FINITE EEMENT ANAYSIS OF BEAMS AND FRAMES INTRODUCTION We learned Direct Stiffness Method in Chapter imited to simple elements such as D bars we will learn Energ Method to build beam finite element
More informationTHE PARABOLA 13.2. section
698 (3 0) Chapter 3 Nonlinear Sstems and the Conic Sections 49. Fencing a rectangle. If 34 ft of fencing are used to enclose a rectangular area of 72 ft 2, then what are the dimensions of the area? 50.
More informationAP Physics - Chapter 8 Practice Test
AP Physics - Chapter 8 Practice Test Multiple Choice Identify the choice that best completes the statement or answers the question. 1. A single conservative force F x = (6.0x 12) N (x is in m) acts on
More informationLaterally Loaded Piles
Laterally Loaded Piles 1 Soil Response Modelled by p-y Curves In order to properly analyze a laterally loaded pile foundation in soil/rock, a nonlinear relationship needs to be applied that provides soil
More informationLab for Deflection and Moment of Inertia
Deflection and Moment of Inertia Subject Area(s) Associated Unit Lesson Title Physics Wind Effects on Model Building Lab for Deflection and Moment of Inertia Grade Level (11-12) Part # 2 of 3 Lesson #
More informationEFFECTS ON NUMBER OF CABLES FOR MODAL ANALYSIS OF CABLE-STAYED BRIDGES
EFFECTS ON NUMBER OF CABLES FOR MODAL ANALYSIS OF CABLE-STAYED BRIDGES Yang-Cheng Wang Associate Professor & Chairman Department of Civil Engineering Chinese Military Academy Feng-Shan 83000,Taiwan Republic
More informationDesigning a Structural Steel Beam. Kristen M. Lechner
Designing a Structural Steel Beam Kristen M. Lechner November 3, 2009 1 Introduction Have you ever looked at a building under construction and wondered how the structure was designed? What assumptions
More informationThe following sketches show the plans of the two cases of one-way slabs. The spanning direction in each case is shown by the double headed arrow.
9.2 One-way Slabs This section covers the following topics. Introduction Analysis and Design 9.2.1 Introduction Slabs are an important structural component where prestressing is applied. With increase
More information4.2 Free Body Diagrams
CE297-FA09-Ch4 Page 1 Friday, September 18, 2009 12:11 AM Chapter 4: Equilibrium of Rigid Bodies A (rigid) body is said to in equilibrium if the vector sum of ALL forces and all their moments taken about
More informationMECHANICS OF MATERIALS
T dition CHTR MCHNICS OF MTRIS Ferdinand. Beer. Russell Johnston, Jr. John T. DeWolf ecture Notes: J. Walt Oler Texas Tech University Stress and Strain xial oading - Contents Stress & Strain: xial oading
More informationSECTION 3 DESIGN OF POST- TENSIONED COMPONENTS FOR FLEXURE
SECTION 3 DESIGN OF POST- TENSIONED COMPONENTS FOR FLEXURE DEVELOPED BY THE PTI EDC-130 EDUCATION COMMITTEE LEAD AUTHOR: TREY HAMILTON, UNIVERSITY OF FLORIDA NOTE: MOMENT DIAGRAM CONVENTION In PT design,
More informationABSTRACT 1. INTRODUCTION 2. DESCRIPTION OF THE SEGMENTAL BEAM
Ninth LACCEI Latin American and Caribbean Conference (LACCEI 11), Engineering for a Smart Planet, Innovation, Information Technology and Computational Tools for Sustainable Development, August 3-, 11,
More informationEDEXCEL NATIONAL CERTIFICATE/DIPLOMA MECHANICAL PRINCIPLES AND APPLICATIONS NQF LEVEL 3 OUTCOME 1 - LOADING SYSTEMS
EDEXCEL NATIONAL CERTIFICATE/DIPLOMA MECHANICAL PRINCIPLES AND APPLICATIONS NQF LEVEL 3 OUTCOME 1 - LOADING SYSTEMS TUTORIAL 1 NON-CONCURRENT COPLANAR FORCE SYSTEMS 1. Be able to determine the effects
More informationINTRODUCTION TO BEAMS
CHAPTER Structural Steel Design LRFD etho INTRODUCTION TO BEAS Thir Eition A. J. Clark School of Engineering Department of Civil an Environmental Engineering Part II Structural Steel Design an Analsis
More informationTo Be or Not To Be a Linear Equation: That Is the Question
To Be or Not To Be a Linear Equation: That Is the Question Linear Equation in Two Variables A linear equation in two variables is an equation that can be written in the form A + B C where A and B are not
More informationChapter 1: Statics. A) Newtonian Mechanics B) Relativistic Mechanics
Chapter 1: Statics 1. The subject of mechanics deals with what happens to a body when is / are applied to it. A) magnetic field B) heat C ) forces D) neutrons E) lasers 2. still remains the basis of most
More informationLecture 9: Lines. m = y 2 y 1 x 2 x 1
Lecture 9: Lines If we have two distinct points in the Cartesian plane, there is a unique line which passes through the two points. We can construct it by joining the points with a straight edge and extending
More informationChapter 5: Indeterminate Structures Slope-Deflection Method
Chapter 5: Indeterminate Structures Slope-Deflection Method 1. Introduction Slope-deflection method is the second of the two classical methods presented in this course. This method considers the deflection
More informationObjectives. Experimentally determine the yield strength, tensile strength, and modules of elasticity and ductility of given materials.
Lab 3 Tension Test Objectives Concepts Background Experimental Procedure Report Requirements Discussion Objectives Experimentally determine the yield strength, tensile strength, and modules of elasticity
More informationNPTEL STRUCTURAL RELIABILITY
NPTEL Course On STRUCTURAL RELIABILITY Module # 0 Lecture Course Format: eb Instructor: Dr. Arunasis Chakraborty Department of Civil Engineering Indian Institute of Technology Guwahati . Lecture 0: System
More information10.1. Solving Quadratic Equations. Investigation: Rocket Science CONDENSED
CONDENSED L E S S O N 10.1 Solving Quadratic Equations In this lesson you will look at quadratic functions that model projectile motion use tables and graphs to approimate solutions to quadratic equations
More informationStatics problem solving strategies, hints and tricks
Statics problem solving strategies, hints and tricks Contents 1 Solving a problem in 7 steps 3 1.1 To read.............................................. 3 1.2 To draw..............................................
More informationVELOCITY, ACCELERATION, FORCE
VELOCITY, ACCELERATION, FORCE velocity Velocity v is a vector, with units of meters per second ( m s ). Velocity indicates the rate of change of the object s position ( r ); i.e., velocity tells you how
More informationThe elements used in commercial codes can be classified in two basic categories:
CHAPTER 3 Truss Element 3.1 Introduction The single most important concept in understanding FEA, is the basic understanding of various finite elements that we employ in an analysis. Elements are used for
More informationLecture 8 Bending & Shear Stresses on Beams
Lecture 8 Bending & hear tresses on Beams Beams are almost always designed on the asis of ending stress and, to a lesser degree, shear stress. Each of these stresses will e discussed in detail as follows.
More informationTorque and Rotary Motion
Torque and Rotary Motion Name Partner Introduction Motion in a circle is a straight-forward extension of linear motion. According to the textbook, all you have to do is replace displacement, velocity,
More informationAPE T CFRP Aslan 500
Carbon Fiber Reinforced Polymer (CFRP) Tape is used for structural strengthening of concrete, masonry or timber elements using the technique known as Near Surface Mount or NSM strengthening. Use of CFRP
More informationFLUID FORCES ON CURVED SURFACES; BUOYANCY
FLUID FORCES ON CURVED SURFCES; BUOYNCY The principles applicable to analysis of pressure-induced forces on planar surfaces are directly applicable to curved surfaces. s before, the total force on the
More informationLINEAR FUNCTIONS OF 2 VARIABLES
CHAPTER 4: LINEAR FUNCTIONS OF 2 VARIABLES 4.1 RATES OF CHANGES IN DIFFERENT DIRECTIONS From Precalculus, we know that is a linear function if the rate of change of the function is constant. I.e., for
More informationCIVL 7/8117 Chapter 3a - Development of Truss Equations 1/80
CIV 7/87 Chapter 3a - Development of Truss Equations /8 Development of Truss Equations Having set forth the foundation on which the direct stiffness method is based, we will now derive the stiffness matri
More informationo Graph an expression as a function of the chosen independent variable to determine the existence of a minimum or maximum
Two Parabolas Time required 90 minutes Teaching Goals:. Students interpret the given word problem and complete geometric constructions according to the condition of the problem.. Students choose an independent
More informationax 2 by 2 cxy dx ey f 0 The Distance Formula The distance d between two points (x 1, y 1 ) and (x 2, y 2 ) is given by d (x 2 x 1 )
SECTION 1. The Circle 1. OBJECTIVES The second conic section we look at is the circle. The circle can be described b using the standard form for a conic section, 1. Identif the graph of an equation as
More informationThe Basics of FEA Procedure
CHAPTER 2 The Basics of FEA Procedure 2.1 Introduction This chapter discusses the spring element, especially for the purpose of introducing various concepts involved in use of the FEA technique. A spring
More informationChapter 18 Static Equilibrium
Chapter 8 Static Equilibrium 8. Introduction Static Equilibrium... 8. Lever Law... Example 8. Lever Law... 4 8.3 Generalized Lever Law... 5 8.4 Worked Examples... 7 Example 8. Suspended Rod... 7 Example
More informationCHAPTER 3 SHEARING FORCE AND BENDING MOMENT DIAGRAMS. Summary
CHAPTER 3 SHEARING FORCE AND BENDING MOMENT DIAGRAMS Summary At any section in a beam carrying transverse loads the shearing force is defined as the algebraic sum of the forces taken on either side of
More informationwww.mathsbox.org.uk Displacement (x) Velocity (v) Acceleration (a) x = f(t) differentiate v = dx Acceleration Velocity (v) Displacement x
Mechanics 2 : Revision Notes 1. Kinematics and variable acceleration Displacement (x) Velocity (v) Acceleration (a) x = f(t) differentiate v = dx differentiate a = dv = d2 x dt dt dt 2 Acceleration Velocity
More informationThe Distance Formula and the Circle
10.2 The Distance Formula and the Circle 10.2 OBJECTIVES 1. Given a center and radius, find the equation of a circle 2. Given an equation for a circle, find the center and radius 3. Given an equation,
More informationChapter 4. Forces and Newton s Laws of Motion. continued
Chapter 4 Forces and Newton s Laws of Motion continued 4.9 Static and Kinetic Frictional Forces When an object is in contact with a surface forces can act on the objects. The component of this force acting
More informationModule 7 (Lecture 24 to 28) RETAINING WALLS
Module 7 (Lecture 24 to 28) RETAINING WALLS Topics 24.1 INTRODUCTION 24.2 GRAVITY AND CANTILEVER WALLS 24.3 PROPORTIONING RETAINING WALLS 24.4 APPLICATION OF LATERAL EARTH PRESSURE THEORIES TO DESIGN 24.5
More informationChapter 11 Equilibrium
11.1 The First Condition of Equilibrium The first condition of equilibrium deals with the forces that cause possible translations of a body. The simplest way to define the translational equilibrium of
More informationPHYS 211 FINAL FALL 2004 Form A
1. Two boys with masses of 40 kg and 60 kg are holding onto either end of a 10 m long massless pole which is initially at rest and floating in still water. They pull themselves along the pole toward each
More informationRigid and Braced Frames
Rigid Frames Rigid and raced Frames Rigid frames are identified b the lack of pinned joints within the frame. The joints are rigid and resist rotation. The ma be supported b pins or fied supports. The
More informationDesign Project 2. Sizing of a Bicycle Chain Ring Bolt Set. Statics and Mechanics of Materials I. ENGR 0135 Section 1040.
Design Project 2 Sizing of a Bicycle Chain Ring Bolt Set Statics and Mechanics of Materials I ENGR 0135 Section 1040 November 9, 2014 Derek Nichols Michael Scandrol Mark Vavithes Nichols, Scandrol, Vavithes
More informationBeam Deflections: 4th Order Method and Additional Topics
11 eam Deflections: 4th Order Method and dditional Topics 11 1 ecture 11: EM DEFECTIONS: 4TH ORDER METHOD ND DDITION TOICS TE OF CONTENTS age 11.1. Fourth Order Method Description 11 3 11.1.1. Example
More information