# 1 of 10 11/23/2009 6:37 PM

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1 hapter 14 Homework Due: 9:00am on Thursday November Note: To understand how points are awarded read your instructor's Grading Policy. [Return to Standard Assignment View] Good Vibes: Introduction to Oscillations Learning Goal: To learn the basic terminology and relationships among the main characteristics of simple harmonic motion. Motion that repeats itself over and over is called periodic motion. There are many examples of periodic motion: the earth revolving around the sun an elastic ball bouncing up and down or a block attached to a spring oscillating back and forth. The last example differs from the first two in that it represents a special kind of periodic motion called simple harmonic motion. The conditions that lead to simple harmonic motion are as follows: There must be a position of stable equilibrium. There must be a restoring force acting on the oscillating object. The direction of this force must always point toward the equilibrium and its magnitude must be directly proportional to the magnitude of the object's displacement from its equilibrium position. Mathematically the restoring force is given by where is the displacement from equilibrium and is a constant that depends on the properties of the oscillating system. The resistive forces in the system must be reasonably small. In this problem we will introduce some of the basic quantities that describe oscillations and the relationships among them. onsider a block of mass attached to a spring with force constant as shown in the figure. The spring can be either stretched or compressed. The block slides on a frictionless horizontal surface as shown. When the spring is relaxed the block is located at. If the block is pulled to the right a distance and then released will be the amplitude of the resulting oscillations. Assume that the mechanical energy of the block-spring system remains unchanged in the subsequent motion of the block. After the block is released from it will remain at rest. move to the left until it reaches equilibrium and stop there. move to the left until it reaches and stop there. move to the left until it reaches and then begin to move to the right. As the block begins its motion to the left it accelerates. Although the restoring force decreases as the block approaches equilibrium it still pulls the block to the left so by the time the equilibrium position is reached the block has gained some speed. It will therefore pass the equilibrium position and keep moving compressing the spring. The spring will now be pushing the block to the right and the block will slow down temporarily coming to rest at. After is reached the block will begin its motion to the right pushed by the spring. The block will pass the equilibrium position and continue until it reaches completing one cycle of motion. The motion will then repeat; if as we've assumed there is no friction the motion will repeat indefinitely. The time it takes the block to complete one cycle is called the period. Usually the period is denoted and is measured in seconds. The frequency denoted is the number of cycles that are completed per unit of time:. In SI units is measured in inverse seconds or hertz ( ). If the period is doubled the frequency is unchanged. doubled. halved. Part An oscillating object takes 0.10 to complete one cycle; that is its period is What is its frequency? Express your answer in hertz. = 10 Part D 1 of 10 11/23/2009 6:37 PM

2 2 of 10 11/23/2009 6:37 PM If the frequency is 40 what is the period? Express your answer in seconds. = The following questions refer to the figure that graphically depicts the oscillations of the block on the spring. Note that the vertical axis represents the x coordinate of the oscillating object and the horizontal axis represents time. Part E Which points on the x axis are located a distance from the equilibrium position? R only Q only both R and Q Part F Suppose that the period is. Which of the following points on the t axis are separated by the time interval? K and L K and M K and P L and N M and P Now assume that the x coordinate of point R is 0.12 and the t coordinate of point K is Part G What is the period? Hint G.1 In moving from the point to the point K what fraction of a full wavelength is covered? all that fraction. Then you can set. Dividing by the fraction will give the period. Express your answer in seconds. = 0.02 Part H How much time does the block take to travel from the point of maximum displacement to the opposite point of maximum displacement? Express your answer in seconds. = 0.01 Part I What distance does the object cover during one period of oscillation? Express your answer in meters. = 0.48 Part J What distance does the object cover between the moments labeled K and N on the graph? Express your answer in meters. = 0.36

3 3 of 10 11/23/2009 6:37 PM Learning Goal: To learn to find kinematic variables from a graph of position vs. time. The graph of the position of an oscillating object as a function of time is shown. Position Velocity and Acceleration of an Oscillator Some of the questions ask you to determine ranges on the graph over which a statement is true. When answering these questions choose the most complete answer. For example if the answer "B to D" were correct then "B to " would technically also be correct--but you will only recieve credit for choosing the most complete answer. Where on the graph is? A to B A to to D to E B to D Where on the graph is? A to B A to to D to E B to D Part Where on the graph is? A only only E only A and A and and E B and D Part D Where on the graph is the velocity? Hint D.1 Finding instantaneous velocity Instantaneous velocity is the derivative of the position function with respect to time. Thus you can find the velocity at any time by calculating the slope of the vs. graph. When is the slope greater than 0 on this graph? A to B A to to D to E B to D Part E Where on the graph is the velocity?

4 4 of 10 11/23/2009 6:37 PM A to B Energy of Harmonic Oscillators Learning Goal: To learn to A apply to the law of conservation of energy to the analysis of harmonic oscillators. to D Systems in simple harmonic motion to E or harmonic oscillators obey the law of conservation of energy just like all other systems do. Using energy considerations one can analyze many aspects of motion of the oscillator. Such an analysis can be simplified B to Dif one assumes that mechanical energy is not dissipated. In other words where is the total mechanical energy of the system is the kinetic energy and is the potential energy. As you know a common example of a harmonic oscillator is a mass attached to a spring. In this problem we will consider a horizontally moving block attached to a spring. Note that since the gravitational potential Part F energy is not changing in this case it can be excluded from the calculations. Where on the graph is the velocity? For such a system the potential energy is stored in the spring and is given by Hint F.1 How to tell if where is the force constant of the spring and is the distance from the equilibrium position. A only The kinetic energy of the system is as always B only only D only E only where is the mass of the block A and and is the speed of the block. A and and E We will also assume that there are no resistive forces; that is. B and D block and the amplitude of vibrations are given. Answer the following questions. Part G Where on the graph is the acceleration? Hint G.1 Finding acceleration Acceleration is the second derivative of the position function with respect to time: onsider a harmonic oscillator at four different moments labeled A B and D as shown in the figure. Assume that the force constant the mass of the. This means that the sign of the acceleration is the same as the sign of the curvature of the x vs. t graph. The acceleration of a curve is negative for downward curvature and positive for upward curvature. Where is the curvature greater than 0? Part A A to B Which moment corresponds to A to the maximum potential energy of the system? to D onsider to the E position of the block B to D Part H A B D Where on the graph is the acceleration? A to B A to Which moment corresponds to to the Dminimum kinetic energy of the system? to E Hint B.1 How does the velocity change? B to D A B Part I D Where on the graph is the acceleration? Hint I.1 How to tell if When the block is displaced a distance from equilibrium the spring is stretched (or compressed) the most and the block is momentarily at rest. Therefore the maximum potential energy is. At that moment of course. Recall that. Therefore A only B only. only D only In general the mechanical E energy only of a harmonic oscillator equals its potential energy at the maximum or minimum displacement. A and A and and E Part B and D onsider the block in the process of oscillating.

5 5 of 10 11/23/2009 6:37 PM If the kinetic energy of the block is increasing the block must be at the equilibrium position. at the amplitude displacement. moving to the right. moving to the left. moving away from equilibrium. moving toward equilibrium. Part D Which moment corresponds to the maximum kinetic energy of the system? Hint D.1 onsider the velocity of the block A B D Part E Which moment corresponds to the minimum potential energy of the system? Hint E.1 onsider the distance from equilibrium A B D When the block is at the equilibrium position the spring is not stretched (or compressed) at all. At that moment of course. Meanwhile the block is at its maximum speed ( ). The maximum kinetic energy can then be written as. Recall that and that at the equilibrium position. Therefore. Recalling what we found out before we can now conclude that or. Part F At which moment is? Hint F.1 onsider the potential energy At this moment. Use the formula for to obtain the corresponding distance from equilibrium. A B D Part G Find the kinetic energy of the block at the moment labeled B. Hint G.1 Find the potential energy first; then use conservation of energy. Hint G.2 Find the potential energy

6 6 of 10 11/23/2009 6:37 PM Find the potential energy of the block at the moment labeled B. Express your answer in terms of and. = Using the facts that the total energy and that you can now solve for the kinetic energy at moment B. Express your answer in terms of and. = The graph shows the position of an oscillating object as a function of time. The equation of the graph is osine Wave where is the amplitude is the angular frequency and is a phase constant. The quantities and are measurements to be used in your answers. What is in the equation? Maximum of What is Hint B.1 in the equation? Period Part What is in the equation? Hint.1 Using the graph and trigonometry What is equal to when? Use your result for to solve for in terms of and. Hint.2 Using the graph and You might be able to find in terms of and then use your result from.

7 7 of 10 11/23/2009 6:37 PM This applet shows two masses on springs each accompanied by a graph of its position versus time. Analyzing Simple Harmonic Motion What is an expression for the position of mass I as a function of time? Assume that position is measured in meters and time is measured in seconds. The most general form of a sinusoidal wave is or depending upon whether you write the equation using the sine or cosine. Notice that the amplitude and the angular frequency will be the same regardless of whether you choose to use sine or cosine. The phase however will be different since for any we have the relation. The amplitude and angular frequency can be determined directly from the graph. The decision whether to use sine or cosine is more a matter of convenience. Which of the following statements correctly identify a choice of function and phase that could be used to describe this graph? heck all that apply. cosine cosine cosine sine sine sine Answer Requested Of the three correct options the simplest is cosine with phase shift zero but any of them will give the correct answer. Hint A.2 Find the amplitude What is the amplitude of the motion of the first mass? Hint A.2.1 Definition of amplitude Express your answer in meters to two significant figures. = 1 Hint A.3 Find the angular frequency What is the angular frequency of the motion of the first mass? Hint A.3.1 Angular frequency and frequency Express your answer in radians per second to three significant figures. = 12.6 Express your answer as a function of. Express numerical constants to three significant figures. = What is the position of mass II as a function of time? Assume that position is measured in meters and time is measured in seconds. Hint B.1 Hint B.2 Hint B.3 Find the amplitude Find the angular frequency

8 8 of 10 11/23/2009 6:37 PM Express your answer as a function of. Express numerical constants to three significant figures. = hanging the Period of a Pendulum A simple pendulum consisting of a bob of mass attached to a string of length swings with a period. If the bob's mass is doubled approximately what will the pendulum's new period be? Period of a simple pendulum If the pendulum is brought on the moon where the gravitational acceleration is about approximately what will its period now be? Hint B.1 Part If the pendulum is taken into the orbiting space station what will happen to the bob? Hint.1 It will continue to oscillate in a vertical plane with the same period. It will no longer oscillate because there is no gravity in space. It will no longer oscillate because both the pendulum and the point to which it is attached are in free fall. It will oscillate much faster with a period that approaches zero. In the space station where all objects undergo the same acceleration due to the earth's gravity the tension in the string is zero and the bob does not fall relative to the point to which the string is attached. Gravity on Another Planet After landing on an unfamiliar planet a space explorer constructs a simple pendulum of length The explorer finds that the pendulum completes 94.0 full swing cycles in a time of 131. What is the value of the acceleration of gravity on this planet? alculate the period of the pendulum and use this to calculate the gravitational acceleration on the planet. Hint A.2 alculate the period alculate the period of the pendulum. Express your answer in seconds. = 1.39 Hint A.3 Equation for the period The period of a simple pendulum is given by the equation where is the length of the pendulum and is the gravitational acceleration on the planet. Express your answer in meters per second per second.

9 9 of 10 11/23/2009 6:37 PM = 10.8 Problem A 2.0 g spider is dangling at the end of a silk thread. You can make the spider bounce up and down on the thread by tapping lightly on his feet with a pencil. You soon discover that you can give the spider the largest amplitude on his little bungee cord if you tap exactly once every second. What is the spring constant of the silk thread? Damped Egg on a Spring A hard-boiled egg moves on the end of a spring with force constant. It is released with an amplitude A damping force acts on the egg. After it oscillates for 5.00 the amplitude of the motion has decreased to alculate the magnitude of the damping coefficient. How damped is it? The system described above is..1 How to determine damping critically damped overdamped underdamped Hint A.2 What formula to use In this problem the motion is described by the general equation for an underdamped oscillator where is position and is time. The displacement is thus a product of a oscillating cosine term and a damping term. This equation is the solution to the damped oscillator equation. Hint A.3 Find the amplitude What is the amplitude as a function of time? Use for the initial displacement of the system and for the mass of the egg. Hint A.3.1 Initial amplitude Give your answer in terms of and. = Now evaluate and set your answer equal to as given in the problem introduction. Finally solve for. Hint A.4 Solving for in If then Express the magnitude of the damping coefficient numerically in kilograms per second to three significant figures. = kg/s Problem An oscillator with a mass of 500 and a period of has an amplitude that decreases by 2.20% during each complete oscillation. If the initial amplitude is 10.6 what will be the amplitude after 37.0 oscillations?

10 10 of 10 11/23/2009 6:37 PM 4.65 At what time will the energy be reduced to 54.0% of its initial value? 12.5 Score Summary: Your score on this assignment is 105%. You received out of a possible total of 65 points plus 4.8 points of extra credit.

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