Samples of conceptual and analytical/numerical questions from chap 21, C&J, 7E

Size: px
Start display at page:

Download "Samples of conceptual and analytical/numerical questions from chap 21, C&J, 7E"

Transcription

1 CHAPTER 1 Magnetism CONCEPTUAL QUESTIONS Cutnell & Johnson 7E 3. ssm A chaged paticle, passing though a cetain egion of space, has a velocity whose magnitude and diection emain constant, (a) If it is known that the extenal magnetic field is zeo evey whee in this egion, can you conclude that the extenal electic field is also zeo? Explain. (b) If it is known that the extenal electic field is zeo eveywhee, can you conclude that the extenal magnetic field is also zeo? Explain. 3. SSM REASONING AND SOLUTION A chaged paticle, passing though a cetain egion of space, has a velocity whose magnitude and diection emain constant. a. If it is known that the extenal magnetic field is zeo eveywhee in the egion, we can conclude that the electic field is also zeo. Any chaged paticle placed in an electic field will expeience a foce given by = qe, whee q is the chage and E is the electic field. If the magnitude and diection of the velocity of the paticle ae constant, then the paticle has zeo acceleation. om Newton's second law, we know that the net foce on the paticle is zeo. But thee is no magnetic field and, hence, no magnetic foce. Theefoe, the net foce is the electic foce. Since the electic foce is zeo, the electic field must be zeo. b. If it is known that the extenal electic field is zeo eveywhee, we cannot conclude that the extenal magnetic field is also zeo. In ode fo a moving chaged paticle to expeience a magnetic foce when it is placed in a magnetic field, the velocity of the moving chage must have a component that is pependicula to the diection of the magnetic field. If the moving chaged paticle entes the egion such that its velocity is paallel o antipaallel to the magnetic field, it will expeience no magnetic foce, even though a magnetic field is pesent. In the absence of an extenal electic field, thee is no electic foce eithe. Thus, thee is no net foce, and the velocity vecto will not change in any way. 7. The dawing shows a top view of fou inteconnected chambes. A negative chage is fied into chambe 1. By tuning on sepaate magnetic fields in each chambe, the chage can be made to exit fom chambe 4, as shown. (a) Descibe how the magnetic field in each chambe should be diected. (b) If the speed of the chage is v when it entes chambe 1, what is the speed of the chage when it exits chambe 4? Why? Compiled by DJJ Page 1 of 8 9/13/6

2 7. REASONING AND SOLUTION The dawing shows a top view of fou inteconnected chambes. A negative chage is fied into chambe 1. By tuning on sepaate magnetic fields in each chambe, the chage is made to exit fom chambe 4. a. In each chambe the path of the paticle is onequate of a cicle. The dawing at the ight also shows the diection of the centipetal foce that must act on the paticle in each chambe in ode fo the paticle to tavese the path. The chaged 1 paticle can be made to move in a cicula path by launching it into a egion in which thee exists a magnetic field that is pependicula to the velocity of the paticle. Using RHR-1, we see that if the palm of the ight hand wee facing in the diection of in chambe 1 so that the thumb points along the path of the paticle, the finges of the ight hand must point out of the page. This is the diection that the magnetic field must have to make a positive chage move along the path shown in chambe 1. Since the paticle is negatively chaged, the field must point opposite to that diection o into the page. Simila easoning using RHR-1, and emembeing that the paticle is negatively chaged, leads to the following conclusions: in egion the field must point out of the page, in egion 3 the field must point out of the page, and in egion 4 the field must point into the page. b. If the speed of the paticle is v when it entes chambe 1, it will emege fom chambe 4 with the same speed v. The magnetic foce is always pependicula to the velocity of the paticle; theefoe, it cannot do wok on the paticle and cannot change the kinetic enegy of the paticle, accoding to the wok-enegy theoem. Since the kinetic enegy is unchanged, the speed emains constant. 15. o each electomagnet at the left of the dawing, explain whethe it will be attacted to o epelled fom the pemanent magnet at the ight. 4 v q 3 Compiled by DJJ Page of 8 9/13/6

3 15. REASONING AND SOLUTION The figue below shows the aangements of electomagnets and magnets. (a) S N N S (b) S N N S We can detemine the polaity of the electomagnets by using RHR-. Imagine holding the cuent-caying wie of the electomagnet in the ight hand as the wie begins to coil aound the ion coe. The thumb points in the diection of the cuent. o the electomagnet in figue (a), the finges of the ight hand wap aound the wie on the left end so that they point, inside the coil, towad the ight end. Thus, the ight end of the coil must be a noth pole. Simila easoning can be used to identify the noth and south poles of the electomagnet in figue (b). The esults ae shown in the figue above. Since the like poles of two diffeent magnets epel each othe and the dissimila poles of two diffeent magnets attact each othe, we can conclude that in both aangements, the electomagnet is epelled fom the pemanent magnet at the ight. CHAPTER 1 MAGNETIC ORCES AND MAGNETIC IELDS Samples of solutions to Poblems fom chapte 1Cutnell & Johnson 7E 4. When a chaged paticle moves at an angle of 5 with espect to a magnetic field, it expeiences a magnetic foce of magnitude. At what angle (less than 9 ) with espect to this field will this paticle, moving at the same speed, expeience a magnetic foce of magnitude? 4. REASONING Accoding to Equation 1.1, the magnetic foce has a magnitude of = q vb sin θ, whee q is the magnitude of the chage, B is the magnitude of the magnetic field, v is the speed, and θ is the angle of the velocity with espect to the field. As θ inceases fom to 9, the foce inceases. Theefoe, the angle we seek must lie between 5 and 9. Compiled by DJJ Page 3 of 8 9/13/6

4 SOLUTION Letting θ 1 = 5 and θ be the desied angle, we jcan apply Equation 1.1 to both situations as follows: = q vbsin θ and = q vbsinθ 1 Situation 1 Situation Dividing the equation fo situation by the equation fo situation 1 gives qvbsinθ = o sin θ=sin θ1 =sin 5 =.85 q vbsinθ 1 1 ( ) θ = sin.85 = A chaged paticle entes a unifom magnetic field and follows the cicula path shown in the dawing. (a) Is the paticle positively o negatively chaged? Why? (b) The paticle s speed is 14 m/s, the magnitude of the magnetic field is.48 T, and the adius of the path is 96 m. Detemine the mass of the paticle, given that its chage has a magnitude of. 11. REASONING a. The dawing shows the velocity v of the paticle at the top of its path. The magnetic foce, which povides the centipetal foce, must be diected towad the cente of the cicula path. Since the diections of v,, and B ae known, we can use Right-Hand Rule No. 1 (RHR-1) to detemine if the chage is positive o negative. v B (out of pape) b. The adius of the cicula path followed by a chaged paticle is given by Equation 1. as = mv/ q B. The mass m of the paticle can be obtained diectly fom this elation, since all othe vaiables ae known. SOLUTION a. If the paticle wee positively chaged, an application of RHR-1 would show that the foce would be diected staight up, opposite to that shown in the dawing. Thus, the chage on the paticle must be negative. b. Solving Equation 1. fo the mass of the paticle gives ( C)(.48 T)( 96 m) qb 3 m = = =.7 1 kg v 14 m/s Compiled by DJJ Page 4 of 8 9/13/6

5 19. ssm Review Conceptual Example as an aid in undestanding this poblem. The dawing shows a positively chaged paticle enteing a.5-t magnetic field (diected out of the pape). The paticle has a speed of 7 m/s and moves pependicula to the magnetic field. Just as the paticle entes the magnetic field, an electic field is tuned on. What must be the magnitude and diection of the electic field such that the net foce on the paticle is twice the magnetic foce? 19. SSM REASONING AND SOLUTION Accoding to Right-Hand Rule No. 1, the magnetic foce on the positively chaged paticle is towad the bottom of the page in the dawing in the text. If the pesence of the electic field is to double the magnitude of the net foce on the chage, the electic field must also be diected towad the bottom of the page. Note that this esults in the electic field being pependicula to the magnetic field, even though the electic foce and the magnetic foce ae in the same diection. uthemoe, if the magnitude of the net foce on the paticle is twice the magnetic foce, the electic foce must be equal in magnitude to the magnetic foce. In othe wods, combining Equations 18. and 1.1, we find qe= qvbsinθ, with sinθ = sin 9. =1.. Then, solving fo E E = vbsin θ = ( 7 m / s)(.5 T)(1.) = 14 V / m 9. A squae coil of wie containing a single tun is placed in a unifom.5-t magnetic field, as the dawing shows. Each side has a length of.3 m, and the cuent in the coil is 1 A. Detemine the magnitude of the magnetic foce on each of the fou sides. 9. REASONING AND SOLUTION The foce on each side can be found fom = ILB sin θ. o the top side, θ = 9., so = (1 A)(.3 m)(.5 T) sin 9. =.96 N The foce on the bottom side (θ = 9. ) is the same as that on the top side, =.96 N. o each of the othe two sides θ =, so that the foce is = N. Compiled by DJJ Page 5 of 8 9/13/6

6 41. ssm www The ectangula loop in the dawing consists of 75 tuns and caies a cuent of I = 4.4 A. A 1.8-T magnetic field is diected along the +y axis. The loop is fee to otate about the z axis. (a) Detemine the magnitude of the net toque exeted on the loop and (b) state whethe the 35 angle will incease o decease. 41. SSM WWW REASONING The toque on the loop is given by Equation 1.4, τ = NIABsinφ. om the dawing in the text, we see that the angle φ between the nomal to the plane of the loop and the magnetic field is 9 35 = 55. The aea of the loop is.7 m.5 m =.35 m. SOLUTION a. The magnitude of the net toque exeted on the loop is τ = NIAB sin φ = (75)(4.4 A)(.35 m )(1.8 T) sin 55 = 17 N m b. As discussed in the text, when a cuent-caying loop is placed in a magnetic field, the loop tends to otate such that its nomal becomes aligned with the magnetic field. The nomal to the loop makes an angle of 55 with espect to the magnetic field. Since this angle deceases as the loop otates, the 35 angle inceases. 59. The dawing shows an end-on view of thee wies. They ae long, staight, and pependicula to the plane of the pape. Thei coss sections lie at the cones of a squae. The cuents in wies 1 and ae I 1 = I = I and ae diected into the pape. What is the diection of the cuent in wie 3, and what is the atio I 3 /I, such that the net magnetic field at the empty cone is zeo? 59. REASONING AND SOLUTION The cuents in wies 1 and poduce the magnetic fields B 1 and B at the empty cone, as shown in the following dawing. The diections of these fields can be obtained using RHR-. Since thee ae equal cuents in wies 1 and and since these wies ae each the same distance fom the empty cone, B 1 and B have equal magnitudes. Using Equation 1.5, we can wite the field magnitude as B = B = µ I 1 /b g. Since the fields B 1 and B ae pependicula, it follows fom the Pythagoean theoem that they combine to poduce a net magnetic field that has the diection shown in the dawing at the ight and has a magnitude B 1+ given by Compiled by DJJ Page 6 of 8 9/13/6

7 B B B = + = H G I + KJ H G I K J = µ I µ I µ I The cuent in wie 3 poduces a field B 3 at the empty cone. Since B 3 and B 1+ combine to give a zeo net field, B 3 must have a diection opposite to that of B 1+. Thus, B 3 must point upwad and to the left, and RHR- indicates that B 3 Wie 1 X B 1 X Wie 3 Wie B B 1+ B the cuent in wie 3 must be diected out of the plane of the pape. Moeove, the magnitudes of B 3 and B 1+ must be the same. Recognizing that wie 3 is a distance of d = + = fom the empty cone, we have µ I µ I I 3 3 = B o = so that = + I 3 1 d i 6. The wie in igue 1.4 caies a cuent of 1 A. Suppose that a second long, staight wie is placed ight next to this wie. The cuent in the second wie is 8 A. Use Ampèe s law to find the magnitude of the magnetic field at a distance of =.7 m fom the wies when the cuents ae (a) in the same diection and (b) in opposite diections. 6. REASONING Since the two wies ae next to each othe, the net magnetic field is eveywhee paallel to in igue 1.4. Moeove, the net magnetic field B has the same magnitude B at each point along the cicula path, because each point is at the same distance fom the wies. Thus, in Ampèe's law (Equation 1.8), B = B, I = I1+ I, and we have ( ) µ ( ) ΣB = B Σ = I + I 1 But Σ is just the cicumfeence () of the cicle, so Ampèe's law becomes This expession can be solved fo B. ( ) = µ ( + ) B I I 1 SOLUTION a. When the cuents ae in the same diection, we find that Compiled by DJJ Page 7 of 8 9/13/6

8 7 ( ) ( )( ) I1+ I 4π 1 T m/a 8A+ 1A 5 µ B = = = T.7 m ( ) b. When the cuents have opposite diections, a simila calculation shows that 7 ( ) ( )( ) I1 I 4π 1 T m/a 8 A 1 A 6 µ B = = = T.7 m ( ) 65. ssm A long solenoid has 14 tuns pe mete of length, and it caies a cuent of 3.5 A. A small cicula coil of wie is placed in side the solenoid with the nomal to the coil oiented at an angle of 9. with espect to the axis of the solenoid. The coil consists of 5 tuns, has an aea of m, and caies a cuent of.5 A. ind the toque exeted on the coil. 65. SSM REASONING The coil caies a cuent and expeiences a toque when it is placed in an extenal magnetic field. Thus, when the coil is placed in the magnetic field due to the solenoid, it will expeience a toque given by Equation 1.4: τ = NIABsinφ, whee N is the numbe of tuns in the coil, A is the aea of the coil, B is the magnetic field inside the solenoid, and φ is the angle between the nomal to the plane of the coil and the magnetic field. The magnetic field in the solenoid can be found fom Equation 1.7: B = µ ni, whee n is the numbe of tuns pe unit length of the solenoid and I is the cuent. SOLUTION The magnetic field inside the solenoid is ( ) 7 3 B= µ ni = (4π 1 T m/a) 14 tuns/m (3.5 A)=6. 1 T The toque exeted on the coil is τ = NIABsin φ = (5)(.5 A)(1. 1 m )(6. 1 T)(sin 9. )= N m Compiled by DJJ Page 8 of 8 9/13/6

Magnetism: a new force!

Magnetism: a new force! -1 Magnetism: a new foce! o fa, we'e leaned about two foces: gaity and the electic field foce. F E = E, FE = E Definition of E-field kq E-fields ae ceated by chages: E = 2 E-field exets a foce on othe

More information

Forces & Magnetic Dipoles. r r τ = μ B r

Forces & Magnetic Dipoles. r r τ = μ B r Foces & Magnetic Dipoles x θ F θ F. = AI τ = U = Fist electic moto invented by Faaday, 1821 Wie with cuent flow (in cup of Hg) otates aound a a magnet Faaday s moto Wie with cuent otates aound a Pemanent

More information

Problem Set 6: Solutions

Problem Set 6: Solutions UNIVESITY OF ALABAMA Depatment of Physics and Astonomy PH 16-4 / LeClai Fall 28 Poblem Set 6: Solutions 1. Seway 29.55 Potons having a kinetic enegy of 5. MeV ae moving in the positive x diection and ente

More information

Problems on Force Exerted by a Magnetic Fields from Ch 26 T&M

Problems on Force Exerted by a Magnetic Fields from Ch 26 T&M Poblems on oce Exeted by a Magnetic ields fom Ch 6 TM Poblem 6.7 A cuent-caying wie is bent into a semicicula loop of adius that lies in the xy plane. Thee is a unifom magnetic field B Bk pependicula to

More information

AP Physics Electromagnetic Wrap Up

AP Physics Electromagnetic Wrap Up AP Physics Electomagnetic Wap Up Hee ae the gloious equations fo this wondeful section. F qsin This is the equation fo the magnetic foce acting on a moing chaged paticle in a magnetic field. The angle

More information

Magnetic Field and Magnetic Forces. Young and Freedman Chapter 27

Magnetic Field and Magnetic Forces. Young and Freedman Chapter 27 Magnetic Field and Magnetic Foces Young and Feedman Chapte 27 Intoduction Reiew - electic fields 1) A chage (o collection of chages) poduces an electic field in the space aound it. 2) The electic field

More information

Chapter F. Magnetism. Blinn College - Physics Terry Honan

Chapter F. Magnetism. Blinn College - Physics Terry Honan Chapte F Magnetism Blinn College - Physics 46 - Tey Honan F. - Magnetic Dipoles and Magnetic Fields Electomagnetic Duality Thee ae two types of "magnetic chage" o poles, Noth poles N and South poles S.

More information

Physics 107 HOMEWORK ASSIGNMENT #14

Physics 107 HOMEWORK ASSIGNMENT #14 Physics 107 HOMEWORK ASSIGNMENT #14 Cutnell & Johnson, 7 th edition Chapte 17: Poblem 44, 60 Chapte 18: Poblems 14, 18, 8 **44 A tube, open at only one end, is cut into two shote (nonequal) lengths. The

More information

So we ll start with Angular Measure. Consider a particle moving in a circular path. (p. 220, Figure 7.1)

So we ll start with Angular Measure. Consider a particle moving in a circular path. (p. 220, Figure 7.1) Lectue 17 Cicula Motion (Chapte 7) Angula Measue Angula Speed and Velocity Angula Acceleation We ve aleady dealt with cicula motion somewhat. Recall we leaned about centipetal acceleation: when you swing

More information

12. Rolling, Torque, and Angular Momentum

12. Rolling, Torque, and Angular Momentum 12. olling, Toque, and Angula Momentum 1 olling Motion: A motion that is a combination of otational and tanslational motion, e.g. a wheel olling down the oad. Will only conside olling with out slipping.

More information

Chapter 30: Magnetic Fields Due to Currents

Chapter 30: Magnetic Fields Due to Currents d Chapte 3: Magnetic Field Due to Cuent A moving electic chage ceate a magnetic field. One of the moe pactical way of geneating a lage magnetic field (.1-1 T) i to ue a lage cuent flowing though a wie.

More information

The force between electric charges. Comparing gravity and the interaction between charges. Coulomb s Law. Forces between two charges

The force between electric charges. Comparing gravity and the interaction between charges. Coulomb s Law. Forces between two charges The foce between electic chages Coulomb s Law Two chaged objects, of chage q and Q, sepaated by a distance, exet a foce on one anothe. The magnitude of this foce is given by: kqq Coulomb s Law: F whee

More information

Solution Derivations for Capa #8

Solution Derivations for Capa #8 Solution Deivations fo Capa #8 1) A ass spectoete applies a voltage of 2.00 kv to acceleate a singly chaged ion (+e). A 0.400 T field then bends the ion into a cicula path of adius 0.305. What is the ass

More information

General Physics (PHY 2130)

General Physics (PHY 2130) Geneal Physics (PHY 130) Lectue 11 Rotational kinematics and unifom cicula motion Angula displacement Angula speed and acceleation http://www.physics.wayne.edu/~apetov/phy130/ Lightning Review Last lectue:

More information

Chapter 23: Gauss s Law

Chapter 23: Gauss s Law Chapte 3: Gauss s Law Homewok: Read Chapte 3 Questions, 5, 1 Poblems 1, 5, 3 Gauss s Law Gauss s Law is the fist of the fou Maxwell Equations which summaize all of electomagnetic theoy. Gauss s Law gives

More information

2008 Quarter-Final Exam Solutions

2008 Quarter-Final Exam Solutions 2008 Quate-final Exam - Solutions 1 2008 Quate-Final Exam Solutions 1 A chaged paticle with chage q and mass m stats with an initial kinetic enegy K at the middle of a unifomly chaged spheical egion of

More information

Magnetism. The Magnetic Force. B x x x x x x x x x x x x v x x x x x x. F = q

Magnetism. The Magnetic Force. B x x x x x x x x x x x x v x x x x x x. F = q Magnetism The Magnetic Foce F = qe + qv x x x x x x x x x x x x v x x x x x x F q v q F v F = q 0 IM intoduced the fist had disk in 1957, when data usually was stoed on tapes. It consisted of 50 plattes,

More information

FXA 2008. Candidates should be able to : Describe how a mass creates a gravitational field in the space around it.

FXA 2008. Candidates should be able to : Describe how a mass creates a gravitational field in the space around it. Candidates should be able to : Descibe how a mass ceates a gavitational field in the space aound it. Define gavitational field stength as foce pe unit mass. Define and use the peiod of an object descibing

More information

Chapter 13 Gravitation. Problems: 1, 4, 5, 7, 18, 19, 25, 29, 31, 33, 43

Chapter 13 Gravitation. Problems: 1, 4, 5, 7, 18, 19, 25, 29, 31, 33, 43 Chapte 13 Gavitation Poblems: 1, 4, 5, 7, 18, 19, 5, 9, 31, 33, 43 Evey object in the univese attacts evey othe object. This is called gavitation. We e use to dealing with falling bodies nea the Eath.

More information

XIIth PHYSICS (C2, G2, C, G) Solution

XIIth PHYSICS (C2, G2, C, G) Solution XIIth PHYSICS (C, G, C, G) -6- Solution. A 5 W, 0 V bulb and a 00 W, 0 V bulb ae connected in paallel acoss a 0 V line nly 00 watt bulb will fuse nly 5 watt bulb will fuse Both bulbs will fuse None of

More information

Revision Guide for Chapter 11

Revision Guide for Chapter 11 Revision Guide fo Chapte 11 Contents Student s Checklist Revision Notes Momentum... 4 Newton's laws of motion... 4 Gavitational field... 5 Gavitational potential... 6 Motion in a cicle... 7 Summay Diagams

More information

mv2. Equating the two gives 4! 2. The angular velocity is the angle swept per GM (2! )2 4! 2 " 2 = GM . Combining the results we get !

mv2. Equating the two gives 4! 2. The angular velocity is the angle swept per GM (2! )2 4! 2  2 = GM . Combining the results we get ! Chapte. he net foce on the satellite is F = G Mm and this plays the ole of the centipetal foce on the satellite i.e. mv mv. Equating the two gives = G Mm i.e. v = G M. Fo cicula motion we have that v =!

More information

PHYSICS 111 HOMEWORK SOLUTION #5. March 3, 2013

PHYSICS 111 HOMEWORK SOLUTION #5. March 3, 2013 PHYSICS 111 HOMEWORK SOLUTION #5 Mach 3, 2013 0.1 You 3.80-kg physics book is placed next to you on the hoizontal seat of you ca. The coefficient of static fiction between the book and the seat is 0.650,

More information

Voltage ( = Electric Potential )

Voltage ( = Electric Potential ) V-1 Voltage ( = Electic Potential ) An electic chage altes the space aound it. Thoughout the space aound evey chage is a vecto thing called the electic field. Also filling the space aound evey chage is

More information

AP-C Magnetism. AP-C Objectives (from College Board Learning Objectives for AP Physics)

AP-C Magnetism. AP-C Objectives (from College Board Learning Objectives for AP Physics) AP-C Magnetism AP-C (fom Coege oad Leaning fo AP Physics) 1. oces on moving chages in magnetic fieds a. Cacuate the magnitude and diection of the foce in tems of q, v, and, and expain why the magnetic

More information

Chapter 26 - Electric Field. A PowerPoint Presentation by Paul E. Tippens, Professor of Physics Southern Polytechnic State University

Chapter 26 - Electric Field. A PowerPoint Presentation by Paul E. Tippens, Professor of Physics Southern Polytechnic State University Chapte 6 lectic Field A PowePoint Pesentation by Paul. Tippens, Pofesso of Physics Southen Polytechnic State Univesity 7 Objectives: Afte finishing this unit you should be able to: Define the electic field

More information

Vector Calculus: Are you ready? Vectors in 2D and 3D Space: Review

Vector Calculus: Are you ready? Vectors in 2D and 3D Space: Review Vecto Calculus: Ae you eady? Vectos in D and 3D Space: Review Pupose: Make cetain that you can define, and use in context, vecto tems, concepts and fomulas listed below: Section 7.-7. find the vecto defined

More information

PY1052 Problem Set 8 Autumn 2004 Solutions

PY1052 Problem Set 8 Autumn 2004 Solutions PY052 Poblem Set 8 Autumn 2004 Solutions H h () A solid ball stats fom est at the uppe end of the tack shown and olls without slipping until it olls off the ight-hand end. If H 6.0 m and h 2.0 m, what

More information

Experiment 6: Centripetal Force

Experiment 6: Centripetal Force Name Section Date Intoduction Expeiment 6: Centipetal oce This expeiment is concened with the foce necessay to keep an object moving in a constant cicula path. Accoding to Newton s fist law of motion thee

More information

MAGNETIC FIELDS AND FORCES 24

MAGNETIC FIELDS AND FORCES 24 MAGNETIC FIELDS AND FORCES 24 Q24.1. Reason: When a ba magnet is bought nea the cente of anothe ba magnet as shown in Figue Q24.1, the foce between the ba magnets is zeo. The attactive foce between the

More information

Gauss Law. Physics 231 Lecture 2-1

Gauss Law. Physics 231 Lecture 2-1 Gauss Law Physics 31 Lectue -1 lectic Field Lines The numbe of field lines, also known as lines of foce, ae elated to stength of the electic field Moe appopiately it is the numbe of field lines cossing

More information

PY1052 Problem Set 3 Autumn 2004 Solutions

PY1052 Problem Set 3 Autumn 2004 Solutions PY1052 Poblem Set 3 Autumn 2004 Solutions C F = 8 N F = 25 N 1 2 A A (1) A foce F 1 = 8 N is exeted hoizontally on block A, which has a mass of 4.5 kg. The coefficient of static fiction between A and the

More information

Solutions to Homework Set #5 Phys2414 Fall 2005

Solutions to Homework Set #5 Phys2414 Fall 2005 Solution Set #5 1 Solutions to Homewok Set #5 Phys414 Fall 005 Note: The numbes in the boxes coespond to those that ae geneated by WebAssign. The numbes on you individual assignment will vay. Any calculated

More information

Physics: Electromagnetism Spring PROBLEM SET 6 Solutions

Physics: Electromagnetism Spring PROBLEM SET 6 Solutions Physics: Electomagnetism Sping 7 Physics: Electomagnetism Sping 7 PROBEM SET 6 Solutions Electostatic Enegy Basics: Wolfson and Pasachoff h 6 Poblem 7 p 679 Thee ae si diffeent pais of equal chages and

More information

Chapter 13 Gravitation

Chapter 13 Gravitation Chapte 13 Gavitation Newton, who extended the concept of inetia to all bodies, ealized that the moon is acceleating and is theefoe subject to a centipetal foce. He guessed that the foce that keeps the

More information

Lesson 9 Dipoles and Magnets

Lesson 9 Dipoles and Magnets Lesson 9 Dipoles and Magnets Lawence B. Rees 007. You may make a single copy of this document fo pesonal use without witten pemission. 9.0 Intoduction In this chapte we will lean about an assotment of

More information

Mon., 3/9 Tues., 3/10 Wed., 3/11 Thurs., 3/12 Fri., 3/ 13. RE19 HW19:RQ.42, 49, 52; P.61, 66, 69 RE20, Exp new RE ,3-4 Magnetic Force

Mon., 3/9 Tues., 3/10 Wed., 3/11 Thurs., 3/12 Fri., 3/ 13. RE19 HW19:RQ.42, 49, 52; P.61, 66, 69 RE20, Exp new RE ,3-4 Magnetic Force Mon., 3/9 Tues., 3/10 Wed., 3/11 Thus., 3/12 Fi., 3/ 13 Mon., 3/16 Tues., 3/17 Wed., 3/18 Thus., 3/19 Fi., 3/20 20.1,3-4 Magnetic Foce 20.2,5 Cuent and Motional Emf Quiz Ch 19, Lab 8 Cycloton & Electon

More information

GRAVITATIONAL FIELD: CHAPTER 11. The groundwork for Newton s great contribution to understanding gravity was laid by three majors players:

GRAVITATIONAL FIELD: CHAPTER 11. The groundwork for Newton s great contribution to understanding gravity was laid by three majors players: CHAPT 11 TH GAVITATIONAL FILD (GAVITY) GAVITATIONAL FILD: The goundwok fo Newton s geat contibution to undestanding gavity was laid by thee majos playes: Newton s Law of Gavitation o gavitational and inetial

More information

Gauss Law in dielectrics

Gauss Law in dielectrics Gauss Law in dielectics We fist deive the diffeential fom of Gauss s law in the pesence of a dielectic. Recall, the diffeential fom of Gauss Law is This law is always tue. E In the pesence of dielectics,

More information

Introduction to Electric Potential

Introduction to Electric Potential Univesiti Teknologi MARA Fakulti Sains Gunaan Intoduction to Electic Potential : A Physical Science Activity Name: HP: Lab # 3: The goal of today s activity is fo you to exploe and descibe the electic

More information

Lab 5: Circular Motion

Lab 5: Circular Motion Lab 5: Cicula motion Physics 193 Fall 2006 Lab 5: Cicula Motion I. Intoduction The lab today involves the analysis of objects that ae moving in a cicle. Newton s second law as applied to cicula motion

More information

8-1 Newton s Law of Universal Gravitation

8-1 Newton s Law of Universal Gravitation 8-1 Newton s Law of Univesal Gavitation One of the most famous stoies of all time is the stoy of Isaac Newton sitting unde an apple tee and being hit on the head by a falling apple. It was this event,

More information

F = kq 1q 2 r 2. F 13 = k( q)(2q) 2a 2 cosθˆx + sinθŷ F 14 = k( 2q)(2q) F 12 = k(q)(2q) a 2. tanθ = a a

F = kq 1q 2 r 2. F 13 = k( q)(2q) 2a 2 cosθˆx + sinθŷ F 14 = k( 2q)(2q) F 12 = k(q)(2q) a 2. tanθ = a a .1 What ae the hoizontal and vetical components of the esultant electostatic foce on the chage in the lowe left cone of the squae if q =1. 1 7 and a =5.cm? +q -q a +q a -q F = kq 1q F 1 = k(q)(q) a F 13

More information

Chapter 22. Outside a uniformly charged sphere, the field looks like that of a point charge at the center of the sphere.

Chapter 22. Outside a uniformly charged sphere, the field looks like that of a point charge at the center of the sphere. Chapte.3 What is the magnitude of a point chage whose electic field 5 cm away has the magnitude of.n/c. E E 5.56 1 11 C.5 An atom of plutonium-39 has a nuclea adius of 6.64 fm and atomic numbe Z94. Assuming

More information

Voltage ( = Electric Potential )

Voltage ( = Electric Potential ) V-1 of 9 Voltage ( = lectic Potential ) An electic chage altes the space aound it. Thoughout the space aound evey chage is a vecto thing called the electic field. Also filling the space aound evey chage

More information

Experiment MF Magnetic Force

Experiment MF Magnetic Force Expeiment MF Magnetic Foce Intoduction The magnetic foce on a cuent-caying conducto is basic to evey electic moto -- tuning the hands of electic watches and clocks, tanspoting tape in Walkmans, stating

More information

Hour Exam No.1. p 1 v. p = e 0 + v^b. Note that the probe is moving in the direction of the unit vector ^b so the velocity vector is just ~v = v^b and

Hour Exam No.1. p 1 v. p = e 0 + v^b. Note that the probe is moving in the direction of the unit vector ^b so the velocity vector is just ~v = v^b and Hou Exam No. Please attempt all of the following poblems befoe the due date. All poblems count the same even though some ae moe complex than othes. Assume that c units ae used thoughout. Poblem A photon

More information

1.1 KINEMATIC RELATIONSHIPS

1.1 KINEMATIC RELATIONSHIPS 1.1 KINEMATIC RELATIONSHIPS Thoughout the Advanced Highe Physics couse calculus techniques will be used. These techniques ae vey poweful and knowledge of integation and diffeentiation will allow a deepe

More information

7 Circular Motion. 7-1 Centripetal Acceleration and Force. Period, Frequency, and Speed. Vocabulary

7 Circular Motion. 7-1 Centripetal Acceleration and Force. Period, Frequency, and Speed. Vocabulary 7 Cicula Motion 7-1 Centipetal Acceleation and Foce Peiod, Fequency, and Speed Vocabulay Vocabulay Peiod: he time it takes fo one full otation o evolution of an object. Fequency: he numbe of otations o

More information

Section 5-3 Angles and Their Measure

Section 5-3 Angles and Their Measure 5 5 TRIGONOMETRIC FUNCTIONS Section 5- Angles and Thei Measue Angles Degees and Radian Measue Fom Degees to Radians and Vice Vesa In this section, we intoduce the idea of angle and two measues of angles,

More information

Physics 111 Fall 2007 Electrostatic Forces and the Electric Field - Solutions

Physics 111 Fall 2007 Electrostatic Forces and the Electric Field - Solutions Physics 111 Fall 007 Electostatic Foces an the Electic Fiel - Solutions 1. Two point chages, 5 µc an -8 µc ae 1. m apat. Whee shoul a thi chage, equal to 5 µc, be place to make the electic fiel at the

More information

Exam I. Spring 2004 Serway & Jewett, Chapters 1-5. Fill in the bubble for the correct answer on the answer sheet. next to the number.

Exam I. Spring 2004 Serway & Jewett, Chapters 1-5. Fill in the bubble for the correct answer on the answer sheet. next to the number. Agin/Meye PART I: QUALITATIVE Exam I Sping 2004 Seway & Jewett, Chaptes 1-5 Assigned Seat Numbe Fill in the bubble fo the coect answe on the answe sheet. next to the numbe. NO PARTIAL CREDIT: SUBMIT ONE

More information

Deflection of Electrons by Electric and Magnetic Fields

Deflection of Electrons by Electric and Magnetic Fields Physics 233 Expeiment 42 Deflection of Electons by Electic and Magnetic Fields Refeences Loain, P. and D.R. Coson, Electomagnetism, Pinciples and Applications, 2nd ed., W.H. Feeman, 199. Intoduction An

More information

Your Comments. during the last couple lectures its been getting really noisy and hard to hear, especially for the last couple rows.

Your Comments. during the last couple lectures its been getting really noisy and hard to hear, especially for the last couple rows. You Comments lease explain the ight hand ule when thee ae two wies and ou ae ting to find the diection of the foce I am getting confused with all these ight hand ules So do ou have an age-old advice fo

More information

Gravitation. AP Physics C

Gravitation. AP Physics C Gavitation AP Physics C Newton s Law of Gavitation What causes YOU to be pulled down? THE EARTH.o moe specifically the EARTH S MASS. Anything that has MASS has a gavitational pull towads it. F α Mm g What

More information

2 r2 θ = r2 t. (3.59) The equal area law is the statement that the term in parentheses,

2 r2 θ = r2 t. (3.59) The equal area law is the statement that the term in parentheses, 3.4. KEPLER S LAWS 145 3.4 Keple s laws You ae familia with the idea that one can solve some mechanics poblems using only consevation of enegy and (linea) momentum. Thus, some of what we see as objects

More information

CHAPTER 17 MAGNETIC DIPOLE MOMENT

CHAPTER 17 MAGNETIC DIPOLE MOMENT 1 CHAPTER 17 MAGNETIC DIPOLE MOMENT 17.1 Intoduction A numbe of diffeent units fo expessing magnetic dipole moment (heeafte simply magnetic moment ) ae commonly seen in the liteatue, including, fo example,

More information

Lesson 32: Measuring Circular Motion

Lesson 32: Measuring Circular Motion Lesson 32: Measuing Cicula Motion Velocity hee should be a way to come up with a basic fomula that elates velocity in icle to some of the basic popeties of icle. Let s ty stating off with a fomula that

More information

Physics 235 Chapter 5. Chapter 5 Gravitation

Physics 235 Chapter 5. Chapter 5 Gravitation Chapte 5 Gavitation In this Chapte we will eview the popeties of the gavitational foce. The gavitational foce has been discussed in geat detail in you intoductoy physics couses, and we will pimaily focus

More information

Ch. 8 Universal Gravitation. Part 1: Kepler s Laws. Johannes Kepler. Tycho Brahe. Brahe. Objectives: Section 8.1 Motion in the Heavens and on Earth

Ch. 8 Universal Gravitation. Part 1: Kepler s Laws. Johannes Kepler. Tycho Brahe. Brahe. Objectives: Section 8.1 Motion in the Heavens and on Earth Ch. 8 Univesal Gavitation Pat 1: Keple s Laws Objectives: Section 8.1 Motion in the Heavens and on Eath Objectives Relate Keple s laws of planetay motion to Newton s law of univesal gavitation. Calculate

More information

rotation -- Conservation of mechanical energy for rotation -- Angular momentum -- Conservation of angular momentum

rotation -- Conservation of mechanical energy for rotation -- Angular momentum -- Conservation of angular momentum Final Exam Duing class (1-3:55 pm) on 6/7, Mon Room: 41 FMH (classoom) Bing scientific calculatos No smat phone calculatos l ae allowed. Exam coves eveything leaned in this couse. Review session: Thusday

More information

Geostrophic balance. John Marshall, Alan Plumb and Lodovica Illari. March 4, 2003

Geostrophic balance. John Marshall, Alan Plumb and Lodovica Illari. March 4, 2003 Geostophic balance John Mashall, Alan Plumb and Lodovica Illai Mach 4, 2003 Abstact We descibe the theoy of Geostophic Balance, deive key equations and discuss associated physical balances. 1 1 Geostophic

More information

14. Gravitation Universal Law of Gravitation (Newton):

14. Gravitation Universal Law of Gravitation (Newton): 14. Gavitation 1 Univesal Law of Gavitation (ewton): The attactive foce between two paticles: F = G m 1m 2 2 whee G = 6.67 10 11 m 2 / kg 2 is the univesal gavitational constant. F m 2 m 1 F Paticle #1

More information

Episode 401: Newton s law of universal gravitation

Episode 401: Newton s law of universal gravitation Episode 401: Newton s law of univesal gavitation This episode intoduces Newton s law of univesal gavitation fo point masses, and fo spheical masses, and gets students pactising calculations of the foce

More information

(a) The centripetal acceleration of a point on the equator of the Earth is given by v2. The velocity of the earth can be found by taking the ratio of

(a) The centripetal acceleration of a point on the equator of the Earth is given by v2. The velocity of the earth can be found by taking the ratio of Homewok VI Ch. 7 - Poblems 15, 19, 22, 25, 35, 43, 51. Poblem 15 (a) The centipetal acceleation of a point on the equato of the Eath is given by v2. The velocity of the eath can be found by taking the

More information

Mechanics 1: Work, Power and Kinetic Energy

Mechanics 1: Work, Power and Kinetic Energy Mechanics 1: Wok, Powe and Kinetic Eneg We fist intoduce the ideas of wok and powe. The notion of wok can be viewed as the bidge between Newton s second law, and eneg (which we have et to define and discuss).

More information

Exam 3: Equation Summary

Exam 3: Equation Summary MASSACHUSETTS INSTITUTE OF TECHNOLOGY Depatment of Physics Physics 8.1 TEAL Fall Tem 4 Momentum: p = mv, F t = p, Fext ave t= t f t= Exam 3: Equation Summay total = Impulse: I F( t ) = p Toque: τ = S S,P

More information

TRIGONOMETRY REVIEW. The Cosines and Sines of the Standard Angles

TRIGONOMETRY REVIEW. The Cosines and Sines of the Standard Angles TRIGONOMETRY REVIEW The Cosines and Sines of the Standad Angles P θ = ( cos θ, sin θ ) . ANGLES AND THEIR MEASURE In ode to define the tigonometic functions so that they can be used not only fo tiangula

More information

Seventh Edition DYNAMICS 15Ferdinand P. Beer E. Russell Johnston, Jr. Lecture Notes: J. Walt Oler Texas Tech University

Seventh Edition DYNAMICS 15Ferdinand P. Beer E. Russell Johnston, Jr. Lecture Notes: J. Walt Oler Texas Tech University Seenth 15Fedinand P. ee E. Russell Johnston, J. Kinematics of Lectue Notes: J. Walt Ole Texas Tech Uniesity Rigid odies CHPTER VECTOR MECHNICS FOR ENGINEERS: YNMICS 003 The McGaw-Hill Companies, Inc. ll

More information

Your Comments. did not understand any of this wtf. so over my head I have no idea what I am doing :(

Your Comments. did not understand any of this wtf. so over my head I have no idea what I am doing :( You Comments Llamas, and why it is so difficult to get someone to buy me one as a pet. All ask is that it beathes fie. have simple needs people. Seiously. p.s. this lectue was had. did not undestand any

More information

The Electric Potential, Electric Potential Energy and Energy Conservation. V = U/q 0. V = U/q 0 = -W/q 0 1V [Volt] =1 Nm/C

The Electric Potential, Electric Potential Energy and Energy Conservation. V = U/q 0. V = U/q 0 = -W/q 0 1V [Volt] =1 Nm/C Geneal Physics - PH Winte 6 Bjoen Seipel The Electic Potential, Electic Potential Enegy and Enegy Consevation Electic Potential Enegy U is the enegy of a chaged object in an extenal electic field (Unit

More information

The Role of Gravity in Orbital Motion

The Role of Gravity in Orbital Motion ! The Role of Gavity in Obital Motion Pat of: Inquiy Science with Datmouth Developed by: Chistophe Caoll, Depatment of Physics & Astonomy, Datmouth College Adapted fom: How Gavity Affects Obits (Ohio State

More information

Chapter 4. Gauss s Law

Chapter 4. Gauss s Law Chapte 4 Gauss s Law 4.1 lectic Flux...4-4. Gauss s Law...4-3 xample 4.1: Infinitely Long Rod of Unifom Chage Density...4-8 xample 4.: Infinite Plane of Chage...4-9 xample 4.3: Spheical Shell...4-1 xample

More information

2.2. Trigonometric Ratios of Any Angle. Investigate Trigonometric Ratios for Angles Greater Than 90

2.2. Trigonometric Ratios of Any Angle. Investigate Trigonometric Ratios for Angles Greater Than 90 . Tigonometic Ratios of An Angle Focus on... detemining the distance fom the oigin to a point (, ) on the teminal am of an angle detemining the value of sin, cos, o tan given an point (, ) on the teminal

More information

Algebra and Trig. I. A point is a location or position that has no size or dimension.

Algebra and Trig. I. A point is a location or position that has no size or dimension. Algeba and Tig. I 4.1 Angles and Radian Measues A Point A A B Line AB AB A point is a location o position that has no size o dimension. A line extends indefinitely in both diections and contains an infinite

More information

EXPERIMENT 16 THE MAGNETIC MOMENT OF A BAR MAGNET AND THE HORIZONTAL COMPONENT OF THE EARTH S MAGNETIC FIELD

EXPERIMENT 16 THE MAGNETIC MOMENT OF A BAR MAGNET AND THE HORIZONTAL COMPONENT OF THE EARTH S MAGNETIC FIELD 260 16-1. THEORY EXPERMENT 16 THE MAGNETC MOMENT OF A BAR MAGNET AND THE HORZONTAL COMPONENT OF THE EARTH S MAGNETC FELD The uose of this exeiment is to measue the magnetic moment μ of a ba magnet and

More information

1240 ev nm 2.5 ev. (4) r 2 or mv 2 = ke2

1240 ev nm 2.5 ev. (4) r 2 or mv 2 = ke2 Chapte 5 Example The helium atom has 2 electonic enegy levels: E 3p = 23.1 ev and E 2s = 20.6 ev whee the gound state is E = 0. If an electon makes a tansition fom 3p to 2s, what is the wavelength of the

More information

TORQUE AND ANGULAR MOMENTUM IN CIRCULAR MOTION

TORQUE AND ANGULAR MOMENTUM IN CIRCULAR MOTION MISN-0-34 TORQUE AND ANGULAR MOMENTUM IN CIRCULAR MOTION shaft TORQUE AND ANGULAR MOMENTUM IN CIRCULAR MOTION by Kiby Mogan, Chalotte, Michigan 1. Intoduction..............................................

More information

Moment and couple. In 3-D, because the determination of the distance can be tedious, a vector approach becomes advantageous. r r

Moment and couple. In 3-D, because the determination of the distance can be tedious, a vector approach becomes advantageous. r r Moment and couple In 3-D, because the detemination of the distance can be tedious, a vecto appoach becomes advantageous. o k j i M k j i M o ) ( ) ( ) ( + + M o M + + + + M M + O A Moment about an abita

More information

Learning Objectives. Decreasing size. ~10 3 m. ~10 6 m. ~10 10 m 1/22/2013. Describe ionic, covalent, and metallic, hydrogen, and van der Waals bonds.

Learning Objectives. Decreasing size. ~10 3 m. ~10 6 m. ~10 10 m 1/22/2013. Describe ionic, covalent, and metallic, hydrogen, and van der Waals bonds. Lectue #0 Chapte Atomic Bonding Leaning Objectives Descibe ionic, covalent, and metallic, hydogen, and van de Waals bonds. Which mateials exhibit each of these bonding types? What is coulombic foce of

More information

TALLINN UNIVERSITY OF TECHNOLOGY, INSTITUTE OF PHYSICS 14. NEWTON'S RINGS

TALLINN UNIVERSITY OF TECHNOLOGY, INSTITUTE OF PHYSICS 14. NEWTON'S RINGS 4. NEWTON'S RINGS. Obective Detemining adius of cuvatue of a long focal length plano-convex lens (lage adius of cuvatue).. Equipment needed Measuing micoscope, plano-convex long focal length lens, monochomatic

More information

Set 3: 120 N/m units 0.25 Kg. 1A The unit of the damping constant is a) Kg/s b) N/m c) N d) Joule/s e) NA

Set 3: 120 N/m units 0.25 Kg. 1A The unit of the damping constant is a) Kg/s b) N/m c) N d) Joule/s e) NA 05/05/04 PHYSICS 3 Exa #1 NAME Please wite down you nae also on the back side of this exa 1. Hee ae thee sets of values fo the sping constant k, daping constant b, and ass fo thee daped oscillatos: Set

More information

LINES AND TANGENTS IN POLAR COORDINATES

LINES AND TANGENTS IN POLAR COORDINATES LINES AND TANGENTS IN POLAR COORDINATES ROGER ALEXANDER DEPARTMENT OF MATHEMATICS 1. Pola-coodinate equations fo lines A pola coodinate system in the plane is detemined by a point P, called the pole, and

More information

In this section we shall look at the motion of a projectile MOTION IN FIELDS 9.1 PROJECTILE MOTION PROJECTILE MOTION

In this section we shall look at the motion of a projectile MOTION IN FIELDS 9.1 PROJECTILE MOTION PROJECTILE MOTION MOTION IN FIELDS MOTION IN FIELDS 9 9. Pojectile motion 9. Gavitational field, potential and enegy 9.3 Electic field, potential and enegy 9. PROJECTILE MOTION 9.. State the independence of the vetical

More information

Chapter 2. Electrostatics

Chapter 2. Electrostatics Chapte. Electostatics.. The Electostatic Field To calculate the foce exeted by some electic chages,,, 3,... (the souce chages) on anothe chage Q (the test chage) we can use the pinciple of supeposition.

More information

Ch. 14: Gravitation (Beta Version 7/01) 14 Gravitation

Ch. 14: Gravitation (Beta Version 7/01) 14 Gravitation Ch. 14: Gavitation (Beta Vesion 7/01) 14 Gavitation The Milky Way galaxy is a disk-shaped collection of dust, planets, and billions of stas, including ou Sun and sola system. The foce that binds it o any

More information

Copyright 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley.

Copyright 2008 Pearson Education, Inc., publishing as Pearson Addison-Wesley. Chapte 5. Foce and Motion In this chapte we study causes of motion: Why does the windsufe blast acoss the wate in the way he does? The combined foces of the wind, wate, and gavity acceleate him accoding

More information

Chapter 19: Electric Charges, Forces, and Fields ( ) ( 6 )( 6

Chapter 19: Electric Charges, Forces, and Fields ( ) ( 6 )( 6 Chapte 9 lectic Chages, Foces, an Fiels 6 9. One in a million (0 ) ogen molecules in a containe has lost an electon. We assume that the lost electons have been emove fom the gas altogethe. Fin the numbe

More information

Chapter 3: Vectors and Coordinate Systems

Chapter 3: Vectors and Coordinate Systems Coodinate Systems Chapte 3: Vectos and Coodinate Systems Used to descibe the position of a point in space Coodinate system consists of a fied efeence point called the oigin specific aes with scales and

More information

Multiple choice questions [60 points]

Multiple choice questions [60 points] 1 Multiple choice questions [60 points] Answe all o the ollowing questions. Read each question caeully. Fill the coect bubble on you scanton sheet. Each question has exactly one coect answe. All questions

More information

2 - ELECTROSTATIC POTENTIAL AND CAPACITANCE Page 1

2 - ELECTROSTATIC POTENTIAL AND CAPACITANCE Page 1 - ELECTROSTATIC POTENTIAL AND CAPACITANCE Page. Line Integal of Electic Field If a unit positive chage is displaced by `given by dw E. dl dl in an electic field of intensity E, wok done is Line integation

More information

Gauss s Law. Figure 22.1 A great white shark can detect tiny electric fields generated by its prey.

Gauss s Law. Figure 22.1 A great white shark can detect tiny electric fields generated by its prey. lectic Fields and Gauss s Law What We Will Lean 711.1 Definition of an lectic Field 711. Field Lines 71 Point Chage 71 Two Point Chages of Opposite Sign 71 Two Point Chages with the Same Sign 71 Geneal

More information

Chapter 22 The Electric Field II: Continuous Charge Distributions

Chapter 22 The Electric Field II: Continuous Charge Distributions Chapte The lectic Field II: Continuous Chage Distibutions 1 [M] A unifom line chage that has a linea chage density l equal to.5 nc/m is on the x axis between x and x 5. m. (a) What is its total chage?

More information

The Grating Spectrometer and Atomic Spectra

The Grating Spectrometer and Atomic Spectra PHY 19 Gating Spectomete 1 The Gating Spectomete and Atomic Specta Intoduction In the pevious expeiment diffaction and intefeence wee discussed and at the end a diffaction gating was intoduced. In this

More information

L19 Geomagnetic Field Part I

L19 Geomagnetic Field Part I Intoduction to Geophysics L19-1 L19 Geomagnetic Field Pat I 1. Intoduction We now stat the last majo topic o this class which is magnetic ields and measuing the magnetic popeties o mateials. As a way o

More information

Rotation. Problem solving strategy is the same as for problems with linear motion... Rotation

Rotation. Problem solving strategy is the same as for problems with linear motion... Rotation Rotation The basic quantity in otation is the angula displacement simila ole to the linea displacement studied in chapte units: adians, eolutions, degees, θ Poblem soling stategy is the same as fo poblems

More information

Mechanics 1: Motion in a Central Force Field

Mechanics 1: Motion in a Central Force Field Mechanics : Motion in a Cental Foce Field We now stud the popeties of a paticle of (constant) ass oving in a paticula tpe of foce field, a cental foce field. Cental foces ae ve ipotant in phsics and engineeing.

More information

Space-Time Structure, Newton s Laws and Galilean Transformation

Space-Time Structure, Newton s Laws and Galilean Transformation Chapte 1 Space-Time Stuctue, Newton s Laws and Galilean Tansfomation What is motion? The phase change of position with time expesses the basic idea of motion. We say that an object is moving if it occupies

More information

UNIT CIRCLE TRIGONOMETRY

UNIT CIRCLE TRIGONOMETRY UNIT CIRCLE TRIGONOMETRY The Unit Cicle is the cicle centeed at the oigin with adius unit (hence, the unit cicle. The equation of this cicle is + =. A diagam of the unit cicle is shown below: + = - - -

More information