# Objective: Part 1: Open-Loop System. ITI SimulationX Page 1 of 20 ITI GmbH 2003

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1 ITI SimulationX Page 1 of 20 ITI GmbH 2003 Tutorial 2: Hydraulic Cylinder Drive Objective: In this tutorial you will create a model for a simple hydraulic cylinder drive, which is controlled by a proportional directional control valve. In a first step you will create an Open-Loop System, which means that there is no feedback of the actual cylinder position to the control valve. In a second step, the position of the cylinder is measured and compared to the position command signal, in order to create a Closed-Loop System. The purpose of the circuit is to lift (or lower, respectively) the load mass in vertical direction, according to the command signal of the proportional directional control valve. For the pressure supply, we simply use a constant displacement pump, driven at a constant speed and connected to a pressure relief valve. The advantage of this system is its simple structure. Of course, it shows a very poor efficiency, since a great amount of energy is consumed by the flow through the relief valve. It is assumed that you are familiar with the basic functionality of SimulationX. Therefore, please refer to Tutorial 1: Getting Started for a general introduction on how to select Elements from the libraries, how to connect them and enter parameters, how to run a simulation and how to open result windows. Part 1: Open-Loop System Create the SimulationX model of the hydraulic cylinder drive according to Figure 1. Use the elements listed in Table 1. You can change the label text and label position of each object by double clicking on an element and selecting General/Name. You have to write the name without a blank (e.g. CylinderDrive ). When connecting the elements with each other, you should remember, that in SimulationX you can only connect element ports of the same type. The mass of the cylinder piston is not included in the cylinder object. So you have to model the piston mass by connecting an element Mass (Library Mechanics Linear Mechanics Mass) to the cylinder. It represents the piston mass as well as the load mass at the same time.

2 ITI SimulationX Page 2 of 20 ITI GmbH 2003 Figure 1: Model structure of the Open-Loop Cylinder Drive In order to cut an already existing connection, click on it and press Del. The path of a connection will be determined automatically, but changing the path is possible at any time. To do this, move the mouse over a connection, while pressing the Alt-key. The mouse pointer shows you in which direction you can move the selected connection line.

3 ITI SimulationX Page 3 of 20 ITI GmbH 2003 Table 1: Elements required for the circuit in Figure 1 Number of elements Library name Element name Symbol 1 Hydraulics/ Actuators Differential Cylinder 1 Hydraulics/ Actuators Constant Displacement Pump/Motor 1 Hydraulics/ Basic Elements Volume 1 Hydraulics/ Valves/ Pressure Valves Pressure Relief Valve 1 Hydraulics/ Basic Elements Tank 1 Hydraulics/ Valves/ Proportional Directional Control Valves 1 Mechanics/ Linear Mechanics 1 Mechanics/ Linear Mechanics 1 Mechanics/ Rotational Mechanics Proportional Directional Control Valve Mass External Force Preset

4 ITI SimulationX Page 4 of 20 ITI GmbH Signal Blocks/ Signal Sources Curve Once you have succeeded in creating the model structure according to Figure 1, you have to enter the parameters for the elements and activate the protocol attribute for the variables which you want to plot after the simulation. Since almost all elements have default parameters, you only have to enter the parameters which are different from the default values. Table 2 gives an overview about the parameter settings which you have to enter. Some of the parameter dialogs have more than one page. Table 2: Parameter settings for the elements listed in Table 1 Element Parameter Input Cylinder Dialog Page Geometry : Set the Maximum Cylinder Stroke to 400 mm Set the Dead Volume at Port A and B to 100 cm 3 (select appropriate unit first and enter the value secondly) Set the Transformation of Piston Housing to mm The coordinate transformation dxh of 200 mm means, that the displacement of the Mass is zero while the piston stroke is 200 mm. It sets the center of the mass to the half of the piston stroke. Dialog Page Friction :

5 ITI SimulationX Page 5 of 20 ITI GmbH 2003 Dialog Page Results 2 : Activate the result attributes -> Mass Set the mass to 100 kg Set the initial displacement and velocity to zero Activate the protocol attribute GravityForce Set the force to (Mass.m*9.81) N Note, that in SimulationX you can enter constant values as well as arithmetical and/or booelan expressions, variables and functions for any parameter. In the case above, the expression considers the gravity force of Mass.m (100) kg. When using the "External Force" element, you have to decide whether to connect the left or the right side to the mechanical element (i.e. mass). In our case, we have connected the left side of the force to the mass (see Figure 1). This means, that the force will act against the positive direction of motion of the mass. The positive coordinate direction of the element (mass) is indicated by the small red arrows, the positive coordinate direction of the force is indicated by the big white arrows.

6 ITI SimulationX Page 6 of 20 ITI GmbH 2003 Activate the protocol attributes for the force : Pump Dialog page Geometry : Set the displacement volume to 50 cm 3 Dialog page Friction : Dialog page Leakage : Dialog page Results : Activate the protocol attribute for the flow at port A Motor Dialog page Parameters : Select the kind "Rotational Speed" Select at first the unit rpm and then the value for the rotational speed Activate the protocol attributes for Torque and Power

7 ITI SimulationX Page 7 of 20 ITI GmbH 2003 ReliefValve Activate the protocol attribute for the result variables Pressure Drop, Volume Flow and Power Dissipation ProportionalControlValve Dialog page Stroking : In the selection box Stroke Signal select Normalized Signal Note, that Normalized Signal means the valid range of the input signal must be from 1 to +1. At an input signal of zero the valve will be in its center position. Dialog page Q-y-Function : In the selection box Type of Edges select Identical Edges Set the flow per change of Stroke to (60 l/min)/- Note: A value of 60 (l/min)/- means, that we will have a flow of 60l/min at a pressure drop of 35 bar (at one single edge) for full valve opening stroke. Dialog page Dynamics : Turn off the check box for the valve dynamics

8 ITI SimulationX Page 8 of 20 ITI GmbH 2003 Dialog page Results : Activate the protocol attribute for the Relative Valve Stroke Activate the protocol attribute for the flow at port A & B Activate the protocol attribute for Power Dissipation ControlSignal Dialog Parameters : The power Dissipation allows you to investigate the overall efficiency of your system. Select Simulation Time t [s] Click the Edit button to open the dialog for the Input of Values Select the quantity and the labels for the axis by using the Properties button in the toolbar In the Properties - window you have to enter the comments and the quantities for the axes.

9 ITI SimulationX Page 9 of 20 ITI GmbH 2003 Enter for the X-axis the simulation time and for the Y-axis as comment Signal Output and quantity Base Quantities/ Relative Magnitude. Enter the following data and click OK when finished: You can also load existing data from ASCII files or double-click directly on the graphic on the right. Alternatively, you can use other elements from the library Signal Sources. Activate the protocol attribute for the result variable Signal Output ". VP Dialog page Parameters : Set the volume to 1 dm 3 Note, that volumes are not required in SimulationX. However a pump volume of zero would result in an infinitely fast pressure change, which is not realistic. Dialog page Results : Activate the protocol attribute for the pressure

10 ITI SimulationX Page 10 of 20 ITI GmbH 2003 Once you have entered the parameters of the model, you can run the simulation and observe the results. Figure 2 shows some of the simulation results.you can also change the hydraulic fluid by double-clicking on the connection and selecting a liquid. The default is HLP 46, a mineral oil with a viscosity behavior according to ISO VG 46. The control signal shows the specified characteristics. If the stroke signal for the valve is negative, the pump is connected to Port A of the cylinder, i.e. the load mass is lifted up. The flow at Port A and B of the valve is somehow proportional to the stroke signal. Because we have a differential cylinder, the flow shows an unsymmetrical behavior. The maximum positive flow can not exceed 50 l/min, which is the flow of the pump. The pressure in volume VP can not exceed 100 bar, which is the set pressure for the relief valve. At full negative opening of the control valve, the pump pressure VP drops to 32 bar, since the pump can not deliver enough flow.

11 Figure 2: ITI SimulationX Page 11 of 20 ITI GmbH 2003 Simulation results for the open-loop cylinder drive The velocity of the piston is proportional to the flow in the valve. As the pump pressure drops from 100 bar to 32 bar, the velocity also decreases slightly. When the control valve is closed, the piston oscillates because of the oil compressibility You can play with the simulation model, in order to improve the performance of the open-loop cylinder drive. (Don t forget to reset the model before you make modifications!) Some interesting changes in the behavior of the system should become obvious, if you change the set pressure in the relief valve from 100 bar to 200 bar, and use a smaller proportional control valve (i.e. change the Flow per Change of Stroke from 60 (l/min)/- to 20 (l/min)/-) Especially with the last modification, the pump pressure will remain constant since the flow demand of the cylinder is now decreased. Figure 3: Improved pressure and velocity characteristic with smaller control valve

12 ITI SimulationX Page 12 of 20 ITI GmbH 2003 Part 2: Adding an Accumulator You will now add an accumulator to the system in order to compensate for short flow demands from the cylinder which exceed the flow of the pump. Before you will do this, please reset the parameter Flow per Change of Stroke of the Proportional Control Valve from 20 (l/min)/- to 60 (l/min)/-. To add the accumulator to the model, carry out the following steps: Reset the simulation model. ( ) Open the library Hydraulics (Accessories and Sensors) and connect the fluid volume VP to the Hydropneumatic Accumulator to Figure 4. according Figure 4: Modified model structure with accumulator

13 Table3: ITI SimulationX Page 13 of 20 ITI GmbH 2003 Accumulator parameters Accu Dialog page Construction 1 : Set construction type to Bladder Accumulator (vertical) Set the accumulator gas volume to 5 dm 3 Set the Pre-Fill Pressure to 80 bar Set the dead volume at oil-side to 100 cm 3 Dialog page Operating Conditions : Set the "Initial Oil Pressure" to 100 bar Dialog page Results 1 : Activate the protocol attribute for Oil Pressure Activate the protocol attribute for Volume Flow of Oil Activate the protocol attribute for Gas Pressure Activate the protocol attribute for Gas Volume

14 ITI SimulationX Page 14 of 20 ITI GmbH 2003 Figure 5: Improved velocity with the accumulator If you run the simulation, you will find that the cylinder reaches its end stop after 0.23 s. At this moment, the velocity of the piston starts to oscillate with a very high frequency, because of the high end-stop stiffness of the cylinder. It would now be possible to adapt the stiffness and the damping of the cylinder end stop to the force of the cylinder and to the piston and load mass. However, you will rather make the system a closed-loop cylinder drive.

15 ITI SimulationX Page 15 of 20 ITI GmbH 2003 Part 3 : Closed-Loop System For many industrial applications, an open-loop cylinder drive is not sufficient. Closed-loop systems are used in such cases. You can easily enhance the given example of the cylinder drive to make it a closed-loop drive. Add the new objects as shown in Figure 6 and listed in Table 4. Figure 6: Closed-loop cylinder drive

16 ITI SimulationX Page 16 of 20 ITI GmbH 2003 Table 4: New objects needed for the closed-loop system Object Library Parameters Sensor Mechanics None PistonError Signal Blocks Set the sign switches as follow Note, that for controlling the process we have to compare the real displacement with the given displacement. Activate the protocol attribute for the output signal Gain Signal Blocks/ Linear Signal Blocks default As the next step, you have to adapt the data table for the command signal from a relative quantity (-) to a displacement signal (mm). To do this, open the parameter dialog for the model object CommandSignal and proceed as follows: Open the curve editor window by clicking on the "Edit"-Button in the dialog Parameters Edit the unit by clicking on Properties -Button

17 ITI SimulationX Page 17 of 20 ITI GmbH 2003 Define the quantity of the signal output as displacement: Adapt the values of the table to a maximum of 100 mm: Close the curve editor window with OK. Now you have finished the parameter entry and we can run the simulation.

18 ITI SimulationX Page 18 of 20 ITI GmbH 2003 You have changed the signal from a command signal to a position signal. It means another behavior as before, because you now control the position and not the signal for the ProportionalControlValve. Figure 7: Simulation Result for the closed-loop cylinder drive with a gain of 1 Figure 7 shows the result of the piston displacement compared to the value of the command signal. It can be observed, that the sign of the gain is OK but the value of 1 is too small. So let us increase the gain of the signal block Gain from 1 to 50: If you run the simulation again, you can observe that the performance has improved considerably (see Figure 8). Figure 8: Simulation result with a gain of 50

19 ITI SimulationX Page 19 of 20 ITI GmbH 2003 However if you open the result window for the mass velocity, you will see that the system tends to be unstable (see Figure 9). Figure 9: Unstable behavior of the mass velocity with the gain of 50 If such an effect occurs in reality, the gain must be decreased. However, in your model you have neglected the dynamic behavior of the control valve. Therefore, you have to include the dynamics of the valve by editing the following parameters of the "ProportionalControlValve": Table 5: New parameters of ProportionalControlValve ProportionalControlValve Activate the valve dynamics: Set the undamped Natural Frequency to 20 Hz: Set the Damping Ratio to 0.75: If you run the simulation again with the valve dynamics included, you can observe that the system shows now a stable behavior see Figure 10.

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