Transcription

1 Graphs. Which of he following opions is correc for haing a sraigh line moion represened by s graph? O D C A s B ) The objec moes wih consanly increasing elociy from O o A hen i moes wih consan elociy. ) Velociy of he objec increases uniformly. 3) Aerage elociy is zero. 4) The graph shown is impossible.. The displacemen of a paricle as a funcion of ime is shown in he figure. The figure shows ha Displacemen Time in second ) The paricle sars wih cerain elociy bu he moion is rearded and finally he paricle sops. ) The elociy of he paricle is consan hroughou. 3) The acceleraion of he paricle is consan hroughou. 4) The paricle sars wih consan elociy, hen moion is acceleraed and finally he paricle moes wih anoher consan elociy.

2 3. A ball is hrown erically upwards. Which of he following graph/graphs represen elociy ime graph of he ball during is fligh (air resisance is negleced) a) b) ) A ) B 3) C 4) D 4. The x graph shown in figure represens. ) Consan elociy ) Velociy of he body is coninuously changing. 3) Insananeous elociy 4) The body raels wih consan speed up o ime and hen sops 5. Figures (i) and (ii) below show he displacemen ime graphs of wo paricles moing along he x axis. We can say ha ) Boh he paricles are haing a uniformly acceleraed moion. ) Boh he paricles are haing a uniformly rearded moion. 3) Paricle (i) is haing a uniformly acceleraed moion while paricle (ii) is haing a uniformly rearded moion. c) d)

3 4) Paricle (i) is haing a uniformly rearded moion while paricle (ii) is haing a uniformly acceleraed moion. 6. Velociy ime cure for a body projeced erically upwards is ) Parabola ) Ellipse 3) Hyperbola 4) raigh-line 7. The displacemen ime graph of moing paricle is shown below. D C E Time F The insananeous elociy of he paricle is negaie a he poin. ) D ) F 3) C 4) E 8. An objec is moing wih a uniform acceleraion which is parallel o is insananeous direcion of moion. The displacemen (elociy () graph of his objec is ) ) 3) 4) 9. Which of he following graph represens uniform moion? ) ) 3) 0. The area under acceleraion - ime graph gies ) Disance raelled ) Change in acceleraion 3) Force acing 4) Change in elociy 4). Which graph represens he uniform acceleraion? ) ) 3) 4)

4 . Which of he following elociy-ime graphs shows a realisic siuaion for a body in moion? ) ) 3) 4) 3. Which of he following elociy-ime graphs represen uniform moion? ) ) 3) 4) 4. An eleaor is going up. The ariaion in he elociy of he eleaor is as gien in he graph. Wha is he heigh o which he eleaor akes he passengers? ) 3.6m ) 8.8m 3) 36.0m 4) 7.0m 5. The displacemen ime graphs of wo moing paricles make angles of 0 45 wih he x-axis. The raio of he wo elociies is 0 30 and ) 3: ) : 3) : 4) : 3

5 6. In he gien - graph, he disance raelled by he body in 5second will be ) 40 m ) 00m 3) 36 m 4) 70m 7. In he following graph, disance raelled by he body in meers is V(m/s) y x (sec) ) 00 ) 50 3) 300 4) 400 I 0 0 = 50 II 0 0 = 00 III 0 0 = 50 oal = 00m 8. The V- graph of a paricle is as shown in he figure. The disance raelled by he paricle in 4 seconds will be () 50 m () 55 m (3) 60 m (4) 65 m

6 9. The elociy ime graph of a body execuing linear moion is shown in he following figure. The displacemen of he paricle in 5 seconds will be () m () 3m (3) 4m (4) 5m 0. A rocke is projeced erically upwards, whose ime elociy graph is shown in fig. The maximum heigh reached by he rocke is () km () 0 km (3) 0 km (4) 60 km ) The elociy ime graph of a body is as follows. Wha is he displacemen in 5 sec? ) m ) 3m 3) 4m 4) 5m

7 ) A paricle sars from res a = 0 and moes on a sraigh line wih acceleraion as shown graphically. The speed will be maximum afer? ) sec ) sec 3) 3 sec 4) 4 sec Key ) 3 ) 3) 4 4) 4 5) 3 6) 4 7) 4 8) 3 9) 0) 4 ) ) 3) 4) 5) 4 6) 7) 8) 9) 0) 4 ) ) 3

8 Hins = 36 m an30 5. = = an ( ) = 00 m I 0 0 = 50 II 0 0 = 00 III 0 0 = 50 oal = 00m 8. The disance coered by he paricle in 4 seconds = Area enclosed by he - graph = area OAB + area ACDB + area CTE + area TEFD + area EFHG = x x 0 + (-) x 0 + = = 55 m 9. Displacemen of paricle = Area under - graph (3-) x (3 -) x 0 + (4-3) x 0 = x 3 x - x x + x = 3m

9 0. Maximum heigh = Area under - cure h = x 0 x 000 = 60 km