25 ppb diluted 5 ml in 100 ml 500 ppb undiluted 5.00 x 10-5 g in g = %

Save this PDF as:
 WORD  PNG  TXT  JPG

Size: px
Start display at page:

Download "25 ppb diluted 5 ml in 100 ml 500 ppb undiluted 5.00 x 10-5 g in g = %"

Transcription

1 1. If a solution is determined to be 25 ppb magnesium and this was formed by dissolving g of an unknown solid into 100 ml and then diluting 5 ml of that solution into a 100 ml volumetric flask. What was the concentration of magnesium in the original solid. 25 ppb diluted 5 ml in 100 ml 500 ppb undiluted 5.00 x 10-5 g in g = % 2. If a solution is determined to be 1.56 ppm sodium and this was formed by taking a 5 ml aliquot of river water and diluting to 100 ml. What would the concentration of the water sample be in mg/l? If all the sodium originated from sodium chloride, what would the concentration of NaCl be in mg/l? in mol/l? 1.56 ppm diluted by 5mL in 100 ml ( a 20 times dilution, therefore) 31.2 ppm undiluted or 3.12 x 10-3 g in 100 ml = 31.2 mg/l Na Na g/mol = mol of NaCl g/mol 79.3 mg/l NaCl

2 3. A river water and a tap water sample are analyzed for Nitrate (NO 3 - ) and Nitrite (NO 2 - ) by analyzing a colored complex of Nitrite (NO 2 - ). A series of Nitrate standards were prepared and then converted to Nitrite by passing them through a cadmium column. The concentration and absorbance of the corresponding colored complex of these standards is presented in the table below. The calibration curve below was also generated from this data. Analogous measurements on the river water and tap water are also presented below. Determine the concentration of Nitrate (NO 3 - ) and Nitrite (NO 2 - ) in the samples. Conc. Of NO nm nm River Water Through Cd column River Untreated by Cd Tap Water Through Cd column Tap Water Untreated by Cd Absorbance y = x R 2 = Conc. (mg/l) From Equation of Line: X = (Y-Intercept)/Slope Sample Type Absorption X calc River Water through Cd Column River Water untreated by Cd Tap Water through Cd Column Tap Water untreated by Cd Slope Intercept River NO ppm River NO ppm Tap NO ppm tapno ppm

3 4a) Determine the hydroxide concentration [OH-] in Molarity of a solution of Calcium Hydroxide that made by dissolving solid Calcium Hydroxide into deionized water if the calcium concentration is determined to be 100 ppm. b) what would the ph of this solution be? 100 ppm Ca g/l Ca g/mol Ca mol/l Ca 2 mol OH- per 1 mol Ca in Ca(OH) 2 5.0E-03 mol/l OH 2.30 poh ph 5. A solution is made up by dissolving grams of MgBr 2 and g of KBr in 100 ml of deionized water. If 10 ml of this solution is placed into a column containing an ion exchange resin, how many moles of H + will be displaced? (Hint: one H + is displaced by a +1 charged cation, 2 H + by a +2 charged cation). If the displaced acid is collected in a beaker, how many mls of M NaOH would be required to neutralize the solution? g MgBr g/mol MgBr mol 100 ml 1.17E-02 mol/l MgBr E-02 mol/l Mg g KBr 119 g/mol KBr mol 100 ml 1.68E-02 mol/l K 1.68E-02 mol/l K + 10 ml 1.17E-04 mol Mg +2 1 mol Mg +2 = 2 mol H E-04 mol H + Displaced Mg ml 1.68E-04 mol K + 1 mol K + = 1 mol H E-04 mol H + Displaced K E-04 mol H + Displaced Mg +2 and K mol/l NaOH ml NaOH required

4 6) Typical seawater contains 2.7 grams of salt (sodium chloride, NaCl) for every 100 ml. Given this, what is the molarity of NaCl in the ocean? (6b) MgCl 2 has a concentration of M in the ocean. How many grams of MgCl 2 are present in 25 ml of seawater? SOLUTION The molecular weight of NaCl is (Na) (Cl) = g/mol. The moles of salt in 2.7 g are (2.7 g)/(58.44 g/mol) = mol, so the molarity is; [NaCl] = (0.046 mol)/(0.100) = 0.46 M Note: Significant Figures in 100 ml ambiguous, also could be 0.5 M SOLUTION (6b) The molecular weight of MgCl 2 is ( (35.45)=) g/mol. The number of grams in 25 ml is therefore; mol/liter x g/mol x Liter = g = 0.13 grams 7) Find the Molarity and Molality of 37.0 wt % HCl. The density of this solution is given as 1.19 g/ml. SOLUTION Molarity is the # moles/liter need to find the number of moles Mass of one Liter of solution = 1.19 g/ml x 1000 ml = 1190 g Mass of HCl = 1190 (g Solution)/Liter x (g HCl)/(g Solution) = 440 (g HCl)/Liter Mol. Wt. HCl = g/mol (440 g/liter) (36.46 g/mol) = 12.1 mol/liter = 12.1 M In g of solution there are 37.0 g HCl and 63.0 g of H 2 O (37.0 g (36.46 g/mol)) (0.063 kg H 2 O) = Molality = 16.1 m

5 8) Cupric Sulfate pentahydrate (CuSO 4 5H 2 O) with a molecular weight of g/mol is used to prepare a 500 ml solution of 8.00 mm Cu +2. How many grams of Cupric Sulfate pentahydrate are required? SOLUTION: The number of moles of 8.00 mm Cu +2 in 500 mls are; 8.00 x 10-3 mole/l x L = 4.00 x 10-3 mol Cu +2 required 4.00 x 10-3 mol x g/mol = grams required 9) How many grams of MgCl 2 (95.20 g/mol) are required top make a 500 ml solution of 8.00 mm Cl -? Answer: grams from 2.00 x 10-3 mol of MgCl 2 10) What would be the procedure used to make the solution specified by 8? What would be the procedure used to make the solution specified by 8? Using a clean 500 ml volumetric flask, add g of CuSO 4 5H 2 O followed by ~300 to 400 ml distilled H 2 O. Swirl to dissolve reagent, then dilute to mark. Invert covered flask approximately 20 times to ensure well mixed.

Calculation of Molar Masses. Molar Mass. Solutions. Solutions

Calculation of Molar Masses. Molar Mass. Solutions. Solutions Molar Mass Molar mass = Mass in grams of one mole of any element, numerically equal to its atomic weight Molar mass of molecules can be determined from the chemical formula and molar masses of elements

More information

Tutorial 4 SOLUTION STOICHIOMETRY. Solution stoichiometry calculations involve chemical reactions taking place in solution.

Tutorial 4 SOLUTION STOICHIOMETRY. Solution stoichiometry calculations involve chemical reactions taking place in solution. T-27 Tutorial 4 SOLUTION STOICHIOMETRY Solution stoichiometry calculations involve chemical reactions taking place in solution. Of the various methods of expressing solution concentration the most convenient

More information

) g /mol = 3.86!10"3 moles

) g /mol = 3.86!103 moles Chem01, Winter 006 Midterm N1 01/6/06 Name Answer key SID 1. A solution is prepared by dissolving 5.8 grams on magnesium chloride (MgCl ) in water to produce 50.0 ml of solution. Molecular weight of the

More information

Chapter 4. Chemical Composition. Chapter 4 Topics H 2 S. 4.1 Mole Quantities. The Mole Scale. Molar Mass The Mass of 1 Mole

Chapter 4. Chemical Composition. Chapter 4 Topics H 2 S. 4.1 Mole Quantities. The Mole Scale. Molar Mass The Mass of 1 Mole Chapter 4 Chemical Composition Chapter 4 Topics 1. Mole Quantities 2. Moles, Masses, and Particles 3. Determining Empirical Formulas 4. Chemical Composition of Solutions Copyright The McGraw-Hill Companies,

More information

The component present in larger proportion is known as solvent.

The component present in larger proportion is known as solvent. 40 Engineering Chemistry and Environmental Studies 2 SOLUTIONS 2. DEFINITION OF SOLUTION, SOLVENT AND SOLUTE When a small amount of sugar (solute) is mixed with water, sugar uniformally dissolves in water

More information

Four common concentration units 1. Molarity 2. Weight Percent (Wt %), ppm, ppb 3. Molality 4. Mole Fraction. Molarity, M =

Four common concentration units 1. Molarity 2. Weight Percent (Wt %), ppm, ppb 3. Molality 4. Mole Fraction. Molarity, M = Four common concentration units 1. Molarity 2. Weight Percent (Wt %), ppm, ppb 3. Molality 4. Mole Fraction Molarity, M tells you how many s of solute are present in every liter of solution (solute-to-solution)

More information

Solutions for Simple ph and concentration calculation problems

Solutions for Simple ph and concentration calculation problems Revision: Solutions for Simple ph and concentration calculation problems 1. hat is the mass of a 51.6 ml sample of gasoline, which has a density of 0.70 g/cm? ρ (density) = m (mass), from this m = ρ V

More information

1. Read P. 368-375, P. 382-387 & P. 429-436; P. 375 # 1-11 & P. 389 # 1,7,9,12,15; P. 436 #1, 7, 8, 11

1. Read P. 368-375, P. 382-387 & P. 429-436; P. 375 # 1-11 & P. 389 # 1,7,9,12,15; P. 436 #1, 7, 8, 11 SCH3U- R.H.KING ACADEMY SOLUTION & ACID/BASE WORKSHEET Name: The importance of water - MAKING CONNECTION READING 1. Read P. 368-375, P. 382-387 & P. 429-436; P. 375 # 1-11 & P. 389 # 1,7,9,12,15; P. 436

More information

n molarity = M = N.B.: n = litres (solution)

n molarity = M = N.B.: n = litres (solution) 1. CONCENTRATION UNITS A solution is a homogeneous mixture of two or more chemical substances. If we have a solution made from a solid and a liquid, we say that the solid is dissolved in the liquid and

More information

Name: Class: Date: 2 4 (aq)

Name: Class: Date: 2 4 (aq) Name: Class: Date: Unit 4 Practice Test Multiple Choice Identify the choice that best completes the statement or answers the question. 1) The balanced molecular equation for complete neutralization of

More information

Formulas, Equations and Moles

Formulas, Equations and Moles Chapter 3 Formulas, Equations and Moles Interpreting Chemical Equations You can interpret a balanced chemical equation in many ways. On a microscopic level, two molecules of H 2 react with one molecule

More information

SOLUTIONS AND SOLUBILITY

SOLUTIONS AND SOLUBILITY Molarity is simply a measure of the "strength" of a solution. A solution that we would call "strong" would have a higher molarity than one that we would call "weak". The unit for molarity is M and is read

More information

Solution a homogeneous mixture = A solvent + solute(s) Aqueous solution water is the solvent

Solution a homogeneous mixture = A solvent + solute(s) Aqueous solution water is the solvent Solution a homogeneous mixture = A solvent + solute(s) Aqueous solution water is the solvent Water a polar solvent: dissolves most ionic compounds as well as many molecular compounds Aqueous solution:

More information

Phenolphthalein-NaOH Kinetics

Phenolphthalein-NaOH Kinetics Phenolphthalein-NaOH Kinetics Phenolphthalein is one of the most common acid-base indicators used to determine the end point in acid-base titrations. It is also the active ingredient in some laxatives.

More information

CH302 Exam 4 Practice Problems (buffers, titrations, Ksp)

CH302 Exam 4 Practice Problems (buffers, titrations, Ksp) CH302 Exam 4 Practice Problems (buffers, titrations, Ksp) 1 Equilibrium Constants The following equilibrium constants will be useful for some of the problems. Substance Constant Substance Constant HCO

More information

2 Stoichiometry: Chemical Arithmetic Formula Conventions (1 of 24) 2 Stoichiometry: Chemical Arithmetic Stoichiometry Terms (2 of 24)

2 Stoichiometry: Chemical Arithmetic Formula Conventions (1 of 24) 2 Stoichiometry: Chemical Arithmetic Stoichiometry Terms (2 of 24) Formula Conventions (1 of 24) Superscripts used to show the charges on ions Mg 2+ the 2 means a 2+ charge (lost 2 electrons) Subscripts used to show numbers of atoms in a formula unit H 2 SO 4 two H s,

More information

Calcium Analysis by EDTA Titration

Calcium Analysis by EDTA Titration Calcium Analysis by EDTA Titration ne of the factors that establish the quality of a water supply is its degree of hardness. The hardness of water is defined in terms of its content of calcium and magnesium

More information

Unit 2: Quantities in Chemistry

Unit 2: Quantities in Chemistry Mass, Moles, & Molar Mass Relative quantities of isotopes in a natural occurring element (%) E.g. Carbon has 2 isotopes C-12 and C-13. Of Carbon s two isotopes, there is 98.9% C-12 and 11.1% C-13. Find

More information

Module Seven Including Liquids and Solutions in Stoichiometric Calculations. Chem 170. Stoichiometric Calculations. Module Seven

Module Seven Including Liquids and Solutions in Stoichiometric Calculations. Chem 170. Stoichiometric Calculations. Module Seven Chem 170 Stoichiometric Calculations Module Seven Including Liquids and Solutions in Stoichiometric Calculations DePauw University Department of Chemistry and Biochemistry Page 1 Introduction to Module

More information

0.279 M Change g to mol: g/mol = mol Molarity = mol L = mol 0.325L = M

0.279 M Change g to mol: g/mol = mol Molarity = mol L = mol 0.325L = M 118 ChemQuest 39 Name: Date: Hour: Information: Molarity Concentration is a term that describes the amount of solute that is dissolved in a solution. Concentrated solutions contain a lot of dissolved solute,

More information

Stoichiometry. Lecture Examples Answer Key

Stoichiometry. Lecture Examples Answer Key Stoichiometry Lecture Examples Answer Key Ex. 1 Balance the following chemical equations: 3 NaBr + 1 H 3 PO 4 3 HBr + 1 Na 3 PO 4 2 C 3 H 5 N 3 O 9 6 CO 2 + 3 N 2 + 5 H 2 O + 9 O 2 2 Ca(OH) 2 + 2 SO 2

More information

Lab #10 How much Acetic Acid (%) is in Vinegar?

Lab #10 How much Acetic Acid (%) is in Vinegar? Lab #10 How much Acetic Acid (%) is in Vinegar? SAMPLE CALCULATIONS NEED TO BE DONE BEFORE LAB MEETS!!!! Purpose: You will determine the amount of acetic acid in white vinegar (sold in grocery stores)

More information

UNITS OF CONCENTRATION

UNITS OF CONCENTRATION UNITS OF CONCENTRATION There are a number of different ways of expressing solute concentration that are commonly used. Some of these are listed below. Molarity, M = moles solute/liter of solution Normality,

More information

Chemistry Ch 15 (Solutions) Study Guide Introduction

Chemistry Ch 15 (Solutions) Study Guide Introduction Chemistry Ch 15 (Solutions) Study Guide Introduction Name: Note: a word marked (?) is a vocabulary word you should know the meaning of. A homogeneous (?) mixture, or, is a mixture in which the individual

More information

Factors that Affect the Rate of Dissolving and Solubility

Factors that Affect the Rate of Dissolving and Solubility Dissolving Factors that Affect the Rate of Dissolving and Solubility One very important property of a solution is the rate of, or how quickly a solute dissolves in a solvent. When dissolving occurs, there

More information

Solutions: Molarity. A. Introduction

Solutions: Molarity. A. Introduction Solutions: Molarity. A. Introduction... 1 B. Molarity... 1 C. Making molar solutions... 2 D. Using molar solutions... 4 E. Other mole-based concentration units [optional]... 6 F. Answers... 7 A. Introduction

More information

9. The molar mass of hydrazine is 32 g/mol and its empirical formula is NH 2. What is its molecular formula?

9. The molar mass of hydrazine is 32 g/mol and its empirical formula is NH 2. What is its molecular formula? Dr. Rogers Solutions Homework 1. Give the name for the following compounds and state whether they are ionic or not A. Ba(NO 3 ) 2 B. NaH C. PCl 5 D. CO E. NH 4 OH F. Ca(MnO 4 ) 2 G. N 2 O 4 H. NaHSO 4

More information

Chemical calculations

Chemical calculations Chemical calculations Stoichiometry refers to the quantities of material which react according to a balanced chemical equation. Compounds are formed when atoms combine in fixed proportions. E.g. 2Mg +

More information

CHEM 201. Quantitative Analysis CHEM 201. Course Objectives. What do you need? Textbook (bcs.whfreeman.com/qca7e)

CHEM 201. Quantitative Analysis CHEM 201. Course Objectives. What do you need? Textbook (bcs.whfreeman.com/qca7e) CHEM 201 Lecture Laboratory CHEM 201 01: T,Th: 11:40 a.m. 12:55 p.m., SH-C136 02: T,Th 8:00 10:50 a.m., PS 824 (Dr. Santillan) 03: T,Th 1:30 4:20 p.m., PS 824 (Dr. Wen) Quantitative Analysis Lecture &

More information

HOW TO MAKE STANDARD SOLUTIONS FOR CHEMISTRY

HOW TO MAKE STANDARD SOLUTIONS FOR CHEMISTRY HOW TO MAKE STANDARD SOLUTIONS FOR CHEMISTRY Phillip Bigelow Chemists make two common types of "standard solutions": Molar solutions Normal solutions Both of these solutions are concentrations (or strengths

More information

From the book (10, 12, 16, 18, 22, 24 52, 54, 56, 58, 62, 64, 66, 68, 74, 76, 78, 80, 82, 86, 88, 90, 92, 106 and 116)

From the book (10, 12, 16, 18, 22, 24 52, 54, 56, 58, 62, 64, 66, 68, 74, 76, 78, 80, 82, 86, 88, 90, 92, 106 and 116) Chem 112 Solutions From the book (10, 12, 16, 18, 22, 24 52, 54, 56, 58, 62, 64, 66, 68, 74, 76, 78, 80, 82, 86, 88, 90, 92, 106 and 116) 1. Which of the following compounds are nonelectrolytes? A. NaF

More information

Cadmium Reduction Method Method 8039 0.3 to 30.0 mg/l NO 3 N (HR) Powder Pillows or AccuVac Ampuls

Cadmium Reduction Method Method 8039 0.3 to 30.0 mg/l NO 3 N (HR) Powder Pillows or AccuVac Ampuls Nitrate DOC316.53.01066 Cadmium Reduction Method Method 8039 0.3 to 30.0 mg/l NO 3 N (HR) Powder Pillows or AccuVac Ampuls Scope and application: For water, wastewater and seawater. Test preparation Instrument-specific

More information

Chemistry: Chemical Equations

Chemistry: Chemical Equations Chemistry: Chemical Equations Write a balanced chemical equation for each word equation. Include the phase of each substance in the equation. Classify the reaction as synthesis, decomposition, single replacement,

More information

Lab 7. Analysis of Hard Water

Lab 7. Analysis of Hard Water Lab 7. Analysis of Hard Water Prelab Assignment Before coming to lab: Use the handout "Lab Notebook Policy" as a guide to complete the following sections of your report for this lab exercise before attending

More information

Determination of calcium by Standardized EDTA Solution

Determination of calcium by Standardized EDTA Solution Determination of calcium by Standardized EDTA Solution Introduction The classic method of determining calcium and other suitable cations is titration with a standardized solution of ethylenediaminetetraacetic

More information

Solutions and Their Concentrations

Solutions and Their Concentrations Chapter 8 Solutions and Their Concentrations Solutions for Practice Problems Section 8.3 Student Tetbook page 305 1. Problem What is the concentration in percent (m/v) of each solution? (a) 14.2 g of potassium

More information

Notes Chapter 9 Limiting Reagent Sample Problems Page 1

Notes Chapter 9 Limiting Reagent Sample Problems Page 1 Notes Chapter 9 Limiting Reagent Sample Problems Page 1 Problem 1: Sodium chloride can be prepared by the reaction of sodium metal with chlorine gas. Suppose that 6.70 Na reacts with 3.20 Cl 2. A. What

More information

PART I: EQUILIBRIUM. 3. Explain why the tetraamminecopper(ii) solution appears blue.

PART I: EQUILIBRIUM. 3. Explain why the tetraamminecopper(ii) solution appears blue. Part A: Formation of a Complex Ion PART I: EQUILIBRIUM Anhydrous copper(ii) sulfate is white, whereas hydrated copper(ii) sulfate is blue. The structure of the hydrated compound is more accurately represented

More information

Name Date Class. SECTION 16.1 PROPERTIES OF SOLUTIONS (pages 471 477)

Name Date Class. SECTION 16.1 PROPERTIES OF SOLUTIONS (pages 471 477) 16 SOLUTIONS SECTION 16.1 PROPERTIES OF SOLUTIONS (pages 471 477) This section identifies the factors that affect the solubility of a substance and determine the rate at which a solute dissolves. Solution

More information

2. ATOMIC, MOLECULAR AND EQUIVALENT MASSES

2. ATOMIC, MOLECULAR AND EQUIVALENT MASSES 2. ATOMIC, MOLECULAR AND EQUIVALENT MASSES INTRODUCTION: EQUIVALENT WEIGHT Since hydrogen is the lightest of all elements, it was chosen as a standard for determination of equivalent weights. On this basis,

More information

Problems you need to KNOW to be successful in the upcoming AP Chemistry exam.

Problems you need to KNOW to be successful in the upcoming AP Chemistry exam. Problems you need to KNOW to be successful in the upcoming AP Chemistry exam. Problem 1 The formula and the molecular weight of an unknown hydrocarbon compound are to be determined by elemental analysis

More information

W1 WORKSHOP ON STOICHIOMETRY

W1 WORKSHOP ON STOICHIOMETRY INTRODUCTION W1 WORKSHOP ON STOICHIOMETRY These notes and exercises are designed to introduce you to the basic concepts required to understand a chemical formula or equation. Relative atomic masses of

More information

STANDARDIZATION OF A SODIUM HYDROXIDE SOLUTION EXPERIMENT 14

STANDARDIZATION OF A SODIUM HYDROXIDE SOLUTION EXPERIMENT 14 STANDARDIZATION OF A SODIUM HYDROXIDE SOLUTION EXPERIMENT 14 OBJECTIVE The objective of this experiment will be the standardization of sodium hydroxide using potassium hydrogen phthalate by the titration

More information

(1) Hydrochloric acid reacts with sodium hypochlorite to form hypochlorous acid: NaOCl(aq) + HCl(aq) HOCl(aq) + NaCl(aq) hypochlorous acid

(1) Hydrochloric acid reacts with sodium hypochlorite to form hypochlorous acid: NaOCl(aq) + HCl(aq) HOCl(aq) + NaCl(aq) hypochlorous acid The Determination of Hypochlorite in Bleach Reading assignment: Chang, Chemistry 10 th edition, pages 156-159. We will study an example of a redox titration in order to determine the concentration of sodium

More information

Essential Maths for Medics and Vets Reference Materials Module 2. Amount and Concentration.

Essential Maths for Medics and Vets Reference Materials Module 2. Amount and Concentration. 2 Amount and concentration: making and diluting solutions 2 Amount and concentration; making and diluting solutions... 2A Rationale... 2B Distinguishing between amount and concentration, g and %w/v...

More information

Concentration Units The concentration of a dissolved salt in water refers to the amount of salt (solute) that is dissolved in water (solvent).

Concentration Units The concentration of a dissolved salt in water refers to the amount of salt (solute) that is dissolved in water (solvent). Concentration Units The concentration of a dissolved salt in water refers to the amount of salt (solute) that is dissolved in water (solvent). Chemists use the term solute to describe the substance of

More information

Solution concentration = how much solute dissolved in solvent

Solution concentration = how much solute dissolved in solvent Solutions 1 Solutions Concentration Solution concentration = how much solute dissolved in solvent Coffee crystal = solute Water = solvent Liquid Coffee = solution so a solute is dissolved in solvent to

More information

The Determination of Acid Content in Vinegar

The Determination of Acid Content in Vinegar The Determination of Acid Content in Vinegar Reading assignment: Chang, Chemistry 10 th edition, pages 153-156. Goals We will use a titration to determine the concentration of acetic acid in a sample of

More information

Dynamic Soil Systems Part A Soil ph and Soil Testing

Dynamic Soil Systems Part A Soil ph and Soil Testing Dynamic Soil Systems Part A Soil ph and Soil Testing Objectives: To measure soil ph and observe conditions which change ph To distinguish between active acidity (soil solution ph) and exchangeable acidity

More information

Expt. 4: ANALYSIS FOR SODIUM CARBONATE

Expt. 4: ANALYSIS FOR SODIUM CARBONATE Expt. 4: ANALYSIS FOR SODIUM CARBONATE Introduction In this experiment, a solution of hydrochloric acid is prepared, standardized against pure sodium carbonate, and used to determine the percentage of

More information

CHAPTER 9. ANS: a. ANS: d. ANS: c. ANS: a. ANS: c

CHAPTER 9. ANS: a. ANS: d. ANS: c. ANS: a. ANS: c CHAPTER 9 1. Which one of the following is the acid in vinegar? a. acetic acid b. citric acid c. muriatic acid d. ascorbic acid 2. Which is a basic or alkaline substance? a. gastric fluid b. black coffee

More information

Molecular Formula: Example

Molecular Formula: Example Molecular Formula: Example A compound is found to contain 85.63% C and 14.37% H by mass. In another experiment its molar mass is found to be 56.1 g/mol. What is its molecular formula? 1 CHAPTER 3 Chemical

More information

Drinking Water Chemistry

Drinking Water Chemistry Drinking Water Chemistry CTB3365x Introduction to water treatment Dr. ir. Doris van Halem Assistant Professor in Drinking Water This lecture Ion balance ph Carbonic acid equilibrium Saturation index (SI)

More information

SCH 3UI Unit 9 Outline: Solutions, Acids and Bases

SCH 3UI Unit 9 Outline: Solutions, Acids and Bases SCH 3UI Unit 9 Outline: Solutions, Acids and Bases Lesson Topics Covered Homework Questions and Assignments 1 Note: Introduction to Solutions review of the organization of matter define: solution, solute,

More information

Experiment: TITRATION OF AN ACID WITH A BASE

Experiment: TITRATION OF AN ACID WITH A BASE Experiment: TITRATION OF AN ACID WITH A BASE INTRODUCTION: The word titration is derived from a French word, "titre" which means "to bestow a title upon or to standardize". The purpose of a chemical titration

More information

Moles. Moles. Moles. Moles. Balancing Eqns. Balancing. Balancing Eqns. Symbols Yields or Produces. Like a recipe:

Moles. Moles. Moles. Moles. Balancing Eqns. Balancing. Balancing Eqns. Symbols Yields or Produces. Like a recipe: Like a recipe: Balancing Eqns Reactants Products 2H 2 (g) + O 2 (g) 2H 2 O(l) coefficients subscripts Balancing Eqns Balancing Symbols (s) (l) (aq) (g) or Yields or Produces solid liquid (pure liquid)

More information

CHM1 Review for Exam 12

CHM1 Review for Exam 12 Topics Solutions 1. Arrhenius Acids and bases a. An acid increases the H + concentration in b. A base increases the OH - concentration in 2. Strong acids and bases completely dissociate 3. Weak acids and

More information

HOMEWORK 4A. Definitions. Oxidation-Reduction Reactions. Questions

HOMEWORK 4A. Definitions. Oxidation-Reduction Reactions. Questions HOMEWORK 4A Oxidation-Reduction Reactions 1. Indicate whether a reaction will occur or not in each of following. Wtiring a balcnced equation is not necessary. (a) Magnesium metal is added to hydrochloric

More information

13.3 Factors Affecting Solubility Solute-Solvent Interactions Pressure Effects Temperature Effects

13.3 Factors Affecting Solubility Solute-Solvent Interactions Pressure Effects Temperature Effects Week 3 Sections 13.3-13.5 13.3 Factors Affecting Solubility Solute-Solvent Interactions Pressure Effects Temperature Effects 13.4 Ways of Expressing Concentration Mass Percentage, ppm, and ppb Mole Fraction,

More information

Calculations for Solutions Worksheet and Key

Calculations for Solutions Worksheet and Key Calculations for Solutions Worksheet and Key 1) 23.5g of NaCl is dissolved in enough water to make.683. a) What is the molarity (M) of the solution? b) How many moles of NaCl are contained in 0.0100 L

More information

Name Class Date. Section: Calculating Quantities in Reactions. Complete each statement below by writing the correct term or phrase.

Name Class Date. Section: Calculating Quantities in Reactions. Complete each statement below by writing the correct term or phrase. Skills Worksheet Concept Review Section: Calculating Quantities in Reactions Complete each statement below by writing the correct term or phrase. 1. All stoichiometric calculations involving equations

More information

I. ACID-BASE NEUTRALIZATION, TITRATION

I. ACID-BASE NEUTRALIZATION, TITRATION LABORATORY 3 I. ACID-BASE NEUTRALIZATION, TITRATION Acid-base neutralization is a process in which acid reacts with base to produce water and salt. The driving force of this reaction is formation of a

More information

EXPERIMENT 10 Chemistry 110. Solutions Part 2 ACIDS, BASES, AND ELECTROLYTES

EXPERIMENT 10 Chemistry 110. Solutions Part 2 ACIDS, BASES, AND ELECTROLYTES EXPERIMENT 10 Chemistry 110 Solutions Part 2 ACIDS, BASES, AND ELECTROLYTES PURPOSE: The purpose of this experiment is to determine the properties of solutions of acids, bases and electrolytes. Students

More information

Chapter 17. The best buffer choice for ph 7 is NaH 2 PO 4 /Na 2 HPO 4. 19)

Chapter 17. The best buffer choice for ph 7 is NaH 2 PO 4 /Na 2 HPO 4. 19) Chapter 17 2) a) HCl and CH 3 COOH are both acids. A buffer must have an acid/base conjugate pair. b) NaH 2 PO 4 and Na 2 HPO 4 are an acid/base conjugate pair. They will make an excellent buffer. c) H

More information

Lecture 6. Classes of Chemical Reactions

Lecture 6. Classes of Chemical Reactions Lecture 6 Classes of Chemical Reactions Lecture 6 Outline 6.1 The Role of Water as a Solvent 6.2 Precipitation Reactions 6.3 Acid-Base Reactions 1 Electron distribution in molecules of H 2 and H 2 O The

More information

Energy (J) -8E-19 -1.2E-18 -1.6E-18 -2E-18

Energy (J) -8E-19 -1.2E-18 -1.6E-18 -2E-18 Spectrophotometry Reading assignment:. http://en.wikipedia.org/wiki/beer-lambert_law Goals We will study the spectral properties of a transition metal-containing compound. We will also study the relationship

More information

ph of strong acid and base

ph of strong acid and base ph of strong acid and base What does strong mean in terms of acids and bases? Solubility. Basically, if you say an acid or base is strong, then it dissociates 100% in water. These types of situations are

More information

CHEMISTRY II FINAL EXAM REVIEW

CHEMISTRY II FINAL EXAM REVIEW Name Period CHEMISTRY II FINAL EXAM REVIEW Final Exam: approximately 75 multiple choice questions Ch 12: Stoichiometry Ch 5 & 6: Electron Configurations & Periodic Properties Ch 7 & 8: Bonding Ch 14: Gas

More information

Guide To Preparation of Stock Standard Solutions

Guide To Preparation of Stock Standard Solutions chemias ft Guide To Preparation of Stock Standard Solutions First Edition May 2011 Na+ 1000 ppm Guide To Preparation Of Stock Standard Solutions By: CHEMIASOFT May 2011 Page 2 of 61 Page 3 of 61 Table

More information

Moles, Molecules, and Grams Worksheet Answer Key

Moles, Molecules, and Grams Worksheet Answer Key Moles, Molecules, and Grams Worksheet Answer Key 1) How many are there in 24 grams of FeF 3? 1.28 x 10 23 2) How many are there in 450 grams of Na 2 SO 4? 1.91 x 10 24 3) How many grams are there in 2.3

More information

MOLARITY = (moles solute) / (vol.solution in liter units)

MOLARITY = (moles solute) / (vol.solution in liter units) CHEM 101/105 Stoichiometry, as applied to Aqueous Solutions containing Ionic Solutes Lect-05 MOLES - a quantity of substance. Quantities of substances can be expressed as masses, as numbers, or as moles.

More information

Aqueous Solutions. Water is the dissolving medium, or solvent. Some Properties of Water. A Solute. Types of Chemical Reactions.

Aqueous Solutions. Water is the dissolving medium, or solvent. Some Properties of Water. A Solute. Types of Chemical Reactions. Aqueous Solutions and Solution Stoichiometry Water is the dissolving medium, or solvent. Some Properties of Water Water is bent or V-shaped. The O-H bonds are covalent. Water is a polar molecule. Hydration

More information

DEIONIZATION IN A "NUT SHELL"

DEIONIZATION IN A NUT SHELL Deionized Water (DI) DEIONIZATION IN A "NUT SHELL" City water is passed through dark amber colored, caviar sized plastic beads called cation ion exchange resin. The cation resin is in the hydrogen form

More information

Molarity of Ions in Solution

Molarity of Ions in Solution APPENDIX A Molarity of Ions in Solution ften it is necessary to calculate not only the concentration (in molarity) of a compound in aqueous solution but also the concentration of each ion in aqueous solution.

More information

CHAPTER 3 COMPOUNDS AND MOLECULES

CHAPTER 3 COMPOUNDS AND MOLECULES Chapter 3 Compounds and Molecules Page 1 CHAPTER 3 COMPOUNDS AND MOLECULES 3-1. Octane, a component of gasoline, has eight carbon atoms and eighteen hydrogen atoms per molecule. Its formula is written

More information

Experiment 4 The Relationship of Density and Molarity of an Aqueous Salt Solution

Experiment 4 The Relationship of Density and Molarity of an Aqueous Salt Solution Experiment 4 The Relationship of Density and Molarity of an Aqueous Salt Solution Purpose: The purpose of this experiment is to investigate the relationship between the concentration of an aqueous salt

More information

PERCENT ACETIC ACID IN VINEGAR EXPERIMENT 15

PERCENT ACETIC ACID IN VINEGAR EXPERIMENT 15 PERCENT ACETIC ACID IN VINEGAR EXPERIMENT 15 PURPOSE A will be titrated using a standardized to determine the percent acetic acid by mass. INTRODUCTION In order to determine the concentration of a, there

More information

Name period Unit 9: acid/base equilibrium

Name period Unit 9: acid/base equilibrium Name period Unit 9: acid/base equilibrium 1. What is the difference between the Arrhenius and the BronstedLowry definition of an acid? Arrhenious acids give H + in water BronstedLowry acids are proton

More information

Water Quality 2 - Determination of Ca, Mg, Fe, and Na by Flame Atomic Spectrophotometry

Water Quality 2 - Determination of Ca, Mg, Fe, and Na by Flame Atomic Spectrophotometry Water Quality 2 - Determination of Ca, Mg, Fe, and Na by Flame Atomic Spectrophotometry Introduction Atomic spectroscopy is one of the most widely used methods for quantitative elemental analysis. There

More information

neutrons are present?

neutrons are present? AP Chem Summer Assignment Worksheet #1 Atomic Structure 1. a) For the ion 39 K +, state how many electrons, how many protons, and how many 19 neutrons are present? b) Which of these particles has the smallest

More information

ATOMS. Multiple Choice Questions

ATOMS. Multiple Choice Questions Chapter 3 ATOMS AND MOLECULES Multiple Choice Questions 1. Which of the following correctly represents 360 g of water? (i) 2 moles of H 2 0 (ii) 20 moles of water (iii) 6.022 10 23 molecules of water (iv)

More information

ACID-BASE TITRATIONS: DETERMINATION OF CARBONATE BY TITRATION WITH HYDROCHLORIC ACID BACKGROUND

ACID-BASE TITRATIONS: DETERMINATION OF CARBONATE BY TITRATION WITH HYDROCHLORIC ACID BACKGROUND #3. Acid - Base Titrations 27 EXPERIMENT 3. ACID-BASE TITRATIONS: DETERMINATION OF CARBONATE BY TITRATION WITH HYDROCHLORIC ACID BACKGROUND Carbonate Equilibria In this experiment a solution of hydrochloric

More information

Solutions Review Questions

Solutions Review Questions Name: Thursday, March 06, 2008 Solutions Review Questions 1. Compared to pure water, an aqueous solution of calcium chloride has a 1. higher boiling point and higher freezing point 3. lower boiling point

More information

The core material is Sect B-D. The rest is optional; do individual sections as suits your interests or needs.

The core material is Sect B-D. The rest is optional; do individual sections as suits your interests or needs. Solutions: Percentage. A. Introduction... 1 B. Comparisons; ratios; the idea of percentage... 1 C. The units of percent... 3 D. Weight percentage, %(w/w)... 5 E. Volume percentage, %(v/v)... 6 F. Weight/volume

More information

To calculate the value of the boiling point constant for water. To use colligative properties to determine the molecular weight of a substance.

To calculate the value of the boiling point constant for water. To use colligative properties to determine the molecular weight of a substance. Colligative Properties of Solutions: A Study of Boiling Point Elevation Amina El-Ashmawy, Collin County Community College (With contributions by Timm Pschigoda, St. Joseph High School, St. Joseph, MI)

More information

Chemical Reactions in Water Ron Robertson

Chemical Reactions in Water Ron Robertson Chemical Reactions in Water Ron Robertson r2 f:\files\courses\1110-20\2010 possible slides for web\waterchemtrans.doc Properties of Compounds in Water Electrolytes and nonelectrolytes Water soluble compounds

More information

Chemical Reactions in Water

Chemical Reactions in Water Chemical Reactions in Water Ron Robertson r2 f:\files\courses\1110-20\2010 possible slides for web\waterchemtrans.doc Acids, Bases and Salts Acids dissolve in water to give H + ions. These ions attach

More information

EXPERIMENT 5. Molecular Absorption Spectroscopy: Determination of Iron With 1,10-Phenanthroline

EXPERIMENT 5. Molecular Absorption Spectroscopy: Determination of Iron With 1,10-Phenanthroline EXPERIMENT 5 Molecular Absorption Spectroscopy: Determination of Iron With 1,10-Phenanthroline UNKNOWN Submit a clean, labeled 100-mL volumetric flask to the instructor so that your unknown iron solution

More information

Atomic mass is the mass of an atom in atomic mass units (amu)

Atomic mass is the mass of an atom in atomic mass units (amu) Micro World atoms & molecules Laboratory scale measurements Atomic mass is the mass of an atom in atomic mass units (amu) By definition: 1 atom 12 C weighs 12 amu On this scale 1 H = 1.008 amu 16 O = 16.00

More information

A) HCl C) 52 g KCl in 100 g water at 80ºC A) temperature of the solution increases B) supersaturated D) low temperature and high pressure D) KClO3

A) HCl C) 52 g KCl in 100 g water at 80ºC A) temperature of the solution increases B) supersaturated D) low temperature and high pressure D) KClO3 1. Which compound becomes less soluble in water as the temperature of the solution is increased? A) HCl B) 2. The solubility of O3(s) in water increases as the A) temperature of the solution increases

More information

ph: Measurement and Uses

ph: Measurement and Uses ph: Measurement and Uses One of the most important properties of aqueous solutions is the concentration of hydrogen ion. The concentration of H + (or H 3 O + ) affects the solubility of inorganic and organic

More information

Solubility of Salts - Ksp. Ksp Solubility

Solubility of Salts - Ksp. Ksp Solubility Solubility of Salts - Ksp We now focus on another aqueous equilibrium system, slightly soluble salts. These salts have a Solubility Product Constant, K sp. (We saw this in 1B with the sodium tetraborate

More information

Liquid phase. Balance equation Moles A Stoic. coefficient. Aqueous phase

Liquid phase. Balance equation Moles A Stoic. coefficient. Aqueous phase STOICHIOMETRY Objective The purpose of this exercise is to give you some practice on some Stoichiometry calculations. Discussion The molecular mass of a compound is the sum of the atomic masses of all

More information

Chelometric Titration : The Determination of Water Hardness and Water Filtration

Chelometric Titration : The Determination of Water Hardness and Water Filtration 1 Chelometric Titration : The Determination of Water Hardness and Water Filtration Things for the lab notebook and to be included in the lab report: 1. Write the equation for the titration of Ca +2 with

More information

Volumetric Analysis. Lecture 5 Experiment 9 in Beran page 109 Prelab = Page 115

Volumetric Analysis. Lecture 5 Experiment 9 in Beran page 109 Prelab = Page 115 Volumetric Analysis Lecture 5 Experiment 9 in Beran page 109 Prelab = Page 115 Experimental Aims To prepare and standardize (determine concentration) a NaOH solution Using your standardized NaOH calculate

More information

CHEM 102: Sample Test 5

CHEM 102: Sample Test 5 CHEM 102: Sample Test 5 CHAPTER 17 1. When H 2 SO 4 is dissolved in water, which species would be found in the water at equilibrium in measurable amounts? a. H 2 SO 4 b. H 3 SO + 4 c. HSO 4 d. SO 2 4 e.

More information

Chapter 3 Mass Relationships in Chemical Reactions

Chapter 3 Mass Relationships in Chemical Reactions Chapter 3 Mass Relationships in Chemical Reactions Student: 1. An atom of bromine has a mass about four times greater than that of an atom of neon. Which choice makes the correct comparison of the relative

More information

5.2. Determining Enthalpy of Reaction by Experiment. Specific Heat Capacity. 234 MHR Unit 3 Energy Changes and Rates of Reaction

5.2. Determining Enthalpy of Reaction by Experiment. Specific Heat Capacity. 234 MHR Unit 3 Energy Changes and Rates of Reaction In this section, you will 5.2 Section Preview/ Specific Expectations determine the heat that is produced by a reaction using a calorimeter, and use the data obtained to calculate the enthalpy change for

More information

Chapter 14 Solutions

Chapter 14 Solutions Chapter 14 Solutions 1 14.1 General properties of solutions solution a system in which one or more substances are homogeneously mixed or dissolved in another substance two components in a solution: solute

More information

Element of same atomic number, but different atomic mass o Example: Hydrogen

Element of same atomic number, but different atomic mass o Example: Hydrogen Atomic mass: p + = protons; e - = electrons; n 0 = neutrons p + + n 0 = atomic mass o For carbon-12, 6p + + 6n 0 = atomic mass of 12.0 o For chlorine-35, 17p + + 18n 0 = atomic mass of 35.0 atomic mass

More information