SOUTH SURVEYING & MAPPING INSTRUMENT CO. NTS-360R . (495) , ,

Save this PDF as:
 WORD  PNG  TXT  JPG

Size: px
Start display at page:

Download "SOUTH SURVEYING & MAPPING INSTRUMENT CO. NTS-360R . (495) , ,"

Transcription

1 2009,.: (495) SOUTH SURVEYING & MAPPING INSTRUMENT CO. NTS-360R ,. (495) , ,

2 2009,.: (495) * ( ) / PPM

3 2009,.: (495) , (%) :

4 2009,.: (495) ( ) C () ( ): ( ) , ( ) ( )

5 2009,.: (495) (REM) (MLM):, H

6 2009,.: (495) (2 ) K A B C

7 2009,.: (495) NTS360 (R) NTS-360 (R) (L). NTS-360L IR. NTS-360R, ( ). NTS-360R.,! :! : 1. NTS-360 (R) (L) SOUTH Survey & Mapping Instruments,,. 2.,. 3. SD-,,, SD-, sd-. SD 1, ,, :,,,,

8 2009,.: (495) NTS-360R,, (,, ), :,,,,... : 1. 2.,.. 3.,,... 4.,,. 5.,.. 6.,..,,,. 7.,. 8..,.. 9.,.,. 10.,,, NTS-360R..,.!!

9 2009,.: (495) ( ) : 3R/IIIa CLASS III LASER PRODUCT,. 3R/IIIa IEC : 2001,. 5 2/II :. :.. :,,,. :.. ( ),.. : 3R,. :, ( IEC :2001)

10 2009,.: (495) : 3R- ( ). 1.,,,. 2.,. 3.,. 4.,.. *),,. 5.,. 6.,,. 7.,, R SOUTH, : ,.,.7,.. (495) , ,

11 2009,.: (495)

12 2009,.: (495)

13 2009,.: (495) : ANG ( ) DIST CORD ( ( ) ) MENU. ( ) NTER () ENT, ESC ) POWER F1 F4 ),

14 2009,.: (495) << >>. ( ) : S h D X Y H * m ft fi '' ' ' D h S X (X) Y (Y) H (H) * ( ) m - ft - fi x H % V [F1] [F2] [F3]

15 2009,.: (495) F1. 1 F F3 F4 ( 2) F F2. F3 % F4 ( 3) F1 0, 90, 180, 270, F2 :<< >> - <<>> -. << >> ( ) F3 F x S* [F.S] << D h [F1] [F2] [F3]

16 2009,.: (495) F1. ( F2 1 2 F3 [N]/ ]/. F4 ( 2) F1 F2 F3. :,. F4 1 3-x X [F.S] << Y H [F1] [F2] [F3] 1 2 F1 F2 F3 [N]/ ]/. F4 2 F1 F2 - F3. F

17 2009,.: (495) F1 F2 F3. F * ( ) * ( ) [ [ ] [ ] 2. [ ]. [ ], / / 3. : F1,,. 4. : [], F2, [] 2- ; F1 - [] F3 - ] - 5. : F3 *1) 6. : [ ] F4, [ ], [ ],, [ ]

18 2009,.: (495) / NTS360R S/N S [POWER] SD,. SD-,. V HR , [POWER] 3-,. 2.2,,.,,,. ( ).,. NTS-360 (L/R) X Y. NTS-360 (L/R) : X-BK(), XYBK( ) ).,, XY

19 2009,.: (495) [] 1. ( ) [ ] : [ ] : 2 : 2 [ XY-B ] 2. [F2],. [F2] 3., *1).., ( ) X(.) Y(.). '' '', [ESC] [ ]. [F3]().. [ESC] X-BK XYBK C1 [XYBK] X-BK XYBK C1 [XYBK] X : Y : < > X-BK XYBK C2 [XYBK] X : Y : X-BK XYBK C2 *1), [F1] X-, [F2] XY

20 2009,.: (495) NTS-350R :,,. NTS-360R ) IR ( ). :,.. NTS-360L IR,.,., 13.,. [ ] 1. ( ) [ ] [MENU]... [ESC],. [MENU]..: [ ]

21 2009,.: (495) ( -30),.,. 0. 1) [ ] 2) ] 3) ( ). ) F4 ],., (). [ESC] [ ] PPM 0.0 ppm [ ] PPM 0.0 ppm [ ] PPM 0.0 ppm [ ] * : , [ ].,,

22 2009,.: (495) [ ] 1) [ ] ) 2 2 2) ( ), ( ) *1), *2) PPM 0.0 ppm [ ] *1), [ ]. *2) ESC. 2.6,.,,.. : : PPM: NTS (. = 0): : 1013 : +20º C : S = P / ( T) (ppm) : S: (. : ) P:. (. : hpa., 1 = 0.75 T: (. :ºC) PPM

23 2009,.: (495) (PPM): 1) [ ] ) F4 ) PPM 0.0 ppm :[ ] 2) ] [ ], PPM PPM 0.0 ppm [ ] 3) PPM, (). *1) PPM 4.0 ppm [ ] : [ ] : 2 *1) 3.7 : PPM : 0.1 PPM : +25 C,

24 2009,.: (495) ) [ ] ( ) 2) 3) F4 ), *1) () PPM 0.0 ppm [ ] PPM 3.5 ppm [ ] hpa 0.0 PPM 3.5 ppm [ ] *1) 3.7 : -30 ~ +60 ( 0.1 ) -22 ~ +140F ( 0.1 F). : 560 ~ 1066 ( 0.1 ) 420 ~ 800 ( 0.1 ) 16.5 ~ 31.5 ( 0.1 ). ( )., ±999.9, : : D=S * [cos + sin * S * cos (K-2) / 2Re] : H= S * [sin + cos * S * cos (1-K) / 2Re], : D=S cos

25 2009,.: (495) H=S sin : =0.14., =0.14 = 0.12 OFF. K=0.14. Re=6370. ) ( ) S 2.8. : NTS360(R) /5 /10 /0.1 /0.1 [ :0.1 1) [MENU], [5] ( ). [MENU] [5] 1/ ) [3] (.). 3) [1] (..). 3) [1]~[4]. : [4] (0.1 ), ( ). [3] [1] [4] 1 :. 2 :. 3 :. 1/ [ ]

26 2009,.: (495) ) (.) 1/ ,.. 1) [MENU], [5]( ). [MENU] [5] 1/ ) [3] (.) [3] ) [4] ). 4) [1]() [2] ( ), ( ). 5) (.) [4] [1]/[2] 1/ [1 ] 2 1/

27 2009,.: (495) ,9., : 1) [MENU], ( ) 2/2, [2]. 2) F4 ().*1),*2) 3) 2/2. [MENU] [2] *1) *2) ESC. 2/ : 1.5. : 0 ppm 2/ *!

28 2009,.: (495) ) [MENU], ( ) 2/2, [3]. 2) *1) [MENU] [3] 2/ SOUTH 3) [F2] () ( ) [ENT]. 4) [ ] [ ]. 5) [ENT]. 2/2. [F2] ] [ ] [ENT] *1) C000.SCO [ ] C001.SCO [ ] C002.SCO [ ] C003.SCO [ ] C000.SCO [ ] C001.SCO [ ] C002.SCO [ ] C003.SCO [ ] 2/

29 2009,.: (495) ,., ),.,. 3.2,....,.,. 1. 1) 2) 1. A B,. 2. ( )

30 2009,.: (495) ) 1.,, A B,, ( ). 90 (100g) (100g). 2.. ( ).., , S* [F.S] << D h

31 2009,.: (495) ,,,. -,,,.. : -,. -. :,!!.,,,.,.. ( - ) :,,., ,.. : ,.,

32 2009,.: (495) :...., : 3.5 ( )

33 2009,.: (495) , ,.. 2.,. 3. ( )..,, ]. 1.. ][ ] ] -> [F1] ( ),

34 2009,.: (495) ,.., 5 5, 1.5. * 2] , [9] 9 ; [0] 0 [.] [1] 1 ; [0] 0 [.] [2] 2 ; [0] ]. SOUTH1. 1., ] [F1]( ),

35 2009,.: (495) F3 : 1 SOUTH :». '''. [F1] (). STU S ; MNO O ; STU U ; STU T ; GHI H ; [STU] 1, ()

36 2009,.: (495) , A. A , 2. [F2] (0 ) ( ). [F2] [ ] [ ] º00 00" B. B : 1. (, )., ; 2.,,

37 2009,.: (495) ,.,,. 4.2, F4 ( ) % V 2. F2 ( / ) [F2] V 3. *1) *1) F2 ( / ). ( ) - HR, ( ) HL ,

38 2009,.: (495) , % 3. [F1] () [F1] >? [ ] [ ] F4 ( ) *1) % *1 F3 ( ) 4.3.2,

39 2009,.: (495) [F3] (). F , *1), : 150º , *1) (%), F4 ( ) % 10.30% 2. F3 ( %) *1) [F3] %

40 2009,.: (495) *1) F3 %. ( 45º 100%, < >. 4.5,..,. A B F4 ( ) F2 (). [F2] 3. A A F1 (0 ). [F1] %. [ 0 ] t m [ ] [ ]

41 2009,.: (495) F4 ( ). 5. B, B F4 (). 6. A, F3 A (REL). [F3] 7. B, F4 B ). 8. 6~7,. : 6.*1) *2). [ 0] t m [ 1 ] t m [ 1] t m REL. [ 2] t m [ 6] t m , F2 (), F4 ( ). [F2] [ ] [ ] % *1) , :,.,. ± *2) ( ) ±30, ±1º 0º (90º, 180º

42 2009,.: (495) º),, 0º00 00, 180º º00 00 )..., F4 ( ).3 2. F1 () [F1] % V [1 ] 2 3. F1 () F2 ( ).. [1] [2] [1 ] F4 ( ) V

43 2009,.: (495) F4 ( ). 3 F V F3 (V ) *1) [F3] V *1) F3, (V )

44 2009,.: (495) NTS-360 (R). 300.,., :,,..,! ( ) IR.. MEAS, ( )., :,, -,..,.,.,., (,,,.),.,.,.,,., (!),. (. 12,11 ).., [ ]

45 2009,.: (495) , ( )., ( ),. (. 12,11 ).,.,, , ,. 1., [], *1) 2..*2) *3) 3. [F1] ( ) ( ). *4) [DIST] [F1] S* [F.S] << D h S* D h S * D h [ ] [ ] 1 SOUTH S

46 2009,.: (495) *1), * *2). ( ), () ( ). *3). *4) NTS -360 (R): F.S, F.N, T.R,. F.R F.S, F.N N-, T.R, F.R.. 1. [DIST],. [DIST] S * [F.S] << D h 2. [F3] () : F.S, F.N, T.R,. F.R [F3] S * [F.S] << D h S * D h

47 2009,.: (495) : ( ) F3.. [F3] S * D h S * D h ,, = : (D), (h) (S). 1. F4 ( ), F2 (). [F2] S * [F.S] << D h D D h S

48 2009,.: (495) F1-F3 F1: D, F2: h, F3: S : F1 ( D) 4. (: ), (). *1) 5. ( )... 6.,. (0 ). [F1] P D D : : S : dd : h : : : S : dd : h : *1) : ( ) : ). (. ) A.,

49 2009,.: (495) ( 0). HD(r)=HD(f) HD(r):. HD(f):.. ( ) F4 ( ) S * D h

50 2009,.: (495) F1 (). [F1] [1] ( ). [1] S D h P F1 (.. *1) [CORD] *2) [P] A0 [CORD] S * [F.R] -< D h S * D h S * D h : X Y H *1) 4 F1 (). *2) ESC

51 2009,.: (495) , (). 0, HD , (+),, (-) 6.2 ' ' 1. F4 ( ),, S * D h F1 (). [F1]

52 2009,.: (495) (. [2] / D D F4 () 5. P1 F1 ()..,. 6. [CORD], 0. *1), *2) P1 [F1] [CORD] *1) F1 4) *2) ESC / D D S * D h S D h X Y H ,. :. ( 1, 2, 3)., 0). 1, 2,

53 2009,.: (495) , 2, ' '. 1. F4 ( ) S * D h F1 (). [F1] ( ). [3] S D

54 2009,.: (495) , F1 ()..,. 5., (P0) 8. 0), [CORD] *1) *2) P1 [F1] P2 [F1] P3 [F1] P0 [CORD] S [F.R] -< D S [F.R] -< D. 03 HR S [F.R] -< D S D h S D h : X Y H *1) F1 () 4) *2) ESC

55 2009,.: (495) ( ) ( 0), ( 2) ( 3) ( 0). = S 2) ( 3). ' ' 1. F4 ( ) S * D h

56 2009,.: (495) F1 (). [F1] ( ). [4] S D ( 1) F1 ()., ( 2) P1 [F1] S [F.R] -< D. 5. P2 F4 ( )., ( 3) P S D P3 F4 ( ).. 0). P S D S D h

57 2009,.: (495) , [CORD]. *1) *2) [CORD] X Y H *1) F1 ( 4) *2) ESC

58 2009,.: (495) , ,, ( : : (Xo, Yo, Ho), : (n, e, z) :. : (N1, E1, Z1) : ( ): Z (VD) N1=N0+n E1=E0+e Z1=Z0+ +Z- : (N0, E0, Z0+ )

59 2009,.: (495) ,,.. 1. *1) 2. B, [CORD]. 3.., [F2] ). 5. [F1] ( )., ( ),.,.,.. [CORD] [F2] [F1] X *[F.R] -< Y H X Y H X Y H [ ] [ ] 1 SOUTH X Y H *1)

60 2009,.: (495) ( ),. (0, 0, 0) 1. F4 ( ) F3 () [F3] X Y H X Y H ). *1) X Y H

61 2009,.: (495) Y H., X Y H *1) : X, Y, H X, Y, H N, E, Z F4 ( ) X Y H F [F1] , ().*1) *1) :

62 2009,.: (495) Z(H) F4 ( ) X Y H F [F1] ).*1) *1) :

63 2009,.: (495) C - : MENU,. 1/2. 1 ( ), 1/2. : [ESC] MENU 1/ [MENU] [1] - SOUTH, / 2 1: 2: 3: 1 / 2 2/2,. 7.3,. 7.4, , / 2 NTS-360 (R),

64 2009,.: (495) , SD-,. 1),,.. 2), ,. 3,. (, ) 4,,,. 5 ( ),. ( ) ,,.,,

65 2009,.: (495) ( ) 1/2. [MENU] [1] MENU 1/ F2 (). [F2] SOUTH 3. (A-. ; B-SD ) ( ) [ENT] 4.. *1) 5. [ ] [ ]. *2) ] [ ] Disk:A Disk:B SOUTH ] SOUTH2.SMD ] SOUTH SOUTH2.SMD ] [] 1 / 2 6. [ENT].,.1/2. [ENT] *1),. *2) F2 ( ). 2/2 F

66 2009,.: (495) / ( ) 2/2., 1 ( ) [1] ( XYH). *1) F2 (). ( ) [ENT] *2) [ ] [ ]. 7. [ENT].. [3] [F2] ] ] [ENT] F1. F2 XYH F3 XYH SOUTH Disk:A Disk:B SOUTH.SCD SOUTH3.SCD SOUTH.SCD SOUTH3.SCD [XYH] [XYH] [XYH] [XYH] 1. 2 XYH 3 XYH

67 2009,.: (495) *1),. *2) , 2/2. 2/2 1. F1 ( ) 2/2. [1] (). [2] 1. 2 XYH XYH XYH SOUTH 7.3 (). ( ),,. : 1) 2) : 1) 2) 3). :

68 2009,.: (495) , ( ). 1/2.. [1] 1 / F4 (). 3. F1 (). [F1] 4. ( ), F4 ) *1) ( ) 5. F4 ( ) *2) F4 6. [ ]. 7. F1 (), F4 (). *3) *4) ] [F1] XYH PT-01 XYH X Y H [ ] [ ]. 1 SOUTH

69 2009,.: (495) F4 ().. 1 SOUTH [F3] (.) *5) [F3]. 1 SOUTH X Y H [ ] [ ] 1 / ( ). 1/ 2. *6) *1) *2), # >. *3),., [F2] () (6) *4) :. *5), F4 ENT *6),,

70 2009,.: (495) ( ):. ( ) (). 1 / ().1/2. [2] F4 ( ). 3. F1 (). *1) [F1] 4. ( ), F4 ). *2) ) 5. F4 ( ). *3) 6.,. *4). 7. [F3] (). [F3] XY/ [ ] [ ] --> 1 : SOUTH SOUTH *S XYH

71 2009,.: (495) ( ). : : [F2] (S).... 1/2. *5) [F2] S* [F..R] <<< D h 1 / *1) F3, :,.. *2) *3), < # >. *4),. *5) > 2.. : 1..--> :. 0! ( ) 1 / ( ). 1/2. [3] F1 F2 2. F1 (). [F1] F

72 2009,.: (495) ( ), F4. *1) 4., *2) ) SOUTH 5. F3 (). [F3] 3 SOUTH 6. F1 F3.*3) : F2 (*S) , F4 ( ) ( ).. F4,,. F3, [F2] SOUTH *S XYH S* [F..R] <<< D h S D h [ ] [ ] 4 SOUTH

73 2009,.: (495) ESC. S D h [ ] [ ] 5 : SOUTH *1) *2),. *3) * ,. 1. F2 ).,. *1) [F2] 4 : SOUTH [ ] [ ] [ ]. 3. [F1] (). F2 F3 *2) ] [F1] D000 D001 D002 D003 [] [] [] [XYH] D001 SOUTH S *1), *2),

74 2009,.: (495) , /. 1., F1 (). 2. [ ],, F4.. [F1] 4 : SOUTH SOUTH [ ],, F2... [F2] 4 : SOUTH , [ ] [ ], ] [ ] , [ENT]. [ENT] *1),

75 2009,.: (495) , : ). 4 : HD(r)=HD(f) HD(r):. HD(f):. 0.,, = 0)

76 2009,.: (495) , F3 ), F4 ). [F3] 5 SOUTH *S XYH ( ). [1] 2 3., F1 ). 4.., F4 ( )., [CORD] P [F1] [CORD] A0 3 4 S D h S * [F.R] < D h X Y H [ ] [ ] X Y H [ ] [ ]

77 2009,.: (495) [DIST], S, D, h. 7. F4 ( ).., F4 (). F3 ), ( ),. [DIST] [F1] X Y H [ ] [ ] 6 SOUTH HR S D h ( ), ( ) : ( ) ( ). 1. F3 (), F4 (). [F3] 3 SOUTH *S XYH

78 2009,.: (495) ( ).. 3. D D, F4 ().*1) 4., F1. 5.., F4 ( ). 6., [CORD].. F4 ( ).. [2] 0D A0 [F1] [CORD] D 0D D 0D S D h S * [F.R] < D h X Y H 9.797? [ ] [ ] ,. :

79 2009,.: (495) P1, P2 P3 0 1, 2, 3 0 ( 1, 2, 3)., ( 0) F3 (), F4 (). [F3] 3 SOUTH *S XYH ( ). [3] , F1 P1 [F1] S D

80 2009,.: (495) , F4 ( ) S * [F.R] < D 5.,. 6.,.. F4 ( ). (P0). F4 (). *3) , [CORD]. P2 [F1] P3 [F1] P0 [CORD] S D S D 4 SOUTH S D h 2.005? [ ] [ ] X Y H ? [ ] [ ]

81 2009,.: (495) F4 ( ).. 5 SOUTH 5 SOUTH *S XYH *1), -. *2). *3), ( ) ( 0), ( 2) ( 3) ( 0)

82 2009,.: (495) = 1/2 S ( 2) 3). 1. F3 (), F4 (). [F3] 3 SOUTH *S XYH ( ). [4] P1), F1 (). P1 [F1] S: D S *[F.S] -< D: 4., ( 2). P2 F4 ( ). P S: D:

83 2009,.: (495) , ( 3). (P3) F4 ( ). P S: D: , P0. 7. P0, [CORD]. [CORD] S: D: h ? [ ] [ ] E N Z ? [ ] [ ] 8. F4 ( ).. 3 SOUTH ( ). 1.XYH S/D S -- D.?

84 2009,.: (495) D --h,

85 2009,.: (495) :. RS-232 USB ( ) 3 ( ). 4 () :

86 2009,.: (495) ) ( SL- ) =R/(R+ )x M R: --. : -- 1) : HDg=HD HDg: HD: 2) HD= HDg/? ( ). 2/2. [3] 2/ = , F4 (). *1) 3.. = =

87 2009,.: (495) , ()..2/2. = *1) : : ( ) : ,,., : 1. 2 () 1/2. 2. F2 ().*1) [F2] [2] 1/ SOUTH 3., ( ) [ENT] *2) [ ]. ] ] Disk:A Disk:B SOUTH.SCD SOUTH3.SCD SOUTH5 SOUTH.SCD SOUTH3.SCD SOUTH5 [XYH] [XYH] [DIR] [XYH] [XYH] [DIR]

88 2009,.: (495) [ENT],. [ENT] 1 / *1). *2) ( ) : 1). 2),. : 1. 1 ( ) 1/2.. F1 (). [1] [F1] PT-1 XYH 2. ( ), F4 (). ) PT F4 ( ).*1) 4. F4 (). X Y H > OK? [ ] [ ]

89 2009,.: (495) /2. *1) / , ( ).1/2.. F3 (XYH). 2.. F4 (). *1) [1] [F3] 3. F4 (). 4. F4 () /2. *1) PT-1 XYH X Y H # X Y H # / ( ) ( ) : 1). 2). 3)

90 2009,.: (495) : ( ). 2. F1 () *1) [F1] 3. ( ), F4 (). 4. F4 ( ). [2] ) 1 / XY/A ? [ ] [ ] F4 ( ).. 1/2. ] [ ] 1 /

91 2009,.: (495) *1) F3,. 1 5 XY/A [F3]( XY/A ) [F3](.) 3 # [F3]( #) : 1. 2 ( ). F3 (XY/A ). [2] [F3] 5 XY/A

92 2009,.: (495) F4 (). *1) ] [ ] 5. F4 ( ). 1/2. *1) / : 1) ( ). 2). : ( ) 1. 3 ( ) 1/2. [3] 1 / F1 (). [F1] 6 XYH

93 2009,.: (495) # *1) F4 () *1) *2) 4. F4 ( ) ,. :. D:. F1 (). 7. :. : =., d =0º00 00". 8. F1 (). D: ( ) dd:. =. dh:.. =.*2) # [F1] [F1] 1 X Y H ? [ ] [ ]. = D = XYH D dd dh D *[F.S] -< dd dh D dd dh

94 2009,.: (495) [F2] () ( ) 10. D, dd dh,. [F2] d D *[F.R] -< dd dh d dd dh d = dd dz = [ESC],. [F2] (XYH),.*3) 12. F4 (). [F2] D = XYH d = dx : dy dh XYH *1) *2),. *3) [F3] (),

95 2009,.: (495) # #,. : ] 2 1., F2 ). [F2] C000 C [ ]:. 3. F1 ). # [ ]. 4. [F1] ( ),. ] [ ] [F1] 5. [ENT]. [ENT] 6. ( ).. C002 C003 C004 C005 C006 C007 : C002 SOUTH X: : C002 SOUTH X: X: [ ] [ ]

96 2009,.: (495) ,, ( ). 1. F4 ( ) 1/2, 2/2. 1 ( ). 1 / 2 2/2 [1] 2. F2 () *1) 3., () [ENT]. 4. [ ] [ ] *2) [F2] ] [ ] SOUTH Disk: A Disk: B SOUTH.SCD [XYH] SOUTH3.SCD [XYH] SOUTH5.SCD [DIR]

97 2009,.: (495) [ENT],. 6. [F1].. F4 () *3) 7. F4 () F4 ( ).., #. *4) [ENT], SOUTH.SCD [XYH] SOUTH3.SCD [XYH] SOUTH5.SCD [DIR] 2 SOUTH SOUTH SOUTH X *[F.S] -< Y H >? [ ] [ ] 3 SOUTH

98 2009,.: (495) *1), F1 (). *2) F2 ( ) *3) *4), , ( 7 ). :. * : 2 * : 3..,, (, 3,

99 2009,.: (495) F4 (C ) 1/2, 2/2. 2 (. ) 2. F1 () *1) [F1] 3.. F4 () *2) [2] 4. F1 (). [F1] 5. A F4 ().*3) A 6. F4 ( ). 1 / 2 2/ SOUTH XYH >? [ ] [ ]

100 2009,.: (495) F4 (). 8. A, F3 (.) F4 (). : F4 () B. 11. (6) (11) B. F4 ),.*4) 12. F1 ( ). 7. [F3] [F1] >? S*[F.S] -< < > dd = dh =

101 2009,.: (495) F4 ( ) F4 (XYH).. F4 ( ) *5) 16., S*[F.R] -< < > S(X) = S(Y) = S(H) = X: >? [ ] [ ] XYH 2/2 *1), F3 (). *2) *3) F3 (XYH). *4).: dd ( )=.dh (Z - ) - (Z ) *5) :, F3 () 2.,

102 2009,.: (495) MENU..,. 9.1 (REM),,,,.. 1) (: h=1.3m) 1. MENU, [1] ( ). 3. [1],. [MENU] [4] [1] [1] 1/2.. 4., F4 () *1)

103 2009,.: (495) , F1 () K, (h).*2), *3) P [F1] K -1 : : D -1 : : D *[F.S] -< -1 : : h * D -1 : : h : D *1) *2) 4, F2 (), 5, F3 (D). *3), ESC. 1) 1. 2 [2]. 2., F1 ). P [F1] -2 < -1> : : D :

104 2009,.: (495) F4 ( ). 5.. F4 ( ). 6. G, G. *1) 7. K, (h). *2) G K -2 < -1> : : D *[F.S] -< -2 < -2> : : D : : D -2 : : h D -2 : : h D *1) (2), F3 (D). (5), F2 ( ). *2), ESC. 9.2 (MLM):,. (dd), (ds), (dh) ( ).,. : (A-B A-C): A-B A-C A-D

105 2009,.: (495) (A-B B-C): A-B B-C C-D ] MLM-1 (A-B, A-C) MLM-2 (A-B, B-C) MLM-1. 1., 2 ( ). 2. [ENT] [ESC],. : [ESC].] : 2..] [2] [ESC] [2] SOUTH [1] -1(A-B,A-C) -2(A-B,B-C)

106 2009,.: (495) A, F1 () *1) 6. (D). 7. B, F1 (). 8. (D) B. 9. (Dd), (ds), (dh) A B. A [F1] B [F1] -1(A-B A-C) < -1> : : XYH -1(A-B A-C) < -1> : : D *[F.S] -< -1 (A-B A-C) < -1> : : D XYH -1 (A-B A-C) < -2> : : D XYH -1 (A-B A-C) < -2> : : D *[F.S] -< -1 (A-B A-C) < -2> : : D XYH PT# -1 (A-B A-C) ds: dd: dh: :

107 2009,.: (495) A C, F1. ) *1) 11. C, F1 (). (D). 12. (Dd), (ds), (dh) A C *2) A D, [F1] C [F1] *1) F3 (XYH),. *2), ESC. -1 (A-B A-C) < -2> : : D XYH PT# -1 (A-B A-C) < -2> : : D *[F.S] -< XYH PT# -1 (A-B A-C) ds: dd: dh: : , [ENT], [F3] (XYH) *1), *2) [F3] -1 (A-B A-C) < -1> : : XYH PT# -1 (A-B A-C) X Y H D

108 2009,.: (495) (PT#),.. [F2] [F2] () *1) F3,. *2) [F3]( D), LM. -1 (A-B A-C) H. H, : 1) ' ',. [] ) [3] 2. [ENT] [ESC],. SOUTH : [ENT].] 3. F4 F2 (). SOUTH

109 2009,.: (495) [1] ( ). [1] F1 (). F4. *1) [F1] 2 XYH OK 6. F4 ( ). 7. F4 (). 8.. X Y H > OK? [ ] [ ].. : *1) [F2] (),. F3 (XYH),. 2) H. [] ) [3]

110 2009,.: (495) [ENT] [ESC],. : [ESC].] 3. [2] (. ). [ESC] [2] SOUTH. 4. F4 (). 5. F4 (). 6. F4 ( ) PT# > -? [ ] [ ] 7. F4 () *1) *[F.3] -< >

111 2009,.: (495) F4 ( ). : d : 9. F4 ( ) [ ] [ ] 10. F1 F2. *1), F : 1) 2) :, MENU, 4. [MENU] [4] 1/

112 2009,.: (495) [4] ( ). [4] 3. [ENT] [ESC],. : [ENT].] *1) [2] : 2..] 5.. *2) SOUTH # DATA-01 #

113 2009,.: (495) A: (), (DATA-01),. B:, [F2] (PT#). A: 0001 : 2 # DATA-02 # B: DATA-02 C: F2 (). [F2] C: C000 C001 C002 [F2] 7. (6). 3, # DATA-02 # *1) F2 (). *2) F3 () F2 ().. * 1) P [F1] 0000 : 2 # DATA-01 #

114 2009,.: (495) *2) X* [F.3] -< Y : H : 3. F1 () 3. [F1] *1) F3 (). *2) : # DATA-01 # F3 () [F3] 2. [F1].. : F2 ( ). [F2] 0000 : 2 # # 0000 : 2 # : # #

115 2009,.: (495) A (0, 0, 0), AB X(n). 2 A B C. 2,.,. 1. MENU, [5] ) 3.. F4 (). 4. P1 ), F4 ( ) *1) [MENU] [4] [5] P1 1/ D >? [ ] [ ]

116 2009,.: (495) S*[F.3] -< 6. B (P2). B (P2). F4 (). 7. B (P2) F4 ( ). *1) P D >? [ ] [ ] S *[F.3] -< 8... (P1-P2) ds dd dh XYH

117 2009,.: (495) [F2] (),. ( ) ds. F1 (XYH). 10. F1 (XYH), F4 () *2) XO YO: HO: (P1-P2) ds dd dh XYH X Y H Y : H : *1) N. *2), F1 () ( ax:30).,,,, 1. [MENU], [4]. [MENU] [4] 1/

118 2009,.: (495) [6] ( ). [6] 3. [1]: ( ) [ENT]. 4. [ENT] *1) 5. [F1] (). F1] ( ) X Y. 6., ), [ESC],.*2) [1] [ENT] [F1] [F1] X Y [ESC]. SOUTH S0001 S0002.SHL [DIR] [DIR] [] 01/ ( ) *1),.2,. *2) [F2],.,,,... :,,. ) ( ) 4-:,,. ( ).,. ENT,... ESC,

119 2009,.: (495) ,, ;..,.., [F1] ( ),. 2. ', () '' (). [F1] [F2] ( ),... :

120 2009,.: (495) F2 ( ). [F2] R ( ) ( ), F4 (). 3.. R. 03 R [F3] ( ),.. :. :

121 2009,.: (495) F3 ( ),. 2. (), F4 () [F3] R ( ),. :, A1 A2. A1 A2.,. A1 A2,

122 2009,.: (495) ( ) X, Y, R A1, A2 (). X,Y, R A1, A2 X Y R A A ]: A1.A2 L1, L2, : [F1] (),. [F1].. 2.,.. 03/05 R

123 2009,.: (495) [F1] ( ), (). [F1]. 03/05 R ( 30 ). :, , [ENT],. [ESC]. 1. [2]:., [ENT],, [ENT]. *1) 2. ( ),,, (). [2] [ENT],.. SOUTH S0001 S0002.SVL [DIR] [DIR] []

124 2009,.: (495) *1),.2, , [F2] ().. [F2] [F1] (), [F1] ( ). 3., (). [ESC],. [F1] [F1]. 03/ /

125 2009,.: (495) ,.,.. : :. :. ( ): ( ) ( )

126 2009,.: (495) ,. 1. [3]:, [1]:. 2., : [3] ( ). *1) 3.,. 4. [F2] (), [ENT]. *2), *3) [3] [1] [3] [F2]. SOUTH SOUTH.SCD [XYH] S0001 DATA.SCD [XYH] [DIR] 5. [ ] [ ]. 6. (), [ESC], ' '. ] [ ] SOUTH.SCD [XYH] S0001 [DIR] DATA.SCD [XYH *1) [1] [2]. *2). *3),.2,

127 2009,.: (495) ( ),., X-Y-H. 1. [3]:, [2]:. 2. [3] [2] # 3., (). 4...,,, ( ), ' '., *1) [F1] ( ), # X Y H

128 2009,.: (495) [3]:, [2]:. [3] [2] [F3] ( #) [F3]. 4. [F2]() *1) [F2] # :SOUTH XYH C000 C001 C002 5., XO ] [ ] YO [ENT] [ ] [ ]. ( ), [ENT] HO ' '. *1) [F1] (),

129 2009,.: (495) ( () ( ) :.. 1). : 1. [3]:, [3]:. [3] [3] [F3] ( #). [F3] # 2 XY/A 4. [F3] (XY/A ). [F3] : : : [F3] ( ). [F3] : # 6... () ] [ ]

130 2009,.: (495) F4 ( ) ). 1. [3]:, [3]: A: ( ), () (. ). B: [F3] ( #). [3] [3] # A: # B: 2 XY/A

131 2009,.: (495) A:.,,, 0.. [F2] (.). [F1] ( ). B: [F2] (),, [ENT] F4). A: B: C000 C001 C [ ] [ ] 5. () F4 ( ) , [ ] [ ] [4]:. [4] ,. (). *1), *2). 1/

132 2009,.: (495) , tdi. tdi.. (). 4., tdi., tdi. tdi.. 2/ tdi tdi tdi ],,, tdi. 6., [F3] ()... [F2] (.). [F1] ( ). F4 ( ). 7., : :. D:. [F3] tdi X Y H = D = XYH

133 2009,.: (495) , [F1](), [F1](). :. : =.. d =0º00 00",. D: dd: =. =. *2) 9. [F2] (). [F1] [F1] [F2] D -< dd D dd D *[F. R] -< dd D, dd d = 0,. 11. (),.,..,. *1) *2) D * dd tdi

134 2009,.: (495) : tdi :. - ( = ) - ( = + )., ().., (). ESC,,., PT# ESC, , tdi [F2] ( ) (1 N)

135 2009,.: (495) ,,. : 1. ' ' [F2] ( ). 2., [ENT]., (),. [F2] tdi (1 N)

136 2009,.: (495) [F2] () [F3] ( ). [F2] [F3] :( )/ ( ) '' ''. 5. [F1] (). : :. : , [F1] ().,. 7. [ESC], :( )/ () ''. 3.. [F1] D D D : ( )/ ( ) : 1),. 2),

137 2009,.: (495) , [5]. 1: (360º) 2. (400G) 3. (6400M) : ºC / ºF 2. : /... /. / / ) : ºC / ºF :.. 2:.. XYH/YXH Z o/vo [S] 2. [N- ] 3. ] XYH 2. YXH 1. Z o - 2. Vo -.. XYH YXH. :

138 2009,.: (495) :. [ /. -.. [1: 1 2: 0.1 ] : 30, W

139 2009,.: (495) : 1). :. 2) :, / 3) : SD-, SD-. 4) :, SD- SD- 5) : (. 9 ). ). : 11.1,, / / / / [MENU], [3] ( ) [MENU] [3]

140 2009,.: (495) [1] ( ),. [1] [6]. : [2] *1) Disk:A (. ) Disk:B (SD-, ) 4. [F1] (),., (P1 ),. [1] [2] [F1] Disk:A Disk:B :B : SD- FAT MB :B MB MB P1 P2 5. [F2] ( ),..,.*2) [F2]..!. B *1) ( ) [ENT],. *2) [F1] ( ),

141 2009,.: (495) ( ),. 2. [F1] ( ). [F1] 3.,,. : [7] ) 4.,. (), *1)-*3) [7] SOUTH.SMD [] SOUTH2 [DIR] SOUTH3.SMD [ ] SOUTH.SMD SOUTH2 SOUTH3.SMD [] [DIR] [] P P2 : SOUTH.SMD *1) *2). *3) ESC

142 2009,.: (495) [ ],. ] [ ] SOUTH.SMD SOUTH2 SOUTH3.SMD [] [DIR] [] 2. ( ). SOUTH.SMD [] SOUTH2 [DIR] SOUTH3.SMD [] 3. [F2] (). [F2] : S () *1) - *3) SOUTH.SMD SOUTH2 S0010.SMD *1) *2). *3) ESC. [] [DIR] [] ,. 1. [ ] [ ],. ] [ ] SOUTH.SMD SOUTH2 SOUTH3.SMD [] [DIR] []

143 2009,.: (495) ( ),. 3. [F3] (). [F3] 4. ( ). *1) [F1]( ). SOUTH.SMD SOUTH2 SOUTH3.SMD [] [DIR] [] RD.SCD. SOUTH.SMD SOUTH2 [] [DIR] #,,,. 1. [MENU], [3] ( ). 2. [1] ( ),.. [1] [6]. : [2],. 3., [ ] [ ], ( ) [ENT],. [MENU] [3] [1] [2] Disk:A Disk:B

144 2009,.: (495) [ ],, [ENT]. 5. [F1] ) *1) [ENT] [F1] 7. [F1] ( ). [F1] 8. [F2] (), ().*3) SOUTH.SCD [XYH] SOUTH2 [DIR] C000 C001 C002 C003 C004 C001 CODE1 X Y H C001 CODE1 X Y H *1) [F2] ( ),. F3] (),. ( ),. *2) [ ] [ ]. [ ] [ 10. *3) ,. 1. [3] ( ). [3]

145 2009,.: (495) [3] ( ),. : [1] ) 3., F4 (). F2. 4., [1]-[3]. : [1] (NTS-300). 5. [F2]. ).*1) 6.,,.*2) [3] [1] [1] *1) NTS NTS B : \ 1000.TXT B : \ SOUTH.SCD 40 *2) (), ' '.( 45) /. PT#, (4) 11.2, [F1] (.),. [F1] 1. NTS NTS

146 2009,.: (495) , [ ] [ ] [1]-[5], [ ] [ ] : PT#/X/Y/H/. 3.,, ( ). 4. [3] (.)... XYH PT# N E Z XYH N E Z PT# 1. NTS NTS [3] ( ). [3] 2. [4] ( ),. : [2] ) 3.,, F4 (). F2. [4] [2]

147 2009,.: (495) , [1]-[3]. : [2] (NTS-660). 5. [F2], (). 6.,, *2), *3), *4) [2] 1. NTS NTS SOUTH :A: \1000.SMD : B: \SOUTH.TXT 45 *1) [F1] (.),. *2) () '.. (* 45):. *3), XT. *4) SOUTH.TXT ,,. A NTS-360R/L : NTS-300, NTS-660 ( ). : RS F1: F2: F3: -- :

148 2009,.: (495) ,.,,,., : RS-232, ( ): [2] ( ). [2] [1] (RS232-). [1] RS232 USB U - 3. [3] ( ). [3] RS [ ], [ ] [ ],. ( ). *1), *2) 5. RS-232. [ ] [ ] [ ] / : 4800 b/s 8 RS *1) [ ]: ; [ ]:, [ESC]. *2) [ ] [ ], [ ] [ ]

149 2009,.: (495) : USB-:. 1. [2] (USB-). [2] RS232 USB U - 2. [3] ( ). [3] USB [ ] [ ],, ( ).: [ ] [ ] / 4. USB. USB RS [2] ( ). 2. [1] RS232- [2] [1] RS232 USB U

150 2009,.: (495) [1] (). : [2] ( ) [1] [2] RS (), [F2].*1) 5., [2] (NTS-660) *2) 6.,,. *3) [2] 1 1. NTS NTS < RS232> A: SOUTH.SCD 123 *1) *2) [F1] (.) *3),, F4 () USB-, USB-.., USB-,. 1. [2] ( ). [2]

151 2009,.: (495) [2] (USB-). [2] RS232 USB U - 3. [2],,. : [1] (. ) 4. (), [F2] *1) 5. [3] (.) *2) [2] [1] [3] USB SOUTH. 1. NTS NTS ,, *3). [USB] A: SOUTH.SCD 102 *1) *2) [F1] (.) *3),, F4 () U :. 1. [2] ( ). [2]

152 2009,.: (495) [3] (U - ) [2] RS232 USB U U - 4.,, J F. 5. J,,,

153 2009,.: (495) F (SD- ),,.. (),.,

154 2009,.: (495) ,.,.,, ,. 1),,.,. 2) 180.,, (1). 3)

155 2009,.: (495) ,.,,.,,,,., ). 2) ( ). 3),..,. 1),, 4. 2) 4,,. 3),,. 4)

156 2009,.: (495) (2 ) 1),, 2), : L= ).. : R= ) 2C=L-R+180 = -30 ±20,. A: 1.,, MENU. 2. [1] ( ), [2]: ( ) 3.,,,, F4. 4.,. F4 ). [MENU] [1] [2] 2/ < -1> < -2>

157 2009,.: (495) , B: ( ) 1). R+C= = )..,.. 3) 2C <20. 4). : ),,.. 2).,. 3), 10, b. 3,.,,,

158 2009,.: (495) , i, ). A L. 2). A, R. 3) 0, i = (L+R-360 )/2. 0, i = (L+R-360 )/2 (L+R-540 )/2. 4) i 10,. : 1.,, MENU. 2. [1] ( ), [1]: ( ) 3.,,, F4. 4.,,,. F4 ( ). [MENU] [1] [1] 2/ < -1> < -2>

159 2009,.: (495) , : 1) - i. -i,., 2) - i,,.,,. 12.7,,.,....,,.,.. 1.,, MENU. 2. [1] ( ), [3]: ). 3.,,, ( ) 10.( ±10 < < ±45 ) [MENU] [1] [3] 2/ < -1> ±10 ± [00/10]

160 2009,.: (495) ,. ) ,. < -2> ±10 ± [00/10] ),. 2),. 3),. 4) 90,. 5),., : 1). 2). 90. A, B, C, D. 3) AC BD O. 4),.. O. 5) 4,,. 6)

161 2009,.: (495) (K) =0., 1-2. : : 1)., 50 B C,. 2), AB AC. 3) B,, BC. 4) : K = AC (AB+BC) K 0, K >5,. :,,.( F1),,,.,,, J

162 2009,.: (495) ) ),. 3)..,,. 4),,. :, ,,,.,...,. :! :.. - :., 5 20,. II.,

163 2009,.: (495) ,..,.,.. (), ;,. ( ), , ,. -. a),. b),,

164 2009,.: (495) ( NTS-362R/5R ) EDM NTS-362R/5R m NTS-362L/5L / 20 NTS-362R/5R ) / 50. ) ax: in:0.1 2~255 NTS-362R/5R : ±(2 +2ppm D) <1.2 ±(5 +2ppm D) <0.5 ±(5 +2ppm D) <1.2 : ±(5 +2ppm D) <1.2 ±(10 +2ppm D) <

165 2009,.: (495) NTS-362L/5L/ NTS-362/5 ±(2 2ppm D) <1.2 ±(5 2ppm D) <0.5 NTS-362R/5R , )* Codac Grey NTS-362L/5L ) NTS-362L/5L 5.0, ( ) NTS-362(L/R) NTS-365(L/R). 79 / 5 : :

166 2009,.: (495) mm 45, EDM: NTS-360L/ R, ±3 30 / 2 / ~ 5 LCD, 6-x, RS - 232, USB, SD Ni-Mh DC 6V NB ~ +50 &

167 2009,.: (495) USB- 1. SD CD

168 2009,.: (495) A 1. NTS-660 : ( ) ( ) JOB INST,. UNITS (,,, STN PT#,, XYZ E(Y), N(X), Z(H) BS PT#,, SS PT#,, HV HA( ), VA( ) SD HA( ), VA( ), SD( ), HD( ), VD( ) NTS-300 : [ ] 1)

169 2009,.: (495) ) _+9_ < d014_*56_, ) D: _+10_ R m d t _*56_,

170 2009,.: (495) SD Measure S: _+12_? m d t _*56_, ) _+11_ U m d086_*56_,

171 2009,.: (495) ) : NTS-660 : PT#, Y, X, H, 1, , , , STN 2, , , , STN 101, , , , STN 102, , , , STN 103, , , , STN 104, , , , STN 1001, , , , PT 1002, , , , PT 1003, , , , PT 1004, , , , PT NTS-300 _+1 _ x _ y _ z _+2 _ x _ y _ z _+3 _ x _ y _ z _+4 _ x _ y _ z _ 3), 1, TREE 2, FENCE 3, CL 4, EP 5, GUTTER 6, PATH 7, DRAIN 8, BM 9, MH 10, GUS 11, WATER 12, LP 13, LIGHTS 14, ROCK

172 2009,.: (495) ),..,,. : KEYWORD ( ) nnn,nnn[,nnn] : START( ), Y, X STRAIGHT(), ARC(. ) R, SPIRAL() R, PT( ) Y, X1, A1, A2] (A1, A2: ) 1: START( ) , , STRAIGHT() , SPIRAL() , ARC(. ) , SPIRAL() , STRAIGHT() , : START( ) , , PT( ) , , ,80.000, PT( ) , ,200 PT( ) , ),,,,,,. :,, : ,50.000, ,70.000, ,70.000, ,90.000,

173 2009,.: (495) B,,,. : 1), 2) 1) : : - -, :, R,. R, ( ) X, Y, R, A1, A2 : PT#,. PT# X Y A1 A2 (N) (E) (R) BP IP IP EP

174 2009,.: (495) : : 0 X Y [ENT] ( ), X Y R A A X Y R A A X Y R A A , : START 0.000, , CRLF PT , , , , CRLF PT , , , 0.000, CRLF PT , , CRLF 2) (1) ( ) A L1. 2 = R L1. 2 : A1. 2 : R

175 2009,.: (495) L1 = A 2 1 = 80 2 =64 m L2 = A 2 2 = 80 2 =64 m R 100 R 100 (2) : 2 = L 2 2 A 2 1 = = 0.32 rad deg 0.32 = = - 2 (3) N A 2 (1...) E A 2 (...) (0.32) (0.32) (0.32) N (1...) (1 ) ( ) 64 * : (0.32) (0.32) (0.32) E (...) ( ) N1=N2 E1=E2 (4) R

176 2009,.: (495) R E R( 1 cos ) R (1 cos ) R 1 R2 (5) N m N Rsin = sin = N N m1 m 2 (6) D LA tan( ) R2cos ec( LA) R1cot( LA 2 N 1 R ) m1 LA , 1 cos ec, sin cot 1 tan D1 100 * tan( / 2) +1.7(1 / sin ) 1.7(1 / tan ) = = (7) KA1 N KA1 IP1 1 cos 1 N D E KA1 IP1 1 sin 1 E D BP IP N KA1 E KA * cos = m * sin = m (8)

177 2009,.: (495) L R( LA 2) 1 =R( * ) =100( = m ) (9) KA2 N KA2 IP1 2 cos 2 N D E KA2 IP1 2 sin 2 E D IP1 IP N KA ( ) * cos = m E KA ( ) * sin = m (10) BC, EC ARC (IP1, IP2, EP) CL R IA IA= CL=200 * * 180 = m TL R tan( IA ) 200 * tan( / 2) = m 2 : N E N E BC BC EC EC N E N E IP IP IP 2 TL cos 2 2 TL sin 2 IP 2 TL cos 3 2 TL sin 3 :

178 2009,.: (495) ( IP1 IP2) = ( IP2 EP) = N BC E BC N EC E EC * cos = m * sin = m 1750 ( ) * cos = m 1400 ( ) * sin = m : : BP KA1= m ( ) ( ) 2 2 KA2 BC ( ) ( ) m

179 2009,.: (495) EC EP ( ) ( ) m (BP) N m E m BP KA m KA1 KE1-100 m 64 m KE1 KE2-100 m m KE2 KA2-100 m 64 m KA2 BC m BC EC m Ec EP m

180 2009,.: (495) C 1) NTS (1) 1. 1) (S) 2) / (D/ h) 3) (H/V)

181 2009,.: (495) ) (N/E/Z) (2) 0,1. 1) (S) 2) / (D/ h) 3) (H ( ) / V( )) 4) (N(x) / E(y) / Z(H))

182 2009,.: (495) ) :,. C 067 ETX CRLF ASCII: 43H 30H 36H 37H 03H 0DH 0AH :? ACK 006 ETX CRLF ASCII: 06H 30H 30H 36H 03H 0DH 0AH NAK 021 ETX CRLF ASCII: 14H 30H 32H 31H 03H 0DH 0AH : Z ETX CRLF H/V ASCII: 5AH 31H 30H 30H 39H 31H 03H 0DH 0AH Z ETX CRLF HR ASCII: 5AH 31H 32H 30H 39H 31H 03H 0DH 0AH Z ETX CRLF HL ASCII: 5AH 31H 33H 30H 39H 31H 03H 0DH 0AH Z ETX CRLF SD ASCII: 5AH 33H 32H 30H 39H 31H 03H 0DH 0AH Z ETX CRLF SD ASCII: 5AH 33H 34H 30H 39H 33H 03H 0DH 0AH Z ETX CRLF SD ASCII: 5AH 33H 35H 30H 39H 32H 03H 0DH 0AH Z ETX CRLF HD ASCII: 5AH 34H 32H 30H 39H 32H 03H 0DH 0AH Z ETX CRLF HD ASCII: 5AH 34H 34H 30H 39H 30H 03H 0DH 0AH Z ETX CRLF HD ASCII: 5AH 34H 35H 30H 39H 31H 03H 0DH 0AH Z ETX CRLF NEZ ASCII: 5AH 36H 32H 30H 39H 34H 03H 0DH 0AH Z ETX CRLF NEZ ASCII: 5AH 36H 34H 30H 38H 38H 03H 0DH 0AH Z ETX CRLF NEZ ASCII: 5AH 36H 35H 30H 38H 39H 03H 0DH 0AH

183 2009,.: (495) ) SOUTH.. (1). 1) 1 ( C ) 2) BBC "C",, "ACK" 0.05.,. 3) "ACK" 0.05., "C". 4) 3) 10, 10,. 5) "C",,. 6) BBC, "ACK" 0.3., "ACK". 7), "ACK".. 8) 7) 10,,,. C 067 ETX ACK 006 ETX ---> ACK 006 ETX : C 067 ETX ( ) C 067 ETX ( ) 10 : ( ) ( )

184 2009,.: (495) :. (2) 1) 5. 2) BBC "C",, "ACK" ) "ACK" 0.05.,. 4) 3) 10,. 5 ACK 006 ETX : ( ) 5 ( ) 10 :

Victims Compensation Claim Status of All Pending Claims and Claims Decided Within the Last Three Years

Victims Compensation Claim Status of All Pending Claims and Claims Decided Within the Last Three Years Claim#:021914-174 Initials: J.T. Last4SSN: 6996 DOB: 5/3/1970 Crime Date: 4/30/2013 Status: Claim is currently under review. Decision expected within 7 days Claim#:041715-334 Initials: M.S. Last4SSN: 2957

More information

Enterprise Data Center A c h itec tu re Consorzio Operativo Gruppo MPS Case S t u d y : P r o g et t o D i sast er R ec o v er y Milano, 7 Febbraio 2006 1 Il G r u p p o M P S L a B a n c a M o n t e d

More information

C o a t i a n P u b l i c D e b tm a n a g e m e n t a n d C h a l l e n g e s o f M a k e t D e v e l o p m e n t Z a g e bo 8 t h A p i l 2 0 1 1 h t t pdd w w wp i j fp h D p u b l i c2 d e b td S t

More information

COMPRESSION SPRINGS: STANDARD SERIES (INCH)

COMPRESSION SPRINGS: STANDARD SERIES (INCH) : STANDARD SERIES (INCH) LC 014A 01 0.250 6.35 11.25 0.200 0.088 2.24 F F M LC 014A 02 0.313 7.94 8.90 0.159 0.105 2.67 F F M LC 014A 03 0.375 9.52 7.10 0.126 0.122 3.10 F F M LC 014A 04 0.438 11.11 6.00

More information

!" #" $ % $ & ' % "( ) $* ( + $, - $. /

! # $ % $ & ' % ( ) $* ( + $, - $. / !" #"$ %$ & '% "( )$* (+$, - $. / 0 & 1&&##+.2 " 2&%%.&, &#& $ & 1 $ + $1 & 31,4!%'"%# 1$4 % 2.& # &2 5 + 670894, ' &" '$+.&2 2$%&##" +..$&&+%1$%114+1 &$ +1&#&+,#%11" &&.1&.$$!$%&'" &:#1;#.!, $& &' +".2

More information

FORT WAYNE COMMUNITY SCHOOLS 12 00 SOUTH CLINTON STREET FORT WAYNE, IN 468 02 6:02 p.m. Ma r c h 2 3, 2 015 OFFICIAL P ROCEED ING S Ro l l Ca l l e a r d o f h o o l u e e o f t h e r t y m m u t y h o

More information

URL encoding uses hex code prefixed by %. Quoted Printable encoding uses hex code prefixed by =.

URL encoding uses hex code prefixed by %. Quoted Printable encoding uses hex code prefixed by =. ASCII = American National Standard Code for Information Interchange ANSI X3.4 1986 (R1997) (PDF), ANSI INCITS 4 1986 (R1997) (Printed Edition) Coded Character Set 7 Bit American National Standard Code

More information

Transient Voltage Suppressor SMBJ5.0 - SMBJ440CA

Transient Voltage Suppressor SMBJ5.0 - SMBJ440CA Features: Glass passivated junction Low incremental surge resistance, excellent clamping capability 600W peak pulse power capability with a 10/1,000μs waveform, repetition rate (duty cycle): 0.01% Very

More information

B I N G O B I N G O. Hf Cd Na Nb Lr. I Fl Fr Mo Si. Ho Bi Ce Eu Ac. Md Co P Pa Tc. Uut Rh K N. Sb At Md H. Bh Cm H Bi Es. Mo Uus Lu P F.

B I N G O B I N G O. Hf Cd Na Nb Lr. I Fl Fr Mo Si. Ho Bi Ce Eu Ac. Md Co P Pa Tc. Uut Rh K N. Sb At Md H. Bh Cm H Bi Es. Mo Uus Lu P F. Hf Cd Na Nb Lr Ho Bi Ce u Ac I Fl Fr Mo i Md Co P Pa Tc Uut Rh K N Dy Cl N Am b At Md H Y Bh Cm H Bi s Mo Uus Lu P F Cu Ar Ag Mg K Thomas Jefferson National Accelerator Facility - Office of cience ducation

More information

H ig h L e v e l O v e r v iew. S te p h a n M a rt in. S e n io r S y s te m A rc h i te ct

H ig h L e v e l O v e r v iew. S te p h a n M a rt in. S e n io r S y s te m A rc h i te ct H ig h L e v e l O v e r v iew S te p h a n M a rt in S e n io r S y s te m A rc h i te ct OPEN XCHANGE Architecture Overview A ge nda D es ig n G o als A rc h i te ct u re O ve rv i ew S c a l a b ili

More information

HR DEPARTMENTAL SUFFIX & ORGANIZATION CODES

HR DEPARTMENTAL SUFFIX & ORGANIZATION CODES HR DEPARTMENTAL SUFFIX & ORGANIZATION CODES Department Suffix Organization Academic Affairs and Dean of Faculty, VP AA 1100 Admissions (Undergraduate) AD 1330 Advanced Ceramics, Colorado Center for--ccac

More information

Coordinate Geometry Fundamentals

Coordinate Geometry Fundamentals Coordinate Geometry Fundamentals 01 Edition Professor Todd W. Horton, PE, PLS Engineering Science & Technologies Department Parkland College Champaign, Illinois thorton@parkland.edu Coordinate Geometry

More information

1.- L a m e j o r o p c ió n e s c l o na r e l d i s co ( s e e x p li c a r á d es p u é s ).

1.- L a m e j o r o p c ió n e s c l o na r e l d i s co ( s e e x p li c a r á d es p u é s ). PROCEDIMIENTO DE RECUPERACION Y COPIAS DE SEGURIDAD DEL CORTAFUEGOS LINUX P ar a p od e r re c u p e ra r nu e s t r o c o rt a f u e go s an t e un d es a s t r e ( r ot u r a d e l di s c o o d e l a

More information

The ASCII Character Set

The ASCII Character Set The ASCII Character Set The American Standard Code for Information Interchange or ASCII assigns values between 0 and 255 for upper and lower case letters, numeric digits, punctuation marks and other symbols.

More information

www.sakshieducation.com

www.sakshieducation.com LENGTH OF THE PERPENDICULAR FROM A POINT TO A STRAIGHT LINE AND DISTANCE BETWEEN TWO PAPALLEL LINES THEOREM The perpendicular distance from a point P(x 1, y 1 ) to the line ax + by + c 0 is ax1+ by1+ c

More information

Version 1.0 English. Leica TS02&06/09 plus Quick Guide

Version 1.0 English. Leica TS02&06/09 plus Quick Guide Version 1.0 English Leica TS02&06/09 plus Quick Guide TS02&06/09 plus, Important Information about your Instrument 1 Important Information about your Instrument 2 Read and follow the User Manual on the

More information

Online EFFECTIVE AS OF JANUARY 2013

Online EFFECTIVE AS OF JANUARY 2013 2013 A and C Session Start Dates (A-B Quarter Sequence*) 2013 B and D Session Start Dates (B-A Quarter Sequence*) Quarter 5 2012 1205A&C Begins November 5, 2012 1205A Ends December 9, 2012 Session Break

More information

Special Advertising Section

Special Advertising Section S Ad S Nw Yk H F S B R, f d -kd f kwd wkf, h G Rh, Nw Yk R d k d b. By S H. B Th d f h -y G Rh, Nw Yk R f: 18 d d, xy j k, f h w hh- d 7% f h wd y f fh w. By y, h wh h d f b. Y h f y f, y d b k d h I Dy

More information

JCUT-3030/6090/1212/1218/1325/1530

JCUT-3030/6090/1212/1218/1325/1530 JCUT CNC ROUTER/CNC WOODWORKING MACHINE JCUT-3030/6090/1212/1218/1325/1530 RZNC-0501 Users Guide Chapter I Characteristic 1. Totally independent from PC platform; 2. Directly read files from U Disk; 3.

More information

Campus Sustainability Assessment and Related Literature

Campus Sustainability Assessment and Related Literature Campus Sustainability Assessment and Related Literature An Annotated Bibliography and Resource Guide Andrew Nixon February 2002 Campus Sustainability Assessment Review Project Telephone: (616) 387-5626

More information

The first 32 characters in the ASCII-table are unprintable control codes and are used to control peripherals such as printers.

The first 32 characters in the ASCII-table are unprintable control codes and are used to control peripherals such as printers. The following ASCII table contains both ASCII control characters, ASCII printable characters and the extended ASCII character set ISO 8859-1, also called ISO Latin1 The first 32 characters in the ASCII-table

More information

AP Calculus BC Exam. The Calculus BC Exam. At a Glance. Section I. SECTION I: Multiple-Choice Questions. Instructions. About Guessing.

AP Calculus BC Exam. The Calculus BC Exam. At a Glance. Section I. SECTION I: Multiple-Choice Questions. Instructions. About Guessing. The Calculus BC Exam AP Calculus BC Exam SECTION I: Multiple-Choice Questions At a Glance Total Time 1 hour, 45 minutes Number of Questions 45 Percent of Total Grade 50% Writing Instrument Pencil required

More information

Squirrel-cage motors Dimensions

Squirrel-cage motors Dimensions Squirrelcage motors Dimension sheet generator: (part of the SD Configurator The SD Configurator contains a dimension drawing for each motor in this catalog. Provided that a complete Order No. is entered

More information

3 3RG78 45 program overview

3 3RG78 45 program overview Overview RG78 45 light curtains and arrays with integrated processing unit for type 4 in accordance with IEC/EN 61496 With "Standard" function package Resolutions: 14, 0, 50, and 90 Protective zone height:

More information

Chapter 11 Area of Quadrilateral

Chapter 11 Area of Quadrilateral 75 Chapter 11 11.1 Quadrilateral A plane figure bounded by four sides is known as a quadrilateral. The straight line joining the opposite corners is called its diagonal. The diagonal divides the quadrilateral

More information

SCO TT G LEA SO N D EM O Z G EB R E-

SCO TT G LEA SO N D EM O Z G EB R E- SCO TT G LEA SO N D EM O Z G EB R E- EG Z IA B H ER e d it o r s N ) LICA TIO N S A N D M ETH O D S t DVD N CLUDED C o n t e n Ls Pr e fa c e x v G l o b a l N a v i g a t i o n Sa t e llit e S y s t e

More information

ASCII CODES WITH GREEK CHARACTERS

ASCII CODES WITH GREEK CHARACTERS ASCII CODES WITH GREEK CHARACTERS Dec Hex Char Description 0 0 NUL (Null) 1 1 SOH (Start of Header) 2 2 STX (Start of Text) 3 3 ETX (End of Text) 4 4 EOT (End of Transmission) 5 5 ENQ (Enquiry) 6 6 ACK

More information

ASCII Code - The extended ASCII table

ASCII Code - The extended ASCII table ASCII Code - The extended ASCII table ASCII stands for American Standard Code for Information Interchange. It's a 7-bit character code where every single bit represents a unique character. On this webpage

More information

Answers to Selected Even-Numbered Problems

Answers to Selected Even-Numbered Problems Answers to Selected Even-Numbered Problems NOTE TO INSTRUCTORS CONSIDERING ADOPTION: Additional content (e.g., FBDs, shear and moment diagrams, etc.) is in the process of being added to this document.

More information

DATING YOUR GUILD 1952-1960

DATING YOUR GUILD 1952-1960 DATING YOUR GUILD 1952-1960 YEAR APPROXIMATE LAST SERIAL NUMBER PRODUCED 1953 1000-1500 1954 1500-2200 1955 2200-3000 1956 3000-4000 1957 4000-5700 1958 5700-8300 1959 12035 1960-1969 This chart displays

More information

FedEx Ground Rates. Effective January 7, 2013

FedEx Ground Rates. Effective January 7, 2013 FedEx Ground Rates Effective January 7, 2013 Introduction FedEx Ground shipping services provide you with dependable, cost-effective, day-definite delivery for packages that don t require the speed of

More information

BARCODE READER V 2.1 EN USER MANUAL

BARCODE READER V 2.1 EN USER MANUAL BARCODE READER V 2.1 EN USER MANUAL INSTALLATION OF YOUR DEVICE PS-2 Connection RS-232 Connection (need 5Volts power supply) 1 INSTALLATION OF YOUR DEVICE USB Connection 2 USING THIS MANUAL TO SETUP YOUR

More information

FUNDAMENTALS OF ENGINEERING (FE) EXAMINATION REVIEW

FUNDAMENTALS OF ENGINEERING (FE) EXAMINATION REVIEW FE: Electric Circuits C.A. Gross EE1-1 FUNDAMENTALS OF ENGINEERING (FE) EXAMINATION REIEW ELECTRICAL ENGINEERING Charles A. Gross, Professor Emeritus Electrical and Comp Engineering Auburn University Broun

More information

DL910 SERIES. Instruction Manual

DL910 SERIES. Instruction Manual DL910 SERIES Instruction Manual DL910 SERIES INSTRUCTION MANUAL ALL RIGHTS RESERVED Datalogic reserves the right to make modifications and improvements without prior notification. Datalogic shall not

More information

TOPPER Sample Paper - I. Class : XI MATHEMATICS. Questions. Time Allowed : 3 Hrs Maximum Marks: 100

TOPPER Sample Paper - I. Class : XI MATHEMATICS. Questions. Time Allowed : 3 Hrs Maximum Marks: 100 TOPPER Sample Paper - I Class : XI MATHEMATICS Questions Time Allowed : 3 Hrs Maximum Marks: 100 1. All questions are compulsory.. The question paper consist of 9 questions divided into three sections

More information

english parliament of finland

english parliament of finland gh f fd 2012 P cvd f h f y f h g Mdy, 6 Fby 2012. A h d MP, K T hd h ch h c f h S. E H (Sc Dcc Py) w -cd S, P Rv (N C Py) F Dy S d A Jh (F Py) Scd Dy S. Th g c c Tdy, 7 Fby, whch Pd f h Rbc Tj H d P f

More information

Total Station Setup and Operation. Sokkia SET Total Station

Total Station Setup and Operation. Sokkia SET Total Station Total Station Setup and Operation Sokkia SET Total Station Parts of the SET Total Station Parts of the SET Total Station Sokkia SET 550 Total Station Keys/Screen SET 550 Menu Pages SET 550 Menu Pages Leveling

More information

Visa Smart Debit/Credit Certificate Authority Public Keys

Visa Smart Debit/Credit Certificate Authority Public Keys CHIP AND NEW TECHNOLOGIES Visa Smart Debit/Credit Certificate Authority Public Keys Overview The EMV standard calls for the use of Public Key technology for offline authentication, for aspects of online

More information

USB PC Adapter V4 Configuration

USB PC Adapter V4 Configuration Programming PC adapter V4 USB PC Adapter V4 Configuration PC adapter with USB cable Flat Ribbon Cable Power Supply Unit Device Driver General The USB PC adapter V4 is used for communication between a PC

More information

Co-ordinate Geometry THE EQUATION OF STRAIGHT LINES

Co-ordinate Geometry THE EQUATION OF STRAIGHT LINES Co-ordinate Geometry THE EQUATION OF STRAIGHT LINES This section refers to the properties of straight lines and curves using rules found by the use of cartesian co-ordinates. The Gradient of a Line. As

More information

How to Subnet a Network How to use this paper Absolute Beginner: Read all Sections 1-4 N eed a q uick rev iew : Read Sections 2-4 J ust need a little h elp : Read Section 4 P a r t I : F o r t h e I P

More information

THREE DIMENSIONAL GEOMETRY

THREE DIMENSIONAL GEOMETRY Chapter 11 THREE DIMENSIONAL GEOMETRY 111 Overview 1111 Direction cosines of a line are the cosines of the angles made by the line with positive directions of the co-ordinate axes 111 If l, m, n are the

More information

CHEM 10113, Quiz 7 December 7, 2011

CHEM 10113, Quiz 7 December 7, 2011 CHEM 10113, Quiz 7 December 7, 2011 Name (please print) All equations must be balanced and show phases for full credit. Significant figures count, show charges as appropriate, and please box your answers!

More information

tis, cis cunc - cunc - tis, cis tis, cis cunc - tis, func - def - def - tis, U func - def - func - tis, pa - tri pa - tri pa - tri tu - per - tu -

tis, cis cunc - cunc - tis, cis tis, cis cunc - tis, func - def - def - tis, U func - def - func - tis, pa - tri pa - tri pa - tri tu - per - tu - 1 B Ihsu dulcs cuncts [Supr 1] [Supr 2] Tnr B B B B - B - B - Ih - Ih - Ih - su su su cs cs cs cunc - cunc - cunc - Amns, Bblthèqu Cntl L Agn, ms 162 D, ff 2v-10 ts, ts, ts, E-tr - E-tr - E-tr - n p n

More information

Pump Front Cartr. GPM Rear Cartr. GPM Shaft Equipment Series From 955H 955H 950F 950F 966F 966F E 926E

Pump Front Cartr. GPM Rear Cartr. GPM Shaft Equipment Series From 955H 955H 950F 950F 966F 966F E 926E 3A1692 3G1266 30 9J5090 955H 60A 001-UP 3A1692 3G1266 30 9J5090 955H 72A 001-UP 6E2063 6E2396 35 4T2626 21 4T2111 950F 6YG 001-UP 6E2063 6E2396 35 4T2626 21 4T2111 950F 7ZF 001-UP 6E2064 6E2387 50 1U2667

More information

www.passpe.com Surveying for California Civil PE License Dr. Shahin A. Mansour, PE Chapter 10 Horizontal, Spiral and Vertical Curves

www.passpe.com Surveying for California Civil PE License Dr. Shahin A. Mansour, PE Chapter 10 Horizontal, Spiral and Vertical Curves www.passpe.com Surveying for California Civil PE License Dr. Shahin A. Mansour, PE Chapter 0 Horizontal, Spiral and Vertical Curves Topics to be covered Types of Horizontal Curves Deflection Angles, Chord

More information

ROBO CYLINDER. Serial Communications Protocol. Intelligent Actuator, Inc.

ROBO CYLINDER. Serial Communications Protocol. Intelligent Actuator, Inc. ROBO CYLINDER Serial Communications Protocol Intelligent Actuator, Inc. 1. Preface Caution! This manual contains information pertaining to communicating serially with the Robo Cylinder controller using

More information

Future Trends in Airline Pricing, Yield. March 13, 2013

Future Trends in Airline Pricing, Yield. March 13, 2013 Future Trends in Airline Pricing, Yield Management, &AncillaryFees March 13, 2013 THE OPPORTUNITY IS NOW FOR CORPORATE TRAVEL MANAGEMENT BUT FIRST: YOU HAVE TO KNOCK DOWN BARRIERS! but it won t hurt much!

More information

ffi I Q II MM I VI I V2 I V3 I V 4 I :11 a a a e b Math 101, Final Exam, Term IANSWER KEY I : 1 a e b c e 2 a b a c d!

ffi I Q II MM I VI I V2 I V3 I V 4 I :11 a a a e b Math 101, Final Exam, Term IANSWER KEY I : 1 a e b c e 2 a b a c d! Math 0, Final Exam, Term 3 IANSWER KEY I I Q II MM I VI I V I V3 I V 4 I : a e b c e a b a c d! 3 a d e d c i 4 a a a e a 5 a e d e c! 6 a a d e c 7 a e c d c 8 a d d b b! 9 a c d b e 0 a c a c a : a a

More information

USI Master Policy Information

USI Master Policy Information Policy I.D. Gender A.B. (#327) M 86 United of Omaha $ 1,000,000.00 A.B. (#430) - (#436) M 86 Metlife $ 2,000,000.00 A.G. #1 (#371), (#610), (#624) M Conseco Life $ 3,125,000.00 10/Apr/10 A.G. #2 (#380),

More information

Electrical Safety Tester

Electrical Safety Tester Electrical Safety Tester GPT-9000 Series QUICK START GUIDE GW INSTEK PART NO. 82PT-99040MA1 ISO-9001 CERTIFIED MANUFACTURER This manual contains proprietary information, which is protected by copyright.

More information

Projective Geometry - Part 2

Projective Geometry - Part 2 Projective Geometry - Part 2 Alexander Remorov alexanderrem@gmail.com Review Four collinear points A, B, C, D form a harmonic bundle (A, C; B, D) when CA : DA CB DB = 1. A pencil P (A, B, C, D) is the

More information

Memory is implemented as an array of electronic switches

Memory is implemented as an array of electronic switches Memory Structure Memory is implemented as an array of electronic switches Each switch can be in one of two states 0 or 1, on or off, true or false, purple or gold, sitting or standing BInary digits (bits)

More information

i n g S e c u r it y 3 1B# ; u r w e b a p p li c a tio n s f r o m ha c ke r s w ith t his å ] í d : L : g u id e Scanned by CamScanner

i n g S e c u r it y 3 1B# ; u r w e b a p p li c a tio n s f r o m ha c ke r s w ith t his å ] í d : L : g u id e Scanned by CamScanner í d : r ' " B o m m 1 E x p e r i e n c e L : i i n g S e c u r it y. 1-1B# ; u r w e b a p p li c a tio n s f r o m ha c ke r s w ith t his g u id e å ] - ew i c h P e t e r M u la e n PACKT ' TAÞ$Æo

More information

Frederikshavn kommunale skolevæsen

Frederikshavn kommunale skolevæsen Frederikshavn kommunale skolevæsen Skoleåret 1969-70 V e d K: Hillers-Andersen k. s k o l e d i r e k t ø r o g Aage Christensen f u l d m æ g t i g ( Fr e d e rik sh av n E k sp r e s- T ry k k e rie

More information

Math 209 Solutions to Assignment 7. x + 2y. 1 x + 2y i + 2. f x = cos(y/z)), f y = x z sin(y/z), f z = xy z 2 sin(y/z).

Math 209 Solutions to Assignment 7. x + 2y. 1 x + 2y i + 2. f x = cos(y/z)), f y = x z sin(y/z), f z = xy z 2 sin(y/z). Math 29 Solutions to Assignment 7. Find the gradient vector field of the following functions: a fx, y lnx + 2y; b fx, y, z x cosy/z. Solution. a f x x + 2y, f 2 y x + 2y. Thus, the gradient vector field

More information

RAJALAKSHMI ENGINEERING COLLEGE MA 2161 UNIT I - ORDINARY DIFFERENTIAL EQUATIONS PART A

RAJALAKSHMI ENGINEERING COLLEGE MA 2161 UNIT I - ORDINARY DIFFERENTIAL EQUATIONS PART A RAJALAKSHMI ENGINEERING COLLEGE MA 26 UNIT I - ORDINARY DIFFERENTIAL EQUATIONS. Solve (D 2 + D 2)y = 0. 2. Solve (D 2 + 6D + 9)y = 0. PART A 3. Solve (D 4 + 4)x = 0 where D = d dt 4. Find Particular Integral:

More information

All answers must use the correct number of significant figures, and must show units!

All answers must use the correct number of significant figures, and must show units! CHEM 10113, Quiz 2 September 7, 2011 Name (please print) All answers must use the correct number of significant figures, and must show units! IA Periodic Table of the Elements VIIIA (1) (18) 1 2 1 H IIA

More information

INDUSTRIAL TF1: 16 keys with LED 6AV1 902-0AA00 KEYBOARDS TF2: 20 keys with LED 6AV1 902-0AB00 6AV3 017-1NE30-0AX0 6AV3 503-1DB10 6AV3 505-1FB12

INDUSTRIAL TF1: 16 keys with LED 6AV1 902-0AA00 KEYBOARDS TF2: 20 keys with LED 6AV1 902-0AB00 6AV3 017-1NE30-0AX0 6AV3 503-1DB10 6AV3 505-1FB12 Siemens SIMATIC S5 SYSTEMS FOR CONTROL AND MONITORING OPERATOR PANELS INDUSTRIAL TF1: 16 keys with LED 6AV1 902-0AA00 KEYBOARDS TF2: 20 keys with LED 6AV1 902-0AB00 TF3: 24 keys with LED 6AV1 902-0AC00

More information

Masters Mens Physique 45+

Masters Mens Physique 45+ C G x By, F, hysq, Bk Chpshps Ap, Cv Cy, Cf Mss Ms hysq + Fs Ls Css Ov Css s G MC Chpk M+ W M+/MC y Bs 9 8 9 9 8 B O'H 8 9 8 S Rs 8 8 9 h K 9 D Szwsk 8 9 8 9 9 G M+ h D Ly Iz M+ 8 M R : : C G x By, F,

More information

C e r t ifie d Se c u r e W e b

C e r t ifie d Se c u r e W e b C r t ifi d S c u r W b Z r t ifizi r t Sic h r h it im W b 1 D l gat s N ic o las M ay n c o u r t, C EO, D r am lab T c h n o lo gi s A G M ar c -A n d r é B c k, C o n su lt an t, D r am lab T c h n

More information

SEATTLE CENTRAL COMMUNITY COLLEGE DIVISION OF SCIENCE AND MATHEMATICS. Oxidation-Reduction

SEATTLE CENTRAL COMMUNITY COLLEGE DIVISION OF SCIENCE AND MATHEMATICS. Oxidation-Reduction SEATTLE CENTRAL COMMUNITY COLLEGE DIVISION OF SCIENCE AND MATHEMATICS OxidationReduction Oxidation is loss of electrons. (Oxygen is EN enough to grab e away from most elements, so the term originally meant

More information

Semester Exam Review Answers. 3. Construct a perpendicular at point B, then bisect the right angle that is formed. 45 o

Semester Exam Review Answers. 3. Construct a perpendicular at point B, then bisect the right angle that is formed. 45 o Unit 1, Tpic 1 1. pint, line, and plane 2. angle bisectr cnstructin 3. Cnstruct a perpendicular at pint B, then bisect the right angle that is frmed. B 45 4. Draw a line thrugh pint H, then cpy the angle

More information

Unit 16 : Software Development Standards O b jec t ive T o p r o v id e a gu ide on ho w t o ac h iev e so f t wa r e p r o cess improvement through the use of software and systems engineering standards.

More information

Factoring - Factoring Special Products

Factoring - Factoring Special Products 6.5 Factoring - Factoring Special Products Objective: Identify and factor special products including a difference of squares, perfect squares, and sum and difference of cubes. When factoring there are

More information

Mathematical Procedures

Mathematical Procedures CHAPTER 6 Mathematical Procedures 168 CHAPTER 6 Mathematical Procedures The multidisciplinary approach to medicine has incorporated a wide variety of mathematical procedures from the fields of physics,

More information

Put the human back in Human Resources.

Put the human back in Human Resources. Put the human back in Human Resources A Co m p l et e Hu m a n Ca p i t a l Ma n a g em en t So l u t i o n t h a t em p o w er s HR p r o f essi o n a l s t o m eet t h ei r co r p o r a t e o b j ect

More information

MANGIS MOTOR SERVICE CO.

MANGIS MOTOR SERVICE CO. INVENTORY- BORGWARNER FROM Jobber Price Sheet 7/1/2001 INVENTORY DATE 7/5/02 GRAND TOTAL ENTIRE LINE $ 11,534.38 PART NUMBER BRAND POP CODE QUANTITY JOBB EA JOBB TOTAL CARB KITS + COMPONENTS PRICE SHEET

More information

The Math Circle, Spring 2004

The Math Circle, Spring 2004 The Math Circle, Spring 2004 (Talks by Gordon Ritter) What is Non-Euclidean Geometry? Most geometries on the plane R 2 are non-euclidean. Let s denote arc length. Then Euclidean geometry arises from the

More information

Excel Invoice Format. SupplierWebsite - Excel Invoice Upload. Data Element Definition UCLA Supplier website (Rev. July 9, 2013)

Excel Invoice Format. SupplierWebsite - Excel Invoice Upload. Data Element Definition UCLA Supplier website (Rev. July 9, 2013) Excel Invoice Format Excel Column Name Cell Format Notes Campus* Supplier Number* Invoice Number* Order Number* Invoice Date* Total Invoice Amount* Total Sales Tax Amount* Discount Amount Discount Percent

More information

Math 2280 - Assignment 6

Math 2280 - Assignment 6 Math 2280 - Assignment 6 Dylan Zwick Spring 2014 Section 3.8-1, 3, 5, 8, 13 Section 4.1-1, 2, 13, 15, 22 Section 4.2-1, 10, 19, 28 1 Section 3.8 - Endpoint Problems and Eigenvalues 3.8.1 For the eigenvalue

More information

x(x + 5) x 2 25 (x + 5)(x 5) = x 6(x 4) x ( x 4) + 3

x(x + 5) x 2 25 (x + 5)(x 5) = x 6(x 4) x ( x 4) + 3 CORE 4 Summary Notes Rational Expressions Factorise all expressions where possible Cancel any factors common to the numerator and denominator x + 5x x(x + 5) x 5 (x + 5)(x 5) x x 5 To add or subtract -

More information

The MyOWNMcMaster degree pathway has three parts: diploma, elective and undergraduate courses.

The MyOWNMcMaster degree pathway has three parts: diploma, elective and undergraduate courses. MyOWNMcMaster Degree Pathway: Diploma in Human Resources Management & Bachelor of Arts in History Requirements The MyOWNMcMaster degree pathway has three parts: diploma, elective and undergraduate courses.

More information

afe advisors investment Defining a Global Fiduciary Standard of Excellence self-assessment of fiduciary excellence for U.S.

afe advisors investment Defining a Global Fiduciary Standard of Excellence self-assessment of fiduciary excellence for U.S. self-assessment of fiduciary excellence for investment advisors afe Defining a Global Fiduciary Standard of Excellence For professionals who provide investment advice, including financial advisors, broker-consultants,

More information

Device I n s t r u m en t a t io n E x a m p l es : I P S L A s & N et F l o w Presented by Emmanuel Tychon Techni cal M ark eti ng Eng i neer TU D resden, J anuary 1 7 th 2 0 0 7 1. C is co I O S I P

More information

Sticky News. sticky rice cooking school newsletter

Sticky News. sticky rice cooking school newsletter S R C S V A T 3 HS SA 2009 S Nw w #05 m 2010 j v T L & S O I M T Ow C F... S C Nw C C A Smb 2010 M C S R C S BEST FOOD EXPERIENCE 2009 N F C w S R C S w w b Aw T 6 B F Ex A. A N F A Tv Tm Aw, w b M Ex

More information

Solutions for Review Problems

Solutions for Review Problems olutions for Review Problems 1. Let be the triangle with vertices A (,, ), B (4,, 1) and C (,, 1). (a) Find the cosine of the angle BAC at vertex A. (b) Find the area of the triangle ABC. (c) Find a vector

More information

DHL EXPRESS CANADA E-BILL STANDARD SPECIFICATIONS

DHL EXPRESS CANADA E-BILL STANDARD SPECIFICATIONS DHL EXPRESS CANADA E-BILL STANDARD SPECIFICATIONS 1 E-Bill Standard Layout A B C D E F G Field/ DHL Account Number Billing Customer Name Billing Customer Address Billing Customer City Billing Customer

More information

GRADE 12 SEPTEMBER 2014 MATHEMATICS P2

GRADE 12 SEPTEMBER 2014 MATHEMATICS P2 NATIONAL SENIOR CERTIFICATE GRADE 1 SEPTEMBER 014 MATHEMATICS P MARKS: 150 TIME: 3 hours *MATHE* This question paper consists of 15 pages, including diagram sheets and 1 information sheet. MATHEMATICS

More information

Pattern Co. Monkey Trouble Wall Quilt. Size: 48" x 58"

Pattern Co. Monkey Trouble Wall Quilt. Size: 48 x 58 .............................................................................................................................................. Pattern Co..........................................................................................

More information

2016 TOURNAMENT OF CHAMPIONS NORTHWEST ALL-STARS & SEATTLE YOUTH BASKETBALL

2016 TOURNAMENT OF CHAMPIONS NORTHWEST ALL-STARS & SEATTLE YOUTH BASKETBALL SAT RENTON HIGH SCHOOL 400 - S 2ND ST. 21ST RENTON, 98055 RHS 1 RHS 2 RHS 3 RHS 4 GIRLS ELITE PURPLE POOL C GIRLS ELITE PURPLE POOL D GIRLS 5TH POOL S GIRLS 7TH ROYAL POOL N 9:00AM EBC ELITE EXCEL 253

More information

Review Solutions MAT V1102. 1. (a) If u = 4 x, then du = dx. Hence, substitution implies 1. dx = du = 2 u + C = 2 4 x + C.

Review Solutions MAT V1102. 1. (a) If u = 4 x, then du = dx. Hence, substitution implies 1. dx = du = 2 u + C = 2 4 x + C. Review Solutions MAT V. (a) If u 4 x, then du dx. Hence, substitution implies dx du u + C 4 x + C. 4 x u (b) If u e t + e t, then du (e t e t )dt. Thus, by substitution, we have e t e t dt e t + e t u

More information

Using a Balanced Scorecard to Tie the Results Act to Your Day-to-Day Operational Priorities

Using a Balanced Scorecard to Tie the Results Act to Your Day-to-Day Operational Priorities Using a Balanced Scorecard to Tie the Results Act to Your Day-to-Day Operational Priorities September 2004 Institute for the Study of Public Policy Implementation Overview Background Behind the Results

More information

Scilab Textbook Companion for Digital Electronics: An Introduction To Theory And Practice by W. H. Gothmann 1

Scilab Textbook Companion for Digital Electronics: An Introduction To Theory And Practice by W. H. Gothmann 1 Scilab Textbook Companion for Digital Electronics: An Introduction To Theory And Practice by W. H. Gothmann 1 Created by Aritra Ray B.Tech Electronics Engineering NIT-DURGAPUR College Teacher Prof. Sabyasachi

More information

Paper 2 83602 Mark scheme

Paper 2 83602 Mark scheme AQA Qualifications AQA CERTIFICATE FURTHER MATHEMATICS Paper 860 Mark scheme 860 June 04 Version/Stage:V.0 Final Mark schemes are prepared by the Lead Assessment Writer and considered, together with the

More information

UNDERSTANDING FLOW PROCESSING WITHIN THE CISCO ACE M ODULE Application de liv e r y pr odu cts can distr ib u te tr af f ic to applications and w e b se r v ice s u sing v ar y ing le v e ls of application

More information

EMERGING DISPLAY CUSTOMER ACCEPTANCE SPECIFICATIONS 16400(LED TYPES) EXAMINED BY : FILE NO. CAS-10068 ISSUE : JAN.19,2000 TOTAL PAGE : 7 APPROVED BY:

EMERGING DISPLAY CUSTOMER ACCEPTANCE SPECIFICATIONS 16400(LED TYPES) EXAMINED BY : FILE NO. CAS-10068 ISSUE : JAN.19,2000 TOTAL PAGE : 7 APPROVED BY: EXAMINED BY : FILE NO. CAS-10068 APPROVED BY: EMERGING DISPLAY TECHNOLOGIES CORPORATION ISSUE : JAN.19,2000 TOTAL PAGE : 7 VERSION : 3 CUSTOMER ACCEPTANCE SPECIFICATIONS MODEL NO. : 16400(LED TYPES) FOR

More information

Geometry in a Nutshell

Geometry in a Nutshell Geometry in a Nutshell Henry Liu, 26 November 2007 This short handout is a list of some of the very basic ideas and results in pure geometry. Draw your own diagrams with a pencil, ruler and compass where

More information

Practical Geometry CHAPTER. 4.1 Introduction DO THIS

Practical Geometry CHAPTER. 4.1 Introduction DO THIS PRACTICAL GEOMETRY 57 Practical Geometry CHAPTER 4 4.1 Introduction You have learnt how to draw triangles in Class VII. We require three measurements (of sides and angles) to draw a unique triangle. Since

More information

Vehicle Identification Numbering System 00.03

Vehicle Identification Numbering System 00.03 Vehicle Identification Numbering System 00.03 IMPORTANT: See Subject 050 for the vehicle identification numbering system for vehicles built before May 1, 2000. Federal Motor Vehicle Safety Standard 115

More information

Second Grade Phonics Scope and Sequence With Concepts of Print and Phonemic Awareness

Second Grade Phonics Scope and Sequence With Concepts of Print and Phonemic Awareness Second Grade Phonics Scope and Sequence With Concepts of Print and Phonemic Awareness Revised 8/22/13 CCSS CCSS.ELA-Literacy.RF.2.3 Know and apply grade-level phonics and word analysis skills in decoding

More information

UPDATED 24/06/16 O-RINGS 1 WEEK DELIVERY STOCK PRIOR TO SALES PAGE 1 / 55

UPDATED 24/06/16 O-RINGS 1 WEEK DELIVERY STOCK PRIOR TO SALES PAGE 1 / 55 UPDATED 24/06/16 O-RINGS 1 WEEK DELIVERY STOCK PRIOR TO SALES PAGE 1 / 55 PARKER P/N BOX Q.TY STOCK AA150 2-227 224 244 E1257 2-013 1342 1122 E1257 2-117 100 320 F00VE24026 5000 500 LM158 2-012 5000 120

More information

MK-SERIE 1000/1500/2000 AllOfBarcode.de Michael Krug - 83278Traunstein BARCODE SCANNER

MK-SERIE 1000/1500/2000 AllOfBarcode.de Michael Krug - 83278Traunstein BARCODE SCANNER MK-SERIE 1000/1500/2000 AllOfBarcode.de Michael Krug - 83278Traunstein BARCODE SCANNER Configuration Guide - 1 - Table of Contents Chapter 1 System Information 1.1 About this manual 3 1.2 How to set up

More information

ASCII Driver Manual 2800/2900

ASCII Driver Manual 2800/2900 ASCII Driver Manual 2800/2900 Compact Operator Interface Terminal with ASCII communication drivers Quartech Corporation 15923 Angelo Drive Macomb Township, Michigan 48042-4050 Phone: (586) 781-0373 FAX:

More information

EMERGING DISPLAY CUSTOMER ACCEPTANCE SPECIFICATIONS 20400 (LED TYPES) EXAMINED BY : FILE NO. CAS-10184 ISSUE : DEC.01,1999 TOTAL PAGE : 7 APPROVED BY:

EMERGING DISPLAY CUSTOMER ACCEPTANCE SPECIFICATIONS 20400 (LED TYPES) EXAMINED BY : FILE NO. CAS-10184 ISSUE : DEC.01,1999 TOTAL PAGE : 7 APPROVED BY: EXAMINED BY : FILE NO. CAS-10184 APPROVED BY: EMERGING DISPLAY TECHNOLOGIES CORPORATION ISSUE : DEC.01,1999 TOTAL PAGE : 7 VERSION : 2 CUSTOMER ACCEPTANCE SPECIFICATIONS MODEL NO. : 20400 (LED TYPES) FOR

More information

The Greatest Common Factor; Factoring by Grouping

The Greatest Common Factor; Factoring by Grouping 296 CHAPTER 5 Factoring and Applications 5.1 The Greatest Common Factor; Factoring by Grouping OBJECTIVES 1 Find the greatest common factor of a list of terms. 2 Factor out the greatest common factor.

More information

1 Symmetries of regular polyhedra

1 Symmetries of regular polyhedra 1230, notes 5 1 Symmetries of regular polyhedra Symmetry groups Recall: Group axioms: Suppose that (G, ) is a group and a, b, c are elements of G. Then (i) a b G (ii) (a b) c = a (b c) (iii) There is an

More information

Honors Geometry A. Semester Exam Review Answers 2015-2016

Honors Geometry A. Semester Exam Review Answers 2015-2016 Hnrs Gemetry A 015-016 Unit 1, Tpic 1 1. pint, line, and plane. angle bisectr cnstructin 3. Cnstruct segment BC, then cnstruct the perpendicular bisectr f CC. C B C 4. Draw a line thrugh pint H, then cpy

More information

T c k D E GR EN S. R a p p o r t M o d u le Aa n g e m a a k t o p 19 /09 /2007 o m 09 :29 u u r BJB 06 013-0009 0 M /V. ja a r.

T c k D E GR EN S. R a p p o r t M o d u le Aa n g e m a a k t o p 19 /09 /2007 o m 09 :29 u u r BJB 06 013-0009 0 M /V. ja a r. D a t a b a n k m r in g R a p p o r t M Aa n g e m a a k t o p 19 /09 /2007 o m 09 :29 u u r I d e n t if ic a t ie v a n d e m S e c t o r BJB V o lg n r. 06 013-0009 0 V o o r z ie n in g N ie u w la

More information

DevOps & WebSphere: Experiences in Chef enabling the IBM WebSphere Liberty Profile

DevOps & WebSphere: Experiences in Chef enabling the IBM WebSphere Liberty Profile Jm h WbSh S d dm 5 h h 4 DO & WbSh: Ex Chf b h IB WbSh Lb f 4 IB C 4 IB C L Dm IB C 4 Rh Rd h fm d h b dd f fm Wh ff w md f h m d f h fm d h b, dd S IS wh w f kd, x md I dd, h fm bd IB d d, whh b h b IB

More information