Unit 7 - Test. Name: Class: Date: 1. If BCDE is congruent to OPQR, then DE is congruent to?. A. PQ B. OR C. OP D. QR 2. BAC?

Transcription

1 Class: Date: Unit 7 - Test 1. If BCDE is congruent to OPQR, then DE is congruent to?. A. PQ B. OR C. OP D. QR 2. BAC? A. PNM B. NPM C. NMP D. MNP 3. Given QRS TUV, QS = 3v + 2, and TV = 7v 6, find the length of QS and TV. A. 2 B. 9 C. 8 D Given ABC PQR, m B = 3v + 4, and m Q = 8v 6, find m B and m Q. A. 22 B. 11 C. 10 D. 25 1

2 5. Justify the last two steps of the proof. Given: RS UT and RT US Prove: RST UTS Proof: 1. RS UT 1. Given 2. RT US 2. Given 3. ST TS 3.? 4. RST UTS 4.? A. Symmetric Property of ; SSS C. Reflexive Property of ; SSS B. Reflexive Property of ; SAS D. Symmetric Property of ; SAS 6. Name the angle included by the sides PN and NM. A. N B. P C. M D. none of these 2

3 7. What other information do you need in order to prove the triangles congruent using the SAS Congruence Postulate? A. BAC DAC C. CBA CDA B. AC BD D. AC BD 8. State whether ABC and AED are congruent. Justify your answer. A. yes, by either SSS or SAS B. yes, by SSS only C. yes, by SAS only D. No; there is not enough information to conclude that the triangles are congruent. 9. Which triangles are congruent by ASA? A. ABC and GFH C. HGF and VTU B. HGF and ABC D. none 3

4 10. Which two triangles are congruent by ASA? MR bisects QO, and MQP ROP. A. MQP and MPN C. MNP and ONP B. MPQ and RPO D. none 11. What is the missing reason in the two-column proof? Given: MO bisects PMN and OM bisects PON Prove: PMO NMO Statements Reasons 1. MO bisects PMN 1. Given 2. PMO NMO 2. Definition of angle bisector 3. MO MO 3. Reflexive property 4. OM bisects PON 4. Given 5. POM NOM 5. Definition of angle bisector 6. PMO NMO 6.? A. ASA Postulate C. AAS Theorem B. SSS Postulate D. SAS Postulate 4

5 12. From the information in the diagram, can you prove FDG FDE? Explain. A. yes, by ASA C. yes, by SAS B. yes, by AAA D. no 13. Supply the reasons missing from the proof shown below. Given: AB AC, BAD CAD Prove: AD bisects BC Statements Reasons 1. AB AC 1. Given 2. BAD CAD 2. Given 3. AD AD 3. Reflexive Property 4. BAD CAD 4.? 5. BD CD 5.? 6. AD bisects BC 6. Definition of segment bisector A. ASA; Corresp. parts of are. C. SSS; Reflexive Property B. SAS; Reflexive Property D. SAS; Corresp. parts of are. 5

6 14. What is the value of x? A. 71 B. 142 C. 152 D What is the value of x? A. 68 B. 62 C. 112 D What is the value of x? A B C D

7 17. Find the value of x. The diagram is not to scale. Given: RS ST, m RST = 7x 54, m STU = 8x A. 14 B. 152 C. 16 D Two sides of an equilateral triangle have lengths x + 2 and 2x Which could be the length of the third side: 14 x or 2x + 4? A. 2x + 4 only C. 14 x only B. both 14 x and 2x + 4 D. neither 14 x nor 2x The legs of an isosceles triangle have lengths x + 1 and x + 7. The base has length 3x 3. What is the length of the base? A. 4 C. 3 B. 6 D. cannot be determined 20. Find the values of x and y. A. x = 44, y = 46 C. x = 90, y = 44 B. x = 46, y = 44 D. x = 90, y = 46 7

8 21. Find the value of x. The diagram is not to scale. A. x = 60 B. x = 21 C. x = 15 D. none of these 22. What additional information will allow you to prove the triangles congruent by the HL Theorem? 23. A. A E C. AC DC B. m BCE = 90 D. AC BD Find the length of the missing side. The triangle is not drawn to scale. A. 10 B. 48 C. 28 D

9 24. A. 8 B. 64 C. 4 D. 23 Find the length of the missing side. Leave your answer in simplest radical form. 25. A. 26 ft B. 206 ft C. 296 ft D ft 26. A. 69 ft B. 269 ft C. 23 ft D. 3 ft 27. A triangle has sides of lengths 27, 79, and 84. Is it a right triangle? Explain. A. yes; = 84 2 C. yes; B. no; = 84 2 D. no; A triangle has sides of lengths 24, 143, and 145. Is it a right triangle? Explain. A. yes; = C. yes; B. no; = D. no; A triangle has side lengths of 12 cm, 35 cm, and 37 cm. Classify it as acute, obtuse, or right. A. obtuse B. right C. acute 9

10 30. A triangle has side lengths of 23 in, 6 in, and 28 in. Classify it as acute, obtuse, or right. A. obtuse B. right C. acute 31. Find the length of the hypotenuse. A. 12 B. 6 C. 5 D In triangle ABC, A is a right angle and m B = 45. Find BC. If your answer is not an integer, leave it in simplest radical form. A ft B ft C. 10 ft D. 20 ft 33. Find the length of the leg. If your answer is not an integer, leave it in simplest radical form. A. 2 3 B. 288 C. 24 D

11 34. Find the value of the variable. If your answer is not an integer, leave it in simplest radical form. A B. 5 3 C. 5 2 D The area of a square garden is 98 m 2. How long is the diagonal? A. 49 m B. 14 m C. 7 6 m D. 196 m 36. Quilt squares are cut on the diagonal to form triangular quilt pieces. The hypotenuse of the resulting triangles is 10 inches long. What is the side length of each piece? A. 5 3 C B. 5 2 D Find the value of x and y rounded to the nearest tenth. A. x = 48.1, y = 46.4 C. x = 24.0, y = B. x = 48.1, y = D. x = 24.0, y = The length of the hypotenuse of a triangle is 9. Find the perimeter. A C B D

12 Find the value of the variable(s). If your answer is not an integer, leave it in simplest radical form. 39. A. 5 3 B. 1 2 C D A. x = 22 3, y = 11 C. x = 22, y = 11 3 B. x = 11 3, y = 22 D. x = 11, y = Find the missing value to the nearest hundredth. A B C D Find the missing value to the nearest hundredth. A B C D

13 Use a trigonometric ratio to find the value of x. Round your answer to the nearest tenth. 43. A. 2.6 B. 4.8 C. 3.4 D A. 6.2 cm B cm C cm D cm 45. A. 5 B. 5.8 C D

14 Find the value of x. Round to the nearest tenth. 46. A B C D A B. 8.1 C. 8.2 D Viola drives 2 kilometers up a hill that makes an angle of 9 with the horizontal. To the nearest tenth of a kilometer, what horizontal distance has she covered? A km B. 3.2 km C. 2 km D. 0.3 km 49. Find the value of w, then x. Round lengths of segments to the nearest tenth. A. w = 13.3, x = 10.2 C. w = 13.3, x = 23.6 B. w = 10.8, x = 6.1 D. w = 10.8, x =

15 Find the value of x. Round to the nearest degree. 50. A. 60 B. 57 C. 29 D A. 53 B. 37 C. 49 D. 39 Find the value of x to the nearest degree. 52. A. 24 B. 66 C. 69 D A. 67 B. 23 C. 83 D

16 54. Find the value of w and then x. Round lengths to the nearest tenth and angle measures to the nearest degree. 55. A. w = 7.7, x = 44 C. w = 7.7, x = 54 B. w = 6.4, x = 54 D. w = 6.4, x = 44 Find the value of x. Round the length to the nearest tenth. 56. A m B. 6.5 m C m D. 6 m 57. A. 6.5 ft B. 4.7 ft C. 9.9 ft D. 5.8 ft A. 6.9 cm B. 9.8 cm C. 8.4 cm D cm 16

17 58. A m B m C m D m 59. A. 4.6 yd B. 10 yd C yd D. 5.1 yd 60. To find the height of a pole, a surveyor moves 140 feet away from the base of the pole and then, with a transit 4 feet tall, measures the angle of elevation to the top of the pole to be 44. To the nearest foot, what is the height of the pole? A. 145 ft B. 149 ft C. 135 ft D. 139 ft 61. A spotlight is mounted on a wall 7.4 feet above a security desk in an office building. It is used to light an entrance door 9.3 feet from the desk. To the nearest degree, what is the angle of depression from the spotlight to the entrance door? A. 39 B. 51 C. 53 D An airplane pilot over the Pacific sights an atoll at an angle of depression of 5. At this time, the horizontal distance from the airplane to the atoll is 4629 meters. What is the height of the plane to the nearest meter? A. 403 m B. 405 m C m D m 17

18 63. To approach the runway, a pilot of a small plane must begin a 10 descent starting from a height of 1983 feet above the ground. To the nearest tenth of a mile, how many miles from the runway is the airplane at the start of this approach? 64. Find b. A. 2.2 mi B. 0.4 mi C. 11,419.6 mi D. 2.1 mi Use the Law of Sines to find the missing side of the triangle. A B C D Find the measure of AB given m A = 55, m B = 44, and b = 68. A C B D Find the measure of b, given m A = 38, m B = 74, and a = 31. A B C D

19 Use the Law of Sines to find the missing angle of the triangle. 67. Find m C to the nearest tenth. A B C D Find m B to the nearest tenth. A B C D Find m C to the nearest tenth if c = 48, a = 34, and m A = 41. A B C D

20 70. Find m B given that c =83, a =44, and m A =31. A B C D Use the Law of Cosines to find the missing angle. 71. In FGH, g = 8 ft, h = 13 ft, and m F = 72. Find m G. Round your answer to the nearest tenth. A B C D In FGH, g = 5 ft, h = 22 ft, and m F = 50. Find the measure of f. Round your answer to the nearest whole number. A. 18 B. 13 C. 19 D Find the measure of a. A. 3 B. 6 C. 8 D

21 74. Find m A to the nearest tenth of a degree. A B C D Find m B, given a = 11, b = 12, and c = 17. A. m B = 49.9 B. m B = 40.1 C. m B = 45.3 D. m B = In JKL, j = 12 cm, k = 9 cm, and l = 9.75 cm. Find m J. A. 47 B. 59 C. 40 D

22 Use the Law of Cosines to solve the problem. 77. On a baseball field, the pitcher s mound is 60.5 feet from home plate. During practice, a batter hits a ball 216 feet deep. The path of the ball makes a 34 angle with the line connecting the pitcher and the catcher, to the right of the pitcher s mound. An outfielder catches the ball and throws it to the pitcher. How far does the outfielder throw the ball? A ft B ft C ft D ft 22

23 For each triangle shown below, determine whether you would use the Law of Sines or Law of Cosines to find angle x. Then find angle x to the nearest tenth. 78. A by The Law of Sines C by The Law of Sines B by The Law of Cosines D by The Law of Cosines 79. A. 8.8 by The Law of Sines (SSA) C by The Law of Sines (SAS) B by The Law of Cosines (SAS) D by The Law of Cosines (SSS) 23

24 80. The perimeter of ABC = 37 A. 133 by The Law of Sines C. 60 by The Law of Sines B by The Law of Cosines D by The Law of Cosines 24

25 Unit 7 - Test Answer Section 1. ANS: D PTS: 1 DIF: L3 NAT: CC G.SRT.5 G.2.e G.3.e STA: NC 2.03a TOP: 4-1 Problem 1 Finding Congruent Parts KEY: congruent polygons corresponding parts word problem 2. ANS: C PTS: 1 DIF: L2 NAT: CC G.SRT.5 G.2.e G.3.e STA: NC 2.03a TOP: 4-1 Problem 1 Finding Congruent Parts KEY: congruent polygons corresponding parts 3. ANS: C PTS: 1 DIF: L4 NAT: CC G.SRT.5 G.2.e G.3.e STA: NC 2.03a TOP: 4-1 Problem 2 Using Congruent Parts KEY: congruent polygons corresponding parts 4. ANS: C PTS: 1 DIF: L4 NAT: CC G.SRT.5 G.2.e G.3.e STA: NC 2.03a TOP: 4-1 Problem 2 Using Congruent Parts KEY: congruent polygons corresponding parts 5. ANS: C PTS: 1 DIF: L3 NAT: CC G.SRT.5 G.2.e G.3.e G.5.e STA: NC 2.03a TOP: 4-2 Problem 1 Using SSS KEY: SSS reflexive property proof 6. ANS: A PTS: 1 DIF: L2 NAT: CC G.SRT.5 G.2.e G.3.e G.5.e STA: NC 2.03a TOP: 4-2 Problem 2 Using SAS KEY: angle 7. ANS: B PTS: 1 DIF: L4 NAT: CC G.SRT.5 G.2.e G.3.e G.5.e STA: NC 2.03a TOP: 4-2 Problem 2 Using SAS KEY: SAS reasoning 8. ANS: A PTS: 1 DIF: L3 NAT: CC G.SRT.5 G.2.e G.3.e G.5.e STA: NC 2.03a TOP: 4-2 Problem 3 Identifying Congruent Triangles KEY: SSS SAS reasoning 9. ANS: B PTS: 1 DIF: L2 NAT: CC G.SRT.5 G.2.e G.3.e G.5.e STA: NC 2.03a TOP: 4-3 Problem 1 Using ASA KEY: ASA 10. ANS: B PTS: 1 DIF: L4 NAT: CC G.SRT.5 G.2.e G.3.e G.5.e STA: NC 2.03a TOP: 4-3 Problem 1 Using ASA KEY: ASA vertical angles 11. ANS: A PTS: 1 DIF: L3 NAT: CC G.SRT.5 G.2.e G.3.e G.5.e STA: NC 2.03a TOP: 4-3 Problem 2 Writing a Proof Using ASA KEY: ASA proof two-column proof 12. ANS: A PTS: 1 DIF: L3 NAT: CC G.SRT.5 G.2.e G.3.e G.5.e STA: NC 2.03a TOP: 4-3 Problem 4 Determining Whether Triangles Are Congruent KEY: ASA reasoning 13. ANS: D PTS: 1 DIF: L4 NAT: CC G.CO.10 CC G.CO.13 CC G.SRT.5 G.1.c G.2.e G.3.e STA: NC 2.03a TOP: 4-5 Problem 1 Using the Isosceles Triangle Theorems KEY: segment bisector isosceles triangle proof two-column proof 14. ANS: A PTS: 1 DIF: L2 NAT: CC G.CO.10 CC G.CO.13 CC G.SRT.5 G.1.c G.2.e G.3.e STA: NC 2.03a TOP: 4-5 Problem 2 Using Algebra KEY: isosceles triangle Converse of Isosceles Triangle Theorem Triangle Angle-Sum Theorem 15. ANS: A PTS: 1 DIF: L2 NAT: CC G.CO.10 CC G.CO.13 CC G.SRT.5 G.1.c G.2.e G.3.e STA: NC 2.03a TOP: 4-5 Problem 2 Using Algebra KEY: isosceles triangle Isosceles Triangle Theorem Triangle Angle-Sum Theorem word problem 1

26 16. ANS: B PTS: 1 DIF: L3 NAT: CC G.CO.10 CC G.CO.13 CC G.SRT.5 G.1.c G.2.e G.3.e STA: NC 2.03a TOP: 4-5 Problem 2 Using Algebra KEY: Isosceles Triangle Theorem Triangle Angle-Sum Theorem isosceles triangle 17. ANS: A PTS: 1 DIF: L4 NAT: CC G.CO.10 CC G.CO.13 CC G.SRT.5 G.1.c G.2.e G.3.e STA: NC 2.03a TOP: 4-5 Problem 2 Using Algebra KEY: Isosceles Triangle Theorem isosceles triangle problem solving Triangle Angle-Sum Theorem 18. ANS: C PTS: 1 DIF: L4 NAT: CC G.CO.10 CC G.CO.13 CC G.SRT.5 G.1.c G.2.e G.3.e STA: NC 2.03a TOP: 4-5 Problem 2 Using Algebra KEY: equilateral triangle word problem problem solving 19. ANS: B PTS: 1 DIF: L4 NAT: CC G.CO.10 CC G.CO.13 CC G.SRT.5 G.1.c G.2.e G.3.e STA: NC 2.03a TOP: 4-5 Problem 2 Using Algebra KEY: isosceles triangle Isosceles Triangle Theorem word problem problem solving 20. ANS: C PTS: 1 DIF: L3 NAT: CC G.CO.10 CC G.CO.13 CC G.SRT.5 G.1.c G.2.e G.3.e STA: NC 2.03a TOP: 4-5 Problem 2 Using Algebra KEY: angle bisector isosceles triangle 21. ANS: B PTS: 1 DIF: L4 NAT: CC G.CO.10 CC G.CO.13 CC G.SRT.5 G.1.c G.2.e G.3.e STA: NC 2.03a TOP: 4-5 Problem 3 Finding Angle Measures KEY: Isosceles Triangle Theorem isosceles triangle 22. ANS: C PTS: 1 DIF: L3 NAT: CC G.SRT.5 G.2.e G.3.e G.5.e STA: NC 2.03a TOP: 4-6 Problem 2 Writing a Proof Using the HL Theorem KEY: hypotenuse HL Theorem right triangle reasoning 23. ANS: A PTS: 1 DIF: L2 NAT: CC G.SRT.4 CC G.SRT.8 N.5.e G.3.d TOP: 8-1 Problem 1 Finding the Length of the Hypotenuse KEY: Pythagorean Theorem leg hypotenuse Pythagorean triple 24. ANS: A PTS: 1 DIF: L3 NAT: CC G.SRT.4 CC G.SRT.8 N.5.e G.3.d TOP: 8-1 Problem 2 Finding the Length of a Leg KEY: Pythagorean Theorem leg hypotenuse Pythagorean triple 25. ANS: D PTS: 1 DIF: L3 NAT: CC G.SRT.4 CC G.SRT.8 N.5.e G.3.d TOP: 8-1 Problem 1 Finding the Length of the Hypotenuse KEY: Pythagorean Theorem leg hypotenuse 26. ANS: A PTS: 1 DIF: L3 NAT: CC G.SRT.4 CC G.SRT.8 N.5.e G.3.d TOP: 8-1 Problem 2 Finding the Length of a Leg KEY: Pythagorean Theorem leg hypotenuse 27. ANS: D PTS: 1 DIF: L3 NAT: CC G.SRT.4 CC G.SRT.8 N.5.e G.3.d TOP: 8-1 Problem 4 Identifying a Right Triangle KEY: Pythagorean Theorem Pythagorean triple 2

27 28. ANS: A PTS: 1 DIF: L3 NAT: CC G.SRT.4 CC G.SRT.8 N.5.e G.3.d TOP: 8-1 Problem 4 Identifying a Right Triangle KEY: Pythagorean Theorem Pythagorean triple 29. ANS: B PTS: 1 DIF: L3 NAT: CC G.SRT.4 CC G.SRT.8 N.5.e G.3.d TOP: 8-1 Problem 5 Classifying a Triangle KEY: right triangle obtuse triangle acute triangle 30. ANS: A PTS: 1 DIF: L3 NAT: CC G.SRT.4 CC G.SRT.8 N.5.e G.3.d TOP: 8-1 Problem 5 Classifying a Triangle KEY: right triangle obtuse triangle acute triangle 31. ANS: B PTS: 1 DIF: L3 NAT: CC G.SRT.8 TOP: 8-2 Problem 1 Finding the Length of the Hypotenuse KEY: special right triangles hypotenuse 32. ANS: A PTS: 1 DIF: L2 NAT: CC G.SRT.8 TOP: 8-2 Problem 1 Finding the Length of the Hypotenuse KEY: special right triangles hypotenuse leg 33. ANS: D PTS: 1 DIF: L3 NAT: CC G.SRT.8 TOP: 8-2 Problem 2 Finding the Length of a Leg KEY: special right triangles hypotenuse leg 34. ANS: A PTS: 1 DIF: L3 NAT: CC G.SRT.8 TOP: 8-2 Problem 2 Finding the Length of a Leg KEY: special right triangles hypotenuse leg 35. ANS: B PTS: 1 DIF: L4 NAT: CC G.SRT.8 TOP: 8-2 Problem 3 Finding Distance KEY: special right triangles diagonal 36. ANS: B PTS: 1 DIF: L3 NAT: CC G.SRT.8 TOP: 8-2 Problem 3 Finding Distance KEY: special right triangles word problem 37. ANS: D PTS: 1 DIF: L3 NAT: CC G.SRT.8 TOP: 8-2 Problem 4 Using the Length of One Side KEY: special right triangles leg hypotenuse 38. ANS: B PTS: 1 DIF: L4 NAT: CC G.SRT.8 TOP: 8-2 Problem 4 Using the Length of One Side KEY: special right triangles perimeter hypotenuse leg 39. ANS: A PTS: 1 DIF: L2 NAT: CC G.SRT.8 TOP: 8-2 Problem 4 Using the Length of One Side KEY: special right triangles leg hypotenuse 40. ANS: B PTS: 1 DIF: L3 NAT: CC G.SRT.8 TOP: 8-2 Problem 4 Using the Length of One Side KEY: special right triangles leg hypotenuse 41. ANS: B PTS: 1 DIF: L3 NAT: CC G.SRT.7 CC G.SRT.8 CC G.MG.1 STA: NC 1.01 TOP: 8-3 Problem 3 Using Inverses KEY: cosine 42. ANS: D PTS: 1 DIF: L3 NAT: CC G.SRT.7 CC G.SRT.8 CC G.MG.1 STA: NC 1.01 TOP: 8-3 Problem 3 Using Inverses KEY: sine 3

28 43. ANS: B PTS: 1 DIF: L2 NAT: CC G.SRT.7 CC G.SRT.8 CC G.MG.1 STA: NC 1.01 TOP: 8-3 Problem 2 Using a Trigonometric Ratio to Find Distance KEY: tangent 44. ANS: A PTS: 1 DIF: L3 NAT: CC G.SRT.7 CC G.SRT.8 CC G.MG.1 STA: NC 1.01 TOP: 8-3 Problem 2 Using a Trigonometric Ratio to Find Distance KEY: tangent 45. ANS: B PTS: 1 DIF: L2 NAT: CC G.SRT.7 CC G.SRT.8 CC G.MG.1 STA: NC 1.01 TOP: 8-3 Problem 2 Using a Trigonometric Ratio to Find Distance KEY: tangent 46. ANS: D PTS: 1 DIF: L3 NAT: CC G.SRT.7 CC G.SRT.8 CC G.MG.1 STA: NC 1.01 TOP: 8-3 Problem 2 Using a Trigonometric Ratio to Find Distance KEY: cosine 47. ANS: B PTS: 1 DIF: L3 NAT: CC G.SRT.7 CC G.SRT.8 CC G.MG.1 STA: NC 1.01 TOP: 8-3 Problem 2 Using a Trigonometric Ratio to Find Distance KEY: cosine 48. ANS: C PTS: 1 DIF: L3 NAT: CC G.SRT.7 CC G.SRT.8 CC G.MG.1 STA: NC 1.01 TOP: 8-3 Problem 2 Using a Trigonometric Ratio to Find Distance KEY: cosine word problem problem solving 49. ANS: A PTS: 1 DIF: L4 NAT: CC G.SRT.7 CC G.SRT.8 CC G.MG.1 STA: NC 1.01 TOP: 8-3 Problem 2 Using a Trigonometric Ratio to Find Distance KEY: tangent problem solving 50. ANS: B PTS: 1 DIF: L3 NAT: CC G.SRT.7 CC G.SRT.8 CC G.MG.1 STA: NC 1.01 TOP: 8-3 Problem 3 Using Inverses KEY: cosine 51. ANS: A PTS: 1 DIF: L3 NAT: CC G.SRT.7 CC G.SRT.8 CC G.MG.1 STA: NC 1.01 TOP: 8-3 Problem 3 Using Inverses KEY: sine 52. ANS: B PTS: 1 DIF: L2 NAT: CC G.SRT.7 CC G.SRT.8 CC G.MG.1 STA: NC 1.01 TOP: 8-3 Problem 3 Using Inverses KEY: tangent 53. ANS: B PTS: 1 DIF: L4 NAT: CC G.SRT.7 CC G.SRT.8 CC G.MG.1 STA: NC 1.01 TOP: 8-3 Problem 3 Using Inverses KEY: tangent 54. ANS: A PTS: 1 DIF: L4 NAT: CC G.SRT.7 CC G.SRT.8 CC G.MG.1 STA: NC 1.01 TOP: 8-3 Problem 3 Using Inverses KEY: sine 55. ANS: D PTS: 1 DIF: L3 NAT: CC G.SRT.8 STA: NC 1.01 TOP: 8-4 Problem 2 Using the Angle of Elevation KEY: sine 4

29 56. ANS: A PTS: 1 DIF: L3 NAT: CC G.SRT.8 STA: NC 1.01 TOP: 8-4 Problem 2 Using the Angle of Elevation KEY: cosine 57. ANS: C PTS: 1 DIF: L3 NAT: CC G.SRT.8 STA: NC 1.01 TOP: 8-4 Problem 2 Using the Angle of Elevation KEY: tangent 58. ANS: A PTS: 1 DIF: L3 NAT: CC G.SRT.8 STA: NC 1.01 TOP: 8-4 Problem 3 Using the Angle of Depression KEY: sine angles of elevation and depression 59. ANS: D PTS: 1 DIF: L3 NAT: CC G.SRT.8 STA: NC 1.01 TOP: 8-4 Problem 3 Using the Angle of Depression KEY: tangent angles of elevation and depression 60. ANS: D PTS: 1 DIF: L4 NAT: CC G.SRT.8 STA: NC 1.01 TOP: 8-4 Problem 2 Using the Angle of Elevation KEY: word problem problem solving tangent angles of elevation and depression 61. ANS: A PTS: 1 DIF: L3 NAT: CC G.SRT.8 STA: NC 1.01 TOP: 8-4 Problem 3 Using the Angle of Depression KEY: tangent angles of elevation and depression word problem problem solving 62. ANS: B PTS: 1 DIF: L3 NAT: CC G.SRT.8 STA: NC 1.01 TOP: 8-4 Problem 3 Using the Angle of Depression KEY: tangent angles of elevation and depression word problem problem solving 63. ANS: A PTS: 1 DIF: L3 NAT: CC G.SRT.8 STA: NC 1.01 TOP: 8-4 Problem 3 Using the Angle of Depression KEY: sine angles of elevation and depression word problem problem solving 64. ANS: B PTS: 1 DIF: L3 NAT: CC G.SRT.10 CC G.SRT.11 TOP: 8-5 Problem 1 Using the Law of Sines (AAS) KEY: Law of Sines 65. ANS: B PTS: 1 DIF: L4 NAT: CC G.SRT.10 CC G.SRT.11 TOP: 8-5 Problem 1 Using the Law of Sines (AAS) KEY: Law of Sines 66. ANS: D PTS: 1 DIF: L3 NAT: CC G.SRT.10 CC G.SRT.11 TOP: 8-5 Problem 1 Using the Law of Sines (AAS) KEY: Law of Sines 67. ANS: D PTS: 1 DIF: L3 NAT: CC G.SRT.10 CC G.SRT.11 TOP: 8-5 Problem 2 Using the Law of Sines (SSA) KEY: Law of Sines 68. ANS: B PTS: 1 DIF: L4 NAT: CC G.SRT.10 CC G.SRT.11 TOP: 8-5 Problem 2 Using the Law of Sines (SSA) KEY: Law of Sines 69. ANS: D PTS: 1 DIF: L4 NAT: CC G.SRT.10 CC G.SRT.11 TOP: 8-5 Problem 2 Using the Law of Sines (SSA) KEY: Law of Sines 70. ANS: C PTS: 1 DIF: L4 NAT: CC G.SRT.10 CC G.SRT.11 TOP: 8-5 Problem 2 Using the Law of Sines (SSA) KEY: Law of Sines 71. ANS: B PTS: 1 DIF: L3 NAT: CC G.SRT.10 CC G.SRT.11 TOP: 8-6 Problem 1 Using the Law of Cosines (SAS) KEY: Law of Cosines 72. ANS: C PTS: 1 DIF: L3 NAT: CC G.SRT.10 CC G.SRT.11 TOP: 8-6 Problem 1 Using the Law of Cosines (SAS) KEY: Law of Cosines 73. ANS: B PTS: 1 DIF: L3 NAT: CC G.SRT.10 CC G.SRT.11 TOP: 8-6 Problem 1 Using the Law of Cosines (SAS) KEY: Law of Cosines 74. ANS: A PTS: 1 DIF: L3 NAT: CC G.SRT.10 CC G.SRT.11 TOP: 8-6 Problem 2 Using the Law of Cosines (SSS) KEY: Law of Cosines 5

30 75. ANS: D PTS: 1 DIF: L4 NAT: CC G.SRT.10 CC G.SRT.11 TOP: 8-6 Problem 2 Using the Law of Cosines (SSS) KEY: Law of Cosines 76. ANS: D PTS: 1 DIF: L4 NAT: CC G.SRT.10 CC G.SRT.11 TOP: 8-6 Problem 2 Using the Law of Cosines (SSS) KEY: Law of Cosines 77. ANS: C PTS: 1 DIF: L4 NAT: CC G.SRT.10 CC G.SRT.11 TOP: 8-5 Problem 3 Using the Law of Cosines to Solve a Problem KEY: Law of Cosines 78. ANS: D PTS: 1 DIF: L4 NAT: CC G.SRT.10 CC G.SRT.11 TOP: 8-6 Problem 2 Using the Law of Cosines (SSS) KEY: determine Law of Sines or Law of Cosines problem solving 79. ANS: C PTS: 1 DIF: L4 NAT: CC G.SRT.10 CC G.SRT.11 TOP: 8-5 Problem 1 Using the Law of Sines (AAS) KEY: determine Law of Sines or Law of Cosines SAS problem solving 80. ANS: D PTS: 1 DIF: L4 NAT: CC G.SRT.10 CC G.SRT.11 TOP: 8-6 Problem 2 Using the Law of Cosines (SSS) KEY: determine Law of Sines or Law of Cosines SAS problem solving 6