3_given a graph of current_voltage for a resistor, determine the resistance. Three resistance R1 = 1.0 kω, R2 = 1.5 kω, R3 = 2.


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1 Ohm s Law Objectives: 1_measure the current_voltage curve for a resistor 2_construct a graph of the data from objective 1 3_given a graph of current_voltage for a resistor, determine the resistance Equipment: Three resistance R1 = 1.0 kω, R2 = 1.5 kω, R3 = 2.2 kω One dc ammeter 0_10 ma, wires Theory: Potential difference is the work required to transfer electrical charge from one point to another, and measured in volt. The flow of electrical charge in a circuit is called current; current is measured in units of amperes. the relationship between current and voltage is an important characteristic that defines various electronic devices. the relationship is frequently shown with a graph, usually the voltage is controlled (the independent variable ), and the current is observed (the dependent variable). Fixed resistors have a straight line or linear current _voltage curve. This linear relationship illustrates the basic relationship of ohm s law. If passed in the current conductor, it generates a potential difference in this connector is directly proportional to the current flowing in it is called ohm s law.ohm s law is the most important law of electronics. it is written in equation form as : I = V/R Where I: current, V : voltage, R : resistance
2 Procedure: 1_ Measure three resistor with listed values of 1.0kΩ, 1.5kΩ, 2.2kΩ. The measured values is Component Listed value Measured value R1 1.0 kω 1.0 kω R2 1.5 kω 1.5 kω R3 2.2 kω 2.2 kω Table 5.1 2_ Connect the circuit shown in figure 5_1 (a). The ammeter is in series with the resistor and forms a single loop as shown in the protoboard wiring diagram in figure 5_1 (b). The voltmeter is in parallel with the resistor. 3_Connect the power supply for a voltage of 2.0 v. Read the current that is flowing through the resistor and record it in table 5_2. 4_Connect the power supply for 4.0 v and measure the current. Record the current in table 5_2. Continue taking current readings for each of the voltage listed in table 5_2. Vs = 2.0 v 3.0 v 4.0 v 8.0 v 10 v I = 2.04 ma 4.04 ma 6.04 ma 8.04 ma ma
3 Current (ma) Table 5.2 (R1) 5_ Replace R1 with R2 and repeat step 3 and 4. Record the data in table 5_3. Vs = 2.0 v 3.0 v 4.0 v 8.0 v 10 v I = 1.37 ma 2.7 ma 4.04 ma 5.37 ma 6.7 ma Table 5.3 (R2) 6_ Replace R2 with R3 and repeat step 3 and 4. Record the data in table 5_4. Vs = 2.0 v 3.0 v 4.0 v 8.0 v 10 v I= 0.93 ma 1.84 ma 2.75 ma 3.66 ma 4.56 ma Table 5.4 (R3) 7_ graph all three IV curves using the data from tables 5_2, 5_3, and 5_4. The dependent variable (current) on the yaxis and the independent variable (voltage) on the xaxis. 12 IV Curves for R Series Voltage (v)
4 Current (ma) Current (ma) 8 IV Curves for R Series Voltage (v) IV Curves for R Voltage (v) Series1 Conclusion: The relationship between voltage and current is that the voltage is directly proportional to the current. The relationship between the resistance and the current is that the resistance is inversely proportional to the Current.
5 The relationship between the resistance and the voltage is that the resistance is directly proportional to the current. Evaluation and Review Questions: 1_ the slope of a line is the change in the y direction divided by the change in the x direction. The definition for slope is illustrated in figure 5_2. Find the slope for each resistor on graph. For R1 = 1.0kΩ Slope = change in Y/change in x = ( ) / (42) = 1 For R2 =1.5kΩ Slope = ( ) / (42) = For R3 = 2.2kΩ Slope = ( ) / (42) = _ what happens to the slope of the IV curve for large resistors? The value of the slope for large resistors equals this is small value, and this shows the inverse proportionality between the resistance and the current. 3_ (a) If the resistance is halved and the voltage is not changed, what will happen to the current in a resistive circuit? I = V / 0.5 R I = 2V / R Current is increasing because it is inversely proportional to the resistance. (b) If the voltage is doubled and the resistance is not changed, what will happen to the current in a resistive circuit? I = 2V / R Current is increasing because it is directly proportional to the voltage.
6 4_ if the current in a resistive circuit is 24 ma and the applied voltage is 48 v, what is the resistance? R = V / I R = 48 / 24 = 2kΩ 5_ what current will flow through a 10Ω resistor with a 5.0 v applied? I = V / R I = 5/10 = 0.5 A
7 Power in Dc Circuits Objectives: 1_Determine the power in a variable resistor at various settings of resistance 2_plot data for power as a function of resistance. From the plot, determine when maximum power is delivered to the variable resistor Equipment: One 2.2 kω resistor One 10 kω resistor Theory: When current flows through a resistor, electrical energy is converted into heat. Heat is then radiated from the resistor. The rate that heat is dissipated is called power. Power is measured in units of joules per second (j/s), which defines the unit called the watt (W). The power dissipated by a resistor is given by the power law equation: P = V * I By applying ohm s law to the power, we get two equations for power. These are: P = I² * R and P= V² / R
8 Procedure: 1_ Measure the resistance of R1.the color code value is 2.2kΩ. R1 = 2.2kΩ. 2_ Construct the circuit shown in figure 6_1. R2 is a 10 kω potentiometer. Connect the center (variable) terminal to one of the outside terminals. Connect the potentiometer for 0.5 kω. Always remove power when measuring resistance and make certain you are measuring only the potentiometer resistance. 3_Measure the voltage across R1 and the voltage across R2. Enter the measured voltages in table 6_1. As a check, make sure that the sum of V1 and V2 is equal to 12 v. then compute the power in R2 using the equations: P2 = V2 2 / R2 4_ disconnect the power supply and set R2 to the next value shown in table 6_1. Reconnect the power supply and repeat the measurements made in step 2. Continue in this manner for each of the resistance settings in table 6_1. Table 6_1 Variable resistance setting R2 V1 (Measured) V2 (Measured) Power in R2 : P2 = V2 2 / R2 0.5 kω v 2.23 v mw 1.0 kω v 3.76 v mw 2.0 kω v 5.73 v mw 2.2 kω v 6.02 v mw 3.0 kω v 6.94 v mw 4.0 kω v 7.76 v mw 5.0 kω v 8.35 v mw 7.5 kω v 9.29 v mw 10 kω v 9.85 v mw
9 Power(mW) 5_ graph the relationship of the power as a function of resistance R2. Since resistance is the independent variable. Plot it long the xaxis and plot power along the yaxis. An implied data dissipated R2 without resistance. The Relationship b/w power and resistance resistance (kω) Series1 Conclusion: Power: Is the time rate of flow of electrical energy in an electrical circuit, and the unit is measured in watts. P = V 2 / R, If the voltage is constant inverse relationship between power and resistance. P = I 2 R, But if the current is constant in the relationship, then power is directly proportional to the resistance. Evaluation and Review Questions: 1_ observe the graph of resistance versus power for your experiment. Compare the resistance R1 and R2 when power in R2 is a maximum. The power maximum equals 16.47mW, when R2 = R1 2_ what was happening to the total current in the circuit as R2 was increasing? The total current decreases.
10 3_what was happening to the power in R1 as the resistance of R2 was increasing? Explain your answer Variable resistance V1 P1 = V1 2 /R1 setting R2 (Measured) 0.5 kω v mw 1.0 kω v mw 2.0 kω v mw 2.2 kω v mw 3.0 kω v mw 4.0 kω v mw 5.0 kω v mw 7.5 kω v mw 10 kω v mw The power in R1 drop when the resistance of R2 was increasing 4_ A 1.5 kω resistor is found to have 22.5 V across it. (a)what is the current in the resistor? I = V / R I = 22.5 / 1.5 =15 ma (b) What is the power dissipated in the resistor? P = V* I P =22.5 * 15 =337.5 mw 5_ what physical characteristic the power rating of a resistor? 1_P = V 2 / R, If the voltage is constant inverse relationship between power and resistance.
11 Current 1 (ma) 2_P = I 2 R, But if the current is constant in the relationship, then power is directly proportional to the resistance. For further Investigation: R1 = 2.2 kω V1 I1 = V1 / R1 (Measured) v ma v ma v ma v ma v ma v ma v ma v ma v ma R2 (kω) Series1
12 V2 (v) Series R2 (kω)
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