AP CHEMISTRY 2008 SCORING GUIDELINES (Form B)
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1 AP CHEMISTRY 2008 SCORING GUIDELINES (Form B) Question 1 Answer the following questions regarding the decomposition of arsenic pentafluoride, AsF 5 (g). (a) A 55.8 g sample of AsF 5 (g) is introduced into an evacuated 10.5 L container at 105 C. (i) What is the initial molar concentration of AsF 5 (g) in the container? mol AsF 5 = 55.8 g AsF 5 [AsF 5 ] i = mol AsF L 1 mol AsF g AsF = M 5 = mol One point is earned for the correct molar mass. One point is earned for the correct concentration. (ii) What is the initial pressure, in atmospheres, of the AsF 5 (g) in the container? PV = nrt P = mol L atm mol K 378 K 10.5 L = atm One point is earned for the correct substitution. One point is earned for the correct pressure. At 105 C, AsF 5 (g) decomposes into AsF 3 (g) and F 2 (g) according to the following chemical equation. AsF 5 (g) AsF 3 (g) + F 2 (g) (b) In terms of molar concentrations, write the equilibrium-constant expression for the decomposition of AsF 5 (g). K = [AsF 3] [F 2] [AsF ] 5 One point is earned for the correct equation. (c) When equilibrium is established, 27.7 percent of the original number of moles of AsF 5 (g) has decomposed. (i) Calculate the molar concentration of AsF 5 (g) at equilibrium % 27.7% = 72.3% [AsF 5 ] = M = M One point is earned for the correct concentration The College Board. All rights reserved.
2 AP CHEMISTRY 2008 SCORING GUIDELINES (Form B) Question 1 (continued) (ii) Using molar concentrations, calculate the value of the equilibrium constant, K eq, at 105 C. [AsF 3 ] = [F 2 ] = [AsF 5 ] i = M = M One point is earned for setting [AsF 3 ] = [F 2 ]. Note: the point is not earned if the student indicates that [AsF 3 ] = [F 2 ] = [AsF 5 ]. K eq = [AsF 3] [F 2] [AsF ] 5 = [ ] [ ] [0.0226] = One point is earned for the correct calculation of [AsF 3 ] and [F 2 ]. One point is earned for the correct calculation of K eq. (d) Calculate the mole fraction of F 2 (g) in the container at equilibrium. mol AsF 5 = M 10.5 L = mol mol F 2 = mol AsF 3 = M 10.5 L = mol mol fraction F 2 = = OR mol fraction F 2 = mol F mol F + mol AsF + mol AsF = = One point is earned for the correct calculation of the mole fraction of F 2 (g) The College Board. All rights reserved.
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10 AP CHEMISTRY 2008 SCORING COMMENTARY (Form B) Question 1 Sample: 1A Score: 10 This response earned all 10 points: 2 for part (a)(i), 2 for part (a)(ii), 1 for part (b), 1 for part (c)(i), 3 for part (c)(ii), and 1 for part (d). Sample: 1B Score: 7 Two points were earned in part (a)(i). Only 1 of the 2 points was earned in part (a)(ii); molarity is substituted for n instead of number of moles, so the substitution point was not earned. The point was earned in part (b). The point was not earned in part (c)(i); number of moles is used in the calculation instead of molarity. In part (c)(ii) 1 point was earned for setting [AsF 3 ] = [F 2 ], and 1 point was earned for correct calculation of their concentrations, but no point was earned for the calculation because of a math error. The point was earned in part (d). Sample: 1C Score: 4 In part (a)(i) 1 point was earned for the correct molar mass, but the second point was not earned because the initial molar concentration is not calculated. In part (a)(ii) 1 point was earned for the correct substitution into PV = nrt. However, the second point was not earned because the incorrect number of significant figures in 0.3 mol results in an incorrect pressure. The point was earned for the correct equation in part (b). The point was not earned in part (c)(i). In part (c)(ii) 1 point was earned for setting [AsF 3 ] = [F 2 ], but the other 2 points were not earned. The point was not earned in part (d) The College Board. All rights reserved.
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