Version : 1.0: 1105 abc. General Certificate of Education examination June series
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1 Version : 1.: 115 abc General Certificate of Education Mathematics MPC1 Pure Core 1 Mark Scheme 5 examination June series Mark schemes are prepared by the Principal Examiner and considered, together with the relevant questions, by a panel of subject teachers. This mark scheme includes any amendments made at the standardisation meeting attended by all examiners and is the scheme which was used by them in this examination. The standardisation meeting ensures that the mark scheme covers the candidates responses to questions and that every examiner understands and applies it in the same correct way. As preparation for the standardisation meeting each examiner analyses a number of candidates scripts: alternative answers not already covered by the mark scheme are discussed at the meeting and legislated for. If, after this meeting, examiners encounter unusual answers which have not been discussed at the meeting they are required to refer these to the Principal Examiner. It must be stressed that a mark scheme is a working document, in many cases further developed and expanded on the basis of candidates reactions to a particular paper. Assumptions about future mark schemes on the basis of one year s document should be avoided; whilst the guiding principles of assessment remain constant, details will change, depending on the content of a particular examination paper. Copyright 5 AQA and its licensors. All rights reserved.
2 MPC1 - AQA GCE Mark Scheme, 5 June series Key to mark scheme and abbreviations used in marking M m or dm A B E mark is for method mark is dependent on one or more M marks and is for method mark is dependent on M or m marks and is for accuracy mark is independent of M or m marks and is for method and accuracy mark is for explanation or ft or F follow through from previous incorrect result MC mis-copy CAO correct answer only MR mis-read CSO correct solution only RA required accuracy AWFW anything which falls within FW further work AWRT anything which rounds to ISW ignore subsequent work ACF any correct form FIW from incorrect work AG answer given BOD given benefit of doubt SC special case WR work replaced by candidate OE OE FB formulae book A,1 or 1 (or ) accuracy marks NOS not on scheme x EE deduct x marks for each error G graph NMS no method shown c candidate PI possibly implied sf significant figure(s) SCA substantially correct approach dp decimal place(s) Application of Mark Scheme No method shown: Correct answer without working Incorrect answer without working mark as in scheme zero marks unless specified otherwise More than one method / choice of solution: or more complete attempts, neither/none crossed out mark both/all fully and award the mean mark rounded down 1 complete and 1 partial attempt, neither crossed out award credit for the complete solution only Crossed out work Alternative solution using a correct or partially correct method do not mark unless it has not been replaced award method and accuracy marks as appropriate
3 AQA GCE Mark Scheme 5 June series MPC1 MPC1 1(a) One coordinate correct unsimplified Midpoint, = (4, ) Both correct and simplified (c)(i) (d) (a) (i) AB = ( ) + (5 + 1) = (1 + ) = 5 AB = 1 Gradient AB = (5 1) / ( ) = = =1.5 4 Pythagoras used (condone one slip) 5 or 5 seen Must be y on top and subtraction ( ) Any correct equivalent y 5 = m( x ) or y+ 1 = m( x ) or y = mx + c and attempt to find c. y 1 = x 18 etc leading to x y = 8 AG (be convinced) Attempt to eliminate x or y x = 8 etc x = 4 y = C is point (4,) ( x ) 1 y + x Vertex (, ) graph Total 1 p = q = ft their p ft their q parabola (ft on vertex approx position) correct with y = 1 marked or stated (iii) Line of symmetry x = 1 Must have correct equation (c) Translation (and no additional transf n) E1 Not shift, move, transformation, etc one part correct eg units up through all correct if not vector must say units in positive x- direction etc Total 1 (a) ( x ) + ( y+ 1) ( x ± a) + ( y± b) = 5 or 5 Correct equation for circle Sub x =, y = into their circle equation Or distance PC = 4 + ( ) + (+1) =1+9 =5 Shown to equal radius (c) Gradient CP = ( 1) / ( ) Must be y on top and subtraction ( ) = 4 =.5 Any correct equivalent (d)(i) Grad of perp = 1 / their gradient CP Or mm 1 = 1 used or stated = 4/ y = their ( d)( i)gradient( x ) 1 OE such as y + 4x = Total 1
4 MPC1 - AQA GCE Mark Scheme, 5 June series MPC1 (cont) 4(a)(i) p() = Finding p() p() = x is a factor Shown = plus a statement Or ( x )( x x+ 1) B is point (,) 1 Must have coordinates (i) dy x 1x dx = + One term correct All correct with NO +c etc x 1x+ = ( x 1)(x ) = at M, x= (c) x 1 d x = sub x =1, = 4 d x (d)(i) 4 x 5x x + x ( + c) 4 m1 4 Putting their dx = Attempt to use quad formula or factorise CSO factors correct etc ft their dx ft their d x Increase one power by 1 One term correct Two other terms correct All correct (condone missing + c) Realisation that limits are and = 1 Condone wrong way round Attempt to sub their limits into their (d)(i) CSO. Must use F(1) F() correctly Area = 11 1 E1 4 CSO. Convincing argument Total 18 5(a) + 1+ = 4+ Multiplied out At least terms with m = 4, n = term Multiplying top and bottom by + 1 Denominator = 1 = Expression = 4 + = + CSO m =, n = 1 Total 5 4
5 AQA GCE Mark Scheme 5 June series MPC1 MPC1 (cont) (a) p( x) = x + x + x x x Condone one slip = x x + x a = 1, b = 1 p( 1) = or (Remainder is) 9 Must use p( 1) and not long division (c) Considering x + x+ = and attempting to solve or use discriminant b 4ac< no real roots Only real root is b CSO x = 4ac= 1 1 = 11 Total (a) x > 5x Multiplying out (condone one slip) 8x > 4 Or correct equivalent eg 8x < 4 x > (Penalise!, " once only in (a) and ) x x = ( x )( x+ ) Attempt to use quad formula or factorise (critical points are) and May be seen in diagram or solution Sketch or sign diagram < x < 4 Total + + 8(a) mx 1= x 5x + x 5x mx+ 4= x (5 + m) x+ 4 = 1 Strict mark here no trailing equals signs AG (be convinced about algebra and = ) (5 + m) 1 = Equal roots when b 4ac = used 5+ m = ( ± ) 4 or ( m+ 1)( m+ 9) = m1 Square root or factor/formula attempt m = 1 m = 9 4 SC, only for 1, 9 (no working) (c) Line is a tangent to the curve E1 1 Line touches curve, cuts at one point etc Total Total 5 5
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