Draw a ring around the correct answer to complete the following sentences. air resistance. friction. gravity. air resistance. gravity. weight.

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1 Q. The diagram shows the forces acting on a skydiver. Draw a ring around the correct answer to complete the following sentences. air resistance. (a) Force J is caused by friction. gravity. () Force K is caused by air resistance. gravity. weight. () (c) When the skydiver jumps from the aircraft, force J is bigger than the same as smaller than accelerates downwards. force K and the skydiver accelerates upwards. falls at a steady speed. (2) (Total 4 marks) Page of 3

2 Q2. (a) The diagram shows the horizontal forces acting on a car travelling along a straight road. (i) Calculate the size of the resultant force acting on the car. Show clearly how you work out your answer. Resultant force =... N (2) (ii) Describe the motion of the car when the forces shown in the diagram act on it. (2) A car driver makes an emergency stop. The chart shows the thinking distance and the braking distance needed to stop the car. (i) Calculate the total stopping distance of the car. Stopping distance =... m () Page 2 of 3

3 (ii) The graph shows that speed affects thinking distance. Use the graph to find the thinking distance for a car driven at 30 m/s. Thinking distance =... m () (iii) Give one further factor that will affect the thinking distance. () (Total 7 marks) Q3. The diagram shows the horizontal forces acting on a car of mass 200 kg. Page 3 of 3

4 (a) Calculate the acceleration of the car at the instant shown in the diagram. Write down the equation you use, and then show clearly how you work out your answer and give the unit. Acceleration =... (4) Explain why the car reaches a top speed even though the thrust force remains constant at 3500 N. (3) Page 4 of 3

5 (c) The diagram shows a car and a van. The two vehicles have the same mass and identical engines. Explain why the top speed of the car is higher than the top speed of the van. (4) (Total marks) Q4. The diagram shows the passenger train on part of a rollercoaster ride. (a) Which arrow shows the direction of the resultant force acting on the passenger train? Put a tick ( ) in the box next to your choice. () Page 5 of 3

6 At the bottom of the slope, the passengers in the train all have the same speed but they each have a different kinetic energy. Why is the kinetic energy of each passenger different? () (c) For part of the ride, the maximum gravitational field strength acting on the passengers seems 3 times bigger than normal. Normal gravitational field strength = 0 N/kg (i) Calculate the maximum gravitational field strength that seems to act on the passengers during the ride Maximum gravitational field strength =... N/kg () (ii) One of the passengers has a mass of 80 kg. Use the equation in the box to calculate the maximum weight this passenger seems to have during the ride. weight = mass gravitational field strength Show clearly how you work out your answer Maximum weight =... N (2) (Total 5 marks) Page 6 of 3

7 Q5. (a) The diagram shows a steel ball-bearing falling through a tube of oil. The forces, L and M, act on the ball-bearing. What causes force L?... () The distance time graph represents the motion of the ball-bearing as it falls through the oil. Page 7 of 3

8 (i) Explain, in terms of the forces, L and M, why the ball-bearing accelerates at first but then falls at constant speed (3) (ii) What name is given to the constant speed reached by the falling ball-bearing?... () (iii) Calculate the constant speed reached by the ball-bearing. Show clearly how you use the graph to work out your answer Speed =... m/s (2) (Total 7 marks) Page 8 of 3

9 M. (a) gravity (c) air resistance bigger than accelerates downwards correct order only [4] M2. (a) (i) 500 allow mark for subtraction shown ie (ii) it accelerates in a forward direction accept gains speed/velocity (i) 23 (m) (ii) 20 (m) only this answer (iii) any one from: drinking alcohol taking drugs tired accept (a specific) distraction accept any factor that affects the drivers reactions [7] Page 9 of 3

10 M3. (a).25 allow mark for correct resultant force ie 500N allow 2 marks for correct transformation and substitution ie allow mark for a correct transformation but clearly substituting an incorrect value for force eg = 3 m/s 2 (c) as speed increases so does the size of the drag force accept frictional force / resistive force / air resistance for drag eventually the drag force becomes equal to the thrust the resultant force is now equal to zero and therefore there is no further acceleration the car and van will reach top speed when the forward force equals the drag force accept air resistance / frictional / resistive force for drag force the drag force at any speed is smaller for the car than for the van as the car is more streamlined therefore the car s drag force will equal the forward force at a higher speed allow converse throughout [] Page 0 of 3

11 M4. (a) correct box ticked each passenger has a different mass accept weight for mass ignore other irrelevant factors about the person e.g. mass and height do not accept a list with incorrect factors e.g. mass and position accept passengers started with different (gravitational) potential energy (c) (i) 30 ignore added units (ii) 2400 accept their (c)(i) 80 correctly calculated for both marks allow mark for correct substitution of their (c)(i) and 80 an answer of 800 gains mark only if answer to (c)(i) is not 0 2 [5] M5. (a) gravity accept weight do not accept mass accept gravitational pull Page of 3

12 (i) Initially force L greater than force M accept there is a resultant force downwards (as speed increases) force M increases accept the resultant force decreases when M = L, (speed is constant) accept resultant force is 0 accept gravity/weighty for L accept drag/ upthrust/resistance/friction for M do not accept air resistance for M but penalise only once (ii) terminal velocity (iii) 0.5 accept an answer between an answer of 0. gains no credit allow mark for showing correct use of the graph 2 [7] Page 2 of 3

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