EE247 Lecture 4. For simplicity, will start with all pole ladder type filters. Convert to integrator based form example shown


 Magdalene Todd
 1 years ago
 Views:
Transcription
1 EE247 Lecture 4 Ldder type filters For simplicity, will strt with ll pole ldder type filters Convert to integrtor bsed form exmple shown Then will ttend to high order ldder type filters incorporting zeros Implement the sme 7th order elliptic filter in the form of ldder C with zeros Find level of sensitivity to component mismtch Compre with cscde of biquds Convert to integrtor bsed form utilizing SFG techniques Effect of Integrtor NonIdelities on Filter Frequency Chrcteristics EECS 247 Lecture 4: Active Filters 2007 H.K. Pge LC Ldder Filters L2 L4 in C C3 C5 Design: Filter tbles A. Zverev, Hndbook of filter synthesis, Wiley, 967. A. B. Willims nd F. J. Tylor, Electronic filter design, 3 rd edition, McGrwHill, 995. CAD tools Mtlb Spice EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 2
2 LC Ldder Filter Design Exmple Design LPF with mximlly flt pssbnd: f3db = 0MHz, fstop = 20MHz >27dB Mximlly flt pssbnd Butterworth Find minimum filter order : Use of Mtlb or Tbles Here tbles used fstop / f3db = 2 >27dB 3dB Stopbnd Attenution db Minimum Filter Order 5th order Butterworth 2 Νοrmlized ω From: Willims nd Tylor, p. 237 EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 3 LC Ldder Filter Design Exmple Find vlues for L & C from Tble: Note L &C vlues normlized to ω 3dB = Denormliztion: Multiply ll L Norm, C Norm by: L r = R/ω 3dB C r = /(RXω 3dB ) R is the vlue of the source nd termintion resistor (choose both Ω for now) Then: L= L r xl Norm C= C r xc Norm From: Willims nd Tylor, p..3 EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 4
3 LC Ldder Filter Design Exmple Find vlues for L & C from Tble: Normlized vlues: C Norm =C5 Norm =0.68 C3 Norm = 2.0 L2 Norm = L4 Norm =.68 Denormliztion: Since ω 3dB =2πx0MHz L r = R/ω 3dB = 5.9 nh C r = /(RXω 3dB )= 5.9 nf R = C=C5=9.836nF, C3=3.83nF L2=L4=25.75nH From: Willims nd Tylor, p..3 EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 5 Lst Lecture: Exmple: 5 th Order Butterworth Filter in =Ohm L2=25.75nH C 9.836nF L4=25.75nH C3 3.83nF C nF =Ohm Specifictions: f3db = 0MHz, fstop = 20MHz >27dB Used filter tbles to obtin Ls & Cs Mgnitude (db) SPICE simultion Results 30dB Frequency [MHz] EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 6
4 LowPss C Ldder Filter Conversion to Integrtor Bsed Active Filter in I L2 I3 L4 I 5 C C3 C5 I 2 I4 I 6 I 7 Use KCL & KL to derive equtions: I = in 2, 2 2 =, 3 = 2 sc 4 I I =, 5 = 4 6, 6 = o = 6 sc 3 sc 5 3 I =, I 2 = I I 3, I 3 = sl2 5 6 I 4 = I 3 I 5, I 5 =, I 6 = I 5 I 7, I7 = sl4 EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 7 I LowPss C Ldder Filter Signl Flowgrph = in 2, I 2 2 = sc, 3 = 2 4 I I =, 5 = 4 6, 6 = sc 3 sc 5 o = 6 3 I =, I 2 = I I 3, I3 = sl2 5 6 I 4 = I 3 I 5, I 5 =, I 6 = I 5 I 7, I7 = sl4 in 2 sc sl2 sc3 sl4 sc5 I o I3 I4 I 5 I 6 I 7 SFG EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 8
5 LowPss C Ldder Filter Signl Flowgrph in I L2 I3 L4 I 5 C C3 C5 I 2 I4 I 6 I 7 in 2 sc sl2 sc3 sl4 sc5 o I I 2 I3 I4 I 5 I 6 I 7 SFG EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 9 in 2 sc I LowPss C Ldder Filter Normlize I sl2 sc3 sl4 sc5 o I 3 I4 I 5 I 6 I 7 in * R * * R R sc * R sc * sl 3R sl sc * 2 4 5R o * R 7 EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 0
6 in * R LowPss C Ldder Filter Synthesize * * R R sc * R sc * sl 3R sl sc * 2 4 5R o * R 7 in * R sτ 2 sτ sτ 3 sτ 4 sτ 5 * R 3 5 EECS 247 Lecture 4: Active Filters 2007 H.K. Pge LowPss C Ldder Filter Integrtor Bsed Implementtion in * R sτ 2 sτ sτ 3 sτ 4 sτ 5 * R 3 * L2 * * L4 * * = C.R, 2 = = C.R, C.R, C.R, C.R * 2 3 = 3 4 = = * 4 5 = 5 R R τ τ τ τ τ 5 Building Block: RC Integrtor 2 = src EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 2
7 Negtive Resistors o 2 o 2 o 2 EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 3 Integrtor Bsed Implementtion of LP Ldder Filter Synthesize EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 4
8 Frequency Response MHz 0MHz EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 5 Scle Node oltges Scle by fctor s EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 6
9 Node Scling 2 3 X.2 X.2 X.2/.6 X /.2 X.6/.2 4 X.6 5 X.8 X.8/2 X.8/.6 X.6/.8 X 2/.8 O X 2 EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 7 Mximizing Signl Hndling by Node oltge Scling Before Node Scling After Node Scling Scle by fctor s EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 8
10 Filter Noise Totl the output:.4 μ rms (noiseless opmps) Tht s excellent, but the cpcitors re very lrge (nd the resistors smll high power dissiption). Not possible to integrte. Suppose our ppliction llows higher noise in the order of 40 μ rms EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 9 Scle to Meet Noise Trget Scle cpcitors nd resistors to meet noise objective s = 0 4 Noise: 4 μ rms (noiseless opmps) EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 20
11 Completed Design th order ldder filter Finl design utilizing: Node scling Finl R & C scling bsed on noise considertions 5 4 EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 2 Sensitivity C mde (rbitrrily) 50% (!) lrger thn its nominl vlue 0.5 db error t bnd edge 3.5 db error in stopbnd Looks like very low sensitivity EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 22
12 Differentil 5 th Order Lowpss Filter in Since ech signl nd its inverse redily vilble, elimintes the need for negtive resistors! Differentil design hs the dvntge of even order hrmonic distortion components nd common mode spurious pickup utomticlly cncels Disdvntge: Double resistor nd cpcitor re! EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 23 C Ldder Filters Including Trnsmission Zeros All poles in C L2 C3 L4 C5 Poles & Zeros C2 C4 C6 in C L2 C3 L4 C5 L6 C7 EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 24
13 C Ldder Filter Design Exmple Design bsebnd filter for CDMA IS95 cellulr phone receive pth with the following specs. Filter frequency msk shown on the next pge Allow enough mrgin for mnufcturing vritions Assume pssbnd mgnitude vrition of.8db Assume the 3dB frequency cn vry by 8% due to mnufcturing tolernces & circuit inccurcies Assume ny phse impirment cn be compensted in the digitl domin * Note this is the sme exmple s for cscde of biqud while the specifictions re given closer to rel product cse EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 25 C Ldder Filter Design Exmple CDMA IS95 Receive Filter Frequency Msk 0 Mgnitude (db) k 700k 900k.2M Frequency [Hz] EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 26
14 C Ldder Filter Design Exmple: CDMA IS95 Receive Filter Since phse impirment cn be corrected for, use filter type with mx. rolloff slope/pole Filter type Elliptic Design filter freq. response to fll well within the freq. msk Allow mrgin for component vritions & mismtches For the pssbnd ripple, llow enough mrgin for ripple chnge due to component & temperture vritions Design nominl pssbnd ripple of 0.2dB For stopbnd rejection dd few db mrgin 445=49dB Finl design specifictions: fpss = 650 khz Rpss = 0.2 db fstop = 750 khz top = 49 db Use Mtlb or filter tbles to decide the min. order for the filter (sme s cscded biqud exmple) 7 th Order Elliptic EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 27 C LowPss Ldder Filter Design Exmple: CDMA IS95 Receive Filter 7 th order Elliptic C2 C4 C6 in C L2 C3 L4 C5 L6 C7 Use filter tbles to determine LC vlues EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 28
15 C Ldder Filter Design Exmple: CDMA IS95 Receive Filter Specifictions fpss = 650 khz Rpss = 0.2 db fstop = 750 khz top = 49 db Use filter tbles to determine LC vlues Tble from: A. Zverev, Hndbook of filter synthesis, Wiley, 967 Elliptic filters tbulted wrt reflection coeficient ρ Rpss= 0 log( ρ 2 ) Since Rpss=0.2dB ρ =20% Use tble ccordingly EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 29 C Ldder Filter Design Exmple: CDMA IS95 Receive Filter Tble from Zverev book pge #28 & 282: Since our spec. is Amin=44dB dd 5dB mrgin & design for Amin=49dB EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 30
16 Tble from Zverev pge #28 & 282: Normlized component vlues: C=.7677 C2= L2=.9467 C3=.534 C4=.0098 L4= C5= C6=0.72 L6= C7= EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 3 C Filter Frequency Response Frequency msk superimposed Frequency response well within spec. Mgnitude (db) Frequency [khz] EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 32
17 Pssbnd Detil Pssbnd well within spec Mgnitude (db) Frequency [khz] EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 33 C Ldder Filter Sensitivity The design hs the sme specifictions s the previous exmple implemented with cscded biquds To compre the sensitivity of C ldder versus cscdedbiquds: Chnged ll Ls &Cs one by one by 2% in order to chnge the pole/zeros by % (similr test s for cscded biqud) Found frequency response most sensitive to L4 vritions Note tht by vrying L4 both poles & zeros re vried EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 34
18 RCL Ldder Filter Sensitivity Component mismtch in C filter: Increse L4 from its nominl vlue by 2% Decrese L4 by 2% Mgnitude (db) L4 nom L4 low L4 high Frequency [khz] EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 35 RCL Ldder Filter Sensitivity 5 0.2dB 5 Mgnitude (db) dB Frequency [khz] EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 36
19 Sensitivity of Cscde of Biquds Component mismtch in Biqud 4 (highest Q pole): Increse ω p4 by % Decrese ω z4 by % 2.2dB Mgnitude (db) dB kHz 600kHz Frequency [Hz] MHz High Q poles High sensitivity in Biqud reliztions EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 37 Sensitivity Comprison for CscdedBiquds versus C Ldder 7 th Order elliptic filter % chnge in pole & zero pir Pssbnd devition Stopbnd devition Cscded Biqud 2.2dB (29%) 3dB (40%) C Ldder 0.2dB (2%).7dB (2%) Doubly terminted LC ldder filters Significntly lower sensitivity compred to cscdedbiquds prticulrly within the pssbnd EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 38
20 7 th order Elliptic C Ldder Filter Design Exmple: CDMA IS95 Receive Filter C2 C4 C6 in C L2 C3 L4 C5 L6 C7 Previously lerned to design integrtor bsed ldder filters without trnsmission zeros Question: o How do we implement the trnsmission zeros in the integrtorbsed version? o Preferred method no extr power dissiption no ctive elements EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 39 Integrtor Bsed Ldder Filters How Do to Implement Trnsmission zeros? C in I 2 3 L2 I 3 C I 2 I 4 4 C3 I 5 Use KCL & KL to derive : I I I3 IC I 2 2 = I I3 I C, IC = ( 2 4) s C, 2 =, sc 2 = sc Substituting for IC nd rerrnging : I I3 C 2 = s 4 ( C C ) C C EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 40
21 Integrtor Bsed Ldder Filters How Do to Implement Trnsmission zeros? C in I 2 3 L2 I 3 C I 2 I 4 4 C3 I 5 Use KCL & KL to derive : I I C 3 2 = 4 s( C C ) C C I3 I5 C 4 = s 2 ( C 3 C ) C 3 C Frequency independent constnts Cn be substituted by: oltgecontrolled oltge Source EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 4 Integrtor Bsed Ldder Filters Trnsmission zeros C in I 2 3 L2 I 3 C C I 2 4 I 5 ( ) ( C 3 C ) C 4 C C C I 4 2 C 3 C Replce shunt cpcitors with voltge controlled voltge sources: I I3 C 2 = s 4 ( C C ) C C I3 I5 C 4 = s 2 ( C 3 C ) C 3 C EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 42
22 3 rd Order Lowpss Filter All Poles & No Zeros in I 2 3 L2 I 3 C I2 I 4 4 C 3 I 5 in 2 sc 3 4 sl2 sc 3 o I I 2 I 3 I 4 EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 43 in Trnsmission Zero Implementtion W/O Use of Active Elements I I 5 L2 I 3 ( C C ) ( C 3 C ) C C 4 C C I 2 I 2 4 C 3 C C C C C C 3 C in s C C sl2 s( C3 C) ( ) I I 2 I 3 I 4 o EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 44
23 Integrtor Bsed Ldder Filters Higher Order Trnsmission zeros 2 C 4 C b 6 Convert zero generting Cs in C loops to voltgecontrolled voltge sources C C ( ) ( ) C C C 3 C C b C C 4 C C 2 C C 3 C b 6 C 3 C b C 5 6 ( C 5 C b) C b 4 C 3 C b EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 45 in in 2 * R s( C C ) R * Higher Order Trnsmission zeros I I 7 I L2 I 3 I L4 4 ( C C ) ( C 3 C C b) ( C 5 C b) C C 2 C 4 C C C C I 3 b 4 C C 2 I 6 5 C b b 6 C 3 C b C C C b C C C C 3 C C 3 C b b C 5 C b * R * R sr * sl2 ( C3 C Cb) sl4 sr * C C ( 5 b ) EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 46 o * R 7
24 Exmple: 5 th Order Chebyshev II Filter 5 th order Chebyshev II Tble from: Willims & Tylor book, p..2 50dB stopbnd ttenution f 3dB =0MHz EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 47 Reliztion with Integrtor C = sc C R i 2 3 ( ) * C C R* EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 48
25 5 th Order Butterworth Filter 2 From: Lecture 4 pge EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 49 5 th Order Chebyshev II Filter OpmpRC Simultion EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 50
26 in 7th Order Differentil Lowpss Filter Including Trnsmission Zeros Trnsmission zeros implemented with pir of coupling cpcitors EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 5 Effect of Integrtor NonIdelities on Filter Frequency Chrcteristics In the pssive filter design (C filters) section: Rective element (L & C) nonidelities expressed in the form of Qulity Fctor (Q) Filter impirments due to component nonidelities explined in terms of component Q In the context of ctive filter design (integrtorbsed filters) Integrtor nonidelities Trnslted to hve form of Qulity Fctor (Q) Filter impirments due to integrtor nonidelities explined in terms of integrtor Q EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 52
27 Effect of Integrtor NonIdelities on Filter Performnce Idel integrtor chrcteristics Rel integrtor chrcteristics: Effect of opmp finite DC gin Effect of integrtor nondominnt poles EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 53 Effect of Integrtor NonIdelities on Filter Performnce Idel Integrtor C R in Idel opmp DC gin= Single DC no nondominnt poles ω H(s) = o s ωo = / RC 0dB ψ 90 o Idel Idel Intg. Intg. log H ( s) ω 0 EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 54
28 Idel Integrtor Qulity Fctor Idel intg. trnsfer function: Since component Q is defined s:: ωo ωo H(s) = = = s jω ω j ωo H Q ( jω ) = R( ω) jx( ω) X ( ω) = R ( ω) Then: intg. Q idel = EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 55 Rel Integrtor NonIdelities Idel Intg. log H ( s) Rel Intg. log H ( s) ω 0 ω P = 0 ω 0 P2P3 ψ ψ 90 o 90 o ωo H(s) = H(s) s s s ( s o )( p2)( ω p3)... EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 56
29 Effect of Integrtor Finite DC Gin on Q log H ( s) ψ ω P = 0 ω ω o ω π ArctnP 2 ωo P Phse ω ω o o (in rdin) 90 o Exmple: P/ ω 0 = /00 phse error 0.5degree EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 57 Effect of Integrtor Finite DC Gin on Q Idel intg Intg with finite DC gin Phse ω 0 Droop in the pssbnd Mgnitude (db) Droop in the pssbnd Normlized Frequency EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 58
30 Effect of Integrtor NonDominnt Poles log H ( s) ψ ω 0 P2P ω o ω ω π Arctn o 2 p i= 2 i ωo Phse ω p o i= 2 i (in rdin) 90 o Exmple: ω 0 /P2 =/00 phse error 0.5degree EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 59 Effect of Integrtor NonDominnt Poles Idel intg Opmp with finite bndwidth Mgnitude (db) Peking in the pssbnd Phse ω 0 Peking in the pssbnd In extreme cses could result in oscilltion! Normlized Frequency EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 60
31 Effect of Integrtor NonDominnt Poles & Finite DC Gin on Q log H ( s ) ω P = 0 ψ ω 0 P2P3 ω o ω π Arctn 2 P ωo ω Arctn o p 90 i = 2 i 90 o Note tht the two terms hve different signs Cn cncel ech other s effect! EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 6 Integrtor Qulity Fctor Rel intg. trnsfer function: Bsed on the definition of Q nd ssuming tht: H(s) s... ( s s )( p2)( ω p3) o ωo << & >> p 2,3,... It cn be shown tht in the vicinity of unityginfrequency: Q intg. rel ω o i= 2 p i Phse ω 0 Phse ω 0 EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 62
32 Exmple: Effect of Integrtor Finite Q on Bndpss Filter Behvior 0.5 ο φ ω o intg 0.5 ο φ ω o intg Idel Idel Integrtor DC gin=00 Integrtor 00.ω o EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 63 Exmple: Effect of Integrtor Q on Filter Behvior ( 0.5 ο φ led 0.5 ο φ excess ω o intg φ ω o intg ~ 0 Idel Integrtor DC gin=00 & 00. ω ο EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 64
33 Summry Effect of Integrtor NonIdelities on Q Q intg. idel = Q intg. rel ω o p i= 2 i Amplifier DC gin reduces the overll Q in the sme mnner s series/prllel resistnce ssocited with pssive elements Amplifier poles locted bove integrtor unitygin frequency enhnce the Q! If nondominnt poles close to unitygin freq. Oscilltion Depending on the loction of unityginfrequency, the two terms cn cncel ech other out! EECS 247 Lecture 4: Active Filters 2007 H.K. Pge 65
EE247 Administrative
EE47 Administrtive Finl exm group hs een chnged to group 3 Finl exm new dte/time Dec. 3 th, 5pm to 8pm Homework # hs een posted on course wesite nd is due Sept th (next Thurs.) Sumissions cn e on pper
More informationIntegrator Based Filters
Integrator Based Filters Main building block for this category of filters integrator By using signal flowgraph techniques conventional filter topologies can be converted to integrator based type filters
More informationEE247 Lecture 3. Signal flowgraph concept First order integrator based filter Second order integrator based filter & biquads
Summary last week EE47 Lecture 3 Integrator based filters Signal flowgraph concept First order integrator based filter Second order integrator based filter & biquads High order & high Q filters Cascaded
More information2 DIODE CLIPPING and CLAMPING CIRCUITS
2 DIODE CLIPPING nd CLAMPING CIRCUITS 2.1 Ojectives Understnding the operting principle of diode clipping circuit Understnding the operting principle of clmping circuit Understnding the wveform chnge of
More informationEE247 Administrative. EE247 Course Reading Material
EE47 Administrative Due to office hour conflict with EE4 class: New office hours: Tues: 4 to 5pm (same as before) Wed.: :3 to :3am (new) Thurs.: no office hours Office hours held @ 567 Cory Hall EECS 47
More informationTwo hours UNIVERSITY OF MANCHESTER SCHOOL OF COMPUTER SCIENCE. Date: Friday 16 th May 2008. Time: 14:00 16:00
COMP20212 Two hours UNIVERSITY OF MANCHESTER SCHOOL OF COMPUTER SCIENCE Digitl Design Techniques Dte: Fridy 16 th My 2008 Time: 14:00 16:00 Plese nswer ny THREE Questions from the FOUR questions provided
More informationEconomics Letters 65 (1999) 9 15. macroeconomists. a b, Ruth A. Judson, Ann L. Owen. Received 11 December 1998; accepted 12 May 1999
Economics Letters 65 (1999) 9 15 Estimting dynmic pnel dt models: guide for q mcroeconomists b, * Ruth A. Judson, Ann L. Owen Federl Reserve Bord of Governors, 0th & C Sts., N.W. Wshington, D.C. 0551,
More informationSpace Vector Pulse Width Modulation Based Induction Motor with V/F Control
Interntionl Journl of Science nd Reserch (IJSR) Spce Vector Pulse Width Modultion Bsed Induction Motor with V/F Control Vikrmrjn Jmbulingm Electricl nd Electronics Engineering, VIT University, Indi Abstrct:
More informationVersion 001 CIRCUITS holland (1290) 1
Version CRCUTS hollnd (9) This printout should hve questions Multiplechoice questions my continue on the next column or pge find ll choices efore nswering AP M 99 MC points The power dissipted in wire
More informationTunable Active DualBand Bandpass Filter Design Using MMIC Technology
Interntionl Journl of Engineering & Technology IJETIJENS Vol: 11 No: 1 11 Tunle Active DulBnd Bndpss Filter Design Using MMIC Technology A. Alhyri 1, A.Hizdeh, M. Dousti 3 1 Islmic Azd University Broujerd
More informationGraphs on Logarithmic and Semilogarithmic Paper
0CH_PHClter_TMSETE_ 3//00 :3 PM Pge Grphs on Logrithmic nd Semilogrithmic Pper OBJECTIVES When ou hve completed this chpter, ou should be ble to: Mke grphs on logrithmic nd semilogrithmic pper. Grph empiricl
More informationDispersion in Coaxial Cables
Dispersion in Coxil Cbles Steve Ellingson June 1, 2008 Contents 1 Summry 2 2 Theory 2 3 Comprison to Welch s Result 4 4 Findings for RG58 t LWA Frequencies 5 Brdley Dept. of Electricl & Computer Engineering,
More informationThe Velocity Factor of an Insulated TwoWire Transmission Line
The Velocity Fctor of n Insulted TwoWire Trnsmission Line Problem Kirk T. McDonld Joseph Henry Lbortories, Princeton University, Princeton, NJ 08544 Mrch 7, 008 Estimte the velocity fctor F = v/c nd the
More informationSPARK QUENCHERS EFFECT OF SPARK QUENCHER
Sprk Quenchers re esily selectble electronic components designed to prevent or substntilly minimize the occurrence of rcing nd noise genertion in rely nd switch contcts. EFFECT OF SPARK QUENCHER Arc suppression
More informationAll pay auctions with certain and uncertain prizes a comment
CENTER FOR RESEARC IN ECONOMICS AND MANAGEMENT CREAM Publiction No. 12015 All py uctions with certin nd uncertin prizes comment Christin Riis All py uctions with certin nd uncertin prizes comment Christin
More informationBKW, BKDW. 1 Technical description
, BKDW 1 Technicl description Rective power compenstors re designed for compensting rective power (improving power coefficient cos? ) in low voltge networks in industril sites nd division sttions.in the
More informationBinary Representation of Numbers Autar Kaw
Binry Representtion of Numbers Autr Kw After reding this chpter, you should be ble to: 1. convert bse rel number to its binry representtion,. convert binry number to n equivlent bse number. In everydy
More information4 ChopperControlled DC Motor Drive
4 ChopperControlled DC Motor Drive Chopper: The vrible dc voltge is controlled by vrying the on nd offtimes of converter. Fig. 4.1 is schemtic digrm of the chopper. Its frequency of opertion is f 1
More informationMathematics. Vectors. hsn.uk.net. Higher. Contents. Vectors 128 HSN23100
hsn.uk.net Higher Mthemtics UNIT 3 OUTCOME 1 Vectors Contents Vectors 18 1 Vectors nd Sclrs 18 Components 18 3 Mgnitude 130 4 Equl Vectors 131 5 Addition nd Subtrction of Vectors 13 6 Multipliction by
More informationMATH 150 HOMEWORK 4 SOLUTIONS
MATH 150 HOMEWORK 4 SOLUTIONS Section 1.8 Show tht the product of two of the numbers 65 1000 8 2001 + 3 177, 79 1212 9 2399 + 2 2001, nd 24 4493 5 8192 + 7 1777 is nonnegtive. Is your proof constructive
More informationMath 135 Circles and Completing the Square Examples
Mth 135 Circles nd Completing the Squre Exmples A perfect squre is number such tht = b 2 for some rel number b. Some exmples of perfect squres re 4 = 2 2, 16 = 4 2, 169 = 13 2. We wish to hve method for
More informationHelicopter Theme and Variations
Helicopter Theme nd Vritions Or, Some Experimentl Designs Employing Pper Helicopters Some possible explntory vribles re: Who drops the helicopter The length of the rotor bldes The height from which the
More informationPolynomial Functions. Polynomial functions in one variable can be written in expanded form as ( )
Polynomil Functions Polynomil functions in one vrible cn be written in expnded form s n n 1 n 2 2 f x = x + x + x + + x + x+ n n 1 n 2 2 1 0 Exmples of polynomils in expnded form re nd 3 8 7 4 = 5 4 +
More informationTreatment Spring Late Summer Fall 0.10 5.56 3.85 0.61 6.97 3.01 1.91 3.01 2.13 2.99 5.33 2.50 1.06 3.53 6.10 Mean = 1.33 Mean = 4.88 Mean = 3.
The nlysis of vrince (ANOVA) Although the ttest is one of the most commonly used sttisticl hypothesis tests, it hs limittions. The mjor limittion is tht the ttest cn be used to compre the mens of only
More informationRotating DC Motors Part II
Rotting Motors rt II II.1 Motor Equivlent Circuit The next step in our consiertion of motors is to evelop n equivlent circuit which cn be use to better unerstn motor opertion. The rmtures in rel motors
More informationEngineertoEngineer Note
EngineertoEngineer Note EE265 Technicl notes on using Anlog Devices DSPs, processors nd development tools Contct our technicl support t dsp.support@nlog.com nd t dsptools.support@nlog.com Or visit our
More informationProject 6 Aircraft static stability and control
Project 6 Aircrft sttic stbility nd control The min objective of the project No. 6 is to compute the chrcteristics of the ircrft sttic stbility nd control chrcteristics in the pitch nd roll chnnel. The
More informationwww.mathsbox.org.uk e.g. f(x) = x domain x 0 (cannot find the square root of negative values)
www.mthsbo.org.uk CORE SUMMARY NOTES Functions A function is rule which genertes ectl ONE OUTPUT for EVERY INPUT. To be defined full the function hs RULE tells ou how to clculte the output from the input
More informationEcon 4721 Money and Banking Problem Set 2 Answer Key
Econ 472 Money nd Bnking Problem Set 2 Answer Key Problem (35 points) Consider n overlpping genertions model in which consumers live for two periods. The number of people born in ech genertion grows in
More informationExample 27.1 Draw a Venn diagram to show the relationship between counting numbers, whole numbers, integers, and rational numbers.
2 Rtionl Numbers Integers such s 5 were importnt when solving the eqution x+5 = 0. In similr wy, frctions re importnt for solving equtions like 2x = 1. Wht bout equtions like 2x + 1 = 0? Equtions of this
More informationUnderstanding Basic Analog Ideal Op Amps
Appliction Report SLAA068A  April 2000 Understnding Bsic Anlog Idel Op Amps Ron Mncini Mixed Signl Products ABSTRACT This ppliction report develops the equtions for the idel opertionl mplifier (op mp).
More informationExperiment 6: Friction
Experiment 6: Friction In previous lbs we studied Newton s lws in n idel setting, tht is, one where friction nd ir resistnce were ignored. However, from our everydy experience with motion, we know tht
More informationWeek 11  Inductance
Week  Inductnce November 6, 202 Exercise.: Discussion Questions ) A trnsformer consists bsiclly of two coils in close proximity but not in electricl contct. A current in one coil mgneticlly induces n
More informationReasoning to Solve Equations and Inequalities
Lesson4 Resoning to Solve Equtions nd Inequlities In erlier work in this unit, you modeled situtions with severl vriles nd equtions. For exmple, suppose you were given usiness plns for concert showing
More informationUse Geometry Expressions to create a more complex locus of points. Find evidence for equivalence using Geometry Expressions.
Lerning Objectives Loci nd Conics Lesson 3: The Ellipse Level: Preclculus Time required: 120 minutes In this lesson, students will generlize their knowledge of the circle to the ellipse. The prmetric nd
More informationProject Recovery. . It Can Be Done
Project Recovery. It Cn Be Done IPM Conference Wshington, D.C. Nov 47, 200 Wlt Lipke Oklhom City Air Logistics Center Tinker AFB, OK Overview Mngement Reserve Project Sttus Indictors Performnce Correction
More informationAssuming all values are initially zero, what are the values of A and B after executing this Verilog code inside an always block? C=1; A <= C; B = C;
B26 Appendix B The Bsics of Logic Design Check Yourself ALU n [Arthritic Logic Unit or (rre) Arithmetic Logic Unit] A rndomnumer genertor supplied s stndrd with ll computer systems Stn KellyBootle,
More information9 CONTINUOUS DISTRIBUTIONS
9 CONTINUOUS DISTIBUTIONS A rndom vrible whose vlue my fll nywhere in rnge of vlues is continuous rndom vrible nd will be ssocited with some continuous distribution. Continuous distributions re to discrete
More informationSolenoid Operated Proportional Directional Control Valve (with Pressure Compensation, Multiple Valve Series)
Solenoid Operted Proportionl Directionl Control Vlve (with Pressure Compenstion, Multiple Vlve Series) Hydrulic circuit (Exmple) v Fetures hese stcking type control vlves show pressure compensted type
More informationMA 15800 Lesson 16 Notes Summer 2016 Properties of Logarithms. Remember: A logarithm is an exponent! It behaves like an exponent!
MA 5800 Lesson 6 otes Summer 06 Rememer: A logrithm is n eponent! It ehves like n eponent! In the lst lesson, we discussed four properties of logrithms. ) log 0 ) log ) log log 4) This lesson covers more
More informationFactoring Polynomials
Fctoring Polynomils Some definitions (not necessrily ll for secondry school mthemtics): A polynomil is the sum of one or more terms, in which ech term consists of product of constnt nd one or more vribles
More informationNetwork Configuration Independence Mechanism
3GPP TSG SA WG3 Security S3#19 S3010323 36 July, 2001 Newbury, UK Source: Title: Document for: AT&T Wireless Network Configurtion Independence Mechnism Approvl 1 Introduction During the lst S3 meeting
More information5.2. LINE INTEGRALS 265. Let us quickly review the kind of integrals we have studied so far before we introduce a new one.
5.2. LINE INTEGRALS 265 5.2 Line Integrls 5.2.1 Introduction Let us quickly review the kind of integrls we hve studied so fr before we introduce new one. 1. Definite integrl. Given continuous relvlued
More informationUNIVERSITY OF NOTTINGHAM. Discussion Papers in Economics STRATEGIC SECOND SOURCING IN A VERTICAL STRUCTURE
UNVERSTY OF NOTTNGHAM Discussion Ppers in Economics Discussion Pper No. 04/15 STRATEGC SECOND SOURCNG N A VERTCAL STRUCTURE By Arijit Mukherjee September 004 DP 04/15 SSN 10438 UNVERSTY OF NOTTNGHAM Discussion
More informationModule 2. Analysis of Statically Indeterminate Structures by the Matrix Force Method. Version 2 CE IIT, Kharagpur
Module Anlysis of Stticlly Indeterminte Structures by the Mtrix Force Method Version CE IIT, Khrgpur esson 9 The Force Method of Anlysis: Bems (Continued) Version CE IIT, Khrgpur Instructionl Objectives
More informationThreephase Active Power Filter for Power Quality: Compensation and Balancing
1 Threephse Active Power Filter for Power Qulity: Compenstion nd Blncing C. G. Binchin, Electronic System Division, LACTEC, R. Demonti, Electronic System Division, LACTEC nd J. S. Omori, Prnense Electic
More informationDouble Integrals over General Regions
Double Integrls over Generl egions. Let be the region in the plne bounded b the lines, x, nd x. Evlute the double integrl x dx d. Solution. We cn either slice the region verticll or horizontll. ( x x Slicing
More informationLectures 8 and 9 1 Rectangular waveguides
1 Lectures 8 nd 9 1 Rectngulr wveguides y b x z Consider rectngulr wveguide with 0 < x b. There re two types of wves in hollow wveguide with only one conductor; Trnsverse electric wves
More informationLecture 3 Gaussian Probability Distribution
Lecture 3 Gussin Probbility Distribution Introduction l Gussin probbility distribution is perhps the most used distribution in ll of science. u lso clled bell shped curve or norml distribution l Unlike
More informationCS99S Laboratory 2 Preparation Copyright W. J. Dally 2001 October 1, 2001
CS99S Lortory 2 Preprtion Copyright W. J. Dlly 2 Octoer, 2 Ojectives:. Understnd the principle of sttic CMOS gte circuits 2. Build simple logic gtes from MOS trnsistors 3. Evlute these gtes to oserve logic
More informationEnterprise Risk Management Software Buyer s Guide
Enterprise Risk Mngement Softwre Buyer s Guide 1. Wht is Enterprise Risk Mngement? 2. Gols of n ERM Progrm 3. Why Implement ERM 4. Steps to Implementing Successful ERM Progrm 5. Key Performnce Indictors
More informationAREA OF A SURFACE OF REVOLUTION
AREA OF A SURFACE OF REVOLUTION h cut r πr h A surfce of revolution is formed when curve is rotted bout line. Such surfce is the lterl boundr of solid of revolution of the tpe discussed in Sections 7.
More informationCOMPARISON OF SOME METHODS TO FIT A MULTIPLICATIVE TARIFF STRUCTURE TO OBSERVED RISK DATA BY B. AJNE. Skandza, Stockholm ABSTRACT
COMPARISON OF SOME METHODS TO FIT A MULTIPLICATIVE TARIFF STRUCTURE TO OBSERVED RISK DATA BY B. AJNE Skndz, Stockholm ABSTRACT Three methods for fitting multiplictive models to observed, crossclssified
More information15.6. The mean value and the rootmeansquare value of a function. Introduction. Prerequisites. Learning Outcomes. Learning Style
The men vlue nd the rootmensqure vlue of function 5.6 Introduction Currents nd voltges often vry with time nd engineers my wish to know the verge vlue of such current or voltge over some prticulr time
More informationAn Undergraduate Curriculum Evaluation with the Analytic Hierarchy Process
An Undergrdute Curriculum Evlution with the Anlytic Hierrchy Process Les Frir Jessic O. Mtson Jck E. Mtson Deprtment of Industril Engineering P.O. Box 870288 University of Albm Tuscloos, AL. 35487 Abstrct
More informationStraight pipe model. Orifice model. * Please refer to Page 3~7 Reference Material for the theoretical formulas used here. Qa/Qw=(ηw/ηa) (P1+P2)/(2 P2)
Air lek test equivlent to IX7nd IX8 In order to perform quntittive tests Fig. shows the reltionship between ir lek mount nd wter lek mount. Wter lek mount cn be converted into ir lek mount. By performing
More informationExample A rectangular box without lid is to be made from a square cardboard of sides 18 cm by cutting equal squares from each corner and then folding
1 Exmple A rectngulr box without lid is to be mde from squre crdbord of sides 18 cm by cutting equl squres from ech corner nd then folding up the sides. 1 Exmple A rectngulr box without lid is to be mde
More informationRate and Activation Energy of the Iodination of Acetone
nd Activtion Energ of the Iodintion of Acetone rl N. eer Dte of Eperiment: //00 Florence F. Ls (prtner) Abstrct: The rte, rte lw nd ctivtion energ of the iodintion of cetone re detered b observing the
More informationORBITAL MANEUVERS USING LOWTHRUST
Proceedings of the 8th WSEAS Interntionl Conference on SIGNAL PROCESSING, ROBOICS nd AUOMAION ORBIAL MANEUVERS USING LOWHRUS VIVIAN MARINS GOMES, ANONIO F. B. A. PRADO, HÉLIO KOII KUGA Ntionl Institute
More informationLecture 9 Microwave Network Analysis A. Nassiri  ANL June 19, 2003. Microwave Physics and Techniques UCSB June 2003 1
Lecture 9 Microwve Network nlysis. Nssiri  NL June 9, 003 Microwve Physics nd Techniques UC June 003 Prmeter Mesurement Technique VVM: The vector voltmeter mesures the mgnitude of reference nd test voltge
More informationMechanics Cycle 1 Chapter 5. Chapter 5
Chpter 5 Contct orces: ree Body Digrms nd Idel Ropes Pushes nd Pulls in 1D, nd Newton s Second Lw Neglecting riction ree Body Digrms Tension Along Idel Ropes (i.e., Mssless Ropes) Newton s Third Lw Bodies
More informationOperations with Polynomials
38 Chpter P Prerequisites P.4 Opertions with Polynomils Wht you should lern: Write polynomils in stndrd form nd identify the leding coefficients nd degrees of polynomils Add nd subtrct polynomils Multiply
More informationPlotting and Graphing
Plotting nd Grphing Much of the dt nd informtion used by engineers is presented in the form of grphs. The vlues to be plotted cn come from theoreticl or empiricl (observed) reltionships, or from mesured
More informationAnswer, Key Homework 10 David McIntyre 1
Answer, Key Homework 10 Dvid McIntyre 1 This printout should hve 22 questions, check tht it is complete. Multiplechoice questions my continue on the next column or pge: find ll choices efore mking your
More informationPHY 222 Lab 8 MOTION OF ELECTRONS IN ELECTRIC AND MAGNETIC FIELDS
PHY 222 Lb 8 MOTION OF ELECTRONS IN ELECTRIC AND MAGNETIC FIELDS Nme: Prtners: INTRODUCTION Before coming to lb, plese red this pcket nd do the prelb on pge 13 of this hndout. From previous experiments,
More information4. DC MOTORS. Understand the basic principles of operation of a DC motor. Understand the operation and basic characteristics of simple DC motors.
4. DC MOTORS Almost every mechnicl movement tht we see round us is ccomplished by n electric motor. Electric mchines re mens o converting energy. Motors tke electricl energy nd produce mechnicl energy.
More informationEQUATIONS OF LINES AND PLANES
EQUATIONS OF LINES AND PLANES MATH 195, SECTION 59 (VIPUL NAIK) Corresponding mteril in the ook: Section 12.5. Wht students should definitely get: Prmetric eqution of line given in pointdirection nd twopoint
More informationOr more simply put, when adding or subtracting quantities, their uncertainties add.
Propgtion of Uncertint through Mthemticl Opertions Since the untit of interest in n eperiment is rrel otined mesuring tht untit directl, we must understnd how error propgtes when mthemticl opertions re
More informationCHAPTER 11 Numerical Differentiation and Integration
CHAPTER 11 Numericl Differentition nd Integrtion Differentition nd integrtion re bsic mthemticl opertions with wide rnge of pplictions in mny res of science. It is therefore importnt to hve good methods
More information, and the number of electrons is 19. e e 1.60 10 C. The negatively charged electrons move in the direction opposite to the conventional current flow.
Prolem 1. f current of 80.0 ma exists in metl wire, how mny electrons flow pst given cross section of the wire in 10.0 min? Sketch the directions of the current nd the electrons motion. Solution: The chrge
More informationVendor Rating for Service Desk Selection
Vendor Presented By DATE Using the scores of 0, 1, 2, or 3, plese rte the vendor's presenttion on how well they demonstrted the functionl requirements in the res below. Also consider how efficient nd functionl
More informationSTATUS OF LANDBASED WIND ENERGY DEVELOPMENT IN GERMANY
Yer STATUS OF LANDBASED WIND ENERGY Deutsche WindGurd GmbH  Oldenburger Strße 6526316 Vrel  Germny +49 (4451)/9515  info@windgurd.de  www.windgurd.com Annul Added Cpcity [MW] Cumultive Cpcity [MW]
More informationWarmup for Differential Calculus
Summer Assignment Wrmup for Differentil Clculus Who should complete this pcket? Students who hve completed Functions or Honors Functions nd will be tking Differentil Clculus in the fll of 015. Due Dte:
More informationRedistributing the Gains from Trade through Nonlinear. Lumpsum Transfers
Redistributing the Gins from Trde through Nonliner Lumpsum Trnsfers Ysukzu Ichino Fculty of Economics, Konn University April 21, 214 Abstrct I exmine lumpsum trnsfer rules to redistribute the gins from
More informationSection 5.2, Commands for Configuring ISDN Protocols. Section 5.3, Configuring ISDN Signaling. Section 5.4, Configuring ISDN LAPD and Call Control
Chpter 5 Configurtion of ISDN Protocols This chpter provides instructions for configuring the ISDN protocols in the SP201 for signling conversion. Use the sections tht reflect the softwre you re configuring.
More informationand thus, they are similar. If k = 3 then the Jordan form of both matrices is
Homework ssignment 11 Section 7. pp. 24925 Exercise 1. Let N 1 nd N 2 be nilpotent mtrices over the field F. Prove tht N 1 nd N 2 re similr if nd only if they hve the sme miniml polynomil. Solution: If
More informationClearPeaks Customer Care Guide. Business as Usual (BaU) Services Peace of mind for your BI Investment
ClerPeks Customer Cre Guide Business s Usul (BU) Services Pece of mind for your BI Investment ClerPeks Customer Cre Business s Usul Services Tble of Contents 1. Overview...3 Benefits of Choosing ClerPeks
More information2015 EDITION. AVMA Report on Veterinary Compensation
2015 EDITION AVMA Report on Veterinry Compenstion AVMA Report on Veterinry Compenstion 2015 EDITION Copyright 2015 by the All rights reserved. ISBN13: 9781882691319 AVMA Report on Veterinry Compenstion
More information2. Transaction Cost Economics
3 2. Trnsction Cost Economics Trnsctions Trnsctions Cn Cn Be Be Internl Internl or or Externl Externl n n Orgniztion Orgniztion Trnsctions Trnsctions occur occur whenever whenever good good or or service
More informationPulsedIV PulsedRF Measurements Using a Large Signal Network Analyzer
PulsedIV PulsedRF Mesurements Using Lrge Signl Network Anlyzer Seok Joo Doo*, Ptrick Roblin* #, Sunyoung Lee*, Dominique Chillot* + nd Mrc Vnden Bossche + *The Ohio Stte University, * + on leve from
More informationHomework #4: Answers. 1. Draw the array of world outputs that free trade allows by making use of each country s transformation schedule.
Text questions, Chpter 5, problems 15: Homework #4: Answers 1. Drw the rry of world outputs tht free trde llows by mking use of ech country s trnsformtion schedule.. Drw it. This digrm is constructed
More informationBasic Analysis of Autarky and Free Trade Models
Bsic Anlysis of Autrky nd Free Trde Models AUTARKY Autrky condition in prticulr commodity mrket refers to sitution in which country does not engge in ny trde in tht commodity with other countries. Consequently
More informationEfficient loadbalancing routing for wireless mesh networks
Computer Networks 51 (007) 50 66 www.elsevier.com/locte/comnet Efficient lodblncing routing for wireless mesh networks Yigl Bejerno, SeungJe Hn b, *,1, Amit Kumr c Bell Lbortories, Lucent Technologies,
More informationAppendix D: Completing the Square and the Quadratic Formula. In Appendix A, two special cases of expanding brackets were considered:
Appendi D: Completing the Squre nd the Qudrtic Formul Fctoring qudrtic epressions such s: + 6 + 8 ws one of the topics introduced in Appendi C. Fctoring qudrtic epressions is useful skill tht cn help you
More informationRational Functions. Rational functions are the ratio of two polynomial functions. Qx bx b x bx b. x x x. ( x) ( ) ( ) ( ) and
Rtionl Functions Rtionl unctions re the rtio o two polynomil unctions. They cn be written in expnded orm s ( ( P x x + x + + x+ Qx bx b x bx b n n 1 n n 1 1 0 m m 1 m + m 1 + + m + 0 Exmples o rtionl unctions
More information4.5 Signal Flow Graphs
3/9/009 4_5 ignl Flow Grphs.doc / 4.5 ignl Flow Grphs Reding Assignment: pp. 8997 Q: Using individul device scttering prmeters to nlze comple microwve network results in lot of mess mth! Isn t there n
More informationAnalysis of Digital IIR Filter with LabVIEW
Anlysis of Digitl IIR Filter with LbVIEW Yduvir Singh Associte professor Thpr University, Ptil Punjb, Indi Swet Tripthi Assistnt professor Mewr University, Chittorgrh Rjsthn, Indi Mnoj Pndey Assistnt professor
More informationHillsborough Township Public Schools Mathematics Department Computer Programming 1
Essentil Unit 1 Introduction to Progrmming Pcing: 15 dys Common Unit Test Wht re the ethicl implictions for ming in tody s world? There re ethicl responsibilities to consider when writing computer s. Citizenship,
More informationTITLE THE PRINCIPLES OF COINTAP METHOD OF NONDESTRUCTIVE TESTING
TITLE THE PRINCIPLES OF COINTAP METHOD OF NONDESTRUCTIVE TESTING Sung Joon Kim*, DongChul Che Kore Aerospce Reserch Institute, 45 EoeunDong, YouseongGu, Dejeon, 35333, Kore Phone : 824286231 FAX
More informationVersion 001 Summer Review #03 tubman (IBII20142015) 1
Version 001 Summer Reiew #03 tubmn (IBII20142015) 1 This printout should he 35 questions. Multiplechoice questions my continue on the next column or pge find ll choices before nswering. Concept 20 P03
More informationWEB DELAY ANALYSIS AND REDUCTION BY USING LOAD BALANCING OF A DNSBASED WEB SERVER CLUSTER
Interntionl Journl of Computers nd Applictions, Vol. 9, No., 007 WEB DELAY ANALYSIS AND REDUCTION BY USING LOAD BALANCING OF A DNSBASED WEB SERVER CLUSTER Y.W. Bi nd Y.C. Wu Abstrct Bsed on our survey
More informationTo Hunt or to Scavenge: Competitive Advantage and Competitive Strategy in Platform Industries *
To Hunt or to Scvenge: Competitive dvntge nd Competitive Strtegy in Pltform Industries * Srit Mrkovich** IDC Hertzliy Johnnes Moenius*** University of Redlnds Mrch 0 BSTRCT Firms choose their competitive
More informationVectors 2. 1. Recap of vectors
Vectors 2. Recp of vectors Vectors re directed line segments  they cn be represented in component form or by direction nd mgnitude. We cn use trigonometry nd Pythgors theorem to switch between the forms
More informationHomework #6 Chapter 7 Homework Acids and Bases
Homework #6 Chpter 7 Homework Acids nd Bses 18. ) H O(l) H 3O (q) OH (q) H 3 O OH Or H O(l) H (q) OH (q) H OH ) HCN(q) H O(l) H 3O (q) CN (q) H 3 O HCN CN Or HCN(q) H (q) CN (q) H CN HCN c) NH 3(q) H O(l)
More informationModule Summary Sheets. C3, Methods for Advanced Mathematics (Version B reference to new book) Topic 2: Natural Logarithms and Exponentials
MEI Mthemtics in Ection nd Instry Topic : Proof MEI Structured Mthemtics Mole Summry Sheets C, Methods for Anced Mthemtics (Version B reference to new book) Topic : Nturl Logrithms nd Eponentils Topic
More informationDesign Example 1 Special Moment Frame
Design Exmple 1 pecil Moment Frme OVERVIEW tructurl steel specil moment frmes (MF) re typiclly comprised of wideflnge bems, columns, nd bemcolumn connections. Connections re proportioned nd detiled to
More informationLECTURE #05. Learning Objectives. How does atomic packing factor change with different atom types? How do you calculate the density of a material?
LECTURE #05 Chpter : Pcking Densities nd Coordintion Lerning Objectives es How does tomic pcking fctor chnge with different tom types? How do you clculte the density of mteril? 2 Relevnt Reding for this
More informationWhy is the NSW prison population falling?
NSW Bureu of Crime Sttistics nd Reserch Bureu Brief Issue pper no. 80 September 2012 Why is the NSW prison popultion flling? Jcqueline Fitzgerld & Simon Corben 1 Aim: After stedily incresing for more thn
More informationICL7136, ICL7137. 3 1 / 2 Digit LCD/LED Low Power Display A/D Converter with Overrange Recovery. Description. Features. Ordering Information
SEMICONDUCTOR ICL1, ICL13 Jnury 1994 3 1 / 2 Digit LCD/LED Low Power Disply A/D Converter with Overrnge Recovery Fetures First Reding Overrnge Recovery in One Conversion Period Gurnteed Zero Reding for
More informationObjectives: to get acquainted with active filter circuits and parameters, design methods, build and investigate active LPF, HPF and BPF.
Laboratory of the circuits and signals Laboratory work No. 4 ACTIVE FILTERS Objectives: to get acquainted with active filter circuits and parameters, design methods, build and investigate active LPF, HPF
More information