# Perimeter and Area of Similar Figures

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1 11.3 erimeter and Area of Similar igures Before You used ratios to find perimeters of similar figures. Now You will use ratios to find areas of similar figures. Why So you can apply similarity in cooking, as in xample 3. Key Vocabulary regular polygon, p. 43 corresponding sides, p. 5 similar polygons, p. 37 In Chapter 6 you learned that if two polygons are similar, then the ratio of their perimeters, or of any two corresponding lengths, is equal to the ratio of their corresponding side lengths. As shown below, the areas have a different ratio. Ratio of perimeters Blue } Red 5 10t } 10 5 t Ratio of areas Blue } Red 5 6t } 6 5 t 3 3t t THORM or Your Notebook THORM 11.7 Areas of Similar olygons If two polygons are similar with the lengths of corresponding sides in the ratio of a : b, then the ratio of their areas is a : b. Side length of olygon I }}} Side length of olygon II 5 a } b Area of olygon I }} 5 } a Area of olygon II b a I b II Justification: x. 30, p. 74 olygon I, olygon II X A M L 1 ind ratios of similar polygons In the diagram, n ABC, n. ind the indicated ratio. INTRRT RATIOS You can also compare the measures with fractions. The perimeter of n ABC is two thirds of the perimeter of n. The area of n ABC is four ninths of the area of n. a. Ratio (red to blue) of the perimeters B b. Ratio (red to blue) of the areas 8 1 A C Solution The ratio of the lengths of corresponding sides is } 8 5 }, or : a. By Theorem 6.1 on page 374, the ratio of the perimeters is : 3. b. By Theorem 11.7 above, the ratio of the areas is : 3, or 4 : erimeter and Area of Similar igures 737

2 X A M L Standardized Test ractice You are installing the same carpet in a bedroom and den. The floors of the rooms are similar. The carpet for the bedroom costs \$5. Carpet is sold by the square foot. How much does it cost to carpet the den? A \$115 B \$161 C \$315 \$441 US STIMATION The cost for the den is 49 } 5 times the cost for the bedroom. Because 49 } 5 is a little less than, the cost for the den is a little less than twice \$5. The only possible choice is. Solution The ratio of a side length of the den to the corresponding side length of the bedroom is 14 : 10, or 7 : 5. So, the ratio of the areas is 7 : 5, or 49 : 5. This ratio is also the ratio of the carpeting costs. Let x be the cost for the den. 49 } 5 5 x } 5 x Solve for x. cost of carpet for den cost of carpet for bedroom c It costs \$441 to carpet the den. The correct answer is.abc GUI RACTIC for xamples 1 and 1. The perimeter of n ABC is 16 feet, and its area is 64 feet. The perimeter of n is 1 feet. Given n ABC, n, find the ratio of the area of n ABC to the area of n. Then find the area of n. X A M L 3 Use a ratio of areas COOKING A large rectangular baking pan is 15 inches long and 10 inches wide. A smaller pan is similar to the large pan. The area of the smaller pan is 96 square inches. ind the width of the smaller pan. ANOTHR WAY or an alternative method for solving the problem in xample 3, turn to page 744 for the roblem Solving Workshop. Solution irst draw a diagram to represent the problem. Label dimensions and areas. Then use Theorem If the area ratio is a : b, then the length ratio is a : b. 15 in. A 5 15(10) in. Area of smaller pan }} 5 } 96 5 } 16 Write ratio of known areas. Then simplify. Area of large pan Length in smaller pan }} Length in large pan 5 4 } 5 ind square root of area ratio. 10 in.? A 5 96 in. c Any length in the smaller pan is 4 } 5, or 0.8, of the corresponding length in the large pan. So, the width of the smaller pan is 0.8(10 inches) 5 8 inches. 738 Chapter 11 Measuring Length and Area

3 RGULAR OLYGONS Consider two regular polygons with the same number of sides. All of the angles are congruent. The lengths of all pairs of corresponding sides are in the same ratio. So, any two such polygons are similar. Also, any two circles are similar. X A M L 4 Solve a multi-step problem GAZBO The floor of the gazebo shown is a regular octagon. ach side of the floor is 8 feet, and the area is about 309 square feet. You build a small model gazebo in the shape of a regular octagon. The perimeter of the floor of the model gazebo is 4 inches. ind the area of the floor of the model gazebo to the nearest tenth of a square inch. ANOTHR WAY In Step 1, instead of finding the perimeter of the full-sized and comparing perimeters, you can find the side length of the model and compare side lengths , so the ratio of side lengths is 8 ft. 96 in. } 5} 5 } 3. 3 in. 3 in. 1 Solution All regular octagons are similar, so the floor of the model is similar to the floor of the full-sized gazebo. ST 1 ind the ratio of the lengths of the two floors by finding the ratio of the perimeters. Use the same units for both lengths in the ratio. erimeter of full-sized 8(8 ft) 64 ft 64 ft }} 5} 5} 5 } 5 } 3 erimeter of model 4 in. 4 in. ft 1 So, the ratio of corresponding lengths (full-sized to model) is 3 : 1. ST Calculate the area of the model gazebo s floor. Let x be this area. (Length in full-sized) Area of full-sized }} 5}} Theorem 11.7 (Length in model) Area of model 3 } ft } x ft Substitute. 104x Cross roducts roperty ST 3 Convert the area to square inches ft p x ø 0.30 ft Solve for x. 144 in. } 1 ft ø 43.5 in. c The area of the floor of the model gazebo is about 43.5 square inches. at classzone.com GUI RACTIC for xamples 3 and 4. The ratio of the areas of two regular decagons is 0 : 36. What is the ratio of their corresponding side lengths in simplest radical form? 3. Rectangles I and II are similar. The perimeter of Rectangle I is 66 inches. Rectangle II is 35 feet long and 0 feet wide. Show the steps you would use to find the ratio of the areas and then find the area of Rectangle I erimeter and Area of Similar igures 739

4 11.3 XRCISS SKILL RACTIC HOMWORK KY 5 WORK-OUT SOLUTIONS on p. WS1 for xs. 7, 17, and 7 5 STANARIZ TST RACTIC xs., 1, 18, 8, 3, and VOCABULARY Sketch two similar triangles. Use your sketch to explain what is meant by corresponding side lengths.. WRITING Two regular n-gons are similar. The ratio of their side lengths is is 3 : 4. o you need to know the value of n to find the ratio of the perimeters or the ratio of the areas of the polygons? xplain. XAMLS 1 and on pp for xs. 3 8 INING RATIOS Copy and complete the table of ratios for similar polygons. Ratio of corresponding side lengths Ratio of perimeters Ratio of areas : 11?? 0 : 36 5??? RATIOS AN ARAS Corresponding lengths in similar figures are given. ind the ratios (red to blue) of the perimeters and areas. ind the unknown area. 5. A 5 ft ft 6 ft cm 0 cm A 5 40 cm 7. A 5 10 in. 8. A 5 40 yd 7 in. 9 in. 5 yd 3 yd XAML 3 on p. 738 for xs INING LNGTH RATIOS The ratio of the areas of two similar figures is given. Write the ratio of the lengths of corresponding sides. 9. Ratio of areas 5 49 : Ratio of areas 5 16: Ratio of areas 5 11 : MULTIL CHOIC The area of n LMN is 18 ft and the area of n GH is 4 ft. If n LMN, n GH, what is the ratio of LM to G? A 3 : 4 B 9 : 16 C Ï } 3 : 4 : 3 INING SI LNGTHS Use the given area to find XY. 13. n, n XYZ 14. UVWXY, LMNQ 4 cm A 5 7 cm X Y Z A 5 8 cm U V A in. Y W X L A 5 88 in. N M 10 in. 740 Chapter 11 Measuring Length and Area

5 15. RROR ANALYSIS In the diagram, Rectangles G and WXYZ are similar. The ratio of the area of G to the area of WXYZ is 1 : 4. escribe and correct the error in finding ZY. W G 1 Z Y ZY 5 4(1) 5 48 X XAML 4 on p. 739 for xs RGULAR NTAGONS Regular pentagon QRSTU has a side length of 1 centimeters and an area of about 48 square centimeters. Regular pentagon VWXYZ has a perimeter of 140 centimeters. ind its area. 17. RHOMBUSS Rhombuses MNQ and RSTU are similar. The area of RSTU is 8 square feet. The diagonals of MNQ are 5 feet long and 14 feet long. ind the area of MNQ. Then use the ratio of the areas to find the lengths of the diagonals of RSTU. 18. SHORT RSONS You enlarge the same figure three different ways. In each case, the enlarged figure is similar to the original. List the enlargements in order from smallest to largest. xplain. Case 1 The side lengths of the original figure are multiplied by 3. Case The perimeter of the original figure is multiplied by 4. Case 3 The area of the original figure is multiplied by 5. RASONING In xercises 19 and 0, copy and complete the statement using always, sometimes, or never. xplain your reasoning. 19. oubling the side length of a square? doubles the area. 0. Two similar octagons? have the same perimeter. 1. INING ARA The sides of n ABC are 4.5 feet, 7.5 feet, and 9 feet long. The area is about 17 square feet. xplain how to use the area of n ABC to find the area of a n with side lengths 6 feet, 10 feet, and 1 feet.. RCTANGLS Rectangles ABC and G are similar. The length of ABC is 4 feet and the perimeter is 84 square feet. The width of G is 3 yards. ind the ratio of the area of ABC to the area of G. SIMILAR TRIANGLS xplain why the red and blue triangles are similar. ind the ratio (red to blue) of the areas of the triangles. Show your steps m L M 4. A 5 94 m 1 m N T U Y 3 yd 308 X W V 5. CHALLNG In the diagram shown, ABC is a parallelogram. The ratio of the area of n AGB to the area of n CG is 9 : 5, CG 5 10, and G a. ind AG, GB, G, and. Show your methods. b. Give two area ratios other than 9 : 5 or 5 : 9 for pairs of similar triangles in the figure. xplain. A G C B 11.3 erimeter and Area of Similar igures 741

6 ROBLM SOLVING 6. BANNR Two rectangular banners from this year s music festival are shown. Organizers of next year s festival want to design a new banner that will be similar to the banner whose dimensions are given in the photograph. The length of the longest side of the new banner will be 5 feet. ind the area of the new banner. 3 ft XAML 3 on p. 738 for x ATIO A new patio will be an irregular hexagon. The patio will have two long parallel sides and an area of 360 square feet. The area of a similar shaped patio is 50 square feet, and its long parallel sides are 1.5 feet apart. What will be the corresponding distance on the new patio? 1 ft 8. MULTIL CHOIC You need 0 pounds of grass seed to plant grass inside the baseball diamond shown. About how many pounds do you need to plant grass inside the softball diamond? A 6 B 9 C ft 90 ft softball diamond baseball diamond 9. MULTI-ST ROBLM Use graph paper for parts (a) and (b). a. raw a triangle and label its vertices. ind the area of the triangle. b. Mark and label the midpoints of each side of the triangle. Connect the midpoints to form a smaller triangle. Show that the larger and smaller triangles are similar. Then use the fact that the triangles are similar to find the area of the smaller triangle. 30. JUSTIYING THORM 11.7 Choose a type of polygon for which you know the area formula. Use algebra and the area formula to prove Theorem 11.7 for that polygon. (Hint: Use the ratio for the corresponding side lengths in two similar polygons to express each dimension in one polygon as a } b times the corresponding dimension in the other polygon.) 31. MISLAING GRAHS A student wants to show that the students in a science class prefer mysteries to science fiction books. Over a two month period, the students in the class read 50 mysteries, but only 5 science fiction books. The student makes a bar graph of these data. xplain why the graph is visually misleading. Show how the student could redraw the bar graph Books Read Recently 74 5 WORK-OUT SOLUTIONS on p. WS1 5 STANARIZ TST RACTIC

7 3. ON-N MATH The ratio of the areas of two similar polygons is 9 : 6. raw two polygons that fit this description. ind the ratio of their perimeters. Then write the ratio in simplest radical form. 33. XTN RSONS Use the diagram shown at the right. a. Name as many pairs of similar triangles as you can. xplain your reasoning. b. ind the ratio of the areas for one pair of similar triangles. A 10 9 B 11 C c. Show two ways to find the length of }. 34. CHALLNG In the diagram, the solid figure is a cube. Quadrilateral JKNM is on a plane that cuts through the cube, with JL 5 KL. a. xplain how you know that n JKL, n MN. b. Suppose JK } MN 5 1 } 3. ind the ratio of the area of n JKL to the area of one face of the cube. c. ind the ratio of the area of n JKL to the area of pentagon JKQRS. R S J L K M T N MIX RVIW RVIW repare for Lesson 11.4 in xs ind the circumference of the circle with the given radius r or diameter d. Use p ø Round your answers to the nearest hundredth. (p. 49) 35. d 5 4 cm 36. d 5 10 ft 37. r 5.5 yd 38. r m ind the value of x. 39. (p. 95) 40. (p. 67) 41. (p. 680) x 10 x x8 888 QUIZ for Lessons The height of ~ ABC is 3 times its base. Its area is 108 square feet. ind the base and the height. (p. 70) ind the area of the figure.. 13 (p. 70) (p. 730) 4. (p. 730) The ratio of the lengths of corresponding sides of two similar heptagons is 7 : 0. ind the ratio of their perimeters and their areas. (p. 737) 6. Triangles QR and XYZ are similar. The area of n QR is 100 ft and the area of n XYZ is 48 ft. Given Q 5 50 ft, find XY. (p. 737) XTRA RACTIC for Lesson 11.3, p. 916 ONLIN QUIZ at classzone.com 743

8 LSSON 11.3 Using ALTRNATIV MTHOS Another Way to Solve xample 3, page 738 MULTIL RRSNTATIONS In xample 3 on page 738, you used proportional reasoning to solve a problem about cooking. You can also solve the problem by using an area formula. RO B L M COOKING A large rectangular baking pan is 15 inches long and 10 inches wide. A smaller pan is similar to the large pan. The area of the smaller pan is 96 square inches. ind the width of the smaller pan. M T H O Using a ormula You can use what you know about side lengths of similar figures to find the width of the pan. ST 1 Use the given dimensions of the large pan to write expressions for the dimensions of the smaller pan. Let x represent the width of the smaller pan. 15 in. 10 in. A 5 96 in. x The length of the larger pan is 1.5 times its width. So, the length of the smaller pan is also 1.5 times its width, or 1.5x. ST Use the formula for the area of a rectangle to write an equation. A 5 lw ormula for area of a rectangle xpx Substitute 1.5x forl and x for w. 8 5 x Solve for a positive value of x. c The width of the smaller pan is 8 inches. R AC T I C 1. COOKING A third pan is similar to the large pan shown above and has 1.44 times its area. ind the length of the third pan.. TRAZOIS Trapezoid QRS is similar to trapezoid WXYZ. The area of WXYZ is 8 square units. ind WZ. 9 R X Y 3. SQUARS One square has sides of length s. If another square has twice the area of the first square, what is its side length? 4. RASONING n ABC, n and the area of n is 11.5 square centimeters. ind and. xplain your reasoning. A 6 1 S W Z 5 cm B 8 cm C 744 Chapter 11 Measuring Length and Area

9 MIX RVIW of roblem Solving Lessons MULTI-ST ROBLM The diagram below represents a rectangular flower bed. In the diagram, AG feet and G 5 15 feet. STAT TST RACTIC classzone.com 4. SHORT RSONS What happens to the area of a rhombus if you double the length of each diagonal? if you triple the length of each diagonal? xplain what happens to the area of a rhombus if each diagonal is multiplied by the same number n. a. xplain how you know that BH is a rhombus. b. ind the area of rectangle ACG and the area of rhombus BH. c. You want to plant asters inside rhombus BH and marigolds in the other parts of the flower bed. It costs about \$.30 per square foot to plant marigolds and about \$.40 per square foot to plant asters. How much will you spend on flowers?. ON-N A polygon has an area of 48 square meters and a height of 8 meters. raw three different triangles that fit this description and three different parallelograms. xplain your thinking. 3. XTN RSONS You are tiling a 1 foot by 1 foot rectangular floor. rices are shown below for two sizes of square tiles. 18 in. \$.5 \$ in. a. How many small tiles would you need for the floor? How many large tiles? b. ind the cost of buying large tiles for the floor and the cost of buying small tiles for the floor. Which tile should you use if you want to spend as little as possible? c. Compare the side lengths, the areas, and the costs of the two tiles. Is the cost per tile based on side length or on area? xplain. 5. MULTI-ST ROBLM The pool shown is a right triangle with legs of length 40 feet and 41 feet. The path around the pool is 40 inches wide. R U Not drawn to scale 40 a. ind the area of nstu. b. In the diagram, nqr, nstu, and the scale factor of the two triangles is 1.3 : 1. ind the perimeter of nqr. c. ind the area of nqr. Then find the area of the path around the pool. 6. GRI ANSWR In trapezoid ABC, }AB i } C, m 5 908, A 5 5 inches, and C 5 3pAB. The area of trapezoid ABC is 150 square inches. ind the length (in inches) of } C. 7. XTN RSONS In the diagram below, n H is an isosceles right triangle, and n GH is an equilateral triangle H 608 a. ind H. xplain your reasoning. b. ind G. xplain your reasoning. c. ind the area of GH. S T J G Mixed Review of roblem Solving 745

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