# The Use of Dynamic Geometry Software in the Teaching and Learning of Geometry through Transformations

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1 The Use of Dynamic Geometry Software in the Teaching and Learning of Geometry through Transformations Dynamic geometry technology should be used to maximize student learning in geometry. Such technology may help students in their learning processes by enabling them to visualize geometry concepts being studied. With dynamic geometry packages, students explore properties of congruence and similarity, focusing on the role of transformations. The use of technology depends on the teacher, and the teacher s role in making curriculum decisions is very important. Recognizing that today s students are using technology outside of the classroom and the study of mathematics should keep pace, teachers need to take advantage of the technology for learning. Thus, one goal for using dynamic geometry is to enable students to examine mathematical ideas on their own, allowing them not to be just consumers of technology but producers of knowledge through technology. By allowing freedom and free access to technology at any time, students can be creative, be involved, and can advance their learning as they study geometry. (It is noted that allowing students free use of technology may cause concern for some teachers because with this free access, some class control may be lost.) Moving from Concept to Construction Dynamic geometry can be used in different ways. One approach is to move from concept to construction with technology. The following example from geometry illustrates the approach. Another example involving algebra is described in the Connecting Transformational Geometry and Transformations of Functions brief. Congruent Triangles by Side-Angle-Side (SAS) Concept

2 Consider an investigation of a fundamental congruence test for triangles such as the Side-Angle-Side theorem, If two sides and the included angle of one triangle are congruent to two corresponding sides and the included angle of another triangle, the triangles are congruent. Students can be asked: How can you determine if two triangles are congruent? For example, what if two sides and the included angle of one triangle are congruent to two sides and the included angle of the second triangle? Construction (Modeling) In most situations, the students determine an answer by investigation. They may construct triangles with two sides of certain lengths and a certain included angle measure. They might draw the figure on patty paper and then overlay it with a partner s drawing to observe if the triangles match exactly. Sometimes the students cut out the triangles they draw and put them together to compare whether they match. They may complete the process without formally thinking about transformations, but students should discover that the triangles appear congruent and conjecture the Side-Angle-Side theorem. Dynamic Geometry Software Generally speaking, the SAS theorem for congruent triangles can be introduced as above. However, if dynamic geometry software were used in the class, what new or different learning of SAS could be accomplished? Imagine a classroom scene where a teacher has students sketch triangles using dynamic geometry with two sides of given lengths and an included angle between them with a given measure. If student sketches are displayed for all to see, most should recognize that the triangles are

3 the same size and shape, or appear to be congruent even though they may have different orientations and be at different locations on individual screens. By having students copy any two of the triangles on their own screens, they could be challenged to try and make one fit atop the other using transformation properties of the geometry software. For example, the student may use a translation to drag one triangle toward the other until two vertices of congruent appearing angles match. The student might then rotate the dragged triangle around the matched vertex until the angles match. The triangles may match exactly after this movement, or set of movements, but sometimes the translated triangle may also need to be reflected to get them to match exactly. In any event, after no more than three movements, the two triangles should be made to match and thus appear congruent. In the second approach, the students actively move the triangles electronically using the mathematical notions of transformations given in the dynamic geometry. Visualizing the triangles moving on the screen using transformations they have chosen, students not only see the geometric transformations intuitively, they know precisely which transformations have been used to make them match exactly. With this background, the teacher can explain the congruent triangles in a mathematical way--two triangles are congruent if one can be mapped onto the other by a sequence of isometries (rigid transformations). The two approaches aid each other. It is important to note that working with patty paper gives credence to the movements that take place with the dynamic geometry package, but the use of the dynamic geometry mathematizes the informal movement with patty paper.

4 The second approach using dynamic geometry allows students to engage in more formal reasoning. Consider the above example constructed with technology where two triangles in Figure 1 below have AB = A'B', AC = A'C', and BAC is congruent to B'A'C'. This figure is used to examine SAS with dynamic geometry software. Figure 1: Two triangles with respective two sides and an included angle congruent To investigate the informal description above more systematically, students first find a line that reflects A to A' as in Figure 2. An intuitive way to reflect a point to a point is to reflect the point over the perpendicular bisector, n, of the segment connecting the two points, in this case, the perpendicular bisector of AA'.

5 Figure 2: Triangle ABC reflected in line n, where C is reflected to C' As pictured, line n is the perpendicular bisector of AA'. The image of triangle ABC under this reflection is triangle A'B"C". There are many ways to continue; one is to find a line that will reflect A'B" onto A'B'. Because the segments share an endpoint, any reflecting line that maps one segment to the other must contain the common point A'. Thus, to map a line onto an intersecting line, an angle bisector containing the intersection point can be used. In Figure 3, students might use the angle bisector, j, of B"A'B'. Now because A'B" and A'B' are congruent, and the angle bisector reflects A'B" onto A'B', point B" is mapped onto point B' This is shown in Figure 3 yielding the image of triangle A'B"C" as triangle A'B'C'.

6 Figure 3: Triangle A'BC reflected to triangle A'B'C' In this situation, it appears that r j r n (triangle ABC) = triangle A'B'C'. The remaining question to be sure this is true is to consider what happens to point C. Is its image point C'? If so, the triangles are congruent. To answer this question, students may consider what can possibly happen to point C. They know that AC is congruent to A'C" because the latter is the image of the former in a reflection in line n. And they know that the image of A'C" is mapped to a congruent segment in the reflection in line j. The only question is whether the image of C is C'. They know that any isometry preserves angle measures, that line j is the bisector of B"A'B' making B"A'X congruent to B'A'X. Additionally students know that B"A'C" maps to a congruent angle in the reflection in line j. Having congruent angles and with A'C" congruent to A'C ' gives point C' as the image of point C" and thus the image of point C. Hence, the transformation to make triangle ABC congruent to triangle A'B'C' used two reflections in intersecting lines, n and j.

7 Suppose lines n and j intersect in point O. What else can be learned about the original (triangle ABC) and the final image (triangle A'B'C')? Consider the measures of angles AOA', BOB', and COC' as seen in Figure 4. B l1 A B" C j C' ' A' B' I O C' Figure 4: Measures of rotation angles are approximately 104 Because OA = OA' (O is the perpendicular bisector of AA' and any point on n is equidistant from A and A'.), there is a circle with center O and radius OA containing points A" and A'. Additionally because OB = OB" = OB' using properties of isometries, there is a circle with center O and radius OB containing points B, B", and B', and similarly because OC = OC" = OC', there is a circle with center O and radius OC containing points C, C", and C'. Using the dynamic geometry measuring tool, a rotation of 104º with center O can be accomplished by the composition of reflections in intersecting lines n and j. Moreover, the measure of the

8 angle between the intersecting lines is 52º. (To consider why the angle has measure 52º, think about the reflecting lines as angle bisectors.) In this way, technology can be used to build a rotation in a step-by-step development that is the composition in two intersecting lines, n and j. Further, the angle of rotation is twice the measure of the angle formed by the two reflecting lines. Though this is a specific example, it is possible to use the same reasoning to prove that the composition of two reflections in intersecting lines is a rotation with center at the point of intersection of the lines and the angle of rotation twice the measure of the angle formed by the lines. [Actually there are two different angle measures formed by the lines, but consider the points and their images to determine the angle measure being used.] Using Transformational Geometry to Obtain Properties of Figures Transformational geometry may be used to make and prove conjectures about properties of geometric figures. An example is given in the following: Example. Show that the angle bisectors of a triangle are concurrent. As a class, students are encouraged to investigate the statement on their own and make conjectures. It may be advantageous to have students investigate this using dynamic geometry with their choice of triangles. Once they have made the conjecture that all angle bisectors are concurrent, a teacher may use the following to reason and prove the conjecture. In Figure 5, let ABC be any triangle.

9 Figure 5: Scalene triangle ABC Construct the bisector of CAB. Reflect AC in this angle bisector. The image of AC must be AB to preserve angle measures as in Figure 6. Figure 6: Triangle ABC with bisectors of angles A and B Now the bisector of ABC is constructed. The image of AB in this bisector is CB (Why?). The final step in thinking about how this may be done is to find a

10 line that contains the point of intersection of the first two angle bisectors and makes CB its own image. [The reason for doing this involves a basic theorem of transformational geometry; that is, a composition of reflections in three concurrent lines may be replaced by a single line concurrent with those three original lines. The teacher may wish to have students try this result with dynamic geometry before this problem is given.] A natural line that meets both conditions is the perpendicular from the point of intersection of the two angle bisectors to CB. This line is constructed as in Figure 7, and the image of CB in a reflection in the perpendicular is CB itself. Figure 7: Triangle ABC with bisectors of angles A and B with a perpendicular to CB through the point of intersection of the angle bisectors The point of intersection of the angle bisectors is its own image in each of the reflections. Moreover, r l r k r j ( AC ) = CB. But the image of AC in the bisector

11 of angle ACB is also CB. Thus the angle bisectors of the angles of triangle ABC are concurrent; that is, contain the same point. Advantages of using technology Using technology to work with geometric transformations provides many advantages to students. Students are able to generate fast, accurate and easy arguments leading to conjectures and suggested ways of reasoning, to problem solutions, and to explorations of new and unknown mathematics. They may create their own conjectures and make a construction with technology to write a proof or argument. Teachers on the other hand may need examples to encourage students to create conjectures. As an example, consider the following: Given AB CD with AE = 5 cm; BE = 3 cm and EC = 9 cm, calculate the value of x (ED in the diagram) in Figure 8. Figure 8: Geometric figure with AB CD Students may solve this problem by first proving that ABE is similar to DCE using theorems related angles to parallel lines and then deducing the ratios:

12 5 3 = x 9 x =15 cm However, suppose students use geometric transformations and rotate ABE180º about E to produce EA'B'which sits on EDC. (This can be shown using properties of the rotation.) Now EA'B' is a dilation of EDC with center E and scale factor 3/9, or 1/3 (Again, students can show this is true using properties of a dilation.). Thus x = 3(5 cm) = 15 cm. Another investigation that can be made easier is to consider properties of a quadrilateral by constructing it using transformations and a dynamic geometry and beginning with any isosceles triangle as in Figure 9. Choose the base, and either rotating the triangle 180º about a midpoint of the base or reflect the triangle in the base. The pre-image and the image from the reflection form a quadrilateral. What are the properties of this quadrilateral? What would happen for a scalene triangle, an equilateral triangle or a right triangle if similar transformations were used?

13 Figure 9: Isosceles triangle DAB is reflected in base DB Disadvantages of Using Technology The discussion above illustrated some advantages of using technology but did not mention disadvantages. For example, when do measurements using dynamic geometry software, typically approximations, possibly lead to incorrect results and is this important to consider in terms of student learning? Another concern with a dynamic geometry package, students only see a small portion of the plane displayed but do not see what happens to the rest of the plane under the transformation being considered. As a result, they may forget that an entire plane is being transformed. Conclusion Dynamic geometry software can be a beneficial tool for using geometric transformations in the study of geometry. An important consideration is to use technology to develop background knowledge and ways of thinking as well as help students move further in their understanding of core geometry concepts. To maximize the potential of technology, teachers need to understand the how, what and why of teaching with technology. They need experience in considering when technology can most effectively be used. Transformational geometry provides one area where the technology can be used for more learning as long as student have free access to dynamic geometric software as they explore problems and develop understanding.

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