Chapter Two. Deductive Reasoning


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1 Chapter Two Deductive Reasoning
2 Objectives A. Use the terms defined in the chapter correctly. B. Properly use and interpret the symbols for the terms and concepts in this chapter. C. Appropriately apply the properties and theorems in this chapter. D. Correctly interpret the information contained in a conditional. E. Understand and properly use algebraic properties F. Properly prove theorems relating to lines and angles.
3 Section 21 IfThen Statements; Converses Homework Page 35: 130
4 Objectives A. Identify and properly use conditional statements. B. Identify the hypothesis and conclusion of conditionals. C. Identify and state the converse of a conditional. D. Provide correct counterexamples to prove statements false. E. Identify and use biconditional statements.
5 Conditional Statements We use conditional statements in our everyday language, as well as in our mathematical language. The common form of a conditional statement, or conditional, is: If hypothesis, then conclusion.
6 Hypothesis Conditional Statements According to MerriamWebster dictionary a tentative assumption made in order to draw out and test its logical or empirical consequences More simply a set of preconditions from which we attempt to reach a conclusion. Or the information which must be known in order to apply the conclusion to a problem. In geometry, it is common for the hypothesis to describe a diagram, or to be part of a diagram. Conclusion Information which can be added to a problem when the criteria of the hypothesis have been met.
7 Conditional Statements Conditional statements can be TRUE or FALSE: If they are considered TRUE, they must be TRUE in ALL cases. If there is a SINGLE case where the statement is false, then the ENTIRE conditional is considered FALSE! Examples: If I do not eat, then I will eventually starve. If I live in Bexley, then I live in Ohio. If I add 3 to 4, then I will have 7. If you cheat on homework, then you won t do well in this class. If you want the freedom of an adult, then you must accept adult responsibilities.
8 Other Forms of Conditional Statements Thanks to the English language, you have several other ways of expressing a conditional statement: IF hypothesis, THEN conclusion. hypothesis IMPLIES conclusion. hypothesis ONLY IF conclusion. conclusion IF hypothesis.
9 Equivalent Conditionals: Examples If you live in Ohio, then you live in the United States. You live in Ohio implies that you live in the United States. You live in Ohio only if you live in the United States. You live in the United States if you live in Ohio. 4
10 Say it ain t so! A major outcome of your work in this class will be your ability to prove or disprove conditionals. Remember, a conditional is always true or it is false, there is no sometimes this, sometimes that. To prove a conditional or theorem to be true usually takes a number of steps. The proof MUST show that the statement to be true for ALL cases. To prove something is false we need ONLY ONE example where the hypothesis contradicts the conclusion. Such an example is known as a counterexample: A counterexample proves a conditional false by agreeing with the hypothesis but disagreeing with the conclusion.
11 Counterexamples If it is a week night, then you have geometry homework. Counterexample December 25 th may be a week night this year, but you don t have geometry homework on Christmas. This statement agrees with the hypothesis, but disagrees with the conclusion. Since we have found one counterexample for the conditional we say the conditional is false. If we find at least one counterexample that proves the conditional false, it makes no difference how many examples we can find where it is true. Because the conditional was false once, it may be false again. So the conditional has no value in predicting the future or judging the present. 4
12 Converse of a Conditional converse: The converse of a conditional is another ifthen statement formed by interchanging the hypothesis and the conclusion of a given statement. Conditional statement If p then q Converse of above statement If q then p Example: Conditional If tomorrow is Saturday, then today is Friday. Converse If today is Friday, then tomorrow is Saturday.
13 Converses of Conditionals NOTE! Just because the conditional statement is true does NOT make the converse of the statement true! Likewise, just because the converse of a statement is true does not make the conditional true. Example: Conditional If I have 2 dimes and a nickel, then I have 25 cents. Converse If I have 25 cents, I have 2 dimes and a nickel. Remember, you need only ONE counterexample to prove a statement false.
14 Biconditionals For a statement to be biconditional, both the original conditional (statement) and its converse must be true. One sign that you have a biconditional statement is the key phrase if and only if to connect the parts of the statement. In a biconditional, the order of the phrases can be switched without changing the meaning.
15 Biconditional Example Conditional If I draw a right angle, then I draw a 90 degree angle. Converse If I draw a 90 degree angle, then I draw a right angle. Biconditional I draw a right angle if and only if I draw a 90 degree angle.
16 Definitions Written as Biconditionals An angle is acute if and only if it measures between 0 and 90. An angle measures between 0 and 90 if and only if the angle is acute. A ray bisects an angle if and only if it divides the angle into two congruent adjacent angles. A ray divides the angle into two congruent adjacent angles if and only if the ray bisects an angle. Points are collinear if and only if the points lie on one line. Points lie on one line if and only if the points are collinear. 3
17 Recommendations When it is possible, I HIGHLY recommend that you reword any definitions, postulates, and theorems in their biconditional form. In all other cases, I HIGHLY recommend you reword any definitions, postulates, and theorems in their IF/THEN form.
18 Section 21 Sample Problems Write the hypothesis and the conclusion of each conditional. 1. If 3x  7 = 32, then x = 13 If 3x  7 = 32, then x = I ll try if you will. I ll try if you will. 5. a + b = a implies b = 0. a + b = a implies b = 0.
19 Section 21 Sample Problems Rewrite each pair of conditionals as a biconditional. 7. If B is between A and C, then AB + BC = AC. If AB + BC = AC, then B is between A and C. B is between A and C if and only if AB + BC = AC. AB + BC = AC if and only if B is between A and C. Write each biconditional as two conditionals that are converses of each other. 9. Points are collinear if and only if they all lie on one line. If points are collinear, then they all lie on one line. If points all lie on one line, then they are collinear.
20 Sample Problems Section 21 Provide a counterexample to show that each statement is false. You may use words or diagrams. 11. If ab < 0, then a < 0. Let a = 2 and b = 3. Therefore, ab = 6. In this case, ab < 0 (agrees with hypothesis), but a > 0 (disagrees with conclusion). 13. If point G is on AB, then G is on BA. 15. If a four sided figure has four right angles, then it has four congruent sides.
21 Sample Problems Section 21 Tell whether each statement is true or false. Then write the converse and tell whether it is true or false. 17. If x =  6, then x = 6. True If x = 6, then x = 6. False, x = If b > 4, then 5b > If Pam lives in Chicago, then she lives in Illinois. 23. a 2 > 9 if a > 3.
22 25. n > 5 only if n > 7. Sample Problems Section If points D, E and F are collinear, then DE + EF = DF. 29. Write a definition of congruent angles as a biconditional.
23 Section 22 Properties from Algebra Homework Pages 4142: 114
24 Objectives A. Properly use and describe algebraic properties. B. Relate the algebraic properties to geometric properties. C. Properly apply geometric properties.
25 Algebraic Properties of Equality: Transformations Addition: You may add the same value to both sides of an equation. If a = b, then a + c = b + c. Subtraction (add a negative): You may subtract the same value from both sides of an equation. If a = b, then a  c = b  c. Multiplication: You may multiply the same value to both side of an equation. If a = b, then a * c = b * c.
26 Algebraic Properties of Equality: Transformations Division (multiply by a reciprocal): You may divide the same value into both sides of an equation. If a = b, then a / c = b / c. HOWEVER: c cannot be zero! Distribution: You may multiply a factor next to a grouping symbol to every term inside the grouping symbol. If a (b + c + d) = e, then ab + ac + ad = e. Substitution: Left and right sides of an equation are interchangeable. Either statement may be used in another equation. If a + b = c AND d e = c, then: a + b = d e
27 Algebraic Properties of Equality: Transformations Reflexive: A value must equal itself. a = a Symmetric: The left and right sides of an equation can be switched. If a = b, then b = a. Transitive: Any two values in a chain of equality are equal. If a = b AND If b = c. then a = c.
28 But what about GEOMETRIC properties? Remember, we cannot talk about two FIGURES being EQUAL! Two geometric figures can be CONGRUENT. So certain properties, such as the Addition Property of Equality, cannot be applied to figures. However, SOME algebraic properties can be applied to figures. Lengths of line segments and measures of angles are real numbers. Therefore, we can apply algebraic properties of equalities (such as the Addition Property) to these real numbers.
29 Properties of Congruence Reflexive: Any object must be congruent (same size and shape) to itself. DE DE D D Symmetric: The objects on the left and right sides of a congruence statement may be switched. If If DE D FG E then FG DE. then E D. Transitive: Any two objects in a chain of congruence statements are congruent (same size and shape). If DE FG and FG JK then DE JK. If D E and E F then D F.
30 So, what do we do with these properties? We use these algebraic and geometric properties to prove statements. For example: If 3X + 5 = 17, then X = 4. 3X + 5 ( 5) = 17 ( 5) 3X = 12 3X 12X X X = 4 Given. Subtraction Property of Equality. Division Property of Equality. Symmetric Property of Equality.
31 Sample Problems Section 22 Justify each step. (Give the reason for each step.) 1. 4x 5 = 2 Given. 4x = 3 Addition Property of Equality x 3 4 Division Property of Equality
32 Sample Problems Section 22 Justify each step. (Give the reason for each step.) 3. z 7 11 Given. 3 z 7 33 Multiplication Property of Equality z = 40 Addition Property of Equality
33 Sample Problems Section 22 Justify each step. (Give the reason for each step.) 5. 2 b 8 2b 3 2b 3(8 2b) 2b 8b b 24 6b 3 24
34 Sample Problems Section 22 Given: AOD as shown Prove: m AOD = m 1 + m 2 + m 3 A B O 1 C 2 3 D Statements 0. AOD as shown 1. m AOD = m AOC + m 3 2. m AOC = m 1 + m 2 3. m AOD = m 1 + m 2 + m Reasons Given. Angle Addition Postulate Angle Addition Postulate Substitution Property of Equality
35 Sample Problems Section 22 Given: DW = ON Prove: DO = WN D O W N Statements 1. DW = ON 2. DW = DO + OW ON = OW = OW Reasons 3. Substitution 4. 5.
36 1. m 1 m 2; m 3 m 4 2. m SRT m 1 m 3; m STR m 2 m 4 3. m SRT m 2 m 3 Sample Problems Section Given: m 1 = m 2; m 3 = m 4 Prove: m SRT = m STR 4. m SRT m 2 m 4 5. m SRT m STR R 1. Given P S Z Q Angle Addition Postulate 3. Substitution Property of = 4. Substitution Property of = 5. Substitution Property of = T
37 Sample Problems Section Given: RQ = TP ZQ = ZP Prove: RZ = TZ S P Z Q R T
38 Section 23 Proving Theorems Homework Page 46: 116
39 Objectives A. Use the Midpoint Theorem and the Angle Bisector Theorem correctly. B. Understand the valid reasons used in proofs. C. Apply valid reasons to prove theorems and conditionals.
40 Also known as direct proof Deductive Reasoning Deductive reasoning is one logical process used to prove conditionals true by building an argument based upon valid reasoning.
41 Valid Reasons Used in Proofs The items you may use in a proof are: Information given in the hypothesis, Information given in diagrams, Accepted postulates, Algebraic and geometric properties, Definitions, Previously proven or accepted theorems, and Previously proven or accepted corollaries.
42 Theorem 21 (Midpoint Theorem) If M is the midpoint of segment AB, A M B then AM = ½AB and MB = ½AB.
43 Proof Of Midpoint Theorem If M is the midpoint of segment AB, then AM = ½AB and MB = ½AB. A M B Now that I know M is the midpoint, what else can I say? Statements Reasons M is the midpoint of AM MB AM MB AM + MB = AB AM + AM = AB 2AM = AB AM = ½ AB AB Given Definition of Midpoint. Definition of Congruence. Segment Addition Postulate. Substitution Property. Simple addition. Division Property of Equality
44 Theorem 22 (Angle Bisector Theorem) If ray BX is the bisector of ABC, A X B C then m ABX = ½m ABC and m XBC = ½m ABC.
45 Proof Of Angle Bisector Theorem If ray BX is the bisector of ABC, then m ABX = ½ m ABC and m XBC = ½ m ABC. A X Statements B Reasons C
46 Sample Problems Section 23 Name the definition, postulate or theorem that justifies the statement about the diagram. 1. If D is the midpoint of BC, then BD 3. If AD bisects BAC, then 1 2. DC A 5. If BD DC, then D is the midpoint of BC m 1 + m 2 = m BAC 1. Definition of midpoint. 3. Definition of angle bisector. 5. Definition of midpoint. 7. Angle Addition Postulate B 3 4 D C
47 Sample Problems Section 23 Write the number that is paired with the bisector of CDE. C E 11. D C E D
48 Sample Problems Section The coordinates of points L and X are 16 and 40, respectively. N is the midpoint of LX, and Y is the midpoint of LN. Sketch a diagram and find: a. LN b. the coordinate of N c. LY d. the coordinate of Y L Y N X LN = Length of the segment LN = = 24 = 24 N = Midpoint of the segment LX = ( ) / 2 = 28 LY = Length of the segment LY = ½ LN LN = ½ LX = ½ (24) = 12 LY = ½ LN = ½ (12) = 6 Y = Midpoint of the segment LN = ( ) / 2 = 22
49 Sample Problems Section a. Suppose M and N are the midpoints of LK and GH, respectively. What segments are congruent? b. What additional information about the picture would enable you to deduce that LM = NH. G N H LM = NH LM = GN MK = NH LK = GH
50 Sample Problems Section 23 What can you deduce from the given information? 17. Given: AE = DE; A CE = BE B E D C AE = BE? DE = EC? AC = DB?
51 Section 24 Special Pairs of Angles Homework Pages 5254: 133
52 Objectives A. Use the terms complementary, supplementary, and vertical angles correctly. B. Apply these terms to proofs. C. Use the Vertical Angle Theorem correctly.
53 Definitions complementary angles: A pair of coplanar angles, called complements, whose measurements add up to be 90. supplementary angles: A pair of coplanar angles whose measurements add up to be 180. A supplement of an angle is another angle that when added to the first makes 180. vertical angles: A pair of coplanar angles such that the sides of one angle are opposite rays to the sides of the other angle.
54 Complementary Angles 3
55 Supplementary Angles 6
56 Vertical Angles 6
57 Vertical angles are congruent. Theorem 23
58 Proof Of Theorem 23 (Vertical Angles Theorem) Given: Diagram Prove: Statements Reasons 1. Diagram 1. Given 2. Angles 1 & 2 are vertical angles 2. Definition of vertical angles 3. m 1 m m 2 m m 1 m 3 m 2 m 3 5. m 3 m 3 6. m 1 m Definition of straight angles (Angle Addition Postulate) 4. Substitution Property of Equality 5. Reflexive Property of Equality 6. Subtraction Property of Equality 7. Definition of congruence
59 Sample Problems Section 24 Find the measures of a complement and a supplement of K. 1. m K = m K = x 5. Two complementary angles are congruent. Find their measures. 1. Complimentary angles add to 90. Supplementary angles add to 180. Compliment + m K = 90 Compliment + 20 = 90 Compliment = Compliment + m K = 90 Compliment + x = 90 Compliment = 90  x 5. x + x = 90 2x = 90 x = 45 Supplement + m K = 180 Supplement + 20 = 180 Supplement = 160 Supplement + m K = 180 Supplement + x = 180 Supplement = x
60 Sample Problems Section 24 In the diagram, AFB is a right angle. Name the figures described. 7. Another right angle. 9. Two congruent supplementary angles. 11. Two acute vertical angles. 7. AFD 9. AFD and AFB A E 11. EFD and BFC B F D How can you PROVE these angles are acute and vertical? C
61 In the diagram, Sample Problems Section 24 OTbisects SOU, m UOV = 35, and m YOW = 120. Find the measure of each angle. 13. m ZOY 17. ½ (120 ) = m VOW 17. m TOU T U 35 V S = 25 O W Z Y X
62 Find the value of x. Sample Problems Section x 19. (3x 5) = 70 3x = 75 x = = 100 WHY? 4x = 100 WHY? x = 25 WHY?
63 Sample Problems Section Given: 2 3 Prove: and diagram Transitive Property
64 Sample Problems Section 24 If A and B are supplementary, find the value of x, m A and m B. 25. m A = x + 16, m B = 2x m A + m B = 180 REASON? x x  16 = 180 REASON? 3x = 180 REASON? x = 60 REASON? m A = 76 m B = 104 REASON?
65 Sample Problems Section 24 If C and D are complementary, find the value of y, m C and m D. 27. m C = y  8, m D = 3y + 2 Use the information given to write an equation and solve the problem. 29. Find the measure of an angle that is half as large as its complement. 31. A supplement of an angle is six times as large as a complement of the angle. Find the measures of the angle, its supplement and its complement.
66 Sample Problems Section 24 Find the values of x and y for each diagram. 33. x 50 (3x  y)
67 Section 25 Perpendicular Lines Homework Pages 5860: 125, 28
68 Objectives A. Use the term perpendicular lines correctly. B. Apply the term perpendicular lines to theorems. C. Use the theorems associated with perpendicular lines (Theorems 24, 25, and 26) correctly.
69 Definition of Perpendicular Lines Perpendicular lines are two lines that intersect to form right angles. Notice how we are using previous terms (defined and undefined) to build new terms.
70 Theorem 24 If two lines are perpendicular, then they form congruent adjacent angles.
71 Theorem 25 If two lines form congruent adjacent angles, then the lines are perpendicular.
72 Comparing Theorems 24 and 25 How is Theorem 24 (If two lines are perpendicular, then they form congruent adjacent angles) related to Theorem 25 (If two lines form congruent adjacent angles, then the lines are perpendicular)? Are they the same? Could they be written as a single statement? What type of statement?
73 Theorem 26 If the exterior sides of two adjacent acute angles are perpendicular, then the angles are complementary. A D B C m ABD + m DBC = 90
74 Proof Of Theorem 26: If the exterior sides of two adjacent acute angles are perpendicular, then the angles are complementary. Given : OA OC Prove : AOB and BOC are complimentary. A O B C Statements 1. OA OC 1. Given 2. AOC is a right angle. 3. m AOC 90. Reasons 2. Definition of lines. 3. Definition of right angle. 4. m AOB m BOC m AOC 4. Angle addition postulate. 5. AOB m BOC 90 m 5. Substitution property of = m 6. Def. of complimentary s. 6. AOB and m BOC complimentary s
75 Sample Problems Section In the diagram, UL MJ and m JUK = x. Express in terms of x the measures of the angles: a. LUK b. MUK L K x M U J a. m LUK 90 x b. m MUK 180 x
76 Sample Problems Section 25 Name the definition or state the theorem that justifies the statement about the diagram. 3. If EBC is a right angle, then BE AC. 5. If BE AC, then ABD and DBE are complementary. 7. If BE AC, then m ABE = 90. D E F A B C 3. Definition of perpendicular lines. 5. If the exterior sides of 2 adjacent acute angles are perpendicular, then the angles are complementary. 7. Definition of perpendicular lines and right angles.
77 Sample Problems Section 25 In the diagram, BE AC and BD BF. Find the value of x. 9. m ABD = 2x  15, m DBE = x 11. m ABD = 3x  12, m DBE = 2x + 2, m EBF = 2x + 8 E D F A B C 9. m ABD + m DBE = 90 2x x = 90 3x  15 = 90 3x = 105 x = m ABD + m DBE = 90 3x x + 2 = 90 5x  10 = 90 5x = 100 x = 20
78 Sample Problems Section 25 In the figure BF AE, m BOC = x, and m GOH = y. Express the measures of the angles in terms of x and y. 15. COH 17. DOE 15. m COH = y 17. m DOE = 90  (x + y ) B x C D A H y O E G F
79 Sample Problems Section 25 Can you conclude from the information given for each exercise that XY XZ? and 3 are complementary 21. m 1 = m m 1 = m 2 and m 3 = m and No, m 1 = 40 m 2 = 10 m 3 = No, what if m 1 = 70? 23. Yes: m 1 + m 2 + m 3 + m 4 = 180 2m 2 + 2m 3 = 180 m 2 + m 3 = No, what if m 1 = 70? X Y Z
80 Sample Problems Section 25 What can you conclude from the information given. 27. Given: AD AC; CE AC; m 1 = m 4 D B E A C
81 Section 26 Planning a Proof Homework Pages 6364: 122
82 Objectives A. Understand and apply theorems 27 (supplementary angles) and 28 (complementary angles) correctly. B. Apply the twocolumn deductive proof method to prove statements, theorems, and/or corollaries.
83 Theorem 27 If two angles are supplements of congruent angles (or the same angle), then the two angles are congruent. A B D C ABC & BCD are supplementary ADC & BCD are supplementary ABC & ADC are congruent
84 Theorem 28 If two angles are complements of congruent angles (or of the same angle), then the two angles are congruent. A B C O D AOB & BOC are complementary COD & BOC are complementary AOC & COD are congruent
85 Producing a Proof All proofs you will produce will be twocolumn proofs, regardless of the directions in the book. Therefore, if the book says produce a paragraph proof, you will instead produce a twocolumn proof. All twocolumn proof should appear as a twocolumn table The left column will be the statements column. The right column will be the reasons column. Statements Reasons
86 Statements: Parts of a Two Column Proof Each statement should be numbered and supported in the reason column. The first statement is a list of the given information found in the hypothesis of the conditional or from information in a diagram. The body of the proof consists of a logical series of statements and reasons flowing from the givens and from information that can be proved from the diagram. The last statement must be what you were required to prove, found in the conclusion of the conditional.
87 Reasons: Parts of a Two Column Proof Each reason should be numbered so that it matches the statement it supports. The first reason will be given provided that the first statement was a list of the given information. Only given, definitions, postulates, algebraic properties, theorems and their corollaries are acceptable reasons for the body of the proof. The final reason will depend upon the logical structure of the whole proof, but it still must come from the list above (except that it cannot be given ).
88 Each Row in the Twocolumn Proof Remember! For each row in the proof: The hypothesis in the reason must be shown to be true in preceding statements. The conclusion in the reason must match the statement. Writing all definitions, postulates, properties, theorems and corollaries as standard ifthen conditionals will make this a lot easier! C A O B D Statements Reasons 1. Given lines AB and CD are perpendicular and intersect at point O. 1. Given 2. Angle BOC is a right angle. 2. If two lines are perpendicular then they intersect at right angles.
89 Steps for Writing a Two Column Proof Step 1: Identify the conditional you are required to prove. Step 2: Draw, label, and annotate a diagram for the proof. Step 3: List from the conditional, in terms of the figure, what is given. This is the first statement/reason in the proof. Step 4: Determine from the conditional, in terms of the diagram, what is to be proven. This will be the last statement in the proof. Step 5: List from the diagram, in terms of the figure, what can be proven and why. Step 6: Select and arrange, in a logical order, those statements from steps 3, 4 & 5 that will allow you to move from the given information to the statement to be proved. N.B. If you get stuck writing the proof from the top down, then work up from the conclusion by deciding what you had to know to make that statement. 22 N
90 Example of a Two Column Proof: #21 page 64 Step 1: If AC BC and 3 is complementary to 1, then 3 2. Step 2: A 3 C 1 2 D B Step 3: Given: AC BC 3 is complementary to 1 Step 4: Prove: 3 2 Step 5: m ACB = 90, Definition of perpendicular lines, right angles m 3 + m 1 = 90, def comp s m 2 + m 1 = m ACB, Angle Addition Postulate m 2 + m 1 = 90, substitution property of equality 2 is complementary to 1, def comp s m 3 + m 1 = m 2 + m 1, transitive m 3 = m 2, subtraction property of equality 3 2, Th. 28: Complementary Angles P
91 Example of a Two Column Proof: #21 page 64 Step 5: m ACB = 90, definition of right angles, definition of m 3 + m 1 = 90, def comp s m 2 + m 1 = m ACB, Angle Addition Postulate m 2 + m 1 = 90, substitution property of = 2 is complementary to 1, def comp s m 3 + m 1 = m 2 + m 1, transitive property of = m 3 = m 2, subtraction property of equality 3 2, Th. 28: Complimentary Angles Step 6: Statements Reasons 1. AC BC, 3 is complementary to 1 1. Given 2. m ACB = def 3. m 2 + m 1 = m ACB 3. Angle Add. Post. 4. m 2 + m 1 = Substitution prop = 5. 2 is complementary to 1 5. def comp s Th. 28 P
92 Sample Problems Section 26 Write the name or statement of the definition, postulate, property, or theorem that justifies the statement about the diagram. 1. AD + DB = AB If D is on the line segment AB, then AD + DB = AB. 3. If vertical angles exist, then the angles are congruent. A H 6 C D 5 E G F B
93 Sample Problems Section 26 Write the name or statement of the definition, postulate, property, or theorem that justifies the statement about the diagram. 5. If DF bisects CDB, then If CD AB, then m CDB = If two lines are perpendicular, then they meet to form right angles. If an angle is a right angle, then it measures If a ray bisects an angle, then it cuts the angle into 2 congruent angles. A H 6 C D 5 E G F B
94 Sample Problems Section 26 Write the name or statement of the definition, postulate, property, or theorem that justifies the statement about the diagram. 9. If m 3 + m 4 = 90, then 3 & 4 are complementary. 11. If AB CE, then ADC ADE. 13. If FDG is a right angle, then DF DG. 9. If the sum of the measure of two angles is 90, then the angles are complementary. 11. If two lines are perpendicular, then they form congruent adjacent angles. A H 6 C D 5 E G F B
95 Sample Problems Section Given: 1 & 5 are supplementary 3 & 5 are supplementary Prove: & 5 are supplementary 1. 3 & 5 are supplementary 2. m 1 + m 5 = m 3 + m 5 = m 1 + m 5 = m 3 + m m 5 = m m 1 = m 3 or
96 Sample Problems Section Given: PQ QR, PS SR, 1 4 Prove: 2 5 Q P R 4 5 S 6 1. PQ QR, PS SR, is comp. to is comp to
97 Sample Problems Section Given: 2 3 Prove: Given: AC BC 3 is comp. to 1 Prove: A C 1 2 D B
98 Chapter Two Deductive Reasoning Review Homework Pages 6869: 112
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