# ARITHMETIC AND GEOMETRIC PROGRESSIONS

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1 Arithmetic Ad Geometric Progressios Sequeces Ad ARITHMETIC AND GEOMETRIC PROGRESSIONS Successio of umbers of which oe umber is desigated as the first, other as the secod, aother as the third ad so o gives rise to what is called a sequece. Sequeces have wide applicatios. I this lesso we shall discuss particular types of sequeces called arithmetic sequece, geometric sequece ad also fid arithmetic mea (A.M), geometric mea (G.M) betwee two give umbers. We will also establish the relatio betwee A.M ad G.M. Let us cosider the followig problems : (a) A ma places a pair of ewly bor rabbits ito a warre ad wats to kow how may rabbits he would have over a certai period of time. A pair of rabbits will start producig offsprigs two moths after they were bor ad every followig moth oe ew pair of rabbits will appear. At the begiig the ma will have i his warre oly oe pair of rabbits, durig the secod moth he will have the same pair of rabbits, durig the third moth the umber of pairs of rabbits i the warre will grow to two; durig the fourth moth there will be three pairs of rabbits i the warre. Thus, the umber of pairs of rabbits i the cosecutive moths are :,,,, 5, 8,,... (b) The recurrig decimal 0. ca be writte as a sum (c) A ma ears Rs.0 o the first day, Rs. 0 o the secod day, Rs. 50 o the third day ad so o. The day to day earig of the ma may be writte as 0, 0, 50, 70, 90, We may ask what his earigs will be o the 0 th day i a specific moth. Agai let us cosider the followig sequeces: MATHEMATICS 405

3 Arithmetic Ad Geometric Progressios covert recurrig decimals to fractios usig G.P; isert G.M. betwee two umbers; ad establish relatioship betwee A.M. ad G.M. EXPECTED BACKGROUND KNOWLEDGE Laws of idices Simultaeous equatios with two ukows. Quadratic Equatios. Sequeces Ad. SEQUENCE A sequece is a collectio of umbers specified i a defiite order by some assiged law, whereby a defiite umber a of the set ca be associated with the correspodig positive iteger. The differet otatios used for a sequece are.. a, a, a,..., a,.... a,,,,.... {a } Let us cosider the followig sequeces :.,, 4, 8, 6,,...., 4, 9, 6, 5,...., 4, 4, 5, 4.,,, 4, 5, 6, I the above examples, the expressio for th term of the sequeces are as give below : () a () a () a + for all positive iteger. (4) a Also for the first problem i the itroductio, the terms ca be obtaied from the relatio a, a, a a + a, A fiite sequece has a fiite umber of terms. A ifiite sequece cotais a ifiite umber of terms.. ARITHMETIC PROGRESSION Let us cosider the followig examples of sequece, of umbers : (), 4, 6, 8, (),,, 5, MATHEMATICS 407

4 Sequeces Ad () 0, 8, 6, 4, (4) 5,,,,, Arithmetic Ad Geometric Progressios Note that i the above four sequeces of umbers, the first terms are respectively,, 0, ad. The first term has a importat role i this lesso. Also every followig term of the sequece has certai relatio with the first term. What is the relatio of the terms with the first term i Example ()? First term Secod term 4 + Third term 6 + Fourth term 8 + ad so o. The cosecutive terms i the above sequece are obtaied by addig to its precedig term. i.e., the differece betwee ay two cosecutive terms is the same. A fiite sequece of umbers with this property is called a arithmetic progressio. A sequece of umbers with fiite terms i which the differece betwee two cosecutive terms is the same o-zero umber is called the Arithmetic Progressio or simply A. P. The differece betwee two cosecutive terms is called the commo defferece of the A. P. ad is deoted by 'd'. I geeral, a A. P. whose first term is a ad commo differece is d is writte as a, a + d, a + d, a + d, Also we use t to deote the th term of the progressio... GENERAL TERM OF AN A. P. Let us cosider A. P. a, a + d, a + d, a + d, Here, first term (t ) a secod term (t ) a + d a + ( ) d, third term (t ) a + d a + ( ) d By observig the above patter, th term ca be writte as: t a + ( ) d Hece, if the first term ad the commo differece of a A. P. are kow the ay term of A. P. ca be determied by the above formula. Sometimes, the th term of a A. P. is expressed, i terms of, e.g. t. I that case, the 408 MATHEMATICS

5 Arithmetic Ad Geometric Progressios A. P. will be obtaied by substitutig,,, i the expressio. I this case, the terms of the A. P. are,, 5, 7, 9, Note.: (i) If the same o-zero umber is added to each term of a A. P. the resultig sequece is agai a A. P. (ii) If each term of a A. P. is multiplied by the same o-zero umber, the resultig sequece is agai a A. P. Sequeces Ad Example. Fid the 0 th term of the A. P.:, 4, 6,... Solutio : Here the first term (a) ad commo differece d 4 Usig the formula t a + ( ) d, we have t 0 + (0 ) Hece, the 0th term of the give A. P. is 0. Example. The 0 th term of a A. P. is 5 ad st term is 57, fid the 5 th term. Solutio : Let a be the first term ad d be the commo differece of the A. P. The from the formula: We have, t a + ( ) d, we have t 0 a + (0 ) d a + 9d t a + ( ) d a + 0 d a + 9d 5...() a + 0d 57...() Solve equatios () ad () to get the values of a ad d. Subtractig () from (), we have d d Agai from (), a 5 9d 5 9 ( ) Now t 5 a + (5 )d + 4 ( ) 5 Example. Which term of the A. P.: 5,, 7,... is 9? Solutio : Here a 5, d 5 6 MATHEMATICS 409

6 Sequeces Ad t 9 We kow that t a + ( ) d ( ) 6 Arithmetic Ad Geometric Progressios ( ) Therefore, 9 is the 0th term of the give A. P. Example.4 Is 600 a term of the A. P.:, 9, 6,...? Solutio : Here, a, ad d 9 7. Let 600 be the th term of the A. P. We have t + ( ) 7 Accordig to the questio, + ( ) ( ) or Sice is a fractio, it caot be a term of the give A. P. Hece, 600 is ot a term of the give A. P. Example.5 The commo differece of a A. P. is ad the 5 th term is 7. Fid the first term. Solutio : Here, d, t 5 7, ad 5 Let the first term be a. We have t a + ( ) d 7 a + (5 ) or, 7 a + 4 a 5 Thus, first term of the give A. P. is MATHEMATICS

7 Arithmetic Ad Geometric Progressios Example.6 If a + b + c 0 ad,, are also i A. P. b + c c + a a + b a b c b + c, c + a, a + b are. i A. P., the prove that Sequeces Ad Solutio. : Sice a b c b + c, c + a, a + b are i A. P., therefore or, b a c b c + a b + c a + b c + a F b I a c b HG c + a + K J F I HG b + c + K J F I HG a + b + K J F I HG c + a + K J or, a + b + c c + a a + b + c a b c + + b + c a + b a + b + c c + a or, c + a b + c a + b c + a (Sice a + b + c 0) or,,, are i A. P. b + c c + a a + b CHECK YOUR PROGRESS.. Fid the th term of each of the followig A. P s. : (a),, 5, 7, (b), 5, 7, 9,. If t +, the fid the A. P.. Which term of the A. P., 4, 5,... is? Fid also the 0 th term? 4. Is 9 a term of the A. P. 7, 4,,,...? 5. The m th term of a A. P. is ad the th term is m. Show that its (m + ) th term is zero. 6. Three umbers are i A. P. The differece betwee the first ad the last is 8 ad the product of these two is 0. Fid the umbers. 7. The th term of a sequece is a + b. Prove that the sequece is a A. P. with commo differece a. MATHEMATICS 4

8 Sequeces Ad Arithmetic Ad Geometric Progressios. TO FIND THE SUM OF FIRST TERMS IN AN A. P. Let a be the first term ad d be the commo differece of a A. P. Letl deote the last term, i.e., the th term of the A. P. The, Let l t a + ( )d S deote the sum of the first terms of the A. P. The S a + (a + d) + (a + d) (l d) + (l d) + l Reversig the order of terms i the R. H. S. of the above equatio, we have S l + (l d) + (l d) (a + d) + (a + d) + a Addig (ii) ad (ii) vertically, we get S (a + l) + (a + l) + (a + l) +... cotaiig terms (a + l)... (i)... (ii)... (iii) i.e., S a + l ( ) Also S a + d [ ( ) ] [From (i)] It is obvious that t S S Example.7 Fid the sum of terms. Solutio.: Here a, d 4 Usig the formula S a + d [ ( ) ], we get S + [ ( ) ] + + ( ) [ ] ( + ) Example.8 Fid the sum of the sequece,, 5, 9, 8, 5,,... to ( + ) terms Solutio. Let S deote the sum. The S ( + ) terms [ ( + ) terms] + [ terms] [ ( ) ] [ ( ) 6 ] 4 MATHEMATICS

9 Arithmetic Ad Geometric Progressios ( + ) ( + 4) Sequeces Ad [ 7 4 ] Example.9 The 5 th term of a A. P. is 69. Fid the sum of its 69 terms. Solutio. Let a be the first term ad d be the commo differece of the A. P. We have t 5 a + (5 ) d a + 4 d. a + 4 d (i) Now by the formula, S a + d [ ( ) ] We have S a d [ + ( 69 ) ] 69 (a + 4d) [usig (i)] Example.0 The first term of a A. P. is 0, the last term is 50. If the sum of all the terms is 480, fid the commo differece ad the umber of terms. Solutio : We have: a 0, l t 50, S 480. By substitutig the values of a, t ad S i the formulae S a + ( ) d ad t a+ ( ) d, we get ( ) d (i) ( ) d (ii) From (ii), ( ) d (iii) MATHEMATICS 4

10 Sequeces Ad From (i), we have 480(0 40) + usig (i) or, From (iii), Arithmetic Ad Geometric Progressios 40 8 d (as 6 5) 5 Example. Let the th term ad the sum of terms of a A. P. be p ad q respectively. q p Prove that its first term is. Solutio: I this case, t p ad S q Let a be the first term of the A. P. Now, S ( a + t ) or, () a + p q q or, a + p or, q a p q p a CHECK YOUR PROGRESS.. Fid the sum of the followig A. P s. (a) 8,, 4, 7, up to 5 terms (b) 8,,, 7,, up to terms.. How may terms of the A. P.: 7,, 9, 5,... have a sum 95?. A ma takes a iterest-free loa of Rs. 740 from his fried agreeig to repay i mothly 44 MATHEMATICS

13 Arithmetic Ad Geometric Progressios Sequeces Ad 60 The last A. M We have : : or, or, or, The umber of A. M's betwee 0 ad 80 is. Example.4 If x, y, z are i A. P., show that (x + y z) (y + z x) (z + x y) 4xy z Solutio : x,y, z are i A. P. y x + z (x + y z) (y + z x) (z + x y)...(i) (x + x + z z) (x + z + z x) (y y) [From (i)] (x) (z) (y) 4x yz. R. H. S. CHECK YOUR PROGRESS.. Prove that if the umber of terms of a A. P. is odd the the middle term is the A. M. betwee the first ad last terms.. Betwee 7 ad 85, m umber of arithmetic meas are iserted so that the ratio of (m ) th ad m th meas is : 4. Fid the value of m.. Prove that the sum of arithmetic meas betwee two umbers is times the sigle A. M. betwee them. 4. If the A. M. betwee p th ad q th terms of a A. P., be equal ad to the A. M. betwee r th ad s th terms of the A. P., the show that p + q r + s. MATHEMATICS 47

14 Sequeces Ad.5 GEOMETRICAL PROGRESSION Let us cosider the followig sequece of umbers : (),, 4, 8, 6, (),,, 9, 7 (),, 9, 7, (4) x, x, x, x 4, Arithmetic Ad Geometric Progressios If we see the patters of the terms of every sequece i the above examples each term is related to the leadig term by a defiite rule. For Example (), the first term is, the secod term is twice the first term, the third term is times of the leadig term. Agai for Example (), the first term is, the secod term is times of the first term, third term is times of the first term. A sequece with this property is called a gemetric progressio. A sequece of umbers i which the ratio of ay term to the term which immediately precedes is the same o zero umber (other tha), is called a geometric progressio or simply G. P. This ratio is called the commo ratio. Thus, Secod term Third term First term Secod term... is called the commo ratio of the geometric progressio. Examples () to (4) are geometric progressios with the first term,,,x ad with commo ratio,,, ad x respectively. The most geeral form of a G. P. with the first term a ad commo ratio r is a, ar, ar, ar, GENERAL TERM Let us cosider a geometric progressio with the first term a ad commo ratio r. The its terms are give by a, ar, ar, ar,... I this case, t a ar - t ar ar t ar ar t 4 ar ar 4 48 MATHEMATICS

15 Arithmetic Ad Geometric Progressios O geeralisatio, we get the expressio for the th term as Sequeces Ad t ar... (A).5. SOME PROPERTIES OF A G. P. (i) If all the terms of a G. P. are multiplied by the same o-zero quatity, the resultig series is also i G. P. The resultig G. P. has the same commo ratio as the origial oe. If a, b, c, d,... are i G. P. the ak, bk, ck, dk... are also i G. P. ( k 0) (ii) If all the terms of a G. P. are raised to the same power, the resultig series is also i G. P. Let a, b, c, d... are i G. P. the a k, b k, c k, d k,... are also i G. P. ( k 0) The commo ratio of the resultig G. P. will be obtaied by raisig the same power to the origial commo ratio. Example.5 Fid the 6 th term of the G. P.: 4, 8, 6,... Solutio : I this case the first term (a) 4 Commo ratio (r) 8 4 Now usig the formula t ar, we get t Hece, the 6 th term of the G. P. is 8. Example.6 The 4 th ad the 9 th term of a G. P. are 8 ad 56 respectively. Fid the G. P. Solutio : Let a be the first term ad r be the commo ratio of the G. P., the t 4 ar 4 ar t 9 ar 9 ar 8 Accordig to the questio, ar 8 56 () ad ar 8 () ar ar or r 5 5 r Agai from (),a 8 MATHEMATICS 49

16 Sequeces Ad 8 a 8 Therefore, the G. P. is,, 4, 8, 6,... Arithmetic Ad Geometric Progressios Example.7 Which term of the G. P.: 5, 0, 0, 40,... is 0? Solutio : I this case, a 5; r 0 5. Suppose that 0 is the th term of the G. P. By the formula,t ar, we get t 5. ( ) 5. ( ) 0 (Give) ( ) 64 ( ) Hece, 0 is the 7 th term of the G. P. Example.8 If a, b, c, ad d are i G. P., the show that (a + b), (b + c), ad (c + d) are also i G. P. Solutio. Sice a, b, c, ad d are i G. P., b c a b d c b ac, c bd, ad bc...() Now, (a + b) (c + d) ( )( ) a + b c + d (ac + bc + ad + bd) (b + c + bc)...[usig ()] ( b c) + ( c + d ) ( b + c) ( b + c) ( a + b) Thus, (a + b), (b + c), (c + d) are i G. P. 40 MATHEMATICS

17 Arithmetic Ad Geometric Progressios CHECK YOUR PROGRESS.4. The first term ad the commo ratio of a G. P. are respectively ad the first five terms.. Write dow. Which term of the G. P. series,, 4, 8, 6,... is 04? Is 50 a term of the G. P. series.?. Three umbers are i G. P. Their sum is 4 ad their product is 6. Fid the umbers i proper order. 4. The th term of a G. P. is for all. Fid (a) the first term (b) the commo ratio of the G. P..6 SUM OF TERMS OF A G. P. Let a deote the first term ad r the commo ratio of a G. P. Let S represet the sum of first terms of the G. P. Thus, S a + ar + ar ar + ar... () Multiplyig () byr, we get r S ar + ar ar + ar + ar... () Sequeces Ad () () S rs a ar or S ( r) a ( r ) S a r ( ) r...(a) a r ( )...(B) r Either (A) or (B) gives the sum up to the th term whe r. It is coveiet to use formula (A) whe r < ad (B) whe r >. Example.9 Fid the sum of the G. P.:,, 9, 7,... up to the 0 th term. Solutio : Here the first term (a) ad the commo ratio ( ) Now usig the formula, S.( ) 0 0 S 0 ( ) a r, r ( r >) we get r MATHEMATICS 4

18 Sequeces Ad Example.0 Fid the sum of the G. P.: Arithmetic Ad Geometric Progressios,,,,, 8 Solutio : Here, a ; r ad t l 8 Now t 8 ( ) ( ) ( ) ( ) 8 or S 0 ( ) 0 Example. Fid the sum of the G. P.: 0.6, 0.06, 0.006, , to terms. Solutio. Here, a ad r Usig the formula S a r ( ), we have [ r <] r S 0 Hece, the required sum is 0 F I HG K J. 4 MATHEMATICS

19 Arithmetic Ad Geometric Progressios Example. How may terms of the followig G. P.: 64,, 6, has the sum 7? Solutio : Here, a 64, r 64 (<) ad S 7 Usig the formula S S 64 R S T 64 a r ( ), we get r F I HG K J U V W F HG I K J U V R S T W (give) 55. Sequeces Ad or 55 8 or or F 8 F H G I K J HG I K J F H G I K J Thus, the required umber of terms is 8. Example. Fid the sum of the followig sequece :,,,... to terms. Solutio : Let S deote the sum. The S to terms ( to terms) 8 9 ( to terms) MATHEMATICS 4

20 Sequeces Ad {( ) ( ) ( ) to terms } ) 9 Arithmetic Ad Geometric Progressios {( to terms) ( to terms) } R( 0 ) U S 9 T 0 VW L0 9 N M O 9 9 QP [ is a G P with r 0<] ( ) Example. 4 Fid the sum up to terms of the sequece: 0.7, 0.77, 0.777, Solutio : Let S deote the sum, the S to terms 7( to terms) 7 9 ( to terms) 7 9 {( 0.) + ( 0.0) + ( 0.00) + to terms} 7 9 {( terms) ( to terms)} to terms R S T F HG 9 0 I K J U V W (Sice r < ) MATHEMATICS

21 Arithmetic Ad Geometric Progressios L NM O QP Sequeces Ad CHECK YOUR PROGRESS.5. Fid the sum of each of the followig G. P's : (a) 6,, 4,... to 0 terms (b),, 4, 8,... to 0 terms. 6. How may terms of the G. P. 8, 6,, 64, have their sum 884?. Show that the sum of the G. P. a + b l is bl a b a 4. Fid the sum of each of the followig sequeces up to terms. (a) 8, 88, 888,... (b) 0., 0., 0.,....7 INFINITE GEOMETRIC PROGRESSION So far, we have foud the sum of a fiite umber of terms of a G. P. We will ow lear to fid out the sum of ifiitely may terms of a G P such as.,, 4, 8, 6, We will proceed as follows: Here a, r. The th term of the G. P. is t ad sum to terms i.e., S <. So, o matter, how large may be, the sum of terms is ever more tha. MATHEMATICS 45

22 Sequeces Ad Arithmetic Ad Geometric Progressios So, if we take the sum of all the ifiitely may terms, we shall ot get more tha as aswer. Also ote that the recurrig decimal 0. is really i.e., 0. is actually the sum of the above ifiite sequece. O the other had it is at oce obvious that if we sum ifiitely may terms of the G. P.,, 4, 8, 6,... we shall get a fiite sum. So, sometimes we may be able to add the ifiitely may terms of G. P. ad sometimes are may ot. We shall discuss this questio ow..7. SUM OF INFINITE TERMS OF A G. P. Let us cosider a G. P. with ifiite umber of terms ad commo ratior. Case : We assume that r > The expressio for the sum of terms of the G. P. is the give by S a( r ) r a r a r r... (A) Now as becomes larger ad larger r also becomes larger ad larger. Thus, whe is ifiitely large ad r > the the sum is also ifiitely large which has o importace i Mathematics. We ow cosider the other possibility. Case : Let r < Formula (A) ca be writte as a ( r ) a ar S r r r Now as becomes ifiitely large, r becomes ifiitely small, i.e., as, r 0, the the above expressio for sum takes the form a S r Hece, the sum of a ifiite G. P. with the first terma ad commo ratio r is give by a S r, whe r <...(i) 46 MATHEMATICS

23 Arithmetic Ad Geometric Progressios Example.5 Fid the sum of the ifiite G. P. 4 8,,,, Solutio : Here, the first term of the ifiite G. P. is a, ad r 9. Sequeces Ad Here, r < Usig the formula for sum S a r we have S F H G I K J + 5 Hece, the sum of the give G. P. is 5. Example.6 Express the recurrig decimal 0. as a ifiite G. P. ad fid its value i ratioal form. Solutio The above is a ifiite G. P. with the first term a 0 ad Hece, by usig the formula S a, r we get r < Hece, the recurrig decimal 0.. MATHEMATICS 47

24 Sequeces Ad Arithmetic Ad Geometric Progressios Example.7 The distace travelled (i cm) by a simple pedulum i cosecutive secods are 6,, 9,... How much distace will it travel before comig to rest? Solutio : The distace travelled by the pedulum i cosecutive secods are, 6,, 9,... is a ifiite geometric progressio with the first terma 6 ad r Hece, usig the formula S a r we have < S Distace travelled by the pedulum is 64 cm. Example.8 The sum of a ifiite G. P. is ad sum of its first two terms is 8. Fid the first term. Solutio: I this problem S. Let a be the first term ad r be the commo ratio of the give ifiite G. P. The accordig to the questio. a + ar 8 or, () a + 8r... () Also from S a, r we have a r or, a () r... () From () ad (), we get.. ( r) ( + r) 8 8 or, r 9 48 MATHEMATICS

25 Arithmetic Ad Geometric Progressios or, r 9 Sequeces Ad or, r ± From (), a or 4 accordig as r ±. CHECK YOUR PROGRESS.6 () Fid the sum of each of the followig iifiite G. P's : (a) (b) Express the followig recurrig decimals as a ifiite G. P. ad the fid out their values as a ratioal umber. (a) 0.7 (b) 0.5. The sum of a ifiite G. P. is 5 ad the sum of the squares of the terms is 45. Fid the G.P. 4. The sum of a ifiite G. P. is ad the first term is. Fid the G.P. 4.8 GEOMETRIC MEAN (G. M.) If a, G, b are i G. P., the G is called the geometric mea betwee a ad b. If three umbers are i G. P., the middle oe is called the geometric mea betwee the other two. If a, G, G,..., G, b are i G. P., the G, G,... G are called G. M.'s betwee a ad b. The geometric mea of umbers is defied as the th root of their product. Thus if a, a,..., a are umbers, the their G. M. (a, a,... a ) Let G be the G. M. betwee a ad b, the a, G, b are i G. P. G b a G MATHEMATICS 49

26 b e t w e e t h e m. L e t a Sequeces Ad or, G ab or, G ab Arithmetic Ad Geometric Progressios Geometric mea Product of extremes Give ay two positive umbers a ad b, ay umber of geometric meas ca be iserted, a, a..., a be geometric meas betwee a ad b. The a, a, a,... a, b is a G. P. Thus, b beig the ( + ) th term, we have b a r + or, or, r + b a b r a + Hece, a ar a F H G I K J + b a a ar b a a + b a a ar a + Further we ca show that the product of these G. M.'s is equal to th power of the sigle geometric mea betwee a ad b. Multiplyig a. a,... a, we have b a, a a a a b a a MATHEMATICS

28 Sequeces Ad Arithmetic Ad Geometric Progressios If we itroduce betwee 4 ad 6 ad 08 betwe 6 ad 4, the umbers 4,, 6, 08, 4 form a G. P. The two ew umbers iserted are ad 08. Example. Fid the value of such that a a betwee a ad b. Solutio : If x be G. M. betwee a ad b, the + b + b + + may be the geometric mea x a b a a b + b a b + + or, a + b a b ( a + b ) or, + + a + b a b + a b or, a a. b a b b F HG I KJ + + or, a a b b a b + + or, a b F H G I KJ or, a b + + or, F ai HG b K J + a b F H G I K J or, 4 MATHEMATICS

31 Arithmetic Ad Geometric Progressios Also p ad q are two A. M.'s betwee a ad b a, p, q, b are i A. P. p a q p ad q p b q a p q ad b q p G ab (p q) (q p) Sequeces Ad Example.6 The product of first three terms of a G. P. is 000. If we add 6 to its secod term ad 7 to its rd term, the three terms form a A. P. Fid the terms of the G. P. a Solutio : Let t, t a ad t r ar be the first three terms of G. P. The, their product a r. a. ar 000 or, a 000, or, a 0 By the questio, t, t + 6, t + 7 are i A. P....() i.e. a, a + 6, ar + 7 are i A. P. r (a + 6) a r (ar + 7) (a + 6) or, a ( a + 6 ) + ( ar + 7 ) r or, 0 ( 0 + 6) + ( 0r + 7) r [usig ()] or, r r + 7r or, 0r 5r r 5 ± , 5 ± 5 0 Whe a 0, r. the the terms are 0, 0() i.e., 5, 0, 0 Whe a 0, r the the terms are 0(), 0, 0 F I HG K J i.e., 0, 0, 5 MATHEMATICS 45

33 Arithmetic Ad Geometric Progressios ( +) Sequeces Ad A arithmetic mea betwee a ad b is a + b. A sequece i which the ratio of two cosecutive terms is always costat ( 0) is called a Geometric Progressio (G. P.) The th term of a G. P.: a, ar, ar,... is ar Sum of the first terms of a G. P.: a, ar, ar,... is S a r ( ) r for r > a r ( ) for r < r The sums of a ifitite G. P. a, ar, ar,... is give by a S r for r < Geometric mea G betwee two umbers a ad b is a b The arithmetic mea A betwee two umbers a ad b is always greater tha the correspodig Geometric mea G i.e., A > G. SUPPORTIVE WEB SITES TERMINAL EXERCISE. Fid the sum of all the atural umbers betwee 00 ad 00 which are divisible by 7.. The sum of the first terms of two A. P.'s are i the ratio ( ) : ( + ). Fid the ratio of their 0 th terms.. If a, b, c are i A. P. the show that b + c, c + a, a + b are also i A. P. MATHEMATICS 47

34 Sequeces Ad 4. If a, a,..., a are i A. P., the prove that a a a a a a a a a a 4 5. If (b c), (c a), (a b) are i A. P., the prove that b c, c a, a b, are also i A. P. Arithmetic Ad Geometric Progressios 6. If the p th, q th ad r th terms are P, Q, R respectively. Prove that P (Q R) + Q (R P) + r (P Q) If a, b, c are i G. P. the prove that F I HG K J + + a b c + + a b c a b c 8. If a, b, c, d are i G. P., show that each of the followig form a G. P. : (a) (a b ), (b c ), (c d ) (b),, a + b b + c c d 9. If x, y, z are the p th, q th ad r th terms of a G. P., prove that x q r y r p z p q 0. If a, b, c are i A. P. ad x, y, z are i G. P. the prove that x b c y c a z a b. If the sum of the first terms of a G. P. is represeted by S, the prove that S (S S ) (S S ). If p, q, r are i A. P. the prove that the p th, q th ad r th terms of a G. P. are also i G. P.. If S , fid the least value of such that S < If the sum of the first terms of a G. P. is S ad the product of these terms isp ad the sum of their reciprocals is R, the prove that p S R F H G I K J 48 MATHEMATICS

35 Arithmetic Ad Geometric Progressios ANSWERS Sequeces Ad CHECK YOUR PROGRESS.. (a) (b) +., 5, 7, 9,.... 0, 6 4. o 5. m , 6,,... CHECK YOUR PROGRESS.. (a) 45 (b) , 9 6. a CHECK YOUR PROGRESS.. 5 CHECK YOUR PROGRESS. 4.,, 4, 8, 6. th, o. 6, 6, or, 6, 6 4. (a) 6 (b) CHECK YOUR PROGRESS.5. (a) 68 (b). 0. c h (b) 9 4. (a) F HG 0 F HG I K J 8 0 I K J MATHEMATICS 49

36 Sequeces Ad CHECK YOUR PROGRESS. 6. (a) (b) 4 Arithmetic Ad Geometric Progressios. (a) 7 9 (b) , , 9, 7, ,,,, CHECK YOUR PROGRESS.7. 4,,,,,,,, ,, 4 or,, , 8, 6 TERMINAL EXERCISE : MATHEMATICS

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