Unit 2, Quiz 1 (Practice Quiz)
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1 Name: Class: Date: Unit 2, Quiz 1 (Practice Quiz) 1. Researchers randomly choose two groups from 15 volunteers. Over a period of 9 weeks, one group watches television before going to sleep, and the other does not. Volunteers wear monitoring devices while sleeping, and researchers record dream activity. Which type of study method is described in each situation? a. observational study c. controlled experiment b. survey Identify the type of sampling method used. 2. A trucking company places a card with their office phone number on the door step of every home within 5 miles of their office. 3. A candidate for the Senate creates an automated message that calls every third listed phone number and reminds them to vote for him in the upcoming election. Find the mean, median, and mode of the data set. Round to the nearest tenth. 4. 2, 10, 6, 9, 1, 15, 11, 10, 15, 13, 15 a. mean = 8.9, mode = 15 b. mean = 9.7, median = 8, mode =15 c. mean = 9.7, mode = 15 d. mean = 8.9, mode = 8 Find the outlier(s) in the set of data , 4.8, 3.1, 0.2, 6.9, 5.5, 6.6, 5.1 a. 3.1 b. 5.1 c. 0.2 d , 13, 16, 18, 38, 14, 21, 24, 30, 8, 61, 2 a. no outliers b. 2 c. 61 d. 38 and Over the first five years of owning her car, Gina drove about 12,700 miles the first year, 15,478 miles the second year, 12,675 the third year, 11,850 the fourth year, and 13,075 the fifth year. a. Find the mean, median, and mode of this data. b. Explain which measure of central tendency will best predict how many miles Gina will drive in the sixth year. a. mean = 13,156; median = 12,700; no mode; the median is the best choice because it is not skewed by the high outlier. b. mean = 13,156; median = 12,700; mode = 3,628; the median is the best choice because it is not skewed by the high outlier. c. mean = 12,700; median = 13,156; no mode; the mean is the best choice because it is representative of the entire data set. d. mean = 13,156; median = 12,700; no mode; the mean is the best choice because it is representative of the entire data set. 1
2 Name: Make a box-and-whisker plot of the data , 18, 29, 21, 16, 23, 13, 11 a. b. c. d. 9. Average daily temperatures in Tucson, Arizona, in December: 67, 57, 52, 51, 64, 58, 67, 58, 55, 59, 66, 50, 57, 62, 58, 50, 58, 50, 60, 63 What are the mean, variance, and standard deviation of these values? Round to the nearest tenth , 9, 4, 12, 13, 13 a. mean = 10.5 variance = 2.2; standard deviation = 4.6 b. mean = 8.7 variance = 2.2; standard deviation = 5.1 c. mean = 10.5 variance = 21.6; standard deviation = 5.1 d. mean = 8.7 variance = 21.6; standard deviation = , 97, 53, 90, 95, 98 2
3 Name: 12. x x x (x x) a. mean = b. mean = 47.6 variance = 65.3 c. mean = 47.6 d. mean = 47.6 standard deviation = Use a calculator to find the mean and standard deviation of the data. Round to the nearest tenth , 726, 956, 519, 104, 415, 428, 457, 614, 201, 772, 801 a. mean = 566.5; standard deviation = c. mean = 566.5; standard deviation = b. mean = 578.3; standard deviation = d. mean = 578.3; standard deviation = The height (in feet) of a sample of trees in the school playground: 12.5, 9.8, 13.5, 11.2, 12.3, 14.2, 11.7, 9.8, 12.6, A stem and leaf display is shown below. The stem is the tens place and the leaf is the units place. a. 57 c. 62 b. 59 d. 78 3
4 Unit 2, Quiz 1 (Practice Quiz) Answer Section 1. ANS: C PTS: 1 DIF: L2 TOP: 1-3 Problem 2 Analyzing Study Methods KEY: observational study controlled experiment survey 2. ANS: convenience sample PTS: 1 DIF: L3 TOP: 1-3 Problem 1 Analyzing Sampling Methods KEY: sample bias self-selected sample 3. ANS: systematic sample PTS: 1 DIF: L3 TOP: 1-3 Problem 1 Analyzing Sampling Methods KEY: sample bias systematic sample 4. ANS: C PTS: 1 DIF: L2 TOP: 1-1 Problem 1 Finding Measures of Central Tendency KEY: measure of central tendency mean median mode 5. ANS: C PTS: 1 DIF: L2 TOP: 1-1 Problem 2 Identifying an Outlier KEY: outlier 6. ANS: C PTS: 1 DIF: L3 TOP: 1-1 Problem 2 Identifying an Outlier KEY: outlier 7. ANS: A PTS: 1 DIF: L3 TOP: 1-1 Problem 3 Comparing Data Sets KEY: measure of central tendency mean median mode range of a set of data interquartile range 8. ANS: A PTS: 1 DIF: L2 TOP: 1-1 Problem 4 Using a Box-and-Whisker Plot KEY: median quartile box-and-whisker plot 9. ANS: PTS: 1 DIF: L3 TOP: 1-1 Problem 4 Using a Box-and-Whisker Plot KEY: median quartile box-and-whisker plot 10. ANS: D PTS: 1 DIF: L3 NAT: CC S.ID.4 CC S.IC.6 D.1.c 1
5 11. ANS: mean = 87.5 variance = 245.6; standard deviation = 15.7 PTS: 1 DIF: L3 NAT: CC S.ID.4 CC S.IC.6 D.1.c 12. ANS: C PTS: 1 DIF: L2 NAT: CC S.ID.4 CC S.IC.6 D.1.c 13. ANS: D PTS: 1 DIF: L3 NAT: CC S.ID.4 CC S.IC.6 D.1.c TOP: 1-2 Problem 2 Using a Calculator to Find Standard Deviation KEY: mean standard deviation 14. ANS: mean = 11.8 ft; standard deviation = 1.43 ft PTS: 1 DIF: L4 NAT: CC S.ID.4 CC S.IC.6 D.1.c TOP: 1-2 Problem 2 Using a Calculator to Find Standard Deviation KEY: mean standard deviation 15. ANS: B PTS: 1 2
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