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3 Example 1 : Evaluate without using a calculator. Solution : There are no parentheses or exponents, so do multiplications and divisions from left to right in the order they appear, then do additions and subtractions = = 13-3 = 10 Note: Often it is a good idea in complicated expressions to use extra parentheses to document the order of operations. For example, the expression can be written in a more readable form using parentheses: 7 + (3. ) - (18 6 ). Example : Evaluate 6 + 3(8-3) without using a calculator. Solution : According to the order of operations, we have to calculate what is inside the parentheses first: 6 + 3(8-3) = 6 + 3(5) do what is inside the parentheses first = multiply before adding = 1 Example 3 : Evaluate 6-4[8 + 3(7-3)] without using a calculator. Solution : This expression has nested parentheses where the [ ] are used in the same way as parentheses. In a case like this, we move to the innermost set of parentheses first and begin simplifying: 6-4[8 + 3(7-3)] = 6-4[8 + 3(4)] = 6-4[8 + 1] = 6-4[0] = 6-80 = - 74 Witkowski and Phillips Page 3

4 Example 4 : Evaluate without using a calculator. Solution : There are no parentheses or exponents, so we go from left to right and do all multiplications and divisions in the order they appear. In this case a division comes before a multiplication, so the division is done first = = = 19-8 = 11 Example 5 : Evaluate without using a calculator. Solution : We do powers(exponents) first = Now do multiplications and divisions from left to right. = = 76-8 = 68 Example 6 : Evaluate 5 7(8 4) without using a calculator. Solution: First, we must do what is inside the parentheses and then square that number. Next, we would multiply the answer by 7, then add (8 4) = 5 7(4) When computing an expression such as , the fraction bar has the same function as parentheses. Any operations that appear above or below a fraction bar should be completed first. Witkowski and Phillips Page 4

5 Example 7 : Compute Solution: We have to compute and 6-3 before we divide = = 18 3 = 6 You should be able to write this problem on a horizontal line because, as was mentioned previously, this is how you enter it on a calculator or a computer. So becomes ( ) (6-3) or ( ) / (6-3) Example 8 : Compute (6) Solution: We have to compute what is under the square root first. Since the entire fraction is under the square root, we simplify that first, then take the square root (6) = Note: If you write this problem on a horizontal line to put in a calculator or computer, be sure to put parentheses around everything under the. It would look like 0.5 ((9. 0.(6)) / ). Witkowski and Phillips Page 5

6 Activity 1 Evaluate the following without using a calculator: (3 + ). 4[6-4( - 7)] (9 6) [9 5 8 ] It is important to be able to translate from mathematical symbols into words and vice versa. For example, 3 + 4(3 + 1), is translated into words as, 3 added to the product of 4 and the sum of 3 and 1. Key words to remember: sum is the answer to an addition problem, difference is the answer to a subtraction problem, product is the answer to a multiplication problem, and quotient is the answer to a division problem. Witkowski and Phillips Page 6

7 Example 9 : Translate the following English expressions into mathematical expressions written in symbols. a) 6 times the sum of 7 and 10 b) The sum of 3 times and 1 times 5 c) Three times the difference of 14 and 8 d) 6 subtracted from the quotient of 4 and 8 Solution: a) 6(7 + 10) Note that the words "sum of" required the use of ( ) so that we would add before multiplying. b) Here we do not need the ( ) because the order of operations tells us to multiply first, then add. c) 3(14-8) Note that the words "difference of" required the use of ( )so that we would subtract before multiplying. d) or We can use either a fraction bar or a division symbol,, to indicate a quotient. Activity 1. Translate the following English expressions into mathematical expressions written in symbols. a) 8 times the sum of 4 and. b) 4 added to 3 times the sum of 5 and 8 c) The difference of 6 times 9 and the sum of 4 and 7.. Translate the following mathematical expressions into English expressions. a) 30 - (19-5) b) c) (4 + 6) 8 d) Witkowski and Phillips Page 7

8 Section 3: The Distributive Property The expression 4(6 + 7) can be computed two ways: 1. using the order of operations, 4(6 + 7) = 4(13) = 5,. by using the distributive property. The distributive property states that the product of one number and the sum of two or more other numbers is equal to the sum of the products of the first number and each of the other numbers of the sum. For example using the distributive property on the expression 4(6 + 7), we get 4(6 + 7) = = = 5. The Distributive Properties a(b + c) = ab + ac a(b - c) = ab - ac Terms and Factors When an expression consists of several parts connected by addition and subtraction signs, each part (along with its sign) is known as a term of the expression. Factors are quantities that are multiplied together. For example, in the expression the terms are 3 and The factors are 5 and 6. To properly apply the distributive property one has to distinguish between terms and factors. When you look at the distributive property you see that the parentheses are removed by multiplying each of the terms inside the parentheses by the other factor. Example 10: a) 5x and 3ab are the terms of the expression 5x + 3ab. b) 3x y 5 has only one term. c) x - 7 has two terms, x and -7. d) (x + 5) has only one term. In the above example, 3x y 5 has only one term, however this one term it is made up of three factors. Factors are numbers (coefficients) or variables that are multiplied in a product. In this example the factors are 3, x, and y 5. In an expression, if you followed the order of operations and the last operation is multiplication, there is only one term. Example 11 : a) (x + 1)(x + ) has two factors, (x + 1) and (x + ). b) x + 3 has one factor, x + 3. Witkowski and Phillips Page 8

9 Activity 3 In each of the following algebraic expressions, name the terms and factors. number of terms terms factors a) x b) 6x 1 6x 6 and x c) 6x + 1 d) x(x + 1) e) ( - x)(x + 1) f) 4[6-4( - 7)] Example 1 : Use the distributive property to simplify 5x (1 x)(8). Solution: Even though the 8 is to the right of the parentheses, we still distribute it. Then we would need to combine like terms to simplify. 5x (1 x)8 5x 1(8) (x)(8) 5x 8 8x combine 5x 8x 3x 3x 8 Now let's use the distributive property to evaluate some expressions. Activity 4 Evaluate 3 + 5[6-9] first using the order of operations and then using the distributive property. Evaluate 4[6-4( - 7)] using the distributive property. Witkowski and Phillips Page 9

10 Section 4: Using a Calculator You have to remember that the minus sign is used in two different ways: (1) to indicate subtraction and () to designate a negative number. The - key is used for subtraction, and the +/- key is used to change the sign of a number. If you are using a graphing calculator, the negative sign of is entered with the (-) key before the 3.97 is entered. Also note that on a graphing calculator, you have a ENTER key rather than a = key. Example 13 : Compute 5( ) using your calculator. Solution: You want to enter the expression the way it is written using the parenthesis key. 5 x [(] [)] = 350 Example 14 : Compute using your calculator. Solution: The calculator does not have a fraction bar, so we have to use the says divide the sum of 4 and 8 by the product of and 3. Note that the sum and product are single quantities, therefore they have to be enclosed in parentheses. The following would be entered in the calculator: [(] [)] [(] x 3 [)] = Witkowski and Phillips Page 10

11 Activity 5 In the following perform the indicated operations on your calculator. Round answers to three decimal places. a) 1.( ) b) -3.( ) c) 13(40.) Section 5: Evaluation of Formulas Example 15 : The circumference (distance around) of a circle is given by the formula C = r, where r is the radius of the circle. Find the circumference of a circle if the radius is 6.51 inches. Round your answer to decimal places. Solution: In this example we want to use the key and not use an approximation like Enter the following on your calculator. x x 6.51 = 39.8 square inches (in ) Witkowski and Phillips Page 11

12 Activity 6 Evaluation of formulas requires the substitution of numerical values for the letters (variables). In the expression 15y, 15 is called the coefficient of y and 15y means 15 times y. If y = - 4, then 15y = 15( - 4) = Using your calculator evaluate x(4x - 30), when x = 3. First write down your key strokes. Formulas involving subscripts In most science courses, instead of using different letters to represent different quantities, the same letter is used with different subscripts. Just as a and b in an expression or formula represent different quantities, so do R 1 and R. Look at the nutritional value of a particular food and you will see vitamins such as Vitamin B 6 and Vitamin B 1 identified by subscripts. Activity 7 The equivalent resistance R (in ohms) of two resistors connected in parallel is R 1 R given by the formula R = R 1 + R, where R 1 and R are the resistances of the two resistors (in ohms). Find the value of R if R 1 = 15,000 and R = 3,000. Use your calculator. Witkowski and Phillips Page 1

13 Exercises for Order of Operations Do all the exercises on separate paper, showing all work neatly. 1. Evaluate the following expressions with paper and pencil. Check your answers with a calculator. a) b) 3(45-1) c) (45-1) (7-10) d) 64-5[14 + 0(14-3)] e) 3(1-7) f) 4-4( ). 5-7 g) 11-5(3) 7(3) - 10(-3) h) 4( () 3 ) i) 13-{18 + (19 - [7 + 1])} 4. Evaluate the following expressions, using a 1 =, a = 6, and a 3 = 8. a) 1.5a 1 + a - 6a 3 b) a 3 - a 1. a c) 5a + 6a 1 a 1. a 3 - d) 5{a - a 1 [4 - (3 + a 3 )] + 3} e) a 1 a 3 - a (a 1 - a 3 ) 3. Translate each of the following sentences into an expression using the operations +, -,.,, and parentheses as needed. Then use your calculator to evaluate each expression. a) A car rental company charges \$0 per day and 3.5 cents per mile for a compact car. The first 100 miles are free. If I rented the car for three days and drove 365 miles, how much will the rental company charge me? b) A transcript costs \$3.00 for the first copy and \$.50 for each additional copy. If I want five transcripts sent, what is my total cost? Witkowski and Phillips Page 13

14 4. A friend of yours wanted to evaluate following: [(] [)] on his calculator. He entered the a) Translate into an English expression the mathematical expression that was entered into the calculator. b) Translate into an English expression. c) What is wrong with the way your friend entered the expression into the calculator? 5. On the previous problem, suppose another friend calculated the problem as follows: 1. add 1. and 5.7 to get 6.9. multiplied.3 by.39 and rounded this answer to divided 6.9 by.76 to get Do you see anything wrong with doing the problem this way? 6. Name the terms in each of the following expressions. a) r b) - 1 gt + v 0 t + h 0 Witkowski and Phillips Page 14

15 Math for Management Solutions To Activities ORDER OF OPERATIONS Activity 1: 1) (5) 7(3 ) ) 4[6 4( 7)] 4[6 4( 5)] ) ) ) (9 (3) (9) 18 6) 6) 1 [9 5 1 [9 5 1 [9 5 1 [74] (1 ) ] ] 8 18] *************************************************************************************************************** Activity : 1) a) 8 (4 ) b) 4 3(5 8) c) 6 9 (4 7) ) a) thirty minus the difference of nineteen and five b) four times six, plus seven c) the sum of four and six, divided by eight d) the product of four and six, divided by the difference of six and nine Witkowski and Phillips Page 15

16 Activity 3: expression number of terms terms factors a) x 1 x and x b) 6x 1 6x 6 and x c) 6x + 1 6x and 1 (6 x + 1) only 1 factor d) x(x + 1) 1 x(x + 1) x and (x + 1) e) ( x)(x + 1) 1 ( x)(x + 1) ( x) and (x + 1) f) 4[6-4(-7)] 1 4[6-4(-7)] 4 and [6-4(-7)] *************************************************************************************************************** Activity 4: 1) Evaluate 3 + 5[6 9] a) using order of operations b) using the distributive property 3 + 5[-3] 3 + 5(6) 5(9) ) Evaluate 4[6 4( 7)] a) using order of operations b) using the distributive property 4[6 4(-5)] 4[6 4() 4(-7)] 4[6 + 0] 4[ ] 4[6] 4(6) + 4(-8) + 4(8) *************************************************************************************************************** Activity 5: a) 1. x ( ) = b) -3. x ( ) = c) ( 13 x 40. ) ( ) = *************************************************************************************************************** Activity 6: Key strokes: [(] / 3 [)] x [(] 4 * [(] / 3 [)] 30 [)] = -18. *************************************************************************************************************** Activity 7: R R R1R R R (3000) ohms Witkowski and Phillips Page 16

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