# All Solutions: the ph will lie between 0 and 14

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2 2 only 1; 0.01 molar hydrochloric acid will have a p of 2, and an infinitely dilute solution of hydrochloric acid (or any acid or base, strong or weak) will have a p of 7. Thus first aid for spills of acids or bases is dilution, not neutralization Weak Acids; pk a of the acid is between 2 and 12 If you make a 1 molar solution of a weak acid like acetic acid, only a fraction of the acetic acid molecules will donate their most acidic proton to water. The resulting solution will be less acidic than a solution of a strong acid of the same concentration. More precisely, 1 molar acetic acid, whose pk a is about 4.8, will have a p of only 2.4, which is less acidic than 1 molar hydrochloric acid, whose p will be 0. A shortcut to the p of 2.4 for 1 molar acetic acid is to see that 2.4 equals 1/2 of 4.8, the pk a of acetic acid. This is because the essential mathematical operation for the calculation of the p of a 1 molar solution of a weak acid is taking the square root of the acid ionization constant; dividing the log of a number by 2 is equivalent to taking the square root of the number. If you are willing to round the acid ionization constants for weak acids to the nearest power of ten, the math gets even easier. Thus if you take 5 as the pk a for acetic acid you can estimate the p of 1 molar acetic acid to be 2.5, a value that is for most purposes just as useful as 2.4. You can thus estimate that a 1 molar solution of a slightly stronger acid such as formic acid, pk a = 4, will have a p of 2, and that a 1 molar solution of a somewhat weaker acid such as phenol, pk a = 10, will have a p of about 5. One molar solutions of still weaker acids will be still less acidic, and you can be confident that solutions of ethanol or sugar, pk a about 14, will be no more acidic than pure water. In general, an aqueous solution of a substance whose most acidic proton has a pk a greater than 14 will be neutral. Just as you know that a 0.01 molar solution of Cl is less acidic than a 1 molar solution of Cl you would expect a 0.01 molar solution of acetic acid to be less acidic than a 1 molar solution of this acid. When you do the math you find that 0.01 molar acetic acid will have a p of 3.4, which is 1 p unit to the basic side of 2.4, the p of 1 molar acetic acid. The shortcut, apparently, is that for each factor of 100 by which the solution is diluted the p is 1 unit closer to 7. This is consistent with the idea that the more dilute the solution the more nearly its p will be 7. This also reflects the fact that 1/2[log 100] = 1/2[2] =1. You might now anticipate that the p of 0.1 molar acetic acid should be half way between 2.4 and 3.4, or /2[1] = 2.9; you would be right. Do p in Your ead; w1.0 Addison Ault 1/15/2008, 3:41 PM

3 3 Summary of solutions of acids. Strong acids are completely ionized; 1 molar solutions will have a p of 0, and less concentrated solutions will be less acidic. Weak acids are not completely ionized and 1 molar solutions will have a p equal to 1/2[pK a )] Less concentrated solutions of weak acids will be still less acidic, and if the acid is very weak the solution will be no more acidic than pure water. Table 1 presents a summary of several examples and reveals the pattern. Table 1 Acid pk a p of 1.0 molar solution p of 0.01 molar solution hydrogen chloride formic acid acetic acid anilinium ion pyridinium ion ammonium ion phenol ethanol O C O- 3 C O C O- N + N + N O- formic acid acetic acid anilinium pyridinium ammonium phenol ion ion ion pk a Solutions of Bases: the p will lie between 7 and 14 If you add a base, a source of hydroxide ion, to pure water you will have a basic solution. You can also produce basic solutions by adding substances that consume hydronium ion; salts of weak acids are such substances. Strong bases Do p in Your ead; w1.0 Addison Ault 1/15/2008, 3:41 PM

4 4 Strong bases are hydroxide ion donors that are completely ionized in water. The most common example of such a base is sodium hydroxide, and a 1 molar solution of sodium hydroxide will be 1 molar in hydroxide ion. The solution will therefore be 1x10 14 molar in hydronium ion, and will thus have a p of 14. Potassium hydroxide behaves in the same way. You can see that less concentrated solutions of strong bases will be less basic. For example, 0.1 molar sodium hydroxide will have a p of 13, and 0.01 molar NaO will have a p of 12. Finally, just as is true of an infinitely dilute solution of an acid, an infinitely dilute solution of a base will have a p of 7. Salts of weak acids and strong bases You have been told that the solutions of the salt of a weak acid and a strong base will be basic. An example of such a salt is sodium acetate, the salt of acetic acid, a weak acid, and sodium hydroxide, a strong base. The acetate ions will react to a small extent with water to form a small number of acetic acid molecules and an equally small number of hydroxide ions. The sodium ions will not react at all with water, and so the solution of 1 mole of sodium acetate in 1 liter of water will be slightly more basic than pure water due to the production of hydroxide ions; you have probably done a problem that shows that 1 molar sodium acetate should have a p of about 9.4. A shortcut to the value of 9.4 for the p of 1 molar sodium acetate is to see that just as the p of 1 molar acetic acid is 2.4 p units on the basic side of 0, the p of 1 molar sodium acetate is 2.4 p units on the basic side of 7. This result is, again, based on the essential mathematical operation for the calculation of the p of a 1 molar solution of the salt of a weak acid and a strong base. This operation is to take the square root of [(ionization constant of the acid) x (ion product of water)]. Taking the shortcut, then, the p is 1/2[pK a + pk w ]. For sodium acetate this is 1/2[ ] = = 9.4. If we were to round the pka value for acetic acid to 5, we would then estimate the p of 1 molar sodium acetate to be 9.5. If the weak acid is a little stronger, having a pk a of, say, 4, you can estimate that a 1 molar solution of its sodium salt should have a p of 4/2 + 7 = 9. The salt of the stronger weak acid undergoes hydrolysis to a lesser extent, and solutions of its salt are less basic. A 1 molar solution of this acid would have a p of 4/2 = 2. In general, the more acidic the weak acid the less basic will be its salts. Do p in Your ead; w1.0 Addison Ault 1/15/2008, 3:41 PM

5 5 Picking a weak acid more or less at random, you could predict that a 1 molar solution of fluoroacetic acid, pk a = 2.6, should have a p of about 1.3, and a 1 molar solution of sodium fluoroacetate should have a p of about 8.3. You can see that taking this trend to the extreme gives us something you know to be true: a 1 molar solution of hydrogen chloride should have a p of 0, and a 1 molar solution of sodium chloride should have a p of 7. Finally, just as less concentrated solutions of acids are less acidic so less concentrated solutions of bases are less basic, both types of solutions approaching a p of 7 at infinite dilution. Weak Bronsted bases A substance that can act as a proton acceptor toward water will produce an aqueous solution whose p is between 7 and 14. Because the pyridinium ion is about as acidic as acetic acid, pyridine will be as basic as acetate ion. Since the behavior of pyridine will be the same as that of acetate ion the math will be the same, and the p of 1 molar pyridine should be about 5/2 + 7 = 9.5. Summary of solutions of bases. An aqueous solution of a weak base will have a p between 7 and 14. A stronger base will give a more basic solution. Less concentrated solutions will be less basic. Table 2 presents a summary of several examples and reveals the pattern. Table 2 Base pk a of the conjugate acid p of 1.0 molar solution p of 0.01 molar solution sodium acetate pyridine aniline ammonia sodium phenoxide sodium hydroxide sodium ethoxide sodium amide Do p in Your ead; w1.0 Addison Ault 1/15/2008, 3:41 PM

6 6 Ethoxide ion and amide ion are so basic that they react completely with water to produce hydroxide ion. Thus 1 mole of either ethoxide ion or amide ion in 1 liter of water will give 1 mole of hydroxide ion, and a solution whose p will be 14. Solutions of Salts: The p will tend toward 7 Salts are ionic substances in which the ions are neither the proton or the hydroxide ion. Depending upon the relative tendencies of the two ions to react with water in such a way that protons or hydroxide ions are formed, solutions of salts may be either somewhat acidic, somewhat basic, or nearly neutral. There are four possibilities, and when you see which possibility is represented, you can quickly decide whether the solution will be slightly acidic, slightly basic, or just about neutral. If you know the approximate pk a values of the relevant ions you can estimate quite well the p of the solution. Salts of a strong acid and a strong base: the solution will be neutral Salts of a strong acid and a strong base, substances such as sodium chloride, potassium bromide, sodium nitrate, and potassium iodide will all give solutions with a p of practically 7. Neither ion shows any tendency to react with water to produce either hydronium ion or hydroxide ion. Salts of a strong acid and a weak base: the solution will be acidic Salts of strong acids and weak bases, substances such as pyridinium chloride and ammonium bromide, will give acidic solutions, as we have seen. In these salts the anion does not react with water to give hydroxide ion, but the cation does react with water to produce hydronium ion. The solution will therefore be acidic. Table 1 illustrates this possibility. Salts of a weak acid and a strong base: the solution will be basic Salts of weak acids and strong bases, substances such as sodium acetate and sodium phenoxide, will give basic solutions, as we have also seen. In these salts the cation does not react with water to give hydronium ion, but the anion does react with water to produce hydroxide ion. The solution will therefore be basic. Table 2 illustrates this possibility. Salts of weak acids and weak bases: the solution can be either slightly acidic or slightly basic Do p in Your ead; w1.0 Addison Ault 1/15/2008, 3:41 PM

7 7 Salts of weak acids and weak bases can give solutions that are either slightly acidic or slightly basic, depending upon the relative strengths of the acids and bases that have combined to give the salt. If the weak acid is stronger than the weak base, the solution will be slightly acidic; if the weak base is stronger than the weak acid, the solution will be slightly basic. The numerical value of the p is half way between the pk a values of the weak acid and the conjugate acid of the weak base. The case of ammonium phenoxide provides an example. You can see from Table 1 that 1 molar ammonium chloride will give a solution of p = 4.5, and from Table 2 that 1 molar sodium phenoxide will give a solution of p = 12. Thus you see that the phenoxide ion as a base is stronger than the ammonium ion as an acid. When they are put into competition in the same solution the phenoxide ion will win and he solution will be slightly basic; the p of the solution will be about 9.5, a p half way between the pk a of 9 for the ammonium ion and 10 for phenol. Other examples could include anilinium acetate, where the anilinium ion is a stronger acid than acetate ion is a base (solutions of this salt will have a p of 5), and ammonium acetate, where the ammonium ion as an acid and the acetate ion as a base are equal in strength, with the result that solutions of ammonium acetate will have a p of about 7. These examples and several others are presented in Table 3. An example of relevance in biochemistry is provided by the amino acid glycine. Glycine, or aminoacetic acid, exists as an inner salt, and so in analogy with ammonium acetate the p of 1 molar glycine will be half way between the pk a of the carboxyl group of glycine (2.4) and the pk a of the ammonium group of glycine (9.6). The half way p is [ ]/2 = 12/2 = 6. This half way p is also called the isoelectric p, or the isoelectric point. on the p scale. It is the p at which, over a period of time each glycine molecule is, on the average, neutral. ` + N C C O O pk a = 9.6 pk a = N C C O O conjugate acid of glycine glycine p in pure water = 6.2 Do p in Your ead; w1.0 Addison Ault 1/15/2008, 3:41 PM

8 8 It is generally true that solutions of amino acids without acidic or basic side chains will give aqueous solutions with a p of 6, a p half way between the pk a of the carboxyl group (close to 2.5) and the pk a of the ammonium group (close to 9.5). Summary of solutions of salts of weak acids and weak bases Solutions of salts will be weakly acidic, neutral, or weakly basic, depending upon which ion is the stronger acid or the stronger base. The exact p will be the average of the two relevant pk a values. The p of solutions of several salts are presented in Table 3. Table 3 Salt pk a of acid pk a of conj acid of base p of 1 molar solution sodium chloride 7 ammonium phenoxide anilinium acetate ammonium acetate pyridinium acetate glycine alanine Solutions of Conjugate Pairs Sometimes you will prepare an aqueous solution that contains both an acid, such as acetic acid, and its conjugate base, in this case an acetate salt, perhaps sodium acetate. When you do this, the p of the resulting solution will be close to the pk a of acetic acid, the exact value of the p depending upon the ratio of the concentrations of the members of the conjugate pair. The isoconjugate p If you should dissolve equimolar amounts of acetic acid and sodium acetate in water, the ratio of acetic acid molecules to acetate ions, the members of this conjugate pair, will be 1 to 1, and the p of the solution will equal the 4.8, the pk a of acetic acid, the acidic member of this conjugate pair. For the Do p in Your ead; w1.0 Addison Ault 1/15/2008, 3:41 PM

9 9 conjugate pair acetic acid and acetate ion, the p of 4.8 is the isoconjugate p or isoconjugate point on the p scale. Deviations from the isoconjugate p If you prepare a solution in which the acidic member of the conjugate pair predominates, the p of the solution will be on the acidic side of the isoconjugate p. Conversely, if you prepare a solution in which the basic member of the conjugate pair predominates the p of the solution will be on the basic side of the isoconjugate p. The degree to which the p of the solution deviates from the isoconjugate p equals the log of the ratio of the members of the conjugate pair. If the ratio is 10 to 1, the deviation is 1 p unit, and smaller ratios will give smaller deviations. And, of course, as the ratio approaches 1 to 1, the deviation will approach 0; the log of 1 is 0, and the p will equal the pk a. The math here follows the enderson-asselbalch equation, but if you round the pk a values to integers and ratios to powers of 10 you can do the math in your head to get approximate values that are quite adequate. Table 4 illustrates the pattern for deviations from the isoconjugate p. Table 4 ratio of members of conjugate pair log of ratio of members of conjugate pair deviation from isoconjugate p 1000 to to to to to to Buffers You may have recognized the solutions that we have just described as buffered solutions, solutions that resist a change in p either by dilution or by the addition of small amounts of acids and bases. These solutions resist a change in p by dilution because the p is determined by the ratio of the concentrations of the members of the conjugate pair. Although dilution will change the concentrations of both members of the conjugate pair, dilution will not change their ratio. Do p in Your ead; w1.0 Addison Ault 1/15/2008, 3:41 PM

10 10 These solutions will also resist a change in p upon the addition of small amounts of either acid or base. Continuing with the acetic acid/acetate ion solution, so long as added acid or base does not reduce either acetate ion or acetic acid below 1/10 of the total of acetate ion plus acetic acid, the ratio of the members of this conjugate pair will stay within the range of 10:1 to 1:10 and the p of the solution will stay within 1 p unit of the isoconjugate p. We call solutions such as this, which resist these efforts to change the p, buffered solutions. Table 5 presents examples of acetic acid/acetate ion buffers. The isoconjugate p of this pair is about 4.8. Table 5 acetic acid to acetate ion ratio p of the solution 10 to to to to to to to Do p in Your ead; w1.0 Addison Ault 1/15/2008, 3:41 PM

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