) 0.7 = N m.


 Lambert Willis
 1 years ago
 Views:
Transcription
1 Exam 2 Solutions Prof. Paul Avery Prof. Andrey Korytov Oct. 29, A loop of wire carrying a current of 2.0 A is in the shape of a right triangle with two equal sides, each with length L = 15 cm as shown in the figure. The triangle lies within a 0.7 T uniform magnetic field in the plane of the triangle and perpendicular to the hypotenuse. The magnetic force on either of the two sides has a magnitude of: Answer: 0.15 N Solution: The force on each side is F! = ( I! B! )L, F = IBLsinθ F = BLisin 45 = = 0.15 N. B 2. Refer to the previous problem. What is the magnitude of the torque on this loop due to the magnetic field (in N m)? Answer: Solution: The torque is! τ = (! µ B! ), τ = µbsinθ = (ia)bsinθ τ = iabsin90! = 2.0 ( ) 0.7 = N m. 3. An electrical device with an equivalent resistance of 100 Ω has a maximum instantaneous voltage rating of 60 V. Assume that it is plugged into a standard 120 V electrical outlet in series with a resistance R. What is the approximate minimum value of R needed to keep the instantaneous voltage across the device within its safety limits? Answer: 183 Ω Solution: The maximum instantaneous voltage from the 120 V outlet is = V. We want to find the value of R such that the voltage across the device is no more than 60 V. The device and resistor R are connected in series: R TOT =100+R. The current through the device is I = 169.7/ R TOT. And the voltage across the device is V=100 I must satisfy the condition V 60 V. Putting all together, we get ( ) / ( R) = 60. Solving for R yields R = 183 Ω. 4. A 14.0 g conducting rod of length 1.30 m and resistance 8.0 Ω slides freely downward between two vertical conducting rails without friction. The entire apparatus is placed in a 0.43 T uniform magnetic field. Ignore the electrical resistance of the rails. What is the terminal velocity of the rod? (g = 9.8 m/s 2 ) Answer: 3.51 m/s 1
2 Solution: The motional emf is ε = BLv which generates a loop current of i = ε / R = BLv / R. At terminal velocity, the magnetic force on this current equals the force due to gravity or mg = BiL = B 2 L 2 v / R. Solving yields v = 3.51 m/s. 5. A transformer consists of a 300turn primary coil and a 2000turn secondary coil. If the current in the secondary coil is 9.00 A, what is the primary current? Answer: 60.0 A Solution: Using V 2 / V 1 = N 2 / N 1 = 6.67 and i 1 V 1 = i 2 V 2, with i 2 = 9.0 A, we get i 1 = 60.0 A. 6. A hair dryer has a power rating of 1200 W when plugged into a standard 110 V AC receptacle. How much current does it draw if it is connected instead to a 110 V DC source? Answer: 10.9 A 2 Solution: Power dissipated into hit by a resistor connected to AC of rms emf ε rms is P =ε rms from where one can find R. The current through a resistor connected to DC source emf ε 0 is I =ε 0 / R. Therefore, I =ε 0 P =10.9 A. 2 εrms / R, 7. The number of turns is tripled for an ideal solenoid, and its length is doubled while holding its crosssectional area constant. If the old inductance is L, what is the new inductance? Answer: 9L/2 Solution: The inductance is proportional to the cross sectional area, the solenoid length and the square of n = number of turns/length: L = µ 0 n 2 Al Then, if n 3n / 2 (triple turns over twice the length) and l 2l (length doubled), the new inductance will be L old 3 / 2 ( ) 2 2 = ( 9 / 2) L old 2
3 8. In the circuit shown, what is the current through the 15 V battery? Answer: 1.18 A upwards Solution: We choose the currents in the branches to be I 1 (left branch upwards), I 2 (middle branch upwards) and I 3 = I 1 + I 2 (right branch downwards). Then the loop equations for leftmiddle 4Ω 8Ω 2Ω and middleright (others are possible, but these are convenient) are 4I I 2 = 0 8I I 3 = 0 Solving for I 2 yields I 2 = +33/ A V 15 V 9. An ammeter with fullscale deflection for I = 20.0 A has an internal resistance of 31.5 Ω. We need to use this ammeter to measure currents up to 30.0 A. What size resistor should be used to protect the ammeter? Answer: 63.0 Ω Solution: The shunt resistance R is placed in parallel with the ammeter so that part of the current to be measured is shunted around the device to avoid damaging it. We pick R so that at 30 A total current, 10 A goes through the shunt resistor and 20 A through the ammeter itself. The voltage across the ammeter is = 630V, which is the same as the voltage across R. Thus to get a current of 10 A through the resistor we require R = 63.0 Ω. 10. An electromagnetic flowmeter is used to measure blood flow rates during surgery. Blood containing Na + ions flow to the left through an B artery with an inner diameter of D = 4.00 mm. The artery is in a downward magnetic field of B = T and develops a Hall voltage V H = 80.0 µv across its diameter. What is the volumetric flow rate of the blood in (m 3 /s)? Answer: Solution: In the Hall effect, ions are bent in the magnetic field toward the arterial walls until the force F E = ee = e V H / D ( ) due to electric field E generated by the charges on opposite sides of the diameter exactly balances the magnetic force F B = evb. The force equality condition is ( ) = evb. This yields v = V H / BD for the velocity. The volume flow rate F = area ( ) = π DV H / 4B = m 3 /s. e V H / D velocity or F = π D 2 / 4 ( ) V H / BD v 3
4 11. An electromagnet is made by inserting a soft iron core into a solenoid. The solenoid has 1,700 turns, radius 2.4 cm, and length 13.0 cm. When 0.5 A of current flows through the solenoid, the magnetic field inside the iron core has magnitude 0.43 T. What is the relative permeability κ B of the iron core? Answer: 52.3 Solution: The B field of a solenoid with a ferromagnetic core is B = κ B µ 0 ni, where κ B is the permeability of the core material. Here n = 1700 / 0.13 = 13,100. Using the values shown we obtain κ B = Four long parallel wires pass through the corners of a square with side 14.1 cm as shown in the figure. All four wires carry the same magnitude of current I = 5.7 A in the directions indicated. Find the magnetic field at the center of the square. Answer: 32.3 µt Solution: Magnetic field lines make circles around lines of current, with their direction going clockwise for wires with currents into the page and counterclockwise for currents going out of the page. At the center of the square they point either at 45 (for the topleft and bottomright wires) or at 45 (for the topright and bottomleft wires). By inspection, we see that the y components of the field cancel at the center while the four x components are all identical. If the side length is L, we obtain B = 4 2µ 0 i / 2π L = 32.3 µt. 13. The armature of an AC generator is a rectangular coil 10.5 cm 4.0 cm with 210 turns. It is immersed in a uniform magnetic field of magnitude 1.5 T. If the amplitude of the emf in the coil is 30.0 V, at what angular speed (in rad/sec) is the armature rotating? Answer: 22.7 Solution: Emf induced in a coil of N loops and area A (A = ab ) rotating with angular velocity ω in magnetic field B is ε = ωnba sinωt. Using the values shown for the emf amplitude, B field, number of turns and coil dimensions yields ω = 22.7 rad/sec. 14. A dc motor has coils with resistance of 13 Ω and is connected to an emf of 127 V. When the motor operates at full speed, the back emf is 63 V. If the current is 6.1 A with the motor operating at less than full speed, what is the back emf at that time? Answer: 47.7 V Solution: I = ( ε external ε back ) / R. Therefore, back emf is = 47.7 V. 4
5 15. A coil has an inductance of 0.31 H and a resistance of 43 Ω. The coil is connected to a 6.4 V battery. After a long time elapses, the current in the coil is no longer changing. What is the energy stored in the coil? Answer: 3.43 mj Solution: After a long time the inductance has no effect and the current is obtained from i = ε / R = 6.4 / 43 = A. The energy stored in the coil is then U L = 1 2 Li2 = 3.43 mj. 16. A circuit breaker trips when the rms current exceeds 10.3 A. How many 60 W lightbulbs, connected in parallel, can be run on this circuit without tripping the breaker? (The rms voltage of the circuit is 110 V.) Answer: 18 Solution: Each lightbulb draws a current of 60/110 = A. Since 10.3/0.545 ~ 18.9, we see that no more than 18 lightbulbs can be supported on this circuit. 17. A sample containing carbon (atomic mass 12 u) and oxygen (16 u) is placed in a mass spectrometer. The ions all have the same charge and are accelerated through the same potential difference before entering a uniform magnetic field. For each ion, the spectrometer measures the distance between the entrance point and the place where it strikes the bottom of the region. If the carbon ions strike the detector at a distance of 9.14 cm from the entrance point, at what distance will oxygen ions strike the detector? Answer: 10.6 cm Solution: The ions travel in circular paths and land a distance of one diameter from the entrance point. The centripetal force equation mv 2 / r = evb yields for the diameter d = 2r = 2mv / eb. All ions have the same kinetic energy 1 2 mv2 = ev which gives mv = 2meV. This yields for the diameter d = 2 2mV / eb 2 ~ m, i.e. the distance is proportional to the square root of the mass. The distance for O 16 ions can then be determined by scaling the distance for C 12 ions: d O = d C m O / m C = / 12 = 10.6 cm. 18. The current I in a long wire is going up as shown in the figure and increasing in magnitude. What is the direction of the induced current in the left loop and the right loop? List the direction of the induced current in the left loop first. (CW = clockwise, CCW = counterclockwise) Answer: CW, CCW Solution: Using the right hand rule, we see that the B field is increasing out of the page on the left side and increasing into the page on the right. Lenz law says that to counteract those fields the induced currents must generate B fields into the page and out of the page, respectively. Thus the currents must flow clockwise (left) and counterclockwise (right). I 5
6 19. In the circuit shown in the figure, the switch is in position 1 for a long time. It is then moved to position 2. How long will it take for the charge on the capacitor to reach 50 µc after the switch is moved to its new position? The values are C = 21 µf, R 1 = 5000 Ω and R 2 = 25 Ω. The battery has a voltage of 50 V. Answer: 1.60 ms Solution: After a long time the capacitor becomes fully charged with a charge Q max = CV = 1050 µc. It then discharges through R 2 with an RC time of msec. Thus we must solve 1050 e t/0.525 = 50, which yields t = 1.60 msec C R 2 R A toroid is like a solenoid that has been bent around in a circle until its ends meet, as shown in the figure (inner radius 4 cm, outer radius 8 cm). What is the magnitude of the magnetic field inside a toroid of 1000 turns carrying a current 0.5 A at a distance 6 cm from the center of the toroid? (Hint: Use Ampere's Law applied to a closed loop in the toroid midplane, as shown by a dashed line.) Answer: 1.67 mt Solution: We solve using Ampere s law: B i Δs = µ i 0 i enc where Δs is a short distance along a closed path and i enc is the enclosed current within the path. For the path we use a circular loop at r = 6 cm where the B field is constant, obtaining B( 2πr ) = Nµ 0 i, where N = 1000 is the number of turns. Solving yields B = 1.67 mt. 6
Physics 1653 Exam 3  Review Questions
Physics 1653 Exam 3  Review Questions 3.0 Two uncharged conducting spheres, A and B, are suspended from insulating threads so that they touch each other. While a negatively charged rod is held near, but
More informationExam 2 Solutions. PHY2054 Spring Prof. P. Kumar Prof. P. Avery March 5, 2008
Prof. P. Kumar Prof. P. Avery March 5, 008 Exam Solutions 1. Two cylindrical resistors are made of the same material and have the same resistance. The resistors, R 1 and R, have different radii, r 1 and
More informationPhysics 126 Practice Exam #3 Professor Siegel
Physics 126 Practice Exam #3 Professor Siegel Name: Lab Day: 1. Which one of the following statements concerning the magnetic force on a charged particle in a magnetic field is true? A) The magnetic force
More informationProfs. A. Petkova, A. Rinzler, S. Hershfield. Exam 2 Solution
PHY2049 Fall 2009 Profs. A. Petkova, A. Rinzler, S. Hershfield Exam 2 Solution 1. Three capacitor networks labeled A, B & C are shown in the figure with the individual capacitor values labeled (all units
More informationExam 1 Solutions. PHY2054 Fall 2014. Prof. Paul Avery Prof. Andrey Korytov Sep. 26, 2014
Exam 1 Solutions Prof. Paul Avery Prof. Andrey Korytov Sep. 26, 2014 1. Charges are arranged on an equilateral triangle of side 5 cm as shown in the diagram. Given that q 1 = 5 µc and q 2 = q 3 = 2 µc
More information104 Practice Exam 23/21/02
104 Practice Exam 23/21/02 1. Two electrons are located in a region of space where the magnetic field is zero. Electron A is at rest; and electron B is moving westward with a constant velocity. A nonzero
More informationInduction. d. is biggest when the motor turns fastest.
Induction 1. A uniform 4.5T magnetic field passes perpendicularly through the plane of a wire loop 0.10 m 2 in area. What flux passes through the loop? a. 5.0 T m 2 c. 0.25 T m 2 b. 0.45 T m 2 d. 0.135
More informationInduced voltages and Inductance Faraday s Law
Induced voltages and Inductance Faraday s Law concept #1, 4, 5, 8, 13 Problem # 1, 3, 4, 5, 6, 9, 10, 13, 15, 24, 23, 25, 31, 32a, 34, 37, 41, 43, 51, 61 Last chapter we saw that a current produces a magnetic
More information1. The diagram below represents magnetic lines of force within a region of space.
1. The diagram below represents magnetic lines of force within a region of space. 4. In which diagram below is the magnetic flux density at point P greatest? (1) (3) (2) (4) The magnetic field is strongest
More informationPhys222 Winter 2012 Quiz 4 Chapters 2931. Name
Name If you think that no correct answer is provided, give your answer, state your reasoning briefly; append additional sheet of paper if necessary. 1. A particle (q = 5.0 nc, m = 3.0 µg) moves in a region
More informationQuiz: Work and Energy
Quiz: Work and Energy A charged particle enters a uniform magnetic field. What happens to the kinetic energy of the particle? (1) it increases (2) it decreases (3) it stays the same (4) it changes with
More information45. The peak value of an alternating current in a 1500W device is 5.4 A. What is the rms voltage across?
PHYS Practice Problems hapters 8 hapter 8. 45. The peak value of an alternating current in a 5W device is 5.4 A. What is the rms voltage across? The power and current can be used to find the peak voltage,
More information1) Magnetic field lines come out of the south pole of a magnet and enter at the north pole.
Exam Name 1) Magnetic field lines come out of the south pole of a magnet and enter at the north pole. 2) Which of the following statements is correct? A) Earth's north pole is magnetic north. B) The north
More informationMagnetic Forces and Magnetic Fields
1 Magnets Magnets are metallic objects, mostly made out of iron, which attract other iron containing objects (nails) etc. Magnets orient themselves in roughly a north  south direction if they are allowed
More informationEðlisfræði 2, vor 2007
[ Assignment View ] [ Pri Eðlisfræði 2, vor 2007 29a. Electromagnetic Induction Assignment is due at 2:00am on Wednesday, March 7, 2007 Credit for problems submitted late will decrease to 0% after the
More informationPhysics 112 Homework 5 (solutions) (2004 Fall) Solutions to Homework Questions 5
Solutions to Homework Questions 5 Chapt19, Problem2: (a) Find the direction of the force on a proton (a positively charged particle) moving through the magnetic fields in Figure P19.2, as shown. (b) Repeat
More informationPHYS 155: Final Tutorial
Final Tutorial Saskatoon Engineering Students Society eric.peach@usask.ca April 13, 2015 Overview 1 2 3 4 5 6 7 Tutorial Slides These slides have been posted: sess.usask.ca homepage.usask.ca/esp991/ Section
More informationMagnetism. d. gives the direction of the force on a charge moving in a magnetic field. b. results in negative charges moving. clockwise.
Magnetism 1. An electron which moves with a speed of 3.0 10 4 m/s parallel to a uniform magnetic field of 0.40 T experiences a force of what magnitude? (e = 1.6 10 19 C) a. 4.8 10 14 N c. 2.2 10 24 N b.
More informationReview Questions PHYS 2426 Exam 2
Review Questions PHYS 2426 Exam 2 1. If 4.7 x 10 16 electrons pass a particular point in a wire every second, what is the current in the wire? A) 4.7 ma B) 7.5 A C) 2.9 A D) 7.5 ma E) 0.29 A Ans: D 2.
More informationForce on Moving Charges in a Magnetic Field
[ Assignment View ] [ Eðlisfræði 2, vor 2007 27. Magnetic Field and Magnetic Forces Assignment is due at 2:00am on Wednesday, February 28, 2007 Credit for problems submitted late will decrease to 0% after
More informationPhysics 2220 Module 09 Homework
Physics 2220 Module 09 Homework 01. A potential difference of 0.050 V is developed across the 10cmlong wire of the figure as it moves though a magnetic field perpendicular to the page. What are the strength
More informationPhysics 121 Sample Common Exam 3 NOTE: ANSWERS ARE ON PAGE 6. Instructions: 1. In the formula F = qvxb:
Physics 121 Sample Common Exam 3 NOTE: ANSWERS ARE ON PAGE 6 Signature Name (Print): 4 Digit ID: Section: Instructions: Answer all questions 24 multiple choice questions. You may need to do some calculation.
More informationTest  A2 Physics. Primary focus Magnetic Fields  Secondary focus electric fields (including circular motion and SHM elements)
Test  A2 Physics Primary focus Magnetic Fields  Secondary focus electric fields (including circular motion and SHM elements) Time allocation 40 minutes These questions were ALL taken from the June 2010
More informationPhys 102 Spg Exam No. 2 Solutions
Phys 102 Spg. 2008 Exam No. 2 Solutions I. (20 pts) A 10turn wire loop measuring 8.0 cm by 16.0 cm carrying a current of 2.0 A lies in the horizontal plane and is free to rotate about a horizontal axis
More informationPhysics 2212 GH Quiz #4 Solutions Spring 2015
Physics 1 GH Quiz #4 Solutions Spring 15 Fundamental Charge e = 1.6 1 19 C Mass of an Electron m e = 9.19 1 31 kg Coulomb constant K = 8.988 1 9 N m /C Vacuum Permittivity ϵ = 8.854 1 1 C /N m Earth s
More informationCandidate Number. General Certificate of Education Advanced Level Examination June 2010
entre Number andidate Number Surname Other Names andidate Signature General ertificate of Education dvanced Level Examination June 1 Physics PHY4/1 Unit 4 Fields and Further Mechanics Section Friday 18
More informationUniversity of California, Berkeley Physics H7B Spring 1999 (Strovink) SOLUTION TO PROBLEM SET 10 Solutions by P. Pebler
University of California, Berkeley Physics H7B Spring 1999 (Strovink) SOLUTION TO PROBLEM SET 10 Solutions by P Pebler 1 Purcell 66 A round wire of radius r o carries a current I distributed uniformly
More information1 of 7 4/13/2010 8:05 PM
Chapter 33 Homework Due: 8:00am on Wednesday, April 7, 2010 Note: To understand how points are awarded, read your instructor's Grading Policy [Return to Standard Assignment View] Canceling a Magnetic Field
More informationChapter 14: Magnets and Electromagnetism
Chapter 14: Magnets and Electromagnetism 1. Electrons flow around a circular wire loop in a horizontal plane, in a direction that is clockwise when viewed from above. This causes a magnetic field. Inside
More informationPhysics 9 Fall 2009 Homework 8  Solutions
1. Chapter 34  Exercise 9. Physics 9 Fall 2009 Homework 8  s The current in the solenoid in the figure is increasing. The solenoid is surrounded by a conducting loop. Is there a current in the loop?
More informationDirection of Induced Current
Direction of Induced Current Bar magnet moves through coil Current induced in coil A S N v Reverse pole Induced current changes sign B N S v v Coil moves past fixed bar magnet Current induced in coil as
More informationPhysics 12 Study Guide: Electromagnetism Magnetic Forces & Induction. Text References. 5 th Ed. Giancolli Pg
Objectives: Text References 5 th Ed. Giancolli Pg. 58896 ELECTROMAGNETISM MAGNETIC FORCE AND FIELDS state the rules of magnetic interaction determine the direction of magnetic field lines use the right
More informationChapter 14 Magnets and
Chapter 14 Magnets and Electromagnetism How do magnets work? What is the Earth s magnetic field? Is the magnetic force similar to the electrostatic force? Magnets and the Magnetic Force! We are generally
More informationAP2 Magnetism. (c) Explain why the magnetic field does no work on the particle as it moves in its circular path.
A charged particle is projected from point P with velocity v at a right angle to a uniform magnetic field directed out of the plane of the page as shown. The particle moves along a circle of radius R.
More information( )( 10!12 ( 0.01) 2 2 = 624 ( ) Exam 1 Solutions. Phy 2049 Fall 2011
Phy 49 Fall 11 Solutions 1. Three charges form an equilateral triangle of side length d = 1 cm. The top charge is q =  4 μc, while the bottom two are q1 = q = +1 μc. What is the magnitude of the net force
More informationChapter 31. Faraday s Law
Chapter 31 Faraday s Law Michael Faraday 1791 1867 British physicist and chemist Great experimental scientist Contributions to early electricity include: Invention of motor, generator, and transformer
More informationSolution Derivations for Capa #10
Solution Derivations for Capa #10 1) A 1000turn loop (radius = 0.038 m) of wire is connected to a (25 Ω) resistor as shown in the figure. A magnetic field is directed perpendicular to the plane of the
More informationLast Name: First Name: Physics 102 Spring 2006: Exam #2 MultipleChoice Questions 1. A charged particle, q, is moving with speed v perpendicular to a uniform magnetic field. A second identical charged
More information!"#$%&&''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''& ()*+,&./0.& 1*2&3+,,&!"#$%&% 456(&07/&
!"#$%'''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''''' ()*+,./0. 1*23+,,!"#$%% 456(07/ Directions: Complete each problem to the best of your ability. Be sure to show all
More informationMagnetic Fields; Sources of Magnetic Field
This test covers magnetic fields, magnetic forces on charged particles and currentcarrying wires, the Hall effect, the BiotSavart Law, Ampère s Law, and the magnetic fields of currentcarrying loops
More informationForce on a square loop of current in a uniform Bfield.
Force on a square loop of current in a uniform Bfield. F top = 0 θ = 0; sinθ = 0; so F B = 0 F bottom = 0 F left = I a B (out of page) F right = I a B (into page) Assume loop is on a frictionless axis
More informationElectroMagnetic Induction. AP Physics B
ElectroMagnetic Induction AP Physics B What is E/M Induction? Electromagnetic Induction is the process of using magnetic fields to produce voltage, and in a complete circuit, a current. Michael Faraday
More information= (0.400 A) (4.80 V) = 1.92 W = (0.400 A) (7.20 V) = 2.88 W
Physics 2220 Module 06 Homework 0. What are the magnitude and direction of the current in the 8 Ω resister in the figure? Assume the current is moving clockwise. Then use Kirchhoff's second rule: 3.00
More informationHomework #11 20311721 Physics 2 for Students of Mechanical Engineering
Homework #11 20311721 Physics 2 for Students of Mechanical Engineering 2. A circular coil has a 10.3 cm radius and consists of 34 closely wound turns of wire. An externally produced magnetic field of
More informationCh.20 Induced voltages and Inductance Faraday s Law
Ch.20 Induced voltages and Inductance Faraday s Law Last chapter we saw that a current produces a magnetic field. In 1831 experiments by Michael Faraday and Joseph Henry showed that a changing magnetic
More informationLecture PowerPoints. Chapter 20 Physics: Principles with Applications, 7 th edition Giancoli
Lecture PowerPoints Chapter 20 Physics: Principles with Applications, 7 th edition Giancoli This work is protected by United States copyright laws and is provided solely for the use of instructors in teaching
More informationChapter 14 Magnets and Electromagnetism
Chapter 14 Magnets and Electromagnetism Magnets and Electromagnetism In the 19 th century experiments were done that showed that magnetic and electric effects were just different aspect of one fundamental
More informationChapter 20. Magnetic Induction Changing Magnetic Fields yield Changing Electric Fields
Chapter 20 Magnetic Induction Changing Magnetic Fields yield Changing Electric Fields Introduction The motion of a magnet can induce current in practical ways. If a credit card has a magnet strip on its
More informationPH 102 Exam II SOLUTION
PH 102 Exam II SOLUTION 20Mar07 LeClair INSTRUCTIONS 1. Solve 8 problems out of the 12 below. All problems have equal weight. 2. Clearly mark the problems you choose by filling in the adjacent circle.
More information4.1.Motion Of Charged Particles In Electric And Magnetic Field Motion Of Charged Particles In An Electric Field
4.1.Motion Of Charged Particles In Electric And Magnetic Field 4.1.1. Motion Of Charged Particles In An Electric Field A charged particle in an electric field will experience an electric force due to the
More informationGeneral Physics (PHY 2140)
General Physics (PHY 2140) Lecture 12 Electricity and Magnetism Magnetism Magnetic fields and force Application of magnetic forces http://www.physics.wayne.edu/~apetrov/phy2140/ Chapter 19 1 Department
More informationHomework #8 20311721 Physics 2 for Students of Mechanical Engineering. Part A
Homework #8 20311721 Physics 2 for Students of Mechanical Engineering Part A 1. Four particles follow the paths shown in Fig. 3233 below as they pass through the magnetic field there. What can one conclude
More informationConceptual: 1, 3, 5, 6, 8, 16, 18, 19. Problems: 4, 6, 8, 11, 16, 20, 23, 27, 34, 41, 45, 56, 60, 65. Conceptual Questions
Conceptual: 1, 3, 5, 6, 8, 16, 18, 19 Problems: 4, 6, 8, 11, 16, 20, 23, 27, 34, 41, 45, 56, 60, 65 Conceptual Questions 1. The magnetic field cannot be described as the magnetic force per unit charge
More informationChapter 23 Magnetic Flux and Faraday s Law of Induction
Chapter 23 Magnetic Flux and Faraday s Law of Induction 23.1 Induced EMF 23.2 Magnetic Flux 23.3 Faraday s Law of Induction 23.4 Lenz s Law 23.5 Mechanical Work and Electrical Energy 23.6 Generators and
More informationFall 12 PHY 122 Homework Solutions #8
Fall 12 PHY 122 Homework Solutions #8 Chapter 27 Problem 22 An electron moves with velocity v= (7.0i  6.0j)10 4 m/s in a magnetic field B= (0.80i + 0.60j)T. Determine the magnitude and direction of the
More informationHMWK 3. Ch 23: P 17, 23, 26, 34, 52, 58, 59, 62, 64, 73 Ch 24: Q 17, 34; P 5, 17, 34, 42, 51, 52, 53, 57. Chapter 23
HMWK 3 Ch 23: P 7, 23, 26, 34, 52, 58, 59, 62, 64, 73 Ch 24: Q 7, 34; P 5, 7, 34, 42, 5, 52, 53, 57 Chapter 23 P23.7. Prepare: The connecting wires are ideal with zero resistance. We have to reduce the
More informationMOVING CHARGES AND MAGNETISM
MOVING CHARGES AND MAGNETISM 1. A circular Coil of 50 turns and radius 0.2m carries of current of 12A Find (a). magnetic field at the centre of the coil and (b) magnetic moment associated with it. 3 scores
More informationMultiple Choice Questions for Physics 1 BA113 Chapter 23 Electric Fields
Multiple Choice Questions for Physics 1 BA113 Chapter 23 Electric Fields 63 When a positive charge q is placed in the field created by two other charges Q 1 and Q 2, each a distance r away from q, the
More informationObjectives for the standardized exam
III. ELECTRICITY AND MAGNETISM A. Electrostatics 1. Charge and Coulomb s Law a) Students should understand the concept of electric charge, so they can: (1) Describe the types of charge and the attraction
More information1 of 7 10/1/2012 3:17 PM
Assignment Previewer http://www.webassign.net/v4cgijfederici@njit/control.pl 1 of 7 10/1/2012 3:17 PM HW11Faraday (2861550) Question 1 2 3 4 5 6 7 8 9 10 1. Question Details SerPSE8 31.P.011.WI. [1742725]
More information2. B The magnetic properties of a material depend on its. A) shape B) atomic structure C) position D) magnetic poles
ame: Magnetic Properties 1. B What happens if you break a magnet in half? A) One half will have a north pole only and one half will have a south pole only. B) Each half will be a new magnet, with both
More informationChapter 22 Magnetism
22.6 Electric Current, Magnetic Fields, and Ampere s Law Chapter 22 Magnetism 22.1 The Magnetic Field 22.2 The Magnetic Force on Moving Charges 22.3 The Motion of Charged particles in a Magnetic Field
More informationChapter 19 Magnetic Forces and Fields
Chapter 19 Magnetic Forces and Fields Student: 3. The magnetism of the Earth acts approximately as if it originates from a huge bar magnet within the Earth. Which of the following statements are true?
More information** Can skip to Problems: 6, 7, 9, 15, 19, 28, 29, 35, 36, 39, 42 **
Walker, Physics, 3 rd Edition Chapter 22 ** Can skip to Problems: 6, 7, 9, 15, 19, 28, 29, 35, 36, 39, 42 ** Conceptual Questions (Answers to oddnumbered Conceptual Questions can be found in the back
More informationFaraday s Law; Inductance
This test covers Faraday s Law of induction, motional emf, Lenz s law, induced emf and electric fields, eddy currents, selfinductance, inductance, RL circuits, and energy in a magnetic field, with some
More informationFaraday s Law of Induction
Chapter 10 Faraday s Law of Induction 10.1 Faraday s Law of Induction...1010.1.1 Magnetic Flux...103 10.1. Lenz s Law...105 10. Motional EMF...107 10.3 Induced Electric Field...1010 10.4 Generators...101
More information2015 Pearson Education, Inc. Section 24.5 Magnetic Fields Exert Forces on Moving Charges
Section 24.5 Magnetic Fields Exert Forces on Moving Charges Magnetic Fields Sources of Magnetic Fields You already know that a moving charge is the creator of a magnetic field. Effects of Magnetic Fields
More information1. Units of a magnetic field might be: A. C m/s B. C s/m C. C/kg D. kg/c s E. N/C m ans: D
Chapter 28: MAGNETIC FIELDS 1 Units of a magnetic field might be: A C m/s B C s/m C C/kg D kg/c s E N/C m 2 In the formula F = q v B: A F must be perpendicular to v but not necessarily to B B F must be
More informationPhysics 122 (Sonnenfeld), Spring 2013 ( MPSONNENFELDS2013 ) My Courses Course Settings
Signed in as Richard Sonnenfeld, Instructor Help Sign Out Physics 122 (Sonnenfeld), Spring 2013 ( MPSONNENFELDS2013 ) My Courses Course Settings Course Home Assignments Roster Gradebook Item Library Essential
More informationNAME. and 2I o. (1) Two long wires carry magnetic fields I o. , where I o
(1) Two long wires carry magnetic fields I o and 2I o, where I o is a constant. The two wires cross at the origin (but without making any electrical connection), and lie in the xy plane. (a) Find the
More informationChapter 27 Magnetic Induction. Copyright 2008 Pearson Education Inc., publishing as Pearson AddisonWesley
Chapter 27 Magnetic Induction Motional EMF Consider a conductor in a Bfield moving to the right. In which direction will an electron in the bar experience a magnetic force? V e  V The electrons in the
More informationQuestion Bank. 1. Electromagnetism 2. Magnetic Effects of an Electric Current 3. Electromagnetic Induction
1. Electromagnetism 2. Magnetic Effects of an Electric Current 3. Electromagnetic Induction 1. Diagram below shows a freely suspended magnetic needle. A copper wire is held parallel to the axis of magnetic
More informationCandidate Number. General Certificate of Education Advanced Level Examination June 2014
entre Number andidate Number Surname Other Names andidate Signature General ertificate of Education dvanced Level Examination June 214 Physics PHY4/1 Unit 4 Fields and Further Mechanics Section Wednesday
More informationMagnetic Field Lines. Uniform Magnetic Field. Earth s Magnetic Field 6/3/2013
Chapter 33: Magnetism Ferromagnetism Iron, cobalt, gadolinium strongly magnetic Can cut a magnet to produce more magnets (no magnetic monopole) Electric fields can magnetize nonmagnetic metals Heat and
More informationphysics 112N electromagnetic induction
physics 112N electromagnetic induction experimental basis of induction! seems we can induce a current in a loop with a changing magnetic field physics 112N 2 magnetic flux! useful to define a quantity
More informationThe purposes of this experiment are to test Faraday's Law qualitatively and to test Lenz's Law.
260 171 I. THEORY EXPERIMENT 17 QUALITATIVE STUDY OF INDUCED EMF Along the extended central axis of a bar magnet, the magnetic field vector B r, on the side nearer the North pole, points away from this
More informationLesson 3 DIRECT AND ALTERNATING CURRENTS. Task. The skills and knowledge taught in this lesson are common to all missile repairer tasks.
Lesson 3 DIRECT AND ALTERNATING CURRENTS Task. The skills and knowledge taught in this lesson are common to all missile repairer tasks. Objectives. When you have completed this lesson, you should be able
More informationEðlisfræði 2, vor 2007
[ Assignment View ] [ Pri Eðlisfræði 2, vor 2007 28. Sources of Magnetic Field Assignment is due at 2:00am on Wednesday, March 7, 2007 Credit for problems submitted late will decrease to 0% after the deadline
More informationPearson Physics Level 30 Unit VI Forces and Fields: Chapter 12 Solutions
Concept Check (top) Pearson Physics Level 30 Unit VI Forces and Fields: Chapter 1 Solutions Student Book page 583 Concept Check (bottom) The northseeking needle of a compass is attracted to what is called
More informationPhysics Notes for Class 12 Chapter 4 Moving Charges and Magnetrism
1 P a g e Physics Notes for Class 12 Chapter 4 Moving Charges and Magnetrism Oersted s Experiment A magnetic field is produced in the surrounding of any current carrying conductor. The direction of this
More informationThe Big Idea. Key Concepts
The ig Idea For static electric charges, the electromagnetic force is manifested by the Coulomb electric force alone. If charges are moing, howeer, there is created an additional force, called magnetism.
More informationCopyright 2014 Edmentum  All rights reserved.
Copyright 2014 Edmentum  All rights reserved. Science Physics Electromagnetic Blizzard Bag 20142015 1. Two coils of insulated wire are placed side by side, as shown in the illustration. The blue lines
More informationPHY2049 Exam #2 Solutions Fall 2012
PHY2049 Exam #2 Solutions Fall 2012 1. The diagrams show three circuits consisting of concentric circular arcs (either half or quarter circles of radii r, 2r, and 3r) and radial segments. The circuits
More informationMagnetism Conceptual Questions. Name: Class: Date:
Name: Class: Date: Magnetism 22.1 Conceptual Questions 1) A proton, moving north, enters a magnetic field. Because of this field, the proton curves downward. We may conclude that the magnetic field must
More informationElectromagnetic Induction. Physics 231 Lecture 91
Electromagnetic Induction Physics 231 Lecture 91 Induced Current Past experiments with magnetism have shown the following When a magnet is moved towards or away from a circuit, there is an induced current
More informationChapter 31: Induction and Inductance
Chapter 31: Induction and Inductance In Ch 30 we learned the following about magnetic fields: a) A magnetic field can exert a force on a current carrying wire b) If the wire is a closed loop then the magnetic
More information1. A wire carries 15 A. You form the wire into a singleturn circular loop with magnetic field 80 µ T at the loop center. What is the loop radius?
CHAPTER 3 SOURCES O THE MAGNETC ELD 1. A wire carries 15 A. You form the wire into a singleturn circular loop with magnetic field 8 µ T at the loop center. What is the loop radius? Equation 33, with
More informationPhysics 6C, Summer 2006 Homework 1 Solutions F 4
Physics 6C, Summer 006 Homework 1 Solutions All problems are from the nd edition of Walker. Numerical values are different for each student. Chapter Conceptual Questions 18. Consider the four wires shown
More information4/16/ Bertrand
Physics B AP Review: Electricity and Magnetism Name: Charge (Q or q, unit: Coulomb) Comes in + and The proton has a charge of e. The electron has a charge of e. e = 1.602 1019 Coulombs. Charge distribution
More informationSCS 139 II.3 Induction and Inductance
SCS 139 II.3 Induction and Inductance Dr. Prapun Suksompong prapun@siit.tu.ac.th L d dt di L dt B 1 Office Hours: Library (Rangsit) Mon 16:2016:50 BKD 36017 Wed 9:2011:20 Review + New Fact Review Force
More informationPhysics 202: Lecture 10, Pg 1
Physics 132: Lecture e 21 Elements of Physics II Forces on currents Agenda for Today Currents are moving charges Torque on current loop Torque on rotated loop Currents create Bfields Adding magnetic fields
More informationMagnets and the Magnetic Force
Magnets and the Magnetic Force We are generally more familiar with magnetic forces than with electrostatic forces. Like the gravitational force and the electrostatic force, this force acts even when the
More informationSolution Derivations for Capa #11
Solution Derivations for Capa #11 Caution: The symbol E is used interchangeably for energy and EMF. 1) DATA: V b = 5.0 V, = 155 Ω, L = 8.400 10 2 H. In the diagram above, what is the voltage across the
More informationChapter 33. The Magnetic Field
Chapter 33. The Magnetic Field Digital information is stored on a hard disk as microscopic patches of magnetism. Just what is magnetism? How are magnetic fields created? What are their properties? These
More informationInduction and Inductance
Induction and Inductance How we generate E by B, and the passive component inductor in a circuit. 1. A review of emf and the magnetic flux. 2. Faraday s Law of Induction 3. Lentz Law 4. Inductance and
More informationReading Quiz. 1. Currents circulate in a piece of metal that is pulled through a magnetic field. What are these currents called?
Reading Quiz 1. Currents circulate in a piece of metal that is pulled through a magnetic field. What are these currents called? A. Induced currents B. Displacement currents C. Faraday s currents D. Eddy
More information6. ELECTROMAGNETIC INDUCTION
6. ELECTROMAGNETIC INDUCTION Questions with answers 1. Name the phenomena in which a current induced in coil due to change in magnetic flux linked with it. Answer: Electromagnetic Induction 2. Define electromagnetic
More informationMagnetic Field of a Circular Coil Lab 12
HB 112607 Magnetic Field of a Circular Coil Lab 12 1 Magnetic Field of a Circular Coil Lab 12 Equipment coil apparatus, BK Precision 2120B oscilloscope, Fluke multimeter, Wavetek FG3C function generator,
More informationChapter 21. Magnetic Forces and Magnetic Fields
Chapter 21 Magnetic Forces and Magnetic Fields 21.1 Magnetic Fields The needle of a compass is permanent magnet that has a north magnetic pole (N) at one end and a south magnetic pole (S) at the other.
More informationCandidate Number. General Certificate of Education Advanced Level Examination June 2012
entre Number andidate Number Surname Other Names andidate Signature General ertificate of Education dvanced Level Examination June 212 Physics PHY4/1 Unit 4 Fields and Further Mechanics Section Monday
More information