2007. Ж. А., А.. З, Ж. Е. Й, З. О. Л Йapple М. К.З. ъ ИОЗ
|
|
- Stephanie Lyons
- 7 years ago
- Views:
Transcription
1 ЩВИЩ ЕҐЩЙДЕЩ ВЙЗВА ЛЕЖЕҐЩЙДВГ ЩЛЗВВРЕЕ, 007, 41,, Н Д : Рappleapple apple apple apple applefl appleapple apple apple, applefl fl 007. Ж. А., А.. З, Ж. Е. Й, З. О. Л Йapple М. К.З. ИОЗ К apple Вapple apple applefl apple apple apple, apple, apple appleapple appleapple apple apple appleapple apple, apple apple applefl appleapple apple - apple, applefl fl. З appleapple apple appleapple applefl apple 10% - apple 60%. Чapple- apple ( 1 ) apple apple fl,, [1]. А, - fl apple fl apple- apple []. Йfl 1 fl- flfl apple apple- fl- apple, applefl apple apple apple flfl 3 д 94.3 /, apple applefl 60. З apple appleapple apple (РЙД) apple apple apple appleapple apple apple [3]. appleapple fl apple apple - apple 113 ДК apple ( 1 ) 60% [4]. А РЙД apple- apple apple apple apple appleapple 0шЙ applefl 1 / apple apple (N h > N b ); appleapple applefl H : ВЗ + З В H +З В. (1) И apple (1) apple, applefl H apple apple- appleapple [OH ] [H ] [5]. Ж- applefl ( 1 ) fl apple [6]. Кapple apple apple - apple apple - appleapple apple apple apple apple apple apple apple appleapple, apple H 100%- apple ( 1 ) [7]: Cl + H ( ) + Cl + H +, K ч /( ), [8] H + + H H. () Е apple applefl ( 1 ) fl- apple: 1 Cl + ВЗ + З В = ( 1 ) +З В + Йl. (3) Дapplefl OH apple- H apple apple apple OH apple Д [8, 9], - apple apple apple apple OH apple apple- apple. Вapplefl apple apple apple - flfl appleapple apple apple-. Зfl appleapple apple apple- apple apple - apple. Иfl apple appleapple, apple applefl ( 1 ), fl D c, KN b appleapple applefl fl З- D 0 KN b apple ( 1 ), appleapple appleapple, fl apple appleapple applefl -, applefl fl. Зapple- apple, apple N b = 1 /, D 0 ч D c ч / apple- D c 176
2 Рappleapple apple 177 fl apple, apple applefl ( 1 ), appleapple 1, applefl fl ( 1 ) appleapple apple apple appleapple- 10 9, apple 10 6 appleapple [10]. В - applefl fl fl ( 1 ) apple apple fl 100% [11]. Чapple- apple ( 1 ) apple- fl (applefl apple apple apple, 3 /): ( 1 ) + ( 1 ) ( 1 д) + ( 3 д), , (4) ( 1 д) + З В ( 1 ) + З В, , (5) ( 1 ) + ( 1 ) ( 3 д) + ( 3 д), , (6) ( 1 ) +Cl ( 3 д) + Cl, , (7) ( 1 ) +H O ( 3 д) + H O, (8) А apple (4) applefl apple apple apple- fl apple 157 /. Рappleapple apple applefl- - apple, apple apple fl- flfl apple- apple ( 1 ). Д fl apple appleapple РЙД apple [], apple [4], - [1], [13] apple-. Йapple ( 1 ) applefl (4)(8) apple apple- apple. Ч apple applefl appleapple apple apple, apple fl apple apple apple apple apple ( 1 ). - fl apple РЙД apple applefl ( 1 ) apple. Дapple, apple fl, appleapple, apple- apple, apple appleapple H РЙД. А fl apple apple - РЙД apple apple applefl appleapple H, - applefl fl. Е - apple- РЙД fl apple-- apple apple apple apple [14]. apple apple appleapple РЙД, apple applefl ( 1 ), applefl. Кapplefl apple- РЙД apple apple. 1. Аapple apple apple РЙД 135, - 80 apple 50 apple 540 apple fl apple 0.. А apple appleapple applefl apple apple 1-5. Иfl apple. А apple applefl apple,. З applefl 135 apple fl apple- fl applefl apple appleapple apple apple. Вapplefl - apple appleapple apple apple. Рapple apple appleapple apple apple apple, appleapple appleapple. Р apple- apple apple 15 apple 50 apple. РЙД apple- apple fl - fl apple, apple - apple 4. В appleappleapple applefl apple fl V T = = apple apple apple apple fl, apple apple fl applefl apple apple, ( 1 ), apple, appleapple fl. А N c applefl apple 337, N apple- fl apple apple I, appleappleapple ( 1 ) 176, N = AI. Й apple (5), apple N w ( apple apple - РЙД) fl N, N д apple fl apple- fl Аapplefl fl РЙД - appleapple ( 1 ) apple, N - apple (4), (6)(8) apple apple appleapple-. А fl appleapple N д flflfl apple : N д N = N w Й, apple apple-, appleappleapple ( 1 д) 76 I д C I = N w fl apple- fl apple apple, fl РЙД. Дapple applefl - apple apple N c apple - fl fl fl = = 337. Еapple fl apple apple (.3 с 0.01) 10 19, 5
3 178 apple. У appleapple H Д Cl Кapple И. 1. Й apple- РЙД: 1, fl apple, 3 apple, 4 apple. applefl [15]. Д- apple ( 1 ) apple apple apple fl apple apple- apple ( 133 К) applefl apple, 1 : 10, ( 1 ) applefl (4)(8) applefl appleappleapple - apple appleapple apple apple appleapple appleapple. А apple apple ( 1 ) - applefl apple Y 0 apple appleapple H. А - appleapple appleflfl apple fl Y 0 75 [16] 94% [11]. Оapple fl apple ( 1 ) apple Y 0 =. fl - apple applefl apple apple - applefl apple apple appleapple appleapple. Кapple apple apple, apple appleapple appleapple N w apple, applefl - N apple C = w I д. А apple apple fl- I, fl apple apple- fl Y apple с10%, apple - applefl apple apple с0.1 с0.05 apple.. fl apple apple. appleapple apple applefl appleapple, apple- fl - fl ( 1 ) apple. И appleapple РЙД apple- apple applefl fl: CI w = kt, I д c = N c kt,
4 Рappleapple apple 179 Кapple N w > N < , - apple N д N, - apple ( 1 ) fl: N Y N kt = N ч w, c applefl applefl apple fl- fl 1 3 д N o ч w c /kt. Ж applefl applefl applefl РЙД: V з r = / c1 kt GRT 1 applefl appleappleapple з c1 ( V + V T ) T = RT 1 G Кapple з r з appleapple 1 apple- apple appleapple apple apple- apple apple apple. Й, fl ( 1 ) appleapple apple- apple appleapple apple, c, w Y. Й apple apple РЙД applefl apple flfl apple G c = (1 U)G, G o = UG c, G = YUG c, Q(N b N b1 ) = = UG, Q(N h N h1 ) = UG, G w = w (G o + G c ). У appleapple apple apple apple- 14 Ж appleapple ДВЗ 38%- apple apple - apple. Кapple fl РЙД apple - fl fl apple appleapple apple Q = = 1. /. М apple- 10 3, apple apple 13.5 apple 1 1.9, fl apple applefl- apple ~1. apple, appleflfl fl apple applefl apple ~ apple. В appleapple applefl, fl, apple- V = 380 3, V + V T appleapple- apple apple apple w w w =, c w U = , 1 ( w ) c1 = apple Кapple apple apple c 1 apple- 5.4 / apple apple applefl. fl appleapple- apple appleapple H applefl 1 РЙД flfl. З apple- apple appleapple fl. А appleapple РЙД - apple apple, apple, - flapple appleapple appleapple H, apple fl apple. Йapple fl applefl appleapple apple- apple. А appleapple fl, - apple apple, apple appleapple - fl 10. Ч apple apple- apple apple applefl РЙД з r ч apple apple.. А, - apple apple fl. fl apple apple apple apple fl apple applefl apple з r (apple. ). Кapple з r apple fl fl, fl - apple apple apple apple applefl [17]. Йfl - apple apple fl з r, apple apple - appleapple H apple fl H, apple apple apple appleflfl H apple [17]. Кapple apple apple apple apple apple fl РЙД apple fl ( 1 ) applefl (4)(8). В apple- ( 1 ) РЙД appleflfl apple- apple fl apple И 1 apple applefl з,.. И 1 з (apple. 3). Зfl applefl fl apple apple- Y = 5 (1 + И 1 з ) 1. З -, appleapple apple - apple Д appleapple И 1 з , appleapple apple- apple apple - appleapple И 1 (з з r ) apple ( 1 ) apple appleapple- apple applefl apple fl., apple РЙД, apple apple 5*
5 180 apple. U 1.0 () G, / () з r, () t, шc 1.0 () Q, / Y c1 з T И. 3. В apple ( 1 ) И c1 з r, apple Q = 1. /, N b = 6.5 /, N h = 7.5 /, t = = 16шC. И apple G, /: a 0, 40, 57, 75. ( 1 ) apple appleapple -. Й appleapple apple- apple H apple - fl (apple. ), apple - fl fl appleapple, apple - apple H appleapple, apple apple (). Кapple fl apple appleapple - appleapple H apple- apple apple %, ( 1 ) flfl. Н apple - appleapple H apple - apple (apple. ). А fl - applefl apple 4 6% applefl ( 1 ) Кapple - appleapple РЙД apple ДВЗ appleapple H apple () И.. Ч apple: apple apple apple applefl РЙД з r ч c, Q = 1. /, N b = 6.5 /, N h = 7.5 /, t = 16шC; apple applefl РЙД apple Q = 1. /, N b = 6.5 /, N h = 7.5 /, t = 16шC. И apple G, /: 40; 57, 75; appleapple appleapple apple apple- apple Q = 1. /, N b = 6.5 /, N h = 7.5 /, G = = 57 /, c1 = 3.3 apple.., з r ч 10 c; apple appleapple apple apple apple N b = 6.5 /, N h = 7.5 /, G = 57 /, t = N А, / = 16шC, c1 = 0 apple.., з r ч c; - apple ДВЗ apple- apple apple apple apple Q = 1. /, G = = 57 /, t = 10шC, c1 = 0 apple.., з r ч c.
6 Рappleapple apple 181 apple. А 38%- apple apple - fl 14 Ж ДВЗ fl fl apple. apple, appleapple H, apple - applefl fl applefl apple apple. Й apple appleapple apple - apple (apple. ), apple apple apple appleapple- fl apple apple-. А apple apple- N h fl ( 1 ) apple - apple apple. И apple 1 : 4 apple РЙД, apple apple applefl РЙД apple apple apple fl apple apple РЙД fl - apple ( 1 ). И- - appleapple РЙД. Иapple РЙД - ( 1 ) fl apple - apple- apple, apple [18]. Кapple apple apple 57 / - fl apple 150 А. Ч- apple, apple apple apple РЙД applefl [18]. В apple apple- РЙД, apple - appleapple H appleapple - apple. К 60 appleapple apple apple apple apple apple appleapple. Йapple- РЙД - ( 1 ) fl apple apple- fl, fl apple- apple. З fl apple apple- fl apple appleapple H apple-, РЙД applefl [18]. Лfl РЙД applefl- fl apple ~5 1, fl apple apple-- РЙД, apple apple apple fl (apple appleapple H, - apple, applefl applefl ) - apple apple РЙД applefl. А - fl apple apple appleapple applefl - apple appleapple H,, -, apple apple. П fl apple apple apple apple- РЙД flflfl apple apple apple. И apple apple Щapple apple - appleapple (apple ) - apple apple Жapple - apple (apple 30). Вfl О apple ; Й apple ; D c apple - appleapple apple apple, /; D o apple - appleapple apple apple, /; G flapple apple apple РЙД, /; G c flapple apple apple РЙД, /; G o flapple apple apple РЙД, /; G flapple apple apple РЙД, /; G w flapple apple apple РЙД, /; I apple apple, apple- appleapple apple fl 1 ; I д apple apple, apple- appleapple apple fl 1 д; Д apple apple, /( ); k flfl П; N w applefl apple apple-, 3 ; N c applefl apple apple, 3 ; N b, N b1 flapplefl applefl - appleapple apple apple РЙД, /; N h, N h1 flapplefl applefl apple - apple appleapple apple apple РЙД, /; N o applefl applefl apple - flfl 1 3 д, 3 ; N applefl apple fl 1, 3 ; N д applefl apple fl 1 д, 3 ; И 1 РЙД, apple.. И apple, apple..; И 1 apple РЙД, apple..; И apple apple, apple..;
7 18 apple. И w apple apple, apple..; Q apple apple- apple apple apple, /; R applefl fl flfl; 1 appleapple РЙД, Д; appleapple apple, Д; t appleapple appleapple apple apple, шй; U apple РЙД; V fl РЙД, apple- applefl, 3 ; V T appleappleapple apple- fl apple, 3 ; N Y = apple ( 1 ); N o Y 0 Y apple appleapple apple apple; w apple apple ; з r applefl applefl applefl, ; з T applefl appleappleapple apple apple,. ЙКЕЙВД Е ЩИО НИ 1. Khan A.U. Singlet molecular oxygen. A new kind of oxygen // The Journal of hysical Chemistry V McDermott W.E., chelkin N.R., Benard D.J., Bousek R.R. An electronic transition chemical laser// Appl.hys.Lett. 1978, V Browne R.J., Ogryzlo E.A. Chemiluminescence from the reaction of chlorine with aqueous hydrogen peroxide // roc.chem.soc Оfl А.З., Ж.А., З А.. apple. Йapple appleapple ( 1 ) apple 13.3 К // Дfl apple Й Balej J, Spalek O. Calculation of equilibrium composition in more concentrated systems H KOH (or NaOH)H O // Collection Czechoslov.Chem.Commun. 1979, V Richardson R.J., Kelley J.D., Wiswall C.E. ( 1 ) generation mechanisms in the chemically pumped iodine laser // J. Appl. hys V Storch D.M., Dymek C.J., Davis L.. MNDO study of the mechanism of ( 1 ) formation by reaction of Cl with basic H // J. Am. Chem. Soc V Оfl А.З., Ж.А., З А.., Н З.Е. Д apple Cl appleapple H OH KOH H OKOH // Ъapple Й Gershenzon M., Davidovits., Jayne J.T. et al. Rate constant for the reaction of Cl (aq) with OH // J. hys. Chem. A. 00. V Rogers M.A. Lifetime of ( 1 ) in liquid water as determined by time resolved infrared luminescence measurements // J.Am. Chem. Soc V П З.Р., Ж.А., Е А.Е. apple. apple apple- apple // apple МЕОЗ Й Blauer J.A., Munjee S.A., Truesdell K.A. et al. Aerosol generators for singlet oxygen production// J. Appl. hys V Harpole G.M., English W.D., Berd J.G., Miller D.J. Rotating disk oxygen generator // AIAA aper resented on 3 rd lasmadynamics and Lasers conference. July 68, 199. Nashville. USA. 14. Vetrovec J. Singlet oxygen generator with filamentguided jets // roceedings of SIE V В Л. Мfl. Ж.: Жapple, Yang T.T., Copeland D.A., Bauer A.H. et al. Chemical oxygen-iodine laser performance modeling // AIAA aper resented on 8 th lasmadynamics and laser conference. June apple К.А. Р apple. Ж.: Л- fl, Hager G.D., Nikolaev V.D., Svistun M.I., Zagidullin M.V. Lasing performance of a chemical oxygen iodine laser (COIL) with advanced ejector nozzle banks // Appl. hys. A V
ЗВАГ ЙКВЙВП ДВЗ ЩЗ ИЕИВАОЗЕБ Е Е АЩҐЩЗЕБ ВВ О Е РИОМЕ ВАЛ ИН НИРЩЗЩАЙДВРВ ЖЩЙ ВИВЪ ЩЗЕБ, КИЕЖВИ Щ
ВДО ОДО ЩЖЕЕ ЗОНД, 2008, 423, 1,. 110113 Н Д 553.411+546.59 РЩВЛЕЖЕБ ЗВАГ ЙКВЙВП ДВЗ ЩЗ ИЕИВАОЗЕБ Е Е АЩҐЩЗЕБ ВВ О Е РИОМЕ ВАЛ ИН НИРЩЗЩАЙДВРВ ЖЩЙ ВИВЪ ЩЗЕБ, КИЕЖВИ Щ 2008. О О. Е. Л, Ж. О. Ж,. К. К, А.
More informationЗВАВЩ ЙЩЖЩГЙ АВ ЕЙКЩИРЕИВАОЗЗЛ КВА ВИВА Е РЩЗВЖО ҐЩХНГҐО Л ИЩК ЕЕГ
ЖВЩДНБИЗОБ ПЕВВРЕБ, 2006, 40, 2,. 378382 Н Д 577.21 Дapple ъfl ЗВАВЩ ЙЩЖЩГЙ АВ ЕЙКЩИРЕИВАОЗЗЛ КВА ВИВА Е РЩЗВЖО ҐЩХНГҐО Л ИЩК ЕЕГ 2006. Й. О. Д, В. И. Пapple, А. А. Рapple*,. О. Дappleapple Е flapple ъ
More informationProgramming the Microchip Pic 16f84a Microcontroller As a Signal Generator Frequencies in Railway Automation
988 Programming the Microchip Pic 16f84a Microcontroller As a Signal Generator Frequencies in Railway Automation High School of Transport "Todor Kableshkov" 1574 Sofia, 158 Geo Milev str. Ivan Velev Abstract
More informationProblem A. Nanoassembly
Problem A. Nanoassembly 2.5 seconds One of the problems of creating elements of nanostructures is the colossal time necessary for the construction of nano-parts from separate atoms. Transporting each of
More informationThe European Ombudsman
Overview The European Ombudsman Е в р о п е й с к и о м б у д с м а н E l D e f e n s o r d e l P u e b l o E u r o p e o E v r o p s k ý v e ř e j n ý o c h r á n c e p r á v D e n E u r o p æ i s k e
More informationттгт ци тг цсс пястсгс цсгс TELOS
пепистги ягтгр сг хети епистг тг епистггс упцист гисс пхг еусгс и диеияисгс ттгт ци тг цсс пястсгс цсгс TELOS цв цв applefi евfl г, ж 1994 пепистги ягтгр сг хети епистг тг епистггс упцист гисс пхг еусгс
More informationIС A A RT 2013. Proceedings Volume 2. 5th International Conference on Agents and Artificial Intelligence. Barcelona, Spain 15-18 February, 2013
«'.''«ИЧИЧГШ ИШ М Ш * /////>. л ъ и г ш я ш и ъ в т ъ т ', : 4 р * т Ъ ъ ^ Х 'Ш У Л *а * 1 ЛЧй==:й?й!^'ййй IС A A RT 2013. *»ф«ч>»д* 'И И в Я в З Г З г И Ж /а 1 * icw-ia & «:*>if E M e i i i i y. x '-
More informationUNDERGRADUATE STUDY SKILLS GUIDE 2014-15
SCHOOL OF SLAVONIC AND EAST EUROPEAN STUDIES UNDERGRADUATE STUDY SKILLS GUIDE 2014-15 ECONOMICS AND BUSINESS HISTORY LANGUAGES AND CULTURE POLITICS AND SOCIOLOGY 1 1. AN INTRODUCTION TO STUDY SKILLS 5
More information4 theoretical problems 2 practical problems
1 st 4 theoretical problems 2 practical problems FIRST INTERNATIONAL CHEMISTRY OLYMPIAD PRAGUE 1968 CZECHOSLOVAKIA THEORETICAL PROBLEMS PROBLEM 1 A mixture of hydrogen and chlorine kept in a closed flask
More informationTest Review # 9. Chemistry R: Form TR9.13A
Chemistry R: Form TR9.13A TEST 9 REVIEW Name Date Period Test Review # 9 Collision theory. In order for a reaction to occur, particles of the reactant must collide. Not all collisions cause reactions.
More informationChemistry: Chemical Equations
Chemistry: Chemical Equations Write a balanced chemical equation for each word equation. Include the phase of each substance in the equation. Classify the reaction as synthesis, decomposition, single replacement,
More informationChem 31 Fall 2002. Chapter 3. Stoichiometry: Calculations with Chemical Formulas and Equations. Writing and Balancing Chemical Equations
Chem 31 Fall 2002 Chapter 3 Stoichiometry: Calculations with Chemical Formulas and Equations Writing and Balancing Chemical Equations 1. Write Equation in Words -you cannot write an equation unless you
More informationThe 5 Types of Chemical Reactions (Chapter 11) By C B 6 th period
The 5 Types of Chemical Reactions (Chapter 11) By C B 6 th period 1) Combination Reactions Is also referred to as a synthesis reaction It is a chemical change in which two or more substances react to form
More informationRussian Introductory Course
Russian Introductory Course Natasha Bershadski Learn another language the way you learnt your own Succeed with the and learn another language the way you learnt your own Developed over 50 years, the amazing
More informationCLASS TEST GRADE 11. PHYSICAL SCIENCES: CHEMISTRY Test 6: Chemical change
CLASS TEST GRADE PHYSICAL SCIENCES: CHEMISTRY Test 6: Chemical change MARKS: 45 TIME: hour INSTRUCTIONS AND INFORMATION. Answer ALL the questions. 2. You may use non-programmable calculators. 3. You may
More informationUnit 2: Quantities in Chemistry
Mass, Moles, & Molar Mass Relative quantities of isotopes in a natural occurring element (%) E.g. Carbon has 2 isotopes C-12 and C-13. Of Carbon s two isotopes, there is 98.9% C-12 and 11.1% C-13. Find
More informationMOLECULAR MASS AND FORMULA MASS
1 MOLECULAR MASS AND FORMULA MASS Molecular mass = sum of the atomic weights of all atoms in the molecule. Formula mass = sum of the atomic weights of all atoms in the formula unit. 2 MOLECULAR MASS AND
More informationAPPENDIX B: EXERCISES
BUILDING CHEMISTRY LABORATORY SESSIONS APPENDIX B: EXERCISES Molecular mass, the mole, and mass percent Relative atomic and molecular mass Relative atomic mass (A r ) is a constant that expresses the ratio
More informationChapter 3. Chemical Reactions and Reaction Stoichiometry. Lecture Presentation. James F. Kirby Quinnipiac University Hamden, CT
Lecture Presentation Chapter 3 Chemical Reactions and Reaction James F. Kirby Quinnipiac University Hamden, CT The study of the mass relationships in chemistry Based on the Law of Conservation of Mass
More informationVictims Compensation Claim Status of All Pending Claims and Claims Decided Within the Last Three Years
Claim#:021914-174 Initials: J.T. Last4SSN: 6996 DOB: 5/3/1970 Crime Date: 4/30/2013 Status: Claim is currently under review. Decision expected within 7 days Claim#:041715-334 Initials: M.S. Last4SSN: 2957
More informationChemical Equations & Stoichiometry
Chemical Equations & Stoichiometry Chapter Goals Balance equations for simple chemical reactions. Perform stoichiometry calculations using balanced chemical equations. Understand the meaning of the term
More informationHydrogen Bonds in Water-Methanol Mixture
Bulg. J. Phys. 34 (2007) 103 107 Hydrogen Bonds in Water-Methanol Mixture G.M. Georgiev, K. Vasilev, K. Gyamchev Faculty of Physics, University of Sofia 5J.Bourchier Blvd., 1164 Sofia, Bulgaria Received
More informationCHEM 105 HOUR EXAM III 28-OCT-99. = -163 kj/mole determine H f 0 for Ni(CO) 4 (g) = -260 kj/mole determine H f 0 for Cr(CO) 6 (g)
CHEM 15 HOUR EXAM III 28-OCT-99 NAME (please print) 1. a. given: Ni (s) + 4 CO (g) = Ni(CO) 4 (g) H Rxn = -163 k/mole determine H f for Ni(CO) 4 (g) b. given: Cr (s) + 6 CO (g) = Cr(CO) 6 (g) H Rxn = -26
More informationCOMPLIANCE OF MANAGEMENT ACCOUNTING WHEN USING INFORMATION TECHNOLOGIES
Margaryta I. Skrypnyk, Mykola M. Matiukha COMPLIANCE OF MANAGEMENT ACCOUNTING WHEN USING INFORMATION TECHNOLOGIES The article studies the correspondence of management accounting structure when using of
More information7-5.5. Translate chemical symbols and the chemical formulas of common substances to show the component parts of the substances including:
7-5.5 Translate chemical symbols and the chemical formulas of common substances to show the component parts of the substances including: NaCl [salt], H 2 O [water], C 6 H 12 O 6 [simple sugar], O 2 [oxygen
More informationIB Chemistry 1 Mole. One atom of C-12 has a mass of 12 amu. One mole of C-12 has a mass of 12 g. Grams we can use more easily.
The Mole Atomic mass units and atoms are not convenient units to work with. The concept of the mole was invented. This was the number of atoms of carbon-12 that were needed to make 12 g of carbon. 1 mole
More informationLiquid phase. Balance equation Moles A Stoic. coefficient. Aqueous phase
STOICHIOMETRY Objective The purpose of this exercise is to give you some practice on some Stoichiometry calculations. Discussion The molecular mass of a compound is the sum of the atomic masses of all
More informationLingjie Zhao Singlet Oxygen 1. Singlet Oxygen. Lingjie Zhao. Free Radical and Radiation Biology Graduate Program. Department of Radiology B-180 ML
Lingjie Zhao Singlet Oxygen 1 Singlet Oxygen By Lingjie Zhao Free Radical and Radiation Biology Graduate Program Department of Radiology B-180 ML The University of Iowa Iowa City, IA 52242-1181 For 77:222,
More informationEXPERIMENT 12: Empirical Formula of a Compound
EXPERIMENT 12: Empirical Formula of a Compound INTRODUCTION Chemical formulas indicate the composition of compounds. A formula that gives only the simplest ratio of the relative number of atoms in a compound
More informationINTI COLLEGE MALAYSIA A? LEVEL PROGRAMME CHM 111: CHEMISTRY MOCK EXAMINATION: DECEMBER 2000 SESSION. 37 74 20 40 60 80 m/e
CHM111(M)/Page 1 of 5 INTI COLLEGE MALAYSIA A? LEVEL PROGRAMME CHM 111: CHEMISTRY MOCK EXAMINATION: DECEMBER 2000 SESSION SECTION A Answer ALL EIGHT questions. (52 marks) 1. The following is the mass spectrum
More informationAP CHEMISTRY 2009 SCORING GUIDELINES (Form B)
AP CHEMISTRY 2009 SCORING GUIDELINES (Form B) Question 3 (10 points) 2 H 2 O 2 (aq) 2 H 2 O(l) + O 2 (g) The mass of an aqueous solution of H 2 O 2 is 6.951 g. The H 2 O 2 in the solution decomposes completely
More informationNotes on Unit 4 Acids and Bases
Ionization of Water DEMONSTRATION OF CONDUCTIVITY OF TAP WATER AND DISTILLED WATER Pure distilled water still has a small conductivity. Why? There are a few ions present. Almost all the pure water is H
More informationSurvival Organic Chemistry Part I: Molecular Models
Survival Organic Chemistry Part I: Molecular Models The goal in this laboratory experience is to get you so you can easily and quickly move between empirical formulas, molecular formulas, condensed formulas,
More informationISSN 0975-413X CODEN (USA): PCHHAX. The study of dissolution kinetics of drugs with riboxinum (inosine)
Available online at www.derpharmachemica.com ISSN 0975-413X CODEN (USA): PCHHAX Der Pharma Chemica, 2016, 8(1):412-416 (http://derpharmachemica.com/archive.html) The study of dissolution kinetics of drugs
More informationChemical Reactions 2 The Chemical Equation
Chemical Reactions 2 The Chemical Equation INFORMATION Chemical equations are symbolic devices used to represent actual chemical reactions. The left side of the equation, called the reactants, is separated
More informationUnit 6 The Mole Concept
Chemistry Form 3 Page 62 Ms. R. Buttigieg Unit 6 The Mole Concept See Chemistry for You Chapter 28 pg. 352-363 See GCSE Chemistry Chapter 5 pg. 70-79 6.1 Relative atomic mass. The relative atomic mass
More informationChapter 5, Calculations and the Chemical Equation
1. How many iron atoms are present in one mole of iron? Ans. 6.02 1023 atoms 2. How many grams of sulfur are found in 0.150 mol of sulfur? [Use atomic weight: S, 32.06 amu] Ans. 4.81 g 3. How many moles
More informationChemistry Themed. Types of Reactions
Chemistry Themed Types of Reactions 1 2 Chemistry in the Community-2015-2016 Types of Reactions Date In-Class Assignment Homework T 10/20 TEST on Reactivity of Metals and Redox None W 10/21 Late Start
More informationThe Gas Laws. Our Atmosphere. Pressure = Units of Pressure. Barometer. Chapter 10
Our Atmosphere The Gas Laws 99% N 2 and O 2 78% N 2 80 70 Nitrogen Chapter 10 21% O 2 1% CO 2 and the Noble Gases 60 50 40 Oxygen 30 20 10 0 Gas Carbon dioxide and Noble Gases Pressure Pressure = Force
More informationWriting and Balancing Chemical Equations
Name Writing and Balancing Chemical Equations Period When a substance undergoes a chemical reaction, chemical bonds are broken and new bonds are formed. This results in one or more new substances, often
More informationChemistry B11 Chapter 4 Chemical reactions
Chemistry B11 Chapter 4 Chemical reactions Chemical reactions are classified into five groups: A + B AB Synthesis reactions (Combination) H + O H O AB A + B Decomposition reactions (Analysis) NaCl Na +Cl
More informationChronic Fatigue Syndrome
256 Srp Arh Celok Lek. 2011 Mar-Apr;139(3-4):256-261 ПРЕГЛЕД ЛИТЕРАТУРЕ / REVIEW ARTICLE DOI: 10.2298/SARH1104256B Chronic Fatigue Syndrome Snežana Brkić, Slavica Tomić, Maja Ružić, Daniela Marić Hospital
More informationIMPORTANT INFORMATION: S for liquid water is 4.184 J/g degree C
FORM A is EXAM II, VERSION 2 (v2) Name 1. DO NOT TURN THIS PAGE UNTIL DIRECTED TO DO SO. 2. These tests are machine graded; therefore, be sure to use a No. 1 or 2 pencil for marking the answer sheets.
More informationChapter 17. How are acids different from bases? Acid Physical properties. Base. Explaining the difference in properties of acids and bases
Chapter 17 Acids and Bases How are acids different from bases? Acid Physical properties Base Physical properties Tastes sour Tastes bitter Feels slippery or slimy Chemical properties Chemical properties
More informationFormulas, Equations and Moles
Chapter 3 Formulas, Equations and Moles Interpreting Chemical Equations You can interpret a balanced chemical equation in many ways. On a microscopic level, two molecules of H 2 react with one molecule
More information1. Oblast rozvoj spolků a SU UK 1.1. Zvyšování kvalifikace Školení Zapojení do projektů Poradenství 1.2. Financování 1.2.1.
1. O b l a s t r o z v o j s p o l k a S U U K 1. 1. Z v y š o v á n í k v a l i f i k a c e Š k o l e n í o S t u d e n t s k á u n i e U n i v e r z i t y K a r l o v y ( d á l e j e n S U U K ) z í
More informationIB Chemistry. DP Chemistry Review
DP Chemistry Review Topic 1: Quantitative chemistry 1.1 The mole concept and Avogadro s constant Assessment statement Apply the mole concept to substances. Determine the number of particles and the amount
More informationMARI-ENGLISH DICTIONARY
MARI-ENGLISH DICTIONARY This project was funded by the Austrian Science Fund (FWF) 1, grant P22786-G20, and carried out at the Department of Finno-Ugric Studies 2 at the University of Vienna 3. Editors:
More informationFormulae, stoichiometry and the mole concept
3 Formulae, stoichiometry and the mole concept Content 3.1 Symbols, Formulae and Chemical equations 3.2 Concept of Relative Mass 3.3 Mole Concept and Stoichiometry Learning Outcomes Candidates should be
More informationYIELD YIELD REACTANTS PRODUCTS
Balancing Chemical Equations A Chemical Equation: is a representation of a chemical reaction in terms of chemical formulas Example: 1. Word Description of a Chemical Reaction When methane gas (CH 4 ) burns
More informationHow to Quickly Solve Spectrometry Problems
How to Quickly Solve Spectrometry Problems You should be looking for: Mass Spectrometry (MS) Chemical Formula DBE Infrared Spectroscopy (IR) Important Functional Groups o Alcohol O-H o Carboxylic Acid
More informationHonors Chemistry: Unit 6 Test Stoichiometry PRACTICE TEST ANSWER KEY Page 1. A chemical equation. (C-4.4)
Honors Chemistry: Unit 6 Test Stoichiometry PRACTICE TEST ANSWER KEY Page 1 1. 2. 3. 4. 5. 6. Question What is a symbolic representation of a chemical reaction? What 3 things (values) is a mole of a chemical
More informationLecture 22 The Acid-Base Character of Oxides and Hydroxides in Aqueous Solution
2P32 Principles of Inorganic Chemistry Dr. M. Pilkington Lecture 22 The Acid-Base Character of Oxides and Hydroxides in Aqueous Solution Oxides; acidic, basic, amphoteric Classification of oxides - oxide
More informationPeriodic Table, Valency and Formula
Periodic Table, Valency and Formula Origins of the Periodic Table Mendelѐѐv in 1869 proposed that a relationship existed between the chemical properties of elements and their atomic masses. He noticed
More informationWork hard. Be nice. Name: Period: Date: UNIT 1: Introduction to Matter Lesson 4: A Fine Line Between Compounds and Mixtures
Name: Period: Date: UNIT 1: Introduction to Matter Lesson 4: A Fine Line Between Compounds and Mixtures Do Now: PRE-READING OPEN-NOTES QUIZ! By the end of today, you will have an answer to: How do pure
More informationNET IONIC EQUATIONS. A balanced chemical equation can describe all chemical reactions, an example of such an equation is:
NET IONIC EQUATIONS A balanced chemical equation can describe all chemical reactions, an example of such an equation is: NaCl + AgNO 3 AgCl + NaNO 3 In this case, the simple formulas of the various reactants
More informationReaction Rates and Chemical Kinetics. Factors Affecting Reaction Rate [O 2. CHAPTER 13 Page 1
CHAPTER 13 Page 1 Reaction Rates and Chemical Kinetics Several factors affect the rate at which a reaction occurs. Some reactions are instantaneous while others are extremely slow. Whether a commercial
More informationReview - After School Matter Name: Review - After School Matter Tuesday, April 29, 2008
Name: Review - After School Matter Tuesday, April 29, 2008 1. Figure 1 The graph represents the relationship between temperature and time as heat was added uniformly to a substance starting at a solid
More informationFinal. Mark Scheme. Chemistry CHEM5. (Specification 2420) Unit 5: Energetics, Redox and Inorganic Chemistry
Version.2 General Certificate of Education (A-level) January 202 Chemistry CHEM5 (Specification 2420) Unit 5: Energetics, Redox and Inorganic Chemistry Final Mark Scheme Mark schemes are prepared by the
More informationFUNCTIONS OF THE MODAL VERBS IN ENGLISH (MODAL VERBS ANALOGIES IN THE RUSSIAN LANGUAGE) Сompiled by G.V. Kuzmina
FUNCTIONS OF THE MODAL VERBS IN ENGLISH (MODAL VERBS ANALOGIES IN THE RUSSIAN LANGUAGE) Сompiled by G.V. Kuzmina Москва Издательство Российского университета дружбы народов 2002 FUNCTIONS OF THE MODAL
More informationCalculating Atoms, Ions, or Molecules Using Moles
TEKS REVIEW 8B Calculating Atoms, Ions, or Molecules Using Moles TEKS 8B READINESS Use the mole concept to calculate the number of atoms, ions, or molecules in a sample TEKS_TXT of material. Vocabulary
More informationAP CHEMISTRY 2006 SCORING GUIDELINES
AP CHEMISTRY 2006 SCORING GUIDELINES Question 6 6. Answer each of the following in terms of principles of molecular behavior and chemical concepts. (a) The structures for glucose, C 6 H 12 O 6, and cyclohexane,
More informationAustin Peay State University Department of Chemistry CHEM 1021 TESTING FOR ORGANIC FUNCTIONAL GROUPS
TESTING FOR ORGANIC FUNCTIONAL GROUPS Caution: Chromic acid is hazardous as are many of the organic substances in today s experiment. Treat all unknowns with extreme care. Many organic substances are flammable.
More informationThe course of understanding British and American prose and poetry by future managers
4. Полат Е. С. Новые педагогические и информационные технологии в системе образования. М.: Просвещение, 2000. 5. Гальцова Н. П., Мезенцева Т. И., Швадленко И. А. Использование электронных информационно-образовательных
More informationUnit 9 Compounds Molecules
Unit 9 Compounds Molecules INTRODUCTION Compounds are the results of combinations of elements. These new substances have unique properties compared to the elements that make them up. Compounds are by far
More informationMoles. Moles. Moles. Moles. Balancing Eqns. Balancing. Balancing Eqns. Symbols Yields or Produces. Like a recipe:
Like a recipe: Balancing Eqns Reactants Products 2H 2 (g) + O 2 (g) 2H 2 O(l) coefficients subscripts Balancing Eqns Balancing Symbols (s) (l) (aq) (g) or Yields or Produces solid liquid (pure liquid)
More information@ Oxford Fajar Sdn. Bhd. (008974-T) 2012. Matter. 1.1 Atoms and Molecules 1.2 Mole Concept 1.3 Stoichiometry
1 Matter 1.1 Atoms and Molecules 1.2 Mole Concept 1.3 Stoichiometry 2 Chemistry for Matriculation Semester 1 1.1 Atoms and Molecules LEARNING OUTCOMES Describe proton, electron and neutron in terms of
More informationChemistry 12 Worksheet 1-1 - Measuring Reaction Rates
Chemistry 12 Worksheet 1-1 - Measuring Reaction Rates 1. A chemist wishes to determine the rate of reaction of zinc with hydrochloric acid. The equation for the reaction is: Zn (s) + 2HCl (aq) oh 2(g)
More informationThe Empirical Formula of a Compound
The Empirical Formula of a Compound Lab #5 Introduction A look at the mass relationships in chemistry reveals little order or sense. The ratio of the masses of the elements in a compound, while constant,
More informationFuture Trends in Airline Pricing, Yield. March 13, 2013
Future Trends in Airline Pricing, Yield Management, &AncillaryFees March 13, 2013 THE OPPORTUNITY IS NOW FOR CORPORATE TRAVEL MANAGEMENT BUT FIRST: YOU HAVE TO KNOCK DOWN BARRIERS! but it won t hurt much!
More informationMr. Bracken. Multiple Choice Review: Thermochemistry
Mr. Bracken AP Chemistry Name Period Multiple Choice Review: Thermochemistry 1. If this has a negative value for a process, then the process occurs spontaneously. 2. This is a measure of how the disorder
More information7. 1.00 atm = 760 torr = 760 mm Hg = 101.325 kpa = 14.70 psi. = 0.446 atm. = 0.993 atm. = 107 kpa 760 torr 1 atm 760 mm Hg = 790.
CHATER 3. The atmosphere is a homogeneous mixture (a solution) of gases.. Solids and liquids have essentially fixed volumes and are not able to be compressed easily. have volumes that depend on their conditions,
More informationThe Synthesis of trans-dichlorobis(ethylenediamine)cobalt(iii) Chloride
CHEM 122L General Chemistry Laboratory Revision 2.0 The Synthesis of trans-dichlorobis(ethylenediamine)cobalt(iii) Chloride To learn about Coordination Compounds and Complex Ions. To learn about Isomerism.
More informationBoyle s law - For calculating changes in pressure or volume: P 1 V 1 = P 2 V 2. Charles law - For calculating temperature or volume changes: V 1 T 1
Common Equations Used in Chemistry Equation for density: d= m v Converting F to C: C = ( F - 32) x 5 9 Converting C to F: F = C x 9 5 + 32 Converting C to K: K = ( C + 273.15) n x molar mass of element
More informationH 2O gas: molecules are very far apart
Non-Covalent Molecular Forces 2/27/06 3/1/06 How does this reaction occur: H 2 O (liquid) H 2 O (gas)? Add energy H 2O gas: molecules are very far apart H 2O liquid: bonding between molecules Use heat
More informationCh 20 Electrochemistry: the study of the relationships between electricity and chemical reactions.
Ch 20 Electrochemistry: the study of the relationships between electricity and chemical reactions. In electrochemical reactions, electrons are transferred from one species to another. Learning goals and
More informationChapter 2 Atoms and Molecules
Chapter 2 Atoms and Molecules 2-1 Elements and their symbols Most of the chemicals you find in everyday life can be broken down into simper substances Key Concepts: A substance that cannot be broken down
More informationGeneral Chemistry I (FC, 09-10) Lab #3: The Empirical Formula of a Compound. Introduction
General Chemistry I (FC, 09-10) Introduction A look at the mass relationships in chemistry reveals little order or sense. The ratio of the masses of the elements in a compound, while constant, does not
More informationChemical Calculations: The Mole Concept and Chemical Formulas. AW Atomic weight (mass of the atom of an element) was determined by relative weights.
1 Introduction to Chemistry Atomic Weights (Definitions) Chemical Calculations: The Mole Concept and Chemical Formulas AW Atomic weight (mass of the atom of an element) was determined by relative weights.
More informationCHEM6085: Density Functional Theory Lecture 2. Hamiltonian operators for molecules
CHEM6085: Density Functional Theory Lecture 2 Hamiltonian operators for molecules C.-K. Skylaris 1 The (time-independent) Schrödinger equation is an eigenvalue equation operator for property A eigenfunction
More informationChapter 11. Electrochemistry Oxidation and Reduction Reactions. Oxidation-Reduction Reactions. Oxidation-Reduction Reactions
Oxidation-Reduction Reactions Chapter 11 Electrochemistry Oxidation and Reduction Reactions An oxidation and reduction reaction occurs in both aqueous solutions and in reactions where substances are burned
More informationPhysical Changes and Chemical Reactions
Physical Changes and Chemical Reactions Gezahegn Chaka, Ph.D., and Sudha Madhugiri, Ph.D., Collin College Department of Chemistry Objectives Introduction To observe physical and chemical changes. To identify
More informationChapter 2: The Chemical Context of Life
Chapter 2: The Chemical Context of Life Name Period This chapter covers the basics that you may have learned in your chemistry class. Whether your teacher goes over this chapter, or assigns it for you
More informationOther Stoich Calculations A. mole mass (mass mole) calculations. GIVEN mol A x CE mol B. PT g A CE mol A MOLE MASS :
Chem. I Notes Ch. 12, part 2 Using Moles NOTE: Vocabulary terms are in boldface and underlined. Supporting details are in italics. 1 MOLE = 6.02 x 10 23 representative particles (representative particles
More information1332 CHAPTER 18 Sample Questions
1332 CHAPTER 18 Sample Questions Couple E 0 Couple E 0 Br 2 (l) + 2e 2Br (aq) +1.06 V AuCl 4 + 3e Au + 4Cl +1.00 V Ag + + e Ag +0.80 V Hg 2+ 2 + 2e 2 Hg +0.79 V Fe 3+ (aq) + e Fe 2+ (aq) +0.77 V Cu 2+
More informationDiscovering Electrochemical Cells
Discovering Electrochemical Cells Part I Electrolytic Cells Many important industrial processes PGCC CHM 102 Cell Construction e e power conductive medium What chemical species would be present in a vessel
More informationCambridge International Examinations Cambridge International Advanced Subsidiary and Advanced Level
Cambridge International Examinations Cambridge International Advanced Subsidiary and Advanced Level *0123456789* CHEMISTRY 9701/02 Paper 2 AS Level Structured Questions For Examination from 2016 SPECIMEN
More informationTERMINOLOGY OF KOGNITIVE LINGUISTICS: CONCEPTUAL SYSTEM AND CONCEPTUAL PICTURE OF THE WORLD
UDC 811.161.1' 1(082) M. V. PIMENOVA (Kemerovo, Russia) TERMINOLOGY OF KOGNITIVE LINGUISTICS: CONCEPTUAL SYSTEM AND CONCEPTUAL PICTURE OF THE WORLD The article deals with the determination of the terms
More informationK + Cl - Metal M. Zinc 1.0 M M(NO
Redox and Electrochemistry This section should be fresh in your minds because we just did this section in the text. Closely related to electrochemistry is redox chemistry. Count on at least one question
More informationAP Chemistry 2009 Free-Response Questions
AP Chemistry 009 Free-Response Questions The College Board The College Board is a not-for-profit membership association whose mission is to connect students to college success and opportunity. Founded
More informationOxidation of Cyclohexanol to Cyclohexanone
Reminder: These notes are meant to supplement, not replace, the laboratory manual. Oxidation of Cyclohexanol to Cyclohexanone History and Application: Oxidation reactions are incredibly important in the
More informationChapter 14. Chemical Kinetics
14.1 Factors that Affect Reaction Rates Chemical kinetics = the study of how fast chemical reactions occur. Factors which affect rates of reactions: Physical state of the reactants. Concentration of the
More informationChemistry Assessment Unit AS 1
Centre Number 71 Candidate Number ADVANCED SUBSIDIARY (AS) General Certificate of Education January 2011 Chemistry Assessment Unit AS 1 assessing Basic Concepts in Physical and Inorganic Chemistry [AC111]
More informationBalancing Reaction Equations Oxidation State Reduction-oxidation Reactions
Balancing Reaction Equations Oxidation State Reduction-oxidation Reactions OCN 623 Chemical Oceanography Balanced chemical reactions are the math of chemistry They show the relationship between the reactants
More informationInstructions Answer all questions in the spaces provided. Do all rough work in this book. Cross through any work you do not want to be marked.
GCSE CHEMISTRY Higher Tier Chemistry 1H H Specimen 2018 Time allowed: 1 hour 45 minutes Materials For this paper you must have: a ruler a calculator the periodic table (enclosed). Instructions Answer all
More informationPART I: MULTIPLE CHOICE (30 multiple choice questions. Each multiple choice question is worth 2 points)
CHEMISTRY 123-07 Midterm #1 Answer key October 14, 2010 Statistics: Average: 74 p (74%); Highest: 97 p (95%); Lowest: 33 p (33%) Number of students performing at or above average: 67 (57%) Number of students
More informationCambridge International Examinations Cambridge International General Certificate of Secondary Education
Cambridge International Examinations Cambridge International General Certificate of Secondary Education *0123456789* CHEMISTRY 0620/04 Paper 4 Theory (Extended) For Examination from 2016 SPECIMEN PAPER
More informationChemical Light Sources. Incoherent Light Sources Sylvia Bark SS 2013
Chemical Light Sources Incoherent Light Sources Content: Introduction History Chemiluminescence in nature and daily life Requirements General mechanism Most common reactions: - 1. Luminol - 2. Peroxyloxalat
More information