Section 0.4 Inverse Trigonometric Functions

Transcription

1 Section 0.4 Inverse Trigonometric Functions Short Recall from Trigonometry Definition: A function f is periodic of period T if f(x + T ) = f(x) for all x such that x and x+t are in the domain of f. The smallest such number T > 0 is called the fundamental period. Example y = sin x is a periodic function with fundamental period (or just period) π. sin(x + π) = sin x cos π + cos x sin π = sin x The graph of y = sin x below is obtained by plotting points for 0 x π then using the periodic nature of the function to complete the graph. Note that the domain of y = sin x is (, ) i.e. all reals and range of f is the closed interval [, ]. (Also recall sin x = 0 if x = nπ where n is an integer) Out[4]= 3 3 Figure : y=sin x

2 Example y = cos x is a periodic function with fundamental period (or just period) π. cos(x + π) = cos x cos π sin x sin π = cos x The graph of y = cos x below is also obtained by plotting points for one period (could be for 0 x π or π x π ) then using the periodic nature of the function to complete the graph. Note that the domain of y = cos x is also (, ) i.e all reals and range of f is the closed interval [, ]. (Also recall cos x = 0 if x = nπ/ where n is an odd integer) Out[5]= 3 3 Figure : y=cos x The graph of the remaining four trig functions are shown at the end of these lecture notes and their domains can be written directly looking at their graphs. Notice also that tangent and cotangent have range (, ), where as cosecant and secant have range (, ] [, ). All four functions are periodic: tangent and cotangent have period π whereas cosecant and secant have period π. Inverse Trigonometric Functions When we try to find the the inverse of the trig. functions we have slight difficulty they are not -. The solution out of this problem is to restrict the domain of these functions so that they become one to one. For an example apply the horizontal line test to the graph of y = sin x above. But the function f(x) = y = sin x for π/ x π/ is -.

3 3 The inverse function of this restricted sine function f exits and is denoted by sin or arcsin. It is called the inverse sine function or the arcsine function. Using what we learnt about graphing the inverse functions we can obtain the graph of sin x, reflect the graph with respect to the y = x line to get

4 4 Out[7]= Note that sin x : [ π/, π/] [, ] and arcsin x : [, ] [ π/, π/]. Since the definition of an inverse function says that so we have f (x) = y f(y) = x sin x = y sin y = x and π y π or sin(sin x) = x for x [, ] and sin (sin x) = x for x [ π/, π/] Warning Example sin (sin π) = sin (0) = 0. π is not in the domain of arcsin so not ending up with π is not a surprise. Example Evaluate sin ( 3 ) By the definition of sin we want an angle θ [ π/, π/] where sin θ = so θ = π 3. 3 Example Evaluate sin ( Find θ s.t sin θ = π so θ = 6 ) Example Find the domain of f(x) for f(x) = sin ( x ). Domain of arcsin is [, ] so we are interested in those real numbers x such that x. And this inequality is satisfied if x (, ] [, ). So Domain of f=(, ] [, ) Example Find the inverse of y = cos x. Cosine is, like sine, not - so we cannot find the inverse of it unless we restrict our domain. We will restrict our domain to be [0, π]. As you can check from the graph of cos x is

5 5 - on this interval hence invertible. The inverse cosine function cos or arccos is defined as: y = cos x iff cos y = x and 0 y π So cos x has domain [, ] and range [0, π]. The below graph shows the process of reflecting the graph of y = cos x about the y = x line. Out[6]= so the graph of y = arccos x is Out[3]= Example Evaluate arccos( ) We need to find the angle 0 θ π where cos θ =. Since cosine of our angle is negative we expect our angle to be in the nd quadrant hence θ = 3π/4 or arccos( ) = 3π/4. Example Find the inverse of y = tan x. As in the cases of sine and cosine we need to restrict the domain of tangent to find its inverse. And we will restrict the domain of tan x to the interval ( π/, π/) where it is -. Range of tan x on this domain is all R. The inverse of tangent function tan or arctan is defined just like in the cases of sine and cosine. Domain

6 6 of arctan x is all R and range is ( π/, π/). And the graph of y = arctan x is: Out[5]= Remark: Note that this is an example of a function with two different horizontal asymptotes. Think of the horizontal asymptotes for the time being the horizontal lines with which graph of y = arctan x becomes snug in the long run (as x becoming larger and larger or smaller and smaller.). Judging our graph based on this rough definition you can say that arctan x becomes snug with y = π/ line as x becomes smaller and smaller and it becomes snug with the y = π/ line as x becomes larger and larger. Example Simplify the expression cos(tan (x)) Let y = tan x then x = tan y where π/ < y < π/. Construct the triangle with angle y, and whose hypotenuse is + x and x = tan y. From here you can easily read cos(tan (x)) = cos y = +x Rest of the inverses y = cot x(x R) cot y = x and y (0, π) y = sec x( x ) sec y = x and y [0, π/) [π, 3π/) y = csc x( x ) csc y = x and y [0, π/) [π, 3π/) Last graph I ll provide will be for sec x below you should try out the other two yourself.

7 7 Out[9]= Pictorial hint for finding the inverse: The way to find the graph of the inverse function is to rotate your paper (which has the graph on it) by π degrees around the main diagonal (the line through the origin at angle π/4 counterclockwise from the x axis.) You will then find that you have to look through your paper at the function but that can usually be done and if you start with the graph of f you are looking at the graph of the inverse function to f.

8 8 Out[6]= 3 3 Figure 3: y=tan x Out[8]= 3 3 Figure 4: y=cot x Out[9]= 3 3 Figure 5: y=sec x Out[0]= 3 3