ROUND 2 (2 ND YEAR) a) Yes b) No c) Depends on the compiler d) Depends on the standard

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1 ROUND 2 (2 ND YEAR) 1) Find the output? 2. void int x = 1, z = 3; 5. int y = x << 3; 6. printf(" %d\n", y); 7. a) b) -1 c) Run time error d) 8 2) What is the output of this C code? int i =1; 5. if(i++&&(i ==1)) 6. printf("yes\n"); 7. else 8. printf("no\n"); 9. a) Yes b) No c) Depends on the compiler d) Depends on the standard 3) Which of the following cannot be used as LHS of the expression in for (exp1;exp2; exp3)? a) Variable b) Function c) typedef d) macros 4) What is the output of this C code? short i; 5. for (i = 1; i >= 0; i++) 6. printf("%d\n", i); 7. 8.

2 a) The control won t fall into the for loop b) Numbers will be displayed until the signed limit of short and throw a runtime error c) Numbers will be displayed until the signed limit of short and program will successfully terminate d) This program will get into an infinite loop and keep printing numbers with no errors 5) What is the output of this C code? 2. void int k =0; 5. for(k) 6. printf("hello"); 7. a) Compile time error b) Hello c) Nothing d) Varies 6) What is the output of this C code? int i =0; 5. for(i++; i ==1; i =2) 6. printf("in for loop "); 7. printf("after loop\n"); 8. a) In for loop after loop b) After loop c) Compile time error d) Undefined behaviour 7) What is the output of this C code? int i =10; 5. void*p =&i; 6. printf("%d\n",(int)*p); 7. return0; 8. a) Compile time error b) Segmentation fault/runtime crash c) 10 d) Undefined behaviour

3 8)Find the output of the program below: char *p = ayqm ; printf( %c,++*(p++)); a) Compile time error b) Segmentation fault/runtime crash c) b d) Undefined behaviour 9):What is the output of the following code segment? 1. int temp,i,j; 2. int num[7]=7,6,5,4,3,2,1; 3. for (i=1; i<6; i++) 4. for (j=0; j<6; j++) if(num[i]>num[i+1]) temp=num[i]; 9. num[i]=num[i+1]; 10. num[i+1]=temp; for (i=0; i<7; i++) 14. printf("%d",num[i]); a) b) 6 c) d) Compile time error 10) Find the output of the program below: char a[4]="hell"; printf("%s",a); a) HELL b) HELL%@!~@!@???@~~!c) Run time error d) Compile time error

4 11) Find the output of the program below: int i=300; char *ptr = &i; *++ptr=2; printf("%d",i); a) 556 b) 301 c) 302 d)559 12) Find the output of the program below: void static int i; while(i<=10) (i>2)?i++:i--; printf( %d, i); a) Run time error b) 0,1,0,1,0,1,. c) 0,1,2,3,4,5,6,7,8,9,10 d) ) Find the output of the program below: int a= 0;int b = 20;char x =1;char y =10; if(a,b,x,y) printf("hello"); a) Program will excute and nothing will be printed. b) Run time error c) hello d) Compile time error

5 14)Find the output: int i=5,j=6,z; printf("%d",i+++j); a) Compile Time Error b)11 c)5+++6 d)13 15) In the piece of code, arr[ ][ ] is a 2-D array and assume that the contents of the 2D array are already filled up. What is stored in the variable sum at the end of the code segment? int arr[3][3]; int i, sum=0; i = 0; while(i<3) sum += *(*(arr+i)+(i++)); printf("sum:%d", sum); Options: a) Sum of all elements in the matrix b) Sum of alternate elements in the matrix c) Sum of the elements along the principal diagonal d) None of these

6 Answers 1.D 2.B 3.D 4.C 5.A 6.A 7.A 8.C 9.C For every iteration of for loop in line 3, if(num[i] > num[i+1]) on line 6 is executed 6 times(due to the for statement in line 4) for every i. After one iteration of for loop in line 3, the contents of array will be 7,5,6,4,3,2,1; arr[1] and arr[2] in the original array are swapped. After second iteration, arr[2] and arr[3] will be swapped because arr[2] > arr[3]. The contents will be 7,5,4,6,3,2,1 and so on 10.B The character array has the memory just enough to hold the string HELL and doesnt have enough space to store the terminating null character. So it prints the HELL correctly and continues to print garbage values till it accidentally comes across a NULL character. 11.A The integer value 300 in binary notation is: It is stored in memory (small-endian) as: Result of the expression *++ptr = 2 makes the memory representation as: So the integer corresponding to it is => D Since i is static it is initialized to 0. Inside the while loop the conditional operator evaluates to false, executing i--. This continues till the integer value rotates to positive value (32767). The while condition becomes false and hence, comes out of the while loop, printing the i value. 13.C The comma operator has associativity from left to right. Only the rightmost value is returned and the other values are evaluated and ignored. Thus the

7 value of last variable y is returned to check in if. Since it is a non zero value if becomes true so, "hello" will be printed. 14.B the expression i+++j is treated as (i++ + j) 15.C Observe that the unary operator ++ in the program is a post increment operator. Thus the value of i gets incremented only after the execution of the statement. Since arr is a 2-D array, arr represents a pointer to an array of pointers, where each pointer in the array in turn points to a 1-D array(i^th pointer points to the starting location of i^th row in the array). So, *(arr+i) represents the starting address of i^th row. This implies *(arr+i)+i represents the address of i^th element in the i^th row, which is basically a diagonal element.

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