# Duplicating Segments and Angles

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2 Lesson 3.1 Duplicating Segments and ngles (continued) To duplicate using patty paper, simply place the patty paper over the segment and trace it, using a straightedge to ensure the tracing is straight. Investigation 2: Duplicating an ngle In this investigation you will copy this angle using a compass and straightedge. D E F Draw a ray that extends longer than a side of DEF. Label the endpoint of the ray G. This ray will be one side of the duplicate angle. Try to figure out how to duplicate DEF on your own before looking at Step 1 in your book. You can use a protractor to check that the angles are congruent. Step 1 shows the first two stages involved in duplicating DEF. The stages are described below. Stage 1: Use your compass to construct an arc with its center at point E. The arc should intersect both sides of the angle. Without changing the opening of your compass, make an arc centered at point G. Stage 2: On DEF, put the sharp end of your compass on the point where the arc intersects EF. djust the opening so that the other end touches the point where the arc intersects ED, and make an arc. Without changing the opening of your compass, put the sharp end of your compass on the point where the arc intersects the ray with endpoint G, and make an arc that intersects the original arc. To finish the construction, draw a ray from point G through the point where the two arcs intersect. Use a protractor to verify that G is congruent to DEF. ractice duplicating other angles until you are sure you understand the steps. e sure to try duplicating obtuse angles as well as acute angles. Now try to duplicate DEF using patty paper instead of a compass. Write a summary of the construction methods you learned in this lesson. 32 HTE 3 Discovering Geometry ondensed Lessons

3 ONDENSED LESSON 3.2 onstructing erpendicular isectors In this lesson you will onstruct the perpendicular bisector of a segment using patty paper and a straightedge, and using a compass and straightedge omplete the erpendicular isector onjecture Learn about medians and midsegments of triangles segment bisector is a line, ray, or segment that passes through the midpoint of the segment. line that passes through the midpoint of a segment and that is perpendicular to the segment is the perpendicular bisector of the segment. segment has an infinite number of bisectors, but in a plane it has only one perpendicular bisector. m n Lines, m, and n bisect. Line m is the perpendicular bisector of. Investigation 1: Finding the ight isector Follow Steps 1 3 in your book to construct a perpendicular bisector of using patty paper. lace three points,, and on the perpendicular bisector, and use your compass to compare the distances and, and, and and. In each case, you should find that the distances are equal. These findings lead to the following conjecture. erpendicular isector onjecture If a point is on the perpendicular bisector of a segment, then it is equidistant from the endpoints. -5 Is the converse of this statement also true? That is, if a point is equidistant from the endpoints of a segment, is it on the segment s perpendicular bisector? If the converse is true, then locating two such points can help you locate the perpendicular bisector. Investigation 2: ight Down the Middle In this investigation you will use a compass and straightedge to construct the perpendicular bisector of a segment. First, draw a line segment. Then follow the steps below. djust your compass so that the opening is more than half the length of the segment. Using one endpoint as the center, make an arc on one side of the segment. (continued) Discovering Geometry ondensed Lessons HTE 3 33

4 Lesson 3.2 onstructing erpendicular isectors (continued) Without changing the opening of your compass, put the sharp end of your compass on the other endpoint and make an arc intersecting the first arc. The point where the arcs intersect is equidistant from the two endpoints. Follow the same steps to locate another such point on the other side of the segment. Then draw a line through the two points. The line you drew is the perpendicular bisector of the segment. You can check this by folding the segment so that the endpoints coincide (as you did in Investigation 1). The line should fall on the crease of the paper. The construction you did in this investigation demonstrates the conjecture below. onverse of the erpendicular isector onjecture If a point is equidistant from the endpoints of a segment, then it is on the perpendicular bisector of the segment. -6 Now that you know how to construct a perpendicular bisector, you can locate the midpoint of any segment. This allows you to construct two special types of segments related to triangles: medians and midsegments. median is a segment that connects a vertex of a triangle to the midpoint of the opposite side. To construct the median from vertex, use the perpendicular bisector construction to locate the midpoint of. Then connect vertex to this point. midsegment is a segment that connects the midpoints of two sides of a triangle. To construct a midsegment from to, use the perpendicular bisector construction two times to locate midpoints of and. Then connect the midpoints. D U T Write a summary of the construction methods you learned in this lesson. 34 HTE 3 Discovering Geometry ondensed Lessons

5 ONDENSED LESSON 3.3 onstructing erpendiculars to a Line In this lesson you will onstruct the perpendicular to a line from a point not on the line omplete the Shortest Distance onjecture Learn about altitudes of triangles In Lesson 3.2, you learned to construct the perpendicular bisector of a segment. In this lesson you will use what you learned to construct the perpendicular to a line from a point not on the line. Investigation 1: Finding the ight Line Draw a line and a point labeled that is not on the line. With the sharp end of your compass at point, make two arcs on the line. Label the intersection points and. Note that, so point is on the perpendicular bisector of. Use the construction you learned in Lesson 3.2 to construct the perpendicular bisector of. Label the midpoint of point M. You have now constructed a perpendicular to a line from a point not on the line. Now choose any three points on and label them,, and S. Measure,, S, and M. Which distance is shortest? M M S Your observations should lead to this conjecture. Shortest Distance onjecture The shortest distance from a point to a line is measured along the perpendicular segment from the point to the line. -7 In the next investigation you will use patty paper to create a perpendicular from a point to a line. (continued) Discovering Geometry ondensed Lessons HTE 3 35

6 Lesson 3.3 onstructing erpendiculars to a Line (continued) Investigation 2: atty-aper erpendiculars On a piece of patty paper, draw a line and a point that is not on. Fold the line onto itself. Slide the layers of paper (keeping aligned with itself) until point is on the fold. rease the paper, open it up, and draw a line on the crease. The line is the perpendicular to through point. (Why?) Step 1 Step 2 onstructing a perpendicular from a point to a line allows you to find the distance from the point to the line, which is defined as follows, The distance from a point to a line is the length of the perpendicular segment from the point to the line. The altitude of a triangle is a perpendicular segment from a vertex of a triangle to the line containing the opposite side. The length of this segment is the height of the triangle. The illustrations on page 156 of your book show that an altitude can be inside or outside the triangle, or it can be one of the triangle s sides. triangle has three different altitudes, so it has three different heights. EXMLE onstruct the altitude from vertex of. Solution Extend to become and construct a perpendicular segment from point to. Write a summary of the construction methods you learned in this lesson. 36 HTE 3 Discovering Geometry ondensed Lessons

7 ONDENSED LESSON 3.4 onstructing ngle isectors In this lesson you will onstruct an angle bisector using patty paper and a straightedge, and using a compass and a straightedge omplete the ngle isector onjecture n angle bisector is a ray that divides an angle into two congruent angles. You can also refer to a segment as an angle bisector if the segment lies on the ray and passes through the angle vertex. Investigation 1: ngle isecting by Folding Follow Steps 1 3 in your book to construct the bisector of acute using patty paper. You can tell the ray you construct is the angle bisector because the fold forms two angles that coincide. Now construct the bisector of an obtuse angle. an you use the same method you used to bisect the acute angle? Does every angle have a bisector? Is it possible for an angle to have more than one bisector? If you are not sure, experiment until you think you know the answers to both of these questions. Look at the angles you bisected. Do you see a relationship between the points on the angle bisector and the sides of the angle? hoose one of the bisected angles. hoose any point on the bisector and label it. ompare the distances from to each of the two sides. (emember that distance means shortest distance.) To do this, you can place one edge of a second piece of patty paper on one side of the angle. Slide the edge of the patty paper along the side of the angle until an adjacent perpendicular side of the patty paper passes through the point. Mark this distance on the patty paper. ompare this distance with the distance to the other side of the angle by repeating the process on the other ray. Your observations should lead to this conjecture. Mark this distance. ngle isector onjecture If a point is on the bisector of an angle, then it is equidistant from the sides of the angle. -8 (continued) Discovering Geometry ondensed Lessons HTE 3 37

8 Lesson 3.4 onstructing ngle isectors (continued) Investigation 2: ngle isecting with ompass You can also construct an angle bisector using a compass and straightedge. Draw an angle. To start the construction, draw an arc centered at the vertex of the angle that crosses both sides of the angle. Try to complete the construction on your own before reading the following text. Don t be afraid to experiment. If you make a mistake, you can always start over. When you think you have constructed an angle bisector, fold your paper to check whether the ray you constructed is actually the bisector. onstructing the angle bisector: lace the sharp end of your compass on one of the points where the arc intersects the angle, and make an arc. Without changing the opening of your compass, repeat this process with the other point of intersection. If the two small arcs do not intersect, make your compass opening larger and repeat the last two steps. Draw the ray from the vertex of the angle to the point where the two small arcs intersect. EXMLE onstruct an angle with a measure of exactly 45 using only a compass and straightedge. Solution onstruct a 90 angle by constructing the perpendicular to a line from a point not on the line. (Look back at Lesson 3.3 if you need to review this construction.) Then use the angle-bisector construction you learned in this lesson to bisect the 90 angle Write a summary of the construction methods you learned in this lesson. 38 HTE 3 Discovering Geometry ondensed Lessons

9 ONDENSED LESSON 3.5 onstructing arallel Lines In this lesson you will onstruct parallel lines using patty paper and a straightedge s you learned in hapter 1, parallel lines are lines that lie in the same plane and do not intersect. So, any two points on one parallel line will be equidistant from the other line. You can use this idea to construct a line parallel to a given line. Investigation: onstructing arallel Lines by Folding Follow Steps 1 3 in your book to construct parallel lines with patty paper. Notice that the pairs of corresponding angles, alternate interior angles, and alternate exterior angles are congruent. (In this case, all are pairs of right angles.) The next example shows another way to construct parallel lines. EXMLE Use the onverse of the lternate Interior ngles onjecture to construct a pair of parallel lines. (Try to do this on your own before reading the solution.) Solution Draw two intersecting lines and label them m and n. Label their point of intersection and label one of the angles formed 1. On line n, label a point that is on the same side of line m as 1. Using point as the vertex and as a side, duplicate 1 on the opposite side of line n. Label the new angle 2. Extend the side of 2 into line q. n 2 n 2 n q 1 m 1 m 1 m Notice that line m and line q are cut by a transversal (line n) to form a congruent pair of alternate interior angles ( 1 and 2). ccording to the converse of the I onjecture, m q. Now see if you can use the onverse of the orresponding ngles onjecture or the onverse of the lternate Exterior ngles onjecture to construct a pair of parallel lines. Write a summary of the construction methods you learned in this lesson. Discovering Geometry ondensed Lessons HTE 3 39

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11 ONDENSED LESSON 3.6 onstruction roblems In this lesson you will onstruct polygons given information about some of the sides and angles In this chapter you have learned to construct congruent segments and angles, angle and segment bisectors, perpendiculars, perpendicular bisectors, and parallel lines. Once you know these basic constructions, you can create more advanced geometric figures. Example in your book shows you how to construct a triangle if you are given three segments to use as sides. This example also explores an important question: If you are given three segments, how many different-size triangles can you form? ead the example carefully. Example shows you how to construct a triangle if you are given three angles. This example shows that three angles do not determine a unique triangle. Given three angle measures, you can draw an infinite number of triangles. The triangles will all have the same shape, but they will be different sizes. The examples below show some other constructions. EXMLE Use a compass and a straightedge to construct with as a side, and with m 90 and m 45. Solution To construct, extend to the left and construct a perpendicular to through point. To construct, first construct a perpendicular to through point. This creates a right angle with vertex. To create a 45 angle, bisect this angle. To complete the construction, extend the sides of and until they intersect. Label the intersection point. (continued) Discovering Geometry ondensed Lessons HTE 3 41

12 Lesson 3.6 onstruction roblems (continued) EXMLE onstruct kite KITE with KI KE and TI TE, using the segments and angle below. K I T I K Solution Duplicate KI and K. ecause KI KE, duplicate KI on the other side of K to create side KE. E K I To locate vertex T, make a large arc with radius TI centered at point I. Vertex T must be on this arc. ecause TI TE, draw another large arc with radius TI centered at point E. The intersection of the two arcs is point T. onnect points E and I to point T to complete the kite. E T K I 42 HTE 3 Discovering Geometry ondensed Lessons

13 ONDENSED LESSON 3.7 onstructing oints of oncurrency In this lesson you will onstruct the incenter, circumcenter, and orthocenter of a triangle Make conjectures about the properties of the incenter and circumcenter of a triangle ircumscribe a circle about a triangle and inscribe a circle in a triangle You can use the constructions you learned in this chapter to construct special segments related to triangles. In this lesson you will construct the angle bisectors and altitudes of a triangle, and the perpendicular bisectors of a triangle s sides. fter you construct each set of three segments, you will determine whether they are concurrent. Three or more segments, lines, rays, or planes are concurrent if they intersect in a single point. The point of intersection is called the point of concurrency. Investigation 1: oncurrence You can perform the constructions in this investigation with patty paper and a straightedge or with a compass and straightedge. Save your constructions to use in Investigation 2. If you are using patty paper, draw a large acute triangle on one sheet and a large obtuse triangle on another. If you are using a compass, draw the triangles on the top and bottom halves of a piece of paper. onstruct the three angle bisectors of each triangle. You should find that they are concurrent. The point of concurrency is called the incenter of the triangle. Start with two new triangles, one acute and one obtuse, and construct the perpendicular bisector of each side. You should find that, in each triangle, the three perpendicular bisectors are concurrent. The point of concurrency is called the circumcenter. Finally, start with two new triangles and construct the altitude to each side. These segments are also concurrent. The point of concurrency is called the orthocenter. Incenter ircumcenter Orthocenter Your observations in this investigation lead to the following conjectures. ngle isector oncurrency onjecture The three angle bisectors of a triangle are concurrent. -9 (continued) Discovering Geometry ondensed Lessons HTE 3 43

14 Lesson 3.7 onstructing oints of oncurrency (continued) erpendicular isector oncurrency onjecture The three perpendicular bisectors of a triangle are concurrent. -10 ltitude oncurrency onjecture The three altitudes (or the lines containing the altitudes) of a triangle are concurrent. -11 For what type of triangle will the incenter, circumcenter, and orthocenter be the same point? If you don t know, experiment with different types of triangles (scalene, isosceles, equilateral, acute, obtuse, right). Investigation 2: ircumcenter For this investigation you will need your triangles from Investigation 1 that show the perpendicular bisectors of the sides. For each triangle, measure the distance from the circumcenter to each of the three vertices. re the distances the same? Now measure the distance from the circumcenter to each of the three sides. re the distances the same? Use a compass to construct a circle with the circumcenter as center that passes through a vertex of the triangle. What do you notice? You can state your findings as the ircumcenter onjecture. ircumcenter onjecture The circumcenter of a triangle is equidistant from the three vertices. -12 Investigation 3: Incenter You will need your triangles from Investigation 1 that show the angle bisectors. For each triangle, measure the distance from the incenter to each of the three vertices. re the distances the same? onstruct the perpendicular from the incenter to any one of the sides of the triangle. Mark the point of intersection between the perpendicular and the side. Now use a compass to construct a circle with the incenter as center that passes through the point you just marked. What do you notice? What can you conclude about the distance of the incenter from each of the sides? You can state your findings as the Incenter onjecture. Incenter onjecture The incenter of a triangle is equidistant from the three sides. -13 ead the deductive argument for the ircumcenter onjecture on pages of your book and make sure you understand it. circle that passes through each vertex of a polygon is circumscribed about the polygon. The polygon is inscribed in the circle. ircumcenter (continued) 44 HTE 3 Discovering Geometry ondensed Lessons

16 Lesson 3.7 onstructing oints of oncurrency (continued) Deductive rgument circle is the set of points equidistant from a given center point. If a point is equidistant from the three sides of a triangle, it can be used as the center for an inscribed circle. If the ngle isector onjecture is true, every point on the angle bisector is equidistant from the two sides of the angle. Therefore, in STU each point on angle bisector m is equidistant from triangle sides ST and SU. Similarly, each point on angle bisector n is equidistant from triangle sides ST and TU. ecause incenter I lies on both angle bisectors m and n, it is equidistant from all three sides. Thus, the circle with center at incenter I that is tangent to one of the sides will also be tangent to the other two sides. That circle is the inscribed circle in the triangle. EXMLE Inscribe a circle in S. S Solution To find the center of the circle, construct the incenter. Note that you need to construct only two angle bisectors to locate the incenter. (Why?) S The radius of the circle is the distance from the incenter to each side. To find the radius, construct a perpendicular from the incenter to one of the sides. Here, we construct the perpendicular to S. Now, draw the circle. S S 46 HTE 3 Discovering Geometry ondensed Lessons

17 ONDENSED LESSON 3.8 The entroid In this lesson you will onstruct the centroid of a triangle Make conjectures about the properties of the centroid of a triangle You have seen that the three angle bisectors, the three perpendicular bisectors of the sides, and the three altitudes of a triangle are concurrent. In this lesson you will look at the three medians of a triangle. Investigation 1: re Medians oncurrent? On a sheet of patty paper, draw a large scalene acute triangle and label it N. Locate the midpoints of the three sides and construct the medians. You should find that the medians are concurrent. Save this triangle. N N Now start with a scalene obtuse triangle and construct the three medians. re the medians concurrent? You can state your findings as a conjecture. Median oncurrency onjecture The three medians of a triangle are concurrent. -14 The point of concurrency of the three medians is the centroid. On your acute triangle, label the medians T, NO, and E. Label the centroid D. Use your compass or patty paper to investigate the centroid: Is the centroid equidistant from the three vertices? Is it equidistant from the three sides? Is the centroid the midpoint of each median? The centroid D divides each median into two segments. For each median, find the ratio of the length of the longer segment to the length of the shorter segment. You should find that, for each median, the ratio is the same. Use your findings to complete this conjecture. O E D T N entroid onjecture The centroid of a triangle divides each median into two parts so that the distance from the centroid to the vertex is the distance from the centroid to the midpoint of the opposite side. -15 In Lesson 3.7, you learned that the circumcenter of a triangle is the center of the circumscribed circle and the incenter is the center of the inscribed circle. In the next investigation you will discover a special property of the centroid. (continued) Discovering Geometry ondensed Lessons HTE 3 47

18 Lesson 3.8 The entroid (continued) Investigation 2: alancing ct For this investigation you will need a sheet of cardboard and your scalene acute triangle from Investigation 1. lace your patty-paper triangle on the cardboard. With your compass point, mark the three vertices, the three midpoints, and the centroid on the cardboard. emove the patty paper and carefully draw the triangle and the medians on the cardboard. ut out the cardboard triangle. Try balancing the triangle by placing one of its medians on the edge of a ruler. You should be able to get the triangle to balance. epeat the process with each of the other medians. The fact that you can balance the triangle on each median means that each median divides the triangle into two triangular regions of equal area. Now try to balance the triangle by placing its centroid on the end of a pencil or pen. If you have traced and cut out the triangle carefully, it should balance. ecause the triangle balances on its centroid, the centroid is the triangle s center of gravity. You can state your findings as a conjecture. N enter of Gravity onjecture The centroid of a triangle is the center of gravity of the triangular region. -16 Notice that it makes sense that the triangle balances on the centroid because it balances on each median, and the centroid is on each median. s long as the weight of the cardboard is distributed evenly throughout the triangle, you can balance any triangle on its centroid. 48 HTE 3 Discovering Geometry ondensed Lessons

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