Chapter 2: Principles of steadystate converter analysis


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1 Chaper 2 Principles of SeadySae Converer Analysis 2.1. Inroducion 2.2. Inducor volsecond balance, capacior charge balance, and he small ripple approximaion 2.3. Boos converer example 2.4. Cuk converer example 2.5. Esimaing he ripple in converers conaining wopole lowpass filers 2.6. Summary of key poins 1
2 2.1 Inroducion Buck converer SPDwich changes dc componen 1 2 v s v Swich oupu volage waveform Duy cycle D: 0 D 1 complemen D : D = 1  D v s D D' 0 D swich posiion:
3 Dc componen of swich oupu volage v s area = D <v s > = D 0 D 0 Fourier analysis: Dc componen = average value v s = T 1 v s d s 0 v s = 1 (D )=D 3
4 Inserion of lowpass filer o remove swiching harmonics and pass only dc componen 1 2 v s C v V v v s = D D 4
5 Three basic dcdc converers Buck a) 1 2 i C v M(D) M(D)=D D Boos b) i 1 2 C v M(D) M(D)= 1 1D D Buckboos c) 1 2 i C v M(D) D M(D)= D 1D 5
6 Objecives of his chaper Develop echniques for easily deermining oupu volage of an arbirary converer circui Derive he principles of inducor volsecond balance and capacior charge (ampsecond) balance Inroduce he key small ripple approximaion Develop simple mehods for selecing filer elemen values Illusrae via examples 6
7 2.2. Inducor volsecond balance, capacior charge balance, and he small ripple approximaion Acual oupu volage waveform, buck converer Buck converer conaining pracical lowpass filer 1 2 i v C i C v Acual oupu volage waveform v=vv ripple v V Dc componen V acual waveform v = V v ripple 0 7
8 The small ripple approximaion v=vv ripple v V Dc componen V acual waveform v = V v ripple 0 In a welldesigned converer, he oupu volage ripple is small. Hence, he waveforms can be easily deermined by ignoring he ripple: v ripple << V v V 8
9 Buck converer analysis: inducor curren waveform original converer 1 2 i v C i C v swich in posiion 1 swich in posiion 2 i v i C v i C C v i C v 9
10 Inducor volage and curren Subinerval 1: swich in posiion 1 Inducor volage v = v i v i C Small ripple approximaion: C v v V Knowing he inducor volage, we can now find he inducor curren via v = di d Solve for he slope: di d = v V The inducor curren changes wih an essenially consan slope 10
11 Inducor volage and curren Subinerval 2: swich in posiion 2 Inducor volage v =v Small ripple approximaion: v V v i C i C v Knowing he inducor volage, we can again find he inducor curren via v = di d Solve for he slope: di d V The inducor curren changes wih an essenially consan slope 11
12 Inducor volage and curren waveforms v V D D' i I i (0) V i (D ) V swich posiion: V i v = di d 0 D 12
13 Deerminaion of inducor curren ripple magniude i i (D ) I i (0) V V i 0 D (change in i )=(slope)(lengh of subinerval) 2 i = V DT s i = V 2 D = V 2 i D 13
14 Inducor curren waveform during urnon ransien i i ( ) i (0)=0 0 D v v i (n ) 2 n (n1) i ((n1) ) When he converer operaes in equilibrium: i ((n 1) )=i (n ) 14
15 The principle of inducor volsecond balance: Derivaion Inducor defining relaion: v = di d Inegrae over one complee swiching period: i ( )i (0) = 1 0 v d In periodic seady sae, he ne change in inducor curren is zero: 0= v d 0 Hence, he oal area (or volseconds) under he inducor volage waveform is zero whenever he converer operaes in seady sae. An equivalen form: 0= 1 v T d = v s 0 The average inducor volage is zero in seady sae. 15
16 Inducor volsecond balance: Buck converer example Inducor volage waveform, previously derived: v V oal area λ D Inegral of volage waveform is area of recangles: λ = v d =( V)(D )(V)(D' ) Average volage is v 0 = λ = D( V)D'(V) V Equae o zero and solve for V: 0=D (DD')V=D V V = D 16
17 The principle of capacior charge balance: Derivaion Capacior defining relaion: i C =C dv C d Inegrae over one complee swiching period: v C ( )v C (0) = 1 C 0 i C d In periodic seady sae, he ne change in capacior volage is zero: 0= T 1 i C d s 0 = i C Hence, he oal area (or charge) under he capacior curren waveform is zero whenever he converer operaes in seady sae. The average capacior curren is hen zero. 17
18 2.3 Boos converer example 2 Boos converer wih ideal swich i v 1 i C C v D 1 ealizaion using power MOSFET and diode i v D Q 1 i C C v 18
19 Boos converer analysis 2 original converer i v 1 i C C v swich in posiion 1 swich in posiion 2 i v i C i v i C C v C v 19
20 Subinerval 1: swich in posiion 1 Inducor volage and capacior curren v = i C =v/ i v i C C v Small ripple approximaion: v = i C =V/ 20
21 Subinerval 2: swich in posiion 2 Inducor volage and capacior curren v = v i C = i v / i v i C C v Small ripple approximaion: v = V i C = I V / 21
22 Inducor volage and capacior curren waveforms v D D' V i C I V/ D V/ D' 22
23 Inducor volsecond balance Ne volseconds applied o inducor over one swiching period: v D D' 0 v d =( )D ( V)D' V Equae o zero and collec erms: (D D')VD'=0 Solve for V: V = D' The volage conversion raio is herefore M(D)= V = 1 D' = 1 1D 23
24 Conversion raio M(D) of he boos converer 5 4 M(D) = 1 D' = 1 1D M(D) D 24
25 Deerminaion of inducor curren dc componen Capacior charge balance: i C I V/ D D' 0 i C d =( V )D (I V )D' V/ Collec erms and equae o zero: V Solve for I: I = (D D')ID'=0 V D' Eliminae V o express in erms of : I = D' 2 I ( / ) D 25
26 Deerminaion of inducor curren ripple Inducor curren slope during subinerval 1: di d di d = v = v = Inducor curren slope during subinerval 2: = V i I V 0 D Change in inducor curren during subinerval 1 is (slope) (lengh of subinerval): i 2 i = D Solve for peak ripple: i = 2 D Choose such ha desired ripple magniude is obained 26
27 Deerminaion of capacior volage ripple Capacior volage slope during subinerval 1: dv C d = i C C = V C v V V C I C V C v Capacior volage slope during subinerval 2: 0 D dv C d = i C C = I C V C Change in capacior volage during subinerval 1 is (slope) (lengh of subinerval): 2 v= V C D Solve for peak ripple: v = V 2C D Choose C such ha desired volage ripple magniude is obained In pracice, capacior equivalen series resisance (esr) leads o increased volage ripple 27
28 2.4 Cuk converer example Cuk converer, wih ideal swich 1 C 1 2 i 1 v i C 2 v 2 Cuk converer: pracical realizaion using MOSFET and diode 1 C 1 2 i 1 v i 2 1 Q 1 D 1 C 2 v 2 28
29 Cuk converer circui wih swich in posiions 1 and 2 Swich in posiion 1: MOSFET conducs Capacior C 1 releases energy o oupu 1 i 2 i 1 v i v 1 C1 2 2 v 1 C 1 C 2 i C2 v 2 Swich in posiion 2: diode conducs Capacior C 1 is charged from inpu 1 i 1 i 2 v 1 i C1 2 C 1 v 1 C 2 v 2 i C2 v 2 29
30 Waveforms during subinerval 1 MOSFET conducion inerval Inducor volages and capacior currens: v 1 = 1 i 2 i 1 v i v 1 C1 2 2 v 1 C 1 C 2 i C2 v 2 v 2 =v 1 v 2 i C1 =i 2 i C2 =i 2 v 2 Small ripple approximaion for subinerval 1: v 1 = v 2 =V 1 V 2 i C1 =I 2 i C2 =I 2 V 2 30
31 Waveforms during subinerval 2 Diode conducion inerval Inducor volages and capacior currens: v 1 = v 1 v 2 =v 2 i C1 =i 1 1 i 1 i 2 v 1 i C1 C 1 v 1 C 2 2 v 2 i C2 v 2 i C2 =i 2 v 2 Small ripple approximaion for subinerval 2: v 1 = V 1 v 2 =V 2 i C1 =I 1 i C2 =I 2 V 2 31
32 Equae average values o zero The principles of inducor volsecond and capacior charge balance sae ha he average values of he periodic inducor volage and capacior curren waveforms are zero, when he converer operaes in seady sae. Hence, o deermine he seadysae condiions in he converer, le us skech he inducor volage and capacior curren waveforms, and equae heir average values o zero. Waveforms: Inducor volage v 1 v 1 Volsecond balance on 1 : D D' v 1 = D D'( V 1 )=0 V 1 32
33 Equae average values o zero Inducor 2 volage v 2 V 2 D D' V 1 V 2 Average he waveforms: Capacior C 1 curren i C1 I 1 v 2 = D(V 1 V 2 )D'(V 2 )=0 i C1 =DI 2 D'I 1 =0 D I 2 D' 33
34 Equae average values o zero Capacior curren i C2 waveform i C2 D I 2 V 2 / (= 0) D' i C2 =I 2 V 2 =0 Noe: during boh subinervals, he capacior curren i C2 is equal o he difference beween he inducor curren i 2 and he load curren V 2 /. When ripple is negleced, i C2 is consan and equal o zero. 34
35 Cuk converer conversion raio M = V/ 0 D M(D) M(D)= V 2 = D 1D 5 35
36 Inducor curren waveforms Inerval 1 slopes, using small ripple approximaion: di 1 d di 2 d = v 1 1 Inerval 2 slopes: di 1 d di 2 d = 1 = v 2 2 = V 1 V 2 2 = v 1 1 = V 1 1 = v 2 2 = V 2 2 i 1 i 2 I 1 i 1 1 V 1 1 I 2 V 1 V 2 2 D D V 2 2 i2 36
37 Capacior C 1 waveform Subinerval 1: dv 1 d Subinerval 2: dv 1 d = i C1 C 1 = I 2 C 1 = i C1 C 1 = I 1 C 1 v 1 v 1 V 1 I 2 I 1 C 1 D C 1 37
38 ipple magniudes Analysis resuls i 1 = D 2 1 i 2 = V 1 V v 1 = I 2D 2C 1 D Use dc converer soluion o simplify: i 1 = D 2 1 i 2 = D 2 2 v 1 = D 2 2D'C 1 Q: How large is he oupu volage ripple? 38
39 2.5 Esimaing ripple in converers conaining wopole lowpass filers Buck converer example: Deermine oupu volage ripple 1 2 i i C C v C i Inducor curren waveform. Wha is he capacior curren? i I i (0) V i (D ) V 0 D i 39
40 Capacior curren and volage, buck example Mus no neglec inducor curren ripple! i C oal charge q / 2 i D D' If he capacior volage ripple is small, hen essenially all of he ac componen of inducor curren flows hrough he capacior. v C V v v 40
41 Esimaing capacior volage ripple v i C v C V oal charge q D / 2 v D' i v Curren i C is posiive for half of he swiching period. This posiive curren causes he capacior volage v C o increase beween is minimum and maximum exrema. During his ime, he oal charge q is deposied on he capacior plaes, where q = C (2 v) (change in charge)= C(change in volage) 41
42 Esimaing capacior volage ripple v i C oal charge q D / 2 D' i The oal charge q is he area of he riangle, as shown: q = 1 2 i 2 Eliminae q and solve for v: v C v = i 8 C V v v Noe: in pracice, capacior equivalen series resisance (esr) furher increases v. 42
43 Inducor curren ripple in wopole filers Example: problem i T Q1 i 1 i 2 2 V g C 1 v C1 D1 C 2 v v oal flux linkage λ v / 2 D D' can use similar argumens, wih λ = i i λ = inducor flux linkages I i i = inducor volseconds 43
44 2.6 Summary of Key Poins 1. The dc componen of a converer waveform is given by is average value, or he inegral over one swiching period, divided by he swiching period. Soluion of a dcdc converer o find is dc, or seadysae, volages and currens herefore involves averaging he waveforms. 2. The linear ripple approximaion grealy simplifies he analysis. In a welldesigned converer, he swiching ripples in he inducor currens and capacior volages are small compared o he respecive dc componens, and can be negleced. 3. The principle of inducor volsecond balance allows deerminaion of he dc volage componens in any swiching converer. In seadysae, he average volage applied o an inducor mus be zero. 44
45 Summary of Chaper 2 4. The principle of capacior charge balance allows deerminaion of he dc componens of he inducor currens in a swiching converer. In seadysae, he average curren applied o a capacior mus be zero. 5. By knowledge of he slopes of he inducor curren and capacior volage waveforms, he ac swiching ripple magniudes may be compued. Inducance and capaciance values can hen be chosen o obain desired ripple magniudes. 6. In converers conaining muliplepole filers, coninuous (nonpulsaing) volages and currens are applied o one or more of he inducors or capaciors. Compuaion of he ac swiching ripple in hese elemens can be done using capacior charge and/or inducor fluxlinkage argumens, wihou use of he smallripple approximaion. 7. Converers capable of increasing (boos), decreasing (buck), and invering he volage polariy (buckboos and Cuk) have been described. Converer circuis are explored more fully in a laer chaper. 45
6.334 Power Electronics Spring 2007
MI OpenCourseWare hp://ocw.mi.edu 6.334 Power Elecronics Spring 2007 For informaion abou ciing hese maerials or our erms of Use, visi: hp://ocw.mi.edu/erms. Chaper 5 Inroducion o DC/DC Converers Analysis
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