Chapter 3 Vectors. m = m1 + m2 = 3 kg + 4 kg = 7 kg (3.1)

Save this PDF as:

Size: px
Start display at page:

Download "Chapter 3 Vectors. m = m1 + m2 = 3 kg + 4 kg = 7 kg (3.1)"

Transcription

1 COROLLARY I. A body, acted on by two forces simultaneously, will describe the diagonal of a parallelogram in the same time as it would describe the sides by those forces separately. Isaac Newton - Principia 3.1 Introduction Of all the varied quantities that are observed in nature, some have the characteristics of scalar quantities while others have the characteristics of vector quantities. A scalar quantity is a quantity that can be completely described by a magnitude, that is, by a number and a unit. Some examples of scalar quantities are mass, length, time, density, and temperature. The characteristic of scalar quantities is that they add up like ordinary numbers. That is, if we have a mass m1 = 3 kg and another mass m2 = 4 kg then the sum of the two masses is m = m1 + m2 = 3 kg + 4 kg = 7 kg (3.1) A vector quantity, on the other hand, is a quantity that needs both a magnitude and a direction to completely describe it. Some examples of vector quantities are force, displacement, velocity, and acceleration. The velocity of a car moving at 50 km per hour (km/hr) due east can be represented by a vector. Velocity is a vector because it has a magnitude, 50 km, and a direction, due east. A vector is represented in this text book by boldface script, that is, A. Because we cannot write in boldface script on notepaper or a blackboard, a vector is written there as the letter with an arrow over it. A vector can be represented on a diagram by an arrow. A picture of this vector can be obtained by drawing an arrow from the origin of a Cartesian coordinate system. The length of the arrow represents the magnitude of the vector, while the direction of the arrow represents the direction of the vector. The direction is specified by the angle θ that the vector makes with an axis, usually the x-axis, and is shown in figure 3.1. y A θ Figure 3.1 Representation of a vector. x

2 The magnitude of vector A is written as the absolute value of A namely A, or simply by the letter A without boldfacing. One of the defining characteristics of vector quantities is that they must be added in a way that takes their direction into account. 3.2 The Displacement Probably the simplest vector that can be discussed is the displacement vector. Whenever a body moves from one position to another it undergoes a displacement. The displacement can be represented as a vector that describes how far and in what direction the body has been displaced from its original position. The tail of the displacement vector is located at the position where the displacement started, and its tip is located at the position at which the displacement ended. For example, if you walk 3 km due east, this walk can be represented as a vector that is 3 units long and points due east. It is shown as d 1 in figure 3.2. This is an example of a displacement vector. Suppose you now walk 4 km due north. This distance of 4 km in a northerly direction can be represented as another displacement vector d 2, which is also shown in figure 3.2. The result of these two displacements is a final displacement vector d that shows the total displacement from the original position. Figure 3.2 The displacement vector. We now ask how far did you walk? Well, you walked 3 km east and 4 km north and hence you have walked a total distance of 7 km But how far are you from where you started? Certainly not 7 km, as we can easily see using a little high school geometry. In fact the final displacement d is a vector of magnitude d and that distance d can be immediately determined by simple geometry. Applying the Pythagorean theorem to the right triangle of figure 3.2 we get and thus, d = d d 2 2 d = (3 km) 2 + (4 km) 2 = 25 km d = 5 km (3.2) 3-2

3 Even though you have walked a total distance of 7 km, you are only 5 km away from where you started. Hence, when these vector displacements are added d = d 1 + d2 (3.3) we do not get 7 km for the magnitude of the final displacement, but 5 km instead. The displacement is thus a change in the position of a body from its initial position to its final position. Its magnitude is the distance between the initial position and the final position of the body. It should now be obvious that vectors do not add like ordinary scalar numbers. In fact, all the rules of algebra and arithmetic that you were taught in school are the rules of scalar algebra and scalar arithmetic, although the word scalar was probably never used at that time. To solve physical problems associated with vectors it is necessary to deal with vector algebra. 3.3 Vector Algebra--The Addition of Vectors Let us now add any two arbitrary vectors a and b. The result of adding the two vectors a and b forms a new resultant vector R, which is the sum of a and b. This can be shown graphically by laying off the first vector a in the horizontal direction and then placing the tail of the second vector b at the tip of vector a, as shown in figure 3.3. Figure 3.3 The addition of vectors. The resultant vector R is drawn from the origin of the first vector to the tip of the last vector. The resultant vector is written mathematically as R = a + b (3.4) Remember that in this sum we do not mean scalar addition. The resultant vector is the vector sum of the individual vectors a and b. Although a vector is a quantity that has both magnitude and direction, it does not have a position. Consequently a vector may be moved parallel to itself without changing the characteristics of the vector. Because the magnitude of the moved vector is still the same, and its direction is still the same, the vector is the same. Hence, when adding vectors a and b, we can move vector a parallel to itself until the tip of a touches the tip of b. Similarly, we can move vector b parallel to 3-3

4 itself until the tip of b touches the tail end of the top vector a. In moving the vectors parallel to themselves we have formed a parallelogram, as shown in figure 3.4. Figure 3.4 The addition of vectors by the parallelogram method. From what was said before about the resultant of a and b, we can see that the resultant of the two vectors is the main diagonal of the parallelogram formed by the vectors a and b, hence we call this process the parallelogram method of vector addition. It is sometimes stated as part of the definition of a vector, that vectors obey the parallelogram law of addition. Note from the diagram that R = a + b = b + a (3.5) that is, vectors can be added in any order. Mathematicians would say vector addition is commutative. 3.4 Vector Subtraction -- The Negative of a Vector If we are given a vector a, as shown in figure 3.5, then the vector minus a ( a) is a vector of the same magnitude as a but in the opposite direction. That is, if vector a Figure 3.5 The negative of a vector. points to the right, then the vector a points to the left. Vector a is called the negative of the vector a. By defining the negative of a vector in this way, we can now determine the process of vector subtraction. The subtraction of vector b from vector a is defined as a b = a + ( b) (3.6) In other words, the subtraction of b from a is equivalent to adding vector a and the negative vector ( b). This is shown graphically in figure 3.6 (a). If we complete the parallelogram for the addition of a + b, we see that we can move the vector a b parallel to itself until it becomes the minor diagonal of the parallelogram, figure 3.6(b). 3-4

5 b a - b a a + b b. a (a) (b) Figure 3.6 The subtraction of vectors. 3.5 Addition of Vectors by the Polygon Method To find the sum of any number of vectors graphically, we use the polygon method. In the polygon method, we add each vector to the preceding vector by placing the tail of one vector to the head of the previous vector, as shown in figure 3.7. The resultant vector R is the sum of all these vectors. That is, R = a + b + c + d (3.7) We find R by drawing the vector from the origin of the coordinate system to the tip of the final vector, as shown in figure 3.7. Although this set of vectors could Figure 3.7 Addition of vectors by the polygon method. represent forces, velocities, and the like, it is sometimes easier for the beginning student to visualize them as though they were displacement vectors. It is easy to see from the figure that if a, b, c, and d were individual displacements, R would certainly be the resultant displacement of all the individual displacements. Vectors are usually added analytically or mathematically. In order to do that, we need to define the components of a vector. 3-5

6 3.6 Resolution of a Vector into Its Components An arbitrary vector a is drawn onto an x,y-coordinate system, as in figure 3.8. Vector a makes an angle θ with the x-axis. To find the x-component ax of vector a, we project vector a down onto the x-axis, that is, we drop a perpendicular from the tip of a to the x-axis. One way of visualizing this concept of a component of a vector is to place a light beam above vector a and parallel to the y-axis. The light hitting vector a will not make it to the x-axis, and will therefore leave a shadow on the x-axis. We call this shadow on the x-axis the x-component of vector a and denote it by ax. The component is shown as the light red line on the x-axis in figure 3.8. In the same way, we can determine the y-component of vector a, ay, by projecting a onto the y-axis in figure 3.8. That is, we drop a perpendicular from the Figure 3.8 Defining the components of a vector. tip of a onto the y-axis. Again, we can visualize this by projecting light, which is parallel to the x-axis, onto vector a. The shadow of vector a on the y-axis is the y- component ay, shown in figure 3.8 as the light red line on the y-axis. The components of the vector are found mathematically by noting that the vector and its components constitute a triangle, as seen in figure 3.9. From trigonometry, we find the x-component of a from cos θ = ax a (3.8) 3-6

7 Figure 3.9 Finding the components of a vector mathematically. Solving for ax, the x-component of vector a obtained is ax = a cos θ (3.9) We find the y-component of vector a from sin θ = ay a Hence, the y-component of vector a is (3.10) ay = a sin θ (3.11) Example 3.1 Finding the components of a vector. The magnitude of vector a is 10.0 units and the vector makes an angle of with the x-axis. Find the components of a. Solution The x-component of vector a, found from equation 3.9, is ax = a cos θ = 10.0 units cos = 8.66 units The y-component of a, found from equation 3.11, is ay = a sin θ = 10.0 units sin = 5.00 units To go to this interactive example click on this sentence. 3-7

8 What do these components of a vector represent physically? If vector a is a displacement, then ax would be the distance that the object is east of its starting point and ay would be the distance north of it. That is, if you walked a distance of 10.0 km in a direction that is north of east, you would be 8.66 km east of where you started from and 5.00 km north of where you started from. If, on the other hand, vector a were a force of 10.0 N applied at an angle of to the x-axis, then the x-component ax is equivalent to a force of 8.66 N in the x-direction, while the y-component ay is equivalent to a force of 5.00 N in the y-direction. 3.7 Determination of a Vector from Its Components If the components a x and ay of a vector are given, and we want to find the vector a itself, that is, its magnitude a and its direction θ, then the process is the inverse of the technique used in section 3.6. The components ax and ay of vector a are seen in figure If we form the triangle with sides ax and ay, then the hypotenuse of that Figure 3.10 Determining a vector from its components. triangle is the magnitude a of the vector, and is determined by the Pythagorean theorem as a 2 = ax 2 + ay 2 (3.12) Hence, the magnitude of vector a is a = a x 2 + a y 2 (3.13) It is thus very simple to find the magnitude of a vector once its components are known. To find the angle θ that vector a makes with the x-axis the definition of the tangent is used, namely tan θ = ay ax 3-8

9 We find the angle θ by using the inverse tangent, as θ = tan 1 ay ax (3.14) Example 3.2 Finding a vector from its components. The components of a certain vector are given as ax = 7.55 and ay = Find the magnitude of the vector and the angle θ that it makes with the x-axis. The magnitude of vector a, found from equation 3.13, is The angle θ, found from equation 3.14, is Solution a = a x 2 + a y 2 = (7.55) 2 + (3.25) 2 = = 8.22 θ = tan 1 ay = tan = tan ax 7.55 = Therefore, the magnitude of vector a is 8.22 and the angle θ is The techniques developed here will be very useful later for the addition of any number of vectors. To go to this interactive example click on this sentence. The components of a vector can also be found along axes other than the traditional horizontal and vertical ones. A coordinate system can be orientated any way we choose. For example, suppose a block is placed on an inclined plane that makes an angle θ with the horizontal, as shown in figure Let us find the components of the weight of the block parallel and perpendicular to the inclined plane. We draw in a set of axes that are parallel and perpendicular to the inclined plane, as shown in figure 3.11, with the positive x-axis pointing down the plane and the positive y-axis perpendicular to the plane. To find the components parallel and 3-9

10 Figure 3.11 Components of the weight parallel and perpendicular to the inclined plane. perpendicular to the plane, we draw the weight of the block as a vector pointed toward the center of the earth. The weight vector is therefore perpendicular to the base of the inclined plane. To find the component of w perpendicular to the plane, we drop a perpendicular line from the tip of vector w onto the negative y-axis. This length w is the perpendicular component of vector w. Similarly, to find the parallel component of w, we drop a perpendicular line from the tip of w onto the positive x- axis. This length w is the parallel component of the vector w. The angle between vector w and the perpendicular axis is also the inclined plane angle θ, as shown in the comparison of the two triangles in figure Figure 3.12 Comparison of two triangles. (Figure 3.12 is an enlarged view of the two triangles of figure 3.11). In triangle I, the angles must add up to Thus, while for triangle II θ + α = (3.15) 3-10

11 β + α = (3.16) From equations 3.15 and 3.16 we see that β = θ (3.17) This is an important relation that we will use every time we use an inclined plane. Example 3.3 Components of the weight perpendicular and parallel to the inclined plane. A 100-N block is placed on an inclined plane with an angle θ = , as shown in figure Find the components of the weight of the block parallel and perpendicular to the inclined plane. Solution We find the perpendicular component of w from figure 3.11 as The parallel component is w = w cos θ = 100 N cos = 64.3 N (3.18) w = w sin θ = 100 N sin = 76.6 N (3.19) To go to this interactive example click on this sentence. One of the interesting things about this inclined plane is that the component of the weight parallel to the inclined plane supplies the force responsible for making the block slide down the plane. Similarly, if you park your car on a hill with the gear in neutral and the emergency brake off, the car will roll down the hill. Why? You can now see that it is the component of the weight of the car that is parallel to the hill that essentially pulls the car down the hill. That force is just as real as if a person were pushing the car down the hill. That force, as can be seen from equation 3.19, is a function of the angle θ. If the angle of the plane is reduced to zero, then w = w sin 0 0 = 0 Thus, we can reasonably conclude that when a car is not on a hill (i.e., when θ = 0 0 ) there is no force, due to the weight of the car, to cause the car to move. Also note that the steeper the hill, the greater the angle θ, and hence the greater the component of the force acting to move the car down the hill. 3-11

12 3.8 Unit Vectors It is convenient in our analysis to introduce the concept of unit vectors. A unit vector is a vector that has a magnitude of one, hence the name, unit. It is used to specify a particular direction. The most common of the unit vectors are the i j k system of vectors shown in figure The unit vector i is a unit vector in the z y k j i x Figure 3.13 The i j k system of unit vectors. x-direction, the unit vector j is a unit vector in the y-direction, and the unit vector k is a unit vector in the z-direction. Also notice from figure 3.13, the coordinate system is a right-handed coordinated system. This means that if you place your right hand along the x-axis with your palm facing the y-axis, and then rotate your hand toward the y-axis, your thumb will face in the z-direction. Let us now consider an arbitrary vector a in two dimensions, as shown in figure The components ax and ay of the y y a a = i a x + ja y a y a y ja y ja y a x (a) x ia x (b) x Figure 3.14 A vector in terms of unit vectors. vector a are shown in figure 3.14a. If the x-component, ax, is multiplied by the unit vector i, the vector iax is obtained. The vector iax is a vector in the x-direction with magnitude ax as shown in figure 3.14b. Multiplying the y-component of the vector a, ay, by the unit vector j yields the vector jay. The vector jay is a vector in the y- direction with magnitude ay and is also shown in figure 3.14b. As can be seen from 3-12

13 figure 3.14b, adding the vector iax to the vector jay yields the original vector a. This can be written mathematically as a= ia + j a (3.20) x Equation 3.20 is the form of the equation used for writing a vector in terms of its components and the unit vectors. We will use this form of the equation for writing many of the vectors in this course. Besides the i j k unit vectors there are other unit vectors specifying other directions. These will be defined later as the need arises. y Example 3.4 Finding the magnitude and direction of a vector when expressed in terms of unit vectors. Given the vector a = 3i + 6j Find the magnitude of the vector a and the direction it makes with the x-axis. Solution The magnitude of the vector is found from equation 3.13 as a = a x 2 + a y 2 = = 45 = 6.71 The direction is found from equation 3.14 as a 6 θ = = = 1 y 1 1 tan tan tan 2 ax 3 θ = To go to this interactive example click on this sentence. 3.9 The Addition of Vectors by the Component Method A very important technique for the addition of vectors is the addition of vectors by the component method. Let us assume that we are given two vectors, a and b, and we want to find their vector sum. The sum of the vectors is the resultant vector R given by R = a + b (3.21) 3-13

14 and is shown in figure We determine R as follows. First, we find the components ax and ay of vector a by making the projections onto the x- and y-axes, respectively. To find the components of the vector b, we again make a projection onto the x- and y-axes, but note that the tail of vector b is not at the origin of coordinates, but rather at the tip of a. So both the tip and the tail of b are projected onto the x-axis, as shown, to get bx, the x-component of b. In the same way, we project b onto the y-axis to get by, the y-component of b. All these components are shown in figure Figure 3.15 The addition of vectors by the component method. The resultant vector R is given by equation 3.21, and because R is a vector it has components R x and Ry, which are the projections of R onto the x- and y-axes, respectively. They are shown in figure Now let us go back to the original diagram, figure 3.15, and project R onto the x-axis. Here Rx is shown a little distance below the x-axis, so as not to confuse Rx with the other components that are already there. Similarly, R is projected onto the y-axis to get Ry. Again Ry is slightly displaced from the y-axis, so as not to confuse Ry with the other components already there. Look very carefully at figure Note that the length of Rx is equal to the length of ax plus the length of bx. Because components are numbers and hence add like ordinary numbers, this addition can be written simply as R x = ax + bx (3.22) That is, the x-component of the resultant vector is equal to the sum of the x- components of the individual vectors. In the same manner, look at the geometry on the y-axis of figure The length Ry is equal to the sum of the lengths of ay and by, and therefore R y = ay + by (3.23) Thus, the y-component of the resultant vector is equal to the sum of the y-components of the individual vectors. 3-14

15 The same results can be obtained mathematically by writing the vectors in terms of the unit vectors. That is, a = iax + jay (3.24) and b = ibx + jby (3.25) The addition of the two vectors is simply a + b = iax + jay + ibx + jby gathering the terms with the same unit vectors together we obtain and simplifying a + b = iax + ibx + jay + jby a + b = i(ax + bx) + j(ay + by) (3.26) But the resultant vector R can also be written in terms of the unit vectors as However, since R = a + b, it follows that R = irx + jry (3.27) and therefore, irx = i(ax + bx) Rx = ax + bx (3.28) Notice that equation 3.28, obtained mathematically, agrees with equation 3.22, which was obtained geometrically. The y-component of the resultant vector is obtained similarly, i.e., jry = j(ay + by) Ry = ay + by (3.29) Again, notice that equation 3.29, obtained mathematically, agrees with equation 3.23, which was obtained geometrically. We could have performed this entire derivation mathematically, but the geometric approach gives us a more physical picture of what is happening. This demonstration of the addition of vectors was done for two vectors because it is easier to see the results in figure 3.15 for two vectors than it is for many vectors. However, the technique would be the same for the addition of any number of vectors. For the general case where there are many vectors, equations 3.28 and 3.29 for R x and Ry can be generalized to and R x = ax + bx + cx + dx + (3.30) 3-15

16 Ry = ay + by + cy + dy + (3.31) The plus sign and the dots that appear in equations 3.30 and 3.31 indicate additional components can be added for any additional vectors. We now have Rx and Ry, the components of the resulting vector R, as shown in figure But if the components of R are known the resultant vector can be Figure 3.16 The resultant vector. written as R=iR x +jr y (3.32) If it is desired to determine the magnitude of the resultant vector, R, this can be done by using the Pythagorean Theorem, i.e., R = R x 2 + R y 2 (3.33) The angle θ in figure 3.16 is found from the geometry to be Thus, R tanθ = R θ y x R 1 y = tan (3.34) R x where Rx and Ry are given by equations 3.30 and The magnitude R and the direction θ, of the resultant vector R, have thus been found. Therefore, the sum of any number of vectors can be determined by the component method of vector addition. Example 3.5 The addition of vectors by the component method. Find the resultant of the following four vectors: 3-16

17 A = 100, θ1 = B = 200, θ 2 = C = 75.0, θ 3 = D = 150, θ 4 = Solution The four vectors are drawn in figure Because any vector can be moved parallel to itself, all the vectors have been moved so that they are drawn as emanating from Figure 3.17 Addition of four vectors. the origin. Before actually solving the problem, let us first outline the solution. To find the resultant of these four vectors, we must first find the individual components of each vector, then we find the x- and y-components of the resulting vector from R x = Ax + Bx + Cx + Dx (3.35) Ry = Ay + By + Cy + Dy (3.36) We then find the resulting vector from and R = R x 2 + R y 2 θ = tan 1 Ry Rx (3.37) (3.38) The actual solution of the problem is found as follows: we find the individual x- components as Ax = A cos θ1 = 100 cos = 100(0.866) = 86.6 B x = B cos θ2 = 200 cos = 200(0.500) = C x = C cos θ3 = 75 cos = 75( 0.766) =

18 Dx = D cos θ4 = 150 cos = 150( 0.342) = 51.3 R x = Ax + Bx + Cx + Dx = 77.8 whereas the y-components are Ay = A sin θ1 = 100 sin = 100(0.500) = 50.0 B y = B sin θ2 = 200 sin = 200(0.866) = C y = C sin θ3 = 75 sin = 75(0.643) = 48.2 D y = D sin θ4 = 150 sin = 150( 0.940) = R y = Ay + By + Cy + Dy = The x- and y-components of vector R are shown in figure Because Rx and Ry are both positive, we find vector R in the first quadrant. If Rx were negative, R would have been in the second quadrant. It is a good idea to plot the components Rx and Ry for any addition so that the direction of R is immediately apparent. Figure 3.18 The resultant vector. The resultant vector can be written in terms of the unit vectors as R = irx + jry = 77.8i + 130j The magnitude of the resultant vector is found from equation 3.37 as R = R 2 x + R 2 y = (77.8) 2 + (130.2) 2 = 23, = 152 The angle θ that vector R makes with the x-axis is found as θ = tan 1 Ry = tan = tan Rx 77.8 = as is seen in figure

19 It is important to note here that the components Cx, Dx, and Dy are negative numbers. This is because Cx and Dx lie along the negative x-axis and Dy lies along the negative y-axis. We should note that in the solution of the components of the vector C in this problem, the angle of was entered directly into the calculator to give the solution for the cosine and sine of that angle. The calculator automatically gives the correct sign for the components if we always measure the angle from the positive x-axis. 1 To go to this interactive example click on this sentence. Example 3.6 Vectors in terms of unit vectors. Given the two vectors a = 3i + 2j b = 6i + 3j Find the following vector, its magnitude and its direction for (a) a + b, (b) a b, and (c) b a. a. The sum of the two vectors is found as Solution Its magnitude is Its direction is found as a + b = (3 + 6)i + (2 + 3)j a + b = 9i + 5j a + b = = 106 = 10.3 R 5 θ = = = 1 y 1 1 tan tan tan Rx 9 0 θ = We can also measure the angle that the vector makes with any axis other than the positive x-axis. For example, instead of using the angle of with respect to the positive x-axis, an angle of 40 0 with respect to the negative x-axis can be used to describe the direction of vector C. The x-component of vector C would then be given by Cx = C cos 40 0 = 75.0 cos 40 0 = Note that this is the same numerical value we obtained before, however the answer given by the calculator is now positive. But as we can see in figure 3.17, Cx is a negative quantity because it lies along the negative x-axis. Hence, if you do not use the angle with respect to the positive x-axis, you must add the positive or negative sign that is associated with that component. In most of the problems that will be covered in this text, we will measure the angle from the positive x-axis because of the simplicity of the calculation. However, whenever it is more convenient to measure the angle from any other axis, we will do so. 3-19

20 b. The difference between the two vectors is Its magnitude is a b = (3 6)i + (2 3) a b = 3i j a b = ( 3) 2 + ( 1) 2 = 10.0 = 3.16 Its direction is found as R 1 θ = = = R 3 1 y 1 1 tan tan tan x θ = Notice that both Rx and Ry are negative indicating that the angle θ is an angle in the third quadrant, between the negative x-axis and the vector (a b). The angle that the vector (a b) makes with the positive x-axis is found by adding to the angle θ, giving an angle of with respect to the positive x-axis. c. The difference between the two vectors is b a = (6 3)i + (3 2)j b a = 3i + j = (a b) Its magnitude is the same as the magnitude of a b, Its direction is found as b a = ( 3) 2 + (1) 2 = 10.0 = 3.16 R 1 θ = = = R 3 1 y 1 1 tan tan tan x θ = Notice that in this case both Rx and Ry are positive indicating that the angle θ is in the first quadrant, and hence the angle should be considered as positive. To go to this interactive example click on this sentence. Although most problems treated in this text will be two dimensional, we do live in a three dimensional world and hence most vectors are 3-dimensional. For those problems requiring three-dimensional vectors the extension to three dimensions is 3-20

21 quite simple. A three dimensional vector a is shown in figure Notice that it has the component ax in the x-direction, ay in the y-direction, and az in the z- direction. z a a z a x y x a y Figure 3.19 A vector in three dimensions. The vector a is written mathematically as a = iax + jay + kaz (3.39) while another arbitrary vector, b, is written as b = ibx + jby + kbz (3.40) The sum of the two vectors is determined as before R = a + b = iax + jay + kaz + ibx + jby + kbz R = a + b = i(ax + bx ) + j(ay + by) + k(az + bz) (3.41) And the resultant vector R can also be written in terms of the unit vectors as And as determined for the two dimensional case, R = irx + jry + krz (3.42) Rx = ax + bx (3.43) Ry = ay + by (3.44) Rz = az + bz (3.45) Finally, the magnitude of the resultant vector is found by the extension of the Pythagorean theorem to three dimensions as 3-21

22 R = R x 2 + R y 2 + R z 2 (3.46) Example 3.7 The magnitude of a three dimensional vector. Given the vector Find the magnitude of the vector a. a = 4i + 3j + 6k Solution The magnitude of the vector is found from equation 3.46 as a = a x 2 + a y 2 + a z 2 = a = 61 = 7.81 To go to this interactive example click on this sentence. Example 3.8 The resultant of three-dimensional vectors. Given the two vectors a = 7i + 2j + 8k b = 4i + 5j 3k Find the resultant vector and its magnitude. The sum of the two vectors is found as Solution R = a + b = (7 + ( 4))i + (2 + 5)j + (8 3)k R = a + b = 3i + 7j + 5k Its magnitude is found from equation 3.46 as R = R 2 x + R 2 2 y + R z R = = 83.0 = 9.11 To go to this interactive example click on this sentence. 3-22

23 3.10 The Multiplication of Vectors Not only can vectors be added and subtracted they can also be multiplied. The multiplication of vectors is important because there are many physical laws that are expressed as the product of vectors. There are three types of multiplication involving vectors. They are: 1) The multiplication of a vector by a scalar. Consider the vector a in figure 3.20a. This vector has both magnitude and direction. If a is multiplied by a scalar k then the product ka is a new vector, say b, where b = ka If k is a positive number greater than one, then the product represents a vector in the same direction as a but elongated by a factor k, as shown in figure 3.20b. If k is less than one, but greater than zero, the new vector is shorter than a, figure 3.20c, and if k is negative, the new vector is in the opposite direction of a, figure 3.20d. (a) a (b) ka k > 1 (c) ka 0 < k < 1 (d) ka k < 0 Figure 3.20 Multiplication of a vector by a scalar. 2) The scalar product. The scalar product is the multiplication of two vectors, the result of which is a scalar. The scalar product will be discussed in detail in the next section. 3) The vector product. The vector product is the multiplication of two vectors, the result of which is a vector. The vector product will be discussed in detail in section The Scalar Product or Dot Product The scalar product of two vectors a and b, figure 3.21, is defined to be ab= abcosθ (3.47) 3-23

24 b θ a Figure 3.21 The scalar product. where θ is the angle between the two vectors when they are drawn tail-to-tail, and a and b are the magnitudes of the two vectors. The symbol for this type of multiplication is the dot,, between the vectors a and b. Hence, the scalar product is also called the dot product. The definition, equation 3.47 might seem quite arbitrary with the inclusion of the cosθ. You might ask, why not use the tanθ or some other trigonometric function? The answer is quite simple; as will be shown shortly, equation 3.47 can represent different physical concepts and phenomena. As can be observed in figure 3.21, b cosθ is the component of the vector b in the a direction. Thus, the scalar product is the component of the vector b in the direction of the vector a, multiplied by the magnitude of the vector a itself. It can also be stated that the quantity, a cosθ, is the component of the vector a in the b direction and hence the scalar product is also the component of the vector a in the b direction, multiplied by the magnitude of the vector b itself. Either description is correct. The inclusion of the cosθ in the definition of the scalar product gives rise to some interesting special cases. If the vectors a and b are parallel to each other, then the angle θ between a and b is equal to zero. In that case, the scalar product becomes a b = ab cos0 0 But the cos0 0 = 1, therefore a b = ab (for a b) (Note that as a special case, a a = a 2, and hence a = aa defines the magnitude of any vector.) On the other hand, if a is perpendicular to b, then the angle between the two vectors is 90 0, and the scalar product becomes But the cos90 0 = 0, and hence a b = ab cos 90 0 a b = 0 (for a b) As an example, if the vector a has a magnitude of 2 units and vector b a magnitude of 3 units, then their dot product can take on any value between 6 and +6 depending on the angle θ between the two vectors. For scalars, on the other hand, 2 times 3 is always equal to 6 and nothing else. 3-24

25 Example 3.9 The scalar or dot product. The vector a has a magnitude of 5.00 units and the vector b a magnitude of 7.00 units. If the angle between the vectors is , find their scalar product. Solution The scalar product of the two vectors is found, by equation 3.47, to be a b = ab cosθ a b = (5.00)(7.00)cos a b = 21.1 To go to this interactive example click on this sentence. If the vectors are expressed in terms of the unit vectors, the dot product becomes a b = (iax + jay + kaz) (ibx + jby + kbz) The dot product of the unit vectors are a b = i iaxbx + i jaxby + i kaxbz + j iaybx + j jayby + j kaybz (3.48) + k iazbx + k jazby + k kazbz i i = (1)(1)cos0 0 = 1 j j = (1)(1)cos0 0 = 1 k k = (1)(1)cos0 0 = 1 (3.49) i j = j i = (1)(1)cos90 0 = 0 i k = k i = (1)(1)cos90 0 = 0 k j = j k = (1)(1)cos90 0 = 0 Notice that the dot product of a unit vector by itself is equal to one, because the magnitude of the unit vectors is equal to one and the angle between the unit vector and itself is equal to zero, and of course, the cosine of zero degrees is equal to one. Also notice that the dot product of two different unit vectors is equal to zero, because the angle between two different unit vectors is 90 0 and the cosine of 90 degrees is equal to zero. Using the results of equations 3.49, the dot product of two vectors becomes ab= ab + ab + ab (3.50) x x y y z z A special case of equation 3.50 is the dot product of a vector by itself. That is, 3-25

26 a a = axax + ayay + azaz aa= a + a + a = a (3.51) x y z and hence the magnitude of any vector is given by, a = a x 2 + a y 2 + a z 2 (3.52) Example 3.10 The dot product of three-dimensional vectors. Find the dot product of the following vectors a = 3i + 5j + 2k b = 4i + 7j + 5k Solution The dot product is found from equation 3.50 as a b = axbx + ayby + azbz a b = (3)( 4) + (5)(7) + (2)(5) a b = 33 Notice that the result of the dot product of two vectors is a scalar, that is, a number. To go to this interactive example click on this sentence The Vector Product or Cross Product The magnitude of the vector product of two vectors a and b is defined to be a b =absinθ (3.53) where θ is the angle between the two vectors when they are drawn tail-to-tail, and is shown in figure The symbol for the multiplication is designated by the 3-26

27 z a x b b? y a x Figure 3.22 The cross product. cross sign,, between the two vectors, and hence the name, cross product. The result of the cross product of two vectors, a and b, is another vector, a b, which is perpendicular to the plane made by the vectors a and b. The direction of a b is found by taking your right hand with the fingers in the same direction as the vector a, your palm facing toward the vector b, and then rotating your right hand through the angle between a and b. Your thumb will then point in the direction of a b as seen in figure The new vector is both perpendicular to the vector a and the vector b. This rule is called the right hand rule and it is imperative that the right hand be used. a x b b a Figure 3.23 The right hand rule to determine the direction of the cross product. One of the characteristics of this vector product, is that the order of the multiplication is very important, for as can be seen from figure 3.24 θ a b= b a (3.54) a xb b θ a a Figure 3.24 The sequence of the cross multiplication is very important. 3-27

28 The magnitude of a cross b is the same as the magnitude of b cross a from the defining equation 3.53, but their directions are opposite to each other as seen in figure This result is often stated as: vectors are non-commutative under vector multiplication. If the vectors a and b are parallel to each other then θ = 0 0 and But sin0 0 = 0, therefore a b = ab sin0 0 a b = 0 (for a b) (3.55) If the vector a is perpendicular to the vector b, then θ = 90 0 and But the sin 90 0 = 1, therefore a b = ab sin 90 0 a b = ab (for a b) (3.56) Note that these two cases are the opposite of what was found for the dot product. This is because the dot product contains the cosθ term, while the cross product contains the sinθ. The cosθ and sinθ are complementary functions and they are out of phase with each other by Example 3.11 The vector or cross product. The vector a has a magnitude of 5.00 units and the vector b of 7.00 units. If the angle between the vectors is , find the magnitude of their cross product. Solution The magnitude of their cross product is found from equation 3.53 to be a b = ab sinθ a b = (5.00)(7.00)sin a b = 28.0 The direction of a b is as shown in figure To go to this interactive example click on this sentence. The area of a surface can be represented by the cross product of the two vectors that generate the area. As an example, consider the two vectors, a and b, in figure If vectors a and b are moved parallel to themselves they are still the same vectors, since they still have the same magnitude and direction. But in the process 3-28

29 A = a x b θ b bsinθ a a b Figure 3.25 The area of a surface. of moving them parallel to themselves they have generated a parallelogram. As you recall from elementary geometry, the area of a parallelogram is equal to the product of its base times its altitude, i.e., A = (base)(altitude) The base of the parallelogram is given by the magnitude of the vector a, and the altitude is given by altitude = b sinθ Therefore, the area of the parallelogram is given by But A = ab sinθ ab sinθ = a b Therefore, the area of a parallelogram generated by sides a and b is A = a b = ab sinθ (3.57) Because a b is a vector perpendicular to the surface generated by the vectors a and b, the area of the surface can be represented as the vector A, where A = a b (3.58) The area vector A is thus perpendicular to the surface generated by the vectors a and b. If the vectors are expressed in terms of the unit vectors, the cross product becomes a b = (iax + jay + kaz) (ibx + jby + kbz) (3.59) a b = i iaxbx + i jaxby + i kaxbz + j iaybx + j jayby + j kaybz + k iazbx + k jazby + k kazbz (3.60) The magnitudes of the cross product of the unit vectors are i i = (1)(1)sin0 0 = 0 j j = (1)(1)sin0 0 =

30 k k = (1)(1)sin0 0 = 0 (3.61) i j = j i = (1)(1)sin90 0 = 1 i k = k i = (1)(1)sin90 0 = 1 k j = j k = (1)(1)sin90 0 = 1 Notice that the cross product of a unit vector by itself is equal to zero, because the magnitude of the unit vector is equal to one and the angle between the unit vector and itself is equal to zero, and of course, the sine of zero degrees is equal to zero. Also notice that the magnitude of the cross product of two different unit vectors is equal to one, because the angle between two different unit vectors is 90 0 and the sine of 90 degrees is equal to one. Because the cross product of two vectors yields another vector, the cross product of two different unit vectors must be another unit vector. It is now necessary to determine the direction of this unit vector. The direction of the new unit vector obtained by the cross product of two unit vectors is obtained with the help of figure 3.26(a). The direction of the cross product of i j is obtained by placing the right hand in the direction of the unit vector i, with the palm facing toward the unit vector j, and then rotating the hand toward the vector j. The thumb will point in the direction of the new vector. But as can be seen in figure 3.26(a), the thumb would point in the direction of the unit vector k. Since the cross product of the unit vectors i and j must be a unit vector, and the direction of this vector has been shown to be in the k direction, the new unit vector must be the unit vector k. Hence, z k = i xj y j = k x i i = j x k x k i j (a) (b) Figure 3.26 Multiplication of the unit vectors. i j = k (3.62) That is, the cross product of the unit vectors i and j is equal to the unit vector k. Using the same technique and figure 3.26(a), it can be seen that and j k = i (3.63) k i = j (3.64) Because the cross product is non-commutative, as shown in equation 3.54, the cross product of j i will point in the negative k direction, as can be seen in figure 3.26(a). Therefore, we also have 3-30

31 and j i = k (3.65) i k= j (3.66) k j = i (3.67) Using the results of equations 3.61 through 3.67 in equation 3.60 gives the cross product of two vectors as a b = (0)axbx + (k)axby + ( j)axbz + ( k)aybx + (0)ayby + (i)aybz + (j)azbx + ( i)azby + (0)azbz (3.68) Upon gathering like terms together, this becomes a b = i(aybz azby) + j(azbx axbz) + k(axby aybx) (3.69) Every student should make this calculation at least once to see how the cross products of the unit vectors are determined. However, once this has been accomplished it is easy to remember the sequence of the result by using the little circle shown in figure 3.26(b). If you go around the circle in a clockwise manor from i to j to k to i, the cross product of the first two vectors will yield the next unit vector in the cycle. Thus, i j = k; j k = i; and k i = j. If the circle is traversed in a counterclockwise direction, the resultant unit vector will be negative. Hence, i k = j; k j = i; and j i = k. The same cyclic relation can be used to remember the form of equation 3.69 because i is in the x-direction, j is in the y direction, and k is in the z direction. Hence, the cycle i j k is the same as the cycle x y z. The first term in equation 3.69 starts the cycle with i, which is associated with x, the next term in the parenthesis has the subscripts y and z. The minus term within the parenthesis then reverses the subscripts to z and y. The second term in equation 3.69 starts with j, which is associated with y, and the next term in the parenthesis has the subscripts z and x. The minus term within the parenthesis then reverses the subscripts to x and z. Finally the last term in equation 3.69 starts with k which is associated with z, and the next term in the parenthesis has the subscripts x and y. The minus term within the parenthesis then reverses the subscripts to y and x. Hence by remembering the cycle i j k and x y z it is easy to remember the form of equation Example 3.12 The vector product in terms of components. Given the two vectors Find their vector product. a = 3i + 5j + 2k b = 4i + 7j + 5k 3-31

32 Solution The cross product is found from equation 369 as a b = i(aybz azby) + j(azbx axbz) + k(axby aybx) a b = i{(5)(5) (2)(7)} + j{(2)( 4) (3)(5)} + k{(3)(7) (5)( 4)} a b = 11i 23j + 41k Notice that the result of the cross product is indeed a vector. To go to this interactive example click on this sentence. Example 3.13 The vector product in terms of a determinant. Show that the cross product of two vectors can be represented by a determinant as i j k a b = a a a (3.70) x y z b b b x y z Solution Using the rules for expansion of a determinant, equation 3.70 can be expressed as a a a a a a a b = i b b j b b + k b b y z x z x y y z x z x y a b = i(aybz azby) j(axbz azbx) + k(axby aybx) Factoring a minus one from inside the second term this becomes a b = i(aybz azby) + j(azbx axbz) + k(axby aybx) which is identical to equation Thus, the cross product can also be represented by a determinant. 3-32

33 The Language of Physics Scalar A scalar quantity is a quantity that can be completely described by a magnitude, that is, by a number and a unit (p. ). Vector A vector quantity is a quantity that needs both a magnitude and direction to completely describe it (p. ). Resultant The vector sum of any number of vectors is called the resultant vector (p. ). Parallelogram method of vector addition The main diagonal of a parallelogram is equal to the magnitude of the sum of the vectors that make up the sides of the parallelogram (p. ). Component of a vector The projection of a vector onto a specified axis. The length of the projection of the vector onto the x-axis is called the x-component of the vector. The length of the projection of the vector onto the y-axis is called the y-component of the vector (p. ). The addition of vectors by the component method The x-component of the resultant vector R x is equal to the sum of the x-components of the individual vectors, while the y-component of the resultant vector Ry is equal to the sum of the y-components of the individual vectors. The magnitude of the resultant vector is then found by the Pythagorean theorem applied to the right triangle with sides Rx and Ry. The direction of the resultant vector is found by trigonometry (p. ). Scalar Product The multiplication of two vectors, the result of which is a scalar (p. ). Vector Product The multiplication of two vectors, the result of which is a vector (p. ). Summary of Important Equations Vector addition is commutative R = a + b = b + a (3.5) Subtraction of vectors a b = a + ( b) (3.6) Addition of vectors R = a + b + c + d (3.7) 3-33

34 x-component of a vector ax = a cos θ (3.9) y-component of a vector ay = a sin θ (3.11) Magnitude of a vector Direction of a vector Vector in terms of unit vectors (3.20) a = a 2 2 x + a y θ = tan 1 ay ax a = iax + jay (3.13) (3.14) x-component of resultant vector R x = ax + bx + cx + dx... (3.30) y-component of resultant vector Ry = ay + by + cy + dy... (3.31) Resultant vector R = irx + jry (3.32) Magnitude of resultant vector R = R x 2 + R y 2 (3.33) Direction of resultant vector θ = tan 1 Ry (3.34) Three dimensional vector a = iax + jay + kaz (3.39) Resultant vector R = irx + jry + krz (3.42) Scalar product a b = ab cosθ (3.47) Scalar product a b = axbx + ayby + azbz (3.50) Rx Magnitude of a vector a = a x 2 + a y 2 + a z 2 (3.52) Magnitude of cross product a b = ab sinθ (3.53) Vector product is non-commutative a b = b a (3.54) Area of a parallelogram A = a b = ab sinθ (3.57) Vector product a b = i(aybz azby) + j(azbx axbz) + k(axby aybx) (3.69) 3-34

35 i j k Vector product a b = ax ay az (3.70) b b b x y z Questions for Chapter 3 1. Give an example of some quantities that are scalars and vectors other than those listed in section Can a vector ever be zero? What does a zero vector mean? 3. Since time seems to pass from the past to the present and then to the future, can you say that time has a direction and therefore could be represented as a vector quantity? 4. Does the subtraction of two vectors obey the commutative law? 5. What happens if you multiply a vector by a scalar? 6. What happens if you divide a vector by a scalar? 7. If a person walks around a block that is 80.0 m on each side and ends up at the starting point, what is the person s displacement? 8. How can you add three vectors of equal magnitude in a plane such that their resultant is zero? 9. When are two vectors a and b equal? 10. If a coordinate system is rotated, what does this do to the vector? to the components? 11. Why are all the fundamental quantities scalars? 12. A vector equation is equivalent to how many component equations? 13. If the components of a vector a are a x and ay, what are the components of the vector b = 5a? 14. If a + b = a b, what is the angle between a and b? Problems for Chapter Resolution of a Vector into Its Components and Determination of a Vector from Its Components 1. A strong child pulls a sled with a force of 100 N at an angle of 35 0 above the horizontal. Find the vertical and horizontal components of this pull. 2. A 50-N force is directed at an angle of 50 0 above the horizontal. Resolve this force into vertical and horizontal components. 3. A girl wants to hold a 68.0-N sled at rest on a snow-covered hill. The hill makes an angle of with the horizontal. (a) What force must he exert parallel to the slope? (b) What is the force perpendicular to the surface of the hill that presses the sled against the hill? 3-35

36 4. A displacement vector makes an angle of with respect to the x-axis. If the y-component of the vector is equal to 150 cm, what is the magnitude of the displacement vector? 5. A plane is traveling northeast at 200 km/hr. What is (a) the northward component of its velocity, and (b) the eastward component of its velocity? 6. While taking off, an airplane climbs at an 8 0 angle with respect to the ground. If the aircraft s speed is 200 km/hr, what are the vertical and horizontal components of its velocity? 7. The vector A has a magnitude of 50.0 m and points in a direction of north of east. What are the magnitudes and directions of the vectors, (a) 2A, (b) 0.5A, (c) A, (d) 5A, (e) A + 4A, (f) A 4A. 8. A car that weighs 8900 N is parked on a hill that makes an angle of 43 0 with the horizontal. Find the component of the car s weight parallel to the hill and perpendicular to the hill. 9. A girl pushes a lawn mower with a force of 90 N. The handle of the mower makes an angle of 40 0 with the ground. What are the vertical and horizontal components of this force and what are their physical significances? What effect does raising the handle to 50 0 have? 10. A missile is launched with a speed of 1000 m/s at an angle of 73 0 above the horizontal. What are the horizontal and vertical components of the missile s velocity? 11. When a ladder leans against a smooth wall, the wall exerts a horizontal force F on the ladder, as shown in the diagram. If F is equal to 50 N and θ is equal to 63 0, find the component of the force perpendicular to the ladder and the component parallel to the ladder. Diagram for problem Unit Vectors 12. Express the following three displacements in vector notation in terms of the unit vectors i and j: (a) 3 miles due east, (b) 6 miles east-northeast, and (c) 7 miles northwest. 13. A 50 N force is directed at an angle of above the horizontal. (a) Resolve this force into vertical and horizontal components, and (b) write the vector in terms of unit vectors If a = 5i + 6j, find the magnitude of a and the angle θ that the vector makes with the x-axis. 15. A point in space is located by the position vector 3-36

Figure 1.1 Vector A and Vector F

Figure 1.1 Vector A and Vector F CHAPTER I VECTOR QUANTITIES Quantities are anything which can be measured, and stated with number. Quantities in physics are divided into two types; scalar and vector quantities. Scalar quantities have

More information

Review A: Vector Analysis

Review A: Vector Analysis MASSACHUSETTS INSTITUTE OF TECHNOLOGY Department of Physics 8.02 Review A: Vector Analysis A... A-0 A.1 Vectors A-2 A.1.1 Introduction A-2 A.1.2 Properties of a Vector A-2 A.1.3 Application of Vectors

More information

PHYSICS 151 Notes for Online Lecture #6

PHYSICS 151 Notes for Online Lecture #6 PHYSICS 151 Notes for Online Lecture #6 Vectors - A vector is basically an arrow. The length of the arrow represents the magnitude (value) and the arrow points in the direction. Many different quantities

More information

Unified Lecture # 4 Vectors

Unified Lecture # 4 Vectors Fall 2005 Unified Lecture # 4 Vectors These notes were written by J. Peraire as a review of vectors for Dynamics 16.07. They have been adapted for Unified Engineering by R. Radovitzky. References [1] Feynmann,

More information

6. Vectors. 1 2009-2016 Scott Surgent (surgent@asu.edu)

6. Vectors. 1 2009-2016 Scott Surgent (surgent@asu.edu) 6. Vectors For purposes of applications in calculus and physics, a vector has both a direction and a magnitude (length), and is usually represented as an arrow. The start of the arrow is the vector s foot,

More information

3. KINEMATICS IN TWO DIMENSIONS; VECTORS.

3. KINEMATICS IN TWO DIMENSIONS; VECTORS. 3. KINEMATICS IN TWO DIMENSIONS; VECTORS. Key words: Motion in Two Dimensions, Scalars, Vectors, Addition of Vectors by Graphical Methods, Tail to Tip Method, Parallelogram Method, Negative Vector, Vector

More information

Lecture L3 - Vectors, Matrices and Coordinate Transformations

Lecture L3 - Vectors, Matrices and Coordinate Transformations S. Widnall 16.07 Dynamics Fall 2009 Lecture notes based on J. Peraire Version 2.0 Lecture L3 - Vectors, Matrices and Coordinate Transformations By using vectors and defining appropriate operations between

More information

Section V.3: Dot Product

Section V.3: Dot Product Section V.3: Dot Product Introduction So far we have looked at operations on a single vector. There are a number of ways to combine two vectors. Vector addition and subtraction will not be covered here,

More information

AP Physics - Vector Algrebra Tutorial

AP Physics - Vector Algrebra Tutorial AP Physics - Vector Algrebra Tutorial Thomas Jefferson High School for Science and Technology AP Physics Team Summer 2013 1 CONTENTS CONTENTS Contents 1 Scalars and Vectors 3 2 Rectangular and Polar Form

More information

11.1. Objectives. Component Form of a Vector. Component Form of a Vector. Component Form of a Vector. Vectors and the Geometry of Space

11.1. Objectives. Component Form of a Vector. Component Form of a Vector. Component Form of a Vector. Vectors and the Geometry of Space 11 Vectors and the Geometry of Space 11.1 Vectors in the Plane Copyright Cengage Learning. All rights reserved. Copyright Cengage Learning. All rights reserved. 2 Objectives! Write the component form of

More information

A vector is a directed line segment used to represent a vector quantity.

A vector is a directed line segment used to represent a vector quantity. Chapters and 6 Introduction to Vectors A vector quantity has direction and magnitude. There are many examples of vector quantities in the natural world, such as force, velocity, and acceleration. A vector

More information

9.4. The Scalar Product. Introduction. Prerequisites. Learning Style. Learning Outcomes

9.4. The Scalar Product. Introduction. Prerequisites. Learning Style. Learning Outcomes The Scalar Product 9.4 Introduction There are two kinds of multiplication involving vectors. The first is known as the scalar product or dot product. This is so-called because when the scalar product of

More information

Vector has a magnitude and a direction. Scalar has a magnitude

Vector has a magnitude and a direction. Scalar has a magnitude Vector has a magnitude and a direction Scalar has a magnitude Vector has a magnitude and a direction Scalar has a magnitude a brick on a table Vector has a magnitude and a direction Scalar has a magnitude

More information

Vector Algebra II: Scalar and Vector Products

Vector Algebra II: Scalar and Vector Products Chapter 2 Vector Algebra II: Scalar and Vector Products We saw in the previous chapter how vector quantities may be added and subtracted. In this chapter we consider the products of vectors and define

More information

2 Session Two - Complex Numbers and Vectors

2 Session Two - Complex Numbers and Vectors PH2011 Physics 2A Maths Revision - Session 2: Complex Numbers and Vectors 1 2 Session Two - Complex Numbers and Vectors 2.1 What is a Complex Number? The material on complex numbers should be familiar

More information

Section 1.1. Introduction to R n

Section 1.1. Introduction to R n The Calculus of Functions of Several Variables Section. Introduction to R n Calculus is the study of functional relationships and how related quantities change with each other. In your first exposure to

More information

Chapter 11 Equilibrium

Chapter 11 Equilibrium 11.1 The First Condition of Equilibrium The first condition of equilibrium deals with the forces that cause possible translations of a body. The simplest way to define the translational equilibrium of

More information

13.4 THE CROSS PRODUCT

13.4 THE CROSS PRODUCT 710 Chapter Thirteen A FUNDAMENTAL TOOL: VECTORS 62. Use the following steps and the results of Problems 59 60 to show (without trigonometry) that the geometric and algebraic definitions of the dot product

More information

Solving Simultaneous Equations and Matrices

Solving Simultaneous Equations and Matrices Solving Simultaneous Equations and Matrices The following represents a systematic investigation for the steps used to solve two simultaneous linear equations in two unknowns. The motivation for considering

More information

Difference between a vector and a scalar quantity. N or 90 o. S or 270 o

Difference between a vector and a scalar quantity. N or 90 o. S or 270 o Vectors Vectors and Scalars Distinguish between vector and scalar quantities, and give examples of each. method. A vector is represented in print by a bold italicized symbol, for example, F. A vector has

More information

Vectors and Scalars. AP Physics B

Vectors and Scalars. AP Physics B Vectors and Scalars P Physics Scalar SCLR is NY quantity in physics that has MGNITUDE, but NOT a direction associated with it. Magnitude numerical value with units. Scalar Example Speed Distance ge Magnitude

More information

Vector Math Computer Graphics Scott D. Anderson

Vector Math Computer Graphics Scott D. Anderson Vector Math Computer Graphics Scott D. Anderson 1 Dot Product The notation v w means the dot product or scalar product or inner product of two vectors, v and w. In abstract mathematics, we can talk about

More information

Adding vectors We can do arithmetic with vectors. We ll start with vector addition and related operations. Suppose you have two vectors

Adding vectors We can do arithmetic with vectors. We ll start with vector addition and related operations. Suppose you have two vectors 1 Chapter 13. VECTORS IN THREE DIMENSIONAL SPACE Let s begin with some names and notation for things: R is the set (collection) of real numbers. We write x R to mean that x is a real number. A real number

More information

v 1 v 3 u v = (( 1)4 (3)2, [1(4) ( 2)2], 1(3) ( 2)( 1)) = ( 10, 8, 1) (d) u (v w) = (u w)v (u v)w (Relationship between dot and cross product)

v 1 v 3 u v = (( 1)4 (3)2, [1(4) ( 2)2], 1(3) ( 2)( 1)) = ( 10, 8, 1) (d) u (v w) = (u w)v (u v)w (Relationship between dot and cross product) 0.1 Cross Product The dot product of two vectors is a scalar, a number in R. Next we will define the cross product of two vectors in 3-space. This time the outcome will be a vector in 3-space. Definition

More information

Introduction and Mathematical Concepts

Introduction and Mathematical Concepts CHAPTER 1 Introduction and Mathematical Concepts PREVIEW In this chapter you will be introduced to the physical units most frequently encountered in physics. After completion of the chapter you will be

More information

EDEXCEL NATIONAL CERTIFICATE/DIPLOMA MECHANICAL PRINCIPLES AND APPLICATIONS NQF LEVEL 3 OUTCOME 1 - LOADING SYSTEMS

EDEXCEL NATIONAL CERTIFICATE/DIPLOMA MECHANICAL PRINCIPLES AND APPLICATIONS NQF LEVEL 3 OUTCOME 1 - LOADING SYSTEMS EDEXCEL NATIONAL CERTIFICATE/DIPLOMA MECHANICAL PRINCIPLES AND APPLICATIONS NQF LEVEL 3 OUTCOME 1 - LOADING SYSTEMS TUTORIAL 1 NON-CONCURRENT COPLANAR FORCE SYSTEMS 1. Be able to determine the effects

More information

The Dot and Cross Products

The Dot and Cross Products The Dot and Cross Products Two common operations involving vectors are the dot product and the cross product. Let two vectors =,, and =,, be given. The Dot Product The dot product of and is written and

More information

In order to describe motion you need to describe the following properties.

In order to describe motion you need to describe the following properties. Chapter 2 One Dimensional Kinematics How would you describe the following motion? Ex: random 1-D path speeding up and slowing down In order to describe motion you need to describe the following properties.

More information

Examples of Scalar and Vector Quantities 1. Candidates should be able to : QUANTITY VECTOR SCALAR

Examples of Scalar and Vector Quantities 1. Candidates should be able to : QUANTITY VECTOR SCALAR Candidates should be able to : Examples of Scalar and Vector Quantities 1 QUANTITY VECTOR SCALAR Define scalar and vector quantities and give examples. Draw and use a vector triangle to determine the resultant

More information

The Force Table Introduction: Theory:

The Force Table Introduction: Theory: 1 The Force Table Introduction: "The Force Table" is a simple tool for demonstrating Newton s First Law and the vector nature of forces. This tool is based on the principle of equilibrium. An object is

More information

Copyright 2011 Casa Software Ltd. www.casaxps.com. Centre of Mass

Copyright 2011 Casa Software Ltd. www.casaxps.com. Centre of Mass Centre of Mass A central theme in mathematical modelling is that of reducing complex problems to simpler, and hopefully, equivalent problems for which mathematical analysis is possible. The concept of

More information

1.3. DOT PRODUCT 19. 6. If θ is the angle (between 0 and π) between two non-zero vectors u and v,

1.3. DOT PRODUCT 19. 6. If θ is the angle (between 0 and π) between two non-zero vectors u and v, 1.3. DOT PRODUCT 19 1.3 Dot Product 1.3.1 Definitions and Properties The dot product is the first way to multiply two vectors. The definition we will give below may appear arbitrary. But it is not. It

More information

FRICTION, WORK, AND THE INCLINED PLANE

FRICTION, WORK, AND THE INCLINED PLANE FRICTION, WORK, AND THE INCLINED PLANE Objective: To measure the coefficient of static and inetic friction between a bloc and an inclined plane and to examine the relationship between the plane s angle

More information

Units, Physical Quantities, and Vectors

Units, Physical Quantities, and Vectors Chapter 1 Units, Physical Quantities, and Vectors PowerPoint Lectures for University Physics, Thirteenth Edition Hugh D. Young and Roger A. Freedman Lectures by Wayne Anderson Goals for Chapter 1 To learn

More information

Section 9.1 Vectors in Two Dimensions

Section 9.1 Vectors in Two Dimensions Section 9.1 Vectors in Two Dimensions Geometric Description of Vectors A vector in the plane is a line segment with an assigned direction. We sketch a vector as shown in the first Figure below with an

More information

Math, Trigonometry and Vectors. Geometry. Trig Definitions. sin(θ) = opp hyp. cos(θ) = adj hyp. tan(θ) = opp adj. Here's a familiar image.

Math, Trigonometry and Vectors. Geometry. Trig Definitions. sin(θ) = opp hyp. cos(θ) = adj hyp. tan(θ) = opp adj. Here's a familiar image. Math, Trigonometr and Vectors Geometr Trig Definitions Here's a familiar image. To make predictive models of the phsical world, we'll need to make visualizations, which we can then turn into analtical

More information

Vectors 2. The METRIC Project, Imperial College. Imperial College of Science Technology and Medicine, 1996.

Vectors 2. The METRIC Project, Imperial College. Imperial College of Science Technology and Medicine, 1996. Vectors 2 The METRIC Project, Imperial College. Imperial College of Science Technology and Medicine, 1996. Launch Mathematica. Type

More information

Example SECTION 13-1. X-AXIS - the horizontal number line. Y-AXIS - the vertical number line ORIGIN - the point where the x-axis and y-axis cross

Example SECTION 13-1. X-AXIS - the horizontal number line. Y-AXIS - the vertical number line ORIGIN - the point where the x-axis and y-axis cross CHAPTER 13 SECTION 13-1 Geometry and Algebra The Distance Formula COORDINATE PLANE consists of two perpendicular number lines, dividing the plane into four regions called quadrants X-AXIS - the horizontal

More information

One advantage of this algebraic approach is that we can write down

One advantage of this algebraic approach is that we can write down . Vectors and the dot product A vector v in R 3 is an arrow. It has a direction and a length (aka the magnitude), but the position is not important. Given a coordinate axis, where the x-axis points out

More information

sin(θ) = opp hyp cos(θ) = adj hyp tan(θ) = opp adj

sin(θ) = opp hyp cos(θ) = adj hyp tan(θ) = opp adj Math, Trigonometr and Vectors Geometr 33º What is the angle equal to? a) α = 7 b) α = 57 c) α = 33 d) α = 90 e) α cannot be determined α Trig Definitions Here's a familiar image. To make predictive models

More information

TWO-DIMENSIONAL TRANSFORMATION

TWO-DIMENSIONAL TRANSFORMATION CHAPTER 2 TWO-DIMENSIONAL TRANSFORMATION 2.1 Introduction As stated earlier, Computer Aided Design consists of three components, namely, Design (Geometric Modeling), Analysis (FEA, etc), and Visualization

More information

Lecture 6. Weight. Tension. Normal Force. Static Friction. Cutnell+Johnson: 4.8-4.12, second half of section 4.7

Lecture 6. Weight. Tension. Normal Force. Static Friction. Cutnell+Johnson: 4.8-4.12, second half of section 4.7 Lecture 6 Weight Tension Normal Force Static Friction Cutnell+Johnson: 4.8-4.12, second half of section 4.7 In this lecture, I m going to discuss four different kinds of forces: weight, tension, the normal

More information

Physics Midterm Review Packet January 2010

Physics Midterm Review Packet January 2010 Physics Midterm Review Packet January 2010 This Packet is a Study Guide, not a replacement for studying from your notes, tests, quizzes, and textbook. Midterm Date: Thursday, January 28 th 8:15-10:15 Room:

More information

Geometry of Vectors. 1 Cartesian Coordinates. Carlo Tomasi

Geometry of Vectors. 1 Cartesian Coordinates. Carlo Tomasi Geometry of Vectors Carlo Tomasi This note explores the geometric meaning of norm, inner product, orthogonality, and projection for vectors. For vectors in three-dimensional space, we also examine the

More information

Biggar High School Mathematics Department. National 5 Learning Intentions & Success Criteria: Assessing My Progress

Biggar High School Mathematics Department. National 5 Learning Intentions & Success Criteria: Assessing My Progress Biggar High School Mathematics Department National 5 Learning Intentions & Success Criteria: Assessing My Progress Expressions & Formulae Topic Learning Intention Success Criteria I understand this Approximation

More information

ANALYTICAL METHODS FOR ENGINEERS

ANALYTICAL METHODS FOR ENGINEERS UNIT 1: Unit code: QCF Level: 4 Credit value: 15 ANALYTICAL METHODS FOR ENGINEERS A/601/1401 OUTCOME - TRIGONOMETRIC METHODS TUTORIAL 1 SINUSOIDAL FUNCTION Be able to analyse and model engineering situations

More information

Vectors Math 122 Calculus III D Joyce, Fall 2012

Vectors Math 122 Calculus III D Joyce, Fall 2012 Vectors Math 122 Calculus III D Joyce, Fall 2012 Vectors in the plane R 2. A vector v can be interpreted as an arro in the plane R 2 ith a certain length and a certain direction. The same vector can be

More information

Physics 590 Homework, Week 6 Week 6, Homework 1

Physics 590 Homework, Week 6 Week 6, Homework 1 Physics 590 Homework, Week 6 Week 6, Homework 1 Prob. 6.1.1 A descent vehicle landing on the moon has a vertical velocity toward the surface of the moon of 35 m/s. At the same time it has a horizontal

More information

The Vector or Cross Product

The Vector or Cross Product The Vector or ross Product 1 ppendix The Vector or ross Product We saw in ppendix that the dot product of two vectors is a scalar quantity that is a maximum when the two vectors are parallel and is zero

More information

2. Spin Chemistry and the Vector Model

2. Spin Chemistry and the Vector Model 2. Spin Chemistry and the Vector Model The story of magnetic resonance spectroscopy and intersystem crossing is essentially a choreography of the twisting motion which causes reorientation or rephasing

More information

Addition and Subtraction of Vectors

Addition and Subtraction of Vectors ddition and Subtraction of Vectors 1 ppendi ddition and Subtraction of Vectors In this appendi the basic elements of vector algebra are eplored. Vectors are treated as geometric entities represented b

More information

Mechanics 1: Vectors

Mechanics 1: Vectors Mechanics 1: Vectors roadly speaking, mechanical systems will be described by a combination of scalar and vector quantities. scalar is just a (real) number. For example, mass or weight is characterized

More information

Unit 11 Additional Topics in Trigonometry - Classwork

Unit 11 Additional Topics in Trigonometry - Classwork Unit 11 Additional Topics in Trigonometry - Classwork In geometry and physics, concepts such as temperature, mass, time, length, area, and volume can be quantified with a single real number. These are

More information

Trigonometry Review with the Unit Circle: All the trig. you ll ever need to know in Calculus

Trigonometry Review with the Unit Circle: All the trig. you ll ever need to know in Calculus Trigonometry Review with the Unit Circle: All the trig. you ll ever need to know in Calculus Objectives: This is your review of trigonometry: angles, six trig. functions, identities and formulas, graphs:

More information

VELOCITY, ACCELERATION, FORCE

VELOCITY, ACCELERATION, FORCE VELOCITY, ACCELERATION, FORCE velocity Velocity v is a vector, with units of meters per second ( m s ). Velocity indicates the rate of change of the object s position ( r ); i.e., velocity tells you how

More information

5.3 The Cross Product in R 3

5.3 The Cross Product in R 3 53 The Cross Product in R 3 Definition 531 Let u = [u 1, u 2, u 3 ] and v = [v 1, v 2, v 3 ] Then the vector given by [u 2 v 3 u 3 v 2, u 3 v 1 u 1 v 3, u 1 v 2 u 2 v 1 ] is called the cross product (or

More information

Trigonometric Functions and Triangles

Trigonometric Functions and Triangles Trigonometric Functions and Triangles Dr. Philippe B. Laval Kennesaw STate University August 27, 2010 Abstract This handout defines the trigonometric function of angles and discusses the relationship between

More information

ex) What is the component form of the vector shown in the picture above?

ex) What is the component form of the vector shown in the picture above? Vectors A ector is a directed line segment, which has both a magnitude (length) and direction. A ector can be created using any two points in the plane, the direction of the ector is usually denoted by

More information

Solutions to Exercises, Section 5.1

Solutions to Exercises, Section 5.1 Instructor s Solutions Manual, Section 5.1 Exercise 1 Solutions to Exercises, Section 5.1 1. Find all numbers t such that ( 1 3,t) is a point on the unit circle. For ( 1 3,t)to be a point on the unit circle

More information

28 CHAPTER 1. VECTORS AND THE GEOMETRY OF SPACE. v x. u y v z u z v y u y u z. v y v z

28 CHAPTER 1. VECTORS AND THE GEOMETRY OF SPACE. v x. u y v z u z v y u y u z. v y v z 28 CHAPTER 1. VECTORS AND THE GEOMETRY OF SPACE 1.4 Cross Product 1.4.1 Definitions The cross product is the second multiplication operation between vectors we will study. The goal behind the definition

More information

Angles and Quadrants. Angle Relationships and Degree Measurement. Chapter 7: Trigonometry

Angles and Quadrants. Angle Relationships and Degree Measurement. Chapter 7: Trigonometry Chapter 7: Trigonometry Trigonometry is the study of angles and how they can be used as a means of indirect measurement, that is, the measurement of a distance where it is not practical or even possible

More information

v v ax v a x a v a v = = = Since F = ma, it follows that a = F/m. The mass of the arrow is unchanged, and ( )

v v ax v a x a v a v = = = Since F = ma, it follows that a = F/m. The mass of the arrow is unchanged, and ( ) Week 3 homework IMPORTANT NOTE ABOUT WEBASSIGN: In the WebAssign versions of these problems, various details have been changed, so that the answers will come out differently. The method to find the solution

More information

Linear Algebra: Vectors

Linear Algebra: Vectors A Linear Algebra: Vectors A Appendix A: LINEAR ALGEBRA: VECTORS TABLE OF CONTENTS Page A Motivation A 3 A2 Vectors A 3 A2 Notational Conventions A 4 A22 Visualization A 5 A23 Special Vectors A 5 A3 Vector

More information

What You ll Learn Why It s Important Rock Climbing Think About This physicspp.com 118

What You ll Learn Why It s Important Rock Climbing Think About This physicspp.com 118 What You ll Learn You will represent vector quantities both graphically and algebraically. You will use Newton s laws to analyze motion when friction is involved. You will use Newton s laws and your knowledge

More information

PLANE TRUSSES. Definitions

PLANE TRUSSES. Definitions Definitions PLANE TRUSSES A truss is one of the major types of engineering structures which provides a practical and economical solution for many engineering constructions, especially in the design of

More information

Lab 2: Vector Analysis

Lab 2: Vector Analysis Lab 2: Vector Analysis Objectives: to practice using graphical and analytical methods to add vectors in two dimensions Equipment: Meter stick Ruler Protractor Force table Ring Pulleys with attachments

More information

Two vectors are equal if they have the same length and direction. They do not

Two vectors are equal if they have the same length and direction. They do not Vectors define vectors Some physical quantities, such as temperature, length, and mass, can be specified by a single number called a scalar. Other physical quantities, such as force and velocity, must

More information

Chapter 18 Static Equilibrium

Chapter 18 Static Equilibrium Chapter 8 Static Equilibrium 8. Introduction Static Equilibrium... 8. Lever Law... Example 8. Lever Law... 4 8.3 Generalized Lever Law... 5 8.4 Worked Examples... 7 Example 8. Suspended Rod... 7 Example

More information

Chapter 3B - Vectors. A PowerPoint Presentation by Paul E. Tippens, Professor of Physics Southern Polytechnic State University

Chapter 3B - Vectors. A PowerPoint Presentation by Paul E. Tippens, Professor of Physics Southern Polytechnic State University Chapter 3B - Vectors A PowerPoint Presentation by Paul E. Tippens, Professor of Physics Southern Polytechnic State University 2007 Vectors Surveyors use accurate measures of magnitudes and directions to

More information

Review of Fundamental Mathematics

Review of Fundamental Mathematics Review of Fundamental Mathematics As explained in the Preface and in Chapter 1 of your textbook, managerial economics applies microeconomic theory to business decision making. The decision-making tools

More information

9 Multiplication of Vectors: The Scalar or Dot Product

9 Multiplication of Vectors: The Scalar or Dot Product Arkansas Tech University MATH 934: Calculus III Dr. Marcel B Finan 9 Multiplication of Vectors: The Scalar or Dot Product Up to this point we have defined what vectors are and discussed basic notation

More information

Chapter 4. Forces and Newton s Laws of Motion. continued

Chapter 4. Forces and Newton s Laws of Motion. continued Chapter 4 Forces and Newton s Laws of Motion continued 4.9 Static and Kinetic Frictional Forces When an object is in contact with a surface forces can act on the objects. The component of this force acting

More information

... ... . (2,4,5).. ...

... ... . (2,4,5).. ... 12 Three Dimensions ½¾º½ Ì ÓÓÖ Ò Ø ËÝ Ø Ñ So far wehave been investigatingfunctions ofthe form y = f(x), withone independent and one dependent variable Such functions can be represented in two dimensions,

More information

Section 10.4 Vectors

Section 10.4 Vectors Section 10.4 Vectors A vector is represented by using a ray, or arrow, that starts at an initial point and ends at a terminal point. Your textbook will always use a bold letter to indicate a vector (such

More information

Part I. Basic Maths for Game Design

Part I. Basic Maths for Game Design Part I Basic Maths for Game Design 1 Chapter 1 Basic Vector Algebra 1.1 What's a vector? Why do you need it? A vector is a mathematical object used to represent some magnitudes. For example, temperature

More information

Additional Topics in Math

Additional Topics in Math Chapter Additional Topics in Math In addition to the questions in Heart of Algebra, Problem Solving and Data Analysis, and Passport to Advanced Math, the SAT Math Test includes several questions that are

More information

Trigonometric Functions: The Unit Circle

Trigonometric Functions: The Unit Circle Trigonometric Functions: The Unit Circle This chapter deals with the subject of trigonometry, which likely had its origins in the study of distances and angles by the ancient Greeks. The word trigonometry

More information

Triangle Trigonometry and Circles

Triangle Trigonometry and Circles Math Objectives Students will understand that trigonometric functions of an angle do not depend on the size of the triangle within which the angle is contained, but rather on the ratios of the sides of

More information

General Physics 1. Class Goals

General Physics 1. Class Goals General Physics 1 Class Goals Develop problem solving skills Learn the basic concepts of mechanics and learn how to apply these concepts to solve problems Build on your understanding of how the world works

More information

8-3 Dot Products and Vector Projections

8-3 Dot Products and Vector Projections 8-3 Dot Products and Vector Projections Find the dot product of u and v Then determine if u and v are orthogonal 1u =, u and v are not orthogonal 2u = 3u =, u and v are not orthogonal 6u = 11i + 7j; v

More information

Vectors. Objectives. Assessment. Assessment. Equations. Physics terms 5/15/14. State the definition and give examples of vector and scalar variables.

Vectors. Objectives. Assessment. Assessment. Equations. Physics terms 5/15/14. State the definition and give examples of vector and scalar variables. Vectors Objectives State the definition and give examples of vector and scalar variables. Analyze and describe position and movement in two dimensions using graphs and Cartesian coordinates. Organize and

More information

Geometry and Measurement

Geometry and Measurement The student will be able to: Geometry and Measurement 1. Demonstrate an understanding of the principles of geometry and measurement and operations using measurements Use the US system of measurement for

More information

Solutions to old Exam 1 problems

Solutions to old Exam 1 problems Solutions to old Exam 1 problems Hi students! I am putting this old version of my review for the first midterm review, place and time to be announced. Check for updates on the web site as to which sections

More information

Mechanics 1: Conservation of Energy and Momentum

Mechanics 1: Conservation of Energy and Momentum Mechanics : Conservation of Energy and Momentum If a certain quantity associated with a system does not change in time. We say that it is conserved, and the system possesses a conservation law. Conservation

More information

discuss how to describe points, lines and planes in 3 space.

discuss how to describe points, lines and planes in 3 space. Chapter 2 3 Space: lines and planes In this chapter we discuss how to describe points, lines and planes in 3 space. introduce the language of vectors. discuss various matters concerning the relative position

More information

LINEAR INEQUALITIES. Mathematics is the art of saying many things in many different ways. MAXWELL

LINEAR INEQUALITIES. Mathematics is the art of saying many things in many different ways. MAXWELL Chapter 6 LINEAR INEQUALITIES 6.1 Introduction Mathematics is the art of saying many things in many different ways. MAXWELL In earlier classes, we have studied equations in one variable and two variables

More information

Analysis of Stresses and Strains

Analysis of Stresses and Strains Chapter 7 Analysis of Stresses and Strains 7.1 Introduction axial load = P / A torsional load in circular shaft = T / I p bending moment and shear force in beam = M y / I = V Q / I b in this chapter, we

More information

Module 8 Lesson 4: Applications of Vectors

Module 8 Lesson 4: Applications of Vectors Module 8 Lesson 4: Applications of Vectors So now that you have learned the basic skills necessary to understand and operate with vectors, in this lesson, we will look at how to solve real world problems

More information

Equations Involving Lines and Planes Standard equations for lines in space

Equations Involving Lines and Planes Standard equations for lines in space Equations Involving Lines and Planes In this section we will collect various important formulas regarding equations of lines and planes in three dimensional space Reminder regarding notation: any quantity

More information

Physics 1A Lecture 10C

Physics 1A Lecture 10C Physics 1A Lecture 10C "If you neglect to recharge a battery, it dies. And if you run full speed ahead without stopping for water, you lose momentum to finish the race. --Oprah Winfrey Static Equilibrium

More information

Geometric Transformations

Geometric Transformations Geometric Transformations Definitions Def: f is a mapping (function) of a set A into a set B if for every element a of A there exists a unique element b of B that is paired with a; this pairing is denoted

More information

Linear Algebra Notes for Marsden and Tromba Vector Calculus

Linear Algebra Notes for Marsden and Tromba Vector Calculus Linear Algebra Notes for Marsden and Tromba Vector Calculus n-dimensional Euclidean Space and Matrices Definition of n space As was learned in Math b, a point in Euclidean three space can be thought of

More information

THEORETICAL MECHANICS

THEORETICAL MECHANICS PROF. DR. ING. VASILE SZOLGA THEORETICAL MECHANICS LECTURE NOTES AND SAMPLE PROBLEMS PART ONE STATICS OF THE PARTICLE, OF THE RIGID BODY AND OF THE SYSTEMS OF BODIES KINEMATICS OF THE PARTICLE 2010 0 Contents

More information

Universal Law of Gravitation

Universal Law of Gravitation Universal Law of Gravitation Law: Every body exerts a force of attraction on every other body. This force called, gravity, is relatively weak and decreases rapidly with the distance separating the bodies

More information

Vector Algebra CHAPTER 13. Ü13.1. Basic Concepts

Vector Algebra CHAPTER 13. Ü13.1. Basic Concepts CHAPTER 13 ector Algebra Ü13.1. Basic Concepts A vector in the plane or in space is an arrow: it is determined by its length, denoted and its direction. Two arrows represent the same vector if they have

More information

Parallel and Perpendicular. We show a small box in one of the angles to show that the lines are perpendicular.

Parallel and Perpendicular. We show a small box in one of the angles to show that the lines are perpendicular. CONDENSED L E S S O N. Parallel and Perpendicular In this lesson you will learn the meaning of parallel and perpendicular discover how the slopes of parallel and perpendicular lines are related use slopes

More information

Plotting and Adjusting Your Course: Using Vectors and Trigonometry in Navigation

Plotting and Adjusting Your Course: Using Vectors and Trigonometry in Navigation Plotting and Adjusting Your Course: Using Vectors and Trigonometry in Navigation ED 5661 Mathematics & Navigation Teacher Institute August 2011 By Serena Gay Target: Precalculus (grades 11 or 12) Lesson

More information

MAT 1341: REVIEW II SANGHOON BAEK

MAT 1341: REVIEW II SANGHOON BAEK MAT 1341: REVIEW II SANGHOON BAEK 1. Projections and Cross Product 1.1. Projections. Definition 1.1. Given a vector u, the rectangular (or perpendicular or orthogonal) components are two vectors u 1 and

More information

Vector Spaces; the Space R n

Vector Spaces; the Space R n Vector Spaces; the Space R n Vector Spaces A vector space (over the real numbers) is a set V of mathematical entities, called vectors, U, V, W, etc, in which an addition operation + is defined and in which

More information

Physics 201 Homework 8

Physics 201 Homework 8 Physics 201 Homework 8 Feb 27, 2013 1. A ceiling fan is turned on and a net torque of 1.8 N-m is applied to the blades. 8.2 rad/s 2 The blades have a total moment of inertia of 0.22 kg-m 2. What is the

More information