# Basic Electrical Theory

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1 Basic Electrical Theory Mathematics Review PJM State & Member Training Dept.

2 Objectives By the end of this presentation the Learner should be able to: Use the basics of trigonometry to calculate the different components of a right triangle Compute Per-Unit Quantities Identify the two components of Vectors

3 Right Triangles

4 Mathematics Review To be able to understand basic AC power concepts, a familiarization with the relationships between the angles and sides of a right triangle is essential A right triangle is defined as a triangle in which one of the three angles is a right angle always equal to 90 o Two of the sides which form the right triangle are designated as the adjacent and opposite sides with respect to the angle theta The third side of the right triangle is the longest side and is called the hypotenuse

5 Mathematics Review Angle Alpha Hypotenuse α Opposite Side θ Adjacent Side Angle Theta Symbol for a Right Angle (90 o )

6 Mathematics Review Given the lengths of two sides of a right triangle, the third side can be determined using the Pythagorean Theorem The square of the hypotenuse is equal to the sum of the squares of the remaining two sides: Hypotenuse 2 = Opposite 2 + Adjacent 2

7 Mathematics Review Given a right triangle whose hypotenuse is 10, and the adjacent side is 6, what is the length of the opposite side? Hypotenuse 2 = Adjacent 2 + Opposite = Opposite = 36 + Opposite = Opposite = Opposite 64 = Opposite Opposite = 8

8 Mathematics Review Once the sides are known, the next step in solving the right triangle is to determine the two unknown angles of the right triangle Three angles of any triangle always add up to 180 o In solving a right triangle, the remaining two unknown angles must add up to 90 o Basic trigonometric functions are needed to solve for the values of the unknown angles

9 Trigonometry

10 Mathematics Review The sine function is a periodic function in that it continually repeats itself

11 Mathematics Review In order to solve right triangles, it is necessary to know the value of the sine function between 0 o and 90 o Sine of either of the unknown angles of a right triangle is the ratio of the length of the opposite side to the length of the hypotenuse SIN = Opposite side / Hypotenuse

12 Mathematics Review Cosine function is a periodic function that is identical to the sine function except that it leads the sine function by 90 o

13 Mathematics Review As an example, the cosine function at 0 o is 1 whereas the sine function does not reach the value of 1 until 90 o Cosine function of either of the unknown angles of a right triangle is the ratio of the length of the adjacent side to the length of the hypotenuse COS = Adjacent side / Hypotenuse

14 Mathematics Review The tangent function of either of the unknown angles of a right triangle is the ratio of the length of the opposite side to the length of the adjacent side TAN = Opposite side / Adjacent side

15 Mathematics Review Example: Given: Side H = 5, Side A = 4 Find: Side O, Angle and Angle Hypotenuse Side H 5 α Opposite Side Side O θ 90 o 4 Adjacent Side Side A

16 Mathematics Review Find Side O: H A O 16 O O O α O = 3? Find : sin sin(. 6) O O H θ A = 4 90 o Find :

17 Mathematics Review Find X α 3 cm θ 4 cm 90 o

18 Mathematics Review

19 Question 1 Calculate the value of the hypotenuse and the angle θ in the following triangle A B 12 cm θ α 20 cm C

20 Question 1 - Answer 2 2 A O H =59 12 cm 20 cm A B C θ α H A hypotenuse adjacent cos cos cm H H H cos(.514).514 cos cos 1 cm cm

21 Question 2 Calculate the length of the side x, given that tan θ = 0.4 A B x α θ 15 cm C

22 Question 2 - Answer tan opposite adjacent 0.4 x x 15 (0.4)(15) B α tan θ = 0.4 θ A x 6cm 15 cm C

23 Question 3 Calculate the length of the side x, given that sin θ = 0.6 A θ x cm α 12 cm B C

24 Question 3 - Answer sin x opposite hypotenuse H 12 H 0.6 H 20cm H 2 A 2 A sin θ =0.6 θ x= x 16cm α 12 cm B x x C x cm

25 Per-unit Quantities

26 Mathematics Review Ratios play an important part in estimating power system performance A ratio is defined as a relationship between two numbers as a fraction Generally, ratios are used when the relationship of two pairs of values is the same, and one of two similarly related values is known Ratios only provide exact answers in linear systems where the relationship between two variables in the system is the same regardless of the magnitude of the two variables

27 Question 4 Assume that the loss of a 1000 MW generating unit will typically result in a 0.2 Hz dip in system frequency. Estimate the frequency dip for the loss of an 800 MW generating unit.

28 Hz x MW MW Hz ) ( 1000 ) )(800 ( ) ( MW MW Hz x MW MW Hz Mathematics Review MW Hz x MW Hz 800 ) ( Hz Hz x

29 Question 5 Assume that the loss of a 500 MW generating unit will typically result in a 0.3 Hz dip in system frequency. Estimate the frequency dip for the loss of an 300 MW generating unit.

30 Hz x MW Hz MW ) ( 500 ) )(0.3 ( ) ( MW MW Hz x MW MW Hz Mathematics Review MW Hz x MW Hz 300 ) ( Hz Hz x

31 Mathematics Review Quantities on the power system are often specified as a percentage or a per-unit of their base or nominal value Per-unit values makes it easier to see where a system value is in respect to its base value and also how it compares between different parts of the system with different base values Per-unit values also allow for a dispatcher to view the system and quickly obtain a feel for the voltage profile

32 Mathematics Review Assume that, at a certain substation, the voltage being measured is 510 kv on the 500 kv system. What is its per-unit value with respect to the nominal voltage? Base or nominal voltage = 500 kv Measured voltage = 510 kv 510 kv / 500 kv = 1.02 per-unit or 102%

33 Mathematics Review 358 kv 345 kv per- unit 345 kv 345 kv 1.0 per- unit 143 kv 138 kv 139 kv 138 kv per- unit per- unit 22 kv 20 kv 1.1per- unit Bus Voltage Legend Bus 1 20kV Bus 2 345kV Bus 3 345kV Bus 4 138kV Bus 5 138kV

34 Vectors

35 Vectors A vector is alternative way to represent a sinusoidal function with amplitude, and phase information A vectors length represents magnitude A vectors direction represents the phase angle Example: 10 miles east N W 10 Miles E S

36 Vectors Vectors are a means of expressing both magnitude and direction Horizontal line to the right is positive; horizontal line to the left is negative Vertical line going up is positive; vertical line going down is negative Arrowhead on the end away from the point of origin indicates the direction of the vector and is called the displacement vector Vectors can go in any direction in space

37 Vectors The difference between a scalar quantity and a vector: a) A scalar quantity is one that can be described with a single number, including any units, giving its size or magnitude b) A vector quantity is one that deals inherently with both magnitude and direction

38 Conceptual Question 6 There are places where the temperature is +20 o C at one time of the year and -20 o C at another time. Do the plus and minus signs that signify positive and negative temperatures imply that temperature is a vector quantity?

39 Question 7 Which of the following statements, if any, involves a vector? a) I walked two miles along the beach b) I walked two miles due north along the beach c) A ball fell off a cliff and hit the water traveling at 17 miles per hour d) A ball fell off a cliff and traveled straight down 200 feet e) My bank account shows a negative balance of -25 dollars

40 Vectors When adding vectors, the process must take into account both the magnitude and direction of the vectors Vectors are usually written in bold with an arrow over the top of the letter, ( A ) When adding two vectors, there is always a resultant vector, R, and the addition is written as follows: R = A + B

41 Vectors Example: Adding vectors in the same direction Vector A has a length of 2 and a direction of 90 o Vector B has a length of 3 and a direction of 90 o 90 o B R 180 o A 0 o 270 o

42 Vectors Example: Adding vectors in the opposite direction Vector A has a length of 2 and a direction of 90 o Vector B has a length of 3 and a direction of o A 180 o 0 o R B 270 o

43 Question 8 Two vectors, A and B, are added to give a resultant vector, R. The magnitudes are 3 and 8 meters, respectively, but the vectors can have any orientation. What is the maximum and minimum possible values for the magnitude of R? 90 o Maximum: 3+8=11 A 180 o 0 o Minimum: (-3)+(-8)=(-11) B 270 o

44 Vectors Subtraction of one vector from another is carried out in a way that depends on the following: When a vector is multiplied by -1, the magnitude of the vector remains the same, but the direction of the vector is reversed Vector subtraction is carried out exactly like vector addition except that one of the vectors added is multiplied by the scalar factor of -1

45 Vectors C B C B A A C = A + B A = C + (-B)

46 Vectors If the magnitude and direction of a vector is known, it is possible to find the components of the vector The process is called resolving the vector into its components If the vector components are perpendicular and form a right triangle, the process can be carried out with the aid of trigonometry

47 Vectors To calculate the sum of two or more vectors using their components (x and y) in the vertical and horizontal directions, trigonometry is used Opposite Side (X) θ Adjacent Side (Y)

48 Vectors The Pythagorean Theorem is a special relationship that exists in any triangle and describes the relationship between the lengths of the sides of a right triangle z 2 = x 2 + y 2 Three basic trigonometric functions defined by a right triangle are: sin θ = x/z = opposite side/hypotenuse cos θ = y/z = adjacent side/hypotenuse tan θ = x/y = opposite side/adjacent side tan θ = sine θ/cos θ

49 Vectors To find theta, the inverse of the trigonometric function must be used θ = sin -1 y/z θ = cos -1 x/z θ = tan -1 y/x When adding vectors, magnitude is found by: R = (R x ) 2 + (R y ) 2 The direction of the resultant, R, is found by: θ = sin -1 (R y /R)

50 Vectors Vectors can be added either in the same direction or in opposite directions Vector A Vector B 45 o 30 o

51 Vectors Adding vectors: 30 o Vector B o Vector A 10 Vector R

52 Vectors 30 o Vector B o Vector A 10 A y A x Vector A x = (10)(cos 45 o ) = 7.07 Vector A y = (10)(sin 45 o ) = PJM

53 Vectors 30 o Vector B 15 B y 45 o Vector A 10 B x Vector B x = (15)(cos 30 o ) = Vector B y = (15)(sin 30 o ) = PJM

54 Vectors Determine the resulting vectors, R x and R y : R x = A x + B x R x = o Vector B R x = Vector A R y = R y = A y + B y R y = R y = o R x = 20.06

55 Vectors R 2 2 R x R y R R R R 1 y sin R sin sin o

56 Vectors Polar notation expresses a vector in terms of both a magnitude and a direction such as: where: M M is the magnitude of the vector o is the direction in degrees Example: Vector with a magnitude of 10 and a direction of -40 degrees o

57 Vectors Multiplication in polar notation: Multiply the magnitudes/add the angles (50 25 o )(25 30 o ) = o Division in polar notation: Divide the magnitudes/subtract the angles (50 25 o ) = 2-5 o (25 30 o )

58 Question 9 A displacement vector R has a magnitude of R = 175 m and points at an angle of 50 o relative to the x-axis. Find the x and y components of this vector? α R Y 50 o θ X

59 Question 9 sinθ O H Y R Y sin m Y (175 m)sin m R 50 o α Y X H 2 O 2 R 2 Y 2 θ X X 175 m m m m

60 Summary Discussed the different components of a Right Triangles Reviewed the basics of Trigonometry Computed different Per-Unit Quantities Characterized the two components of Vectors

61 Questions?

62 Disclaimer: PJM has made all efforts possible to accurately document all information in this presentation. The information seen here does not supersede the PJM Operating Agreement or the PJM Tariff both of which can be found by accessing: For additional detailed information on any of the topics discussed, please refer to the appropriate PJM manual which can be found by accessing:

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