# Understanding ph management and plant nutrition Part 5: Choosing the best fertilizer

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2 Table 1. The amount of fertilizer required to obtain specific concentrations of nitrogen in the fertilizer solution. To convert to grams, multiply the value by 28. Amount of fertilizer (in ounces) per 100 gallons to get the desired nitrogen concentration Amount of fertilizer (in ounces) per 5 gallons to get the desired nitrogen concentration 100 ppm N 200 ppm N 300 ppm N 100 ppm N 200 ppm N 300 ppm N Ca Ca-1 Mg Ca-2 Mg Ca-1 Mg Ca-2 Mg Ca-3 Mg Ca-2 Mg To calculate the amount of fertilizer needed to get a specific nitrogen concentration Step #1 Multiply the desired nitrogen concentration (in ppm N) by the gallons of fertilizer you want. Step #2 Multiply the percent nitrogen in the formula by 75 Step #3 Divide the value from Step #1 by the value from Step #2. Example: How much do you need to add to 5 gallons to get a fertilizer solution with 100 ppm N Step #1 100 x 5 = 500 You need to add 0.33 ounces (about 9 grams) of added to 5 Step #2 20 x 75= 1,500 gallons of water to get a fertilizer solution with 100 ppm N. Step # ,500 = 0.33 For people who are only measuring out small quantities of fertilizer, 1 US teaspoon holds about 0.2 ounces (about 6 grams) of fertilizer. Below is the concentration of nitrogen (in ppm total nitrogen) obtained when mixing ¼, ½, 1, or 3 teaspoons into a gallon of water with different fertilizers. Amount of fertilizer added per gallon of solution ¼ teaspoon ½ teaspoon 1 teaspoon 3 teaspoon Ca Ca-1 Mg Ca-2 Mg Ca-1 Mg Ca-2 Mg Ca-3 Mg Ca-2 Mg charge, they can allow an electrical current to move through the water. So, the greater the amount of salt dissolved in the water, the higher the electrical conductivity. However, not all salts dissociate (break apart) the same when dissolved in water. Some salts, like sodium chloride will dissociate completely to form ions, while others, like magnesium sulfate (Epson salts or MgSO 4 ) will dissolve, but will not totally dissociate. When equal amounts of sodium chloride and magnesium sulfate are dissolved in water, the sodium chloride will have the higher EC. Some salts, like urea, will dissolve completely but don t form ions, and so their presence in water doesn t affect EC. Fertilizers are nothing more than combination of salts, but because each formula is different, there is a unique relationship between the concentration you are applying with a specific fertilizer and the EC. For example, is composed of ammonium nitrate, monoammonium phosphate, and potassium nitrate Not for publication or reproduction without the authors consent. Pg. 2

3 Table 2. The relationship between electrical conductivity (EC) and the fertilizer concentration (in ppm total nitrogen) when dissolved in pure water. Values for EC are given in ms/cm 2. Fertilizer concentration in ppm total nitrogen Formula Ca Ca-1 Mg Ca-3 Mg Ca-1 Mg Ca-2 Mg Ca-2 Mg Ca-3 Mg NOTE: There can be some slight differences between the values of the same formulation from different companies. You should always obtain a fertilizer chart from your manufacturer. 1 N-P 2 O 5 -K 2 O formula 2 The terms conductivity, soluble salts, or electrical conductivity (EC) are all used to describe the amount of salt contained in a solution. There are also a variety of units used to measure EC including micromhos (µmho), millimhos (mmhos), microsiemens (µs), millisiemens (ms), or decisiemens µmho/cm = 1000µS/cm = 1mmho/cm = 1mS/cm = 1dS/m. Frequently, you are not using a pure water source without any conductivity. Therefore, you need to take the water into account when determining the relationship between EC and fertilizer concentration. Examples are given below. Calculate ppm Nitrogen from a fertilizer solution with a total EC of 1.8 ms/cm and an using irrigation water with an EC of 0.5 ms/cm. EC of fertilizer solution - EC of water = EC of only the fertilizer 1.8 ms/cm ms/cm = 1.3 ms/cm From the chart above, with an EC of 1.3 ms/cm would give a concentration of about 200 ppm N. To predict the EC of at 200 ppm N using an irrigation water with an EC of 0.5 ms/cm. EC of at 200 ppm N + EC of water = EC of fertilizer solution 1.3 ms/cm ms/cm = 1.8 ms/cm For growers that use proportioners or injectors, sometimes the EC of the fertilizer solution coming out of the hose is not what you expect. The problem can be caused by an incorrect dilution rate from the injector (either broken or not properly adjusted) or the fertilizer stock concentration is wrong. To check the fertilizer concentration, take a small amount from the stock solution, dilute this in water to the target ratio, and check the EC. For example, in you think that your injectors is set at 1:100, then put 10 milliliters into 1 liter of water (this will also give a 1:100 dilution). If the EC of the solution is where is should be, then it is an injector problem. If the EC of the hand-diluted solution is off-target, then the stock concentration is not correct. (along with a small amount of micronutrients, and dye). Dissolving 1 gram of in 1 liter of pure water will give you a solution with a concentration of 200 ppm nitrogen and an EC of about 1.3 ms/cm is composed of monoammonium phosphate, potassium nitrate, and urea. Dissolving 1 gram of in 1 liter of pure water will also give you a solution with a concentration of 200 ppm nitrogen but the EC will only be 0.8 ms/cm is also composed of monoammonium phosphate, potassium nitrate, and urea. Dissolving 1 gram of in 1 liter of water will give you a solution with a concentration of 300 ppm nitrogen, but the EC will only be about 0.4 ms/cm. Don t forget that the irrigation water also has an EC, which needs to be taken into account when determining the relationship between the EC and concentration of a fertilizer solution. For example, dissolving 1 gram per liter of in pure water (no EC) will give a solution with an EC of 1.3 ms/cm. However, dissolving 1 gram of in water with an EC of 0.5 ms/cm will give a solution with an EC of 1.8 ms/cm. See Table 2 for more information on the relationship between EC and fertilizer concentrations. Not for publication or reproduction without the authors consent. Pg. 3

4 Table 3. Relationship between electrical conductivity (EC) of selected fertilizer dissolved in pure water at a constant concentration of 100 ppm total nitrogen and total dissolved solids (TDS) measurements. The exact value that you get will depend on the TDS conversion constant used by the meter. EC value at 100 TDS conversion constants (ppm = 1 ms/cm) Formula ppm N (ms/cm) 420 ppm 500 ppm 640 ppm 700 ppm 1000 ppm ppm 70 ppm 90 ppm 98 ppm 140 ppm ppm 200 ppm 256 ppm 280 ppm 400 ppm ppm 330 ppm 422 ppm 462 ppm 660 ppm ppm 390 ppm 500 ppm 546 ppm 780 ppm ppm 400 ppm 512 ppm 560 ppm 800 ppm At a concentration 100 ppm total nitrogen from , the can range from 277 ppm to 660 ppm, depending on the constant used by the TDS meter. To calculate a TDS for nitrogen concentrations other than those presented above, multiply the corresponding EC from Table 1 by the constant for your meter. Examples are given below. Calculate the expected of at 100 ppm total nitrogen (in pure water) using a meter with a costant of 1000 ppm = 1 ms/cm. EC of fertilizer solution at 100 ppm total nitrogen x Constant = TDS of the fertilizer 0.66 ms/cm x 1000 = 660 ppm TDS Predict the nitrogen concentration of dissolved in pure water with a of 660 ppm Constant = EC of fertilizer solution 660 ppm 1000 = 0.66 ms/cm An EC of 0.66 ms/cm corresponds to a total nitrogen concentration of 100 ppm N. Irrigation water will also affect the TDS value. For example, a water with an EC of 0.5 ms/cm will show a of 500 ppm (if the constant used by the meter is 1000 ppm). At 100 ppm N from (and using the same meter), the of the fertilizer solution would be: + = TDS of the fertilizer solution of the fertilizer of the water 660 ppm ppm = 1160 ppm Calculate the TDS supplied by only the fertilizer when the fertilizer solution (water + fertilizer) has a TDS of 1160 ppm, the water has a TDS of 500 ppm, and the constant used by the meter is = TDS of the fertilizer of the fertilizer solution of the water 1160 ppm ppm = 660 ppm To determine the constant being used by your TDS meter, simply look at the measurable range of the meter for EC and TDS (most TDS meters are combination TDS and EC meters). For example, if the range of the meter for EC is 0 to 10 ms/cm and TDS is 0 to 10,000 ppm, then you know the constant being used is 1000 (1 ms/cm = 1000 ppm). Another way is to purchase a standard EC solution and measure the TDS of the solution. For example, a common standard EC solution used for calibrating meters has an EC of 1.41 ms/cm. A TDS meter using a constant of 1000 would measure 1410 ppm with a standard solution of 1.41 ms/cm. Q) What is the difference between electrical conductivity (EC) and total dissolved solids (TDS)? A) The measurement of EC and TDS are closely related. An EC meter will measure the electrical conductance of the fertilizer solution. A TDS meter will measure the EC of the fertilizer solution and then convert the measurement into parts per million (ppm) by multiplying the EC by a constant. In article 2 of this series, I said that the constant is usually 1 ms/cm = 1000 ppm salt. On further examination, I found five different constants being used by various meters ranging from 420 to See Table 3 for more information on the relationship between EC and TDS. Q) How do I know how much of each nutrient I am applying? A) Both EC and s are generic measurements, they don t tell you any specifics about the fertilizer solution that you are applying. If you want to know the exact concentration of each of the nutrients that you are applying with the fertilizer, then you need to calculate that from the formula on the bag of fertilizer. See Table 4 for more information on the concentration of individual macronutrient supplied by different fertilizers. In addition, the irrigation water can supply significant amounts of some nutrients. Unless you are using a pure water source (which contains little if any nutrients), then you should add the concentration of Not for publication or reproduction without the authors consent. Pg. 4

5 Table 4. The concentration of specific macronutrients (in ppm) supplied by different fertilizers when applied at a total nitrogen concentration of 100 ppm N NH 4 -N Urea-N NO 3 -N P K Ca Mg S Granular fertilizers Ca Ca-1 Mg Ca-2 Mg Ca-1 Mg Ca-2 Mg Ca-3 Mg Ca-2 Mg Liquid fertilizers Ca-0.5 Mg Ca-0.5 Mg Ca-0.5 Mg Ca-0.5 Mg To calculate the concentration of each nutrient in a fertilizer solution, divide the percentage of desired nutrient in the fertilizer formula by the percentage of total nitrogen in the formula, then multiply by the concentration of total nitrogen in the fertilizer solution. Examples are given below: How much calcium will I get from when applied at a concentration of 100 ppm total nitrogen? % desired nutrient in % Total nitrogen concentration (in ppm) in x = Concentration of desired nutrient formula total nitrogen the fertilizer solution 8 13 x 100 = 61.5 When you apply 100 ppm total nitrogen from , the fertilizer is supplying about 62 ppm calcium. To calculate the values for phosphorus and potassium, and addition step is required. For phosphorus, the calculated value will be for P 2 O 5. To calculate the actual concentration of phosphorus you are applying, multiply the P 2 O 5 value by For potassium, the calculated value will be for K 2 O. To calculate the actual concentration of potassium you are applying, multiply the K 2 O value by nutrients supplied by the water with those supplied by the fertilizer to get the total nutrient concentration applied to the plant. Q) Do orchids require high phosphorus fertilizers? A) Phosphorus is needed by the plant to store and transport chemical and light energy. Although there is no specific research, it appears that applying between 10 and 20 ppm phosphorus with every irrigation will supply enough phosphorus to a plant (any plant, not just orchids) for normal growth and flowering. Once this sufficient level is reached, then there is not any particular benefit to applying any more phosphorus. Thus in this case, there is no benefit to using a high phosphorus fertilizer. When plants have a phosphorus deficiency, the older leaves tend to turn purple, and the plants show a marked loss of vigor. Unfortunately, with some plants, phosphorus deficiency is hard to see, and all you will notice is a lack of vigor with poor root growth and limited if any flowering. Because orchids are slow growing to begin with, you might not notice the problem at all. Under these circumstances, it is appropriate to apply a fertilizer that is high in phosphorus simply to get the plant growing again. However, because the plant has been stressed, you will likely see a reduction in blooming and growth when compared to plants that never had the deficiency to begin with. A third possibility has to do with the overapplication of nitrogen rather than the under-application of phosphorus. It is well know that over-applying nitrogen will cause plants to remain vegetative. For example, tomatoes, peppers, squash, new guinea impatiens, or azaleas will not produce fruit (or flowers) if too much nitrogen is applied. Rather, they will produce excess foliage growth. Reducing the nitrogen level in the soil reduces the vegetative growth, and the plants produce flowers or fruit. Orchid fertilizers like lend themselves to the over-application of nitrogen because they have a Not for publication or reproduction without the authors consent. Pg. 5

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