Unit 10. Turing machine Decidability Decision problems in FA
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1 Unit 10 Turing machine Decidability Decision problems in FA 1
2 Turing Machines Proposed by Alan Turing, Unlimited and unrestricted memory. A model of a general purpose computer. Can do anything that a real computer can do. Cannot solve all problems!! 2
3 The Turing Machine An infinite tape - unlimited memory. A tape head - can move left and right. Can read from the tape and write on the tape. head b b a c b b d a c 3
4 Input/Output Initial Configuration Input q 0 * w w1w 2... wn... * 0 1 w0 w_ 1w_ 2... w_ n Final Configuration Output q accept _... 4
5 Initial Configuration Input: Appears on the leftmost n slots of the tape. The rest of the tape is blank ( _ ). Head starts on the left-most square. Initial state: q 0 head q 0... * b b wa _ w1w_ 2... w_ n 5
6 Final Configuration During the computation the head can read and write to the tape and move right or left until it reach reject or accept states. Final state: q {q accept, q reject } The tape contains uw. The string u appears to the left of the head. The string w appears under the head and its right. The rest of the tape is blank. The output is the string u. q accept * 0 0 w1 0w 1w w_ n u w 6
7 Possible Outcomes of a TM The possible outcomes of a TM on a word w can be: stop with reject state. stop with accept state. loop forever. 7
8 Differences Between Finite Automata and TM A TM can both read and write. The head can move left and right. The tape is infinite. The special cases of reject and accept take an immediate action. A TM can produce an output. 8
9 TM: Definition Formally: A TM is defined by (Q,,,, q 0, q accept, q reject ) Q is the set of states. is the input alphabet _. is the tape alphabet, _ and. : Qx Qx x{r,l} the transition function. q 0, q accept, q reject the start, accept and reject states. q accept q reject 9
10 The Transition Function The transition function : Qx Qx x{r,l} The transition (p,a) (q,b,r) is depicted as: p a b,r q p a,c b,r a b,r c b,r q 10
11 Example: L={w#w w {0,1} * } # _ x # _ x # x _... accept x x x x # x x x x _ 11
12 Example: L={w#w w {0,1} * } Process: 1. Scan and check that the input contains a single #. If not reject. 2. Zig-zag to check whether corresponding positions on either sides of # contain the same symbol. If not, reject. Cross off the checked symbols. 3. When all symbols to the left of # are crossed, check for remaining symbols to the right of #. If any symbol, reject. Otherwise, accept. 12
13 TM s state diagram recognizing: B={w#w w {0,1} * } 13
14 The Turing-Church Conjecture 1936 If an algorithm exists for solving a problem then there is an equivalent Turing machine solving that algorithm. This gives a formal model for the intuitive notion of algorithms. This means that a Turing machine can do what any computer can do, and there isn t a more powerful computational model than TM. 14
15 Decision Problems Problems for which the answer is yes/no. Any problem can be reduced to a decision problem. 15
16 Arithmetic as a decision problem A membership problem determines whether a word w is in a language L. Any problem can be reduced to the membership problem of a word in a language. Example: An arithmetical problem of finding the answer to: 3*7=? This problem can be formulated as a question: which of the following words belong to the language of correct arithmetic statements: 3*7=0, 3*7=1,, 3*7=21, 3*7=22, 16
17 Informally: Decidability Decidability of problem X whether the problem has an algorithm which solves it (decides it), i.e. whether there is an TM which: 1. always halts 2. with the correct answer A decidable problem has such an algorithm/tm/grammar. An undecidable problem does not have such an algorithm/tm/grammar. 17
18 DFA Membership Input: DFA A and a string w Output: yes if w L(A); no otherwise. Theorem: DFA membership is decidable. 18
19 Proof of decidability The algorithm to decide the problem is: Simulate A with a TM: start A on w from q 0 if (q 0,w) F return yes otherwise return no The algorithm will always halt after w steps. 19
20 NFA Membership Input: NFA B and a string w Output: yes if w L(B); no otherwise. Theorem: NFA membership is decidable. 20
21 Proof of decidability The algorithm to decide the problem is: Convert NFA B to an equivalent DFA C Apply DFA membership TM to C and w If TM accepts w, accept, otherwise reject. The algorithm will always halt after w steps. 21
22 CFG Membership Input: CFG G and a string w Output: yes if w L(G); no otherwise. Theorem: CFG membership is decidable. 22
23 Proof of decidability Option 1: List all derivations ={u S * u} Check whether w. Will it work? Option2: Convert G into equivalent Chomsky NF. List all derivations ={u S * u} with 2 w -1 steps Check whether w 23
24 TM Membership Input: TM M and a string w Output: yes if M accepts w; no otherwise. Theorem: TM membership is undecidable. 24
25 Proof of un-decidability In next course! 25
26 Classes of Languages Turing -recognizable decidable context-free regular 26
27 Recap 27
28 Recap Regular Languages: Finite Automata (Q,,,q 0,F) Regular languages Closures of RL (union, intersection, complements, minus) Non deterministic automaton: : Qx 2 Q Equivalence DFA NFA Closures of RL (concatenation, Kleene star). 28
29 Recap Regular Expressions Equivalence DFA RE Minimal DFA and equivalent DFAs Non regular languages: The Pumping Lemma 29
30 Recap Context-Free Languages: Context-Free Grammar G=(V,, S, R) Regular grammar (A w, A wb) Equivalence NFA regular-grammar Closure of CFL (Union, Concatenation, Kleene star) Chomsky Normal Form (A BC, A ) Chomsky Hierarchy of grammars 30
31 Recap Pushdown automata (Q,,,, q 0, F) Equivalence PDA CFG Non context-free languages: The pumping lemma Turing Machines Decidability 31
32 Aims Practical techniques and tools - useful in compilation, translation, data compression etc. Formalization of the concept of language - useful in formal linguistics etc. Computational models - useful in answering basic questions about computations. Understanding of the computer abilities and its limits In a problem Solvable? At what resources? 32
33 THE END 33
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